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  • How is the order of execution for HttpModules determined?

    - by jessegavin
    Suppose that both FirstModule and SecondModule handle the Application_BeginRequest event. Will it execute in the order defined in the web.config? <httpModules> <add type="MyApp.FirstModule, MyApp" name="FirstModule"/> <add type="MyApp.SecondModule, MyApp" name="SecondModule"/> <add type="OtherApp.OtherModule, OtherApp" name="OtherModule"/> </httpModules> Are there other ways that the order can be specified?

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  • Does the order of columns in a query matter?

    - by James Simpson
    When selecting columns from a MySQL table, is performance affected by the order that you select the columns as compared to their order in the table (not considering indexes that may cover the columns)? For example, you have a table with rows uid, name, bday, and you have the following query. SELECT uid, name, bday FROM table Does MySQL see the following query any differently and thus cause any sort of performance hit? SELECT uid, bday, name FROM table

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  • Data structure for an ordered set with many defined subsets; retrieve subsets in same order

    - by Aaron
    I'm looking for an efficient way of storing an ordered list/set of items where: The order of items in the master set changes rapidly (subsets maintain the master set's order) Many subsets can be defined and retrieved The number of members in the master set grow rapidly Members are added to and removed from subsets frequently Must allow for somewhat efficient merging of any number of subsets Performance would ideally be biased toward retrieval of the first N items of any subset (or merged subset), and storage would be in-memory (and maybe eventually persistent on disk)

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  • Will the Order of my Associative Array be maintained from PHP to Javascript?

    - by Colin
    In PHP I'm running a mysql_query that has an ORDER BY clause. I'm then iterating through the results to build an associative array, with the row_id as the key. Then, I'm calling json_encode on that array and outputting the result. This page is loaded with AJAX, and defined in a Javascript variable. When I iterate through that Javascript variable, will I still have the order that was returned from the mysql_query?

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  • Why is my List.Sort method in C# reversing the order of my list?

    - by Fiona Holder
    I have a list of items in a generic list: A1 (sort index 1) A2 (sort index 2) B1 (sort index 3) B2 (sort index 3) B3 (sort index 3) The comparator on them takes the form: this.sortIndex.CompareTo(other.sortIndex) When I do a List.Sort() on the list of items, I get the following order out: A1 A2 B3 B2 B1 It has obviously worked in the sense that the sort indexes are in the right order, but I really don't want it to be re-ordering the 'B' items. Is there any tweak I can make to my comparator to fix this?

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  • How do I get results from a Linq query in the order of IDs that I provide?

    - by Keltex
    I'm looking to get query results back from Linq in the order that I pass IDs to the query. So it would look something like this: var IDs = new int [] { 5, 20, 10 } var items = from mytable in db.MyTable where IDs.Contains(mytable.mytableID) orderby // not sure what to do here select mytable; I'm hoping to get items in the order of IDs (5, 20, 10). (Note this is similar to this question, but I would like to do it in Linq instead of SQL)

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  • Can I reverse the order of a multicast delegate event?

    - by Neil Barnwell
    When you subscribe to an event in .NET, the subscription is added to a multicast delegate. When the event is fired, the delegates are called in the order they were subscribed. I'd like to override the subscription somehow, so that the subscriptions are actually fired in the reverse order. Can this be done, and how? I think something like this might be what I need?: public event MyReversedEvent { add { /* magic! */ } remove { /* magic! */ } }

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  • Change stack order in mobile view at 1140 grid?

    - by iHaveacomputer
    I want to implement the 1140grid at my site. The layout is pretty simple: 100% header 25% sidebar 75% page 100% footer see also http://jsfiddle.net/KB5Nq/ the problem is that i would like to change the stack order when the site is in mobile view: 100% header 100% page 100% sidebar 100% footer however, by default it arranges the blocks in the same order as they appear in the source code: header, sidebar, page, footer. is there an easy css-only fix for that?

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  • ORACLE:- 'SELECT ORDER BY ASC' but 'USA' always first.

