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  • Google App Engine appcfg.py data_upload Authentication fail

    - by Pradeep Upadhyay
    Hi, I am using appcfg.py to upload data to datastore from a csv file. But every time I try, I am getting error: [info ] Authentication failed even if i am using Admin id and password. In my app.yaml file I am having: handlers: - url: /remote_api script: $PYTHON_LIB/google/appengine/ext/remote_api/handler.py login: admin - url: .* script: MainHandler.py Can anybody please help me? Thanks in advance.

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  • Java Http request on api.stackexchange with json response

    - by taoder
    I'm trying to use the api-stackexchange with java but when I do the request and try to parse the response with a json parser I have an error. public ArrayList<Question> readJsonStream(InputStream in) throws IOException { JsonReader reader = new JsonReader(new InputStreamReader(in, "UTF-8")); reader.setLenient(true); try { System.out.println(reader.nextString()); // ? special character return readItem(reader); } finally { reader.close(); } } public ArrayList<Question> readItem(JsonReader reader) throws IOException { ArrayList<Question> questions = new ArrayList<Question>(); reader.beginObject(); while (reader.hasNext()) { System.out.println("here");//not print the error is before String name = reader.nextName(); if (name.equals("items")) { questions = readQuestionsArray(reader); } } reader.endObject(); return questions; } public final static void main(String[] args) throws Exception { URIBuilder builder = new URIBuilder(); builder.setScheme("http").setHost("api.stackexchange.com").setPath("/2.0/search") .setParameter("site", "stackoverflow") .setParameter("intitle" ,"workaround") .setParameter("tagged","javascript"); URI uri = builder.build(); String surl = fixEncoding(uri.toString()+"&filter=!)QWRa9I-CAn0PqgUwq7)DVTM"); System.out.println(surl); Test t = new Test(); try { URL url = new URL(surl); t.readJsonStream(url.openStream()); } catch (IOException e) { e.printStackTrace(); } } And the error is: com.google.gson.stream.MalformedJsonException: Expected literal value at line 1 column 19 Here is an example of the Json : { "items": [ { "question_id": 10842231, "score": 0, "title": "How to push oath token to LocalStorage or LocalSession and listen to the Storage Event? (SoundCloud Php/JS bug workaround)", "tags": [ "javascript", "javascript-events", "local-storage", "soundcloud" ], "answers": [ { "question_id": 10842231, "answer_id": 10857488, "score": 0, "is_accepted": false } ], "link": "http://stackoverflow.com/questions/10842231/how-to-push-oath-token-to-localstorage-or-localsession-and-listen-to-the-storage", "is_answered": false },... So what's the problem? Is the Json really malformed? Or did I do something not right? Thanks, Anthony

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  • Why I get java.net.SocketException: Connection reset

    - by Jammy
    I need sent some requests to server side and get reponse, sometimes when I call specific method to run the flollowing common code, I get one error in line(addToCookieJar(connection);), any idea how this get happened? URL url = new URL(providerURL); HttpURLConnection connection = (HttpURLConnection)url.openConnection(); connection.setRequestMethod("POST"); connection.setDoInput(true); connection.setDoOutput(true); connection.setUseCaches(false); connection.setRequestProperty("Content-Type", "application/octet-stream"); // We understand gzip encoding connection.addRequestProperty("Accept-Encoding", "gzip"); if (cookie != null && cookieHandler != null) { connection.setRequestProperty("Cookie", cookie); } if (cookieHandler == null) { addFromCookieJar(connection); } // Send the request ObjectOutputStream oos = new ObjectOutputStream(connection.getOutputStream()); oos.writeObject(remote.getName()); oos.writeObject(m.getName()); // method name oos.writeObject(m.getParameterTypes()); // formal parameters oos.writeObject(args); // actual parameters oos.flush(); oos.close(); if (cookieHandler == null) { cookieJar.put(new URI(providerURL), connection.getHeaderFields()); } Exception: java.lang.reflect.UndeclaredThrowableException at $Proxy0.updateDocument(Unknown Source) at com.agst.ui.gantt.GanttPanel.doUpdateDocument(GanttPanel.java:1931) at com.agst.ui.gantt.GanttPanel.save(GanttPanel.java:1419) at com.agst.ui.gantt.GanttPanel$4.run(GanttPanel.java:1673) at java.lang.Thread.run(Unknown Source) Caused by: java.net.SocketException: Connection reset at sun.reflect.NativeConstructorAccessorImpl.newInstance0(Native Method) at sun.reflect.NativeConstructorAccessorImpl.newInstance(Unknown Source) at sun.reflect.DelegatingConstructorAccessorImpl.newInstance(Unknown Source) at java.lang.reflect.Constructor.newInstance(Unknown Source) at sun.net.www.protocol.http.HttpURLConnection$6.run(Unknown Source) at java.security.AccessController.doPrivileged(Native Method) at sun.net.www.protocol.http.HttpURLConnection.getChainedException(Unknown Source) at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source) at com.agst.rmi.RemoteCallHandler.call(RemoteCallHandler.java:196) at com.agst.rmi.RemoteCallHandler.invoke(RemoteCallHandler.java:142) ... 5 more Caused by: java.net.SocketException: Connection reset at java.net.SocketInputStream.read(Unknown Source) at java.io.BufferedInputStream.fill(Unknown Source) at java.io.BufferedInputStream.read1(Unknown Source) at java.io.BufferedInputStream.read(Unknown Source) at sun.net.www.http.HttpClient.parseHTTPHeader(Unknown Source) at sun.net.www.http.HttpClient.parseHTTP(Unknown Source) at sun.net.www.http.HttpClient.parseHTTP(Unknown Source) at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source) at sun.net.www.protocol.http.HttpURLConnection.getHeaderFields(Unknown Source) at com.agst.rmi.RemoteCallHandler.addToCookieJar(RemoteCallHandler.java:529) at com.agst.rmi.RemoteCallHandler.call(RemoteCallHandler.java:192) ... 6 more

