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  • SQL query to retrieve financial year data grouped by the year

    - by mlevit
    Hi, I have a database with lets assume two columns (service_date & invoice_amount). I would like to create an SQL query that would retrieve and group the data for each financial year (July to June). I have two years of data so that is two financial years (i.e. 2 results). I know I can do this manually by creating an SQL query to group by month then run the data through PHP to create the financial year data but I'd rather have an SQL query. All ideas welcome. Thanks

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  • Multiple Refinement/Clusters in a single search

    - by Brain Teasers
    Suppose I have options of searching are 1.occupation 2.education 3.religion 4.caste 5.country and many more. when i perform this search, i can get easily calculate refinements. problem is i need to calculate refinements in a way that for individual refinement is calculated in a manner that all search parameter is considered expect the calculated refinement check on the left side ... even i have choose the profession area, still search refinements of this is coming.... same functionality if of all refinements.Please help.I use sphinx for searching seen this type of refinements in http://ww2.shaadi.com/search

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  • User has many computers, computers have many attributes in different tables, best way to JOIN?

    - by krismeld
    I have a table for users: USERS: ID | NAME | ---------------- 1 | JOHN | 2 | STEVE | a table for computers: COMPUTERS: ID | USER_ID | ------------------ 13 | 1 | 14 | 1 | a table for processors: PROCESSORS: ID | NAME | --------------------------- 27 | PROCESSOR TYPE 1 | 28 | PROCESSOR TYPE 2 | and a table for harddrives: HARDDRIVES: ID | NAME | ---------------------------| 35 | HARDDRIVE TYPE 25 | 36 | HARDDRIVE TYPE 90 | Each computer can have many attributes from the different attributes tables (processors, harddrives etc), so I have intersection tables like this, to link the attributes to the computers: COMPUTER_PROCESSORS: C_ID | P_ID | --------------| 13 | 27 | 13 | 28 | 14 | 27 | COMPUTER_HARDDRIVES: C_ID | H_ID | --------------| 13 | 35 | So user JOHN, with id 1 owns computer 13 and 14. Computer 13 has processor 27 and 28, and computer 13 has harddrive 35. Computer 14 has processor 27 and no harddrive. Given a user's id, I would like to retrieve a list of that user's computers with each computers attributes. I have figured out a query that gives me a somewhat of a result: SELECT computers.id, processors.id AS p_id, processors.name AS p_name, harddrives.id AS h_id, harddrives.name AS h_name, FROM computers JOIN computer_processors ON (computer_processors.c_id = computers.id) JOIN processors ON (processors.id = computer_processors.p_id) JOIN computer_harddrives ON (computer_harddrives.c_id = computers.id) JOIN harddrives ON (harddrives.id = computer_harddrives.h_id) WHERE computers.user_id = 1 Result: ID | P_ID | P_NAME | H_ID | H_NAME | ----------------------------------------------------------- 13 | 27 | PROCESSOR TYPE 1 | 35 | HARDDRIVE TYPE 25 | 13 | 28 | PROCESSOR TYPE 2 | 35 | HARDDRIVE TYPE 25 | But this has several problems... Computer 14 doesnt show up, because it has no harddrive. Can I somehow make an OUTER JOIN to make sure that all computers show up, even if there a some attributes they don't have? Computer 13 shows up twice, with the same harddrive listet for both. When more attributes are added to a computer (like 3 blocks of ram), the number of rows returned for that computer gets pretty big, and it makes it had to sort the result out in application code. Can I somehow make a query, that groups the two returned rows together? Or a query that returns NULL in the h_name column in the second row, so that all values returned are unique? EDIT: What I would like to return is something like this: ID | P_ID | P_NAME | H_ID | H_NAME | ----------------------------------------------------------- 13 | 27 | PROCESSOR TYPE 1 | 35 | HARDDRIVE TYPE 25 | 13 | 28 | PROCESSOR TYPE 2 | 35 | NULL | 14 | 27 | PROCESSOR TYPE 1 | NULL | NULL | Or whatever result that make it easy to turn it into an array like this [13] => [P_NAME] => [0] => PROCESSOR TYPE 1 [1] => PROCESSOR TYPE 2 [H_NAME] => [0] => HARDDRIVE TYPE 25 [14] => [P_NAME] => [0] => PROCESSOR TYPE 1

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  • selecting data from table based on date .

