Search Results

Search found 3340 results on 134 pages for 'comma operator'.

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

Page 38/134 | < Previous Page | 34 35 36 37 38 39 40 41 42 43 44 45  | Next Page >

  • Avoiding SQL Injection in SQL query with Like Operator using parameters?

    - by MikeJ
    Taking over some code from my predecessor and I found a query that uses the Like operator: SELECT * FROM suppliers WHERE supplier_name like '%'+name+%'; Trying to avoid SQL Injection problem and parameterize this but I am not quite sure how this would be accomplished. Any suggestions ? note, I need a solution for classic ADO.NET - I don't really have the go-ahead to switch this code over to something like LINQ.

    Read the article

  • Can i use a generic implicit or explicit operator? C#

    - by acidzombie24
    How do i change the following statement so it accepts any type instead of long? Now here is the catch, if there is no constructor i dont want it compiling. So if theres a constructor for string, long and double but no bool how do i have this one line work for all of these support types? ATM i just copied pasted it but i wouldnt like doing that if i had 20types (as trivial as the task may be) public static explicit operator MyClass(long v) { return new MyClass(v); }

    Read the article

  • difference between -> and . for member selection operator.

    - by TimothyTech
    in this book i have I'm learning pointers, and i just got done with the chapter about OOP (spits on ground) anyways its telling me i can use a member selection operator like this ( - ). it sayd that is is like the "." except points to objects rather than member objects. whats the difference, it looks like it is used the same way...

    Read the article

  • lambda vs. operator.attrGetter('xxx') as sort key in Python

    - by Paul McGuire
    I am looking at some code that has a lot of sort calls using comparison functions, and it seems like it should be using key functions. If you were to change seq.sort(lambda x,y: cmp(x.xxx, y.xxx)), which is preferable: seq.sort(key=operator.attrgetter('xxx')) or: seq.sort(key=lambda a:a.xxx) I would also be interested in comments on the merits of making changes to existing code that works.

    Read the article

  • lambda vs. operator.attrgetter('xxx') as sort key function in Python

    - by Paul McGuire
    I am looking at some code that has a lot of sort calls using comparison functions, and it seems like it should be using key functions. If you were to change seq.sort(lambda x,y: cmp(x.xxx, y.xxx)), which is preferable: seq.sort(key=operator.attrgetter('xxx')) or: seq.sort(key=lambda a:a.xxx) I would also be interested in comments on the merits of making changes to existing code that works.

    Read the article

  • Input string is not in correct format ternary operator using in grid view .

    - by A.Goutam
    i am using this ternary operator for the display the value but it always says that Input string is not in correct format . <asp:TextBox ID="txtPerOfBase" runat="server" Style="text-align: right;" Text='<%# decimal.Parse(Eval("CommissionableAmountBase").ToString()) == 0 ? Eval("CommissionablePercentBase","{0:N2}"): Eval("CommissionableAmountBase","{0:N2)")%>' Width="80px"></asp:TextBox>

    Read the article

  • C++ template function specialization using TCHAR on Visual Studio 2005

    - by Eli
    I'm writing a logging class that uses a templatized operator<< function. I'm specializing the template function on wide-character string so that I can do some wide-to-narrow translation before writing the log message. I can't get TCHAR to work properly - it doesn't use the specialization. Ideas? Here's the pertinent code: // Log.h header class Log { public: template <typename T> Log& operator<<( const T& x ); template <typename T> Log& operator<<( const T* x ); template <typename T> Log& operator<<( const T*& x ); ... } template <typename T> Log& Log::operator<<( const T& input ) { printf("ref"); } template <typename T> Log& Log::operator<<( const T* input ) { printf("ptr"); } template <> Log& Log::operator<<( const std::wstring& input ); template <> Log& Log::operator<<( const wchar_t* input ); And the source file // Log.cpp template <> Log& Log::operator<<( const std::wstring& input ) { printf("wstring ref"); } template <> Log& Log::operator<<( const wchar_t* input ) { printf("wchar_t ptr"); } template <> Log& Log::operator<<( const TCHAR*& input ) { printf("tchar ptr ref"); } Now, I use the following test program to exercise these functions // main.cpp - test program int main() { Log log; log << "test 1"; log << L"test 2"; std::string test3( "test3" ); log << test3; std::wstring test4( L"test4" ); log << test4; TCHAR* test5 = L"test5"; log << test4; } Running the above tests reveals the following: // Test results ptr wchar_t ptr ref wstring ref ref Unfortunately, that's not quite right. I'd really like the last one to be "TCHAR", so that I can convert it. According to Visual Studio's debugger, the when I step in to the function being called in test 5, the type is wchar_t*& - but it's not calling the appropriate specialization. Ideas? I'm not sure if it's pertinent or not, but this is on a Windows CE 5.0 device.

