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  • Function for putting all database table to an array

    - by jasmine
    I have written a function to print database table to an array like this $db_array= Array( ID=>1, PARENTID =>1, TITLE => LIPSUM, TEXT =>LIPSUM ) My function is: function dbToArray($table) { $allArrays =array(); $query = mysql_query("SELECT * FROM $table"); $dbRow = mysql_fetch_array($query); for ($i=0; $i<count($dbRow) ; $i++) { $allArrays[$i] = $dbRow; } $txt .='<pre>'; $txt .= print_r($allArrays); $txt .= '</pre>'; return $txt; } Anything wrong in my function. Any help is appreciated about my problem. Thanks in advance

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  • Search a string to find which records in table are inside said string

    - by Improfane
    Hello, Say I have a string. Then I have a number of unique tokens or keywords, potentially a large number in a database. I want to search and find out which of these database strings are inside the string I provide (and get the IDs of them). Is there a way of using a query to search the provided string or must it be taken to application space? Am I right in thinking that this is not a 'full text search'? Would the best method be to insert it into the database to make it a full text search?

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  • change password code error

    - by ejah85
    I've created a code to change a password. Now it seem contain an error. When I fill in the form to change password, and click save the error message: Warning: mysql_real_escape_string() expects parameter 2 to be resource, null given in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 103 Warning: mysql_real_escape_string() expects parameter 2 to be resource, null given in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 103 I really don’t know what the error message means. Please guys. Help me fix it. Here's is the code: <?php session_start(); ?> <?php # change password.php //set the page title and include the html header. $page_title = 'Change Your Password'; //include('templates/header.inc'); if(isset($_POST['submit'])){//handle the form require_once('connectioncomplaint.php');//connect to the db. //include "connectioncomplaint.php"; //create a function for escaping the data. function escape_data($data){ global $dbc;//need the connection. if(ini_get('magic_quotes_gpc')){ $data=stripslashes($data); } return mysql_real_escape_string($data, $dbc); }//end function $message=NULL;//create the empty new variable. //check for a username if(empty($_POST['userid'])){ $u=FALSE; $message .='<p> You forgot enter your userid!</p>'; }else{ $u=escape_data($_POST['userid']); } //check for existing password if(empty($_POST['password'])){ $p=FALSE; $message .='<p>You forgot to enter your existing password!</p>'; }else{ $p=escape_data($_POST['password']); } //check for a password and match againts the comfirmed password. if(empty($_POST['password1'])) { $np=FALSE; $message .='<p> you forgot to enter your new password!</p>'; }else{ if($_POST['password1'] == $_POST['password2']){ $np=escape_data($_POST['password1']); }else{ $np=FALSE; $message .='<p> your new password did not match the confirmed new password!</p>'; } } if($u && $p && $np){//if everything's ok. $query="SELECT userid FROM access WHERE (userid='$u' AND password=PASSWORD('$p'))"; $result=@mysql_query($query); $num=mysql_num_rows($result); if($num == 1){ $row=mysql_fetch_array($result, MYSQL_NUM); //make the query $query="UPDATE access SET password=PASSWORD('$np') WHERE userid=$row[0]"; $result=@mysql_query($query);//run the query. if(mysql_affected_rows() == 1) {//if it run ok. //send an email,if desired. echo '<p><b>your password has been changed.</b></p>'; include('templates/footer.inc');//include the HTML footer. exit();//quit the script. }else{//if it did not run OK. $message= '<p>Your password could not be change due to a system error.We apolpgize for any inconvenience.</p><p>' .mysql_error() .'</p>'; } }else{ $message= '<p> Your username and password do not match our records.</p>'; } mysql_close();//close the database connection. }else{ $message .='<p>Please try again.</p>'; } }//end oh=f the submit conditional. //print the error message if there is one. if(isset($message)){ echo'<font color="red">' , $message, '</font>'; } ?> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <body> <script language="JavaScript1.2">mmLoadMenus();</script> <table width="604" height="599" border="0" align="center" cellpadding="0" cellspacing="0"> <tr> <td height="130" colspan="7"><img src="images/banner(E-Complaint)-.jpg" width="759" height="130" /></td> </tr> <tr> <td width="100" height="30" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="100" bgcolor="#ABD519"></td> <td width="160" bgcolor="#ABD519"> <?php include "header.php"; ?>&nbsp;</td> </tr> <tr> <td colspan="7" bgcolor="#FFFFFF"> <fieldset><legend> Enter your information in the form below:</legend> <p><b>User ID:</b> <input type="text" name="username" size="10" maxlength="20" value="<?php if(isset($_POST['userid'])) echo $_POST['userid']; ?>" /></p> <p><b>Current Password:</b> <input type="password" name="password" size="20" maxlength="20" /></p> <p><b>New Password:</b> <input type="password" name="password1" size="20" maxlength="20" /></p> <p><b>Confirm New Password:</b> <input type="password" name="password2" size="20" maxlength="20" /></p> </fieldset> <div align="center"> <input type="submit" name="submit" value="Change My Password" /></div> </form><!--End Form--> </td> </tr> </table> </body> </html>