    - by mehdi
    i have database table like this +-------+--------------+----------+ | id | ip | date | +-------+--------------+----------+ | 505 |192.168.100.1 |2010-04-03| | 252 |192.168.100.5 |2010-03-03| | 426 |192.168.100.6 |2010-03-03| | 201 |192.168.100.7 |2010-04-03| | 211 |192.168.100.10|2010-04-03| +-------+--------------+----------+ how can i retirive data from this table where month=03 how to write sql to do that . select * from table where month=03 something like that .

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  • mysql_connect "bool $new_link = true" is very slow

    - by Mikk
    Hi, I'm using latest version of Xampp on 64bit Win7. The problem is that, when I use mysql_connect with "bool $new_link" set to true like so: mysql_connect('localhost', 'root', 'my_password', TRUE); script execution time increases dramatically (about 0,5 seconds per connection, and when I have 4 diffirent objects using different connections, it takes ~2 seconds). Is setting "bool $new_link" to true, generally a bad idea or could it just be some problem with my software configuration. Thank you.

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  • status update error (null field)

    - by ejah85
    hai guys... i .ve the problem that i cannot be recovered yet... i have one form where admin need to approve or reject the booking request... i've set the b_status field in table usage IN PROCESS default value... i want to update the b_status value BOOKING APPROVED when user click APPROVE button.. otherwise, the b_status will update the value as BOOKING REJECTED when user click on the REJECT button here's is the form code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM vehicle WHERE v_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr><td>&nbsp;</td></tr> <tr> <tr> <td width="200"><font face="Arial" size="2" font color="#000000">Registration Number </font></td> <td><select name="regno"> <option value="" selected>--Registration No--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['regno']; ?>"><?php echo $row['regno']; ?></option> <?php } ?> </select></td> <td><font face="Arial" size="2" font color="#000000">Reason</font></td> <td><textarea name="reason" rows="3" cols="50 "value = ""></textarea></td> </tr> <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM driver WHERE d_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr> <td><font face="Arial" size="2" font color="#000000">Driver</font></td> <td><select id = "d_name" name="d_name"> <option value="" selected>--Driver Name--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['d_name']; ?>"><?php echo $row['d_name']; ?></option> <?php } ?> </select></td> </tr> <tr> <?php mysql_close($db); ?> </table> <p></p> <center><input name="APPROVED" type="submit" id="APPROVED" value="APPROVED"> <input name="REJECT" type="submit" id="REJECT" value="REJECT"> </center> </div> </center> and this is the process page code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $bookingno=mysql_real_escape_string($_POST['bookingno']); $username=mysql_real_escape_string($_POST['username']); $name=mysql_real_escape_string($_POST['name']); $department=mysql_real_escape_string($_POST['department']); $g_date=mysql_real_escape_string($_POST['g_date']); $g_time=mysql_real_escape_string($_POST['g_time']); $r_date=mysql_real_escape_string($_POST['r_date']); $r_time=mysql_real_escape_string($_POST['r_time']); $destination=mysql_real_escape_string($_POST['destination']); $pass_num=mysql_real_escape_string($_POST['pass_num']); $trip_purpose=mysql_real_escape_string($_POST['trip_purpose']); $regno=mysql_real_escape_string($_POST['regno']); $d_name=mysql_real_escape_string($_POST['d_name']); $reason=mysql_real_escape_string($_POST['reason']); $b_status=mysql_real_escape_string($_POST['b_status']); $sql = "INSERT INTO `usage` VALUES('$bookingno','$username','$name','$department','$g_date','$g_time','$r_date','$r_time','$destination', '$pass_num','$trip_purpose','$regno','$d_name','$reason','$b_status')"; $query = "INSERT INTO `usage` VALUES b_status ='BOOKING APPROVED'"; $result = @mysql_query($query); $query1 = "UPDATE driver SET d_status ='OUT' WHERE '$d_name'=d_name"; $result1 = @mysql_query($query1); if(isset($_POST['APPROVED'])) { $query2 = "UPDATE `usage` SET b_status ='BOOKING APPROVED' WHERE '$b_status'='IN PROCESS'"; $result2 = @mysql_query($query2); } if (isset($_POST['REJECT'])) { $query3 = "UPDATE `usage` SET b_status ='BOOKING REJECTED' WHERE '$b_status'='IN PROCESS'"; $result3 = @mysql_query($query3); } //$result = mysql_query($sql) or die ("error!"); $result = mysql_query($sql) or trigger_error (mysql_error().' in '.$sql); i.ve the problem on the b_status field.. plz guys... help me ya :-)