    - by Robert
    I have to write a drop down query for countries. But USA should always be first. The rest of the countries are in alphabetical order I tried the following query SELECT countries_id ,countries_name FROM get_countries WHERE countries_id = 138 UNION SELECT countries_id ,countries_name FROM get_countries WHERE countries_id != 138 ORDER BY 2 ASC

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  • Python - 2 Questions: Editing a variable in a function and changing the order of if else statements

    - by Eric
    First of all, I should explain what I'm trying to do first. I'm creating a dungeon crawler-like game, and I'm trying to program the movement of computer characters/monsters in the map. The map is basically a Cartesian coordinate grid. The locations of characters are represented by tuples of the x and y values, (x,y). The game works by turns, and in a turn a character can only move up, down, left or right 1 space. I'm creating a very simple movement system where the character will simply make decisions to move on a turn by turn basis. Essentially a 'forgetful' movement system. A basic flow chart of what I'm intending to do: Find direction towards destination Make a priority list of movements to be done using the direction eg.('r','u','d','l') means it would try to move right first, then up, then down, then left. Try each of the possibilities following the priority order. If the first movement fails (blocked by obstacle etc.), then it would successively try the movements until the first one that is successful, then it would stop. At step 3, the way I'm trying to do it is like this: def move(direction,location): try: -snip- # Tries to move, raises the exception Movementerror if cannot move in the direction return 1 # Indicates movement successful except Movementerror: return 0 # Indicates movement unsuccessful (thus character has not moved yet) prioritylist = ('r','u','d','l') if move('r',location): pass elif move('u',location): pass elif move('d',location): pass elif move('l',location): pass else: pass In the if/else block, the program would try the first movement on the priority on the priority list. At the move function, the character would try to move. If the character is not blocked and does move, it returns 1, leading to the pass where it would stop. If the character is blocked, it returns 0, then it tries the next movement. However, this results in 2 problems: How do I edit a variable passed into a function inside the function itself, while returning if the edit is successful? I have been told that you can't edit a variable inside a function as it won't really change the value of the variable, it just makes the variable inside the function refer to something else while the original variable remain unchanged. So, the solution is to return the value and then assign the variable to the returned value. However, I want it to return another value indicating if this edit is successful, so I want to edit this variable inside the function itself. How do I do so? How do I change the order of the if/else statements to follow the order of the priority list? It needs to be able to change during runtime as the priority list can change resulting in a different order of movement to try.

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  • MySQL Order By Problem, Why is 1000 being seen as Smaller than 2?

    - by Jack
    I have a strange problem, I am trying to order the output of a set of records by a field called displayOrder. Now even though record A has a displayOrder of 2 and record B has a displayOrder of 1000, record B still shows up before record A. Here's my select statement: SELECT * FROM items ORDER BY displayOrder ASC It works fine until I have a record greater than 9, then 10, 11, 12, etc are seen as smaller than 2, 3, 4 because they start with the number 1. Any way to fox this?

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  • Why load increase ,ssd iops increase but cpu iowait decrease?

