Search Results

Search found 12223 results on 489 pages for 'password generator'.

Page 386/489 | < Previous Page | 382 383 384 385 386 387 388 389 390 391 392 393  | Next Page >

  • How to write Cyrillic text in C++ console?

    - by VextoR
    For example, if I write: cout << "??????!" << endl; //it's hello in Russian in console it would be something like "-?????!" ok, I know that we can use: setlocale(LC_ALL, "Russian"); but after that not working command line arguments in russian (if I start my program through BAT file): StartProgram.bat chcp 1251 MyProgram.exe -user=???? -password=?????? so, after setlocale program can't read russian arguments properly. This happens because BAT file in CP1251, but console is in CP866 So, there is a question: How to write in C++ console russian text and same time russian command line arguments have to be read properly thanks

    Read the article

  • stumped on jquery call inside chrome extension

    - by phil swenson
    In my chrome extension I call this: jsonPost = { email:"[email protected]", password:"demo", content: $('#selected_text').val(), notification_type: $('#notification_type').val(), name:$('#notification_name').val() } $.post('http://localhost:3000/api/create.json', jsonPost, function (data) { console.log("type of data = " + typeof(data)); console.log("data in function = " + data); } The data makes it to the server. But the response is lost, in the console ---type of data = String ---data in function = So for some reason I am not getting the response back. Works from the browser. I even tried doing a get against cnn.com and got no response. any ideas? thanks

    Read the article

  • Server-side application configuration security. Best practices

    - by Andrew Florko
    We publish server-side application to our customer workstation and customer's security guys are concerned about configuration connection strings safety. Connection strings are stored as plain text right now, but as configuration file is not in the public/shared folder we supposed that workstation security itself is enough. What are the ways to improve connection strings security further? It is a big step forward to encrypt password and keep a decryption key on the same workstation? What are the steps we can take to keep connection strings (and alike) information more and more securable? Thank you in advance!

    Read the article

  • SQL Server Reporting Services 2008: How to set the credentials property properly?

    - by wgpubs
    No matter how I configure the Credentials property I get a 401 exception when I try to Render the report. Here is my (latest) code: var rs = new ReportExecutionService(); rs.Url = "https://myserver/reportserver/reportexecution2005.asmx"; var myCache = new System.Net.CredentialCache(); myCache.Add(new Uri(rs.Url), "kerberos" , new System.Net.NetworkCredential("username", "password", "Domain")); rs.Credentials = myCache; The URL and credentials are all correct. But still getting a 401 when I cal rs.Render(...). The Reporting Services install is sitting on a Windows Server 2008 box and requires integrated authentication. Thanks

    Read the article

  • Are SqlCipher open cursors a security concern?

    - by user1178479
    I'm using SqlCipher with content providers. Right now, when I want to lock the app I just clear out the cached password. However, the app can continue to work with any open cursors. This means that re-opening the app grants access to the sensitive data. I fix this issue on the surface by redirecting to a login screen if the app doesn't have passwords. However, I'm concerned if there are any security issues with these open cursors or if I should just continue to block UI access and not worry? SqlCipher's docs say that it reads/writes encrypted pages on the fly, as opposed to decrypting the entire DB, this makes me think that open cursors are still secure. The main concern here is that someone loses their phone and then a knowledgeable individual can use these open cursors to extract sensitive data.

    Read the article

  • Using sessions & session variables in a PHP Login Script

    - by user1325291
    I have just finished creating an entire login and register systsem in PHP, but my problem is I haven't used any sessions yet. (Like, there's not the word "session" in the entire script). I'm kind of a newbie in PHP and I've never used sessions before. What I want to do it, after the user registers and fills out the login form, they will still stay on the same page. So, like one half of the page will be if the session is logged_in and the other part will be else (the user is not logged in so display the login form). I also want to create session variables which will hold the username and password given at login. Thanks in advance! BTW this is my website - CP Cheats

    Read the article

  • What is wrong with my Basic Authentication in FireFox?

    - by Pure.Krome
    Hi folks, i'm trying to goto the following url :- http://user1:pass1@localhost:1234/api/users?format=xml nothing to complex. Notice how i've got the username/password in the url? this, i believe, is for basic authentication. When i do that, the Request Headers are MISSING the 'Authorize' header. Er... that's not right :( I have anonymous authentication only setup on the site. I don't want to have anon off and basic turned on .. because not all of the site requires basic.. only a few action methods. So .. why is this not working? Is this something to do with the fact my code is not sending a 401 challenge or some crap? For What It's Worth, my site is ASP.NET MVC1 running on IIS7 (and the same thing happens when i run it on cassini).