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  • Inbreeding-immune database structure

    - by Nick Savage
    I have an application that requires a "simple" family tree. I would like to be able to perform queries that will give me data for an entire family given one id from a member in the family. I say simple because it does not need to take into account adoption or any other obscurities. The requirements for the application are as follows: Any two people will not be able to breed if they're from the same genetic line Needs to allow for the addition of new family lines (new people with no previous family) Need to be able to pull siblings, parents separately through queries I'm having trouble coming up with the proper structure for the database. So far I've come up with two solutions but they're not very reliable and will probably get out of hand quite quickly. Solution 1 involves placing a family_ids field on the people table and storing a list of unique family ids. Each time two people breed the lists are checked against each other to make sure no ids match and if everything checks out will merge the two lists and set that as the child's family_ids field. Example: Father (family_ids: (null)) breeds with Mother (family_ids: (213, 519)) -> Child (family_ids: (213, 519)) breeds with Random Person (family_ids: (813, 712, 122, 767)) -> Grandchild (family_ids: (213, 519, 813, 712, 122, 767)) And so on and so forth... The problem I see with this is the lists becoming unreasonably large as time goes on. Solution 2 uses cakephp's associations to declare: public $belongsTo = array( 'Father' => array( 'className' => 'User', 'foreignKey' => 'father_id' ), 'Mother' => array( 'className' => 'User', 'foreignKey' => 'mother_id' ) ); Now setting recursive to 2 will fetch the results of the mother and father, along with their mother and father, and so on and so forth all the way down the line. The problem with this route is that the data is in nested arrays and I'm unsure of how to efficiently work through the code. If anyone would be able to steer me in the direction of the most efficient way to handle what I want to achieve that would be tremendously helpful. Any and all help is greatly appreciated and I'll gladly answer any questions anyone has. Thanks a lot.

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  • mod rewrite, title slugs and htaccess

    - by chris
    I have been taken in to provide some seo guidance on a website which has been running since 2005. My problem is i want to use clean urls. The code that handles the url is hidden away in some class file.. and with over a few thousand lines of code its a struggle to rewrite it. So I'm think, I have gone through all the products and created a slug for them as a field in the product table. Is it possible to do something like an intermediate file for htaccess. Some thing like 1./clean-slug-comes-in/ 2.htaccess catches this and uses slug.php to find the relevant product id for the slug. 3.Then product.php?id=(ID.found.from.2) is loaded?

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  • How to construct this query? (Ordering by COUNT() and joining with users table)

    - by Andrew
    users table: id-user-other columns scores table: id-user_id-score-other columns They're are more than one rows for each user, but there's only two scores you can have. (0 or 1, == win or loss). So I want to output all the users ordered by the number of wins, and all the users ordered by the numbers of losses. I know how to do this by looping through each user, but I was wondering how to do it with one query. Any help is appreciated!

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  • How to make an id auto_increment from where it last left off after a record delete?

    - by Sammy
    This isn't that big of a deal but I was wondering if it can be done. Right now when I insert a new record, the id field which is auto_increment and set as primary key increases it's value by one: id | first_name | last_name ------------------------------ 1 | John | Smith 2 | Jane | Doe But if I delete record 2, the next one I insert is going to have an id of 3. Is there any way to make it have an id of 2 automatically (without having to manually insert it)?

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  • How phpmyadmin, php and everything else works?