    - by mq44944
    There is a strange thing on my server which has a mysql running on it. The QPS is more than 4000 but TPS is less than 20. The server load is more than 80 and cpu usr is more than 86% but iowait is less than 8%. The disk iops is more than 16000 and util of disk is more than 99%. When the QPS decreases, the load decreases, the cpu iowait increases. I can't catch this! root@mypc # dmidecode | grep "Product Name" Product Name: PowerEdge R510 Product Name: 084YMW root@mypc # megacli -PDList -aALL |grep "Inquiry Data" Inquiry Data: SEAGATE ST3600057SS ES656SL316PT Inquiry Data: SEAGATE ST3600057SS ES656SL30THV Inquiry Data: ATA INTEL SSDSA2CW300362CVPR201602A6300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR2044037K300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR204402PX300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR204403WN300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR202000HU300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR202001E7300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR204402WE300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR204404E5300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR204401QF300EGN Inquiry Data: ATA INTEL SSDSA2CW300362CVPR20450001300EGN the mysql data files lie on the ssd disks which are organizaed using RAID 10. root@mypc # megacli -LDInfo -L1 -a0 Adapter 0 -- Virtual Drive Information: Virtual Disk: 1 (Target Id: 1) Name: RAID Level: Primary-1, Secondary-0, RAID Level Qualifier-0 Size:1427840MB State: Optimal Stripe Size: 64kB Number Of Drives:2 Span Depth:5 Default Cache Policy: WriteThrough, ReadAheadNone, Direct, No Write Cache if Bad BBU Current Cache Policy: WriteThrough, ReadAheadNone, Direct, No Write Cache if Bad BBU Access Policy: Read/Write Disk Cache Policy: Disk's Default Exit Code: 0x00 -------- -----load-avg---- ---cpu-usage--- ---swap--- -------------------------io-usage----------------------- -QPS- -TPS- -Hit%- time | 1m 5m 15m |usr sys idl iow| si so| r/s w/s rkB/s wkB/s queue await svctm %util| ins upd del sel iud| lor hit| 09:05:29|79.80 64.49 42.00| 82 7 6 5| 0 0|16421.1 10.6262705.9 85.2 8.3 0.5 0.1 99.5| 0 0 0 3968 0| 495482 96.58| 09:05:30|79.80 64.49 42.00| 79 7 8 6| 0 0|15907.4 230.6254409.7 6357.5 8.4 0.5 0.1 98.5| 0 0 0 4195 0| 496434 96.68| 09:05:31|81.34 65.07 42.31| 81 7 7 5| 0 0|16198.7 8.6259029.2 99.8 8.1 0.5 0.1 99.3| 0 0 0 4220 0| 508983 96.70| 09:05:32|81.34 65.07 42.31| 82 7 5 5| 0 0|16746.6 8.7267853.3 92.4 8.5 0.5 0.1 99.4| 0 0 0 4084 0| 503834 96.54| 09:05:33|81.34 65.07 42.31| 81 