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  • jQuery DOM append losing markup

    - by Raj
    This is related to an earlier question. I try to append HTML DOM returned in an AJAX response to an existing DIV. I see all the text, but it seems all markup such as bold, italic, etc is lost. My AJAX (XML) data is like so: <event source="foo"> <contents> <h1>This is an event</h1> This is the body of the event </contents> </event> My jQuery code does this: $("#eventDiv").append( jData.find("contents").contents().clone() ); Attempting to do .html() on the cloned contents throws an exception: TypeError: Cannot call method 'replace' of undefined. I am a little surprised that it is so excruciatingly hard to do this with jQuery. Am I doing something too far off the track?

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  • Django URL Conf Returns Incorrect "Current URL"

    - by natnit
    I have a django app that is mostly done, and the URLs work perfectly when I run it with the manage.py runserver command. However, I've recently tried to get it running via lighttpd, and many links have stopped working. For example: http://mysite.com/races/32 should work, but instead throws this error message. Page not found (404) Request Method: GET Request URL: http://mysite.com/races/32 Using the URLconf defined in racetrack.urls, Django tried these URL patterns, in this order: ^admin/ ^create/$ ^races/$ ^races/(?P<race_id>\d+)/$ ^races/(?P<race_id>\d+)/manage/$ ^races/(?P<text>\w+)/$ ^user/(?P<kol_id>\d+)/$ ^$ ^login/$ ^logout/$ The current URL, 32, didn't match any of these. The request URL is accurate, but the last line (which displays the current URL) is giving 32 instead of races/32 as expected. Here is my urlconf: from django.conf.urls.defaults import * from django.contrib import admin admin.autodiscover() urlpatterns = patterns('racetrack.races.views', (r'^admin/', include(admin.site.urls)), (r'^create/$', 'create'), (r'^races/$', 'index'), (r'^races/(?P<race_id>\d+)/$', 'detail'), (r'^races/(?P<race_id>\d+)/manage/$', 'manage'), (r'^races/(?P<text>\w+)/$', 'index'), (r'^user/(?P<kol_id>\d+)/$', 'user'), # temporary for index page replace with welcome page (r'^$', 'index'), ) urlpatterns += patterns('django.contrib.auth.views', (r'^login/$', 'login', {'template_name': 'races/login.html'}), (r'^logout/$', 'logout', {'next_page': '/'}), ) Thank you.

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  • Where does java.util.logging.Logger store their log

    - by Harry Pham
    This might be a stupid question but I am a bit lost with java Logger private static Logger logger = Logger.getLogger("order.web.OrderManager"); logger.info("Removed order " + id + "."); Where do I see the log? Also this quote from java.util.logging.Logger library: On each logging call the Logger initially performs a cheap check of the request level (e.g. SEVERE or FINE) against the effective log level of the logger. If the request level is lower than the log level, the logging call returns immediately. After passing this initial (cheap) test, the Logger will allocate a LogRecord to describe the logging message. It will then call a Filter (if present) to do a more detailed check on whether the record should be published. If that passes it will then publish the LogRecord to its output Handlers. Does this mean that if I have 3 request level log: logger.log(Level.FINE, "Something"); logger.log(Level.WARNING, "Something"); logger.log(Level.SEVERE, "Something"); And my log level is SEVERE, I can see all three logs, if my log level is WARNING, then I cant see SEVERE log, is that correct? And how do I set the log level?

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  • How do I dynamically load a js file using Prototype?

    - by domagoj412
    Hello, I am using prototype to load external js file (actually it is php file) dynamically. Like this: function UpdateJS(file) { var url = 'main_js.php?file='+file; var myAjax = new Ajax.Request( url, {method: 'get', onComplete: showResponseHeader} ); } function showResponseHeader (originalRequest) { $('jscode').innerHTML = originalRequest.responseText; } Container "jscode" is defined like this: <script type="text/javascript" id="jscode"></script> And it works! But if some different file is called, all the functions from previous one are preserved. And I don't want that. Anybody knows how to "unload" first js file when second one is called? (I also tried using Ajax.Updater function but the result is the same.) Update: It turns out that there is bigger problem: it only loads if function "UpdateJS" is in window.onload that is why it doesn't load anything else after that. So prototypes update it's maybe not such a good way for this...