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  • change password code error.....

    - by shimaTun
    I've created a code to change a password. Now it seem contain an error.before i fill the form. the page display the error message: Parse error: parse error, unexpected $end in C:\Program Files\xampp\htdocs\e-Complaint(FYP)\userChangePass.php on line 222 this the code: <?php # userChangePass.php //this page allows logged in user to change their password. $page_title='Change Your Password'; //if no first_name variable exists, redirect the user if(!isset($_SESSION['nameuser'])){ header("Location: http://" .$_SERVER['HTTP_HOST']. dirname($_SERVER['PHP_SELF'])."/index.php"); ob_end_clean(); exit(); }else{ if(isset($_POST['submit'])) {//handle form. require_once('connectioncomplaint.php'); //connec to the database //check for a new password and match againts the confirmed password. if(eregi ("^[[:alnum:]]{4,20}$", stripslashes(trim($_POST['password1'])))){ if($_POST['password1'] == $_POST['password2']){ $p =escape_data($_POST['password1']); }else{ $p=FALSE; echo'<p><font color="red" size="+1"> Your password did not match the confirmed password!</font></p>'; } }else{ $p=FALSE; echo'<p><font color="red" size="+1"> Please Enter a valid password!</font></p>'; } if($p){ //if everything OK. //make the query $query="UPDATE access SET password=PASSWORD('$p') WHERE userid={$_SESSION['userid']}"; $result=@mysql_query($query);//run the query. if(mysql_affected_rows() == 1) {//if it run ok. //send an email,if desired. echo '<p><b>your password has been changed.</b></p>'; //include('templates/footer.inc');//include the HTML footer. exit(); }else{//if it did not run ok $message= '<p>Your password could not be change due to a system error.We apolpgize for any inconvenience.</p><p>' .mysql_error() .'</p>'; } mysql_close();//close the database connection. }else{//failed the validation test. echo '<p><font color="red" size="+1"> Please try again.</font></p>'; } }//end of the main Submit conditional. ?> And code for form: <h1>Change Your Password</h1> <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> <fieldset> <p><b>New Password:</b><input type="password" name="password1" size="20" maxlength="20" /> <small>Use only letters and numbers.Must be between 4 and 20 characters long.</small></p> <p><b>Confirm New Password:</b><input type="password" name="password2" size="20" maxlength="20" /></p> </fieldset> <div align="center"> <input type="submit" name="submit" value="Change My Password" /></div> </form><!--End Form-->

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  • How phpmyadmin, php and everything else works?

    - by Tom
    Ok, I guess I got crazy, but really. How phpmyadmin works? Does it have his own phpmyadmin or what? And how php works? Why writing echo 'hello'; it returns hello in the browser? I am really interested on how these things really works, maybe you know any books or smth to figure it out? Thank you.

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  • How to make an id auto_increment from where it last left off after a record delete?

    - by Sammy
    This isn't that big of a deal but I was wondering if it can be done. Right now when I insert a new record, the id field which is auto_increment and set as primary key increases it's value by one: id | first_name | last_name ------------------------------ 1 | John | Smith 2 | Jane | Doe But if I delete record 2, the next one I insert is going to have an id of 3. Is there any way to make it have an id of 2 automatically (without having to manually insert it)?

