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  • CakePHP Form Helper Database Interaction

    - by xtine
    Currently I am developing a CakePHP that will list various businesses. In the database, there is a table for businesses that lists them like so: id | name | address | city | state | state_id | zip | url The state column are abbreviations of states (for listing purposes) CA, AK, FL, etc and the state_id matches up with the ids in the states table: id | name | state_abbr I have an admin_add.ctp template with form helpers for inserting new businesses. For entering a state for a business I am going to have a pull down that lists all the states. However, how do I make the database insert so it will know how to add the state abbreviation and state id when I submit the form to add the business?

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  • How many indexes will actually get used?

    - by Ender
    I'm writing a page that does very simple search queries, resulting in something like: SELECT * FROM my_table WHERE A in (a1, a2, a3) AND B in (b1, b2) AND C in (c1, c2, c3, c4) AND And so on for a variable number of columns, usually ~5. If I create a separate index for each column (one for A, one for B, one for C, not (A,B,C)), will all of them be used in the above query?

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  • Sort database entries via a dropdown list

    - by Lin
    Hello! I'm curious if anyone could possibly help me, because I can't find anything exactly related to it anywhere, and it's driving me nuts. I'd like to have a dropdown list on a page, that will give the visitor the option to sort all entries by year. I have entries from i.e. 2001, 2005, 2009, 2010. The years should be displayed in the dropdown, so the visitor can easily just select all entries dated 2001 if they want. The year for each entry is located in the one database table I have. In other words, I simply want a "sort by" dropdown that you can see on pretty much any shopping site nowadays. But with set years. Thanks in advance for any replies!

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  • Saving data that is in a table efficiently and also is easy to retrieve and echo back out

    - by Harry
    Information I currently have a table which image is below, Problem I have made this table using ul & li Here is the code http://jsfiddle.net/8j2qe/1/ Question What would be the best way of storing the data in the image and easily displaying it? Keeping in mind that each column can only have 1 entry. Thank you! And any questions will be answered ASAP! EDIT Sorry, I dont think I was clear enough in my initial question. What I am asking is, what is the best way to store and then display this type of data. I want to DISPLAY data from my database to show like it would in the image. Should I have a column in my database for each column on the table, then say either A,B,C or D depending on what column it is in but then how would I display it using PHP in my code provided? Im struggling to find a good way of explaining this, I am sorry.

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  • Wrong logic in If Statement?

    - by Charles
    $repeat_times = mysql_real_escape_string($repeat_times); $result = mysql_query("SELECT `code`,`datetime` FROM `fc` ORDER by datetime desc LIMIT 25") or die(mysql_error()); $output .=""; $seconds = time() - strtotime($fetch_array["datetime"]); if($seconds < 60) $interval = "$seconds seconds"; else if($seconds < 3600) $interval = floor($seconds / 60) . " minutes"; else if($seconds < 86400) $interval = floor($seconds / 3600) . " hours"; else $interval = floor($seconds / 86400) . " days"; while ($fetch_array = mysql_fetch_array($result)) { $fetch_array["code"] = htmlentities($fetch_array["code"]); $output .= "<li><a href=\"http://www.***.com/code=" . htmlspecialchars(urlencode($fetch_array["code"])) . "\" target=\"_blank\">" . htmlspecialchars($fetch_array["code"]) . "</a> (" . $interval . ") ago.</li>"; } $output .=""; return $output; Why is this returning janice (14461 days) instead of janice (15 minutes ago) The datetime function table has the DATETIME type in my table so it's returning a full string for the date.

