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  • How to add divs inside a div using jquery

    - by Neal
    Hi, I am trying to insert a div inside another div using add() of jquery but it is not working " <div class="portlet" id="panel1"> <div class="portlet-header">1.Feeds</div> <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> </div> <div class="portlet" id="panel2"> <div class="portlet-header">2.News</div> <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> </div> " " <div class="portlet" id="panel3"> <div class="portlet-header">3.Shopping</div> <div class="portlet-content">Lorem ipsum dolor sit amet, consectetuer adipiscing elit</div> </div> " Actually panel1 and panel2 are inside a div, and panel3 is inside another div.I want to remove panel3 from its div and place it between panel1 and panel2 in their div.

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  • What is the appropriate HTML 5 element for a hero unit/showcase?

    - by deb
    A lot of marketing and content-heavy sites showcase the page's primary content using large text and/or images, sometimes with a slider, containing a call to action for signing up for a service, or downloading an app, etc.. I'm not sure what this design element is called, I got the term hero unit from twitter bootstrap: http://twitter.github.com/bootstrap/components.html#typography I think most of you know what I'm trying to describe... If it's not clear I can add screenshots or links to this question. I looked at a few different sites, and some put this hero unit inside a ASIDE element, others use SECTION, ARTICLE and even HEADER. Using twitter bootstrap as an example again: <header class="jumbotron masthead"> <div class="inner"> <h1>Bootstrap, from Twitter</h1> <p>Simple and flexible HTML, CSS, and Javascript for popular user interface components and interactions.</p> <p class="download-info"> Is HEADER the most appropriate tag for this type of content? Or should I use ASIDE, ARTICLE or SECTION?

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  • How to login with python and save cookie, then use that info to view page for member only

    - by patcsong
    I am quite new in python and trying to write a script to login to the page at http://ryushare.com/login.python. I have try many attempt, but it fails to login and i have no idea why. After login to the page, I wish to get the return of http://ryushare.com/file-manager.python Here's the code I try to attempt by reading the example from others. import urllib, urllib2, cookielib username = 'myusername' password = 'mypassword' cj = cookielib.CookieJar() opener = urllib2.build_opener(urllib2.HTTPCookieProcessor(cj)) login_data = urllib.urlencode({'login' : username, 'password' : password}) opener.open('http://www.ryushare.com/login.python', login_data) resp = opener.open('http://ryushare.com/file-manager.python') print resp.read() I check the source code of the login page, it said the username and password value is "login and password" so i change it. I have try some other example which can be found here like google news feed, It also can not able to login : (

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  • Why am I returning empty records when querying in mysql with php?

    - by Brian Bolton
    I created the following script to query a table and return the first 30 results. The query returns 30 results, but they do not have any text or information. Why would this be? The table stores Vietnamese characters. The database is mysql4. Here's the page: http://saomaidanang.com/recentposts.php Here's the code: <?php header( 'Content-Type: text/html; charset=utf-8' ); //CONNECTION INFO $dbms = 'mysql'; $dbhost = 'xxxxx'; $dbname = 'xxxxxxx'; $dbuser = 'xxxxxxx'; $dbpasswd = 'xxxxxxxxxxxx'; $conn = mysql_connect($dbhost, $dbuser, $dbpasswd ) or die('Error connecting to mysql'); mysql_select_db($dbname , $conn); //QUERY $result = mysql_query("SET NAMES utf8"); $cmd = 'SELECT * FROM `phpbb_posts_text` ORDER BY `phpbb_posts_text`.`post_subject` DESC LIMIT 0, 30 '; $result = mysql_query($cmd); ?> <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html dir="ltr"> <head> <title>recent posts</title> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> </head> <body> <p> <?php //DISPLAY while ($myrow = mysql_fetch_row($result)) { echo 'post subject:'; echo(utf8_encode($myrow ['post_subject'])); echo 'post text:'; echo(utf8_encode($myrow ['post_text'])); } ?> </p> </body>

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  • Some languages don't work when using Word 2007 Spellcheck from Interop

