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• unknown column in where clause

  - by ranzy

  $result = mysql_query("SELECT * FROM Volunteers WHERE Volunteers.eventID = " . $var); $sql = mysql_query("SELECT * FROM Members WHERE Members.pid = " . $temp); I am also doing or die(mysql_error()) at the end of both statements if that matter. My problem is that the first statement executes perfectly but in that table I store an attribute called pid. So the second statement is supposed to take that and return the row where it equals that pid so I can get the name. I get an error that says unknown column in 'a2' in 'where clause' where a2 the pid attribute returned from the first statement. Thanks for any help!

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• SQL: Find the max record per group

  - by user319088

  I have one table, which has three fields and data. Name , Top , Total cat , 1 , 10 dog , 2 , 7 cat , 3 , 20 horse , 4 , 4 cat , 5 , 10 dog , 6 , 9 I want to select the record which has highest value of Total for each Name, so my result should be like this: Name , Top , Total cat , 3 , 20 horse , 4 , 4 Dog , 6 , 9 I tried group by name order by total, but it give top most record of group by result. Can anyone guide me, please?

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• Trouble creating stored procedure

  - by MatW

  I'm messing around with stored procedures for the first time, but can't even create a simple select! I'm using phpMyAdmin and this is my SQL: DELIMITER // CREATE PROCEDURE test_select() BEGIN SELECT * FROM products LIMIT 10; END // DELIMITER ; After submitting that, my localhost does some thinking for a loooong time and eventually loads a page with no content called /phpmyadmin/import.php. After reloading phpMyAdmin and trying to invoke the procedure: CALL test_select(); I get a "PROCEDURE doesn't exist" error. Any ideas?

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• Are Conditional subquery

  - by Tobias Schulte

  I have a table foo and a table bar, where each foo might have a bar (and a bar might belong to multiple foos). Now I need to select all foos with a bar. My sql looks like this SELECT * FROM foo f WHERE [...] AND ($param IS NULL OR (SELECT ((COUNT(*))>0) FROM bar b WHERE f.bar = b.id)) with $param being replaced at runtime. The question is: Will the subquery be executed even if param is null, or will the dbms optimize the subquery out?

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• Keeping some choices in the Table for the Field of Type Dropdown

  - by Mercy

  Hi, i am having a Table named Attributes which has id form_id label size sequence_no Type 1 1 Name 200 1 Text 2 1 Age 150 2 Number 3 1 Address 300 3 Textarea 4 1 Gender 200 4 Dropdown I am having the doubt how can i keep the Choices of the Field of type "Dropdown" in the Table Eg. For Gender the choices will Male , Female.. Please give me the suggestions...

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• Duplicate Blob field with foreach

  - by JGSilva

  I have some fields (blob) where I have uploaded some images. The images display correctly and I can open it without problem in Photoshop for example. I created a button where user can duplicate the product and everything works fine, but when it comes to duplicate the image entry I got some errors, like 1064 and others ones that I can't remember cause I am working 3 days inside this. Because de original product have 3 or more images I select then and gave an foreach. What I notice when a print de blob is that in the end it eats the next array, like if don't have an end. In other words, the next item got inside that utf-8 character in the print. That gave me some clue. The next approach was to save it in somewhere, and reupload it. The problem is that only the first one works. When I download the image saved, it opens normally so, it is not a saving in disk problem. When I gave a print in the $result, the same happens, is like the image is hungry and ate the next one. Here is the code. Notice = I created the [$count] to see if was not an rewrite in array error. Even tried to , in beging of the foreach, kind of clean the vars… $count=0; foreach ($original_image as $key => $val) { $count++; //$arquivo = ''; //$image = ''; //$file = ''; //$this->image = ''; //$return = ''; $arquivo[$count] = $val['pi_id'].'.'.$val['pi_type']; $image[$count] = $caminho_url.$arquivo[$count]; if (file_exists($image[$count])) { $this->image = Image::factory($image[$count]); $this->image->save($image[$count]); $file[$count]=mysql_real_escape_string(addslashes(fread(fopen($image[$count], "r"), filesize($image[$count])))); $return[$count] = Product::add_image($id_prod, $file[$count], $val['pi_type'],$val['pi_main']); }else { die('no'); } }

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• How to use SQL - INSERT...ON DUPLICATE KEY UPDATE?