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  • Show Div When Radio Checked

    - by maniootek
    I tried to use this code: <script src="//ajax.googleapis.com/ajax/libs/jquery/1.10.2/jquery.min.js" type="text/javascript"></script> <style type="text/css"> div {display: none} </style> <script type="text/javascript"> $('.radio1').click(function () { $('.div1').show(); }); $('.radio2').click(function () { $('.div2').show(); }); </script> <label><input type="radio" name="group1" class="radio1"></label> <label><input type="radio" name="group1" class="radio2"></label> <div class="div1">Radio1 selected !</div> <div class="div2">Radio2 selected !</div> But when I check any radio then notthing happens. I tried with Fiddle: http://jsfiddle.net/Ac9c4/ and same no results Any idea?

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  • Php variable in several files including jquery

    - by vipinsahu
    i created two variable and these two variable are using everywhere . i don't want to store these variable in to database e.g ( $username ,$password and there are 3 files using these variable load.php,index.php and add.php , i am also using jquery to load the add.php as in ajax (to add the user in JSON) $.ajax({ type: "POST", url: "add.php", data: "twitter="+encodeURIComponent(twitter), /* Sending the filled in twitter name */ success: function(msg){ /* PHP returns 1 on success, and 0 on error */ var status = parseInt(msg); if(status) { $('#response').html('Thank you '); $('#twitterName').val(''); } else $('#response').html('<span style="color:red">There is no user.</span>'); } }); how can i use these two variable in a single file to perform the whole operation Thanks

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  • How do you use jQuery .data() to store html?

    - by Al
    Hi all - when I look up the syntax for .data(), it gives examples like this: $('body').data('foo', 52); I am doing AJAX loads and I was wondering if it is possible to store the incoming html using .data() so once the content is loaded, I would not need to do another AJAX load if the same link is clicked again - I would check to see if the .data key is empty. Would something like this work?: To load the contents of a #ajaxdiv into storage: $('body').data('storage', div#ajaxdiv.html()); To test if the data has already been loaded: if $('body').data('storage') != '' { div#ajaxdiv.html($('body').data('storage')); } Thanks in advance!! Al

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  • How to configure and run a fastcgi application using Lighthttpd...

    - by Airy
    Hi, i've installed Lighthttpd for windows and i'd created a simple program in c++ which uses fastcgi libraries. i'll post the code here... #include "fcgi_stdio.h" #include <stdlib.h> int count; void initialize(void) { count=0; } void main(void) { initialize(); while (FCGI_Accept() >= 0) { printf("Content-type: text/html\r\n" "\r\n" "<title>FastCGI Hello! (C, fcgi_stdio library)</title>" "<h1>FastCGI Hello! (C, fcgi_stdio library)</h1>" "Request number %d running on host <i>%s</i>\n", ++count, getenv("SERVER_HOSTNAME")); } } I've spawned the fastcgi application in lighthttpd using the below configuration in lightttpd-inc.conf fastcgi.server = ( ".exe" => ( "" => ( "bin-path" => "D:\tinycgi.exe", "port" => 8080, "min-procs" => 1, "max-procs" => 1 ) ) ) while sending a request using the browser the server is responding with this message in the console 2009-02-18 16:08:34: (mod_fastcgi.c.2494) unexpected end-of-file (perhaps the fa stcgi process died): pid: 0 socket: tcp:localhost:8080 2009-02-18 16:08:34: (mod_fastcgi.c.3325) response not received, request sent: 1 024 on socket: tcp:localhost:8080 for /new/tinycgi.exe , closing connection I think the fastcgi application is not spawned correctly. Thank you, Varun

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  • Override default javascript functionality with jQuery