    Read the article

  • Why does the assignment operator return a value and not a reference?

    - by Nick Lowman
    I saw the example below explained on this site and thought both answers would be 20 and not the 10 that is returned. He wrote that both the comma and assignment returns a value, not a reference. I don't quite understand what that means. I understand it in relation to passing variables into functions or methods i.e primitive types are passed in by value and objects by reference but I'm not sure how it applies in this case. I also understand about context and the value of 'this' (after help from stackoverflow) but I thought in both cases I would still be invoking it as a method, foo.bar() which would mean foo is the context but it seems both result in a function call bar(). Why is that and what does it all mean? var x = 10; var foo = { x: 20, bar: function () {return this.x;} }; (foo.bar = foo.bar)();//returns 10 (foo.bar, foo.bar)();//returns 10

    Read the article

  • Combining two operators in Evil-mode Emacs

    - by Dyslexic Tangent
    In vim I've remapped > and < when in visual mode to >gv and <gv respectively, like so: vnoremap > >gv vnoremap < <gv Since my target for this question are folks experienced with emacs and not vim, what > and < do is indent/dedent visually selected text. What gv does is reselect the previously selected text. These maps cause > and < to indent/dedent and then reselect the previously selected text. I'm trying out emacs with evil-mode and I'd like to do the same, but I'm having some difficulty figuring out how, exactly, to accomplish the automatic reselection. It looks like I need to somehow call evil-shift-right and evil-visual-restore sequentially, but I don't know how to create a map that will do both, so I tried creating my own function which would call both sequentially and map that instead, but it didn't work, possibly due to the fact that both of them are defined, not as functions with defun but instead as operators with evil-define-operator. I tried creating my own operators: (evil-define-operator shift-left-reselect (beg end) (evil-shift-left beg end) (evil-visual-restore)) (evil-define-operator shift-right-reselect (beg end) (evil-shift-right beg end) (evil-visual-restore)) but that doesn't restore visual as expected. A stab in the dark gave me this: (evil-define-operator shift-left-reselect (beg end) (evil-shift-left beg end) ('evil-visual-restore)) (evil-define-operator shift-right-reselect (beg end) (evil-shift-right beg end) ('evil-visual-restore)) but that selects one additional line whenever it is supposed to reselect. For now I've been using the following, which only has the problem where it reselects an additional line in the < operator. (evil-define-operator shift-right-reselect (beg end) (evil-shift-right beg end) (evil-visual-make-selection beg end)) (evil-define-operator shift-left-reselect (beg end) (evil-shift-left beg end) (evil-visual-make-selection beg end)) and I've mapped them: (define-key evil-visual-state-map ">" 'shift-right-reselect) (define-key evil-visual-state-map "<" 'shift-left-reselect) any help / pointers / tips would be greatly appreciated. Thanks in advance.