7 6 5| 0 0|16498.7 9.6263856.8 92.3 8.0 0.5 0.1 99.3| 0 0 0 4030 0| 507051 96.60| 09:05:34|81.34 65.07 42.31| 80 8 7 6| 0 0|16328.4 11.5261101.6 95.8 8.1 0.5 0.1 98.3| 0 0 0 4119 0| 504409 96.63| 09:05:35|81.31 65.33 42.52| 82 7 6 5| 0 0|16374.0 8.7261921.9 92.5 8.1 0.5 0.1 99.7| 0 0 0 4127 0| 507279 96.66| 09:05:36|81.31 65.33 42.52| 81 8 6 5| 0 0|16496.2 8.6263832.0 84.5 8.5 0.5 0.1 99.2| 0 0 0 4100 0| 505054 96.59| 09:05:37|81.31 65.33 42.52| 82 8 6 4| 0 0|16239.4 9.6259768.8 84.3 8.0 0.5 0.1 99.1| 0 0 0 4273 0| 510621 96.72| 09:05:38|81.31 65.33 42.52| 81 7 6 5| 0 0|16349.6 8.7261439.2 81.4 8.2 0.5 0.1 98.9| 0 0 0 4171 0| 510145 96.67| 09:05:39|81.31 65.33 42.52| 82 7 6 5| 0 0|16116.8 8.7257667.6 96.5 8.0 0.5 0.1 99.1| 0 0 0 4348 0| 513093 96.74| 09:05:40|79.60 65.24 42.61| 79 7 7 7| 0 0|16154.2 242.9258390.4 6388.4 8.5 0.5 0.1 99.0| 0 0 0 4033 0| 507244 96.70| 09:05:41|79.60 65.24 42.61| 79 7 8 6| 0 0|16583.1 21.2265129.6 173.5 8.2 0.5 0.1 99.1| 0 0 0 3995 0| 501474 96.57| 09:05:42|79.60 65.24 42.61| 81 8 6 5| 0 0|16281.0 9.7260372.2 69.5 8.3 0.5 0.1 98.7| 0 0 0 4221 0| 509322 96.70| 09:05:43|79.60 65.24 42.61| 80 7 7 6| 0 0|16355.3 8.7261515.5 104.3 8.2 0.5 0.1 99.6| 0 0 0 4087 0| 502052 96.62| -------- -----load-avg---- ---cpu-usage--- ---swap--- -------------------------io-usage----------------------- -QPS- -TPS- -Hit%- time | 1m 5m 15m |usr sys idl iow| si so| r/s w/s rkB/s wkB/s queue await svctm %util| ins upd del sel iud| lor hit| 09:05:44|79.60 65.24 42.61| 83 7 5 4| 0 0|16469.4 11.6263387.0 138.8 8.2 0.5 0.1 98.7| 0 0 0 4292 0| 509979 96.65| 09:05:45|79.07 65.37 42.77| 80 7 6 6| 0 0|16659.5 9.7266478.7 85.0 8.4 0.5 0.1 98.5| 0 0 0 3899 0| 496234 96.54| 09:05:46|79.07 65.37 42.77| 78 7 7 8| 0 0|16752.9 8.7267921.8 97.1 8.4 0.5 0.1 98.9| 0 0 0 4126 0| 508300 96.57| 09:05:47|79.07 65.37 42.77| 82 7 6 5| 0 0|16657.2 9.6266439.3 84.3 8.3 0.5 0.1 98.9| 0 0 0 4086 0| 502171 96.57| 09:05:48|79.07 65.37 42.77| 79 8 6 6| 0 0|16814.5 8.7268924.1 77.6 8.5 0.5 0.1 99.0| 0 0 0 4059 0| 499645 96.52| 09:05:49|79.07 65.37 42.77| 81 7 6 5| 0 0|16553.0 6.8264708.6 42.5 8.3 0.5 0.1 99.4| 0 0 0 4249 0| 501623 96.60| 09:05:50|79.63 65.71 43.01| 79 7 7 7| 0 0|16295.1 246.9260475.0 6442.4 8.7 0.5 0.1 99.1| 0 0 0 4231 0| 511032 96.70| 09:05:51|79.63 65.71 43.01| 80 7 6 6| 0 0|16568.9 8.7264919.7 104.7 8.3 0.5 0.1 99.7| 0 0 0 4272 0| 517177 96.68| 09:05:53|79.63 65.71 43.01| 79 7 7 6| 0 0|16539.0 8.6264502.9 87.6 8.4 0.5 0.1 98.9| 0 0 0 3992 0| 496728 96.52| 09:05:54|79.63 65.71 43.01| 79 7 7 7| 0 0|16527.5 11.6264363.6 92.6 8.5 0.5 0.1 98.8| 