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  • Comparing date range quarters sql server

    - by CR41G14
    I have a policies in a system PolRef Start End POL123 22/11/2012 23/12/2014 POL212 24/09/2012 23/10/2012 POL214 23/08/2012 29/09/2012 I am asking a user for a reporting date, the user enters 24/10/2012 this becomes @StartDate From this I derive what the quarter is by the month: set @currentMonth = Month(@StartDate) if @currentMonth = 1 or @currentMonth = 2 or @currentMonth = 3 begin set @startmonth = 1 set @endmonth = 3 end if @currentMonth = 4 or @currentMonth = 5 or @currentMonth = 6 begin set @startmonth = 4 set @endmonth = 6 end if @currentMonth = 7 or @currentMonth = 8 or @currentMonth = 9 begin set @startmonth = 7 set @endmonth = 9 end if @currentMonth = 10 or @currentMonth = 11 or @currentMonth = 12 begin set @startmonth = 10 set @endmonth = 12 end I then get a date range: @quarterStartDate = CAST(CAST(YEAR(@StartDate) AS varchar) + '-' + CAST(@startMonth AS varchar) + '-' + '01') AS Date) @quarterEndDate = CAST(CAST(YEAR(@EcdDate) AS varchar) + '-' + CAST(@endMonth AS varchar) + '-' + '31') AS Date) This will give me 01-10-2012 and 31-12-2012. Basically I need a script to only bring back the policies that are in this quarter. The policy doesn't have to span the entire quarter date range, just exist in the quarter date range. The results expected would be PolRef Start End POL123 22/11/2012 23/12/2014 POL212 24/09/2012 23/10/2012 Pol123 appears because it spans over the quarterly date range. Pol212 is there because it expires in that quarter date range. Pol214 does not appear because it neither spans, expires or starts in this quarter. Any help would be greatly appreciated

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  • Unique constraint not created in JPA

    - by homaxto
    I have created the following entity bean, and specified two columns as being unique. Now my problem is that the table is created without the unique constraint, and no errors in the log. Does anyone have an idea? @Entity @Table(name = "cm_blockList", uniqueConstraints = @UniqueConstraint(columnNames = {"terminal", "blockType"})) public class BlockList { @Id @GeneratedValue(strategy = GenerationType.AUTO) private int id; @ManyToOne(cascade = CascadeType.PERSIST) @JoinColumn(name="terminal") private Terminal terminal; @Enumerated(EnumType.STRING) private BlockType blockType; private String regEx; }

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  • PHP reporting error. DB verify how to?

    - by iamfab
    Error reporting Notice: Undefined variable: random_chars in wamp\www\php_sandbox\idgen.php on line 21 Call Stack: # Time Memory Function Location 1 0.0045 678928 {main}( ) ..\idgen.php:0 GPB7446 How do I fix this error? Using this code like an automatic unique id generator. How do I connect to DB to verify code is truly unique before allowing it to be assigned to a user creating a new account? Thanks <?php $characters = array( "A","B","E","F","G","H","J","K","M","N","P","R","S","T","W","X","Y","Z"); $keys = array(); while(count($keys) < 3) { $x = mt_rand(0, count($characters)-1); if(!in_array($x, $keys)) { $keys[] = $x; } } foreach($keys as $key){ $random_chars .= $characters[$key];} $randNum = rand(2327,9987); $randLet = rand(2327,9987); echo $random_chars . $randNum; ?>

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  • How trasmit a Dictionary in a jsons form

    - by xRobot
    I have a dictionary in jsons form like this: $user = "{ name: Mary , born: 1963, money: 213 }"; I need to pass it throught this field: <input type="hidden" name="custom" value="" > and then insert it in the db: INSERT INTO user ( name, born, money ) VALUE ( $name, $born, $money ) How can I do that ?

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  • How to UNION ALL two SELECT statements?

    - by Lisa
    I have 2 tables, one looks like this: TABLE ONE id | Last Name | First Name | Username | Password | Secret Question and another that looks like this: TABLE TWO id | Hobby | Country | I want to combine a Select statement that grabs data from both tables and output the results. The following code: $select = mysql_query(" SELECT * FROM table_one WHERE Username = 'Bob' UNION ALL SELECT * FROM table_two WHERE Hobby = 'Baseball' "); while ($return = mysql_fetch_assoc($select)) { $userName = $return['Username']; $hobby = $return['Hobby']; } echo "$userName likes $hobby"; results in a The used SELECT statements have a different number of columns error, what am I doing wrong?