    Read the article

  • Good design of mapping Java Domain objects to Tables (using Hibernate)

    - by M. McKenzie
    Hey guys, I have a question that is more in the realm of design, than implementation. I'm also happy for anyone to point out resources for the answer and I'll gladly, research for myself. Highly simplified Java and SQL: Say I have a business domain POJO called 'Picture' with three attributes. class Picture int idPicture String fileName long size Say I have another business domain POJO called "Item" with 3 attributes Class Item int idItem String itemName ArrayList itemPictures These would be a normal simple relationship. You could say that 'Picture' object, will never exist outside an 'Item' object. Assume a picture belongs only to a specific item, but that an item can have multiple pictures Now - using good database design (3rd Normal Form), we know that we should put items and pictures in their own tables. Here is what I assume would be correct. table Item int idItem (primary key) String itemName table Picture int idPicture (primary key) varchar(45) fileName long size int idItem (foreign key) Here is my question: If you are making Hibernate mapping files for these objects. In the data design, your Picture table needs a column to refer to the Item, so that a foreign key relation can be maintained. However,in your business domain objects - your Picture does not hold a reference/attribute to the idItem - and does not need to know it. A java Picture instance is always instantiated inside an Item instance. If you want to know the Item that the Picture belongs to you are already in the correct scope. Call myItem.getIdItem() and myItem.getItemPictures(),and you have the two pieces of information you need. I know that Hibernate tools have a generator that can auto make your POJO's from looking at your database. My problem stems from the fact that I planned out the data design for this experiment/project first. Then when I went to make the domain java objects, I realized that good design dictated that the objects hold other objects in a nested way. This is obviously different from the way that a database schema is - where all objects(tables) are flat and hold no other complex types within them. What is a good way to reconcile this? Would you: (A) Make the hibernate mapping files so that Picture.hbm.xml has a mapping to the POJO parent's idItem Field (if it's even possible) (B) Add an int attribute in the Picture class to refer to the idItem and set it at instantiation, thus simplifying the hbm.xml mapping file by having all table fields as local attributes in the class (C) Fix the database design because it is wrong, dork. I'd truly appreciate any feedback

    Read the article

  • http authenitcation in xcode

    - by user313100
    I am trying to make twitter work in my app and everything works fine except the code does not seem to recognize an error from twitter. If the username/password are not valid, I get an error message through this function: - (void)connection:(NSURLConnection *)connection didReceiveData:(NSData *)data { NSString* strData = [[[NSString alloc] initWithBytes:[data bytes] length:[data length] encoding:NSASCIIStringEncoding] autorelease]; NSLog(@"Received data: %@", strData ) ; return ; } It prints: Received data: Could not authenticate you. . However, the app continues to the post a tweet view I have and ignores the error. Obviously, I do not have something setup right to detect such an error from twitter so my question is how do I get xcode to recognize an error like this? This uses basic http auth btw and don't mention anything about OAuth...just trying to get this to work for now.

    Read the article

  • creating multiple users for a c#.net winform application using sql server express

    - by sqlchild
    i have a single sql database in sql server express. i have a login MAINLOGIN, for this database. i want insertion of data in this database through multiple users, U1,U2,U3, each having different userids & passwords. These users would be created by MAINLOGIN , manually or via the winform application. So while creating MAINLOGIN , i would give him permission to further create logins. For this what should i do? i cannot create MULTIPLE users, because for one database, only one user can be created under one login. so should i create multiple logins, L1,L2,L3, then map, U1, U2, U3 to them. Or, is there a better way to do this? like application roles etc. i dont want to use windows authentication. because if i know the system password, then i could simply connect sql via the application and insert wrong data.

