Search Results

Search found 14142 results on 566 pages for 'mysql workbench'.

Page 379/566 | < Previous Page | 375 376 377 378 379 380 381 382 383 384 385 386  | Next Page >

  • laravel multiple where clauses within a loop

    - by user1424508
    Pretty much I want the query to select all records of users that are 25 years old AND are either between 150-170cm OR 190-200cm. I have this query written down below. However the problem is it keeps getting 25 year olds OR people who are 190-200cm instead of 25 year olds that are 150-170 OR 25 year olds that 190-200cm tall. How can I fix this? thanks $heightarray=array(array(150,170),array(190,200)); $user->where('age',25); for($i=0;$i<count($heightarray);i++){ if($i==0){ $user->whereBetween('height',$heightarray[$i]) }else{ $user->orWhereBetween('height',$heightarray[$i]) } } $user->get(); Edit: I tried advanced wheres (http://laravel.com/docs/queries#advanced-wheres) and it doesn't work for me as I cannot pass the $heightarray parameter into the closure. from laravel documentation DB::table('users') ->where('name', '=', 'John') ->orWhere(function($query) { $query->where('votes', '>', 100) ->where('title', '<>', 'Admin'); }) ->get();

    Read the article

  • Selecting rows distinctively

    - by noway
    Lets assume my database table structure is something like | items | weight | |============|==========| | item_1 | 50 | | item_2 | 90 | | item_2 | 45 | | item_2 | 60 | | item_3 | 40 | In the select statement, I want to show an item only for once with the highest weight also ordered by height. So the result should be : | items | weight | |============|==========| | item_2 | 90 | | item_1 | 50 | | item_3 | 40 | I tried something like SELECT DISTINCT items, weight FROM mytable ORDER BY weight DESC but it didn't work because the results are actually distinct. How can I make that selection?

    Read the article

  • In SQL, a Join is actually an Intersection? And it is also a linkage or a "Sideway Union"?

    - by Jian Lin
    I always thought of a Join in SQL as some kind of linkage between two tables. For example, select e.name, d.name from employees e, departments d where employees.deptID = departments.deptID In this case, it is linking two tables, to show each employee with a department name instead of a department ID. And kind of like a "linkage" or "Union" sideway". But, after learning about inner join vs outer join, it shows that a Join (Inner join) is actually an intersection. For example, when one table has the ID 1, 2, 7, 8, while another table has the ID 7 and 8 only, the way we get the intersection is: select * from t1, t2 where t1.ID = t2.ID to get the two records of "7 and 8". So it is actually an intersection. So we have the "Intersection" of 2 tables. Compare this with the "Union" operation on 2 tables. Can a Join be thought of as an "Intersection"? But what about the "linking" or "sideway union" aspect of it?

    Read the article

  • fetch some data from two tables

    - by user1753971
    i have site like imdb and we provide movie information sin site..and our website have option to rate all movies for every users. I have two tables 1 . imdb (its for store movie details) id,name,actors,vote 2. ratings (its for store users rating details) id,rating_id(its same as id from first table),rating_num,IP now what am doing is..when anyone rating a movie take the avg of that movie rating by using rating tables (total ratings/number of ratings) and insert that value into "vote" column in first table..my demands this..thats why done like this.. Now my problem is..i want to fetch top rated movies..i mean in vote column which movie have top rating which want to list and one more condition is that that movie should rated by 10 users(use ratings table for that) thanks in advance

    Read the article

  • Random Alpha numeric generator

    - by AAA
    Hi, I want to give our users in the database a unique alpha-numeric id. I am using the code below, will this always generate a unique id? Below is the old and updated version of the code: New php: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid("something",true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Old PHP: // Generate Guid function NewGuid() { $s = strtoupper(md5(uniqid("something",true))); $guidText = substr($s,0,8) . '-' . substr($s,8,4) . '-' . substr($s,12,4). '-' . substr($s,16,4). '-' . substr($s,20); return $guidText; } // End Generate Guid $Guid = NewGuid(); echo $Guid; echo "<br><br><br>"; Will this first code guarantee uniqueness?