0 0 0 4045 0| 502944 96.59| 09:05:55|79.63 65.71 43.01| 80 7 7 6| 0 0|16374.7 12.5261687.2 134.9 8.6 0.5 0.1 99.2| 0 0 0 4143 0| 507006 96.66| 09:05:56|76.05 65.20 42.96| 77 8 8 8| 0 0|16464.9 9.6263314.3 111.9 8.5 0.5 0.1 98.9| 0 0 0 4250 0| 505417 96.64| 09:05:57|76.05 65.20 42.96| 79 7 6 7| 0 0|16460.1 8.8263283.2 93.4 8.3 0.5 0.1 98.8| 0 0 0 4294 0| 508168 96.66| 09:05:58|76.05 65.20 42.96| 80 7 7 7| 0 0|16176.5 9.6258762.1 127.3 8.3 0.5 0.1 98.9| 0 0 0 4160 0| 509349 96.72| 09:05:59|76.05 65.20 42.96| 75 7 9 10| 0 0|16522.0 10.7264274.6 93.1 8.6 0.5 0.1 97.5| 0 0 0 4034 0| 492623 96.51| -------- -----load-avg---- ---cpu-usage--- ---swap--- -------------------------io-usage----------------------- -QPS- -TPS- -Hit%- time | 1m 5m 15m |usr sys idl iow| si so| r/s w/s rkB/s wkB/s queue await svctm %util| ins upd del sel iud| lor hit| 09:06:00|76.05 65.20 42.96| 79 7 7 7| 0 0|16369.6 21.2261867.3 262.5 8.4 0.5 0.1 98.9| 0 0 0 4305 0| 494509 96.59| 09:06:01|75.33 65.23 43.09| 73 6 9 12| 0 0|15864.0 209.3253685.4 6238.0 10.0 0.6 0.1 98.7| 0 0 0 3913 0| 483480 96.62| 09:06:02|75.33 65.23 43.09| 73 7 8 12| 0 0|15854.7 12.7253613.2 93.6 11.0 0.7 0.1 99.0| 0 0 0 4271 0| 483771 96.64| 09:06:03|75.33 65.23 43.09| 75 7 9 9| 0 0|16074.8 8.7257104.3 81.7 8.1 0.5 0.1 98.5| 0 0 0 4060 0| 480701 96.55| 09:06:04|75.33 65.23 43.09| 76 7 8 9| 0 0|16221.7 9.7259500.1 139.4 8.1 0.5 0.1 97.6| 0 0 0 3953 0| 486774 96.56| 09:06:05|74.98 65.33 43.24| 78 7 8 8| 0 0|16330.7 8.7261166.5 85.3 8.2 0.5 0.1 98.5| 0 0 0 3957 0| 481775 96.53| 09:06:06|74.98 65.33 43.24| 75 7 9 9| 0 0|16093.7 11.7257436.1 93.7 8.2 0.5 0.1 99.2| 0 0 0 3938 0| 489251 96.60| 09:06:07|74.98 65.33 43.24| 75 7 5 13| 0 0|15758.9 19.2251989.4 188.2 14.7 0.9 0.1 99.7| 0 0 0 4140 0| 494738 96.70| 09:06:08|74.98 65.33 43.24| 69 7 10 15| 0 0|16166.3 8.7258474.9 81.2 8.9 0.5 0.1 98.7| 0 0 0 3993 0| 487162 96.58| 09:06:09|74.98 65.33 43.24| 74 7 9 10| 0 0|16071.0 8.7257010.9 93.3 8.2 0.5 0.1 99.2| 0 0 0 4098 0| 491557 96.61| 09:06:10|70.98 64.66 43.14| 71 7 9 12| 0 0|15549.6 216.1248701.1 6188.7 8.3 0.5 0.1 97.8| 0 0 0 3879 0| 480832 96.66| 09:06:11|70.98 64.66 43.14| 71 7 10 13| 0 0|16233.7 22.4259568.1 257.1 8.2 0.5 0.1 99.2| 0 0 0 4088 0| 493200 96.62| 09:06:12|70.98 64.66 43.14| 78 7 8 7| 0 0|15932.4 10.6254779.5 108.1 8.1 0.5 0.1 98.6| 0 0 0 4168 0| 489838 96.63| 09:06:13|70.98 64.66 43.14| 71 8 9 12| 0 0|16255.9 11.5259902.3 103.9 8.3 0.5 0.1 98.0| 0 0 0 3874 0| 481246 96.52| 09:06:14|70.98 64.66 43.14| 60 6 16 18| 0 0|15621.0 9.7249826.1 81.9 8.0 0.5 0.1 99.3| 0 0 0 3956 0| 480278 96.65|

