Search Results

Search found 14016 results on 561 pages for 'n mysql'.

Page 393/561 | < Previous Page | 389 390 391 392 393 394 395 396 397 398 399 400  | Next Page >

  • Calculating number of online visitors?

    - by Syom
    i need to show the number of online visitors, but there is a problem with selecting algoritm to do it! maybe i must create a table in DB, where i'll store ip addresses of visitors and time of visit! by so i can show the count of ip addresses, which's time = NOW() - 10 minutes, for example...("now()-10 minutes" is just to show the logic, i know that this is not a function:) is this goog way to go? or maybe it's better to use AJAX methods to store the data? please give me an idea. Thanks

    Read the article

  • Select value from database and store into a temporary variable

    - by user1616230
    I want to select a stored value from database and then put it into a temporary variable. For example, I have a column called category, one value under it is m, so I want to select this m value from the database, let's say from a table of a database called user_info. Then I want to put it into a variable, let's name it $res. After that, I want to do some condition stuff, such as if $res=="m", Can anyone help me write a simple structure here? Here is the code: <?php $sql = "Select category FROM user_info WHERE user_name = '" .$_SESSION['username']."' and password = '".$_SESSION['password']."'"; $res = mysql_query($sql); if($res == "a"){ include('MPIncomeStrategy.php'); } if($res == "b"){ include('MPIncomeStrategy.php'); } But it seems that the code is not able to detect $res =="category value in database". Did I just use the wrong way to store the category value?

    Read the article

  • How to return result set based on other rows

    - by understack
    I've 2 tables - packages and items. Items table contains all items belonging to the packages along with location information. Like this: Packages table id, name, type(enum{general,special}) 1, name1, general 2, name2, special Items table id, package_id, location 1, 1, America 2, 1, Africa 3, 1, Europe 4, 2, Europe Question: I want to find all 'special' packages belonging to a location and if no special package is found then it should return 'general' packages belonging to same location. So, for 'Europe' : package 2 should be returned since it is special package (Though package 1 also belongs to Europe but not required since its a general package) for 'America' : package 1 should be returned since there are no special packages

    Read the article

  • Put empty spaces in an SQL select

    - by David Undy
    I'm having difficulty creating a month-count select query in SQL. Basically, I have a list of entries, all of which have a date associated with them. What I want the end result to be, is a list containing 12 rows (one for each month), and each row would contain the month number (1 for January, 2 for February, etc), and a count of how many entries had that month set as it's date. Something like this: Month - Count 1 - 12 2 - 0 3 - 7 4 - 0 5 - 9 6 - 0 I can get an result containing months that have a count of higher than 0, but if the month contains no entries, the row isn't created. I get this result just by doing SELECT Month(goalDate) as monthNumber, count(*) as monthCount FROM goalsList WHERE Year(goalDate) = 2012 GROUP BY Month(goalDate) ORDER BY monthNumber Thanks in advance for the help!

    Read the article

  • sql query help join (i think)

    - by milan
    I am having trouble figuring our how I can get results only when products.published, product_types.published, and product_cats.published = 1 but my query isn't working. Please help: SELECT `products`.`title`, `products`.`menu_id`, `products`.`short_description`, `products`.`datasheet_icon`, `products`.`datasheet`, `products`.`ordering`, `products`.`product_type_id`, CASE WHEN CHAR_LENGTH(`products`.`alias`) THEN CONCAT_WS(':', `products`.`id`, `products`.`alias`) ELSE `products`.`id` END AS slug FROM `products`, `product_cats`, `product_types` WHERE `products`.published=1 AND `product_cats`.published=1 AND `product_types`.published=1 AND `products`.`product_cat_id`='42' AND `product_types`.`id` IN (1,40,48,49,50) GROUP BY `products`.`id` ORDER BY `product_types`.`ordering`, `products`.`ordering`