    - by deth4uall
    I am trying to overwrite a JavaScript on change event in the below code with jQuery however I believe that the inline JavaScript is taking priority over the jQuery functionality declared. Essentially I am trying to have an AJAX version of my site which includes an additional JavaScript file. I need this functionality to still work without the additional AJAX version, but I am not sure as to whether I should include it in the main JavaScript file or leave it inline like it is right now. Any suggestions and information regarding them would be greatly appreciated! Thanks! <form action="/cityhall/villages/" method="post" name="submit_village"> <select name="village" onchange="document.submit_village.submit();"> <option value=""></option> </select> </form> I am trying to use the jQuery Form Plugin to submit the posts to the PHP to handle the requests as follows: var bank_load_options = { target: '#content', beforeSubmit: showRequest, success: showResponse }; $('form.get_pages').livequery(function(){ $(this).ajaxForm(bank_load_options); return false; }); I modified the code as following: <form action="/cityhall/villages/" method="post" id="submit_village" name="submit_village"> <select name="village" class="get_pages" rel="submit_village"> <option value=""></option> </select> </form> <script> # main JavaScript $('.get_pages').live('change',function(e){ var submit_page = $(this).attr('rel'); $("#"+submit_page).submit(); }); # ajax JavaScript var bank_load_options = { target: '#content', beforeSubmit: showRequest, success: showResponse }; $('.get_pages').live('change',function(){ var submit_page = $(this).attr('rel'); $("#"+submit_page).ajaxForm(get_pages_load_options); return false; }); </script> However now it only runs every other option when I change it.

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  • display results of jquery in a label in asp.net

    - by Zoya
    I want to display result of this javascript in a label control on my asp.net page, instead of alert. how can i do so? <script type="text/javascript" language="Javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script> <!-- Require EasyJQuery After JQuery --><script type="text/javascript" language="Javascript" src="http://api.easyjquery.com/easyjquery.js"></script> <script type="text/javascript" language="Javascript"> // 1. Your Data Here function my_callback(json) { alert("IP :" + json.IP + " COUNTRY: " + json.COUNTRY); } function my_callback2(json) { alert("IP :" + json.IP + " COUNTRY: " + json.COUNTRY + " City: " + json.cityName + " Region Name: " + json.regionName); } // 2. Setup Callback Function // EasyjQuery_Get_IP("my_callback"); // fastest version EasyjQuery_Get_IP("my_callback2","full"); // full version </script>

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  • Creating a RESTful service in CakePHP

    - by NathanGaskin
    I'm attempting to create a RESTful service in CakePHP but I've hit a bit of a brick wall. I've enabled the default RESTful routing using Router::mapResources('users') and Router::parseExtensions(). This works well if I make a GET request, and returns some nicely formatted XML. So far so good. The problem is if I want to make a POST or PUT request. CakePHP doesn't seem to be able to read the data from the request. At the moment my add(), edit() and delete() actions don't contain any logic, they're simply setting $this-data to the view. I'm testing with the following cURL command: curl -v -d "<user><username>blahblah</username><password>blahblah</password>" http://localhost/users.xml --header 'content-type: text/xml' Which only returns a 404 header. If I remove the --header parameter then it returns the view but no data is set. It feels like I'm missing something obvious here. Any ideas?

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  • Are there hosted jQuery UI themes anywhere? [closed]

    - by Kip
    Possible Duplicate: Downloading jQuery CSS from Google's CDN I'm using Google-hosted jQuery and jQueryUI, but I'm wondering if there are hosted jQueryUI themes anywhere? I'd like to just point to a hosted CSS file (the same way I do with the hosted JS file), so that I don't have to worry about setting up directories for the widget images or the CSS files or anything like that. Update I've found this, referenced by the jqueryui.com source code: <link rel="stylesheet" href="http://ajax.googleapis.com/ajax/libs/jqueryui/1.7.2/themes/ui-lightness/jquery-ui.css" type="text/css" media="all" /> Substituting the name of other themes from the themeroller page seems to work, but I'd love it if someone could find where on Google they list all the available themes that they are hosting. I'm not finding anything about this (maybe it is very recent?).

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  • Read quicktime movie from servlet in a webpage?

    - by khue
    Hi, I have a servlet that construct response to a media file request by reading the file from server: File uploadFile = new File("C:\\TEMP\\movie.mov"); FileInputStream in = new FileInputStream(uploadFile); Then write that stream to the response stream. My question is how do I play the media file in the webpage using embed or object tag to read the media stream from the response? Here is my code in the servlet: public void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { request.getParameter("location"); uploadFile(response); } private void uploadFile(HttpServletResponse response) { File transferFile = new File("C:/TEMP/captured.mov"); FileInputStream in = null; try { in = new FileInputStream(transferFile); } catch (FileNotFoundException e) { System.out.println("File not found"); } try { System.out.println("in byes i s" + in.available()); } catch (IOException e) { } DataOutputStream responseStream = null; try { responseStream = new DataOutputStream(response.getOutputStream()); } catch (IOException e) { System.out.println("Io exception"); } try { Util.copyStream(in, responseStream); } catch (CopyStreamException e) { System.out.println("copy Stream exception"); } try { responseStream.flush(); } catch (IOException e) { } try { responseStream.close(); } catch (IOException e) { } } And here is html page as Ryan suggested: <embed SRC="http://localhost:7101/movies/transferservlet" WIDTH=100 HEIGHT=196 AUTOPLAY=true CONTROLLER=true LOOP=false PLUGINSPAGE="http://www.apple.com/quicktime/"> Any ideas?