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  • 3 small PHP errors I cannot decipher

    - by Dave
    *Notice: Use of undefined constant _ - assumed '_' in /.../uploader.php on line 45* Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Notice: Undefined index: approve in /.../uploader.php on line 81 Line 81 - the second last line here $query = sprintf("INSERT INTO `$db_name`.`the_table` (`id` , `name` , `photo` , `email` , `date` , `code` , `subscribe` , `approve` , `created` ) VALUES ( NULL , '%s', '%s', '%s', '%s', '%s', '%s', '1', CURRENT_TIMESTAMP );", mysql_real_escape_string($_POST['name']), mysql_real_escape_string($newname), mysql_real_escape_string($_POST['email']), mysql_real_escape_string($date), mysql_real_escape_string($_POST['code']), mysql_real_escape_string($subscribe), mysql_real_escape_string($_POST['approve']) ); Warning: Cannot modify header information - headers already sent by (output started at /.../uploader.php:45) in/.../uploader.php on line 102 Line 45 $newname = str_replace(array(' ', '&'), array('_', 'and'), trim( strip_tags( $_POST['name'] ) ) ) . _ . $formKey->generateKey() . '_' . time() . '.jpg'; Line 102 - the third line here if ($success == 'Done') { $page = 'uploader'; header('Location: ./thanks.php'); } else { echo "error"; }

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  • Doctrine 1.2 Column Naming Conventions for Many To Many Relationships

    - by Alan Storm
    I'm working with an existing database schema, and trying to setup two Doctrine models with a Many to Many relationship, as described in this document When creating tables from scratch, I have no trouble getting this working. However, the existing join tables use a different naming convention that what's described in the Doctrine document. Specifically Table 1 -------------------------------------------------- table_1_id ....other columns.... Table 2 -------------------------------------------------- table_2_id ....other columns.... Join Table -------------------------------------------------- fktable1_id fktable_2_id Basically, the previous developers prefaced all forign keys with an fk. From the examples I've seen and some brief experimenting with code, it appears that Doctrine 1.2 requires that the join table use the same column names as the tables it's joining in Is my assumption correct? If so, has the situation changed in Doctrine 2? If the answers to either of the above are true, how do you configure the models so that all the columns "line up"

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  • Where binary in SQL

    - by fire
    I have an SQL statement: SELECT * FROM customers WHERE BINARY login='xxx' AND password='yyyy' There are no blob/binary fields in the table, do I need the BINARY after the WHERE what else does it do?

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  • how to add an ajax jQuery code, that return a row from php file [DB] and then change the value of input text?

    - by Nisreen KH
    //this is a code in php which is fetch a record from database <?php include("dbconn.inc"); $data=mysql_query("SELECT `subtitle`, `mian-title`, `page_num`, `note_path`, `flash_path` FROM `main-page` WHERE `page_num` =".$r." LIMIT 1"); echo $data; if (mysql_num_rows($data) == 0) { echo "No rows found, nothing to print so am exiting"; exit; } while ($row = mysql_fetch_assoc($data)) { echo $row['page_num']; } include("close.php"); ?> //and this is a code in html <form method="post" action="data.php"> <input name="Button1" type="submit" value="&lt;&lt;" /> <input name="test" style="width: 31px; height: 23px" type="text" /> // this is a value of page_num in DB. <input name="Button2" type="submit" value="&gt;&gt;" > </form> //i want to add an ajax code to retrieve the record from php code, and then change the input values depends on returned data ,and also to prevent refreshing the page always!!

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  • Separating Variables Inside an Array

    - by Jake Avila Talledo
    Hey i have an array an I need to separate each value so it would be something like this $arry = array(a,b,c,d,e,f) $point1 = (SELECT distance FROM Table WHERE Origin = a AND Destination = b); $point2 = (SELECT distance FROM Table WHERE Origin = b AND Destination = c); $point3 = (SELECT distance FROM Table WHERE Origin = c AND Destination = d); $point4 = (SELECT distance FROM Table WHERE Origin = d AND Destination = e); $point5 = (SELECT distance FROM Table WHERE Origin = e AND Destination = f); $point6 = (SELECT distance FROM Table WHERE Origin = f AND Destination = g); $point7 = (SELECT distance FROM Table WHERE Origin = g AND Destination = f); $total_trav = $point1+$point2+$point3+$point4+$point5+$point6+$point7

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  • mysqli_query SELECT FROM WHERE [ partial match ] ?

