Display two array's in the same table
- by Naeem Ahmed
$row = $query->fetchAll(PDO::FETCH_ASSOC);
$num_rows = count($row);
for ($i = 0; $i < $num_rows; $i++)
{
$title = htmlspecialchars($row[$i]['title']);
$author =htmlspecialchars($row[$i]['author']);
$school =htmlspecialchars($row[$i]['school']);
$solution = $row[$i]['solution'];
$notes = $row[$i]['notes'];
$ad = array($title, $price, $author, $school, $contact, $content, $date);
$inlcude = array($solutions, $notes);
$field = 0;
echo "<table border='1'>";
// foreach($inlcude as $in) This failled miserably
foreach ($ad as $post)
{
if ($field < 3) //The first three values are placed in the first row
{
echo "<td>$post</td>";
}
if ($field >= 3)
{
echo "<tr><td>$post</td><td>$in</td></tr>";
}
$field++;
}
echo '</table>';
}
I have two arrays and I would like to display them in different columns in my table. $ad displays perfectly fine but I'm having trouble displaying the contents in $inlcude in the second column. I've tried putting another foreach loop to iterate through contents of the second array but that really screws up my table by placing random values in different places on the table. Besides the foreach loop, I don't know of any other way to iterate through the array. Any suggestions would be appreciated.Thanks!
