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Search found 1913 results on 77 pages for 'die in sente'.

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  • mysql import script by query instead of bash

    - by vick
    I have a file called script.sql how can I run that file using q mysql query? global $sql; $res = $sql->query("\. /script.sql")or die(mysql_error()); gives: #1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near '\. /script.sql' at line 1

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  • javascript error: variable is not defined

    - by Hristo
    to is not defined [Break on this error] setTimeout('updateChat(from, to)', 1); I'm getting this error... I'm using Firebug to test and this comes up in the Console. The error corresponds to line 71 of chat.js and the whole function that wraps this line is: function updateChat(from, to) { $.ajax({ type: "POST", url: "process.php", data: { 'function': 'getFromDB', 'from': from, 'to': to }, dataType: "json", cache: false, success: function(data) { if (data.text != null) { for (var i = 0; i < data.text.length; i++) { $('#chat-box').append($("<p>"+ data.text[i] +"</p>")); } document.getElementById('chat-box').scrollTop = document.getElementById('chat-box').scrollHeight; } instanse = false; state = data.state; setTimeout('updateChat(from, to)', 1); // gives error }, }); } This links to process.php with function call getFromDB and the code for that is: case ('getFromDB'): // get the sender and receiver user IDs from their user names $from = mysql_real_escape_string($_POST['from']); $query = "SELECT `user_id` FROM `Users` WHERE `user_name` = '$from' LIMIT 1"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_assoc($result); $fromID = $row['user_id']; $to = mysql_real_escape_string($_POST['to']); $query = "SELECT `user_id` FROM `Users` WHERE `user_name` = '$to' LIMIT 1"; $result = mysql_query($query) or die(mysql_error()); $row = mysql_fetch_assoc($result); $toID = $row['user_id']; $query = "SELECT * FROM `Messages` WHERE `from_id` = '$fromID' AND `to_id` = '$toID' LIMIT 1"; $result = mysql_query($query); while($row = mysql_fetch_assoc($result)) { $text[] = $line = $row['message']; $log['text'] = $text; } break; So I'm confused with the line that is giving the error. setTimeout('updateChat(from,to)',1); aren't the parameters to updateChat the same parameters that came into the function? Or are they being pulled in from somewhere else and I have to define to and from else where? Any ideas how to fix this error? Thanks, Hristo

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  • more radio problems * sighs * been at this for one week now

    - by jeansymolanza
    hi guys really i don't know what im doing wrong... i am trying to process multiple radios with mysql. the first step has involved me echoing the results on the process page. each time i select any radio option it simply displays the first row result. this is that i see after trying to submit the form: Notifications Thank you. The notifications have been updated successfully. statusid: 14 notc2: 1 Return this is the code for the form: <div style="padding: 15px;"> <span class="loginfail" style="font-size:24px; font-weight: bold">Notifications</span><p> <?php include("progress_insertcomment.php"); ?> <?php // Make a MySQL Connection mysql_select_db("speedycm_data") or die(mysql_error()); $query_comment = "select * from tbl_alert order by id desc limit 1"; $comment = mysql_query($query_comment, $speedycms) or die(mysql_error()); $row_comment = mysql_fetch_assoc($comment); $totalRows_comment = mysql_num_rows($comment); ?> <!--- add notification ---> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <span id="sprytextarea1"> <textarea id='comment' name="comment" style="height: 75px; width:330px;"><?php echo $row_comment['comment']; ?></textarea> </span> <p> <button type="submit">Add</button> <input type="hidden" name="notc" value="1"/> </form> <!--- notification history ---> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <table border="0" cellspacing="2" cellpadding="2"> <?php if ( $row_comment == 0 ) { echo "<span style='font-size: 11px;'>No current alerts.</span>"; } else { // Get all the data from the "example" table $result = mysql_query("SELECT * FROM tbl_alert ORDER BY id DESC") or die(mysql_error()); while($rows=mysql_fetch_array($result)){ ?> <tr> <td> <?php echo "<div class='bubble'><div class='pimped'> <blockquote>" . $rows['comment'] . " </blockquote></div> <cite><strong>" . $rows['user'] . "</strong> @ " . $rows['date'] . "</cite> <span style='font-size: 10px;'> <p> <a href='editalert.php?id=". $rows['id'] ."' class='form' >Edit</a>&nbsp;&#8226;&nbsp;<a href='deletealert.php?id=". $rows['id'] ."' class='form'>Delete</a> </span> </div> "; ?> </td> <td valign="top" align="center"><div style="padding-left: 30px;"><span style="font-size: 10px;">Completed?</span> <p class="field switch"> <!--- determine status of notification ---> <?php $status = $rows['status']; $id = $rows['id']; ?> <input type="radio" name="selstatus[<?php echo $id; ?>]" value="no" <?php if($status == 'yes') {echo 'checked';} else {echo '';} ?>/> <input type="radio" name="selstatus[<?php echo $id; ?>]" value="yes" <?php if($status == 'yes') {echo 'checked';} else {echo '';} ?>/> <input type="hidden" name="statusid" value="<?php echo $id; ?>"/> <label for="radio1" class="cb-enable <?php if($status == 'yes') {echo 'selected';} else {echo '';} ?>"><span>Yes</span></label> <label for="radio2" class="cb-disable <?php if($status == 'no') {echo 'selected';} else {echo '';} ?>"><span>No</span></label> </p> </div></td> </tr> <tr> <td></td> <?php } } ?> <td align="center"><div style="padding-left: 30px;"> <button type="submit">Update</button> <input type="hidden" name="notc2" value="1"/> </div></td> </tr> </table> </form> </div> this is the code for the processing page: <?php // 6) update notifications if (array_key_exists('notc2',$_POST)) { $update = $_POST['selstatus']; echo "<p style='font-size: 12px;'>Thank you. The notifications have been updated successfully.<p>"; foreach($_POST as $key => $value){ echo $key . ': ' . $value . '<br>'; } echo "<p><span style='font-size: 12px;'> <a onClick=\"history.go(-1)\" class='form'>Return</a></p> <p></span> "; exit; }; ?> how do i resolve this problem? please any help would be appreciated. i would like to display the id and value of the selected checkbox on the processing page before inserting it into the table. thanking you in advance. GOD BLESS