    - by user296516
    Hi guys, I have a database that a time filed that is stored in this format "2010.06.04. | 18:53 01". What I need is to select rows that have a specific date, for example "2010.06.04." Right now I am doing it my first selecting all rows and then looping through them and adding ones with the specified date to a new array. Maybe there is an easier way to do it and I somehow can select it using mysqli_query? Thanks!

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  • client computer name

    - by Anup Prakash
    After getting the client(Website user) IP address. Now i want to go one step ahead by knowing the Computer name of the user. So, agian i need help from my question viewer to help me regarding computer name of the client(website user). I tried it by myself using google. But at last i thought it is better to ask to all of you who have better and best answers. Thanx again to see my query. And much much thanx for them who are answering this question.

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  • self join to select consecutive numbers

    - by shantanuo
    CREATE TABLE `mybug` ( `SEAT_NO` decimal(2,0) NOT NULL, `ROW_NO` decimal(2,0) NOT NULL, `COL_NO` decimal(2,0) NOT NULL ) ENGINE=MyISAM DEFAULT CHARSET=latin1; INSERT INTO `mybug` VALUES ('1','1','1'),('26','7','2'),('31','8','2'),('32','8','1'),('33','9','1'),('34','9','2'),('35','9','5'),('36','9','6'),('37','10','6'),('38','10','5'),('39','10','2'),('40','10','1'),('41','11','1'),('42','11','2'),('43','11','4'),('44','11','5'); +---------+--------+--------+ | SEAT_NO | ROW_NO | COL_NO | +---------+--------+--------+ | 1 | 1 | 1 | | 26 | 7 | 2 | | 31 | 8 | 2 | | 32 | 8 | 1 | | 33 | 9 | 1 | | 34 | 9 | 2 | | 35 | 9 | 5 | | 36 | 9 | 6 | | 37 | 10 | 6 | | 38 | 10 | 5 | | 39 | 10 | 2 | | 40 | 10 | 1 | | 41 | 11 | 1 | | 42 | 11 | 2 | | 43 | 11 | 4 | | 44 | 11 | 5 | +---------+--------+--------+ 16 rows in set (0.00 sec) In the above chart, I need to select 2 seats those are in the same row AND column numbers are next to each other. For e.g. Seat Numbers 38 & 39 can not be issued even if both the seats are from the same row because the column numbers 2 & 5 are not adjacent. The expected results are as follows: 31 33 35 37 39 41 43 These are the starting numbers and the next seat will be automatically booked as well. for e.g. 31 & 32

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  • How do detect that transaction has already been started?

    - by xelurg
    I am using Zend_Db to insert some data inside a transaction. My function starts a transaction and then calls another method that also attempts to start a transaction and of course fails(I am using MySQL5). So, the question is - how do I detect that transaction has already been started? Here is a sample bit of code: try { Zend_Registry::get('database')->beginTransaction(); $totals = self::calculateTotals($Cart); $PaymentInstrument = new PaymentInstrument; $PaymentInstrument->create(); $PaymentInstrument->validate(); $PaymentInstrument->save(); Zend_Registry::get('database')->commit(); return true; } catch(Zend_Exception $e) { Bootstrap::$Log->err($e->getMessage()); Zend_Registry::get('database')->rollBack(); return false; } Inside PaymentInstrument::create there is another beginTransaction statement that produces the exception that says that transaction has already been started.