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  • Neither if nor else will run

    - by Arlen Beiler
    I don't know what the problem is. This is the code that is the problem: $thisvb = (int) $key2; if ($thisvb == ($lastvb + 1)) { //This don't work echo '<li>'; } else { '<li value="' . $key2 . '">';} $last = (int) $key2; Below is the full code. <?php $voiceboxes = array( '141133' => array( '1' => array( 'Title' => 'Title2', 'Link' => 'http://...', ), '2' => array( 'Title' => 'Title3', 'Link' => 'http://...', ), '3' => array( 'Title' => 'Title4', 'Link' => 'http://...', ) ) ); $last = 0; //$this = 0; echo "<ol>\n"; foreach ($voiceboxes as $key => $value) { $lastvb = 0; $thisvb = 0; //$voiceboxes[$key]['title'] echo "<ol>\n"; foreach ($value as $key2 => $value2) { $thisvb = (int) $key2; if ($thisvb == ($lastvb + 1)) { //This don't work echo '<li>'; } else { '<li value="' . $key2 . '">';} $last = (int) $key2; echo $voiceboxes[$key][$key2]['Title'] . "<br/>" . $voiceboxes[$key][$key2]['Link'] . '</li>' . "\n"; } } echo "</ol>\n"; echo '</ol>'; ?> This is what I get <ol> <ol> <li>Title2<br/>http://...</li> Title3<br/>http://...</li> <!-- this ain't right, it should start with <li> --> Title4<br/>http://...</li> <!-- same here --> </ol> </ol> I can't figure it out, does anyone know?

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  • How to Open quicktime player on iPad

    - by Saurabh
    Hello All, I am programming an iPad app. In this app I want to open a movie URL in default Quicktime player. When I tried to open the URL in the browser the movie starts playing in the browser. How can I open the movie in the default player (so i can get play pause controls..) Any help would be much appreciated. Thanks Saurabh

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  • How to open tab on mouse over using jquery without using iframe and putting all content in same page

    - by jitendra
    I just want to open another tab without refreshing and on mouse over like this http://fnagel.github.com/jQuery-Accessible-RIA/Tabs/mouseover.html . Is it possible with these things. Pages url should be change like as it now. I want to keep content in separate page on clicking on another tab it should open without refreshing i don't want to open tab content as a iframe I liked the idea of this http://jonplante.com/demo/tabs-1-2/?js=on but page url is not changing so other pages cannot be bookmarked

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  • Can a simple web form like this get hacked?