    - by Tom
    Ok, I guess I got crazy, but really. How phpmyadmin works? Does it have his own phpmyadmin or what? And how php works? Why writing echo 'hello'; it returns hello in the browser? I am really interested on how these things really works, maybe you know any books or smth to figure it out? Thank you.

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  • cakePHP and GROUP BY

    - by Lizard
    I am trying to solve a hopefully simple problem here is the query I am trying produce: SELECT `categories`.*, COUNT(`entities`.id) FROM `categories` LEFT JOIN `entities` ON (`categories`.`id` = `entities`.`category_id`) GROUP BY `categories`.`id` I am really struggling to do this is in cakePHP 1.2 How would/should I go about doing this... (I am using 'Containable' if that helps) Thanks in advance

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  • How to exclude rows where matching join is in an SQL tree

    - by Greg K
    Sorry for the poor title, I couldn't think how to concisely describe this problem. I have a set of items that should have a 1-to-1 relationship with an attribute. I have a query to return those rows where the data is wrong and this relationship has been broken (1-to-many). I'm gathering these rows to fix them and restore this 1-to-1 relationship. This is a theoretical simplification of my actual problem but I'll post example table schema here as it was requested. item table: +------------+------------+-----------+ | item_id | name | attr_id | +------------+------------+-----------+ | 1 | BMW 320d | 20 | | 1 | BMW 320d | 21 | | 2 | BMW 335i | 23 | | 2 | BMW 335i | 34 | +------------+------------+-----------+ attribute table: +---------+-----------------+------------+ | attr_id | value | parent_id | +---------+-----------------+------------+ | 20 | SE | 21 | | 21 | M Sport | 0 | | 23 | AC | 24 | | 24 | Climate control | 0 | .... | 34 | Leather seats | 0 | +---------+-----------------+------------+ A simple query to return items with more than one attribute. SELECT item_id, COUNT(DISTINCT(attr_id)) AS attributes FROM item GROUP BY item_id HAVING attributes > 1 This gets me a result set like so: +-----------+------------+ | item_id | attributes | +-----------+------------+ | 1 | 2 | | 2 | 2 | | 3 | 2 | -- etc. -- However, there's an exception. The attribute table can hold a tree structure, via parent links in the table. For certain rows, parent_id can hold the ID of another attribute. There's only one level to this tree. Example: +---------+-----------------+------------+ | attr_id | value | parent_id | +---------+-----------------+------------+ | 20 | SE | 21 | | 21 | M Sport | 0 | .... I do not want to retrieve items in my original query where, for a pair of associated attributes, they related like attributes 20 & 21. I do want to retrieve items where: the attributes have no parent for two or more attributes they are not related (e.g. attributes 23 & 34) Example result desired, just the item ID: +------------+ | item_id | +------------+ | 2 | +------------+ How can I join against attributes from items and exclude these rows? Do I use a temporary table or can I achieve this from a single query? Thanks.

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  • Display Events on PHP Calendar

    - by jl
    Hi, I would like to ask if I have a table of events on my database, e.g. description | startdt | enddt event1 | 2010-04-01 10:00:00 | 2010-04-01 13:00:00 event2 | 2010-04-09 14:00:00 | 2010-04-09 18:00:00 event3 | 2010-04-30 11:00:00 | 2010-05-02 16:00:00 I have already created a php calendar, how can I display these above events onto my calendar, so that it will look something like the google calendar? e.g. on the for 2010-04-01, it will display "event1" on the month calendar. Thank you.

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  • change password code error

