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  • How do I control remote Windows 7 machine? VNC/RDP/?

    - by artfulrobot
    I have a Windows 7 laptop that's going out and about and I'd like to be able to admin' it from my Ubuntu (precise) desktop. While the laptop is in my office I can use Gnome's "Remote Desktop Viewer" (Vinagre) to connect via RDP. However, when it's in the office I don't really need RDP of course! And when it's out of the office I cannot control the routers/firewalls along the way, so I won't know the IP and cannot set up port forwards. I'm looking for a Ubuntu compatible way to achieve this. Nb. I can set up port forwards at the my office end, so a service on the laptop could try a "backwards" connection to my client.

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  • Launching applications on remote windows xp from ubuntu 10.04 machine

    - by Aniket Vibhute
    I have ubuntu 10.04 installed on my machine. I want to execute commands on remote windows xp machine ( I have username and password of admin account of remote machine ) so as to launch application like Internet Explorer, Notepad or some bat script. Is there any command line utility to do this via ubuntu? I tried rdesktop, winexe, ssh, telnet but they are not much of use. Can you please suggest some other way?

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  • Access JBOSS Tomcat Web Application from Remote Computer

    - by Rod
    Hi, I just deployed a web application on JBOSS 4.2. It can be accessed locally only (http://localhost:8080/myApp). I cant access it from remote computer by typing its domain: (www.hostname.com:8080/myApp). I added Port 8080 as Exception in Windows Firewall. Note that the host (www.hostname.com) is reachable from remote computers via IIS on port 80. Thanks, Rod

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  • Remote MySQL connection fails (10060)

    - by Stefan Åstrand
    When I am trying to connect to a MySQL database from a remote computer I get a prompt saying: Connection Failed: [HY000] [MySQL][ODBC 5.1 Driver]Can't Connect to MySQL server on 'XXX.XXX.XX.XX' (10060) I have created a user account in the MySQL Administrator and added a host to enable remote access, I have also made an exception for my Windows Firewall on port 3306 but the connection still fails. What is the problem? Thanks!

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  • How to kill process on Remote Desktop Connection?

    - by user118190
    I am working remotely on a Windows Server via Remote Desktop Connection and some process has hung the server. I looked up how to bring up the Task Manager remote (equivalent of locally doing CTRL+ALT+DEL) and I found CTRL+ALT+END and it doesn't seem to work. I tried logging off and logging back on and the system is still up (tried earlier seeing the properties of My Comptuer, FYI). Does anyone know how I can escape this 'hindrance' and star fresh?!?

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  • How sync the MYSQL database to remote server and from remote to desktop server

    - by qulzam
    I make a application, which has to interfaces. one is desktop and other is web application. both have their own databases (which are same is structure). I want to sync the database from desktop to remote server and also from remote server to desktop but i have no idea that how it does. I use the MYSql database. and my desktop application is in .NET NOTE: There are more than one destop systems who update their databases and also sync databases.

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  • Silverlight play file from samba enabled remote server

    - by Damian
    Hello, Im currently working on Silverlight app, which resides on our ASP.NET webpage. I want to populate listbox with names of (audio wav) files that are on remote linux machine. I also want to be able to play those files using MediaElement. Im wondering if it is possible to get stream of remote samba enabled linux server. thx, for answers

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  • Configure custom SSL certificate for RDP on Windows Server 2012 in Remote Administration mode?

    - by Ryan Bolger
    So the release of Windows Server 2012 has removed a lot of the old Remote Desktop related configuration utilities. In particular, there is no more Remote Desktop Session Host Configuration utility that gave you access to the RDP-Tcp properties dialog that let you configure a custom certificate for the RDSH to use. In its place is a nice new consolidated GUI that is part of the overall "edit deployment properties" workflow in the new Server Manager. The catch is that you only get access to that workflow if you have the Remote Desktop Services role installed (as far as I can tell). This seems like a bit of an oversight on Microsoft's part. How can we configure a custom SSL certificate for RDP on Windows Server 2012 when it's running in the default Remote Administration mode without needlessly installing the Remote Desktop Services role?

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  • Remote desktop logs in with saved credentials when connecting from one computer but asks for username and password from another.

    - by AndrejaKo
    I have two computers on which I recently installed windows 7 64 bit. Using VPN, they connect to remote network on which there is a Windows Server 2000 SP4 computer. User is supposed to connect to server using remote desktop. I set same VPN and remote desktop settings on both computers with Windows 7. I set Remote desktop to save connection credentials on both computers, but when I connect to server form one computer, it uses saved credentials and I don't get log-in prompt on server side. On the other computer with same settings using same username and password, I get log-in prompt once the remote desktop connects to server. I even tried copying the .rdp file from the computer on which everything is working fine to the other computer, but that didn't help. Note that I'm not trying to have both computers connected at the same time. What is causing this and how do I make the other computer skip windows server 2000 log-in prompt.