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  • counting paragraphs in text file

    - by robjez
    I need to create perl code which allows counting paragraphs in text files. I tried this and doesn't work: open(READFILE, "<$filename") or die "could not open file \"$filename\":$!"; $paragraphs = 0; my($c); while($c = getc(READFILE)) { if($C ne"\n") { $paragraphs++; } } close(READFILE); print("Paragraphs: $paragraphs\n");

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  • gets (variable)

    - by borlee
    can anyone tell me why gets(abc) works with char[] but not with int? int abc; char name[] = "lolrofl"; printf("Hello %s.\n",name); printf("\n "); fflush(stdin); gets (abc); printf("\n die zahl ist %i.\n",abc); system("Pause"); return(0);

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  • chained selects with one table

    - by Owen
    I know I am going about this in an unusual way, every tut I've seen uses multiple tables, but due to the way the rest of my site works I would like to create a chained select which operates using a single table. My table structure is: ---------------------- |Catagory|SubCategory| |01|cat1 |subcat1 | |02|cat1 |subcat2 | |03|cat2 |subcat1 | |04|cat2 |subcat2 | ---------------------- The code I have so far looks like: <tr> <td class="shadow"><strong>Category:</strong> </td> <td class="shadow"> <select id="category" name="category" style="width:150px"> <option selected="selected" value="<?php echo $category ?>"><?php echo $category?></option> <?php include('connect.php'); $result1 = mysql_query("SELECT DISTINCT category FROM categories") or die(mysql_error()); while($row = mysql_fetch_array( $result1 )) { $category = $row['category']; echo "<option value='". $row['category'] ."'>". $row['category'] ."</option>"; } ?> </select> </td> </tr> <tr> <td class="shadow"><strong>Sub Category:</strong> </td> <td class="shadow"> <select id="sub_catgory" name="sub_category" style="width:150px;"> <option selected="selected" value="<?php echo $sub_category ?>"><?php echo $sub_category ?></option> <?php include('connect.php'); $result2 = mysql_query("SELECT sub_category FROM categories WHERE ") or die(mysql_error()); while($row = mysql_fetch_array ($result2 )){ echo "<option value='" . $row['sub_category'] . "'>". $row['sub_category']. "</option>"; } ?> </select> </td> </tr> On the second select I am not sure how to state the WHERE clause. I need it to display the subcategories which have the same category as selected in the first select. PART 2 how would I include AJAX in this to preload the data so i don't need to refresh the page. Could someone either help me finish what I've started here or point me to a good tutorial. thanks