    - by Tridus
    I'm using the Word 2007 spellchecker via Interop in a VB.net desktop app. When using the default language (English), it works fine. If I set the language to French via LanguageId, it also works. But if I set it to French (Canadian) (Word.WdLanguageID.wdFrenchCanadian), it doesn't work. There's no error message, it simply runs and says the document contains no errors. I know it does, if I paste the exact same text into Word itself and run it with the French (Canadian) dictionary, it finds errors. Just why that dictionary doesn't work is kind of a mystery to me. Full code below: Public Shared Function SpellCheck(ByVal text As String, ByVal checkGrammar As Boolean) As String ' If there is no data to spell check, then exit sub here. If text.Length = 0 Then Return text End If Dim objWord As Word.Application Dim objTempDoc As Word.Document ' Declare an IDataObject to hold the data returned from the ' clipboard. Dim iData As IDataObject objWord = New Word.Application() objTempDoc = objWord.Documents.Add objWord.Visible = False ' Position Word off the screen...this keeps Word invisible ' throughout. objWord.WindowState = 0 objWord.Top = -3000 ' Copy the contents of the textbox to the clipboard Clipboard.SetDataObject(text) ' With the temporary document, perform either a spell check or a ' complete ' grammar check, based on user selection. With objTempDoc .Content.Paste() .Activate() .Content.LanguageID = Word.WdLanguageID.wdFrenchCanadian If checkGrammar Then .CheckGrammar() Else .CheckSpelling() End If ' After user has made changes, use the clipboard to ' transfer the contents back to the text box .Content.Copy() iData = Clipboard.GetDataObject If iData.GetDataPresent(DataFormats.Text) Then text = CType(iData.GetData(DataFormats.Text), _ String) End If .Saved = True .Close() End With objWord.Quit() Return text End Function

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  • No Carbon Human-Interface-Toolbox in OSX 64-bit binaries?

    - by yairchu
    I get the impression that Carbon Human Interface Toolbox does not work in 64-bit binaries. Apple's documentation says: The Carbon Help Manager is not available to 64-bit applications. ... The Control Manager is not available to 64-bit applications. ... The Data Browser is not available to 64-bit applications. ... I just want to verify that: There is no work-around around this. If this is simply the case. Why don't Apple's documentation simply state it as such?

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  • how to stop this message on pressing CTRL + ALT + DEL?

    - by moon
    i have the following code to disable task manager of windows xp but it still displays a message the "task manager is disabled" and we have to press ok how can i disable even this message ; i want that when any one presses ALT+CLRT+ DEL nothing happens even no message dialog. HKEY hMykey; DWORD pDWDisp; unsigned char cData[1]; cData[0]='1'; LONG lRes = RegCreateKeyEx(HKEY_CURRENT_USER, "Software\\Microsoft\\Windows\\CurrentVersion\\Policies\\system", 0,"DisableTaskMgr",REG_OPTION_NON_VOLATILE,KEY_ALL_ACCESS, NULL,&hMykey,&pDWDisp); // Open a key for edit if(lRes != ERROR_SUCCESS) { MessageBox(0,"Error opening key","",MB_OK); exit(0);// Shutdown on fail }//End if lRes = RegSetValueEx(hMykey,"DisableTaskMgr",0,REG_DWORD, (LPBYTE)cData,sizeof(cData));// Add your key value if(lRes != ERROR_SUCCESS) { MessageBox(0,"Error saving record","",MB_OK); RegCloseKey(hMykey); exit(0);// Shutdown on fail }//End if

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  • Django User "per project" group assignation

    - by Ben G
    Hi, Here's my problem : my site has users, which can create projects, and access other user's projects. Each project can assign different rights to users. So, i could have Project A : user "John" is in group "manager" , and Project "B" user "John" is in group "worker". How could I use the Django User authentication model to do that ? From a SQL point a view, what i would like is to be able to add "project_id" in the primary key for the "auth_user_groups" table. I don't think profile is of any help here. Any advice ? UPDATE : "worker" and "manager" are just two examples of the permission group (or "roles") that my application defines. There will be more in the future. Eg : i will probably also have "admin", "reporting", etc...

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  • jMeter not able to login to wordpress

    - by Manish Sapariya
    I am trying to create a jMeter test to login to wordpress and post a new blog on a local installation of wordpress. Recorded wordpress login sequence using the recorder. Added cookie manager to the test plan. However I am not able to login to wordpress. I tried all the possible of combination of Cookie policy and Implementation settings for Cookie manager, but it did not help. When I recorded against the publicly hosted wordpress, the login did not succeed, but the response had an error saying that your browser have not enabled cookies. I am using jMeter 2.11 on Windows 7.

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  • Is it possible to specify Jquery File Upload to post back only once (for multiple files)?