    - by ejah85
    I've created a code to change a password. Now it seem contain an error. When I fill in the form to change password, and click save the error message: Warning: mysql_real_escape_string() expects parameter 2 to be resource, null given in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 103 Warning: mysql_real_escape_string() expects parameter 2 to be resource, null given in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 103 I really don’t know what the error message means. Please guys. Help me fix it. Here's is the code: <?php session_start(); ?> <?php # change password.php //set the page title and include the html header. $page_title = 'Change Your Password'; //include('templates/header.inc'); if(isset($_POST['submit'])){//handle the form require_once('connectioncomplaint.php');//connect to the db. //include "connectioncomplaint.php"; //create a function for escaping the data. function escape_data($data){ global $dbc;//need the connection. if(ini_get('magic_quotes_gpc')){ $data=stripslashes($data); } return mysql_real_escape_string($data, $dbc); }//end function $message=NULL;//create the empty new variable. //check for a username if(empty($_POST['userid'])){ $u=FALSE; $message .='<p> You forgot enter your userid!</p>'; }else{ $u=escape_data($_POST['userid']); } //check for existing password if(empty($_POST['password'])){ $p=FALSE; $message .='<p>You forgot to enter your existing password!</p>'; }else{ $p=escape_data($_POST['password']); } //check for a password and match againts the comfirmed password. if(empty($_POST['password1'])) { $np=FALSE; $message .='<p> you forgot to enter your new password!</p>'; }else{ if($_POST['password1'] == $_POST['password2']){ $np=escape_data($_POST['password1']); }else{ $np=FALSE; $message .='<p> your new password did not match the confirmed new password!</p>'; } } if($u && $p && $np){//if everything's ok. $query="SELECT userid FROM access WHERE (userid='$u' AND password=PASSWORD('$p'))"; $result=@mysql_query($query); $num=mysql_num_rows($result); if($num == 1){ $row=mysql_fetch_array($result, MYSQL_NUM); //make the query $query="UPDATE access SET password=PASSWORD('$np') WHERE userid=$row[0]"; $result=@mysql_query($query);//run the query. if(mysql_affected_rows() == 1) {//if it run ok. //send an email,if desired. echo '<p><b>your password has been changed.</b></p>'; include('templates/footer.inc');//include the HTML footer. exit();//quit the script. }else{//if it did not run OK. $message= '<p>Your password could not be change due to a system error.We apolpgize for any inconvenience.</p><p>' .mysql_error() .'</p>'; } }else{ $message= '<p> Your username and password do not match our records.</p>'; } mysql_close();//close the database connection. }else{ $message .='<p>Please try again.</p>'; } }//end oh=f the submit conditional. //print the error message if there is one. if(isset($message)){ echo'<font color="red">' , $message, '</font>'; } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <body> <script language="JavaScript1.2">mmLoadMenus();</script> <table width="604" height="599" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td height="130" colspan="7"><img src="images/banner(E-Complaint)-.jpg" width="759" height="130" /></td> </tr> <tr> <td width="100" height="30" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="160" bgcolor="#ABD519"> <?php include "header.php"; ?>&nbsp;</td> </tr> <tr> <td colspan="7" bgcolor="#FFFFFF"> <fieldset><legend> Enter your information in the form below:</legend> <p><b>User ID:</b> <input type="text" name="username" size="10" maxlength="20" value="<?php if(isset($_POST['userid'])) echo $_POST['userid']; ?>" /></p> <p><b>Current Password:</b> <input type="password" name="password" size="20" maxlength="20" /></p> <p><b>New Password:</b> <input type="password" name="password1" size="20" maxlength="20" /></p> <p><b>Confirm New Password:</b> <input type="password" name="password2" size="20" maxlength="20" /></p> </fieldset> <div align="center"> <input type="submit" name="submit" value="Change My Password" /></div> </form><!--End Form--> </td> </tr> </table> </body> </html>

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  • change password code error.....