    Read the article

  • Rails: User specific sequential column

    - by Alex Marchant
    I have an inventory system, where a User has many inventory. We have a barcode column which needs to be sequential for each user. I run into a problem however when doing bulk association building. I end up getting several inventories for a user with the same barcode. For example: Inventory Table: id | user_id | barcode 1 | 1 | 1 2 | 1 | 2 3 | 2 | 1 4 | 2 | 2 5 | 1 | 3 In the Inventory model I have before_validation :assign_barcode, on: :create def assign_barcode self.barcode = (user.inventories.order(barcode: :desc).first.try(:barcode) || 0) + 1 end It generally works, but ran into a problem when seeding my db: (1..5).each do user.inventories.build(...) end user.save I end up with a bunch of inventories for user that have the same barcode. How can I ensure that inventories have unique barcodes even when adding inventories in bulk?

    Read the article

  • weird index behavior

    - by TasostheGreat
    I have set up my table with an index only on done_status(done_status =INT), when I use EXPLAIN SELECT * FROM reminder WHERE done_status=2 i get this back id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE reminder ALL done_status NULL NULL NULL 5 Using where but when I give this command EXPLAIN SELECT * FROM reminder WHERE done_status=1 that's what I get back: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE reminder ref done_status done_status 4 const 2 first time it shows me it uses 5 rows second time 2 rows I don't think the index works, if I understood it right first time it should give me 3 rows. What do I do wrong? SHOW INDEX FROM reminder: Table Non_unique Key_name Seq_in_index Column_name Collation Cardinality Sub_part Packed Null Index_type Comment Index_comment reminder 1 done_status 1 done_status A 5 NULL NULL BTREE

    Read the article

  • Update query not effecting all rows in database

    - by Webnet
    I have the following query.... UPDATE vehicle_catalog SET parent_id = 0 WHERE parent_id = SUBSTR(id, 0, 5) I need to set all parent_ids to 0 where the first 5 characters of id is the same as the parent_id. This is effecting 0 rows when I'm looking at the data and it should be effecting over 10,000. Any ideas on why this wouldn't be effecting all rows?

    Read the article

  • Selecting only the entries that have a distinct combination of values?

    - by Theodore E O'Neal
    I have a table, links1, that has the columns headers CardID and AbilityID, that looks like this: CardID | AbilityID 1001 | 1 1001 | 2 1001 | 3 1002 | 2 1002 | 3 1002 | 4 1003 | 3 1003 | 4 1003 | 5 What I want is to be able to return all the CardID that that have two specific AbilityID. For example: If I choose 1 and 2, it returns 1001. If I choose 3 and 4, it returns 1002 and 1003. Is it possible to do this with only one table, or will I need to create an identical table and do an INNER JOIN on those?

    Read the article

  • What does ‘?’ stand for in SQL?

    - by user295189
    I have this SQL by a programmer: $sql = " INSERT INTO `{$database}`.`table` ( `my_id`, `xType`, `subType`, `recordID`, `textarea` ) VALUES ( {$my_id}, ?xType, ?subType, {$recordID}, ?areaText ) "; My question is why is he using ? before values? How do I see what values are coming in? I did echo and it shows ?xType as ?xType. No values. What does ? stand for in SQL?

    Read the article

  • Codeigniter Active record help

    - by sea_1987
    Hello, I am trying to increment a INT column by 1 if a certain field is not null on an update request, currently I have this update too columns, public function updateCronDetails($transaction_reference, $flag, $log) { $data = array ( 'flag' => $flag, 'log' => "$log" ); $this->db->where('transaction_reference', $transaction_reference); $this->db->update('sy_cron', $data); } What I need to know is how I can check if the value being sent to the log field is NULL and if it is how could I increment a column called count by 1?

    Read the article

  • Should user preferences be included in the users table?

