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  • Continuing education with Visual Basic 9

    - by TSSH
    I am completely new to programming and starting my education with visual basic 9 and SQL. I have read Visual Basic, in easy steps, 2nd edition by Mike Mcgrath. Although it was very easy to understand, it only gave me an introduction to learning VB. I'm looking for something more in depth, albeit for a beginner. I've read through the questions with a VB and book tag. Unfortunately, most of what I've found here references VB 6 and VB 8. Any recommendations? I cannot afford to create a library or college at the moment. So, I need to make sure that what I do buy counts. Thanks for any suggestions!

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  • python foursquare - SSL3 certificate verify failed

    - by user1814277
    I'm trying to make a userless request to the Foursquare API using Mike Lewis' Python wrapper - https://github.com/mLewisLogic/foursquare: client = foursquare.Foursquare(client_id=Client_ID, client_secret=Client_Secret) categs = client.venues.categories() Intermittently, I get a "Error connecting to Foursquare API" msg. Running a logger to catch a more detailed message produces: "SSL routines:SSL3_GET_SERVER_CERTIFICATE:certificate verify failed" This didn't use to happen and occurs both on my local Windows development machine and on a server running ubuntu. Am I missing something basic here about security certificates? The problem is intermittent and sometimes just leaving it a minute and retrying fixes the problem temporarily. I've downloaded the latest 20120716 version of the wrapper although in the code for init.py it still says API_VERSION = '20120608'. I'm using Python 2.73 and have also signed up for the Foursquare API key, using the id and secret in the above code. I listed the urls, using my local IP:8000 and tried using separate keys for the local and dev machines but this seems to make no difference. Help much appreciated. Thanks.

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  • being able to solve google code jam problem sets

    - by JPro
    This is not a homework question, but rather my intention to know if this is what it takes to learn programming. I keep loggin into TopCoder not to actually participate but to get the basic understand of how the problems are solved. But to my knowledge I don't understand what the problem is and how to translate the problem into an algorithm that can solve it. Just now I happen to look at ACM ICPC 2010 World Finals which is being held in china. The teams were given problem sets and one of them is this: Given at most 100 points on a plan with distinct x-coordinates, find the shortest cycle that passes through each point exactly once, goes from the leftmost point always to the right until it reaches the rightmost point, then goes always to the left until it gets back to the leftmost point. Additionally, two points are given such that the the path from left to right contains the first point, and the path from right to left contains the second point. This seems to be a very simple DP: after processing the last k points, and with the first path ending in point a and the second path ending in point b, what is the smallest total length to achieve that? This is O(n^2) states, transitions in O(n). We deal with the two special points by forcing the first path to contain the first one, and the second path contain the second one. Now I have no idea what I am supposed to solve after reading the problem set. and there's an other one from google code jam: Problem In a big, square room there are two point light sources: one is red and the other is green. There are also n circular pillars. Light travels in straight lines and is absorbed by walls and pillars. The pillars therefore cast shadows: they do not let light through. There are places in the room where no light reaches (black), where only one of the two light sources reaches (red or green), and places where both lights reach (yellow). Compute the total area of each of the four colors in the room. Do not include the area of the pillars. Input * One line containing the number of test cases, T. Each test case contains, in order: * One line containing the coordinates x, y of the red light source. * One line containing the coordinates x, y of the green light source. * One line containing the number of pillars n. * n lines describing the pillars. Each contains 3 numbers x, y, r. The pillar is a disk with the center (x, y) and radius r. The room is the square described by 0 = x, y = 100. Pillars, room walls and light sources are all disjoint, they do not overlap or touch. Output For each test case, output: Case #X: black area red area green area yellow area Is it required that people who program should be should be able to solve these type of problems? I would apprecite if anyone can help me interpret the google code jam problem set as I wish to participate in this years Code Jam to see if I can do anthing or not. Thanks.

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  • Why are there 3 conflicting OpenCV camera calibration formulas?