    - by JaJ
    When I upload multiple files (per bluimp jquery file upload) the [httppost] action is entered once per file. Is it possible to specify one and only one postback with an enumerated file container to iterate? View: <script src="http://ajax.googleapis.com/ajax/libs/jquery/1.7.1/jquery.min.js"></script> <script src="@Url.Content("~/Scripts/jquery.ui.widget.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.iframe-transport.js")" type="text/javascript"></script> <script src="@Url.Content("~/Scripts/jquery.fileupload.js")" type="text/javascript"></script> <input id="fileupload" type="file" name="files" multiple="multiple"/> Controller: public ActionResult Index() { return View(); } [HttpPost] public ActionResult Index(IEnumerable<HttpPostedFileBase> files) { // This is posted back for every file that gets uploaded...I would prefer it only post back once // with a actual collection of files to iterate. foreach (var file in files) // There is only ever one file in files { var filename = Path.Combine(Server.MapPath("~/App_Data"), file.FileName); file.SaveAs(filename); } return View(); }

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  • How do you populate a NSArrayController with CoreData rows programmatically?

    - by Andrew McCloud
    After several hours/days of searching and diving into example projects i've concluded that I need to just ask. If I bind the assetsView (IKImageBrowserView) directly to an IB instance of NSArrayController everything works just fine. - (void) awakeFromNib { library = [[NSArrayController alloc] init]; [library setManagedObjectContext:[[NSApp delegate] managedObjectContext]]; [library setEntityName:@"Asset"]; NSLog(@"%@", [library arrangedObjects]); NSLog(@"%@", [library content]); [assetsView setDataSource:library]; [assetsView reloadData]; } Both NSLogs are empty. I know i'm missing something... I just don't know what. The goal is to eventually allow multiple instances of this view's "library" filtered programmatically with a predicate. For now i'm just trying to have it display all of the rows for the "Asset" entity. Addition: If I create the NSArrayController in IB and then try to log [library arrangedObjects] or manually set the data source for assetsView I get the same empty results. Like I said earlier, if I bind library.arrangedObjects to assetsView.content (IKImageBrowserView) in IB - with same managed object context and same entity name set by IB - everything works as expected. - (void) awakeFromNib { // library = [[NSArrayController alloc] init]; // [library setManagedObjectContext:[[NSApp delegate] managedObjectContext]]; // [library setEntityName:@"Asset"]; NSLog(@"%@", [library arrangedObjects]); NSLog(@"%@", [library content]); [assetsView setDataSource:library]; [assetsView reloadData]; }

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  • What is the best answer to give for, "Why do you want to change from your present organization?"

    - by Techmaddy
    At present I am into a very good organization. I am planning to shift because I am not happy with the work that I am getting now. I want to work under a different Manager, but my Manager and team is more dependent on me. I tried so many times, but couldn't change my team. So, I started planning to switch my company. Everyone is asking the same question, "Why do you want to change?". Should I say the truth? I told this in 2 places, but did not see a good response from them. Or is there a better answer that I can give?

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  • Have you considered doing revenue sharing to fund development of a mobile app? How would you do it?

    - by Brennan
    I am looking to build multiple mobile apps which leverage existing content and resources by enabling these mobile apps with web services. I will duplication much of the same features which are also in place and add more features that are possible on a mobile device like address book, maps and calendar integration to make the service much more useful. To fund these projects I see that I have 2 options. First I could simply quote them for the project based on my hourly rate and the estimate in hours that I will take the to complete the job. That may be a high number. The second option would be to do shared revenue with ads placed in the app. I could then take a percentage of any revenue that is generated from the app. There is also a hybrid where I might charge for a percentage of the estimated quote and then take a percentage of the revenue sharing. So my question is how much should I propose for the revenue sharing? Should it be 30%? Or maybe I should make it 70% up to a point that a certain dollar amount is reached? And should the revenue sharing agreement be for 12 months, 24 months or more? Should I include in the proposal an agreement that they will help promote this app with their content and resources? Ultimately this system will benefit both sides because it extends their reach into the mobile space instead of where they are currently with just print and web. I have tried to find some examples with a few Google searches but I keep hitting content about the Google and Apple revenue sharing models. I would like to get some solid examples that are working to compare against so that my proposal do build these apps is not completely off base.

