Search Results

Search found 14348 results on 574 pages for 'planet mysql'.

Page 391/574 | < Previous Page | 387 388 389 390 391 392 393 394 395 396 397 398  | Next Page >

  • Operand should contain 1 column(s) about insert into & select

    - by user1038890
    "insert into NodeProfileSections (profile_no, tpl_section_no) select (np.profile_no, tps.tpl_section_no) from NodeProfile np, TemplateProfileSection tps, TemplateProfile tp where np.hostname = '%s' AND np.role = '%s' AND tp.tpl_profile_no = tps.tpl_profile_no AND tp.tpl_name = '%s' AND tp.role = '%s' AND tps.tpl_section_name = '%s';" %(hostname, role, template_name, role, section_name) error_message = 'Operand should contain 1 column(s)' How to solve this problem?

    Read the article

  • Sphinx without using an auto_increment id

    - by squeeks
    I am current in planning on creating a big database (2+ million rows) with a variety of data from separate sources. I would like to avoid structuring the database around auto_increment ids to help prevent against sync issues with replication, and also because each item inserted will have a alphanumeric product code that is guaranteed to be unique - it seems to me more sense to use that instead. I am looking at a search engine to index this database with Sphinx looking rather appealing due to its design around indexing relational databases. However, looking at various tutorials and documentation seems to show database designs being dependent on an auto_increment field in one form or another and a rather bold statement in the documentation saying that document ids must be 32/64bit integers only or things break. Is there a way to have a database indexed by Sphinx without auto_increment fields as the id?

    Read the article

  • Changing CCK content-types details results in numerous DB calls for the menu system

    - by Paul Strugger
    Every time I make a change in the details of a content-type it takes too long. I though it had to do with the fact that I had too many content-types and fields (~500), but when I load the devel module to see the queries that take that long I see: Executed 32212 queries in 12267.57 milliseconds. Queries taking longer than 5 ms and queries executed more than once, are highlighted. Page execution time was 55763.32 ms When I see the details I notice that the vast majority of db calls come from the menu system, e.g.: _menu_route menu_local_tasks admin_menu_link_save Why is that? Can I avoid some of these? It doesn't seem logical!

    Read the article

  • least value in count

    - by Nyfer
    i have a table employee(id,dept_id,salary,hire_date,job_id) . the following query i have to execute. Show all the employee who were hired on the day of the week on which least no of employee were hired. i have done the query, but am not able to get the least. please check if am correct. select id, WEEKDAY(hire_date)+1 as days,count(WEEKDAY(hire_date)+1) as count from test.employee group by days

    Read the article

  • Persisting Serializable Objects in Hibernate

    - by VeeArr
    I am attempting to persist objects that contain some large Serializable types. I want Hibernate to automatically generate my DDL (using Hibernate annotations). For the most part, this works, but the default database column type used by Hibernate when persisting these types is tinyblob. Unfortunately, this causes crashes when attempting to persist my class, because these types will not fit within the length of tinyblob. However, if I manually set the type (using @Column(columnDefinition="longblob")), it works fine. Is there any way to make the default binary type longblob instead of tinyblob, so that I don't need to manually specify the @Column annotation on each field?

    Read the article

  • Best way to update record X when Y is inserted

    - by Saif Bechan
    I have a huge table that is mainly used for backup and administrative purposes. The only records that matters is the last inserted record. On every hit to order by time inserted is just too slow. I want keep a separate table with the last inserted id. In PHP I now insert, get last inserted id, and update the other table. Is there a more efficient way to do this.

    Read the article

  • Executing multiple update statements in PHP

    - by theband
    I have three update statements to be executed in PHP, i am getting the values of all these as return parameters. How to execute each statement independely and finally show the end user the result that it has been successfully updated. <?php public function name($parameter1,$parameter2.... $parametern) { $records=array(); $sql=""; $sql2=""; $sql3=""; $result=mysql_query($sql); //return $result; if(!$result){throw new Exception(mysql_error());} if(mysql_num_rows($result)==0){return $records;} while($row=mysql_fetch_assoc($result)){$records[]=$row;} return $records; } ?> Then how finally we can get the result in my row object.