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  • is it better to test if a function is needed inside or outside of it?

    - by b0x0rz
    what is the best practice? call a function then return if you test for something, or test for something then call? i prefer the test inside of function because it makes an easier viewing of what functions are called. for example: protected void Application_BeginRequest(object sender, EventArgs e) { this.FixURLCosmetics(); } and private void FixURLCosmetics() { HttpContext context = HttpContext.Current; if (!context.Request.HttpMethod.ToString().Equals("GET", StringComparison.OrdinalIgnoreCase)) { // if not a GET method cancel url cosmetics return; }; string url = context.Request.RawUrl.ToString(); bool doRedirect = false; // remove > default.aspx if (url.EndsWith("/default.aspx", StringComparison.OrdinalIgnoreCase)) { url = url.Substring(0, url.Length - 12); doRedirect = true; } // remove > www if (url.Contains("//www")) { url = url.Replace("//www", "//"); doRedirect = true; } // redirect if necessary if (doRedirect) { context.Response.Redirect(url); } } is this good: if (!context.Request.HttpMethod.ToString().Equals("GET", StringComparison.OrdinalIgnoreCase)) { // if not a GET method cancel url cosmetics return; }; or should that test be done in Application_BeginRequest? what is better? thnx

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  • Why browser doesnt recognize jquery when <script src="...jquery.js> is on a html page served by Goo

    - by indiehacker
    jquery.js source code is not being recognised by browser using my page.html served by Google App Engine as a http:some_request to the SDK, BUT when I load the exact same page.html into the browser directly from my local hard drive as jquery.js all works OK, it is recognized, so I know my path is OK.... I don't understand? In the header of my page.html I have the following: <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.3/jquery.min.js" type="text/javascript"></script> I also tried without success in the header this: <script src="/static/jquery.js" type="text/javascript"></script> I am working along with the examples in the [Jquery tutorial][1]. I am sure there is something simple I dont understand about how .html pages served to the browser from app engine interact differently with the browser than what I normally would expect....but I frustratingly just cant get it.....everything else I have with my app engine app is working fine......would love some help so i can move forward....

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  • Live search results as you type... am I going about this the right way? jQuery + PHP

    - by dallen
    This is my first time building a tool like this, so please bare with me. I'm doing this to learn more about jQuery and AJAX. Basically, I have a search input and a hidden div. When you start typing in the search input, the hidden div becomes visible and results are brought in. In this case, I'm searching for client names. It all works fine, however I think my code could be better but I'm not sure exactly where to begin. Each keyup requests a PHP script which accesses a table in a database to find a like string. But in my PHP script, I'm echo'ing some JS/jQuery which I'm not sure is good practice. Below is my code. Am I going about this the right way or am I totally off base? Any suggestions for improvement? Javascript $("#search").keyup(function() { $("#search_results").show("fast"); $.ajax ({ type: "POST", url: "http://localhost:8888/index.php/welcome/search/" + $("#search").val(), success: function(html) { $("#search_results").html(html); } }); }); PHP function search($search_string = false) { if ($search_string) { $this->db->like('name', $search_string); $query = $this->db->get('clients'); if ($query->num_rows() == 0) { echo "No client exists."; } else { foreach ($query->result() as $row) { echo '<script>'; echo ' $("#client_results_'.$row->id.'").hide(); $("#'.$row->id.'").toggle(function() { $.ajax ({ type: "POST", url: "http://localhost:8888/index.php/welcome/search_client_ads/" + '.$row->id.', success: function(html) { $("#client_results_'.$row->id.'").html(html).show("fast"); } }); }, function() { $("#client_results_'.$row->id.'").hide("fast").html(""); });'; echo '</script>'; echo '<p><span id="'.$row->id.'">'.$row->name.'</span></p>'; echo '<div id="client_results_'.$row->id.'"></div>'; } } } else { echo ''; } } function search_client_ads($client_id) { $query = $this->db->get_where('online_ads', array('client' => $client_id)); if ($query->num_rows() == 0) { echo "No ads exist."; } else { foreach ($query->result() as $row) { echo $row->id; } } }

