Search Results

Search found 14348 results on 574 pages for 'planet mysql'.

Page 382/574 | < Previous Page | 378 379 380 381 382 383 384 385 386 387 388 389  | Next Page >

  • restoring with mysqldump, but where is the data?

    - by Ole Media
    Ok, so I'm in need to restore a table and I do: mysqldump --opt database table_name < table_name.sql I hit enter and Done! Well, not really, when I go to see if there is anything on the table it show 0 records. I have look into the table_name.sql and I see two records. What am I doing wrong?

    Read the article

  • Getting column info from db with C#

    - by lYriCAlsSH
    In PHP I am able to retrieve information from a db like so: <?php $sql = "SELECT * FROM users"; $result = mysql_query($sql); $data = array(); while($row = mysql_fetch_assoc($result)) { $data[] = $row; } I am trying to acomplish the same thing in C#: OdbcCommand cmd = new OdbcCommand("SELECT * FROM users WHERE id = @id"); cmd.Parameters.Add("@id", id); OdbcDataReader reader = cmd.ExecuteReader(); Dictionary<string, string> data = new Dictionary<string, string>(); while (reader.Read()) { data.Add("id", reader.GetString(0)); data.Add("username", reader.GetString(1)); data.Add("firstName", reader.GetString(2)); } return data; Is it possible to reference the column in the table by name without going through all this trouble?

    Read the article

  • How to find and update the next record in a linking table

    - by someoneinomaha
    I have a classifieds system I'm working on. People are able to add photos to a classified, but I only display one when displaying the list of classifieds. To do that, I have a linking table between classifieds and photos that has a "is_main" boolean field. When someone deletes one of their classified photos, I want to: 1) See if there is more than that photo tied to the classified. 2) If there is, update the next photo and set that "is_main" field to TRUE. Just trying to find out the most efficient way to do this.

    Read the article

  • Unknown Column In Where Clause

    - by Corpo
    I have a simple query: SELECT u_name AS user_name FROM users WHERE user_name = "john"; I get "Unknown Column 'user_name' in where clause". Can I not refer to 'user_name' in other parts of the statement even after select 'u_name as user_name'?

    Read the article

  • insert into table where if not in list

    - by jim smith
    Can anybody help me with the syntax? insert into history (company,partnumber,price) values ('blah','IFS0090','0.00') if company NOT IN ('blah','blah2','blah3','blah4','blah4') and partnumber='IFS0090'; Background: I have a history table which stores daily company, products and prices. But sometimes a company will remove itself for a few days. Complicating the issue is because I'm only saving daily CHANGES to prices only and not snapshotting the entire days list (the data would be huge) when I display the data the company will still come up for the previous days price. So I need to do something like this, where a 0.00 price means they're no longer there.

    Read the article

  • Will these security functions be enough? (PHP)

    - by ggfan
    I am trying to secure my site so I don't have sql injections and xss scripting. Here's my code. //here's the from, for brevity, i just show a field for users to put firstname <form> <label for="first_name" class="styled">First Name:</label> <input type="text" id="first_name" name="first_name" value="<?php if (!empty($first_name)) echo $first_name; ?>" /><br /> //submit button etc </form> if (isset($_POST['submit'])) { //gets rid of extra whitesapce and escapes $first_name = mysqli_real_escape_string($dbc, trim($_POST['first_name'])); //check if $first_name is a string if(!is_string($first_name) { echo "not string"; } //then insert into the database. ....... } mysqli_real_espace_string: I know that this func escapes certain letters like \n \r, so when the data gets inputted into the dbc, it would have '\' next to all the escaped letters? --Will this script be enough to prevent most sql injections? just escaping and checking if the data is a string. For integers values(like users putting in prices), i just: is_numeric(). --How should I use htmlspecialchars? Should I use it only when echoing and displaying user data? Or should I also use this too when inputting data to a dbc? --When should I use strip_tags() or htmlspecialchars? SOO with all these function... if (isset($_POST['submit'])) { //gets rid of extra whitesapce and escapes $first_name = mysqli_real_escape_string($dbc, trim($_POST['first_name'])); //check if $first_name is a string if(!is_string($first_name) { echo "not string"; } //gets rid of any <,>,& htmlspecialchars($first_name); //strips any tags with the first name strip_tags($first_name) //then insert into the database. ....... } Which funcs should I use for sql injections and which ones should I use for xss?