    Read the article

  • my sql insert query not working

    - by Piyush
    I am inserting userId.It is displaying correct but inserting 0 in spite of actual userId. mycode- If(! empty($userIDToCheck) || $userIDToCheck != '' ) { echo $userIDToCheck; $sql = "INSERT INTOpnpdb.ruser(userid) VALUES ('$userIDToCheck');"; mysql_query($sql)or die(mysql_error()); echo "Done"; } Output : pi203713 Done But is database it is inserting "0"???

    Read the article

  • How would i output a message that says "values inserted to table" ?

    - by ranlo
    <?php error_reporting(0); $con=mysql_connect("localhost","root",""); if (!$con) { die('could not connect:'.mysql_error()); } mysql_select_db("final?orgdocs",$con); $org_name = $_POST["org_name"]; $org_type = $_POST["org_type"]; $org_code = $_POST["org_code"]; $description = $_POST["description"]; $stmt = "INSERT INTO organization VALUES('".$org_name."','".$org_type."','".$org_code."','".$description."')"; $result = mysql_query("SELECT * FROM organization WHERE org_name = '$org_name' "); echo '<TABLE BORDER = "1">'; $result1 = $result; while ($row = mysql_fetch_array($result1)){ echo '<TR>'.'<TD>'.'Organization Name'.'</TD>'.'<TD>'.'Organization Type'.'</TD>'.'<TD>'.'Organization Code'.'</TD>'.'<TD>'.'Description'.'</TD>'.'<TD>'.'Constitution'.'</TD>'; echo '</TR>'; echo '<TR>'.'<TD>'.$row['org_name'].'</TD>'.'<TD>'.$row['org_type'].'</TD>'; echo '<TD>'.$row['org_code'].'</TD>'.'<TD>'.$row['description'].'</TD>'.'<TD>'; echo '</TR>'; } echo '</TABLE>'; ?>

    Read the article

  • Adding to database. No repeat on refresh

    - by kevstarlive
    I have this code: Episode.php <?$feedback = new feedback; $articles = $feedback->fetch_all(); if (isset($_POST['name'], $_POST['post'])) { $cast = $_GET['id']; $name = $_POST['name']; $email = $_POST['email']; $post = nl2br ($_POST['post']); $ipaddress = $_SERVER['REMOTE_ADDR']; if (empty($name) or empty($post)) { $error = 'All Fields Are Required!'; }else{ $query = $pdo->prepare('INSERT INTO comments (cast, name, email, post, ipaddress) VALUES(?, ?, ?, ?, ?)'); $query->bindValue(1, $cast); $query->bindValue(2, $name); $query->bindValue(3, $email); $query->bindValue(4, $post); $query->bindValue(5, $ipaddress); $query->execute(); } }?> <div align="center"> <strong>Give us your feedback?</strong><br /><br /> <?php if (isset($error)) { ?> <small style="color:#aa0000;"><?php echo $error; ?></small><br /><br /> <?php } ?> <form action="episode.php?id=<?php echo $data['cast_id']; ?>" method="post" autocomplete="off" enctype="multipart/form-data"> <input type="text" name="name" placeholder="Name" /> / <input type="text" name="email" placeholder="Email" /><small style="color:#aa0000;">*</small><br /><br /> <textarea rows="10" cols="50" name="post" placeholder="Comment"></textarea><br /><br /> <input type="submit" onclick="myFunction()" value="Add Comment" /> <br /><br /> <small style="color:#aa0000;">* <b>Email will not be displayed publicly</b></small><br /> </form> </div> Include.php class feedback { public function fetch_all(){ global $pdo; $query = $pdo->prepare("SELECT * FROM comments"); $query->bindValue(1, $cast); $query->execute(); return $query->fetchAll(); } } This code updates to the database as it is suppose to. But after submission it reloads the current page as mentioned in the form action. But when I refresh the page to see the comment being added it asks to re submit. If I hit submit then the comment adds again. How can I stop this from happening? Maybe I could hide the comment box and display a thank you message but that would not stop a repeat entry. Please help. Thank you. Kev