    Read the article

  • I want to keep the values on textbox after onchange function

    - by user1908045
    hello i have problem with this code..I want to keep the values of the textboxes when the pageload and didnt write again the values. I have two drop down list. the First one is the country when the country selected then the page load and appear the city to select but afte the pageload the values on textbox is empty. I want to keep the values of textbox when the page load. This is the code <head> <script type="text/javascript"> function Load_id() { var Count = document.getElementById("Count").value; var Count_txt = "?Count=" location = Count_txt + Count } </script> <meta charset="UTF-8"> </head> <body> <div class="main"> <div class="headers"> <table> <tr><td rowspan="2"><img alt="unipi" src="/Images/logo.jpeg" height="75" width="52"></td> <td>University</td></tr> <tr><td>Data</td></tr> </table> </div> <div class="form"> <h3>Personal</h3><br/><br/><br/> <form id="Page1" name="Page1" action="Form1Sub.php" method="Post"> <table style="width:520px;text-align:left;"> <tr><td><label>Number:</label></td> <td><input type="text" required="required" id="AM" name="AM" value=""/></td> </tr> <tr><td><label>Name:</label></td> <td><input type="text" required="required" name="Name"/></td> </tr> <?php $host="localhost"; $username=""; $password=""; $dbName="Database"; $connection = mysql_connect($host, $username, $password) or die("Couldn't Connect to the Server"); $db = mysql_select_db($dbName, $connection) or die("cannot select DataBase"); $Count = $_GET['Count']; echo "<tr><td><label>Country</label></td>\n"; $country = mysql_query("select DISTINCT Country FROM lut_country_city "); echo " <td><select id=\"Count\" name=\"cat\" onChange=\"Load_id(this)\">\n"; echo " `<option>Select Country</option>\n"; while($nt=mysql_fetch_array($country)){ $selected = ($nt["Country"] == $Count)? "SELECTED":""; echo"<option value=\"".$nt['Country']."\"". $selected." >".$nt['Country']."</option>"; } echo " </select></td></tr>\n"; echo"<tr><td><label>City:</label></td>\n"; $q2 = mysql_query("Select id,City,Country FROM lut_country_city WHERE Country = '$Count'"); echo"<td><select name=\"SelectCity\">\n"; while($row = mysql_fetch_array($q2)) { echo"<option value=\"".$row['id']."\">".$row['City']."</option>"; } echo " </select></td></tr>\n"; ?> </table> <p> <button type="submit" id="Next">Next</button> </form> <form id="form1" action="index.php"> <button id="Back" type="submit">Back</button> </form> </p> </div> </div> </body> </html>

    Read the article

  • Login fails after upgrade to ASP.net 4.0 from 3.5

    - by lomac
    I cannot log in using any of the membership accounts using .net 4.0 version of the app. It fails like it's the wrong password, and FailedPasswordAttemptCount is incremented in my_aspnet_membership table. (I am using membership with mysql membership provider.) I can create new users. They appear in the database. But I cannot log in using the new user credentials (yes, IsApproved is 1). One clue is that the hashed passwords in the database is longer for the users created using the asp.net 4.0 version, e.g 3lwRden4e4Cm+cWVY/spa8oC3XGiKyQ2UWs5fxQ5l7g=, and the old .net 3.5 ones are all like +JQf1EcttK+3fZiFpbBANKVa92c=. I can still log in when connecting to the same db with the .net 3.5 version, but only to the old accounts, not the new ones created with the .net 4.0 version. The 4.0 version cannot log in to any accounts. I tried dropping the whole database on my test system, the membership tables are then auto created on first run, but it's still the same, can create users, but can't log in.

    Read the article

  • MySQL with Java: Open connection only if possible

    - by emempe
    I'm running a database-heavy Java application on a cluster, using Connector/J 5.1.14. Therefore, I have up to 150 concurrent tasks accessing the same MySQL database. I get the following error: Exception in thread "main" com.mysql.jdbc.exceptions.jdbc4.MySQLNonTransientConnectionException: Too many connections This happens because the server can't handle so many connections. I can't change anything on the database server. So my question is: Can I check if a connection is possible BEFORE I actually connect to the database? Something like this (pseudo code): check database for open connection slots if (slot is free) { Connection cn = DriverManager.getConnection(url, username, password); } else { wait ... } Cheers

    Read the article

  • What to keep in mind when creating your own custom web services API?

    - by John Conde
    I have created a website which allows users to sign up for, and use, an online service. To help promote the website we will be have resellers who will be offering their own branded services through us. The initial plan is to allow resellers to place registration, login, and lost password forms on their own website and use an API created by us to handle these requests. I have begun outlining how I expect the API to work (and starting documenting it as well) and I want to make sure I get it right, or as close to right, as I can from the beginning as I know once you have declared a public API you want to avoid changing that API at all costs. So far I have decided: To have the user pass their account credentials with each request To require SSL for all requests What else should I be keeping in mind?