    Read the article

  • Is it possible for a Grails Domain to have no 'id'?

    - by firnnauriel
    Is it possible to create a table that has no 'id'? For example, this is my domain: class SnbrActVector { int nid String term double weight static mapping = { version false id generator: 'identity' } static constraints = { } } When I run this SQL statement, it fails: insert into snbr_act_vector values (5, 'term', 0.5) I checked the table and 'id' is already set to autoincrement. I'm thinking that another option is to remove the 'id' itself. Or is there another workaround for this? Please assume that it is not an option to change the givent SQL statement.

    Read the article

  • How to check if a checkbox/ radio button is checked in php

    - by user225269
    I have this html code: <tr> <td><label><input type="text" name="id" class="DEPENDS ON info BEING student" id="example">ID</label></td> </tr> <tr> <td> <label> <input type="checkbox" name="yr" class="DEPENDS ON info BEING student"> Year</label> </td> </tr> But I don't have any idea on how do I check this checkboxes if they are checked using php, and then output the corresponding data based on the values that are checked. Please help, I'm thinking of something like this. But of course it won't work, because I don't know how to equate checkboxes in php if they are checked: <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $id = mysql_real_escape_string($_POST['idnum']); if($_POST['id'] == checked & $_POST['yr'] ==checked ){ $result2 = mysql_query("SELECT * FROM student WHERE IDNO='$id'"); echo "<table border='1'> <tr> <th>IDNO</th> <th>YEAR</th> </tr>"; while($row = mysql_fetch_array($result2)) { echo "<tr>"; echo "<td>" . $row['IDNO'] . "</td>"; echo "<td>" . $row['YEAR'] . "</td>"; echo "</tr>"; } echo "</table>"; } mysql_close($con); ?>

    Read the article

  • PHP: How to get the days of the week?

    - by fwaokda
    I'm wanting to store items in my database with a DATE value for a certain day. I don't know how to get the current Monday, or Tuesday, etc. from the current week. Here is my current database setup. menuentry id int(10) PK menu_item_id int(10) FK day_of_week date message varchar(255) So I have a class setup that holds all the info then I was going to do something like this... foreach ( $menuEntryArray as $item ) { if ( $item->getDate() == [DONT KNOW WHAT TO PUT HERE] ) { // code to display menu_item information } } So I'm just unsure what to put in "[DONT KNOW WHAT TO PUT HERE]" to compare to see if the date is specified for this week's Monday, or Tuesday, etc. The foreach above runs for each day of the week - so it'll look like this... Monday Item 1 Item 2 Item 3 Tuesday Item 1 Wednesday Item 1 Item 2 ... Thanks!

    Read the article

  • PHP Code Problem...

    - by aamir Fayyaz
    function check_login($array_val) { $strQury = "Select * from tblsignup where usr_email ='".$array_val[0]."' and usr_password = '".$array_val[1]."'" ; $result = mysql_query($strQury); $row_user = mysql_fetch_array($result); if(mysql_num_rows($result)>0) { $msg = "true"; } else { $msg = "false"; } return $msg ; } The return value is Object id #1true???? what is object id#1?

    Read the article

  • Moving from dedicated to shared cpanel - any scripts to do all / some of the install tasks ?