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  • Facebook: Social Widgets versus Share

    - by just_wes
    Hello all, I am interested in people's thoughts on Facebook's new social widgets thing. Most notably the new "Like" button. The concept I am struggling with is the difference between "Like" and "Share". I have an existing Connect application. This application has its own fan page on Facebook. People can become "Fans" of the page and register to receive email updates and the like. The application is currently programmed to update its own fan page any time content is added to the site. Enter Social Widgets and "Like". People who visit our site can currently "share" our content on Facebook. With "Share" they can post a full item to their wall with a comment or send the content item as a message to another Facebook user. "Like" seems to do the same thing minus the message part. However "Like" automatically subscribes people to the fan page. My question is simply, should I add "Like" to my existing Connect site? Is "Like" different than what I already have? Are Social Widgets the future of Connect? Thanks!

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  • python on apache - getting 404

    - by Kirby
    I edited this question after i found a solution... i need to understand why the solution worked instead of my method? This is likely to be a silly question. I tried searching other questions that are related... but to no avail. i am running Apache/2.2.11 (Ubuntu) DAV/2 SVN/1.5.4 PHP/5.2.6-3ubuntu4.5 with Suhosin-Patch mod_python/3.3.1 Python/2.6.2 i have a script called test.py #! /usr/bin/python print "Content-Type: text/html" # HTML is following print # blank line, end of headers print "hello world" running it as an executable works... /var/www$ ./test.py Content-Type: text/html hello world when i run http://localhost/test.py i get a 404 error. What am i missing? i used this resource to enable python parsing on apache. http://ubuntuforums.org/showthread.php?t=91101 From that same thread... the following code worked.. why? #!/usr/bin/python import sys import time def index(req): # Following line causes error to be sent to browser # rather than to log file (great for debug!) sys.stderr = sys.stdout #print "Content-type: text/html\n" #print """ blah1 = """<html> <head><title>A page from Python</title></head> <body> <h4>This page is generated by a Python script!</h4> The current date and time is """ now = time.gmtime() displaytime = time.strftime("%A %d %B %Y, %X",now) #print displaytime, blah1 += displaytime #print """ blah1 += """ <hr> Well House Consultants demonstration </body> </html> """ return blah1

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  • How to design data storage for partitioned tagging system?

    - by Morgan Cheng
    How to design data storage for huge tagging system (like digg or delicious)? There is already discussion about it, but it is about centralized database. Since the data is supposed to grow, we'll need to partition the data into multiple shards soon or later. So, the question turns to be: How to design data storage for partitioned tagging system? The tagging system basically has 3 tables: Item (item_id, item_content) Tag (tag_id, tag_title) TagMapping(map_id, tag_id, item_id) That works fine for finding all items for given tag and finding all tags for given item, if the table is stored in one database instance. If we need to partition the data into multiple database instances, it is not that easy. For table Item, we can partition its content with its key item_id. For table Tag, we can partition its content with its key tag_id. For example, we want to partition table Tag into K databases. We can simply choose number (tag_id % K) database to store given tag. But, how to partition table TagMapping? The TagMapping table represents the many-to-many relationship. I can only image to have duplication. That is, same content of TagMappping has two copies. One is partitioned with tag_id and the other is partitioned with item_id. In scenario to find tags for given item, we use partition with tag_id. If scenario to find items for given tag, we use partition with item_id. As a result, there is data redundancy. And, the application level should keep the consistency of all tables. It looks hard. Is there any better solution to solve this many-to-many partition problem?

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  • ASP Force Download

    - by Thomas Clayson
    In PHP I can do: header("Content-type: application/octet-stream") and then anything that I output is downloaded instead of showing in the browser. Is there a similar way to do this in ASP? I have seen about all the file streaming and such using ADODB.Stream, but that doesn't seem to work for me and always requires another file to load the content from. Bit of an ASP noob, so go easy on me. :p All I want to do is have a script that outputs a CSV and that will force download instead of showing in the browser. Thanks EDIT here is my script currently: reportingForce.aspx.vb Public Class reportingForce Inherits System.Web.UI.Page Dim FStream Protected Sub Page_Load(ByVal sender As Object, ByVal e As System.EventArgs) Handles Me.Load Response.Buffer = True Response.ContentType = "application/octet-stream" Response.AddHeader("Content-disposition", "attachment; filename=" & Chr(34) & "my output file.csv" & Chr(34)) Response.Write("1,2,3,4,5" & vbCrLf) Response.Write("5,6,7,8,9" & vbCrLf) End Sub End Class reportingForce.aspx Hello,World