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  • Parse error in PHP login form

    - by user225269
    I'm trying to have a login form in php. But my current code doesnt work. Here is the form: <form name="form1" method="post" action="loginverify.php"> <td><font size="3">Username:</td> <td></td> <td><input type="text" name="uname" value="" maxlength="15"/><br/></td> <td><font size="3">Password:</td> <td></td> <td><input type="text" name="pword" value="" maxlength="15"/><br/></td> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login" /></td> </form> And the verify.php <?php session_start(); ?> <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="login"; $tbl="users"; $connection=mysql_connect($host, $username, $password) or die("cannot connect"); mysql_select_db($db_name, $connection) or die("cannot select db"); $user=$_POST['uname'] $pass=$_POST['pword'] $sql="SELECT Username, Password from users where Username='$user' and Password='$pass'"; $result=mysql_query[$sql]; $count=mysql_num_rows($result); if($count==1){ $SESSION['Username']=$user; echo"<a href='searchmain.php'> CONTINUE</a>"; } else{ echo"wrong username or password"; echo"<a href='loginform.php'>Back</a>"; } ?> Is there something wrong with my code. I get this parse error at line 15, which is this: $pass=$_POST['pword'] But when I try to remove it.It goes to line 16 or line 17 again. What do I do

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  • I want to do a sql update loop statement, by using the do--while in php

    - by Jean
    Hello, I want to loop the update statement, but it only loops once. Here is the code I am using: do { mysql_select_db($database_ll, $ll); $query_query= "update table set ex='$71[1]' where field='val'"; $query = mysql_query($query_query, $ll) or die(mysql_error()); $row_domain_all = mysql_fetch_assoc($query); } while ($row_query = mysql_fetch_assoc($query)); Thanks Jean

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  • Multiple Forms with Different Actions using Submit Buttons

    - by Adam Coulson
    I have Two forms in my index.php and am trying to get them to submit and POST their data seperatly Form 1 echo '<form action="process.php?type=news" method="post">'; echo '<table cellspacing="0"><tr><th>'; echo 'Add News to News Feed'; echo '</th></tr><tr><td>'; echo 'Title:<br /><input name="newstitle" type="text" id="add" style="height:16px;width:525px;" size="80" maxlength="186" /><br />'; echo 'Main Body Text:<br /><textarea name="newsfeed" id="add" style="width:525px;height:78px;" maxlength="2000" ></textarea>'; echo '<input style="float:right;margin-top:5px;" id="button" type="submit" value="Submit" />'; echo '</td></tr></table></from>'; And Form 2 echo '<form action="process.php?type=suggest" method="post">'; echo '<table cellspacing="0"><tr><th>'; echo 'Suggest Additions to the Intranet'; echo '</th></tr><tr><td>'; echo '<textarea name="suggest" id="add" style="width:330px;height:60px;" maxlength="800" ></textarea>'; echo '<input style="float:right;margin-top:5px;" id="button" type="submit" value="Submit" />'; echo '</td></tr></table></from>'; I want these both to post and do the action after pressing the submit button, but currently the second form submit to the first forms action How can i fix this??? EDIT: Also i am using .PHP for both the index and process page then using it to echo the forms onto the page Also here is the process.php data $type=$_REQUEST['type']; $suggest=$_POST['suggest']; $newstitle=$_POST['newstitle']; $news=mysql_real_escape_string($_POST['newsfeed']); if ($type == "news") { $sql=mysql_query("SELECT * FROM newsfeed WHERE title = ('$newstitle')"); $number_of_rows = mysql_num_rows($sql); if ($number_of_rows > 0) { echo 'This Title is Already Taken'; } else { $sql="INSERT INTO newsfeed (title, news) VALUES ('$newstitle','$news')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } header('Location: index.php'); exit; } } elseif ($type == "suggest") { $sql="INSERT INTO suggestions VALUES ('$suggest')"; if (!mysql_query($sql,$con)) { die('Error: ' . mysql_error()); } header('Location: index.php'); exit; }

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  • Page not redirecting properly(php)

