What is the difference between Startup programs in windows and the same programs being started manually
- by sup
I am no Windows guy, but I am trying to get a seamless integration of Windows program through Virtual Box Windows guest onto my Ubuntu machine. I more or less followed this tutorial: https://nowhere.dk/articles/running-windows-applications-natively-with-seamlessrdp
Basically I start up Windows in Virtual Box and then I try to launch an application (on Ubuntu host) like this:
rdesktop -A -s "c:\Program Files\ThinLinc\WTSTools\seamlessrdpshell.exe notepad.exe" 192.168.123.103:3389 -u user -p password
That just gives me full Windows desktop that I do not want. However, when I run (on the Windows guest)
"c:\Program Files\ThinLinc\WTSTools\seamlessrdpshell.exe" "notepad"
The command above works and I get just the window I want. Now, so I thought I would put this command into startup folder of the Windows machine and everything would be fine. But it says "Unable to set up the virtual channel". (by googling, I nailed it to this file: https://sourceforge.net/p/rdesktop/code/1686/tree/seamlessrdp/trunk/ServerExe/vchannel.c - the warning is triggered (by main.c in the same directory) when function vchannel_open() returns something that C interprets as yes for if condition).
I have no idea why it works when I launch this command manually via a bat file and not when I put it to startup programs. Any ideas?