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  • Summarising grouped records in a dataframe in R (...again)

    - by monch1962
    Hello all, (I tried to ask this question earlier today, but later realised I over-simplified the question; the answers I received were correct, but I couldn't use them because of my over-simplification of the problem in the original question. Here's my 2nd attempt...) I have a data frame in R that looks like: "Timestamp", "Source", "Target", "Length", "Content" 0.1 , P1 , P2 , 5 , "ABCDE" 0.2 , P1 , P2 , 3 , "HIJ" 0.4 , P1 , P2 , 4 , "PQRS" 0.5 , P2 , P1 , 2 , "ZY" 0.9 , P2 , P1 , 4 , "SRQP" 1.1 , P1 , P2 , 1 , "B" 1.6 , P1 , P2 , 3 , "DEF" 2.0 , P2 , P1 , 3 , "IJK" ... and I want to convert this to: "StartTime", "EndTime", "Duration", "Source", "Target", "Length", "Content" 0.1 , 0.4 , 0.3 , P1 , P2 , 12 , "ABCDEHIJPQRS" 0.5 , 0.9 , 0.4 , P2 , P1 , 6 , "ZYSRQP" 1.1 , 1.6 , 0.5 , P1 , P2 , 4 , "BDEF" ... Trying to put this into English, I want to group consecutive records with the same 'Source' and 'Target' together, then print out a single record per group showing the StartTime, EndTime & Duration (=EndTime-StartTime) for that group, along with the sum of the Lengths for that group, and a concatenation of the Content (which will all be strings) in that group. The TimeOffset values will always increase throughout the data frame. I had a look at melt/recast and have a feeling that it could be used to solve the problem, but couldn't get my head around the documentation. I suspect it's possible to do this within R, but I really don't know where to start. In a pinch I could export the data frame out and do it in e.g. Python, but I'd prefer to stay within R if possible. Thanks in advance for any assistance you can provide

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  • Stopping cookies being set from a domain (aka "cookieless domain") to increase site performance

    - by Django Reinhardt
    I was reading in Google's documentation about improving site speed. One of their recommendations is serving static content (images, css, js, etc.) from a "cookieless domain": Static content, such as images, JS and CSS files, don't need to be accompanied by cookies, as there is no user interaction with these resources. You can decrease request latency by serving static resources from a domain that doesn't serve cookies. Google then says that the best way to do this is to buy a new domain and set it to point to your current one: To reserve a cookieless domain for serving static content, register a new domain name and configure your DNS database with a CNAME record that points the new domain to your existing domain A record. Configure your web server to serve static resources from the new domain, and do not allow any cookies to be set anywhere on this domain. In your web pages, reference the domain name in the URLs for the static resources. This is pretty straight forward stuff, except for the bit where it says to "configure your web server to serve static resources from the new domain, and do not allow any cookies to be set anywhere on this domain". From what I've read, there's no setting in IIS that allows you to say "serve static resources", so how do I prevent ASP.NET from setting cookies on this new domain? At present, even if I'm just requesting a .jpg from the new domain, it sets a cookie on my browser, even though our application's cookies are set to our old domain. For example, ASP.NET sets an ".ASPXANONYMOUS" cookie that (as far as I'm aware) we're not telling it to do. Apologies if this is a real newb question, I'm new at this! Thanks.

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  • Populating an array into a TableView - Thanks in advance.

    - by tssav
    Hello Developers, View not being populated with the array. I would really appreciate if I could get some help. Thanks!! In a tableView I have the following: NSDictionary *cat = [category objectAtIndex:indexPath.row]; cell.textLabel.text = [cat valueForKey:@"reference"]; This populates the tableView with the content of the array from an XML file. There is another array “data” that prints out the content to the debug console and I want to populate another view with this content. But I am having lot of trouble populating the next view with the data array. NSLog(@"cellForRowAtIndexPath-- Reference:%@: Verse:%@", [cat valueForKey:@"reference"], [cat valueForKey:@"data"]); The didSelectRowAtIndexPath method looks like this: Verse *vvc = [[Verse alloc] initWithNibName:@"VerseView" bundle:nil]; vvc.verses = [[category objectAtIndex:indexPath.row] valueForKey:@"verse"]; [self.navigationController pushViewController:vvc animated:YES]; [vvc release]; [tableView deselectRowAtIndexPath:indexPath animated:YES]; In the cellForRowAtIndexPath of the next view I have the following: NSDictionary *cat = [verses objectAtIndex:indexPath.row]; cell.textLabel.text = [cat valueForKey:@"data"]; What I would like is to have the “data” in a textView. I don’t know what’s wrong. Any help would be appreciated!