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  • Multiple left joins, how to output in php

    - by Dan
    I have 3 tables I need to join. The contracts table is the main table, the 'jobs' and 'companies' table are extra info that can be associated to the contracts table. so, since I want all entries from my 'contracts' table, and the 'jobs' and 'companies' data only if it exists, I wrote the query like this.... $sql = "SELECT * FROM contracts LEFT JOIN jobs ON contracts.job_id = jobs.id LEFT JOIN companies ON contracts.company_id = companies.id ORDER BY contracts.end_date"; Now how would I output this in PHP? I tried this but kept getting an undefined error "Notice: Undefined index: contracts.id"... $sql_result = mysql_query($sql,$connection) or die ("Fail."); if(mysql_num_rows($sql_result) > 0){ while($row = mysql_fetch_array($sql_result)) { $contract_id = stripslashes($row['contracts.id']); $job_number = stripslashes($row['jobs.job_number']); $company_name = stripslashes($row['companies.name']); ?> <tr id="<?=$contract_id?>"> <td><?=$job_number?></td> <td><?=$company_name?></td> </tr> <? } }else{ echo "No records found"; } Any help is appreciated.

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  • Symfony 1.4: Deleting a sfGuardUser

    - by Tom
    Hi, I'm having some trouble with the following... I have a sfGuardUser table set up normally, and it has a one-to-one relationship with a Profile table, which contains some additional user info. When a user wants to delete themselves from the site, I'd like to retain their info in the Profile table for various purposes BUT delete the sfGuardUser in order to keep that table cleaner/shorter (not just set it to inactive). I was under the impression that I could set the FK in the Profile table to NULL and then delete the sfGuardUser, but it seems the FK-constraint fails. Indeed, it seems I can't delete either and the queries fail: If I try to delete the sfGuardUser, the Profile table will have an invalid FK If I try to delete a Profile, the sfGuardUser will have an invalid FK Other than leaving outdated sfGuardUsers and Profiles in these tables, or having to use a cascaded delete to get rid of both, can anyone tell me if there's any other way around this? Thank you.

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  • Loop results executing twice

    - by ozzysmith
    I creating a simple site with PHP where the users can submit blogs and other users (who are logged in) can post comments on them. I have made a link called "comments" below each blog that when clicked will show / hide all the comments relevant to the specific blog (also if the user is logged in, it will show a form field in which they can submit new comments). So basically each blog will have multiple comments. I have done two different codes for this but they both have the same problem that each comment appears twice (everything else works fine). Could anyone point out why? mysql_select_db ("ooze"); $result = mysql_query ("select * from blog") or die(mysql_error()); $i = 1; while($row = mysql_fetch_array($result)) { echo "<h1>$row[title]</h1>"; echo "<p class ='second'>$row[blog_content]</p> "; echo "<p class='meta'>Posted by .... &nbsp;&bull;&nbsp; $row[date] &nbsp;&bull;&nbsp; <a href='#' onclick=\"toggle_visibility('something$i'); return false\">Comments</a><div id='something$i' style='display: none;'>"; $i++; $a = $row["ID"]; $result2 = mysql_query ("select * from blog, blogcomment where $a=blogID") or die(mysql_error()); while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username]</p><p>said:</p> <p>$sub[comment]</p>"; } if ( isset ($_SESSION["gatekeeper"])) { echo '<form method="post" name="result_'.$row["ID"].'" action="postcomment.php"><input name="ID" type = "hidden" value = "'.$row["ID"].'" /><input name="comment" id="comment" type="text" style="margin-left:20px;"/><input type="submit" value="Add comment" /></form>'; } else { echo '<p class="third"><a href="register.html">Signup </a>to post a comment</p>'; } echo "</div>"; } mysql_close($conn); //second version of inner loop:// if ( isset ($_SESSION["gatekeeper"])) { while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username] said:</p> <p>$sub[comment]</p>"; } echo '<form method="post" name="result_'.$row["ID"].'" action="postcomment.php"><input name="ID" type = "hidden" value = "'.$row["ID"].'" /><input name="comment" id="comment" type="text" style="margin-left:20px;"/><input type="submit" value="Add comment" /></form>'; } else { while($sub = mysql_fetch_array($result2)) { echo "<p class='third' >$sub[commentdate] &nbsp;&bull;&nbsp; $sub[username] said:</p> <p>$sub[comment]</p>"; } echo '<p class="third"><a href="register.html">Signup </a>to post a comment</p>'; } echo "</div>"; } mysql_close($conn);

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