    Read the article

  • LINQ To SQL exception: Local sequence cannot be used in LINQ to SQL implementation of query operator

    - by pcampbell
    Consider this LINQ To SQL query. It's intention is to take a string[] of search terms and apply the terms to a bunch of different fields on the SQL table: string[] searchTerms = new string[] {"hello","world","foo"}; List<Cust> = db.Custs.Where(c => searchTerms.Any(st => st.Equals(c.Email)) || searchTerms.Any(st => st.Equals(c.FirstName)) || searchTerms.Any(st => st.Equals(c.LastName)) || searchTerms.Any(st => st.Equals(c.City)) || searchTerms.Any(st => st.Equals(c.Postal)) || searchTerms.Any(st => st.Equals(c.Phone)) || searchTerms.Any(st => c.AddressLine1.Contains(st)) ) .ToList(); An exception is raised: Local sequence cannot be used in LINQ to SQL implementation of query operators except the Contains() operator Question: Why is this exception raised, and how can the query be rewritten to avoid this exception?

    Read the article

  • Why does the minus operator give different result than the TIMESTAMPDIFF() function in mysql?

    - by f3r3nc
    Since TIMESTAMP in mysql is stored as a 32bit value representing the time interval from 1970-jan-1 0:00:00 in seconds, I assumed that using minus (-) operator on TIMESTAMP values would give the difference of these values in seconds. Actually not: +---------------------------------------------------------------------+ | TIMESTAMP("2010-04-02 10:30:00") - TIMESTAMP("2010-04-02 10:29:59") | +---------------------------------------------------------------------+ | 41.000000 | +---------------------------------------------------------------------+ 1 row in set (0.05 sec) mysql> select timestampdiff(SECOND,TIMESTAMP("2010-04-02 10:30:00"),TIMESTAMP("2010-04-02 10:29:59")); +-----------------------------------------------------------------------------------------+ | timestampdiff(SECOND,TIMESTAMP("2010-04-02 10:30:00"),TIMESTAMP("2010-04-02 10:29:59")) | +-----------------------------------------------------------------------------------------+ | -1 | +-----------------------------------------------------------------------------------------+ mysql> select TIMESTAMP("2010-04-02 10:30:00") - TIMESTAMP("2010-04-02 10:30:01") ; +---------------------------------------------------------------------+ | TIMESTAMP("2010-04-02 10:30:00") - TIMESTAMP("2010-04-02 10:30:01") | +---------------------------------------------------------------------+ | -1.000000 | +---------------------------------------------------------------------+ +---------------------------------------------------------------------+ | TIMESTAMP("2010-04-02 10:30:00") - TIMESTAMP("2010-04-02 10:31:00") | +---------------------------------------------------------------------+ | -100.000000 | +---------------------------------------------------------------------+ It seems like one minute difference is 100 instead of 60. Why is this?

    Read the article

  • How can I extract a value from comma separated values in Perl?

    - by Octopus
    I have a log file containing statistics from different servers. I am separating the statistics from this log file using regex only. I am trying to capture the CPU usage from the running process. For SunOS, I have below output: process,10050,user1,218,59,0,1271M,1260M,sleep,58.9H,0.02%,java Here the CPU % is at 11th field if we separate by commas (,). To get this value I am using below regex: regex => q/^process,(?:.*?),((?:\d+)\.(?:\d+))%,java$/, For the linux system I have below output: process,26190,user1,20,0,1236m,43m,6436,S,0.0,1.1,0:00.00,java, Here the CPU usage is at 10th column. What regex pattern should I use to get this value?

    Read the article

  • Equality and Assigment Operators

    - by Jeremy Smith
    I have a assembly compiled in VB.NET that contains two operators: Public Shared Operator =(quarterA As CalendarQuarter, quarterB As CalendarQuarter) As Boolean Return quarterA.StartDate = quarterB.StartDate AndAlso quarterA.EndDate = quarterB.EndDate AndAlso quarterA.Quarter = quarterB.Quarter End Operator Public Shared Operator <>(quarterA As CalendarQuarter, quarterB As CalendarQuarter) As Boolean Return Not (quarterA = quarterB) End Operator However, when using the assembly in C# to perform equality checks if (qtr != null) I receive the error: Cannot implicity convert type 'object' to 'bool' My original intent with the = operator was only for assignment purposes in VB, so I may be way off base (I don't use custom operators too often). What do I need to do to make the operator behave with both equality and assignment operations?