    Read the article

  • vb.net : is it possible to connect to sql server 2008 via odbc but not through vb.net code?

    - by phill
    I'm supporting an old vb.net program whose database it connected to was moved from SQL Server 2005 to SQL Server 2008. Is there a setting on SQL Server 2008 which will allow ODBC connections to access the database but not allow VB.NET to connect to it programmatically? the error i keep receiving in the app is: An error has occurred while establishing a connection to the server. When connecting to SQL Server 2005, this failure may be caused by the fact that under the default settings SQL Server does not allow remote connections. (provider: Named Pipes Provider, error: 40 – Could not open a connection to SQL Server) however I can connect to it when I create a system dsn to the sql server instance and through VS2005's Tools Connect to Database. Here is the code I'm using to connect: dim strC as string strC = "data source=bob; database=subscribers; user id=bobuser; password=passme" dim connection as New SqlClient.SqlConnection(strC) try connection.open() catch ex as Exception msgbox(ex.message) end try connection.Close()

    Read the article

  • Active Directory on local server and intranet on external server.

    - by cvack
    I have a local Active Directory server and a external web server where my intranet is located. $ad = ldap_connect("ldap://ip-address") or die("Couldn't connect to AD!"); ldap_set_option($ad, LDAP_OPT_PROTOCOL_VERSION, 3); $bd = ldap_bind( $ad, "user@domain", "password") or die("Can't bind to server."); When I run this on a local web server it succesfully binds the connection. If I run the same code on the external server its unable to bind the ldap connection. Both port 389 and 636 is open on the AD server. I've tried google for an answer, but all the tutorials is for Active Directory and webserver on the same server. Is this even possible?