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  • Error running heroku console. can't update heroku

    - by Omnipresent
    When I try to run heroku console I get the following error: user@omnipresent:~/rails/demo$ heroku console ! This version of the heroku gem has been deprecated. ! Please update it by running: gem update heroku When I do the update..it says there is nothing to update! user@omnipresent:~/rails/demo$ gem update heroku Updating installed gems Nothing to update Following are my versions: user@omnipresent:~/rails/demo$ heroku version heroku-gem/1.5.2 user@omnipresent:~/rails/demo$ ruby -v ruby 1.9.1p0 (2009-01-30 revision 21907) [i686-linux] user@omnipresent:~/rails/demo$ rails -v Rails 2.3.5

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  • I have the CSS & JS, how do I convert that to erb for my Rails app?

    - by marcamillion
    So I have the foundation of my Rails app, then I went ahead and did the JS and CSS. How do I then take the CSS and JS that I have, and apply it to the app in a 'Rails Way'. i.e. a dynamic way that works nicely. Can you give me some tutorials/articles/resources that I can read up to guide me, please? I have tried the Rails guides, but I find them a bit lacking. Any other good suggestions or tips that might help get me on the right track? Thanks.

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  • Could not load file or assembly ... or one of its dependencies. An attempt was made to load a progra

    - by Dan
    I am getting the following error message when compiling or attempting to run my application on Windows 7 64 bit. I've scoured the internet and many people have the same error message however none of the solutions address my problem or situation. Using VS 2010. Error 38 Could not load file or assembly 'file:///D:/Projects/Windows Projects/Weld/Components/FileAttachments/FileAttachments/FileAttachments/bin/x86/Debug/FileAttaching.dll' or one of its dependencies. An attempt was made to load a program with an incorrect format. Line 1212, position 5. D:\Projects\Windows Projects\Weld\Weld\Weld.UI\frmMain.resx 1212 5 Weld.UI Ok, so I have 2 projects a UI project and a FileAttachment project. UI project has a reference to FileAttachment project. When I compile UI project in "Any CPU" mode everything works fine and it runs. I assume 'Any CPU' will run in 64bit mode when I compile as that is the platform I am using. I want to run/compile as x86 so I try to do that, so I change configuration for all projects to x86 and verify that these configurations are compiling to x86. I compile and get the error as stated above. I find it odd that it compiles and works fine in 64bit but not 32bit. However when compiled and deployed to users as 'Any CPU', if these users have x86 it still works for them no problem. I just can't compile or run as x86 on my PC. Again, I can compile as Any CPU and deploy to a 32bit PC no problem. Neither project are referencing any 64bit only dlls. Both projects are verified to be targetting 32bit dll's and .NET Framework assemblies. I need to compile and run this locally under 32bit mode. I need JIT edit/continue among other things. Here is the line of code in the resx file that is causing the problem: </data> <data name="Appearance17.Image" type="System.Drawing.Bitmap, System.Drawing" mimetype="application/x-microsoft.net.object.bytearray.base64"> <value> The resx file is verified to be generated for .NET 2.0 amnd is only referencing .NET 2.0 assemblies and not .NET 4.0 versions. Any ideas here? I've searched the net and have found hundreds of people with the same error message but a different problem.

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  • Getting rails to execute root level file edits on system files without compromising security.

    - by voxobscuro
    I'm writing a Rails 3 application that needs to be able to trigger modifications to unix system config files. I'd like to insulate the file modifications from the consumer side by running them in a background process. I've considered writing out a temp file in rails and then copying the file with a bash script but that doesn't really insulate the system. I've also considered pulling from the database manually with a cron based script and updating the configs. But what I would really like is a component that can hook into the rails environment, read out what is needed from the database, and update the config files. This process needs to be run as root because the config files mostly live in /etc/whatever. Any suggestions? Thanks!

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  • SQL SERVER – OVER clause with FIRST _VALUE and LAST_VALUE – Analytic Functions Introduced in SQL Server 2012 – ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING

    - by pinaldave
    Yesterday I had discussed two analytical functions FIRST_VALUE and LAST_VALUE. After reading the blog post I received very interesting question. “Don’t you think there is bug in your first example where FIRST_VALUE is remain same but the LAST_VALUE is changing every line. I think the LAST_VALUE should be the highest value in the windows or set of result.” I find this question very interesting because this is very commonly made mistake. No there is no bug in the code. I think what we need is a bit more explanation. Let me attempt that first. Before you do that I suggest you read yesterday’s blog post as this question is related to that blog post. Now let’s have fun following query: USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO The above query will give us the following result: As per the reader’s question the value of the LAST_VALUE function should be always 114 and not increasing as the rows are increased. Let me re-write the above code once again with bit extra T-SQL Syntax. Please pay special attention to the ROW clause which I have added in the above syntax. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND CURRENT ROW) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Now once again check the result of the above query. The result of both the query is same because in OVER clause the default ROWS selection is always UNBOUNDED PRECEDING AND CURRENT ROW. If you want the maximum value of the windows with OVER clause you need to change the syntax to UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING for ROW clause. Now run following query and pay special attention to ROW clause again. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Here is the resultset of the above query which is what questioner was asking. So in simple word, there is no bug but there is additional syntax needed to add to get your desired answer. The same logic also applies to PARTITION BY clause when used. Here is quick example of how we can further partition the query by SalesOrderDetailID with this new functions. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, FIRST_VALUE(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) FstValue, LAST_VALUE(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ROWS BETWEEN UNBOUNDED PRECEDING AND UNBOUNDED FOLLOWING) LstValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Above query will give us windowed resultset on SalesOrderDetailsID as well give us FIRST and LAST value for the windowed resultset. There are lots to discuss for this two functions and we have just explored tip of the iceberg. In future post I will discover it further deep. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • SQL SERVER – Introduction to LEAD and LAG – Analytic Functions Introduced in SQL Server 2012

