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  • How can I select a column with no values?

    - by Lye
    I have a table with thousands of rows and hundreds of columns (not my design). I'm trying to find out which columns are never used so I can simplify the table a little. How can I find which of the columns have no value in all rows?

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  • How can I figure out a users postal code if I have their latitude / longitude location? Need help w

    - by mike
    I'm using HTML5 geolocation to collect the users lat / long and I need to figure out what their postal code is as well. I have a database of all the lat / long for each postal code in the US & Canada. How can I write a query to find out what their postal code is? Below, is an example of how the data is structured in the 'zips' table. Country PostalCode Latitude Longitude USA 0051 40.813078 -73.046388 USA 00616 18.426456 -66.673779 I can't do a 'SELECT PostalCode FROM zips WHERE Latitude = user.lat AND Longitude = user.long'. I believe I need to find the nearest lat / long. Any suggestions on how I can write this?

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  • how can i make sure only a single record is inserted when multiple apache threads are trying to acce

    - by Ed Gl
    I have a web service (xmlrpc service to be exact) that handles among other things writing data into the database. Here's the scenario: I often receive requests to either update or insert a record. What I would do is this: If the record already exists, append to the record, If not, create a new record The issue is that there are certain times I would get a 'burst' of requests, which spawns several apache threads to handle the request. These 'bursts' would come within less than milliseconds of each other. I now have several threads performing #1 and #2. Often two threads would would 'pass' number #1 and actually create two duplicate records (except for the primary key). I'd like to use some locking mechanism to prevent other threads from accessing the table while the other thread finishes its work. I'm just afraid of using it because if something happens I don't want to leave the table locked. Is there a solid way of handling this? I'm open to using locks if I can do it properly. Thanks,

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  • how can we change the value by using radio buttons

    - by magna
    I am making a website in Adobe Dreamweaver with php. In the site there’s a 3 buttons for selecting payment method that will act as the continue button. What I want is when the user checks a radio buttons (I agree button), it will be add with that amount and display with previous amount.. there is three buttons which has the corresponding values(amount in pounds).. plz check my website http://www.spsmobile.co.uk in this linkgo to mobile phone unlocking and after add the cart click make payment it will go to next page there is a delivery mail details.. for that delivery mail details only am asking.. here i mentioned code: <input id="radio-1" type="radio" name="rmr" value="1"> <label for="radio-1">£3</label> <input id="radio-2" type="radio" name="rmr" value="2"> <label for="radio-2">£5.5</label> <input id="radio-3" type="radio" name="rmr" value="4"> <label for="radio-3">£10</label> <div class="total-text" style="font-size:36px">£10</div> var total = parseInt($("div.total-text").text().substring(1), 10); $("input[name='rmr']").bind('change', function() { var amount = 0; switch (this.value) { case "1": amount = 3; break; case "2": amount = 5.5; break; case "4": amount = 10; break; } $("div.total-text").text("£" + (total + amount)); }); but there is no change , my previous amount did not add with that. while am clicking previous amount only displayed on browser.. i need when i cliks radio button the value should change correspondingly.. where i did that mistake...plz give me some idea and what should i do..is there any need for storing db.. thanks in adv

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  • Relation to multiple tables of different types for rating?

    - by Tronic
    i have a table structure like this Products Team Images and want to implement a rating/commenting-feature, where users can rate each entry of all tables. what's the best way to make a single rating table? e.g. a user votes a a product and a team entry, and it should be possible to get alle these entries from a single table. what kind of table-structure is best for this purpose? i hope, my questions is clear enough :/ thanks in advance!

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  • Session is working in Localhost Properly but not Online (Cpanel)