    - by John
    I'm having a problem with OpenCV's various parameterization of coordinates used for camera calibration purposes. The problem is that three different sources of information on image distortion formulae apparently give three non-equivalent description of the parameters and equations involved: (1) In their book "Learning OpenCV…" Bradski and Kaehler write regarding lens distortion (page 376): xcorrected = x * ( 1 + k1 * r^2 + k2 * r^4 + k3 * r^6 ) + [ 2 * p1 * x * y + p2 * ( r^2 + 2 * x^2 ) ], ycorrected = y * ( 1 + k1 * r^2 + k2 * r^4 + k3 * r^6 ) + [ p1 * ( r^2 + 2 * y^2 ) + 2 * p2 * x * y ], where r = sqrt( x^2 + y^2 ). Assumably, (x, y) are the coordinates of pixels in the uncorrected captured image corresponding to world-point objects with coordinates (X, Y, Z), camera-frame referenced, for which xcorrected = fx * ( X / Z ) + cx and ycorrected = fy * ( Y / Z ) + cy, where fx, fy, cx, and cy, are the camera's intrinsic parameters. So, having (x, y) from a captured image, we can obtain the desired coordinates ( xcorrected, ycorrected ) to produced an undistorted image of the captured world scene by applying the above first two correction expressions. However... (2) The complication arises as we look at OpenCV 2.0 C Reference entry under the Camera Calibration and 3D Reconstruction section. For ease of comparison we start with all world-point (X, Y, Z) coordinates being expressed with respect to the camera's reference frame, just as in #1. Consequently, the transformation matrix [ R | t ] is of no concern. In the C reference, it is expressed that: x' = X / Z, y' = Y / Z, x'' = x' * ( 1 + k1 * r'^2 + k2 * r'^4 + k3 * r'^6 ) + [ 2 * p1 * x' * y' + p2 * ( r'^2 + 2 * x'^2 ) ], y'' = y' * ( 1 + k1 * r'^2 + k2 * r'^4 + k3 * r'^6 ) + [ p1 * ( r'^2 + 2 * y'^2 ) + 2 * p2 * x' * y' ], where r' = sqrt( x'^2 + y'^2 ), and finally that u = fx * x'' + cx, v = fy * y'' + cy. As one can see these expressions are not equivalent to those presented in #1, with the result that the two sets of corrected coordinates ( xcorrected, ycorrected ) and ( u, v ) are not the same. Why the contradiction? It seems to me the first set makes more sense as I can attach physical meaning to each and every x and y in there, while I find no physical meaning in x' = X / Z and y' = Y / Z when the camera focal length is not exactly 1. Furthermore, one cannot compute x' and y' for we don't know (X, Y, Z). (3) Unfortunately, things get even murkier when we refer to the writings in Intel's Open Source Computer Vision Library Reference Manual's section Lens Distortion (page 6-4), which states in part: "Let ( u, v ) be true pixel image coordinates, that is, coordinates with ideal projection, and ( u ~, v ~ ) be corresponding real observed (distorted) image coordinates. Similarly, ( x, y ) are ideal (distortion-free) and ( x ~, y ~ ) are real (distorted) image physical coordinates. Taking into account two expansion terms gives the following: x ~ = x * ( 1 + k1 * r^2 + k2 * r^4 ) + [ 2 p1 * x * y + p2 * ( r^2 + 2 * x^2 ) ] y ~ = y * ( 1 + k1 * r^2 + k2 * r^4 ] + [ 2 p2 * x * y + p2 * ( r^2 + 2 * y^2 ) ], where r = sqrt( x^2 + y^2 ). ... "Because u ~ = cx + fx * u and v ~ = cy + fy * v , … the resultant system can be rewritten as follows: u ~ = u + ( u – cx ) * [ k1 * r^2 + k2 * r^4 + 2 * p1 * y + p2 * ( r^2 / x + 2 * x ) ] v ~ = v + ( v – cy ) * [ k1 * r^2 + k2 * r^4 + 2 * p2 * x + p1 * ( r^2 / y + 2 * y ) ] The latter relations are used to undistort images from the camera." Well, it would appear that the expressions involving x ~ and y ~ coincided with the two expressions given at the top of this writing involving xcorrected and ycorrected. However, x ~ and y ~ do not refer to corrected coordinates, according to the given description. I don't understand the distinction between the meaning of the coordinates ( x ~, y ~ ) and ( u ~, v ~ ), or for that matter, between the pairs ( x, y ) and ( u, v ). From their descriptions it appears their only distinction is that ( x ~, y ~ ) and ( x, y ) refer to 'physical' coordinates while ( u ~, v ~ ) and ( u, v ) do not. What is this distinction all about? Aren't they all physical coordinates? I'm lost! Thanks for any input!

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  • CSG operations on implicit surfaces with marching cubes

    - by Mads Elvheim
    I render isosurfaces with marching cubes, (or perhaps marching squares as this is 2D) and I want to do set operations like set difference, intersection and union. I thought this was easy to implement, by simply choosing between two vertex scalars from two different implicit surfaces, but it is not. For my initial testing, I tried with two spheres, and the set operation difference. i.e A - B. One sphere is moving and the other one is stationary. Here's the approach I tried when picking vertex scalars and when classifying corner vertices as inside or outside. The code is written in C++. OpenGL is used for rendering, but that's not important. Normal rendering without any CSG operations does give the expected result. void march(const vec2& cmin, //min x and y for the grid cell const vec2& cmax, //max x and y for the grid cell std::vector<vec2>& tri, float iso, float (*cmp1)(const vec2&), //distance from stationary sphere float (*cmp2)(const vec2&) //distance from moving sphere ) { unsigned int squareindex = 0; float scalar[4]; vec2 verts[8]; /* initial setup of the grid cell */ verts[0] = vec2(cmax.x, cmax.y); verts[2] = vec2(cmin.x, cmax.y); verts[4] = vec2(cmin.x, cmin.y); verts[6] = vec2(cmax.x, cmin.y); float s1,s2; /********************************** ********For-loop of interest****** *******Set difference between **** *******two implicit surfaces****** **********************************/ for(int i=0,j=0; i<4; ++i, j+=2){ s1 = cmp1(verts[j]); s2 = cmp2(verts[j]); if((s1 < iso)){ //if inside sphere1 if((s2 < iso)){ //if inside sphere2 scalar[i] = s2; //then set the scalar to the moving sphere } else { scalar[i] = s1; //only inside sphere1 squareindex |= (1<<i); //mark as inside } } else { scalar[i] = s1; //inside neither sphere } } if(squareindex == 0) return; /* Usual interpolation between edge points to compute the new intersection points */ verts[1] = mix(iso, verts[0], verts[2], scalar[0], scalar[1]); verts[3] = mix(iso, verts[2], verts[4], scalar[1], scalar[2]); verts[5] = mix(iso, verts[4], verts[6], scalar[2], scalar[3]); verts[7] = mix(iso, verts[6], verts[0], scalar[3], scalar[0]); for(int i=0; i<10; ++i){ //10 = maxmimum 3 triangles, + one end token int index = triTable[squareindex][i]; //look up our indices for triangulation if(index == -1) break; tri.push_back(verts[index]); } } This gives me weird jaggies: It looks like the CSG operation is done without interpolation. It just "discards" the whole triangle. Do I need to interpolate in some other way, or combine the vertex scalar values? I'd love some help with this. A full testcase can be downloaded HERE