    Read the article

  • A column ID occurred more than once in the specification

    - by Puzzle84
    Recently i've picked up my EF 4.1 / MVC 3 project again and started building in actual frontend capabilities. Now i'm developing a "simple" message system but upon going to that page i get the error as stated in the title EDIT It creates the database just not the models. Stack trace: [NullReferenceException: Object reference not set to an instance of an object.] ASP._Page_Views_Inbox_Index_cshtml.Execute() in c:\Development\MVC\DOCCL\Views\Inbox\Index.cshtml:18 System.Web.WebPages.WebPageBase.ExecutePageHierarchy() +197 System.Web.Mvc.WebViewPage.ExecutePageHierarchy() +81 System.Web.WebPages.StartPage.RunPage() +17 System.Web.WebPages.StartPage.ExecutePageHierarchy() +62 System.Web.WebPages.WebPageBase.ExecutePageHierarchy(WebPageContext pageContext, TextWriter writer, WebPageRenderingBase startPage) +76 System.Web.Mvc.RazorView.RenderView(ViewContext viewContext, TextWriter writer, Object instance) +222 System.Web.Mvc.BuildManagerCompiledView.Render(ViewContext viewContext, TextWriter writer) +115 System.Web.Mvc.ViewResultBase.ExecuteResult(ControllerContext context) +295 System.Web.Mvc.ControllerActionInvoker.InvokeActionResult(ControllerContext controllerContext, ActionResult actionResult) +13 System.Web.Mvc.<c_DisplayClass1c.b_19() +23 System.Web.Mvc.ControllerActionInvoker.InvokeActionResultFilter(IResultFilter filter, ResultExecutingContext preContext, Func1 continuation) +242 System.Web.Mvc.<>c__DisplayClass1e.<InvokeActionResultWithFilters>b__1b() +21 System.Web.Mvc.ControllerActionInvoker.InvokeActionResultWithFilters(ControllerContext controllerContext, IList1 filters, ActionResult actionResult) +177 System.Web.Mvc.ControllerActionInvoker.InvokeAction(ControllerContext controllerContext, String actionName) +324 System.Web.Mvc.Controller.ExecuteCore() +106 System.Web.Mvc.ControllerBase.Execute(RequestContext requestContext) +91 System.Web.Mvc.ControllerBase.System.Web.Mvc.IController.Execute(RequestContext requestContext) +10 System.Web.Mvc.<c_DisplayClassb.b_5() +34 System.Web.Mvc.Async.<c_DisplayClass1.b_0() +19 System.Web.Mvc.Async.<c_DisplayClass81.<BeginSynchronous>b__7(IAsyncResult _) +10 System.Web.Mvc.Async.WrappedAsyncResult1.End() +62 System.Web.Mvc.<c_DisplayClasse.b_d() +48 System.Web.Mvc.SecurityUtil.b_0(Action f) +7 System.Web.Mvc.SecurityUtil.ProcessInApplicationTrust(Action action) +22 System.Web.Mvc.MvcHandler.EndProcessRequest(IAsyncResult asyncResult) +60 System.Web.Mvc.MvcHandler.System.Web.IHttpAsyncHandler.EndProcessRequest(IAsyncResult result) +9 System.Web.CallHandlerExecutionStep.System.Web.HttpApplication.IExecutionStep.Execute() +9478661 System.Web.HttpApplication.ExecuteStep(IExecutionStep step, Boolean& completedSynchronously) +178 InnerException : {"A column ID occurred more than once in the specification."} The recently added code is. Controller: // // GET: /Inbox/Index/5/1 public ActionResult Index(int? Id, int Page = 1) { try { const int pageSize = 10; var messages = from m in horseTracker.Messages where m.ReceiverId.Equals(Id) select m; var paginatedMessages = new PaginatedList<Message>(messages, Page, pageSize); return View(paginatedMessages); } catch (Exception ex) { } return View(); } Models public class Message { [Key] public int Id { get; set; } [Required(ErrorMessage = "Subject is required")] [Display(Name = "Subject")] public string Subject { get; set; } [Required(ErrorMessage = "Message is required")] [Display(Name = "Message")] public string Content { get; set; } [Required] [Display(Name = "Date")] public DateTime Created { get; set; } public Boolean Read { get; set; } [Required(ErrorMessage = "Can't create a message without a user")] public int SenderId { get; set; } public virtual User Sender { get; set; } [Required(ErrorMessage = "Please pick a recipient")] public int ReceiverId { get; set; } public virtual User Receiver { get; set; } } public class User { [Key] public int Id { get; set; } [Required] [Display(Name = "Username")] public string UserName { get; set; } [Required] [Display(Name = "First Name")] public string FirstName { get; set; } [Required] [Display(Name = "Last Name")] public string LastName { get; set; } [Required] [Display(Name = "E-Mail")] public string Email { get; set; } [Required] [Display(Name = "Password")] public string Password { get; set; } [Required] [Display(Name = "Country")] public string Country { get; set; } public string EMail { get; set; } //Races public virtual ICollection<Message> Messages { get; set; } } modelBuilder.Entity<User>() .HasMany(u => u.Messages) .WithRequired(m => m.Receiver) .HasForeignKey(m => m.ReceiverId) .WillCascadeOnDelete(false); Anyone have a clue on why i might be getting that error? Before i added these classes it was working fine.

    Read the article

  • Making a Link Appear if a Condition is Met

    - by John
    Hello, The PHP code below echoes a link if the "loginid" of the logged-in user is on a list determined by getEditorList();. It works fairly well, but I think it might work better if I were to do it with Javascript instead. How could I accomplish the same thing with Javascript? Thanks in advance, John $editors = getEditorsList(); foreach($editors as $editor) { $editorids[] = $editor['loginid']; } if(in_array($_SESSION['loginid'], $editorids)) { echo "<div class='footervote'><a href='http://www...com/.../footervote.php'>Vote</a></div>"; } Login function: <?php if (!isLoggedIn()) { if (isset($_POST['cmdlogin'])) { if (checkLogin($_POST['username'], $_POST['password'])) { show_userbox(); } else { echo "Incorrect Login information !"; show_loginform(); } } else { show_loginform(); } } else { show_userbox(); } ?>

    Read the article

  • 400 error when submitting tumblr post (ruby on rails)

    - by Matenia Rossides
    I am having a bit of an issue with getting tumblr working within a rails app. This is the snippet of code which results in a 400 error (meaning that there was an incorrect parameter) @postcontent = @post.content.gsub(/<\/?[^>]*>/, "") post = Tumblr::Post.create(:email => 'valid@email', :password => 'mypassword', :type => 'video', :embed = @post.video_html, :caption = @postcontent) I have checked the API docs and checked my code and code content being rendered, and it still does not want to work. The funny thing is that it worked previously. It was working about a week ago. Has something changed with tumblr?