    - by shimaTun
    I've created a code to change a password. Now it seem contain an error.before i fill the form. the page display the error message: Parse error: parse error, unexpected $end in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 222 this the code: <?php # userChangePass.php //this page allows logged in user to change their password. $page_title='Change Your Password'; //if no first_name variable exists, redirect the user if(!isset($_SESSION['nameuser'])){ header("Location: http://" .$_SERVER['HTTP_HOST']. dirname($_SERVER['PHP_SELF'])."/index.php"); ob_end_clean(); exit(); }else{ if(isset($_POST['submit'])) {//handle form. require_once('connectioncomplaint.php'); //connec to the database //check for a new password and match againts the confirmed password. if(eregi ("^[[:alnum:]]{4,20}$", stripslashes(trim($_POST['password1'])))){ if($_POST['password1'] == $_POST['password2']){ $p =escape_data($_POST['password1']); }else{ $p=FALSE; echo'<p><font color="red" size="+1"> Your password did not match the confirmed password!</font></p>'; } }else{ $p=FALSE; echo'<p><font color="red" size="+1"> Please Enter a valid password!</font></p>'; } if($p){ //if everything OK. //make the query $query="UPDATE access SET password=PASSWORD('$p') WHERE userid={$_SESSION['userid']}"; $result=@mysql_query($query);//run the query. if(mysql_affected_rows() == 1) {//if it run ok. //send an email,if desired. echo '<p><b>your password has been changed.</b></p>'; //include('templates/footer.inc');//include the HTML footer. exit(); }else{//if it did not run ok $message= '<p>Your password could not be change due to a system error.We apolpgize for any inconvenience.</p><p>' .mysql_error() .'</p>'; } mysql_close();//close the database connection. }else{//failed the validation test. echo '<p><font color="red" size="+1"> Please try again.</font></p>'; } }//end of the main Submit conditional. ?> And code for form: <h1>Change Your Password</h1> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <fieldset> <p><b>New Password:</b><input type="password" name="password1" size="20" maxlength="20" /> <small>Use only letters and numbers.Must be between 4 and 20 characters long.</small></p> <p><b>Confirm New Password:</b><input type="password" name="password2" size="20" maxlength="20" /></p> </fieldset> <div align="center"> <input type="submit" name="submit" value="Change My Password" /></div> </form><!--End Form-->

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  • Search a string to find which records in table are inside said string

    - by Improfane
    Hello, Say I have a string. Then I have a number of unique tokens or keywords, potentially a large number in a database. I want to search and find out which of these database strings are inside the string I provide (and get the IDs of them). Is there a way of using a query to search the provided string or must it be taken to application space? Am I right in thinking that this is not a 'full text search'? Would the best method be to insert it into the database to make it a full text search?

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  • PHP getting blank pages after submit a form + signal Segmentation fault (11)

    - by Ole Media
    I few days ago I update my macbook pro to snow leopard, and since then some php files are not showing. This is what happens: I created a php form, when going to 'http://localhost/webform.php' I can see the form just fine. Then, once I submit the form, I just get a blank page. I enable error and warnings reporting under php.ini to make sure I'm not missing something, but still I'm not getting anything, just the blank page. Then I checked under apache log files, and what I notice is that every time I submit the form I see the following line coming up under the apache logs: [Wed Apr 07 21:40:28 2010] [notice] child pid 70223 exit signal Segmentation fault (11) I'm clueless on this one. Any ideas on how to fix it?

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  • hibernate not throwing stale state exception nor it is overwriting data

    - by Reddy
    Our application do the following. 1. Start the transaction. 2. Execute a query using prepared statement 3. Check a condition to see the number of rows updated are equal to the required number. 4. It commits on success of above condition otherwise it will roll back However the problem is that when two threads are simultaneously enter this code. Thread-1 is updating a row in step 2. It checked the condition and committed successfully since the condition is successful. Thread-2 started execution somewhere between steps 1 & 4, and it is failing on at condition checking at step 3 (as it is getting number of updated rows as 0). I expected second thread to throw an exception but it is not. What could be the problem?

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  • Problem with PHP/Java bridge.

    - by Jack
    I am using Tomcat 6. I am running a php script using the JavaBridge. I get the following error when I run my code. Fatal error: Call to undefined function mysqli_connect() in C:\Program Files\apache-tomcat-6.0.26\webapps\JavaBridge\xxxx\xxxxx.php on line 534 Please help.