    - by nando pandi
    Hello guys Sorry for my stupid question regarding to my yesterday question its not solved yet even the advice you have given but still not working. i have removed all of spaces but still showing the problem for me. it's working perfect in localhost but not in CPANEL. Here is the errors which give: Warning: session_start() [function.session-start]: Cannot send session cookie - headers already sent by (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 1 Warning: session_start() [function.session-start]: Cannot send session cache limiter - headers already sent (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 1 Warning: Cannot modify header information - headers already sent by (output started at /home/scalepro/public_html/Admin Panel/Remote Employee/main.php:1) in /home/scalepro/public_html/Admin Panel/Remote Employee/main.php on line 13 Warning: Unknown: Your script possibly relies on a session side-effect which existed until PHP 4.2.3. Please be advised that the session extension does not consider global variables as a source of data, unless register_globals is enabled. You can disable this functionality and this warning by setting session.bug_compat_42 or session.bug_compat_warn to off, respectively in Unknown on line 0 ANY ONE PLEASE ??? Here is my code: <?php session_start(); require_once('../../Admin Panel/db.php'); if(isset($_POST['email']) && !empty($_POST['email']) && isset($_POST['password']) && !empty($_POST['password'])) { $email = $_POST['email']; $password = $_POST['password']; $query="SELECT RemoteEmployeeFullName, RemoteEmployeeEmail, RemoteEmployeePassword FROM remoteemployees WHERE RemoteEmployeeEmail='".$email."' AND RemoteEmployeePassword='".$password."'"; $queryrun=$connection->query($query); if($queryrun->num_rows > 0) { $_SESSION['email']=$RemoteEmployeeFullName; header("Location: /home/scalepro/public_html/Admin Panel/Remote Employee/REPLists.php"); } else { echo 'Email: <b>'.$email. '</b> or Password <b>'. $password.'</b> Is Not Typed Correctly Try Again Please!.'; header( "refresh:5;url= /home/scalepro/public_html/spd/myaccount.php" ); } } else { header( "refresh:5;url= /home/scalepro/public_html/spd/myaccount.php" ); } ?> if the condition gets true this will be redirected to a page by the name of REPLists.php here is the page. <?php session_start(); require_once('../../Admin Panel/db.php'); ?> <html> <head> <style> .wrapper { width:1250px; height:auto; border:solid 1px #000; margin:0 auto; padding:5px; border-radius:5px; -webkit-border-radius:5px; -moz-border-radius:5px; -ms-border-radius:5px; } .wrapper .header { width:1250px; height:20px; border-bottom:solid 1px #f0eeee; margin:auto 0; margin-bottom:12px; } .wrapper .header div { text-decoration:none; color:#F60; } .wrapper .header div a { text-decoration:none; color:#F60; } .wrapper .Labelcon { width:1250px; height:29px; border-bottom:solid 1px #ccc; } .wrapper .Labelcon .Label { width:125px; height:20px; float:left; text-align:center; border-left:1px solid #f0eeee; font:Verdana, Geneva, sans-serif; font-size:14.3px; font-weight:bold; } .wrapper .Valuecon { width:1250px; height:29px; border-bottom:solid 1px #ccc; color:#F60; text-decoration:none; } .wrapper .Valuecon .Value { width:125px; height:20px; float:left; text-align:center; border-left:1px solid #f0eeee; font-size:14px; } </style> </head> <body> <div class="wrapper"> <div class="header"> <div style="float:left;"><font color="#000000">Email: </font> <?php if(isset($_SESSION['email'])) { echo $_SESSION['email']; } ?> </div> <div style="float:right;"> <a href="#">My Profile</a> | <a href="logout.php">Logout</a></div> </div> <div class="Labelcon"> <div class="Label">Property ID</div> <div class="Label">Property Type</div> <div class="Label">Property Deal Type</div> <div class="Label">Property Owner</div> <div class="Label">Proposted Price</div> </div> <?php if(!isset($_SESSION['email'])) { header('Location:../../spd/myaccount.php'); } else { $query = "SELECT properties.PropertyID, properties.PropertyType, properties.PropertyDealType, properties.Status, properties.PropostedPrice, remoteemployees.RemoteEmployeeFullName, propertyowners.PropertyOwnerName, propertydealers.PropertyDealerName FROM remoteemployees, propertyowners, propertydealers, properties WHERE properties.PropertyOwnerID=propertyowners.PropertyOwnerID AND properties.PropertyDealerID=propertydealers.PropertyDealerID AND remoteemployees.RemoteEmployeeID=properties.RemoteEmployeeID ORDER BY properties.PropertyID "; $query_run = $connection->query($query); if( $connection->error ) exit( $connection->error ); while($row=$query_run->fetch_assoc()) { ?> <div class="Valuecon"> <div class="Value"><?php echo $row['PropertyID'] ?></div> <div class="Value"><?php echo $row['PropertyType'] ?></div> <div class="Value"><?php echo $row['PropertyDealType']?></div> <div class="Value"><?php echo $row['PropertyOwnerName'] ?></div> <div class="Value"><?php echo $row['PropostedPrice'];?></div> </div> <?php } }?> </div> </body> </html>