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  • DLL export of a static function

    - by Begbie00
    Hi all - I have the following static function: static inline HandVal StdDeck_StdRules_EVAL_N( StdDeck_CardMask cards, int n_cards ) Can I export this function in a DLL? If so, how? Thanks, Mike Background information: I'm doing this because the original source code came with a VS project designed to compile as a static (.lib) library. In order to use ctypes/Python, I'm converting the project to a DLL. I started a VS project as a DLL and imported the original source code. The project builds into a DLL, but none of the functions (including functions such as the one listed above) are exported (as confirmed by both the absence of dllexport in the source code and tools such as DLL Export Viewer). I tried to follow the general advice here (create an exportable wrapper function within the header) to no avail...functions still don't appear to be exported.

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  • Rails routing to XML/JSON without views gone mad

    - by John Schulze
    I have a mystifying problem. In a very simple Ruby app i have three classes: Drivers, Jobs and Vehicles. All three classes only consist of Id and Name. All three classes have the same #index and #show methods and only render in JSON or XML (this is in fact true for all their CRUD methods, they are identical in everything but name). There are no views. For example: def index @drivers= Driver.all respond_to do |format| format.js { render :json => @drivers} format.xml { render :xml => @drivers} end end def show @driver = Driver.find(params[:id]) respond_to do |format| format.js { render :json => @driver} format.xml { render :xml => @driver} end end The models are similarly minimalistic and only contain: class Driver< ActiveRecord::Base validates_presence_of :name end In routes.rb I have: map.resources :drivers map.resources :jobs map.resources :vehicles map.connect ':controller/:action/:id' map.connect ':controller/:action/:id.:format' I can perform POST/create, GET/index and PUT/update on all three classes and GET/read used to work as well until I installed the "has many polymorphs" ActiveRecord plugin and added to environment.rb: require File.join(File.dirname(__FILE__), 'boot') require 'has_many_polymorphs' require 'active_support' Now for two of the three classes I cannot do a read any more. If i go to localhost:3000/drivers they all list nicely in XML but if i go to localhost:3000/drivers/3 I get an error: Processing DriversController#show (for 127.0.0.1 at 2009-06-11 20:34:03) [GET] Parameters: {"id"=>"3"} [4;36;1mDriver Load (0.0ms)[0m [0;1mSELECT * FROM "drivers" WHERE ("drivers"."id" = 3) [0m ActionView::MissingTemplate (Missing template drivers/show.erb in view path app/views): app/controllers/drivers_controller.rb:14:in `show' ...etc This is followed a by another unexpected error: Processing ApplicationController#show (for 127.0.0.1 at 2009-06-11 21:35:52)[GET] Parameters: {"id"=>"3"} NameError (uninitialized constant ApplicationController::AreaAccessDenied): ...etc What is going on here? Why does the same code work for one class but not the other two? Why is it trying to do a #view on the ApplicationController? I found that if I create a simple HTML view for each of the three classes these work fine. To each class I add: format.html # show.html.erb With this in place, going to localhost:3000/drivers/3 renders out the item in HTML and I get no errors in the log. But if attach .xml to the URL it again fails for two of the classes (with the same error message as before) while one will output XML as expected. Even stranger, on the two failing classes, when adding .js to the URL (to trigger JSON rendering) I get the HTML output instead! Is it possible this has something to do with the "has many polymorphs" plugin? I have heard of people having routing issues after installing it. Removing "has many polymorphs" and "active support" from environment.rb (and rebooting the sever) seems to make no difference whatsoever. Yet my problems started after it was installed. I've spent a number of hours on this problem now and am starting to get a little desperate, Google turns up virtually no information which makes me suspect I must have missed something elementary. Any enlightenment or hint gratefully received! JS

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  • NSFetchedResultsControllerDelegate in a second view controller (not firing?)