    Read the article

  • Comparing datetimes does not work

    - by Koning Baard XIV
    I'm creating a Rails application which uses MySQL. I have a table in my DB like this: create_table "pastes", :force => true do |t| t.string "title" t.text "body" t.string "syntax" t.boolean "private" t.datetime "expire" t.string "password" t.datetime "created_at" t.datetime "updated_at" end I want to show only the non-expired pastes to people, so I do this: @pastes = Paste.find(:all, :conditions => "expire < '#{Time.now.strftime('%Y-%m-%d %H:%M:%S')}'") However, even that returns ALL pastes. Not just those that are not expired yet. Can anyone help me? Thanks Oh, changing < to > returns no pastes, not even the non-expired ones :(

    Read the article

  • Inheritance in tables - structure problem

    - by Naor
    I have 3 types of users in my system. each type has different information I created the following tables: BaseUser(base_user_id, username, password, additional common data) base_user_id is PK and Identity UserType1(user_id, data related to type1 only) user_id is PK and FK to base_user_id UserType2(user_id, data related to type2 only) user_id is PK and FK to base_user_id UserType3(user_id, data related to type3 only) user_id is PK and FK to base_user_id Now I have relation from each type of user to warehouses table. Users from type1 and type2 should have only warehouse_id and users from type3 should have warehouse_id and customer_id. I thought about this structure: WarehouseOfUser(base_user_id,warehouse_id) base_user_id is FK to base_user_id in BaseUser WarehouseOfTyp3User(base_user_id,warehouse_id, customer_id) base_user_id is FK to base_user_id in BaseUser The problem is that such structure allows 2 things I want to prevent: 1. add to WarehouseOfTyp3User data of user from type2 or type1. 2. add to WarehouseOfUser data of user from type3. what is the best structure for such case?

    Read the article

  • How to design this simple database?

    - by Vafello
    I have 2 tables - one storing user information (id, username, password) and the second one storing information about events (id, name, description, date, username(represents the user who created the event)). I would like to implement 'favourite events' functionality. This would allow the user to store his favourite events and later display them in a list. I am not sure how to implement this in terms of design. I need a simple solution. Something like storing the IDs of favourite events in a field in the user table. I am using mysql and php. Can anyone point me to the right direction?

    Read the article

  • How to use avg function?

    - by Marcelo
    I'm new at php and mysql stuff and i'm trying to use an avg function but i don't know how to. I'm trying to do something like this: mysql_connect(localhost,$username,$password); @mysql_select_db($database) or die ("Did not connect to $database"); mysql_query("AVG(column1) FROM table1 ") or die(mysql_error()); mysql_close(); echo AVG(column1); (Q1)I'd like to see the value printed in the screen, but i'm getting nothing but an error message. How could I print this average on the screen ? (Q2)If I had a column month in my table1, how could I print the averages by the months ? Sorry for any bad English, and thanks for the attention.

    Read the article

  • How to save position after reload DataGridView

    - by bobik
    this is my code: private void getData(string selectCommand) { string connectionString = @"Server=localhost;User=SYSDBA;Password=masterkey;Database=C:\data\test.fdb"; dataAdapter = new FbDataAdapter(selectCommand, connectionString); DataTable data = new DataTable(); dataAdapter.Fill(data); bindingSource.DataSource = data; } private void button1_Click(object sender, EventArgs e) { getData(dataAdapter.SelectCommand.CommandText); } private void Form1_Load(object sender, EventArgs e) { dataGridView1.DataSource = bindingSource; getData("SELECT * FROM cities"); } after reload data on button1 click, cell selection jumps on first column and scrollbars is reset. How to save position of DataGridView?

    Read the article

  • .NET desktop App remembering login to a webservice

    - by pete the pagan-gerbil
    I am in the planning stages of a .NET desktop app that will communicate with a web service. The web service requires a username and password, and a common feature in this sort of app is to save the user's credentials for the next logon. I've thought of a few ways of achieving this, but I am not sure what the most secure way would be. Should it be stored encrypted in a file (and could someone nefarious copy that file to their own machine and hence logon as the original person), or in the registry somehow (I've not done any registry work before, is it secure and would it work)? Are there any other options I might not have thought of?

    Read the article

< Previous Page | 382 383 384 385 386 387 388 389 390 391 392 393  | Next Page >