    Read the article

  • No whitespace between a cast and a namespace operator?

    - by Pod
    Hello. Could anyone please explain the following line of code, found on http://docs.openttd.org/ai__cargo_8cpp_source.html return (AICargo::TownEffect)::CargoSpec::Get(cargo_type)->town_effect; If this line was: return (AICargo::TownEffect) ::CargoSpec::Get(cargo_type)->town_effect; (note the space between TownEffect) and the ::) then I would understand it fine. However there is no whitespace in that document*, which would mean (AICargo::TownEffect) is the left operand of the :: operator. How does this code work/compile? Or are the two things equivilent due to some obscure C++ rule? *It's the same in the cpp file as well.

    Read the article

  • How to replace empty string with zero in comma-separated string?

    - by dsaccount1
    "8,5,,1,4,7,,,,7,,1,9,3,6,,,8,6,3,9,,2,5,4,,,,,3,2,,,7,4,1,1,,4,,6,9,,5,,,,5,,,1,,6,3,,,6,5,,,,7,4,,1,7,6,,,,8,,5,,,7,1,,3,9," I'm doing a programming challenge where i need to parse this sequence into my sudoku script. Need to get the above sequence into 8,5,0,1,4,7,0,0,0,7,0,1,9,3,6,0,0,8......... I tried re but without success, help is appreciated, thanks.

    Read the article

  • Grails - How to format a value in a textfield into comma style such that it can be easily read?

    - by WaZ
    Hi there, I want to allow users enter numbers in textfield and once the textbox loses focus. The number is formatted with commas. e.g. User enters 100000 textfield looses focus value displayed: 100,000 How can I achieve this in Grails. I have looked at <g:formatNumber number="${myNumber}" format="\\$###,##0" /> But it doesnt solve my problem as the number is from a textfield. thanks Much appreciated.

    Read the article

  • How to read comma separated values from text file in JAVA?

    - by user1425223
    I have got this text file with latitude and longitude values of different points on a map. I want to store these coordinates into a mySQL database using hibernate. I want to know how can I split my string into latitudes and longitudes? What is the general way to do these type of things that is with other delimiters like space, tab etc.? File: 28.515046280572285,77.38258838653564 28.51430151808072,77.38336086273193 28.513566177802456,77.38413333892822 28.512830832397192,77.38490581512451 28.51208605426073,77.3856782913208 28.511341270865113,77.38645076751709 28.510530488025346,77.38720178604126 28.509615992924807,77.38790988922119 28.50875805732363,77.38862872123718 28.507994394490268,77.38943338394165 28.50728729434496,77.39038825035095 28.506674470385246,77.39145040512085 28.506174780521828,77.39260911941528 28.505665660113582,77.39376783370972 28.505156537248446,77.39492654800415 28.50466626846366,77.39608526229858 28.504175997400655,77.39724397659302 28.503685724059455,77.39840269088745 28.503195448440064,77.39956140518188 28.50276174118543,77.4007523059845 28.502309175192945,77.40194320678711 28.50185660725938,77.40313410758972 28.50140403738471,77.40432500839233 28.500951465568985,77.40551590919495 28.500498891812207,77.40670680999756 28.5000463161144,77.40789771080017 28.49959373847559,77.40908861160278 Code I am using to read from file: try { BufferedReader in = new BufferedReader(new FileReader("G:\\RoutePPAdvant2.txt")); String str; str = in.readLine(); while ((str = in.readLine()) != null) { System.out.println(str); } in.close(); } catch (IOException e) { System.out.println("File Read Error"); }

    Read the article

facebook twitter digg google delicious technorati stumbleupon myspace wordpress linkedin gmail igoogle windows live tumblr viadeo yahoo buzz yahoo mail yahoo bookmarks favorites email print

< Previous Page | 34 35 36 37 38 39 40 41 42 43 44 45  | Next Page >