    Read the article

  • Update all but one result?

    - by Jack M.
    I'm trying to update a table to remove all but the first instance of a group. Basically, I have a table with vehicle data related to an insurance policy. Each policy should only have one power_unit. Everything else should be a towed unit. Unfortunately, a bug has been duplicating power units, and now I need to clean this up. There are ~10k records in the database, and ~4k of them have doubled up power units. The important bits of my table (call it test1 for now) are: +------------+---------+------+-----+---------+----------------+ | Field | Type | Null | Key | Default | Extra | +------------+---------+------+-----+---------+----------------+ | id | int(10) | NO | PRI | NULL | auto_increment | | policy_id | int(10) | NO | | NULL | | | power_unit | int(1) | NO | | 0 | | +------------+---------+------+-----+---------+----------------+ And some sample data: +----+-----------+------------+ | id | policy_id | power_unit | +----+-----------+------------+ | 1 | 1 | 1 | | 2 | 1 | 1 | | 3 | 1 | 1 | | 4 | 2 | 1 | | 5 | 2 | 1 | | 6 | 2 | 1 | | 7 | 4 | 1 | | 8 | 4 | 1 | | 9 | 4 | 1 | | 10 | 5 | 1 | | 11 | 5 | 1 | | 12 | 6 | 1 | +----+-----------+------------+ Basically I'd like to end up where policy_id 1 has only one power_unit=1. Same for policy_id 2, 3, 4, etc. For policy_id 6, nothing should change (there is only one entry, and it is a power_unit already). I don't know if this is possible, but it was an intriguing problem for me, so I thought you guys might find it the same.

    Read the article

  • SELECT Data from multiple tables?

    - by Kyle R
    I have 3 tables, with 3 fields all the same. I basically want to select information from each table For example: userid = 1 I want to select data from all 3 tables, where userid = 1 I am currently using: SELECT r.*, p.*, l.* FROM random r LEFT JOIN pandom p ON r.userid = p.userid LEFT JOIN landom l ON l.userid = r.userid WHERE r.userid = '1' LIMIT 0, 30 But it doesn't seem to work.

    Read the article

  • Pass database data to multiples views-Laravel

    - by user3696018
    I have a database with details of daily sales. To query a database, I have a form in a view with parameters that will query as date of admission, client and others. The result is shown in another view with the daily details of income, and below is a summary of the article do all entered. The summary I wish to transfer to another view, try to view :: composer but only transfer the empty query (I saw it with debug bar). Just appeared an empty view. How I can transfer data from the database without the latter view is empty? The second html view is totaly diferent , only the data is the same.