  - by Probocop

  Hi, I have a script which captures tweets and puts them into a database. I will be running the script on a cronjob and then displaying the tweets on my site from the database to prevent hitting the limit on the twitter API. So I don't want to have duplicate tweets in my database, I understand I can use 'INSERT...ON DUPLICATE KEY UPDATE' to achieve this, but I don't quite understand how to use it. My database structure is as follows. Table - Hash id (auto_increment) tweet user user_url And currently my SQL to insert is as follows: $tweet = $clean_content[0]; $user_url = $clean_uri[0]; $user = $clean_name[0]; $query='INSERT INTO hash (tweet, user, user_url) VALUES ("'.$tweet.'", "'.$user.'", "'.$user_url.'")'; mysql_query($query); How would I correctly use 'INSERT...ON DUPLICATE KEY UPDATE' to insert only if it doesn't exist, and update if it does? Thanks

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• Select statement that combines similar rows with certain ids?

  - by vegatron

  hi I have a warehouse_products table which defines how many products in the warehouses so lets say I have 20 records/rows in the table, some rows may contain the same product id but in a different warehouse I need to create select statement that give every product one row, and in this row I must have the quantity in warehouse A and warehouse B .. so in the end I will get for example 10 rows that contain all the data

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• Is it necessary to use mysql_real_escape_string(), when magic_quotes_gpc is on?

  - by Zack

  To prevent SQL injection, is it necessary to use mysql_real_escape_string(), when magic_quotes_gpc is on?

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• SQL - How to display the students with the same age?

  - by Cristian

  the code I wrote only tells me how many students have the same age. I want their names too... SELECT YEAR(CURRENT DATE-DATEOFBIRTH) AS AGE, COUNT(*) AS HOWMANY FROM STUDENTS GROUP BY YEAR(CURRENT DATE-DATEOFBIRTH); this returns something like this: AGE HOWMANY --- ------- 21 3 30 5 Thank you. TABLE STUDENTS COLUMNS: StudentID (primary key), Name(varchar), Firstname(varchar), Dateofbirth(varchar) I was thinking of maybe using the code above and somewhere add the function concat that will put the stundents' names on the same row as in

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• How can we have check boxs inside a muti valued list/ combo box using php? and then how can we inser

  - by Climb

  i am using prototype.js

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• COUNT issue across multiple tables

  - by Kim

  I am trying to count across 2 tables and I dont see whats wrong with my query yet I get a wrong result. User 2 does not exist in table_two, so the zero is correct. SELECT t1.creator_user_id, COUNT(t1.creator_user_id), COUNT(t2.user_id) FROM table_one AS t1 LEFT JOIN table_two AS t2 ON t2.user_id = t1.creator_user_id GROUP BY t1.creator_user_id, t2.user_id Actual result 1 192 192 2 9 0 Expected result 1 16 12 2 9 0 The result indicate a missing group by condition, but I already got both fields used. Where am I wrong ? Also, can I sum up all users that doesnt exist in table_two for t1 ? Like user 3 exists 21 times in t1, then the results would be: 1 16 12 (users with > 0 in t2 will need their own row) 2 30 0 (user 2=9 + user 3=21 => 30) Its okay for the user Id to be wrong for sum of t1 for all users with 0 in t2. If not possible, then I'll just do two queries.

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• How add column order in careers table???

  - by Mahran Elneel

  this table i want to create and how assign job to first position??? job_id dynamic Jobs Title text Job Description text Order combo box to choose after what job or at first position in the website i create this table and cannot choose first job to view in my website

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• click and submit button id with jquery

  - by user836910

  my aim is to submit a button id using jquery into a database im only interested in the button not its value. $("#button").click(function(){ var p = $(this).attr("id"); $.ajax({ type: "POST", url: subpage.php", data: 'b='+p, cache: false, success: function(html) { //process live } }); return false; }); subpage.php $item = $_POST['b']; $query = mysql_query("SELECT * FROM table WHERE id = '25' AND bttnid = '$item'"); if(count($query)==0){ mysql_query("INSERT INTO table VALUES ('','25','$item') "); } it doesn't submit. please assit

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• How do I get the median/mode/range of a column in SQL using Java?

  - by Derek

  I have to get the median, mode and range of test scores from one column in a table but I am unsure how to go about doing that. When you connect to the database using java, you are normally returned a ResultSet that you can make a table or something out of but how do you get particular numbers or digits? Is there an SQL command to get the median/mode/range or will I have to calculate this myself, and how do you pull out numbers from the table in order to be able to calculate the mode/median/range? Thanks.

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• Need help with many-to-many relationships....