    - by mbbcat
    Hi, I have a few hundred phpld sites to move - each has its own cpanel, ( & the target may have shared cpanel) & I can do a full cpanel backup on the original server, but I don't have whm on the current host - the backups are fairly easy to organize but the installs so far means picking through files & setting up db's & mail etc by hand - I am thinking there ought to be an easier ie scripted way to do the installs or at least some parts - can anyone please suggest something ? I would like to migrate the stats at the same time Thanks M

    Read the article

  • MULTIPLE CRITERIA TABLE JOIN

    - by user1447203
    I have a table listing clothing items (shirt, trousers, etc) named . Each item is identified with a unique CLOTHING.CLOTHING_ID. So a blue shirt is 01, a flowery shirt is 12 and jeans are 07 say. I have a second table identifying outfits with a column for shirts, for trousers, shoes etc. For example Outfit 1: shirt 01, trousers 07 (i.e. blue shirt with jeans) Outfit 2: shirt 12, trousers 07 (so flowery shirt with jeans). This table is named and each outfit is unique with OUTFIT_LIST.OUTFIT_ID. I want to produce a select statement that will list each outfit's contents, i.e. find the clothing specified in Outfit 1. Any help would be very much appreciated, and apologies in advance if I am missing a very simple solution. I have been playing with JOINS of all descriptions and CONCATS and so on with now luck - I am very new to this. Thanks.

    Read the article

  • Show parts of the result of an SQL statement using PHP

    - by mouthpiec
    I have an SQL query which returns a set of data (around 40-50 tuples). I would like to display the results 5 at a time on an HTML page using PHP. I already managed to have the right SELECT statement, but i am having problems to display the results 5 by 5 using a "more" button. Can you please help? Note that every time i call the query, the data is being randomized, so it is not possible to set limits and call the query again. I have to find the method to store the results somewhere, and then show them 5 by 5.

    Read the article

  • Magento: Add (and retrieve) custom database field for CMS pages

    - by Toby H
    I want to assign custom parameters to CMS pages in Magento (i.e. 'about', 'customer service', etc), so they can be grouped. The end goal is to use the parameters for each page to show (or hide) them in a nav menu. Writing a quick method in the page/html block to retrieve the pages (active only) for the menu was easy, but I can't figure out how to group them so that 'testimonials', 'history', and 'contact' are associated with 'about', and 'return policy', 'shipping', and 'contact' are associated with 'customer service'. Any help to point me in the right direction would be greatly appreciated. Thanks!

    Read the article

  • num_rows is 0 when it should be >0 for php mysqli code

    - by jpporterVA
    My num_rows is coming back as 0, and I've tried calling it several ways, but I'm stuck. Here is my code: $conn = new mysqli($dbserver, "dbuser", "dbpass", $dbname); // get the data $sql = 'SELECT AT.activityName, AT.createdOn FROM userActivity UA, users U, activityType AT WHERE U.userId = UA.userId and AT.activityType = UA.activityType and U.username = ? order by AT.createdOn'; $stmt = $conn->stmt_init(); $stmt->prepare($sql); $stmt->bind_param('s', $requestedUsername); $stmt->bind_result($activityName, $createdOn); $stmt->execute(); // display the data $numrows = $stmt->num_rows; $result=array("user activity report for: " . $requestedUsername . " with " . $numrows . " rows:"); $result[]="Created On --- Activity Name"; while ($stmt->fetch()) { $msg = " " . $createdOn . " --- " . $activityName . " "; $result[] = $msg; } $stmt->close(); There are multiple rows found, and the fetch loop process them just fine. Any suggestions on what will enable me to get the number of rows returned in the query? Suggestions are much appreciated. Thanks in advance.

    Read the article

  • RoR: Condition Always False - Why?

    - by Matt Hollingsworth
    Working in RoR 2.3.x. My quiz_results table has a row for user_id (3907) and result (0.1), and two users I'm looking at with no rows in the quiz_results table. This line keeps returining false: -if QuizResult.find_by_user_id(@user_id).present? But if I change it to anything that returns true, the next line reports an error on the * method: ="#{(QuizResult.average('score', :conditions => 'user_id = #{@user.id}') * 100).round}%" The beginning of the code is a loop: [email protected] do |user| Any ideas how to fix? Have tried unsuccessfully all day.