    - by MTBPatriot
    I am running into an issue similar to the one described here: http://stackoverflow.com/questions/1319940/nsfetchedresultscontrollerdelegate-not-firing (the delegate for my NSFetchedResultsControllerDelegate are not being called on my second view controller) I can't seem to get the proposed solutions to work. I have a main view that loads information from Core Data just fine, but when it pushes a separate controller (and passes the managed object to it), the delegate methods won't fire. I've read about 'mergeChangesFromContextDidSaveNotification' but I don't understand how to synchronize the two manage objects and/or get the delegate methods to be called. Any help would be greatly appreciated. Thank you, Mike

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  • Query not returning rows in a table that don't have corresponding values in another [associative] ta

    - by Obay
    I have Table: ARTICLES ID | CONTENT --------------- 1 | the quick 2 | brown fox 3 | jumps over 4 | the lazy Table: WRITERS ID | NAME ---------- 1 | paul 2 | mike 3 | andy Table: ARTICLES_TO_WRITERS ARTICLE_ID | WRITER_ID ----------------------- 1 | 1 2 | 2 3 | 3 To summarize, article 4 has no writer. So when I do a "search" for articles with the word "the": SELECT a.id, a.content, w.name FROM articles a, writers w, articles_to_writers atw WHERE a.id=atw.article_id AND w.id=atw.writer_id AND content LIKE '%the%' article 4 does not show up in the result: ID | CONTENT | NAME ----------------------- 1 | the quick | paul How do I make article 4 still appear in the results even though it has no writers?

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  • IE7 li ul bug on dropdown menu

    - by Berns
    hoping one of you guys can help me please. I have a basic list menu with two dropdowns. This all works fine on all browsers except IE6 and IE7. Please take a look at my markup. <nav> <ul id="topNav" ><li id="topNavFirst"><a href="../about/about.php" id="aboutNav">About Us</a></li ><li id="topNavSecond"><a href="../people/our-people.php" id="peopleNav">Our People</a ><ul id="subList1"><li><a href="../people/mike-hadfield.php">Mike Hadfield</a></li ><li><a href="../people/karen-sampson.php">Karen Sampson</a></li ><li><a href="../people/milhana-farook.php">Milhana Farook</a></li ><li><a href="../people/kim-crook.php">Kim Crook</a></li ><li><a href="../people/amanda-lynch.php">Amanda Lynch</a></li ><li><a href="../people/gideon-scott.php">Gideon Scott</a></li ><li><a href="../people/paul-fuller.php">Paul Fuller</a></li ><li><a href="../people/peter-chaplain.php">Peter Chaplain</a></li ><li><a href="../people/laura-hutley.php">Laura Hutley</a></li ></ul ></li ><li id="topNavThird"><a href="../services/our-services.php" id="servicesNav">Our Services</a ><ul id="subList2"><li><a href="../services/company-and-commercial.php">Company &amp; Commercial</a></li ><li><a href="../services/employment.php">Employment</a></li ><li><a href="../services/civil-litigation.php">Civil Litigation</a></li ><li><a href="../services/debt-recovery.php">Debt Recovery</a></li ><li><a href="../services/conveyancing.php">Conveyancing</a></li ><li><a href="../services/commercial-property.php">Commerical Property</a></li ><li><a href="../services/wills-and-probate.php">Wills &amp; Probate</a></li ><li><a href="../services/family.php">Matrimonial &amp; Family</a></li ></ul ></li ><li><a href="../news/news.php" id="newsNav">News</a></li ><li><a href="../careers/careers.php" id="careersNav">Careers</a></li ><li><a href="../contact/contact.php" id="contactNav">Contact</a></li ></ul><!-- /topNav --> </nav>? and the css a {text-decoration:none;} #topNav { float:right; height:30px; margin:0; font-size:12px; } #topNav li { display:inline; float:left; list-style:none; color:#666; border-left: 1px solid #666; padding: 0 3px 0 3px; position:relative; } #topNav ul a { white-space:nowrap; } #topNav li a:hover { border-bottom:2px solid #369; } #topNavSecond a:hover { border-bottom:2px solid transparent !important; } #topNavFirst { border-left: 1px solid transparent !important; } /*****OUR-PEOPLE DROPDOWN*****/ #topNav ul{ background:#fff; border:1px solid #666; border-top:0px solid transparent; border-bottom:2px solid #666; list-style:none; position:absolute; left:-9999px; width:100px; text-align:left; padding:5px 0 5px 0px; margin:0 0 0 -4px; z-index:10; -webkit-box-shadow: 1px 1px 1px #666; -moz-box-shadow: 1px 1px 1px #666; box-shadow: 1px 1px 1px #666; vertical-align: bottom; } #topNav ul li{ display:block; border-left:0px; margin-bottom: 0px; padding:0; vertical-align: bottom; } #topNav ul a{ padding:0 0 0 5px; } #topNav li:hover ul{ left:auto; } #topNav li:hover a { color:#369; } #topNav li:hover ul a{ text-decoration:none; color:#666; } #topNav li:hover ul li a:hover{ color:#fff;; width:100%; border-bottom:0px solid transparent !important; } #topNav ul li:hover { background:#369; display: block; } #topNav ul li a { display: block; padding:0 0 0 4px; } /************/ /*****OUR-SERVICES DROPDOWN*****/ #topNavThird a:hover { border-bottom:2px solid transparent !important; } #topNavThird ul{ /*background:#fff url(images/service-ul-bg.png) no-repeat;*/ width:135px !important; /*margin-left:120px !important;*/ }? here it is working perfectly http://jsfiddle.net/BcWd9/ here is a screen shot of how it looks in IE7. hadfield.andymcnallydesign.co.uk/images/ie7-error.jpg as you can see the ul is appearing to the right of the li and not the left and it is overlaying the top list. I've tried removing white space, but no luck. Any ideas? If one of you can help it would be much appreciated.