    - by user225269
    I want to do the login page this way so that I won't be having trouble posting the username in the userpage. But everytime I try to access login.php. I get an error in firefox, that the page is not redirecting properly. What do I do? This works when I separate them into two. Into something like, login.php and verifylogin.php as the form action. But if I do it like this, I get redirection errors: <?php $host="localhost"; $username="root"; $password="nitoryolai123$%^"; $db_name="school"; $tbl_name="users"; mysql_connect("$host", "$username", "$password")or die("cannot connect"); mysql_select_db("$db_name")or die("cannot select DB"); $uname = mysql_real_escape_string($_POST['username']); $pword = mysql_real_escape_string($_POST['password']); $SQL = "SELECT * FROM users WHERE username = '$uname' AND password = '$pword'"; $result = mysql_query($SQL); $num_rows = mysql_num_rows($result); if ($result) { if ($num_rows > 0) { session_start(); $_SESSION['login'] = "1"; header ("Location: userpage.php"); } else { session_start(); $_SESSION['login'] = ""; header ("Location: login.php"); } } else { $errorMessage = "Error logging on"; } ?> <tr> <form name="form1" method="post" action="login.php"> <td> <table> <tr> <td><strong><font size="2">Login User</strong></td> </tr> <tr> <td width="30" height="35"><font size="2">Username:</td> <td width="30"><input name="username" type="text" id="username" maxlength="17"></td> </tr> <tr> <td width="30" height="35" ><font size="2">Password:</td> <td width="30"><input name="password" type="password" id="password" maxlength="17"></td> </tr> <td><td align="right" width="30"><input type="submit" name="Submit" value="Submit" /></td> <td><input type="reset" name="Reset" value="Reset"></td></td> </tr> </form> please help, thanks.

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  • (PHP) 1)How to genrate Secreate key on User & Client Side ? 3) How to Compare Server side MD5 and Client side Md5 ?

    - by user557994
    /* In Below Code .. My problem is that 1) How to genrate Secreate key on User Side ? 2) How to genrate Secreate key on Client Side ? 3) How to Compare Server side MD5 and Client side Md5 ? Can you solve my problem ? */ $gid = $_GET['id']; if($gid=="") { $filename = "counter.txt"; $fp = fopen( $filename, "r" ) or die("Couldn't Generate Whiteboard"); while ( ! feof( $fp ) ) { $countfile = fgets( $fp); $countfile++; } fclose( $fp ); $fp = fopen( $filename, "w" ) or die("Couldn't generate whiteboard"); fwrite( $fp, $countfile ); fclose( $fp ); $doc = new DOMDocument('1.0', 'UTF-8'); $ele = $doc-createElement( 'root' ); $ele-nodeValue = $uvar; $doc-appendChild( $ele ); $test = $doc-save("$countfile.xml"); genkey($id); echo ""; $uvar=$_POST['msgval']; exit; } else { if($uvar == "") { $xdoc = new DOMDocument( '1.0', 'UTF-8' ); $xdoc-Load("$gid.xml"); $candidate = $xdoc-getElementsByTagName('root')-item(0); $newElement = $xdoc -createElement('root'); $txtNode = $xdoc -createTextNode ($root); $newElement - appendChild($txtNode); $candidate - appendChild($newElement); $msg = $candidate-nodeValue; } } function genkey($id) { $encrypt_key = "GJHsahakst1468464a"; $key = MD5("$id","$$encrypt_key"); return $key; } ? function sendRequest() { var uvar = document.getElementById('txtHint').value; var xmlhttp = new XMLHttpRequest(); xmlhttp.onreadystatechange = function() { if(xmlhttp.readyState == 4 && xmlhttp.status==200) { document.getElementById('txtHint').value = ""; } } xmlhttp.open("POST","post.php?id=",true); xmlhttp.setRequestHeader("Content-type","application/x-www-form-urlencoded"); xmlhttp.send("umsg="+uvar); return; } Msg " /

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  • my sql insert query not working

    - by Piyush
    I am inserting userId.It is displaying correct but inserting 0 in spite of actual userId. mycode- If(! empty($userIDToCheck) || $userIDToCheck != '' ) { echo $userIDToCheck; $sql = "INSERT INTOpnpdb.ruser(userid) VALUES ('$userIDToCheck');"; mysql_query($sql)or die(mysql_error()); echo "Done"; } Output : pi203713 Done But is database it is inserting "0"???

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  • mysql update enums

    - by FFish
    I have a field with enums: 'preview','active','closed' When I query like this: $query = "UPDATE albums SET album_active = preview WHERE album_id = 3"; $result = mysql_query($query); if (!$result) die('Invalid query: ' . mysql_error()); I get : Invalid query: Unknown column 'preview' in 'field list

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  • Making a function for selecting from MySQL, how is mine?