    Read the article

  • TV Guide script - getting current date programmes to show

    - by whitstone86
    This is part of my TV guide script: //Connect to the database mysql_connect("localhost","root","PASSWORD"); //Select DB mysql_select_db("mytvguide"); //Select only results for today and future $result = mysql_query("SELECT programme, channel, episode, airdate, expiration, setreminder FROM mediumonair where airdate >= now()"); The episodes show up, so there are no issues there. However, it's getting the database to find data that's the issue. If I add a record for a programme that airs today this should show: Medium showing on TV4 8:30pm "Episode" Set Reminder Medium showing on TV4 May 18th - 6:25pm "Episode 2" Set Reminder Medium showing on TV4 May 18th - 10:25pm "Episode 3" Set Reminder Medium showing on TV4 May 19th - 7:30pm "Episode 3" Set Reminder Medium showing on TV4 May 20th - 1:25am "Episode 3" Set Reminder Medium showing on TV4 May 20th - 6:25pm "Episode 4" Set Reminder but this shows instead: Medium showing on TV4 May 18th - 6:25pm "Episode 2" Set Reminder Medium showing on TV4 May 18th - 10:25pm "Episode 3" Set Reminder Medium showing on TV4 May 19th - 7:30pm "Episode 3" Set Reminder Medium showing on TV4 May 20th - 1:25am "Episode 3" Set Reminder Medium showing on TV4 May 20th - 6:25pm "Episode 4" Set Reminder I almost have the SQL working; just not sure what the right code is here, to avoid the second mistake showing - as the record (which indicates a show currently airing) does not seem to work at present. Please can anyone help me with this? Thanks

    Read the article

  • Easy way to compute how close an auto_increment is to its maximum value?

    - by David M
    So yesterday we had a table that has an auto_increment PK for a smallint that reached its maximum. We had to alter the table on an emergency basis, which is definitely not how we like to roll. Is there an easy way to report on how close each auto_increment field that we use is to its maximum? The best way I can think of is to do a SHOW CREATE TABLE statement, parse out the size of the auto-incremented column, then compare that to the AUTO_INCREMENT value for the table. On the other hand, given that the schema doesn't change very often, should I store information about the columns' maximum values and get the current AUTO_INCREMENT with SHOW TABLE STATUS?

    Read the article

  • why does InnoDB keep on growing without for every update?

    - by Akash Kava
    I have a table which consists of heavy blobs, and I wanted to conduct some tests on it. I know deleted space is not reclaimed by innodb, so I decided to reuse existing records by updating its own values instead of createing new records. But I noticed, whether I delete and insert a new entry, or I do UPDATE on existing ROW, InnoDB keeps on growing. Assuming I have 100 Rows, each Storing 500KB of information, My InnoDB size is 10MB, now when I call UPDATE on all rows (no insert/ no delete), the innodb grows by ~8MB for every run I do. All I am doing is I am storing exactly 500KB of data in each row, with little modification, and size of blob is fixed. What can I do to prevent this? I know about optimize table, but I cant do it because on regular usage, the table is going to be 60-100GB big, and running optimize will just stall entire server.

    Read the article

  • How to know record has been updated successfully in php

    - by Lisa Ray
    $sql = "UPDATE...."; if(mysql_query($sql)) { $_SESSION['Trans']="COMMIT"; header("location:result.php"); exit; } else { $_SESSION['Trans']="FAIL"; $_SESSION['errors'] = "Error: Sorry! We are unable to update your Profile, Please contact to PNP HelpDesk."; header("location:result.php"); exit; }//end IF data is getting updated then why compiler is not coming inside IF condition.

    Read the article

< Previous Page | 378 379 380 381 382 383 384 385 386 387 388 389  | Next Page >