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  • Improving performance in this query

    - by Luiz Gustavo F. Gama
    I have 3 tables with user logins: sis_login = administrators tb_rb_estrutura = coordinators tb_usuario = clients I created a VIEW to unite all these users by separating them by levels, as follows: create view `login_names` as select `n1`.`cod_login` as `id`, '1' as `level`, `n1`.`nom_user` as `name` from `dados`.`sis_login` `n1` union all select `n2`.`id` as `id`, '2' as `level`, `n2`.`nom_funcionario` as `name` from `tb_rb_estrutura` `n2` union all select `n3`.`cod_usuario` as `id`, '3' as `level`, `n3`.`dsc_nome` as `name` from `tb_usuario` `n3`; So, can occur up to three ids repeated for different users, which is why I separated by levels. This VIEW is just to return me user name, according to his id and level. considering it has about 500,000 registered users, this view takes about 1 second to load. too much time, but is becomes very small when I need to return the latest posts on the forum of my website. The tables of the forums return the user id and level, then look for a name in this VIEW. I have registered 18 forums. When I run the query, it takes one second for each forum = 18 seconds. OMG. This page loads every time somebody enter my website. This is my query: select `x`.`forum_id`, `x`.`topic_id`, `l`.`nome` from ( select `t`.`forum_id`, `t`.`topic_id`, `t`.`data`, `t`.`user_id`, `t`.`user_level` from `tb_forum_topics` `t` union all select `a`.`forum_id`, `a`.`topic_id`, `a`.`data`, `a`.`user_id`, `a`.`user_level` from `tb_forum_answers` `a` ) `x` left outer join `login_names` `l` on `l`.`id` = `x`.`user_id` and `l`.`level` = `x`.`user_level` group by `x`.`forum_id` asc USING EXPLAIN: id select_type table type possible_keys key key_len ref rows Extra 1 PRIMARY <derived2> ALL NULL NULL NULL NULL 6 Using temporary; Using filesort 1 PRIMARY <derived4> ALL NULL NULL NULL NULL 530415 4 DERIVED n1 ALL NULL NULL NULL NULL 114 5 UNION n2 ALL NULL NULL NULL NULL 2 6 UNION n3 ALL NULL NULL NULL NULL 530299 NULL UNION RESULT ALL NULL NULL NULL NULL NULL 2 DERIVED t ALL NULL NULL NULL NULL 3 3 UNION r ALL NULL NULL NULL NULL 3 NULL UNION RESULT ALL NULL NULL NULL NULL NULL Somebody can help me or give a suggestion?

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  • mod rewrite, title slugs and htaccess

    - by chris
    I have been taken in to provide some seo guidance on a website which has been running since 2005. My problem is i want to use clean urls. The code that handles the url is hidden away in some class file.. and with over a few thousand lines of code its a struggle to rewrite it. So I'm think, I have gone through all the products and created a slug for them as a field in the product table. Is it possible to do something like an intermediate file for htaccess. Some thing like 1./clean-slug-comes-in/ 2.htaccess catches this and uses slug.php to find the relevant product id for the slug. 3.Then product.php?id=(ID.found.from.2) is loaded?

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  • status update error (null field)