    - by Doug
    This is my first time. I will appreciate any thoughts, tips, and what not. How can I improve this? Ultimately, I don't want so many selects in my script. function mysqlSelectCodes($table, $where, $order, $limit) { $sql = "SELECT * FROM $table WHERE $where ORDER BY $order LIMIT $limit" or die(mysql_error()); }

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  • Django Custom Admin

    - by Harry
    Hello there Currently I have an app with a save method in its models.py . So I would like to change this so the models does not do the save() method, but rather have a separate view that will do this in die admin site. Can you please direct me in the correct direction? Thank you

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  • My php script only reads the first row from mysql and doesn't check the rest of the rows for matches

    - by RobertH
    I'm trying to write a script for users to register to a club, and it does all the validation stuff properly and works great until it gets to the part where its supposed to check for duplicates. I'm not sure what is going wrong. HELP PLEASE!!! Thank you in Advance, <?php mysql_connect ("sqlhost", "username", "password") or die(mysql_error()); mysql_select_db ("databasename") or die(mysql_error()); $errormsgdb = ""; $errordb = "Sorry but that "; $error1db = "Name"; $error2db = "email"; $error3db = "mobile number"; $errordbe = " is already registered"; $pass1db = "No Matching Name"; $pass2db = "No Matching Email"; $pass3db = "No Matching Mobile"; $errorcount = 0; $qResult = mysql_query ("SELECT * FROM table"); $nRows = mysql_num_rows($qResult); for ($i=1; $i< $nRows+1; $i++){ $result = mysql_query("SELECT id,fname,lname,dob,email,mobile,agree,code,joindate FROM table WHERE fname = '$ffname"); if ($result > 0) { $errorcount = $errorcount++; $passdb = 0; $errormsgdb = $error1db; echo "<div class=\"box red\">$errordb $errormsgdb } else { $pass = 1; $errormsgdb = $pass1db; echo "<div class=\"box green\">$errormsgdb</div><br />"; } //--------------- Check if DB checks returned errors ------------------------------------> if($errorcount <= 0){ $dobp = $_REQUEST['day'].'/'.$_REQUEST['month'].'/'.$_REQUEST['year']; $dob = $_REQUEST['year'].$_REQUEST['month'].$_REQUEST['day']; //header('Location: thankyou.php?ffname='.$ffname.'&flname='.$flname.'&dob='.$dob.'&femail='.$femail.'&fmobile='.$fmobile.'&agree='.$agree.'&code='.$code.'&dobp='.$dobp); echo "<div class='box green'>Form completed! Error Count = $errorcount</div>"; } else { echo "<div class='box red'>There was an Error! Error Count = $errorcount</div>"; } } ?>

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  • session variable values are not being passed between pages

    - by ravi nankani
    hi, i am a little new to php and although i have managed to pass values of session variables before this piece of code is leaving me puzzled <form action="team_reg2.php" method="post" name="form1" class="cent" id="form1"> Team Registration "; print "member$i"; print "\n"; print "\n"; print "Please enter only id\n"; } ? now this will pass via post to team_reg2.php echo " please note your team id is 1 "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } else { $str="select * from $query where ("; for($i=1;$i<=$num;$i++) { $name='mem'.$i; $text="p_id='$_POST[$name]'"; if($i==1) $str=$str.$text; else $str=$str.' or '.$text; } $str=$str.')'; $query2=$str; echo "$str"; // echo "$query2"; $que=mysql_query($query2,$con) or die(mysql_error()); $num=mysql_num_rows($que); if($num!=0) { while($result=mysql_fetch_array($que)) { echo "$result[p_id] is already registered in team $result[t_id]"; } //include("reg_team.html"); } else if($num==0) { //echo $query; $query2="select max(t_id) from $query"; $que=mysql_query($query2,$con) or die(mysql_error()); //echo "$que"; $result=mysql_fetch_array($que); $max=$result['max(t_id)']; $max++; $num=$_SESSION['max_team']; for($i=1;$i<=$num;$i++) { $name='mem'.$i; if($_POST[$name]!="") { $query2="insert into $query values($max,'$_POST[$name]')"; $que=mysql_query($query2,$con); } } echo " please note your team id is $max "; echo " your team members are : "; for($i=1;$i<=$num;$i++) { $name='mem'.$i; echo "$_POST[$name]"; } } } ? i have done session_start(); at the beginning of the page itself. The problem is that echoing $_SESSION variables in second file is not printing anything. someone please explain me whats going on. thank you