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  • Calculating negative fractions in Objective C

    - by Mark Reid
    I've been coding my way through Steve Kochan's Programming in Objective-C 2.0 book. I'm up to an exercise in chapter 7, ex 4, in case anyone has the book. The question posed by the exercise it will the Fraction class written work with negative fractions such as -1/2 + -2/3? Here's the implementation code in question - @implementation Fraction @synthesize numerator, denominator; -(void) print { NSLog(@"%i/%i", numerator, denominator); } -(void) setTo: (int) n over: (int) d { numerator = n; denominator = d; } -(double) convertToNum { if (denominator != 0) return (double) numerator / denominator; else return 1.0; } -(Fraction *) add: (Fraction *) f { // To add two fractions: // a/b + c/d = ((a * d) + (b * c)) / (b * d) // result will store the result of the addition Fraction *result = [[Fraction alloc] init]; int resultNum, resultDenom; resultNum = (numerator * f.denominator) + (denominator * f.numerator); resultDenom = denominator * f.denominator; [result setTo: resultNum over: resultDenom]; [result reduce]; return result; } -(Fraction *) subtract: (Fraction *) f { // To subtract two fractions: // a/b - c/d = ((a * d) - (b * c)) / (b * d) // result will store the result of the addition Fraction *result = [[Fraction alloc] init]; int resultNum, resultDenom; resultNum = numerator * f.denominator - denominator * f.numerator; resultDenom = denominator * f.denominator; [result setTo: resultNum over: resultDenom]; [result reduce]; return result; } -(Fraction *) multiply: (Fraction *) f { // To multiply two fractions // a/b * c/d = (a*c) / (b*d) // result will store the result of the addition Fraction *result = [[Fraction alloc] init]; int resultNum, resultDenom; resultNum = numerator * f.numerator; resultDenom = denominator * f.denominator; [result setTo: resultNum over: resultDenom]; [result reduce]; return result; } -(Fraction *) divide: (Fraction *) f { // To divide two fractions // a/b / c/d = (a*d) / (b*c) // result will store the result of the addition Fraction *result = [[Fraction alloc] init]; int resultNum, resultDenom; resultNum = numerator * f.denominator; resultDenom = denominator * f.numerator; [result setTo: resultNum over: resultDenom]; [result reduce]; return result; } -(void) reduce { int u = numerator; int v = denominator; int temp; while (v != 0) { temp = u % v; u = v; v = temp; } numerator /= u; denominator /= u; } @end My question to you is will it work with negative fractions and can you explain how you know? Part of the issue is I don't know how to calculate negative fractions myself so I'm not too sure how to know. Many thanks.

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  • How can I store data in a table as a trie? (SQL Server)

    - by Matt
    Hi, To make things easier, the table contains all the words in the English dictionary. What I would like to do is be able to store the data as a trie. This way I can traverse the different branches of the trie and return the most relevant result. First, how do I store the data in the table as a trie? Second, how do I traverse the tree? If it helps at all, the suggestion in this previous question is where this question was sparked from. Please make sure it's SQL we're talking about. I understood the Mike Dunlavey's C implementation because of pointers but can't see how this part (The trie itself) works in SQL. Thanks, Matt

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  • Need some tips on my SQL script?

    - by Nano HE
    Hi I plan to create a tale to store the race result like this, Place RaceNumber Gender Name Result 12 0112 Male Mike Lee 1:32:40 16 0117 Female Rose Marry 2:20:40 I confused at the items type definiation. Q1.I am not sure the result can be set to varchar(32) or other type? Q2. and for racenumber, between int(11) and varchar(11), which one is better? Q3. Can I use `UNIQUE KEY` like my way? Q4. Do I need split name to firstName and lastName in my DB table? DROP TABLE IF EXISTS `race_result`; CREATE TABLE IF NOT EXISTS `race_result` ( `id` int(11) NOT NULL auto_increment, `racenumber` int(11) NOT NULL, `gender` enum('male','female') NOT NULL, `name` varchar(16) NOT NULL, `result` varchar(32) NOT NULL, PRIMARY KEY (`id`), UNIQUE KEY `racenumber` (`racenumber`,`id`) ) ENGINE=MyISAM AUTO_INCREMENT=3 DEFAULT CHARSET=utf8 AUTO_INCREMENT=3;