    Read the article

  • Broken count(*) after adding LEFT JOIN

    - by Iain Urquhart
    Since adding the LEFT JOIN to the query below, the count(*) has been returning some strange values, it seems to have added the total rows returned in the query to the 'level': SELECT `n`.*, exp_channel_titles.*, round((`n`.`rgt` - `n`.`lft` - 1) / 2, 0) AS childs, count(*) - 1 + (`n`.`lft` > 1) + 1 AS level, ((min(`p`.`rgt`) - `n`.`rgt` - (`n`.`lft` > 1)) / 2) > 0 AS lower, (((`n`.`lft` - max(`p`.`lft`) > 1))) AS upper FROM `exp_node_tree_6` `n` LEFT JOIN `exp_channel_titles` ON (`n`.`entry_id`=`exp_channel_titles`.`entry_id`), `exp_node_tree_6` `p`, `exp_node_tree_6` WHERE `n`.`lft` BETWEEN `p`.`lft` AND `p`.`rgt` AND ( `p`.`node_id` != `n`.`node_id` OR `n`.`lft` = 1 ) GROUP BY `n`.`node_id` ORDER BY `n`.`lft` I'm totally stumped... Thank you!

    Read the article

  • How do I select column(s) by their "numeric" position in a table?

    - by DulcimerDude
    I am trying to select columns by their "x" position in the table. DBI my $example = $hookup->prepare(qq{SELECT This,That,Condition,"I also want COLUMN-10" FROM tbl LIMIT ? ?}); ###column_number=10 ordinal_position?? $example->execute('2','10') or die "Did not execute"; Is this possible or do I need to run another single select to just that column? One problem I encountered was with a col named "Condition". For some reason, when I tried to select Condition the execute would die. I never attempted but, What if the column name was SELECT? Another note is the table is 75 cols wide and I only need 50 of them. The Col names are pretty verbose so, I would like to just call them by their "position". This would also allow the col names to be changed in the future without having to change the select statement. I am quite the newbie so please explain any answers down to my level. Thanks for any assistance..

    Read the article

  • Moving from dedicated to shared cpanel - any scripts to do all / some of the install tasks ?

    - by mbbcat
    Hi, I have a few hundred phpld sites to move - each has its own cpanel, ( & the target may have shared cpanel) & I can do a full cpanel backup on the original server, but I don't have whm on the current host - the backups are fairly easy to organize but the installs so far means picking through files & setting up db's & mail etc by hand - I am thinking there ought to be an easier ie scripted way to do the installs or at least some parts - can anyone please suggest something ? I would like to migrate the stats at the same time Thanks M

    Read the article

  • Can't use method return value in write context; Not sure where to go from here

    - by Morgan Green
    This is my source for the variable. <?php if ($admin->get_permissions()=3) echo 'Welcome to the Admin Panel'; else echo 'Sorry, You do not have access to this page'; ?> And the code that I'm actually trying to call with the if statement is: public function get_permissions() { $username = $_SESSION['admin_login']; global $db; $info = $db->get_row("SELECT `permissions` FROM `user` WHERE `username` = '" . $db->escape($username) . "'"); if(is_object($info)) return $info->permissions; else return ''; } This should be a simple way to call my pages that the user is authorized for by using an else if statement. Or So I thought