    - by pinaldave
    SQL Server 2012 introduces new analytical function LEAD() and LAG(). This functions accesses data from a subsequent row (for lead) and previous row (for lag) in the same result set without the use of a self-join . It will be very difficult to explain this in words so I will attempt small example to explain you this function. Instead of creating new table, I will be using AdventureWorks sample database as most of the developer uses that for experiment. Let us fun following query. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, LEAD(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID ) LeadValue, LAG(SalesOrderDetailID) OVER (ORDER BY SalesOrderDetailID ) LagValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Above query will give us following result. When we look at above resultset it is very clear that LEAD function gives us value which is going to come in next line and LAG function gives us value which was encountered in previous line. If we have to generate the same result without using this function we will have to use self join. In future blog post we will see the same. Let us explore this function a bit more. This function not only provide previous or next line but it can also access any line before or after using offset. Let us fun following query, where LEAD and LAG function accesses the row with offset of 2. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, LEAD(SalesOrderDetailID,2) OVER (ORDER BY SalesOrderDetailID ) LeadValue, LAG(SalesOrderDetailID,2) OVER (ORDER BY SalesOrderDetailID ) LagValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Above query will give us following result. You can see the LEAD and LAG functions  now have interval of  rows when they are returning results. As there is interval of two rows the first two rows in LEAD function and last two rows in LAG function will return NULL value. You can easily replace this NULL Value with any other default value by passing third parameter in LEAD and LAG function. Let us fun following query. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, LEAD(SalesOrderDetailID,2,0) OVER (ORDER BY SalesOrderDetailID ) LeadValue, LAG(SalesOrderDetailID,2,0) OVER (ORDER BY SalesOrderDetailID ) LagValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Above query will give us following result, where NULL are now replaced with value 0. Just like any other analytic function we can easily partition this function as well. Let us see the use of PARTITION BY in this clause. USE AdventureWorks GO SELECT s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty, LEAD(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ) LeadValue, LAG(SalesOrderDetailID) OVER (PARTITION BY SalesOrderID ORDER BY SalesOrderDetailID ) LagValue FROM Sales.SalesOrderDetail s WHERE SalesOrderID IN (43670, 43669, 43667, 43663) ORDER BY s.SalesOrderID,s.SalesOrderDetailID,s.OrderQty GO Above query will give us following result, where now the data is partitioned by SalesOrderID and LEAD and LAG functions are returning the appropriate result in that window. As now there are smaller partition in my query, you will see higher presence of NULL. In future blog post we will see how this functions are compared to SELF JOIN. Reference: Pinal Dave (http://blog.SQLAuthority.com) Filed under: Pinal Dave, PostADay, SQL, SQL Authority, SQL Function, SQL Query, SQL Scripts, SQL Server, SQL Tips and Tricks, T SQL, Technology

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  • World Record Siebel PSPP Benchmark on SPARC T4 Servers