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  • Turn database result into array

    - by Industrial
    Hi everyone, I have just made the update/add/delete part for the "Closure table" way of organizing query hierarchical data that are shown on page 70 in this slideshare: http://www.slideshare.net/billkarwin/sql-antipatterns-strike-back My database looks like this: Table Categories: ID Name 1 Top value 2 Sub value1 Table CategoryTree: child parent 1 1 2 2 2 1 However, I have a bit of an issue getting the full tree back as an multidimensional array from a single query. Here's what I would like to get back: array ( 'topvalue' = array ( 'Subvalue', 'Subvalue2', 'Subvalue3' = array ('Subvalue 1', 'Subvalue 2', 'Subvalue 3' ) ); ); Update: Found this link, but I still have a hard time to convert it into an array: http://karwin.blogspot.com/2010/03/rendering-trees-with-closure-tables.html

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  • WHERE id IN doesn't work in UPDATE

    - by Donator
    UPDATE statistics' SET money = money + '$money' WHERE member_id IN ((SELECT member_id FROM races WHERE l_id = '$mem_id'), $other_id) What's wrong with that? I want to retrieve all member_ids from races and also include to member_id $other_id. Without $other_id it works. By the way, it gives me "Subquery returns more than 1 row" error.

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  • Cakephp query doesn't render correct data

    - by user2915012
    I'm totally new in cakephp and fetching problem at the time of query to render data I tried this to find out categories/warehouses table info but failed.. $cart_products = $this->Order->OrdersProduct->find('all', array( 'fields' => array('*'), 'contain' => array('Category'), 'joins' => array( array( 'table' => 'products', 'alias' => 'Product', 'type' => 'LEFT', 'conditions' => array('Product.id = OrdersProduct.product_id') ), array( 'table' => 'orders', 'alias' => 'Order', 'type' => 'LEFT', 'conditions' => array('Order.id = OrdersProduct.order_id') ) ), 'conditions' => array( 'Order.store_id' => $store_id, 'Order.order_status' => 'in_cart' ) )); I need the result something like this... Array ( [0] => Array ( [OrdersProduct] => Array ( [id] => 1 [order_id] => 1 [product_id] => 16 [qty] => 10 [created] => 2013-10-24 08:04:33 [modified] => 2013-10-24 08:04:33 ) [Product] => Array ( [id] => 16 [part] => 56-987xyz [title] => iPhone 5 battery [description] => iPhone 5c description [wholesale_price] => 4 [retail_price] => 8 [purchase_cost] => 2 [sort_order] => [Category] => array( [id] => 1, [name] => Iphone 5 ) [Warehouse] => array( [id] => 1, [name] => Warehouse1 ) [weight] => [created] => 2013-10-22 12:14:57 [modified] => 2013-10-22 12:14:57 ) ) ) How can I find this? Can anybody help me? thanks

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  • Force reload/refresh when pressing the back button

    - by FlyingCat
    I will try my best to explain this. I have an application that show the 50+ projects in my view page. The user can click the individual project and go to the update page to update the project information. Everything works fine except that after user finish updating the individual project information and hit 'back' button on the browser to the previous view page. The old project information (before update) is still there. The user has to hit refresh to see the updated information. It not that bad, but I wish to provide better user experience. Any idea to fix this? Thanks a lot.

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  • add array element to row returned from sql query

    - by bert
    I want to add an additional value into an array before passing it to json_encode function, but I can't get the syntax right. $result = db_query($query); // $row is a database query result resource while ($row = db_fetch_object($result)) { $stack[] = $row; // I am trying to 'inject' array element here $stack[]['x'] = "test"; } echo json_encode($stack);

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  • Finding comma separated values with a colon delimiter