    - by Haskella
    Hi I have a web form that sends a string to one php file which redirects them to a corresponding URL. I've searched about web form hacking and I've only received information about PHP and SQL... my site only uses a single PHP file, very basic etc. Would it be open to any exploits? I'm obviously not going to post the URL, but here is some code I was working on for the php file: http://stackoverflow.com/questions/2888077/newbie-php-coding-problem-header-function-maybe-i-need-someone-to-check-my-cod Thanks

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  • Problems using Hibernate and Spring in web application

    - by user628480
    Hi.I'm having NullPointerException trying to getCurrentSession() java.lang.NullPointerException servlets.ControlServlet.doPost(ControlServlet.java:46) javax.servlet.http.HttpServlet.service(HttpServlet.java:709) javax.servlet.http.HttpServlet.service(HttpServlet.java:802) I use Tomcat 5.5 index.jsp page: <%@ page language="java" contentType="text/html; charset=ISO-8859-1"pageEncoding="ISO-8859-1"%> <!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd"> <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title></title> </head> <body> <%@ page import="java.util.List" %> <%@ page import="data.Singer" %> <jsp:useBean id="singer" class="data.Singer" scope="session"/> <jsp:setProperty name="singer" property="*" /> <form action="ControlServlet" method="POST"> <form method=“POST”> Name:<br /> <input type=“text” name="name" /><br /> Type:<br /> <input type=“text” name="type" /><br /> <input type="submit" name="Add song" value="Add song"> <input type="submit" name="save" value="Save" /><br><br> <input type ="submit" name="values" value="Get values" > </form> </body> </html> web.xml <?xml version="1.0" encoding="UTF-8"?> <web-app id="WebApp_ID" version="2.4" xmlns="http://java.sun.com/xml/ns/j2ee" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://java.sun.com/xml/ns/j2ee http://java.sun.com/xml/ns/j2ee/web-app_2_4.xsd"> <display-name>webproject</display-name> <context-param> <param-name>contextConfigLocation</param-name> <param-value>/WEB-INF/beans.xml, /WEB-INF/conf.xml, /WEB-INF/singers.hbm.xml, /WEB-INF/songs.hbm.xml, /WEB-INF/singerbeans.xml, /WEB-INF/songbeans.xml</param-value> </context-param> <servlet> <servlet-name>context</servlet-name> <servlet-class>org.springframework.web.context.ContextLoaderServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet> <servlet-name>test</servlet-name> <servlet-class>org.springframework.web.servlet.DispatcherServlet</servlet-class> <load-on-startup>1</load-on-startup> </servlet> <servlet-mapping> <servlet-name>test</servlet-name> <url-pattern>*.*</url-pattern> </servlet-mapping> <servlet> <servlet-name>action</servlet-name> <servlet-class>org.apache.struts.action.ActionServlet</servlet-class> <init-param> <param-name>config</param-name> <param-value>/WEB-INF/beans.xml, /WEB-INF/conf.xml, /WEB-INF/singers.hbm.xml, /WEB-INF/songs.hbm.xml, /WEB-INF/singerbeans.xml, /WEB-INF/songbeans.xml</param-value> </init-param> <init-param> <param-name>debug</param-name> <param-value>2</param-value> </init-param> <init-param> <param-name>detail</param-name> <param-value>2</param-value> </init-param> <load-on-startup>2</load-on-startup> </servlet> <servlet> <description> </description> <display-name>ControlServlet</display-name> <servlet-name>ControlServlet</servlet-name> <servlet-class>servlets.ControlServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>action</servlet-name> <url-pattern>*.*</url-pattern> </servlet-mapping> <servlet-mapping> <servlet-name>ControlServlet</servlet-name> <url-pattern>/ControlServlet</url-pattern> </servlet-mapping> </web-app> ControlServlet.java public class ControlServlet extends HttpServlet { private static final long serialVersionUID = 1L; @Autowired private SingerDao singerdao; public SingerDao getSingerDao() { return singerdao; } public void setSingerDao(SingerDao singerdao) { this.singerdao = singerdao; } public ControlServlet() { super(); // TODO Auto-generated constructor stub } protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { // TODO Auto-generated method stub } protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException { if (request.getParameter("values") != null) { response.getWriter().println(singerdao.getDBValues()); } } } and SingerDao.java public class SingerDao implements SingerDaoInterface { @Autowired private SessionFactory sessionFactory; public void setSessionFactory(SessionFactory sessionFactory) { this.sessionFactory = sessionFactory; } public List getDBValues() { Session session = getCurrentSession(); List<Singer> singers = session.createCriteria(Singer.class).list(); return singers; } private org.hibernate.classic.Session getCurrentSession() { return sessionFactory.getCurrentSession(); } public void updateSinger(Singer singer) { Session session = getCurrentSession(); session.update(singer); } public Singer getSinger(int id) { Singer singer = null; Session session = getCurrentSession(); singer = (Singer) session.load(Singer.class, id); return singer; } public void deleteSinger(Singer singer) { Session session = getCurrentSession(); session.delete(singer); } public void insertRow(Singer singer) { Session session = getCurrentSession(); session.save(singer); } } In simple Java Project it works fine.I think sessionFactory doesn't autowires,but why? Thanks all.