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  • Can't step into stored procedure on remote SQL Server 2008

    - by abatishchev
    I have a domain installed on virtual Windows Server 2008 x64. SQL Server 2008 Express x64 is running in Windows Server 2008 x64 and client on Windows 7 RTM x86. Both are into the domain. I'm starting both Visual Studio 2008 and SQL Server Management Studio 2008 under domain admin user. This account is a member of group sysadmin on SQL Server. Server has firewall exceptions for both TCP and UDP on ports 135-139 and 1433-1434. Visual Studio 2008 Remote debugger services is started on server and Domain Admins group is allowed to debug, When I'm starting debugging of a query in SMS I'm getting this error: Failed to start debugger Error HRESULT E_FAIL has been returned from a call to a COM component. (mscorlib) Program Location: at System.Runtime.InteropServices.Marshal.ThrowExceptionForHRInternal(Int32 errorCode, IntPtr errorInfo) at Microsoft.SqlServer.Management.UI.VSIntegration.DebugSession.DebugCallbacks.OnSqlInitializeDebuggingEvent(ISqlInitializeDebuggingEvent sqlInitializeDebuggingEvent) at Microsoft.SqlServer.Management.UI.VSIntegration.DebugSession.DebugCallbacks.Microsoft.VisualStudio.Debugger.Interop.IDebugEventCallback2.Event(IDebugEngine2 debugEngine, IDebugProcess2 debugProcess, IDebugProgram2 debugProgram, IDebugThread2 debugThread, IDebugEvent2 debugEvent, Guid& riidEvent, UInt32 attribute) and Unable to access the SQL Server debugging interface. The Visual Studio debugger cannot connect to the remote computer. A firewall may be preventing communication via DCOM to the remote computer. Please see Help for assistance. and Unable to start program MSSSQL://server.mydomain.local/master/sys/=0 And when stepping-in into a stored procedure using VS I'm getting the first one and this: Exception from HRESULT: 0x89710016 What have I do?

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  • storing data at remote server using php

    - by VIPUL GOYAL
    I want to send data to php file and execute insert query in it to store data in database. When i execute this code, it executes but database does not get updated. Code of PHP file Java code------------------------------Remote.java------------------------------ public class Remote extends Activity { EditText name; Button s; String r; @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); name= (EditText)findViewById(R.id.editText1); s=(Button)findViewById(R.id.button1); s.setOnClickListener(new OnClickListener() { public void onClick(View v) { try { r = name.getText().toString(); ArrayList<NameValuePair> postParameters = new ArrayList<NameValuePair>(); postParameters.add(new BasicNameValuePair("username", r)); CustomHttpClient.executeHttpPost("http://vipul.eu5.org/abc.php", postParameters); //Enetr Your remote PHP,ASP, Servlet file link } catch (Exception e) { e.printStackTrace(); } } }); } } -----------------------------CustomHttpClient.java---------------------------- public class CustomHttpClient { private static HttpClient getHttpClient() { if (mHttpClient == null) { mHttpClient = new DefaultHttpClient(); final HttpParams params = mHttpClient.getParams(); HttpConnectionParams.setConnectionTimeout(params, HTTP_TIMEOUT); HttpConnectionParams.setSoTimeout(params, HTTP_TIMEOUT); ConnManagerParams.setTimeout(params, HTTP_TIMEOUT); } return mHttpClient; } /** * Performs an HTTP Post request to the specified url with the * specified parameters. * * @param url The web address to post the request to * @param postParameters The parameters to send via the request * @return The result of the request * @throws Exception */ public static void executeHttpPost(String url, ArrayList postParameters) throws Exception { try { HttpClient client = getHttpClient(); HttpPost request = new HttpPost(url); UrlEncodedFormEntity formEntity = new UrlEncodedFormEntity(postParameters); request.setEntity(formEntity); HttpResponse response = client.execute(request); } catch(Exception e) { } } }

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  • .Net website create directory to remote server access denied

    - by tmfkmoney
    I have a web application that creates directories. The application works fine when creating a directory on the web server, however, it does not work when it tries to create a directory on our remote fileserver. The fileserver and the webserver are in the same domain. I have created a local user in our domain, "DOMAIN\aspnet". The local user is on both servers. I am running my .Net app pool under the domain user. I have also tried using windows impersonate in the web.config to run under the domain user. I have verified that the domain user has full control to the remote directory. In an effort to debug this I have also given the "everyone" full control to the remote directory. In an effort to debug this I have also added the domain user to the administrators group. I have a simple .net test page on the web server to test this. Through the test page I am able to read the directory on the file server and get a list of everything in it. I am not able to upload files or to create directories on the file server. Here's code that works: var path = @"\\fileserver\images\"; var di = new DirectoryInfo(path); foreach (var d in di.GetDirectories()) { Response.Write(d.Name); } Here's code that doesn't work: path = Path.Combine(path, "NewDirectory"); Directory.CreateDirectory(path); Here's the error I'm getting: Access to the path '\fileserver\images\NewDirectory' is denied. I'm pretty stuck on this. Any ideas?