    - by iconMatrix
    I am setting values in my database for tourneyID,Selected,Paid,Entered,date then separating each selection with a colon So I have a string that may look like this 187,S,,,09-21-2013:141,S,,,06-21-2013:144,S,,,05-24-2013 but it also could look like this 145,S,,,07-12-2013:142,S,,,05-24-2013:187,S,,,09-21-2013 and some times is looks like this 87,S,,,07-11-2013:125,S,,,06-14-2013 I am trying to find this sequence: 187,S,,,09-21-2013 I have data stored like that because I paid a programmer to code it for me. Now, as I learn, I see it was not the best solution, but it is what I have till I learn more and it is working. My problem is when using LIKE it returns both the 187 and 87 values $getTeams = mysql_query("SELECT * FROM teams WHERE (team_tourney_vector LIKE '%$tid,S,P,,$tourney_start_date%' OR team_tourney_vector LIKE '%$tid,S,,,$tourney_start_date%') AND division='$division'"); I tried this using FIND_IN_SET() but it would only return the the team id for this string 187,S,,,09-21-2013:141,S,,,06-21-2013:144,S,,,05-24-2013 and does not find the team id for this string 145,S,,,07-12-2013:142,S,,,05-24-2013:187,S,,,09-21-2013 SELECT * FROM teams WHERE FIND_IN_SET('187',team_tourney_vector) AND (team_tourney_vector LIKE '%S,,,09-21-2013%') Any thoughts on how to achieve this?

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  • Insert names into table if not already existing

    - by John
    I am trying to build an application that allows users to submit names to be added to a db table (runningList). Before the name is added tho, I would like to check firstname and lastname against another table (controlList). It must exist in (controlList) or reply name not valid. If the name is valid I would like to then check firstname and lastname against (runningList) it make sure it isnt already there. If it isnt there, then insert firstname & lastname. If it is there, reply name already used. Below is code that worked before I tried to add the test against the controlList, I somehow broke it altogether while trying to add the extra step. if (mysql_num_rows(mysql_query('SELECT * FROM runninglist WHERE firstname=\'' .$firstname . '\' AND lastname=\'' . $lastname . '\' LIMIT 1')) == 0) { $sql="INSERT INTO runninglist (firstname, lastname) VALUES ('$_POST[firstname]','$_POST[lastname]')"; } else { echo "This name has been used."; } Any direction would be appreciated. Thanx John

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  • How to access website CMS with only access to database

    - by user1741615
    I have a website that uses an "in-house" cms and I don't know the login details. The platform itself doesn't have the "reset your password" functionality. I do have access to ftp and phmyadmin and I found the SQL table containing the user details, but of course the password is MD5 encryption. I tried manually creating a user in php my admin and filling in a password encrypted in MD5 (used a md service online for that), but it still doesn't work. Does anybody know other tricks I can use? Thanks.

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  • CakePHP Form Helper Database Interaction

    - by xtine
    Currently I am developing a CakePHP that will list various businesses. In the database, there is a table for businesses that lists them like so: id | name | address | city | state | state_id | zip | url The state column are abbreviations of states (for listing purposes) CA, AK, FL, etc and the state_id matches up with the ids in the states table: id | name | state_abbr I have an admin_add.ctp template with form helpers for inserting new businesses. For entering a state for a business I am going to have a pull down that lists all the states. However, how do I make the database insert so it will know how to add the state abbreviation and state id when I submit the form to add the business?

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  • Wrong logic in If Statement?

    - by Charles
    $repeat_times = mysql_real_escape_string($repeat_times); $result = mysql_query("SELECT `code`,`datetime` FROM `fc` ORDER by datetime desc LIMIT 25") or die(mysql_error()); $output .=""; $seconds = time() - strtotime($fetch_array["datetime"]); if($seconds < 60) $interval = "$seconds seconds"; else if($seconds < 3600) $interval = floor($seconds / 60) . " minutes"; else if($seconds < 86400) $interval = floor($seconds / 3600) . " hours"; else $interval = floor($seconds / 86400) . " days"; while ($fetch_array = mysql_fetch_array($result)) { $fetch_array["code"] = htmlentities($fetch_array["code"]); $output .= "<li><a href=\"http://www.***.com/code=" . htmlspecialchars(urlencode($fetch_array["code"])) . "\" target=\"_blank\">" . htmlspecialchars($fetch_array["code"]) . "</a> (" . $interval . ") ago.</li>"; } $output .=""; return $output; Why is this returning janice (14461 days) instead of janice (15 minutes ago) The datetime function table has the DATETIME type in my table so it's returning a full string for the date.