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  • Jersey, JAXB and getting an objectextending an abstract class as a parameter

    - by krajol
    I want to get an object as a parameter of a POST request. I got an abstract superclass that is called Promotion and subclasses Product and Percent. Here's how I try to get a request: @POST @Consumes(MediaType.APPLICATION_XML) @Produces(MediaType.APPLICATION_XML) @Path("promotion/") public Promotion createPromotion(Promotion promotion) { Product p = (Product) promotion; System.out.println(p.getPriceAfter()); return promotion; } and here's how I use JAXB in classes' definitions: @XmlRootElement(name="promotion") @XmlSeeAlso({Product.class,Percent.class}) public abstract class Promotion { //body } @XmlRootElement(name="promotion") public class Product extends Promotion { //body } @XmlRootElement(name="promotion") public class Percent extends Promotion { //body } So the problem now is when I send a POST request with a body like this: <promotion> <priceBefore>34.5</priceBefore> <marked>false</marked> <distance>44</distance> </promotion> and I try to cast it to Product (as in this case, fields 'marked' and 'distance' are from Promotion class and 'priceBefore' is from Product class) I get an Exception: java.lang.ClassCastException: Percent cannot be cast to Product. It seems like Percent is chosen as a 'default' subclass. Why is that and how can I get an object that is a Product?

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  • free RSS feed caching

    - by cherouvim
    Hello I've got an application which serves an rss feed of headlines and I need to provide this rss feed to other consumers. I don't want to provide the rss directly from my server though, due to limited server resources, so I need to proxy (cache) it through some service which will handle the load. Assuming the rss feed URL of my application is http://example.com/rss I initially provided my consumers with the url http://ajax.googleapis.com/ajax/services/feed/load?v=1.0&q=http%3A%2F%2Fexample.com%2Frss which solved my server load problem but introduced a liveness problem. The headlines are minutes to hours late from the actual feed (haven't exactly measured how much late). I've also tried distributing through feedburner so the url became something like http://feeds.feedburner.com/example123?format=xml but the liveness problem still exists. Is there a public and free solution for this problem? Anything below 5 minutes of liveness delay would be totally acceptable. thanks

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  • android httpurlconnection [closed]

    - by user620451
    hi im new android developer i am trying to login to my asterisk server passing my username and password it works good but when i am trying to request anther url to the server after login i get access denied and i now the problem because the login connection has disconnected so i want a way to request to urls the first one is login to the server and the second is to do something else after login please help and thx anyway this is a part of my code i want to request this 2 url url1="http://192.168.1.7:8088/rawman?action=login&username=admin&secret=admin" url2="http://192.168.1.5:8088/rawman?action=updateconfig&reload=yes&srcfilename=users.conf&dstfilename=users.conf&Action-000000=newcat&Cat-000000=6001&Var-000000=&Value-000000=" public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); tv1 = (TextView) this.findViewById(R.id.display); ed1 = (EditText) this.findViewById(R.id.editText); bt1 = (Button) this.findViewById(R.id.submit); bt1.setOnClickListener(new OnClickListener() { public void onClick(View view) { { try{ ServerRequest(url1); ServerRequest(url2); } catch(Exception e) { Log.v("Exception", "Exception:"+e.getMessage()); } } } }); } public String ServerRequest(String serverString) throws MalformedURLException, IOException { String newFeed=serverString; StringBuilder response = new StringBuilder(); Log.v("server","server url:"+newFeed); URL url = new URL(newFeed); HttpURLConnection httpconn = (HttpURLConnection) url.openConnection(); if(httpconn.getResponseCode()==HttpURLConnection.HTTP_OK) { BufferedReader input = new BufferedReader( new InputStreamReader(httpconn.getInputStream()), 8192); String strLine = null; while ((strLine = input.readLine()) != null) { response.append(strLine); } input.close(); } tv1.settext(response); return response.toString(); }

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  • jQuery autosuggest example

    - by RUtt
    I need to implement an "autosuggest" feature on our site but it needs to re-query the on every keystroke after a certain number of keys (like every character after 2 it would need to query again). So the result isn't a limiting search. For example, the autocomplete plugins I've seen work like the following: [looking for a county] 1. customer types 'CA' and the first result would return 'Canada', 'Cambodia', and 'Camaroon' 2. customer continues to type and hits 'M' the new results would query within the only the existing 3 results (producing results of just 'Cambodia' and 'Camaroon') I need a solution that would be the equivalent of querying my datasource on each keystroke. I already have the ajax call that will return my results based on the "typed" params. For example (in the above example), it would need to make an ajax call passing 'ca' first and if the customer kept typing passing 'can' on the 3 character and so forth. Thanks.