    - by Brian
    Oracle's SPARC T4 servers set a new World Record for Oracle's Siebel Platform Sizing and Performance Program (PSPP) benchmark suite. The result used Oracle's Siebel Customer Relationship Management (CRM) Industry Applications Release 8.1.1.4 and Oracle Database 11g Release 2 running Oracle Solaris on three SPARC T4-2 and two SPARC T4-1 servers. The SPARC T4 servers running the Siebel PSPP 8.1.1.4 workload which includes Siebel Call Center and Order Management System demonstrates impressive throughput performance of the SPARC T4 processor by achieving 29,000 users. This is the first Siebel PSPP 8.1.1.4 benchmark supporting 29,000 concurrent users with a rate of 239,748 Business Transactions/hour. The benchmark demonstrates vertical and horizontal scalability of Siebel CRM Release 8.1.1.4 on SPARC T4 servers. Performance Landscape Systems Txn/hr Users Call Center Order Management Response Times (sec) 1 x SPARC T4-1 (1 x SPARC T4 2.85 GHz) – Web 3 x SPARC T4-2 (2 x SPARC T4 2.85 GHz) – App/Gateway 1 x SPARC T4-1 (1 x SPARC T4 2.85 GHz) – DB 239,748 29,000 0.165 0.925 Oracle: Call Center + Order Management Transactions: 197,128 + 42,620 Users: 20300 + 8700 Configuration Summary Web Server Configuration: 1 x SPARC T4-1 server 1 x SPARC T4 processor, 2.85 GHz 128 GB memory Oracle Solaris 10 8/11 iPlanet Web Server 7 Application Server Configuration: 3 x SPARC T4-2 servers, each with 2 x SPARC T4 processor, 2.85 GHz 256 GB memory 3 x 300 GB SAS internal disks Oracle Solaris 10 8/11 Siebel CRM 8.1.1.5 SIA Database Server Configuration: 1 x SPARC T4-1 server 1 x SPARC T4 processor, 2.85 GHz 128 GB memory Oracle Solaris 11 11/11 Oracle Database 11g Release 2 (11.2.0.2) Storage Configuration: 1 x Sun Storage F5100 Flash Array 80 x 24 GB flash modules Benchmark Description Siebel 8.1 PSPP benchmark includes Call Center and Order Management: Siebel Financial Services Call Center – Provides the most complete solution for sales and service, allowing customer service and telesales representatives to provide superior customer support, improve customer loyalty, and increase revenues through cross-selling and up-selling. High-level description of the use cases tested: Incoming Call Creates Opportunity, Quote and Order and Incoming Call Creates Service Request . Three complex business transactions are executed simultaneously for specific number of concurrent users. The ratios of these 3 scenarios were 30%, 40%, 30% respectively, which together were totaling 70% of all transactions simulated in this benchmark. Between each user operation and the next one, the think time averaged approximately 10, 13, and 35 seconds respectively. Siebel Order Management – Oracle's Siebel Order Management allows employees such as salespeople and call center agents to create and manage quotes and orders through their entire life cycle. Siebel Order Management can be tightly integrated with back-office applications allowing users to perform tasks such as checking credit, confirming availability, and monitoring the fulfillment process. High-level description of the use cases tested: Order & Order Items Creation and Order Updates. Two complex Order Management transactions were executed simultaneously for specific number of concurrent users concurrently with aforementioned three Call Center scenarios above. The ratio of these 2 scenarios was 50% each, which together were totaling 30% of all transactions simulated in this benchmark. Between each user operation and the next one, the think time averaged approximately 20 and 67 seconds respectively. Key Points and Best Practices No processor cores or cache were activated or deactivated on the SPARC T-Series systems to achieve special benchmark effects. See Also Siebel White Papers SPARC T4-1 Server oracle.com OTN SPARC T4-2 Server oracle.com OTN Siebel CRM oracle.com OTN Oracle Solaris oracle.com OTN Oracle Database 11g Release 2 Enterprise Edition oracle.com OTN Disclosure Statement Copyright 2012, Oracle and/or its affiliates. All rights reserved. Oracle and Java are registered trademarks of Oracle and/or its affiliates. Other names may be trademarks of their respective owners. Results as of 30 September 2012.

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  • How can order of IP addresses issued be controlled?

    - by warren
    Every home router I've setup/used issues addresses from low to high. However, dhcpd from the Internet Systems Consortium seems to issue addresses in reverse order - ie, high to low. Is there a way to change this so that addresses are issued starting at the bottom of the range, and progress higher?

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