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  • PHP displaying error for already used Username and empty field

    - by Pixel Reaper
    I want PHP to make sure the username is not already used and also check to see if the field is empty. Sorry I am a huge noob when it comes to php. Here is my code: // Check for an Username: $dup = mysql_query("SELECT user_username FROM users WHERE user_username='".$_POST['user_username']."'"); if(mysql_num_rows($dup) >0){ $errors[] = 'Username already used.'; } else{ $un = mysqli_real_escape_string($dbc, trim($_POST['user_username'])); echo '<b>Congrats, You are now Registered.</b>'; } else { $errors[] = 'You forgot to enter your Username.'; }

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  • Fill in missing values in a SELECT statement

    - by benjamin button
    If i have a table with two fields.customer id and order. let's say i have in total order ID 1,2,3,4 all the customer can have all the four orders.like below 1234 1 1234 2 1234 3 1234 4 3245 3 3245 4 5436 2 5436 4 you can see above that 3245 customer doesnt have order id 1 and 2. how could i print in the query output like 3245 1 3245 2 5436 1 5436 3 EDIT: i dont have order table but i have list of order's like we can hard code it in the query(1,2,3,4) i dont have an orders table.

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  • How many indexes will actually get used?

    - by Ender
    I'm writing a page that does very simple search queries, resulting in something like: SELECT * FROM my_table WHERE A in (a1, a2, a3) AND B in (b1, b2) AND C in (c1, c2, c3, c4) AND And so on for a variable number of columns, usually ~5. If I create a separate index for each column (one for A, one for B, one for C, not (A,B,C)), will all of them be used in the above query?

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  • What is the best way to reduce code and loop through a hierarchial commission script?

    - by JM4
    I have a script which currently "works" but is nearly 3600 lines of code and makes well over 50 database calls within a single script. From my experience, there is no way to really "loop" the script and minimize it because each call to the database is a subquery of the ones before based on referral ids. Perhaps I can give a very simple example of what I am trying to accomplish and see if anybody has experience with something similar. In my example, there are three tables: Table 1 - Sellers ID | Comm_level | Parent ----------------------------------- 1 | 4 | NULL 2 | 3 | 1 3 | 2 | 1 4 | 2 | 2 5 | 2 | 2 6 | 1 | 3 Where ID is the id of one of our sales agents, comm_level will determine what his commission percentage is for each product he sells, parent indicates the ID for whom recruited that particular agent. In the example above, 1 is the top agent, he recruited two agents, 2 and 3. 2 recruited two agents, 4 and 5. 3 recruited one agent, 6. NOTE: An agent can NEVER recruit anybody equal to or higher than their own level. Table 2 - Commissions Level | Item 1 | Item 2 | Item 3 ----------------------------------------------------- 4 | .5 | .4 | .3 3 | .45 | .35 | .25 2 | .4 | .3 | .2 1 | .35 | .25 | .15 This table lays out the commission percentages for each agent based on their actual comm_level (if an agent is at a level 4, he will receive 50% on every item 1 sold, 40% on every item 2, 30% on every item 3 and so on. Table 3 - Items Sold ID | Item --------------------- 4 | item_1 4 | item_2 1 | item_1 2 | item_3 6 | item_2 1 | item_3 This table pairs the actual item sold with the seller who sold the item. When generating the commission report, calculating individual values is very simple. Calculating their commission based on their sub_sellers however is very difficult. In this example, Seller ID 1 gets a piece of every single item sold. The commission percentages indicate individual sales or the height of their commission. For example: When seller ID 6 sold one of item_2 above, the tree for commissions will look like the following: -ID 6 - 25% of cost(item_1) -ID 3 - 5% of cost(item_1) - (30% is his comm - 25% comm of seller id 6) -ID 1 - 10% of cost(item_1) - (40% is his comm - 30% of seller id 3) This must be calculated for every agent in the system from the top down (hence the DB calls within while loops throughout my enormous script). Anybody have a good suggestion or samples they may have used in the past?

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  • Confusion using MYSQLI

    - by user1020069
    I just started using mysqli API for PHP. Apparently, every time an object of the class MYSQLI is instantiated, it can setup a connection to the database as it connects to the server unlike mysql_connect, which connects to the server first and then you are required to specify the database to query. Now this is a good problem if the db exists, in my case, the db does not exist on the first ever connection to the server/execution of the problem, hence I must connect without specifying the database, which is fine, since the msyqli constructor does not make this database mandatory. My challenge is essentially, how do I check if the database exists before attempting the first connection. The only way to really do this would be to establish a conection to the server and then use the result of the following query to gauge if the database exists: SELECT COUNT(*) AS `exists` FROM INFORMATION_SCHEMA.SCHEMATA WHERE SCHEMATA.SCHEMA_NAME="dbname" ; If this returns true, then the database exists, but now the challenge is how do I get the mysqli object to query this database rather than having to prefix the name of the database in the query. Thanks much

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