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  • Making a relevant search of text in database using regex

    - by madphp
    Can anyone tell me how I could count the possible instances of a keyword in a block of text? I've split a search term up into separate tokens, so just need to run through and do a count for every instance and removing punctuation or other special characters when making the count. Secondly, if someone has inserted search terms surrounded by double quotes, i want to be able to skip explode, but just count instances of that exact phrase. It doesn't have to be case sensitive and I would like to remove punctuation from the phrase when doing the count. Thirdly, in both cases i want to be able to ignore wordpress and html tags. Lastly, if anyone know any good tutorials for relevant searches that answer the questions above, that would cool too. I've got this far. $results = $wpdb->get_results($sql); $tokens = explode('search_terms'); // Re-arrange Relevant Results foreach ($results As $forum_topic){ foreach($tokens As $token){ // count tokens in topic_title if ($token ){ } } }

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  • Improving performance in this query

    - by Luiz Gustavo F. Gama
    I have 3 tables with user logins: sis_login = administrators tb_rb_estrutura = coordinators tb_usuario = clients I created a VIEW to unite all these users by separating them by levels, as follows: create view `login_names` as select `n1`.`cod_login` as `id`, '1' as `level`, `n1`.`nom_user` as `name` from `dados`.`sis_login` `n1` union all select `n2`.`id` as `id`, '2' as `level`, `n2`.`nom_funcionario` as `name` from `tb_rb_estrutura` `n2` union all select `n3`.`cod_usuario` as `id`, '3' as `level`, `n3`.`dsc_nome` as `name` from `tb_usuario` `n3`; So, can occur up to three ids repeated for different users, which is why I separated by levels. This VIEW is just to return me user name, according to his id and level. considering it has about 500,000 registered users, this view takes about 1 second to load. too much time, but is becomes very small when I need to return the latest posts on the forum of my website. The tables of the forums return the user id and level, then look for a name in this VIEW. I have registered 18 forums. When I run the query, it takes one second for each forum = 18 seconds. OMG. This page loads every time somebody enter my website. This is my query: select `x`.`forum_id`, `x`.`topic_id`, `l`.`nome` from ( select `t`.`forum_id`, `t`.`topic_id`, `t`.`data`, `t`.`user_id`, `t`.`user_level` from `tb_forum_topics` `t` union all select `a`.`forum_id`, `a`.`topic_id`, `a`.`data`, `a`.`user_id`, `a`.`user_level` from `tb_forum_answers` `a` ) `x` left outer join `login_names` `l` on `l`.`id` = `x`.`user_id` and `l`.`level` = `x`.`user_level` group by `x`.`forum_id` asc USING EXPLAIN: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY <derived2> ALL NULL NULL NULL NULL 6 Using temporary; Using filesort 1 PRIMARY <derived4> ALL NULL NULL NULL NULL 530415 4 DERIVED n1 ALL NULL NULL NULL NULL 114 5 UNION n2 ALL NULL NULL NULL NULL 2 6 UNION n3 ALL NULL NULL NULL NULL 530299 NULL UNION RESULT ALL NULL NULL NULL NULL NULL 2 DERIVED t ALL NULL NULL NULL NULL 3 3 UNION r ALL NULL NULL NULL NULL 3 NULL UNION RESULT ALL NULL NULL NULL NULL NULL Somebody can help me or give a suggestion?

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  • problem with joomla, php and json

    - by sebastian
    hi, i have a problem with a joomla component. i'm, unsing php and json for some dynamic drop down boxes. here is the code:` jQuery( function () { //jQuery.ajaxSetup({error : function (a,b) {console.dir(a); console.dir(b);}}); jQuery("#util, #loc").change( function() { var locatie = jQuery("#loc").val(); var utilitate = jQuery("#util").val(); if ( (locatie!= '---') && (utilitate!='---') ) jQuery.getJSON( "index.php?option=com_calculator&opt=json_contor&format=raw", { locatie: locatie, utilitate: utilitate }, function (data) { var html = ""; if ( data.success == 'ok' ) for (var i in data.val) html += "<option name=den_contor value ='"+ i+"' >" + data.val[i]+ " </option>"; jQuery("#den_contor").html( html ) } ) }) }); the query works, but only on one PC. we have exactly the same xampp server, exactly the same files. on one pc it works, and on a online server and on my pc it doesn't. EDIT: i have three drop down boxes, the first is populated directly from the database, the second has 4 predefined values. and the third is populated depending on combination of the first two. i have a test site online. http://contor.redxart.com must be logged in to use Calculator in the menu. you can make an new account :) "Adaugare Index" is the part that isn't working any ideas? thanks, sebastian

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