    - by ejah85
    hai guys... i .ve the problem that i cannot be recovered yet... i have one form where admin need to approve or reject the booking request... i've set the b_status field in table usage IN PROCESS default value... i want to update the b_status value BOOKING APPROVED when user click APPROVE button.. otherwise, the b_status will update the value as BOOKING REJECTED when user click on the REJECT button here's is the form code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM vehicle WHERE v_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr><td>&nbsp;</td></tr> <tr> <tr> <td width="200"><font face="Arial" size="2" font color="#000000">Registration Number </font></td> <td><select name="regno"> <option value="" selected>--Registration No--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['regno']; ?>"><?php echo $row['regno']; ?></option> <?php } ?> </select></td> <td><font face="Arial" size="2" font color="#000000">Reason</font></td> <td><textarea name="reason" rows="3" cols="50 "value = ""></textarea></td> </tr> <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $sql="SELECT * FROM driver WHERE d_status='READY'"; $result = mysql_query($sql) or die ("Query failed!"); ?> <tr> <td><font face="Arial" size="2" font color="#000000">Driver</font></td> <td><select id = "d_name" name="d_name"> <option value="" selected>--Driver Name--</option> <?php while($row = mysql_fetch_array($result)){?> <option value="<?php echo $row['d_name']; ?>"><?php echo $row['d_name']; ?></option> <?php } ?> </select></td> </tr> <tr> <?php mysql_close($db); ?> </table> <p></p> <center><input name="APPROVED" type="submit" id="APPROVED" value="APPROVED"> <input name="REJECT" type="submit" id="REJECT" value="REJECT"> </center> </div> </center> and this is the process page code: <?php $db = mysql_connect('localhost','root') or die ("unable to connect"); mysql_select_db('fyp',$db) or die ("able to select"); $bookingno=mysql_real_escape_string($_POST['bookingno']); $username=mysql_real_escape_string($_POST['username']); $name=mysql_real_escape_string($_POST['name']); $department=mysql_real_escape_string($_POST['department']); $g_date=mysql_real_escape_string($_POST['g_date']); $g_time=mysql_real_escape_string($_POST['g_time']); $r_date=mysql_real_escape_string($_POST['r_date']); $r_time=mysql_real_escape_string($_POST['r_time']); $destination=mysql_real_escape_string($_POST['destination']); $pass_num=mysql_real_escape_string($_POST['pass_num']); $trip_purpose=mysql_real_escape_string($_POST['trip_purpose']); $regno=mysql_real_escape_string($_POST['regno']); $d_name=mysql_real_escape_string($_POST['d_name']); $reason=mysql_real_escape_string($_POST['reason']); $b_status=mysql_real_escape_string($_POST['b_status']); $sql = "INSERT INTO `usage` VALUES('$bookingno','$username','$name','$department','$g_date','$g_time','$r_date','$r_time','$destination', '$pass_num','$trip_purpose','$regno','$d_name','$reason','$b_status')"; $query = "INSERT INTO `usage` VALUES b_status ='BOOKING APPROVED'"; $result = @mysql_query($query); $query1 = "UPDATE driver SET d_status ='OUT' WHERE '$d_name'=d_name"; $result1 = @mysql_query($query1); if(isset($_POST['APPROVED'])) { $query2 = "UPDATE `usage` SET b_status ='BOOKING APPROVED' WHERE '$b_status'='IN PROCESS'"; $result2 = @mysql_query($query2); } if (isset($_POST['REJECT'])) { $query3 = "UPDATE `usage` SET b_status ='BOOKING REJECTED' WHERE '$b_status'='IN PROCESS'"; $result3 = @mysql_query($query3); } //$result = mysql_query($sql) or die ("error!"); $result = mysql_query($sql) or trigger_error (mysql_error().' in '.$sql); i.ve the problem on the b_status field.. plz guys... help me ya :-)

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  • How to construct this query? (Ordering by COUNT() and joining with users table)

    - by Andrew
    users table: id-user-other columns scores table: id-user_id-score-other columns They're are more than one rows for each user, but there's only two scores you can have. (0 or 1, == win or loss). So I want to output all the users ordered by the number of wins, and all the users ordered by the numbers of losses. I know how to do this by looping through each user, but I was wondering how to do it with one query. Any help is appreciated!

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  • PHP Show all data in column

    - by user342391
    I am trying to show all of the data in the 'status' column of my table but am having troubles. What am I doing wrong: <?php $query1 = "SELECT id, status FROM alerts WHERE customerid='".$_SESSION['customerid']."' ORDER BY id LIMIT $start, $limit "; $result = mysql_query($query1); while ($row = mysql_fetch_array($result)) { echo $row['status'] ; } ?>

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  • How to exclude rows where matching join is in an SQL tree