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  • recursion resulting in extra unwanted data

    - by spacerace
    I'm writing a module to handle dice rolling. Given x die of y sides, I'm trying to come up with a list of all potential roll combinations. This code assumes 3 die, each with 3 sides labeled 1, 2, and 3. (I realize I'm using "magic numbers" but this is just an attempt to simplify and get the base code working.) int[] set = { 1, 1, 1 }; list = diceroll.recurse(0,0, list, set); ... public ArrayList<Integer> recurse(int index, int i, ArrayList<Integer> list, int[] set){ if(index < 3){ // System.out.print("\n(looping on "+index+")\n"); for(int k=1;k<=3;k++){ // System.out.print("setting i"+index+" to "+k+" "); set[index] = k; dump(set); recurse(index+1, i, list, set); } } return list; } (dump() is a simple method to just display the contents of list[]. The variable i is not used at the moment.) What I'm attempting to do is increment a list[index] by one, stepping through the entire length of the list and incrementing as I go. This is my "best attempt" code. Here is the output: Bold output is what I'm looking for. I can't figure out how to get rid of the rest. (This is assuming three dice, each with 3 sides. Using recursion so I can scale it up to any x dice with y sides.) [1][1][1] [1][1][1] [1][1][1] [1][1][2] [1][1][3] [1][2][3] [1][2][1] [1][2][2] [1][2][3] [1][3][3] [1][3][1] [1][3][2] [1][3][3] [2][3][3] [2][1][3] [2][1][1] [2][1][2] [2][1][3] [2][2][3] [2][2][1] [2][2][2] [2][2][3] [2][3][3] [2][3][1] [2][3][2] [2][3][3] [3][3][3] [3][1][3] [3][1][1] [3][1][2] [3][1][3] [3][2][3] [3][2][1] [3][2][2] [3][2][3] [3][3][3] [3][3][1] [3][3][2] [3][3][3] I apologize for the formatting, best I could come up with. Any help would be greatly appreciated. (This method was actually stemmed to use the data for something quite trivial, but has turned into a personal challenge. :) edit: If there is another approach to solving this problem I'd be all ears, but I'd also like to solve my current problem and successfully use recursion for something useful.

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  • Allow users to pull temporary data then delete table?

    - by JM4
    I don't know the best way to title this question but am trying to accomplish the following goal: When a client logs into their profile, they are presented with a link to download data from an existing database in CSV format. The process works, however, I would like for this data to be 'fresh' each time they click the link so my plan was - once a user has clicked the link and downloaded the CSV file, the database table would 'erase' all of its data and start fresh (be empty) until the next set of data populated it. My EXISTING CSV creation code: <?php $host = 'localhost'; $user = 'username'; $pass = 'password'; $db = 'database'; $table = 'tablename'; $file = 'export'; $link = mysql_connect($host, $user, $pass) or die("Can not connect." . mysql_error()); mysql_select_db($db) or die("Can not connect."); $result = mysql_query("SHOW COLUMNS FROM ".$table.""); $i = 0; if (mysql_num_rows($result) > 0) { while ($row = mysql_fetch_assoc($result)) { $csv_output .= $row['Field'].", "; $i++; } } $csv_output .= "\n"; $values = mysql_query("SELECT * FROM ".$table.""); while ($rowr = mysql_fetch_row($values)) { for ($j=0;$j<$i;$j++) { $csv_output .= '"'.$rowr[$j].'",'; } $csv_output .= "\n"; } $filename = $file."_".date("Y-m-d",time()); header("Content-type: application/vnd.ms-excel"); header("Content-disposition: csv" . date("Y-m-d") . ".csv"); header( "Content-disposition: filename=".$filename.".csv"); print $csv_output; exit; ?> any ideas?