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  • Keyboard for programming

    - by exhuma
    This may seem a bit a tangential topic. It's not directly related to actual code, but is important for our line of work nevertheless. Over the years, I've switched keyboards a few times. All of them had slightly different key layouts. And I'm not talking about the language/locale layout, but the physical layout! Why not the locale layout? Well, quite frankly, that's easy to change via software. I personally have a German keyboard but have it set to the UK layout. Why? It's quite hard to find different layouts in the shops where I live. Even ordering is not always easy in the shops. So that leaves me with Internet shops. But I prefer to "test" my keyboards before buying. The most notable changes are: Mangled "Home Key Block" I've seen this first on a Logitech keyboard, but it may have originated elsewhere. Shape of the "Enter" key I've seen three different cases so far: Two lines high, wider at the top Two lines high, wider at the bottom One line high Shape of the Backspace button I've seen two types so far: One "character" wide Two "characters" wide OS Keys For Macs, you have the Option and Command buttons, for Windows you have the Windows and Context Menu buttons. Cherry even produced a Linux keyboard once (unfortunately I cannot find many details except news results). I assume a dedicated Linux keyboard would sport a Compose key and had the SysRq always labelled as well (note that some standard layouts do this already). Obviously... .. all these differences entail that some keys have to be moved around the board a lot. Which means, if you are used to one and have to work on another one, you happen to hit the wrong keys quite often. As it happens, this is much more annoying for programmers as it is for people who write texts. Mainly because the keys which are moved around are special character keys, often used in programming. Often these hardware layouts depend also indirectly on where you buy the keyboards. Honestly, I haven't seen a keyboard with a one-line "Enter" key in Germany, nor Luxembourg. I may just have missed it but that's how it looks to me at least. A survey I've seen some attempts at surveys in the style "which keyboard is best for programming". But they all - in my opinion - are not using comparable sets. So I was wondering if it was possible to concoct a survey taking the above criteria into account. But ignoring key dimensions that one would be a bit overkill I guess ;) From what I can see there are the following types of physical layout: Backspace: 2-characters wide Enter: 2-Lines, wider top Backspace: 2-characters wide Enter: 1-Line Backspace: 1-character wide Enter: 2-Lines, wider bottom Then there are the other possible permutations (home-key block, os-keys), which in total makes for quite a large list of categories. Now, I wonder... Would anyone be interested in such a survey? I personally would. Because I am looking for the perfect fit for me. If yes, then I could really use the help of anyone here to propose some models to include in the survey. Once I have some models for each category (I'd say at least 3 per category) I could go ahead and write up a survey, put it on-line and let the it collect data for a while. What do you think?

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  • best mysql field setup to have a "couples" member profile data saving.

    - by acctman
    Couple database profile entry, which would be the best way to save data. Also the data will be retrieved via php coding and if it could be down with one query code that would be ideal. Within the site_member table create multiple field for each field... ex: m_firstname1, m_firstname2, m_age1, m_age2, etc... Store the couple member data in one field each... and separate with a comma in the data field ex: m_firstname (Mike, Sherry) Create a separate table site_member_c duplicating the same fields that are in site_member table. This is roughly about 10 fields

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  • Hidden UIView Orientation Change / Layout problems

    - by gargantaun
    The Problem: I have two View Controllers loaded into a root View Controller. Both sub view layouts respond to orientation changes. I switch between the two views using [UIView transformationFromView:...]. Both sub views work fine on their own, but if... Views are swapped Orientation Changes Views are swapped again the View that was previously hidden has serious layout problems. The more I repeat these steps the worse the problem gets. Implementation Details I have three viewsControllers. MyAppViewController A_ViewController B_ViewController A & B ViewControllers have a background image each, and a UIWebView and an AQGridView respectively. To give you an example of how i'm setting it all up, here's the loadView method for A_ViewController... - (void)loadView { [super loadView]; // background image // Should fill the screen and resize on orientation changes UIImageView *bg = [[UIImageView alloc] initWithFrame:self.view.bounds]; bg.contentMode = UIViewContentModeCenter; bg.autoresizingMask = UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleWidth; bg.image = [UIImage imageNamed:@"fuzzyhalo.png"]; [self.view addSubview:bg]; // frame for webView // Should have a margin of 34 on all sides and resize on orientation changes CGRect webFrame = self.view.bounds; webFrame.origin.x = 34; webFrame.origin.y = 34; webFrame.size.width = webFrame.size.width - 68; webFrame.size.height = webFrame.size.height - 68; projectView = [[UIWebView alloc] initWithFrame:webFrame]; projectView.autoresizingMask = UIViewAutoresizingFlexibleHeight | UIViewAutoresizingFlexibleWidth; [self.view addSubview:projectView]; } For the sake of brevity, the AQGridView in B_ViewController is set up pretty much the same way. Now both these views work fine on their own. However, I use both of them in the AppViewController like this... - (void)loadView { [super loadView]; self.view.autoresizesSubviews = YES; [self setWantsFullScreenLayout:YES]; webView = [[WebProjectViewController alloc] init]; [self.view addSubview:webView.view]; mainMenu = [[GridViewController alloc] init]; [self.view addSubview:mainMenu.view]; activeView = mainMenu; [[NSNotificationCenter defaultCenter] addObserver:self selector:@selector(switchViews:) name:SWAPVIEWS object:nil]; } and I switch betweem the two views using my own switchView method like this - (void) switchViews:(NSNotification*)aNotification; { NSString *type = [aNotification object]; if ([type isEqualToString:MAINMENU]){ [UIView transitionFromView:activeView.view toView:mainMenu.view duration:0.75 options:UIViewAnimationOptionTransitionFlipFromRight completion:nil]; activeView = mainMenu; } if ([type isEqualToString:WEBVIEW]) { [UIView transitionFromView:activeView.view toView:webView.view duration:0.75 options:UIViewAnimationOptionTransitionFlipFromLeft completion:nil]; activeView = webView; } // These don't seem to do anything //[mainMenu.view setNeedsLayout]; //[webView.view setNeedsLayout]; } I'm fumbling my way through this, and I suspect a lot of what i've done is implemented incorrectly so please feel free to point out anything that should be done differently, I need the input. But my primary concern is to understand what's causing the layout problems. Here's two images which illustrate the nature of the layout issues... UPDATE: I just noticed that when the orientation is landscape, the transition flips vertically, when I would expect it to be horizontal. I don't know wether that's a clue as to what might be going wrong. Switch to the other view... change orientation.... switch back....