    Read the article

  • second time auto login to twitter using oauth php

    - by JAMES
    Any can tell me how to second time auto connect with twitter from my site. I did... the following CODE if(empty($outh_key_db)){ $token=$_SESSION['oauth_token'] ; $outh_secr_db=$_SESSION['oauth_token_secret']; $con = mysql_connect("localhost","rathin","xxxxxxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_twtbook", $con); mysql_query("UPDATE register SET outh_key = '".$token."', outh_secr='".$outh_secr_db."' WHERE userid='".$loguser_email."'"); mysql_close($con); This code save the outh_token and outh_tk_secret to my DB. But on second time log in to my site I passed the 'outh_token and outh_tk_secret' in session with username. The oauth not authenticate that.... Kindly suggest me.... to make aouth connect to twitter using oauth...if user once(1st time made the) connect twitter

    Read the article

  • Array "tree" creation from db table

    - by Tural Teyyuboglu
    Trying to create array tree for db driven navigation. Getting following errur: array_key_exists() expects exactly 2 parameters, 1 given on line if (!array_key_exists($tree[$parent]['children'][$id])) Function looks like that $tree = array(); $sql = "SELECT id, parent, name FROM menu WHERE parent ... etc.... "; $results = mysql_query($sql) or die(mysql_error()); while(list($id, $parent, $name) = mysql_fetch_assoc($results)) { $tree[$id] = array('name' => $name, 'children' => array(), 'parent' => $parent); if (!array_key_exists($tree[$parent]['children'][$id])) { $tree[$parent]['children'][$id] = $id; } } Db structure How can I fix that? Whats wrong in this function?

    Read the article

  • How can I get all children from a parent row in the same table?

    - by Johnny Freeman
    Let's say I have a table called my_table that looks like this: id | name | parent_id 1 | Row 1 | NULL 2 | Row 2 | NULL 3 | Row 3 | 1 4 | Row 4 | 1 5 | Row 5 | NULL 6 | Row 6 | NULL 7 | Row 7 | 8 8 | Row 8 | NULL 9 | Row 9 | 4 10 | Row 10 | 4 Basically I want my final array in PHP to look like this: Array ( [0] => Array ( [name] => Row 1 [children] => Array ( [0] => Array ( [name] => Row 3 [children] => ) [1] => Array ( [name] => Row 4 [children] => Array ( [0] => Array ( [name] => Row 9 [children] => ) [1] => Array ( [name] => Row 10 [children] => ) ) ) ) ) [1] => Array ( [name] => Row 2 [children] => ) [2] => Array ( [name] => Row 5 [children] => ) [3] => Array ( [name] => Row 6 [children] => ) [4] => Array ( [name] => Row 8 [children] => Array ( [0] => Array ( [name] => Row 7 [children] => ) ) ) ) So, I want it to get all of the rows where parent_id is null, then find all nested children recursively. Now here's the part that I'm having trouble with: How can this be done with 1 call to the database? I'm sure I could do it with a simple select statement and then have PHP make the array look like this but I'm hoping this can be done with some kind of fancy db joining or something like that. Any takers?

    Read the article

  • SQL query for fetching friend list

    - by Bhavyanshu
    I need help with SQL query. I have two tables. One is users and other one is userfriends users table: aid email firstname 1 [email protected] example 2 [email protected] example2 3 [email protected] example3 4 [email protected] example4 userfriends tables: reqid email friendemail status 1 [email protected] [email protected] 1 (example1 is frnds with example2) 2 [email protected] [email protected] 2 (example2 request pending) 3 [email protected] [email protected] 1 (example1 is frnds with example3) 4 [email protected] [email protected] 1 (example1 is frnds with example4) So when status is 2 the add request is pending and at status 1 they are friends. What i want is that i want to retrieve the complete friendlist for user example1. I want to pull out names from users table for corresponding output from previous query to display as friendlist.