  - by yuudachi

  I have a student and faculty table. The primary key for student is studendID (SID) and faculty's primary key is facultyID, naturally. Student has an advisor column and a requested advisor column, which are foreign key to faculty. That's simple enough, right? However, now I have to throw in dates. I want to be able to view who their advisor was for a certain quarter (such as 2009 Winter) and who they had requested. The result will be a table like this: Year | Term | SID | Current | Requested ------------------------------------------------ 2009 | Winter | 860123456 | 1 | NULL 2009 | Winter | 860445566 | 3 | NULL 2009 | Winter | 860369147 | 5 | 1 And then if I feel like it, I could also go ahead and view a different year and a different term. I am not sure how these new table(s) will look like. Will there be a year table with three columns that are Fall, Spring and Winter? And what will the Fall, Spring, Winter table have? I am new to the art of tables, so this is baffling me... Also, I feel I should clarify how the site works so far now. Admin can approve student requests, and what happens is that the student's current advisor gets overwritten with their request. However, I think I should not do that anymore, right?

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• While loop in foreach loop not looping correctly

  - by tominated

  I'm trying to make a very basic php ORM as for a school project. I have got almost everything working, but I'm trying to map results to an array. Here's a snippet of code to hopefully assist my explanation. $results = array(); foreach($this->columns as $column){ $current = array(); while($row = mysql_fetch_array($this->results)){ $current[] = $row[$column]; print_r($current); echo '<br><br>'; } $results[$column] = $current; } print_r($results); return mysql_fetch_array($this->results); This works, but the while loop only works on the first column. The print_r($results); shows the following: Array ( [testID] => Array ( [0] => 1 [1] => 2 ) [testName] => Array ( ) [testData] => Array ( ) ) Can anybody shed some light? Thanks in advance!

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• Mysqli prepared insert statements always returning false

  - by user1754679

  I'm writing prepared statements that are supposed to insert data into a table, on a database that's been pre-selected in the variable $GLOBALS['mysqli']. The connection has been tested, and that's not the problem I'm having. I'm only running into trouble whenever my prepared statement involves INSERT INTO. I know the tablename, and field names are correct, but $stmt is ALWAYS false. What gives? $stmt = $GLOBALS['mysqli']->prepare("INSERT INTO audit_RefreshCount (user, count, lastrefresh) values (?,?,?)"); if ($stmt == TRUE) { $stmt->bindParam('ssi', $_SESSION['username'], '0', time()); //$stmt->bind_Param('ssi', $_SESSION['username'], '0', time()); // Also doesn't work. $stmt->execute(); }

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• sql statement question. Need to query 3 tables in one go!

  - by Stefan

  Hey there, I have an sql database. In this database is 3 tables I need to query. The first table has all the item info called item and the other two tables has data for votes and comments called userComment and the third for votes called userItem I currently have a function which uses this sql query to get the latest more popular (in terms of both votes and comments): $sql = "SELECT itemID, COUNT(*) AS cnt FROM ( SELECT `itemID` FROM `userItem` WHERE FROM_UNIXTIME( `time` ) >= NOW() - INTERVAL 1 DAY UNION ALL SELECT `itemID` FROM `userComment` WHERE FROM_UNIXTIME( `time` ) >= NOW() - INTERVAL 1 DAY AND `itemID` > 0 ) q GROUP BY `itemID` ORDER BY cnt DESC"; I know how to change this for either by votes alone or comments.... HOWEVER - I need to query the database to only return the itemID's of the ones which have specific conditions in only the item table these are WHERE categoryID = 'xx' AND typeID = 'xx' If the sql ninja could please help me on this one? Do I have to first return the results from the above query and the for each in the array fetched then check each against the item table and see if it fits the conditions to build a new array - or is that overkill? Thanks, Stefan

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• How do I write this Django model in SQL?

  - by alex

  I want to create a new column. How do I write this in SQL? class mytable(models.Model): created_at = models.DateTimeField(auto_now_add=True)

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• How to compare filename of uploaded file and string