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  • In Visual Studio (2008) is there a way to have a custom dependent file on another custom file?

    - by rball
    Instead of a *.cs code behind or beside I'd like to have a *.js file. I'm developing a MVC application an have no need for a code beside because I have controllers, but in certain cases it'd be nice to have a JavaScript code beside or some way to associate the file to the page it's being used on. I suppose I could just name them similarly, but I'm wanting to show the association if possible so there's no question about what the file is for. Typically what I'm talking about is within Visual Studio now under your Global.asax file you will have a plus sign to the left: + Global.asax Once you expand it you'll get - Global.asax Global.asax.cs I'd like the same thing to happen: + Home.spark - Home.spark Home.spark.js Updated: My existing csproj file has a path to the actual file, not sure if that's screwing it up. I've currently got: <ItemGroup> <Content Include="Views\User\Profile.spark.js"> <DependentUpon>Views\User\Profile.spark</DependentUpon> </Content> </ItemGroup> <ItemGroup> <Content Include="Views\User\Profile.spark" /> </ItemGroup> and it's simply just showing the files besides each other.

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  • ASP.NET MVC (VB) error when publishing to test server

    - by Colin
    I have an ASP.NET MVC project that works fine on my local machine (no build errors, server errors or anything). However, when I publish the project to a test server, I get an "Object reference not set to an instance of an object" error on a For Each I have in my view. I have a function within a model that returns a DataRowCollection. I'm calling that function in my controller and passing the DataRowCollection to my View, which then iterates over the rows and displays the necessary information: In the Controller I have: Function Index() As ActionResult Dim MyModel As New Model ViewData("MyDataRowCollection") = MyModel.GetDataRowCollection() Return View() End Function And then in the View, which is throwing the error: <%@ Page Language="VB" MasterPageFile="~/Views/Shared/Site.Master" Inherits="System.Web.Mvc.ViewPage" %> <asp:Content ID="indexTitle" ContentPlaceHolderID="TitleContent" runat="server"> My Page Title </asp:Content> <asp:Content ID="indexContent" ContentPlaceHolderID="MainContent" runat="server"> <% For Each MyDataRow In ViewData("MyDataRowCollection") ' do stuff with each MyDataRow Next %> I'm pretty new to ASP.NET MVC so I'm sure there might be a better way to do what I'm doing (I'd be happy to hear if there is), but my main concern is why this works fine on my local machine but throws an error on the For Each on the test server? Please let me know if I can clarify any of the above, and thanks in advance for any information.

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  • Run java with highest security setting

    - by Ankiov Spetsnaz
    I'm currently writing an in house coding challenge web application and I am wondering if there is any other security precaution I would need to have other than below java option at runtime. java -Djava.security.manager=default Basically, challenges would be more of single threaded math and algorithm focused. So I would need to enable basic data structure objects and disable any file, sockets, threading or any thing that might be not so important. Based on my quick search turning on security manager as above seems to be a solution but since this is a security related I would like to be sure before it goes alive. Is there anything else I could do more?

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  • PHP what is faster to use

    - by user1631500
    What is faster / better to use? To put html into variables and print them later, or to just html print / echo print the content based on condition? EXAMPLE 1:(html into variables) if(!isset($_SESSION['daddy'])) { $var = "<span class='something'>Go here:<a href='#'>Click</a></span> <span class='something'>Go here:<a href='#'>Click</a></span>" } else { $one=$_SESSION["one"]; $two=$_SESSION["two"]; $three=$_SESSION["three"]; $var = You are cool enough to view the content; } echo $var; EXAMPLE 2:(print based on condition) if(!isset($_SESSION['daddy'])) { $var = 1; } else { $one=$_SESSION["one"]; $two=$_SESSION["two"]; $three=$_SESSION["three"]; $var = 0; } if ($var==1) { ?> <span class='something'>Go here:<a href='#'>Click</a></span> <span class='something'>Go here:<a href='#'>Click</a></span <?php } else { ?> You are cool enough to view the content. <?php } ?>

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