    Read the article

  • I can NOT submit the form

    - by buri kuri
    Hey guys Im trying to develop an advance consumer website using php and I stuck somewhere while trying to get the data with submitting to another page. All I want to do is to get the checkbox values which are stored in an array and checked by user. I urgently need your help please here is the code: $sql2="SELECT * FROM alinanfis WHERE alinanfis.fis_id='".$fis."'" ; $resultFis=mysql_query($sql2); if(mysql_num_rows($resultFis)>0) { print "<form method='POST' action='deletionResult.php'>"; print "<table>"; print "<tr>"; print "<th style='background: transparent;'></th>"; print "<th>Fis No</th>"; print "<th>isim</th>"; print "<th>soyisim</th>"; print "<th >Tarih</th>"; print "<th>Fis Tipi</th>"; print "<th>Nerede</th>"; print "<th>Litre</th>"; print "<th>Tutar</th>"; print "</tr>"; while($rowAlinan=mysql_fetch_array($resultFis)) { $sqlFisTipi="SELECT * FROM atype WHERE a_id='".$rowAlinan['a_id']."'" ; $resultFisTipi=mysql_query($sqlFisTipi); $rowFisTipi=mysql_fetch_array($resultFisTipi); $sqlNerede="SELECT * FROM isyeri WHERE i_id='".$rowAlinan['nerde']."'" ; $resultNerede=mysql_query($sqlNerede); $rowNerede=mysql_fetch_array($resultNerede); $sqlMID="SELECT * FROM musteri WHERE m_id='".$rowAlinan['m_id']."'" ; $resultMID1=mysql_query($sqlMID); $rowMID1=mysql_fetch_array($resultMID1); print "<tr>"; print "<td><input name='checkBox[]' type='checkbox' value='".$rowAlinan['fis_id']."' /> php</td>"; print "<td>".$rowAlinan['fis_id']."</td>"; print "<td>".$rowMID1['m_name']."</td>"; print "<td>".$rowMID1['m_lastName']."</td>"; print "<td>".$rowAlinan['alinan_tarih']."</td>"; print "<td>".$rowFisTipi['a_name']."</td>"; print "<td>".$rowNerede['i_name']."</td>"; print "<td>".$rowAlinan['litre']."</td>"; print "<td>".$rowAlinan['tutar']."</td>"; print "</tr>"; } print '<div class="form_settings">'; print "<input class='submit' type='submit' name= 'send' value='Send'>"; / print '</div>'; print "</table>"; print "</form>"; }//end of if(num_rows>0) else echo '*no such receipt found!!'; mysql_close($con);

    Read the article

  • Where to store users visited pages?

    - by kofto4ka
    Hi there. I have a project, where I have posts for example. The task is next: I must show to user his last posts visit. This is my solution: every time user visits new (for him) topic, I create a new record in table visits. Table visits has next structure: id, user_id, post_id, last_visit. Now my tables visits has ~14,000,000 records and its still growing every day.. May be my solution isnt optimal and exists another way how to store users visits? Its important to save every visit as standalone record, because I also have feature to select and use users visits. And I cant purge this table, because data could be needed later month, year. How I could optimize this situation?

    Read the article

  • The table '#sql-5f8_9c' is full

    - by gansodesoya
    hello, im trying to delete a foreign key with the following syntax (5.0.45-community-nt): alter table [table] drop foreign key [fk_name] but I'm getting the folling error: The table '#sql-5f8_9c' is full – 99543 ms any ideas? thanks!

    Read the article

  • CONCAT_WS rows in JOIN

    - by Alex Kiselev
    i have tables profiles (id, name, deleted) categories (id, name, deleted) profiles_categories (id, profile_id, category_id, , deleted) I have wrong query SELECT p.id, p.name CONCAT_WS(', ', c.name) AS keywords_categories FROM profiles p LEFT JOIN profiles_categories pc ON p.id = pc.profile_id LEFT JOIN categories c ON pc.id = c.id WHERE p.deleted = FALSE So, i want have result with all profiles with concan categories.name. Thanks

    Read the article

  • what does this ADO OPEN Method do?

    - by every_answer_gets_a_point
    in plain english can you explain to me what happens here: rs.Open "batchinfo", oConn, adOpenKeyset, adLockOptimistic, adCmdTable what i need to do is to be able to insert values into a table called batchinfo. would this be the best way to do an OPEN? the only thing i would be doing is inserting values.

    Read the article

  • error defining foreign key PhpMyAdmin

    - by Ngounou lassale
    I am new to PhpMyAdmin. I will like to create a foreign key for my tables. In fact i have create tableI with this structures(A as int(11) autoincrement, B as varchar) TableII ( A_2 as int(11) auto increment, B_2 as varchar, A as int(11). I have declared A as an index in tableII, now when i go to relationship view to precise A as a foreign key i always have this error Erreur lors de la création de la clé étrangère sur ID_Ville (vérifiez le type des colonnes) Erreur ALTER TABLE tb_quartier ADD FOREIGN KEY ( ID_Ville ) REFERENCES ingenieris2.tb_ville ( ID_Ville ) ON DELETE RESTRICT ; Please Help thanks!

    Read the article

< Previous Page | 387 388 389 390 391 392 393 394 395 396 397 398  | Next Page >