    Read the article

  • Better mode for do a select with group by

    - by Luca Romagnoli
    Hi i've wrote a query that works: SELECT `comments`.* FROM `comments` RIGHT JOIN (SELECT MAX( id ) AS id, core_id, topic_id FROM comments GROUP BY core_id, topic_id order by id desc) comm ON comm.id = comments.id LIMIT 10 I want know if is possible and how rewrite it for get better performance. thanks

    Read the article

  • Converting files to blob to save in database

    - by jimbo
    I have an old user site that we are currently updating. The site's users have previously uploaded profile pics that are stored in a directory. I am now wanting to keep these profile images in the database, (easy to backup all data) but am having trouble working out how to do it. There are a lot of tutorials talking about do ing this from files that have just been uploaded and using the tmp name etc, but how can I re-create with files that have already been uploaded? I have looked into $data = file_get_contents($filename); Which seems to create a binary file, but doesn't seem to save in database with: mysql_query("UPDATE profiles SET company_logo = mysql_real_escape_string('".$data."') WHERE id = 1 ") or die(mysql_error());

    Read the article

  • Hibernate Criteria API: get n random rows

    - by hadrien
    I can't figure out how to fetch n random rows from a criteria instance: Criteria criteria = session.createCriteria(Table.class); criteria.add(Restrictions.eq('fieldVariable', anyValue)); ... Then what? I can't find any doc with Criteria API Does it mean I should use HQL instead? Thanx! EDIT: I get the number of rows by: int max = criteria.setProjecxtion(Projections.rowCount()).uniqueResult(); How do I fetch n random rows with indexes between 0 and max? Thx again!

    Read the article

  • PHP - advice for java HashMap alternative in php?

    - by teutara
    I know it is super noob and will be answered in no time, but I could not figure.. sorry for any inconvenience.. Here is the thing: ID colA colB Length 1 seq1 seq11 1 2 seq1 seq11 11 3 seq3 seq33 21 4 seq3 seq33 14 I have a db with this kind of a table, has more than 10M rows. I want to loop though colA first, get the relevant colB value, and check if there are any other occurrences of the same value. For example in colB (seq11) there are 2 occurrences of colA(seq1), this time I have to combine those and output the sum of the length. Similar to this: ID colA colB Length 1 seq1 seq11 12 2 seq3 seq33 35 I am a bit java guy, but because my colleague has written everything in php and this will be just an adding, i need a php solution. With java i would have used hashmap, so that I would have the colA data once and just increment the value of "Length Column".. I know it is not a proper question, but.. Thank you in advance.. $$$$$$$$$$ EDIT $$$$$$$$$$ I tried this query in order to group by occurences: SELECT COUNT(*) SeqName FROM SeqTable GROUP BY SeqName HAVING COUNT(*)>0;

    Read the article

  • Always get the correct datetime?

    - by Jesper Mansa
    I was wandering if there is a way/site/link whith the correct time? Not the servers datetime or the clients datetime. I'm using datetime to count down on my gaming site for when it is the users time to make a play. Users come from all ower the world so using the users client time would not match if its from the US to Europe. Then normally I would use the servers time, but somehow it skips 1.2 hours sometimes? I would like to make sure that everbody makes a timestamp from the same source and that source always is correct! Hoping for help and thanks in advance.

    Read the article

  • show count of rows between 2 dates

    - by hello
    I am trying to show the number of rows that have a created_at date between 2 dates. Here is my code: $result=mysql_query("select * from payments where created_at between '2013/10/01 00:00:00' and '2013/10/30 00:00:00'") or die('You need to add an administrator ' ); $counter = mysql_query("select * from payments where created_at between '2013/10/01 00:00:00' and '2013/10/30 00:00:00'"); $row = mysql_fetch_array($result); $id = $row['id']; $num = mysql_fetch_array($counter); $countjan = $num["id"]; However when i echo (<?php echo"$jan";?>)this shows as 0 any idea how i can get this to work P.s there is 1 row within this date range

    Read the article

< Previous Page | 375 376 377 378 379 380 381 382 383 384 385 386  | Next Page >