    - by Greg K
    Sorry for the poor title, I couldn't think how to concisely describe this problem. I have a set of items that should have a 1-to-1 relationship with an attribute. I have a query to return those rows where the data is wrong and this relationship has been broken (1-to-many). I'm gathering these rows to fix them and restore this 1-to-1 relationship. This is a theoretical simplification of my actual problem but I'll post example table schema here as it was requested. item table: +------------+------------+-----------+ | item_id | name | attr_id | +------------+------------+-----------+ | 1 | BMW 320d | 20 | | 1 | BMW 320d | 21 | | 2 | BMW 335i | 23 | | 2 | BMW 335i | 34 | +------------+------------+-----------+ attribute table: +---------+-----------------+------------+ | attr_id | value | parent_id | +---------+-----------------+------------+ | 20 | SE | 21 | | 21 | M Sport | 0 | | 23 | AC | 24 | | 24 | Climate control | 0 | .... | 34 | Leather seats | 0 | +---------+-----------------+------------+ A simple query to return items with more than one attribute. SELECT item_id, COUNT(DISTINCT(attr_id)) AS attributes FROM item GROUP BY item_id HAVING attributes > 1 This gets me a result set like so: +-----------+------------+ | item_id | attributes | +-----------+------------+ | 1 | 2 | | 2 | 2 | | 3 | 2 | -- etc. -- However, there's an exception. The attribute table can hold a tree structure, via parent links in the table. For certain rows, parent_id can hold the ID of another attribute. There's only one level to this tree. Example: +---------+-----------------+------------+ | attr_id | value | parent_id | +---------+-----------------+------------+ | 20 | SE | 21 | | 21 | M Sport | 0 | .... I do not want to retrieve items in my original query where, for a pair of associated attributes, they related like attributes 20 & 21. I do want to retrieve items where: the attributes have no parent for two or more attributes they are not related (e.g. attributes 23 & 34) Example result desired, just the item ID: +------------+ | item_id | +------------+ | 2 | +------------+ How can I join against attributes from items and exclude these rows? Do I use a temporary table or can I achieve this from a single query? Thanks.

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  • Problem with PHP/Java bridge.

    - by Jack
    I am using Tomcat 6. I am running a php script using the JavaBridge. I get the following error when I run my code. Fatal error: Call to undefined function mysqli_connect() in C:\Program Files\apache-tomcat-6.0.26\webapps\JavaBridge\xxxx\xxxxx.php on line 534 Please help.

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  • Sample/Example needed for a table/field setup

    - by acctman
    Can someone explain the statement below to me with a working sample/example. thanks in advance. You can not create duplicate fields, but simply add a single extra field, "coupleId", which would have a unique id for each couple; and two rows (one for each person) per couple; then JOIN the table against itself with a constraint like a.coupleId = b.coupleId AND a.id < b.id so that you can condense the data into a single result row for a given couple.

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  • PHP MySQLi and MySQLi_STMT: Which insert_id to use?

    - by Carvell Fenton
    Hello all, Both the MySQLi and MySQLi_STMT classes have an $insert_id property. If I am connected to my database using a MySQLi object (say $db), and then I perform an INSERT with a MySQLi_STMT object (say $stmt), to get the id of the last INSERT, should I use: $last_id = $db->insert_id; or $last_id = $stmt->insert_id; Or would they be the same, in which case it doesn't matter? I thought this might be a quick answer for someone, and save me the time of writing the test code to check it. Thanks in advance as always.

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  • Display Events on PHP Calendar

    - by jl
    Hi, I would like to ask if I have a table of events on my database, e.g. description | startdt | enddt event1 | 2010-04-01 10:00:00 | 2010-04-01 13:00:00 event2 | 2010-04-09 14:00:00 | 2010-04-09 18:00:00 event3 | 2010-04-30 11:00:00 | 2010-05-02 16:00:00 I have already created a php calendar, how can I display these above events onto my calendar, so that it will look something like the google calendar? e.g. on the for 2010-04-01, it will display "event1" on the month calendar. Thank you.

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  • Find a date between start_date and end_date

    - by Margaret
    I have a table of events with a recorded start and end time. I want to find all events that occur on a specific date. Some events started a year ago and some will continue farther ahead. I would like to be able to pick for example May 20, 2010 and find all events occurring on that date.