    - by Patrick
    I'm creating a members site, and I'm currently working on the user Preference settings. Should I create a table with all the preference fields (about 17 fields) or should I include them in the main member table along with the account settings? Is there a limit as to how many fields I should have in a table? currently the member table has about 21 fields... not sure if its okay to add another 17 more fields when I can easily just put them in another table. It'll take more coding to pull up the data though... any sugguestions?

    Read the article

  • TIME REDUCE(OPTIMISE QUERY)

    - by user2527657
    select a.userid,(select firstName from user where userid=NOTUSED.userid) as z, (select max(login_time) from userLoginTime AS b where userid = a.user_id GROUP BY b.user_id ORDER BY b.user_id) as y From(SELECT DISTINCT a.user_id FROM user AS a LEFT OUTER JOIN (SELECT (userid) FROM userlogintime where serialid=15400012)AS b ON user.user_id = b.user_id where a.Serialid=15400012 AND b.userid IS NULL) NOTUSED, Relation r, user a where r.childuserid = NOTUSED.userid and guarduserid = a.userid

    Read the article

  • php mysqli help, first line in DB not being returned?

    - by williamsongibson
    Here is my code <?php require_once 'connect.php'; $sql = "SELECT * FROM `db-pages`"; $result = $mysqli->query($sql) or die($mysqli->error.__LINE__); while ($row = $result->fetch_assoc()) { echo($row['pagetitle'].' - To edit this page <a href="editpage.php?id='.$row['id'].'">click here</a><br>'); } } ?> I've added a couple more rows to the Database and it's returning them all, apart from id=1 in the DB. Any idea why?

    Read the article

  • Storing data from database [mysql_num_rows]

    - by user1717305
    So I have this code to pass items from database to my order table. When I'm echoing the session. The session variable contains something so there's no problem with that. But when I echo those variables under numrows, it only shows nothing. Is there something wrong? <?php error_reporting(E_ALL ^ E_NOTICE); session_start(); require("connect.php"); $UserID = $_SESSION['CustNum']; $UserN = $_SESSION['UserName']; $ProdGTotal = $_SESSION['ProdGTotal']; $queryord = mysql_query("SELECT * FROM customer WHERE UserName = '$UserN'"); $numrows = mysql_num_rows($queryord); if(numrows == 1){ $row = mysql_fetch_assoc($queryord)or die ('Unable to run query:'.mysql_error()); // fetch associated: get function from a query for a database $dbstreet = $row['Street']; $dhousenum = $row['HouseNum']; $dbcnum = $row['CelNum']; $dbarea = $row['Area']; $dbbuilding = $row['Building']; $dbcity = $row['City']; $dbpnum = $row['PhoneNum']; $dbfname = $row['FName']; $dblname = $row['LName']; } else die(mysql_error()); $query4=mysql_query("INSERT INTO orderdetails VALUES ('', '$UserID', Now(), '$dbhousenum', '$dbstreet', '$dbarea', '$dbbuilding', '$dbcity', '$dbfname', '$dblname', '$dbcnum', '$dbpnum', '$ProdGTotal')",$connect); if ($query4){ header("location:index.php"); } else die(mysql_error()); ?>

    Read the article

  • sprintf and % signs in text

    - by Cameron Conner
    A problem I recently ran into was that when trying to update a field in my database using this code would not work. I traced it back to having a % sign in the text being updated ($note, then $note_escaped)... Inserting it with sprintf worked fine though. Should I not be using sprintf for updates, or should it be formed differently? I did some searching but couldn't come up with anything. $id = mysql_real_escape_string($id); $note_escaped = mysql_real_escape_string($note); $editedby = mysql_real_escape_string($author); $editdate = mysql_real_escape_string($date); //insert info from form into database $query= sprintf("UPDATE notes_$suffix SET note='$note_escaped', editedby='$editedby', editdate='$editdate' WHERE id='$id' LIMIT 1"); Thanks much!

    Read the article

< Previous Page | 389 390 391 392 393 394 395 396 397 398 399 400  | Next Page >