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  • javascript increment index in funciton

    - by mcgrailm
    I'm just trying to figure out how to create an index inside a function so I can keep track of the items its generating and I'm not sure how to do this seems like I should know this.. addLocation(options,location) funciton addLocation(options,location){ $('#list').append('<li class="location"><div>'+location.label+'</div>'+ '<input type="hidden" name="location['+x+'][lat]" value="'+location.lat+'" />'+ '<input type="hidden" name="location['+x+'][lon]" value="'+location.lon+'" />'+ '<input type="hidden" name="location['+x+'][loc]" value="'+location.loc+'" />'+ '<input type="hidden" name="location['+x+'][label]" value="'+location.label+'" />'+ '</li>'); } now normally you have a forloop to help you keep track of things but int this instance I'm not appending items in a loop and I keep getting an error saying x in undefined appreciate any help you can give thanks Mike

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  • HTML - Word Doc Images

    - by Michael
    Okay I have roughly 150 + pages of procedures all written in MS word. The person who wrote the procedures did an excellent job of recording the process how to perform specific tasks. This individual went though and created screen shots a MS word doc. There are approx 2 screen shots per page. So it is roughly 300 images and I do not want to recreate the wheel. Does anyone know a quick way of handling the images? The written portion is pretty straightforward but the images is what I am struggling with. Regards, Mike

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  • What's the best way to count unique visitors with Hadoop?

    - by beagleguy
    hey all, just getting started on hadoop and curious what the best way in mapreduce would be to count unique visitors if your logfiles looked like this... DATE siteID action username 05-05-2010 siteA pageview jim 05-05-2010 siteB pageview tom 05-05-2010 siteA pageview jim 05-05-2010 siteB pageview bob 05-05-2010 siteA pageview mike and for each site you wanted to find out the unique visitors for each site? I was thinking the mapper would emit siteID \t username and the reducer would keep a set() of the unique usersnames per key and then emit the length of that set. However that would be potentially storing millions of usernames in memory which doesn't seem right. Anyone have a better way? I'm using python streaming by the way thanks

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  • postgres counting one record twice if it meets certain criteria

    - by Dashiell0415
    I thought that the query below would naturally do what I explain, but apparently not... My table looks like this: id | name | g | partner | g2 1 | John | M | Sam | M 2 | Devon | M | Mike | M 3 | Kurt | M | Susan | F 4 | Stacy | F | Bob | M 5 | Rosa | F | Rita | F I'm trying to get the id where either the g or g2 value equals 'M'... But, a record where both the g and g2 values are 'M' should return two lines, not 1. So, in the above sample data, I'm trying to return: $q = pg_query("SELECT id FROM mytable WHERE ( g = 'M' OR g2 = 'M' )"); 1 1 2 2 3 4 But, it always returns: 1 2 3 4

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  • Mapped Stored Procedures in EF 1

    - by michael.lukatchik
    All, I'm using mapped Stored Procedures in EF 1. I've completed the following steps: 1) I've created my INSERT, UPDATE, and DELETE queries in SQL Server. 2) I've built the EDMX and imported the INSERT, UPDATE, and DELETE sprocs as part of my model. 3) I've set up a Stored Procedure Mapping on a table inside of my EDMX file. The INSERT, UPDATE, and DELETE sprocs were mapped accordingly. Using this approach, I would expect to rebuild the application (and mine builds successfully) and then see the Stored Procedures as available function names via my EDMX object, such as: _entities.InsertComment(..), _entities.UpdateComment(..), and _entities.DeleteComment(..) Intellisense is not picking these names up and I can't figure out why. If I perform these same steps using EF4, the function names are automatically picked up by Intellisense after adding the Stored Procedure Mappings. Is this a bug in EF1? Is there something else I should be doing? Thanks in advance, Mike

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  • calculated colum or stored proceedure or just php funcion needed ?