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  • Is there a better way to write named-pipes in F#?

    - by Niran
    Hi I am new to F#. I am trying to communicate with java from F# using named pipe. The code below works but I am not sure if there is a better way to do this (I know the infinite loop is a bad idea but this is just a proof of concept) if anyone have any idea to improve this code please post your comments. Thanks in advance Niran open System.IO open System.IO.Pipes exception OuterError of string let continueLooping = true while continueLooping do let pipeServer = new NamedPipeServerStream("testpipe", PipeDirection.InOut, 4) printfn "[F#] NamedPipeServerStream thread created." //wait for connection printfn "[F#] Wait for a client to connect" pipeServer.WaitForConnection() printfn "[F#] Client connected." try // Stream for the request. let sr = new StreamReader(pipeServer) // Stream for the response. let sw = new StreamWriter(pipeServer) sw.AutoFlush <- true; // Read request from the stream. let echo = sr.ReadLine(); printfn "[F#] Request message: %s" echo // Write response to the stream. sw.WriteLine("[F#]: " + echo) pipeServer.Disconnect() with | OuterError(str) -> printfn "[F#]ERROR: %s" str printfn "[F#] Client Closing." pipeServer.Close()

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  • Problems using the Razor model when creating my knockout ViewModel

    - by Emil Kantis
    I'm having problems with using the Model in a javascript call when setting up my knockout VM.. @model List<AdminGui.Models.Domain> <script src="http://ajax.aspnetcdn.com/ajax/knockout/knockout-2.2.1.js" type="text/javascript"></script> <script type="text/javascript"> function ViewModel() { var self = this; self.domains = ko.observableArray( ko.utils.arrayMap(@Model, function(item) { return new Domain(item.guid, item.description, item.namespaces); })); } I get a syntax error on @Model in the ko.utils.arrayMap call. I suspect it might be my Razor-fu that is lacking... :)

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  • what is the use of creating proxy for an webservice

    - by prince23
    hi, i have an webserivce written where i do an insertion opertion to DB. path :http://localhost:1838/Ajax/WebService.asmx?wsdl.name of the webservice is localhost i have added webservice for the project now on button click event i try to call this webserice like this localhost obj= new localhost(); obj.insert(); now i am able to do the insertion operation fine. but i wanted to create an proxy for the webservice so wat is the use of it doing like tat? when i run this command in my command prompt in vs wsdl /out:myProxyClass.cs http://localhost:1838/Ajax/WebService.asmx?WSDL i get an error unable to connect the remote server. no connection would be made because the target machine actively refused it looking forward for an solution any help would great thank you

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  • RequestBuilder timeouts and browser connection limits per domain.

    - by WesleyJohnson
    This is specifically about GWT's RequestBuilder, but should apply to general XHR as well. My company is having me build a near realtime chat application over HTTP. Yes, I do realize there are better ways to do chat aplications, but this is what they want. Eventually we want it working on the iPad/iPhone as well so flash is out, which rules out websockets and comet as well, I think? Anyway, I'm running into issues were I've set GWT's RequestBuilder timeout to 10 seconds and we get very random and sporadic timeouts. We've got error handling and emailing on the server side and never get any errors, which suggests the underlying XHR request that RequestBuilder is built on, never gets to the server and times out after 10 seconds. We're using these request to poll the server for new messages rather often and also for sending new messages to the server and also polling (less frequently) for other parts of application. What I'm afraid of is that we're running into the browsers limit on concurrent connections to the same domain (2 for IE by default?). Now my question is - If I construct a RequestBuilder and call it's send() method and the browser blocks it from sending until one of the 2 connections per domain is free, does the timeout still start while the request is being blocked or will it not start until the browser actually releases the underlying XHR? I hope that's clear, if not please let me know and I'll try to explain more.

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