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  • Does calling a click method effect the HtmlPage object if there is a 404?

    - by Blankman
    If I call a click method on a HtmlAnchor, and say that page returns a 404, does that mean the HtmlPage will effect, so searching for another link on the page will result in an error because the page's HTML is the error page (assuming the link is NOT on the error page). Can I manually set the page's HTML, and then locate and click on links and continue on from this approach? (other than connecting via a URL)

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  • Remote desktop in XP?

    - by vineth
    hi, I have enabled remote desktop in my xp sp3 system, (My problem) if my friend take my system in remote with out my authentication my system is connected to him.but few day before i get authentication message(attached in the below link) but nowadays i am not receiving this dialog box... please provide help to get this authentication dialog box.. Link : http://www.freeimagehosting.net/image.php?f9f04c5e0a.jpg Thanks in advance

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  • problem with jQuery menu

    - by ognjenb
    I download menu from http://apycom.com/menus/1-white-smoke.html. When include this menu in my ASP.NET MVC aplication in home page (site.master) menu.js generated link to http://apycom.com. How I remove this link from page?

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  • Javascript AJAX function not working in IE?

    - by Sam152
    I have this code: function render_message(id) { var xmlHttp; xmlHttp=new XMLHttpRequest(); xmlHttp.onreadystatechange=function() { if(xmlHttp.readyState==4) { document.getElementById('message').innerHTML=xmlHttp.responseText; document.getElementById('message').style.display=''; } } var url="include/javascript/message.php"; url=url+"?q="+id; xmlHttp.open("GET",url,true); xmlHttp.send(null); } For some reason it does not work in IE and an error is being reported on this line "document.getElementById('message').innerHTML=xmlHttp.responseText;" with an "Unknown Runtime Error". Can anyone help? Edit: The code being added to the div is valid code ect. Here is the response: <div style="margin-left:auto;margin-right:auto;width:400px;"> <img src="/forum/img/avatars/2.gif" width="90" height="89" style="float:left;"> <div style="margin-left:100px;"> <span style="font-size:16pt;">Sam152</a></span><br> <span style="font-size:10pt;text-transform:uppercase;font-weight:bold;">From Sam152</span><br> <span style="font-size:10pt;font-weight:bold;">Recieved April 17, 2009, 9:44 am</span><br> <br><br> </div> </div> <div style="margin-left:auto;margin-right:auto;width:400px;"> asd</div> <div style="margin-left:auto;margin-right:auto;width:400px;text-align:right;padding-top:10px;"> <span onClick="requestPage('http://www.gametard.com/include/scripts/delete_message.php?id=14');document.getElementById('message14').style.display='none';document.getElementById('message').style.display='none';" class="button">Delete</span> <span onClick="document.getElementById('message').style.display='none';" class="button">Close</span> <span onClick="document.getElementById('to').value ='Sam152';document.getElementById('to').style.color ='#000';document.getElementById('newmessage').style.display='';" class="button">Reply</span> </div>

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  • Wordpress permalinks set

    - by Jimit
    How can I pass category ID using permalinks? my post page id is 205 and for that I used function <?php echo get_page_link('205');?> and I also want to pass category id along with this link, how can I pass category Id with this page link?

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  • Two GET methods in .htaccess

    - by Wayne
    What way it is to be to get two GET methods in the URL by htaccess? RewriteRule ^adm/(.*)$ adm.php?mode=$1 I've used that for the example URL: http://www.domain.com/adm/thismode Now I want to get two methods like: http://www.domain.com/adm/thismode/othermode I've tried this: RewriteRule ^adm/(.*)$/(.*)$ adm.php?mode=$1&othermode=$2 But doesn't seem to work... how do I get it to do that?

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  • C# Parsing html for general use?

    - by Wardy
    What is the best way to take a string of html and turn it in to something useful? Essentially if i take a url and go get the html from that url in .net i get a response but this would come in the form of either a file or stream or string. What if i want an actual document or something I can crawl like an xmldocument object? I have some thoughts and an already implemented solution on this but I am interested to see what the community thinks about this.