  - by user225269

  I use this code to upload image files in xammp server: <?php if ((($_FILES["file"]["type"] == "image/gif") || ($_FILES["file"]["type"] == "image/jpeg") || ($_FILES["file"]["type"] == "image/pjpeg")) && ($_FILES["file"]["size"] < 100000)) { if ($_FILES["file"]["error"] > 0) { echo "Return Code: " . $_FILES["file"]["error"] . "<br />"; } else { echo "Upload: " . $_FILES["file"]["name"] . "<br />"; echo "Type: " . $_FILES["file"]["type"] . "<br />"; echo "Size: " . ($_FILES["file"]["size"] / 1024) . " Kb<br />"; echo "Temp file: " . $_FILES["file"]["tmp_name"] . "<br />"; if (file_exists("upload/" . $_FILES["file"]["name"])) { echo $_FILES["file"]["name"] . " already exists. "; } else { move_uploaded_file($_FILES["file"]["tmp_name"], "upload/" . $_FILES["file"]["name"]); echo "Stored in: " . "upload/" . $_FILES["file"]["name"]; } } } else { echo "Invalid file, File must be less than 100Kb in size with .jpg, .jpeg, or .gif file extension"; } ?> What do I do to compare the file name of the uploaded files with the text inputted by the user? My goal is to be able to compare the user input(ID number) and the file name of the image file which should also be an ID number. So that I will be able to display the image that corresponds with the ID Number provided. What do I need to do?Please give me an idea on how can I achieve this. Thanks

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• Jquery Autocomplete after space press

  - by Limpep

  I am having an issue with my auto-complete feature such as when a user presses the space button the auto-complete doesn't show up again. Here is my code script type="text/javascript"> function lookup(inputString) { if(inputString.length == 0) { // Hide the suggestion box. $('#suggestions').hide(); } else { $.post("autocomplete.php", { queryString: ""+inputString+"" }, function(data){ if(data.length >0) { $('#suggestions').show(); $('#autoSuggestionsList').html(data); } }); } } // lookup function fill(thisValue) { $('#tag').val(thisValue); setTimeout("$('#suggestions').hide();", 200); } here my php code <?php require_once('config.php'); $db = new mysqli(DB_HOST, DB_USER, DB_PASSWORD,DB_DATABASE); if(!$db) { // Show error if we cannot connect. echo 'ERROR: Could not connect to the database.'; } else { // Is there a posted query string? if(isset($_POST['queryString'])) { $queryString = $db->real_escape_string($_POST['queryString']); // Is the string length greater than 0? if(strlen($queryString) >0) { // Run the query: We use LIKE '$queryString%' // The percentage sign is a wild-card, in my example of countries it works like this... // $queryString = 'Uni'; // Returned data = 'United States, United Kindom'; $query = $db->query("SELECT name FROM tag WHERE name LIKE '$queryString%' ORDER BY name LIMIT 10"); if($query) { // While there are results loop through them - fetching an Object (i like PHP5 btw!). while ($result = $query ->fetch_object()) { // Format the results, im using <li> for the list, you can change it. // The onClick function fills the textbox with the result. echo '<li onClick="fill(\''.$result->name.'\');">'.$result->name.'</li>'; } } else { echo 'ERROR: There was a problem with the query.'; } } else { // Dont do anything. } // There is a queryString. } else { echo 'There should be no direct access to this script!'; } } ? Any help would be great, thanks.

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• need help on my query.

  - by Dharmendra

  i have one table : nobel(yr, subject, winner) and i have this query : In which years was the Physics prize awarded but no Chemistry prize. this is what i tried : select distinct yr from nobel where subject='physics' and subject!='chemistry' but is not working where i am going wrong. see, i am not here to make my homework from someone. i am here to learn something. so, please give me suggetion.

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• Is it necessary to write ROLLBACK if queries fail?

  - by Donator

  I write mysql_query("SET AUTOCOMMIT=0"); mysql_query("START TRANSACTION"); before I write all queries. Then check if all of them are true and then write: mysql_query("COMMIT"); But if one of query fails, I just pass COMMIT query. So do I really need ROLLBACK function if one of the queries fail? Because without ROLLBACK it also works. Thanks.

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• PHP MySQLi isn't letting me alter a table (adding a new column)

  - by asdasd

  Well thats pretty much it. This is my query: $query = 'ALTER TABLE permissions ADD '.$name.' INT NOT NULL DEFAULT \'0\''; Where $name is already checked to exist with only lower case alpha letters, and not more than 20 length. Im just starting this out with very simple names. The next 4 lines of code after that one are: if($stmt = $db -> prepare($query)) { $success = $stmt -> execute(); $stmt -> close(); if(!$success) echo 'ERROR: Unsuccessful query: ',$db->error,PHP_EOL; } And I get back, every time ERROR: Unsuccessful query: And no error message. Is there a way to get more error messages so I can see what is failing? I can add new columns through phpmyadmin, but that really doesnt help me at all. The $db is fine, i do lots of stuff before and after this one section. It is only adding new column to the table that fails. side question: prepare() rejected my query every time when i tried to make those 2 variables, the $name and the 0 value as ? ? prepared statement values. Thats why they are in the real query and not bound later. If i could change that too I would like that.

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