    - by mcgrailm
    I have an order table in MySQL database and is has a field/column which store the dattime stamp of when the order was placed and I need to calculate when the order must be shipped. I could probably figure out how to right a function to calculate the ship date and call that when ever needed but I think, not sure it may moake more sense to have the shipdate as a column that is somehow calculate in mysql. that being said I have Never used a stored procedure or created a calculated field. the later I think would be best but again not sure. I used to make calculated field all the time in FMP but I've gotten away from that program. if someone could point me in the right direction or tell me why it would be better to do it one way over another I'd appreciate it . thanks Mike

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  • Restart program from a certain line with an if statement?

    - by user1744093
    could anyone help me restart my program from line 46 if the user enters 1 (just after the comment where it states that the next code is going to ask the user for 2 inputs) and if the user enters -1 end it. I cannot think how to do it. I'm new to C# any help you could give would be great! class Program { static void Main(string[] args) { //Displays data in correct Format List<float> inputList = new List<float>(); TextReader tr = new StreamReader("c:/users/tom/documents/visual studio 2010/Projects/DistanceCalculator3/DistanceCalculator3/TextFile1.txt"); String input = Convert.ToString(tr.ReadToEnd()); String[] items = input.Split(','); Console.WriteLine("Point Latitude Longtitude Elevation"); for (int i = 0; i < items.Length; i++) { if (i % 3 == 0) { Console.Write((i / 3) + "\t\t"); } Console.Write(items[i]); Console.Write("\t\t"); if (((i - 2) % 3) == 0) { Console.WriteLine(); } } Console.WriteLine(); Console.WriteLine(); // Ask for two inputs from the user which is then converted into 6 floats and transfered in class Coordinates Console.WriteLine("Please enter the two points that you wish to know the distance between:"); string point = Console.ReadLine(); string[] pointInput = point.Split(' '); int pointNumber = Convert.ToInt16(pointInput[0]); int pointNumber2 = Convert.ToInt16(pointInput[1]); Coordinates distance = new Coordinates(); distance.latitude = (Convert.ToDouble(items[pointNumber * 3])); distance.longtitude = (Convert.ToDouble(items[(pointNumber * 3) + 1])); distance.elevation = (Convert.ToDouble(items[(pointNumber * 3) + 2])); distance.latitude2 = (Convert.ToDouble(items[pointNumber2 * 3])); distance.longtitude2 = (Convert.ToDouble(items[(pointNumber2 * 3) + 1])); distance.elevation2 = (Convert.ToDouble(items[(pointNumber2 * 3) + 2])); //Calculate the distance between two points const double PIx = 3.141592653589793; const double RADIO = 6371; double dlat = ((distance.latitude2) * (PIx / 180)) - ((distance.latitude) * (PIx / 180)); double dlon = ((distance.longtitude2) * (PIx / 180)) - ((distance.longtitude) * (PIx / 180)); double a = (Math.Sin(dlat / 2) * Math.Sin(dlat / 2)) + Math.Cos((distance.latitude) * (PIx / 180)) * Math.Cos((distance.latitude2) * (PIx / 180)) * (Math.Sin(dlon / 2) * Math.Sin(dlon / 2)); double angle = 2 * Math.Atan2(Math.Sqrt(a), Math.Sqrt(1 - a)); double ultimateDistance = (angle * RADIO); Console.WriteLine("The distance between your two points is..."); Console.WriteLine(ultimateDistance); //Repeat the program if the user enters 1, end the program if the user enters -1 Console.WriteLine("If you wish to calculate another distance type 1 and return, if you wish to end the program, type -1."); Console.ReadLine(); if (Convert.ToInt16(Console.ReadLine()) == 1); { //here is where I need it to repeat }

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  • Jquery to find a name on html page and add hyperlink

    - by mikejones12
    Here is my example: I have a a website that contains the following: <body> Jim Nebraska zipcode 65437 Tony lives in California his zipcode is 98708 </body> I would like to be able to search for zip codes on the page and wrap them with hyperlinks like: <body> Jim Nebraska zipcode <a href="/65437.htm">65437</a> Tony lives in California his zipcode is <a href="/65437.htm">98708</a> </body> Could I use a regex selector to find the string and then wrap the string, or replace it with the new hyperlink? I am new to Jquery and looking for someone to point me in the right direction. Thank you, Mike

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  • Turning A Stacked List into workable data

    - by BoSox
    In Excel I have a list of names that in the cell appear stacked, and I want each name in its own column. I was thinking Python may be a good way to do this? Example: Joe Smith John Hawk Mike Green Lauren Smith One cell will look exactly like that, with each name on its line within the cell but all of the names contained in the cell. I have 50 cells each with 1-20 stacked names and I want to put each name in its own cell on a given row. So, in my example all of those names would occupy the same row but each would have their own column. Any ideas?

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