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  • mysql_connect "bool $new_link = true" is very slow

    - by Mikk
    Hi, I'm using latest version of Xampp on 64bit Win7. The problem is that, when I use mysql_connect with "bool $new_link" set to true like so: mysql_connect('localhost', 'root', 'my_password', TRUE); script execution time increases dramatically (about 0,5 seconds per connection, and when I have 4 diffirent objects using different connections, it takes ~2 seconds). Is setting "bool $new_link" to true, generally a bad idea or could it just be some problem with my software configuration. Thank you.

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  • Making a relevant search of text in database using regex

    - by madphp
    Can anyone tell me how I could count the possible instances of a keyword in a block of text? I've split a search term up into separate tokens, so just need to run through and do a count for every instance and removing punctuation or other special characters when making the count. Secondly, if someone has inserted search terms surrounded by double quotes, i want to be able to skip explode, but just count instances of that exact phrase. It doesn't have to be case sensitive and I would like to remove punctuation from the phrase when doing the count. Thirdly, in both cases i want to be able to ignore wordpress and html tags. Lastly, if anyone know any good tutorials for relevant searches that answer the questions above, that would cool too. I've got this far. $results = $wpdb->get_results($sql); $tokens = explode('search_terms'); // Re-arrange Relevant Results foreach ($results As $forum_topic){ foreach($tokens As $token){ // count tokens in topic_title if ($token ){ } } }

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  • Magento Search returns All Products

    - by user338844
    I have set up a website (www.autobodypartsnow.com) and the search function has gone haywire. Whenever you search for anything, it returns every product in the system making it useless. I have fiddled around with it with no prevail. I have done the Like and FullText thing in the Configuration - nothing. I have reset the Search and FS cache. I have actually gone in the product attributes and disabled all the attributes from being searchable (just to see) and Rebuilt the Search Cache, cleared the FS cache and it still does the same thing - which tells me that something it pretty wrong. Any Ideas? Thanks in Advance!

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  • How to compare a string with an option value

    - by user225269
    I have this html form which has options: <tr> <td width="30" height="35"><font size="3">*List:</td> <td width="30"><input name="specific" type="text" id="specific" maxlength="25" value=""> </td> <td><font size="3">*By:</td> <td> <select name="general" id="general"> <font size="3"> <option value="YEAR">Year</option> <option value="ADDRESS">Address</option> </select></td></td> </tr> And I'm trying to have this as the form action: if ('{$_POST["ADDRESS"]}'="ADDRESS") Which will compare if the value in the option in the html form matches the word "Address". If it matches then it will execute this query: $saddress= mysql_real_escape_string($_POST['specific']);<--this is the input form where the user will put the specific address to search. mysql_query("SELECT * FROM student WHERE ADDRESS='$saddress'"); Please I need help in here, I thinks its wrong: if ('{$_POST["ADDRESS"]}'="ADDRESS")

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  • I can't insert data into my database

    - by Ken
    I don't know why, but my data doesn't go into my database 'users' with the table 'data'. <html> <body> <?php date_default_timezone_set("America/Los_Angeles"); include("mainmenu.php"); $con = mysql_connect("localhost", "root", "g00dfor@boy"); if(!$con){ die(mysql_error()); } $usrname = $_POST['usrname']; $fname = $_POST['fname']; $lname = $_POST['lname']; $password = $_POST['password']; $email = $_POST['email']; mysql_select_db(`users`, $con) or die(mysql_error()); mysql_query(INSERT INTO `users`.`data` (`id`, `usrname`, `fname`, `lname`, `email`, `password`) VALUES (NULL, '$usrname', '$fname', '$lname', '$email', 'password')) or die(mysql_error()); mysql_close($con) echo("Thank you for registering!"); ?> </body> </html> All i get is a blank page.

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  • PHP PDO fetch null

    - by Jacob
    How do you check if a columns value is null? Example code: $db = DBCxn::getCxn(); $sql = "SELECT exercise_id, author_id, submission, result, submission_time, total_rating_votes, total_rating_values FROM submissions LEFT OUTER JOIN submission_ratings ON submissions.exercise_id=submission_ratings.exercise_id WHERE id=:id"; $st = $db->prepare($sql); $st->bindParam(":id", $this->id, PDO::PARAM_INT); $st->execute(); $row = $st->fetch(); if($this->total_rating_votes == null) // this doesn't seem to work even though there is no record in submission_ratings???? { ... }

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