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  • YUI dialog - what's the equivalent of postdata when using "form" (not ('async")

    - by jamesmoorecode
    I'm creating a dialog with YAHOO.widget.Dialog. The dialog is fired off by clicking on a link, and the function the link uses specifies parameters that finally get added to a postdata option like so: var myDialog = new YAHOO.widget.Dialog("myDialog", { fixedcenter: true, // postmethod: "form", postdata: propString }); This works just fine, but now I need to do the same thing but using "form" instead of "async" - and there's no postdata for form submissions. What's the right way to do this? (YUI 2.7.0)

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  • Amazon S3 enforcing access control

    - by KandadaBoggu
    I have several PDF files stored in Amazon S3. Each file is associated with a user and only the file owner can access the file. I have enforced this in my download page. But the actual PDF link points to Amazon S3 url, which is accessible to anybody. How do I enforce the access-control rules for this url?(without making my server a proxy for all the PDF download links)

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  • jQuery AJAX Web service works only locally

    - by Greg
    Hi, I have a simple ASP.NET Web Service [WebService(Namespace = "http://tempuri.org/")] [WebServiceBinding(ConformsTo = WsiProfiles.BasicProfile1_1)] [System.Web.Script.Services.ScriptService] public class Service : System.Web.Services.WebService { public Service () { } [WebMethod] public string SetName(string name) { return "hello my dear friend " + name; } } For this Web Service I created Virtual Directory, so I can receive the access by taping http://localhost:89/Service.asmx. I try to call it via simple html page with jQuery. For this purpose I use function CallWS() { $.ajax({ type: "POST", data: "{'name':'Pumba'}", dataType: "json", url: "http://localhost:89/Service.asmx/SetName", contentType: "application/json; charset=utf-8", success: function (msg) { $('#DIVid').html(msg.d); }, error: function (e) { $('#DIVid').html("Error"); } }); The most interesting fact: If I create the html page in the project with my WebService and change url to Service.asmx/SetName everything works excellent. But if I try to call this webservice remotely - success function works but msg is null. After that I tried to call this service even via SOAP. It is the the same - locally it works excellent, but remotely - not at all. var ServiceUrl = 'http://localhost:89/Service.asmx?op=SetName'; function beginSetName(Name) { var soapMessage = '<?xml version="1.0" encoding="utf-8"?> <soap:Envelope xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema" xmlns:soap="http://schemas.xmlsoap.org/soap/envelope/"> <soap:Body> <SetName xmlns="http://tempuri.org/"> <name>' + Name + '</name> </SetName> </soap:Body> </soap:Envelope>'; $.ajax({ url: ServiceUrl, type: "POST", dataType: "xml", data: soapMessage, complete: endSetName, contentType: "text/xml; charset=\"utf-8\"" }); return false; } function endSetName(xmlHttpRequest, status) { $(xmlHttpRequest.responseXML) .find('SetNameResult') .each(function () { var name = $(this).text(); alert(name); }); } In this case status has value "parseerror". Could you please help me to resolve this problem? What should I do to call another WebService remotely by url via jQuery. Thank you in advance, Greg

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  • unit test for proxy checking

    - by zubin71
    Proxy configuration of a machine can be easily fetched using def check_proxy(): import urllib2 http_proxy = urllib2.getproxies().get('http') I need to write a test for the above written function. In order to do that I need to:- Set the system-wide proxy to an invalid URL during the test(sounds like a bad idea). Supply an invalid URL to http_proxy. How can I achieve either of the above?

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  • Rails: Check output of path helper from console

    - by Thor Thurn
    Rails defines a bunch of magic with named routes that make helpers for your routes. Sometimes, especially with nested routes, it can get a little confusing to keep track of what URL you'll get for a given route helper method call. Is it possible to, using the Ruby console, see what link a given helper function will generate? For example, given a named helper like post_path(post) I want to see what URL is generated.

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  • make a div block share a line?

    - by acidzombie24
    -edit- example: http://jsfiddle.net/AXCap/ i want the three links to be on the same line but the 3rd must be a block to take up remaining space in the li so that it is clickable. I tried a number of things and the example linked above is my closest result. How do i make the 3rd link share the same line and a block so the resut of the line is clickable? I tried float left and that does not allow the third link to take up remaining space.

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  • Eclipse plugin using actionset which will prompt a window for selection,how to do??

    - by Rahul
    *In eclipse plugin using actionSet *Here blue icon for some code(using actionset) ,when i click on that it should prompt a window(some popup) which contains two or more link like web links, when i click 1st link it should perform the 1st action and window should disappear so on...Can anyone help me in this how to do that???* See the picture below for reference ..like this with ok button ok should perform the selected action plz help me to do this...??

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  • Background images and Logos

    - by clone1018
    Ok so I have a Background background-image: url('images/body.png'); now I want to overlay a Logo using background-image: url('images/logo.png'); but the Logo is behind the Background. I've tried z-index. But it doesn't help. Any ideas?

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