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  • problem with get http request from IPhone

    - by user317192
    Hi, I am writing a sample PHP Web Service that is sending GET Http request from the iphone to the web server. The server side code is returning JSON Data to iphone, the server side code looks like: function getUsers(){ $con=mysql_connect("localhost","root","123456") or die(mysql_error()); if(!mysql_select_db("eventsfast",$con)) { echo "Unable to connect to DB"; exit; } $sql="SELECT * from users"; $result=mysql_query($sql); if(!$result) { die('Could not successfully run query Error:'.mysql_error()); } $data = array(); while($row = mysql_fetch_assoc($result)){ $data['username'][] = $row['username']; $data['password'][]= $row['password']; } mysql_close($con); //print_r(json_encode($data)); //return (json_encode($data)); return json_encode('success'); } getUsers(); ? Its a simple code that Fetches all the data from the user table and send it to the iphone application. *****************************************************IPHONE APPLICATION (void)viewDidLoad { [super viewDidLoad]; responseData = [[NSMutableData data] retain]; NSURLRequest *request = [NSURLRequest requestWithURL:[NSURL URLWithString:@"http://localhost:8888/GetData.php"]]; [[NSURLConnection alloc] initWithRequest:request delegate:self]; } (void)connection:(NSURLConnection *)connection didReceiveResponse:(NSURLResponse *)response { [responseData setLength:0]; } (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data { [responseData appendData:data]; } (void)connection:(NSURLConnection *)connection didFailWithError:(NSError *)error { label.text = [NSString stringWithFormat:@"Connection failed: %@", [error description]]; } (void)connectionDidFinishLoading:(NSURLConnection *)connection { [connection release]; NSString *responseString = [[NSString alloc] initWithData:responseData encoding:NSUTF8StringEncoding]; [responseData release]; NSError *error; SBJSON *json = [[SBJSON new] autorelease]; NSArray *luckyNumbers = [json objectWithString:responseString error:&error]; [responseString release]; if (luckyNumbers == nil) label.text = [NSString stringWithFormat:@"JSON parsing failed: %@", [error localizedDescription]]; else { NSMutableString *text = [NSMutableString stringWithString:@"Lucky numbers:\n"]; for (int i = 0; i < [luckyNumbers count]; i++) [text appendFormat:@"%@\n", [luckyNumbers objectAtIndex:i]]; NSLog(text); label.text = text; } } ********************PROBLEM**************** The problem is that nothing is coming on iphone side of the application........... the response doesn't contains anything.............. Please help..............

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  • How do I defer execution of some Ruby code until later and run it on demand in this scenario?

    - by Kyle Kaitan
    I've got some code that looks like the following. First, there's a simple Parser class for parsing command-line arguments with options. class Parser def initialize(&b); ...; end # Create new parser. def parse(args = ARGV); ...; end # Consume command-line args. def opt(...); ...; end # Declare supported option. def die(...); ...; end # Validation handler. end Then I have my own Parsers module which holds some metadata about parsers that I want to track. module Parsers ParserMap = {} def self.make_parser(kind, desc, &b) b ||= lambda {} module_eval { ParserMap[kind] = {:desc => "", :validation => lambda {} } ParserMap[kind][:desc] = desc # Create new parser identified by `<Kind>Parser`. Making a Parser is very # expensive, so we defer its creation until it's actually needed later # by wrapping it in a lambda and calling it when we actually need it. const_set(name_for_parser(kind), lambda { Parser.new(&b) }) } end # ... end Now when you want to add a new parser, you can call make_parser like so: make_parser :db, "login to database" do # Options that this parser knows how to parse. opt :verbose, "be verbose with output messages" opt :uid, "user id" opt :pwd, "password" end Cool. But there's a problem. We want to optionally associate validation with each parser, so that we can write something like: validation = lambda { |parser, opts| parser.die unless opts[:uid] && opts[:pwd] # Must provide login. } The interface contract with Parser says that we can't do any validation until after Parser#parse has been called. So, we want to do the following: Associate an optional block with every Parser we make with make_parser. We also want to be able to run this block, ideally as a new method called Parser#validate. But any on-demand method is equally suitable. How do we do that?

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  • Can IF be used to start a MySQL query?

    - by Littledot
    Hi there, I have a query that looks like this: mysql_query("IF EXISTS(SELECT * FROM predict WHERE uid=$i AND bid=$j) THEN UPDATE predict SET predict_tfidf=$predict_tfidf WHERE uid=$i AND bid=$j ELSE INSERT INTO predict (uid, bid, predict_tfidf) VALUES('$i','$j','$predict_tfidf') END IF")or die(mysql_error()); But it dies and mysql tells me to check the syntax near IF EXISTS(....) Can we not use an IF statement to start a mysql query? Thank you in advance.

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