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  • Encryption puzzle / How to create a ProxyStub for a Remote Assistance ticket

    - by Jon Clegg
    I am trying to create a ticket for Remote Assistance. Part of that requires creating a PassStub parameter. As of the documenation: http://msdn.microsoft.com/en-us/library/cc240115(PROT.10).aspx PassStub: The encrypted novice computer's password string. When the Remote Assistance Connection String is sent as a file over e-mail, to provide additional security, a password is used.<16 In part 16 they detail how to create as PassStub. In Windows XP and Windows Server 2003, when a password is used, it is encrypted using PROV_RSA_FULL predefined Cryptographic provider with MD5 hashing and CALG_RC4, the RC4 stream encryption algorithm. As PassStub looks like this in the file: PassStub="LK#6Lh*gCmNDpj" If you want to generate one yourself run msra.exe in Vista or run the Remote Assistance tool in WinXP. The documentation says this stub is the result of the function CryptEncrypt with the key derived from the password and encrypted with the session id (Those are also in the ticket file). The problem is that CryptEncrypt produces a binary output way larger then the 15 byte PassStub. Also the PassStub isn't encoding in any way I've seen before. Some interesting things about the PassStub encoding. After doing statistical analysis the 3rd char is always a one of: !#$&()+-=@^. Only symbols seen everywhere are: *_ . Otherwise the valid characters are 0-9 a-z A-Z. There are a total of 75 valid characters and they are always 15 bytes. Running msra.exe with the same password always generates a different PassStub, indicating that it is not a direct hash but includes the rasessionid as they say. Some other ideas I've had is that it is not the direct result of CryptEncrypt, but a result of the rasessionid in the MD5 hash. In MS-RA (http://msdn.microsoft.com/en-us/library/cc240013(PROT.10).aspx). The "PassStub Novice" is simply hex encoded, and looks to be the right length. The problem is I have no idea how to go from any hash to way the ProxyStub looks like.

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  • Encryption puzzle / How to create a PassStub for a Remote Assistance ticket

    - by Jon Clegg
    I am trying to create a ticket for Remote Assistance. Part of that requires creating a PassStub parameter. As of the documentation: http://msdn.microsoft.com/en-us/library/cc240115(PROT.10).aspx PassStub: The encrypted novice computer's password string. When the Remote Assistance Connection String is sent as a file over e-mail, to provide additional security, a password is used.<16 In part 16 they detail how to create as PassStub. In Windows XP and Windows Server 2003, when a password is used, it is encrypted using PROV_RSA_FULL predefined Cryptographic provider with MD5 hashing and CALG_RC4, the RC4 stream encryption algorithm. As PassStub looks like this in the file: PassStub="LK#6Lh*gCmNDpj" If you want to generate one yourself run msra.exe in Vista or run the Remote Assistance tool in WinXP. The documentation says this stub is the result of the function CryptEncrypt with the key derived from the password and encrypted with the session id (Those are also in the ticket file). The problem is that CryptEncrypt produces a binary output way larger then the 15 byte PassStub. Also the PassStub isn't encoding in any way I've seen before. Some interesting things about the PassStub encoding. After doing statistical analysis the 3rd char is always a one of: !#$&()+-=@^. Only symbols seen everywhere are: *_ . Otherwise the valid characters are 0-9 a-z A-Z. There are a total of 75 valid characters and they are always 15 bytes. Running msra.exe with the same password always generates a different PassStub, indicating that it is not a direct hash but includes the rasessionid as they say. Some other ideas I've had is that it is not the direct result of CryptEncrypt, but a result of the rasessionid in the MD5 hash. In MS-RA (http://msdn.microsoft.com/en-us/library/cc240013(PROT.10).aspx). The "PassStub Novice" is simply hex encoded, and looks to be the right length. The problem is I have no idea how to go from any hash to way the PassStub looks like.

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  • architecture and tools for a remote control application?

    - by slothbear
    I'm working on the design of a remote control application. From my iPhone or a web browser, I'll send a few commands. Soon my home computer will perform the commands and send back results. I know there are remote desktop apps, but I want something programmable, something simpler, and something that I wrote. My current direction is to use Amazon Simple Queue Service (SQS) as the message bus. The iPhone places some messages in a queue. My local Java/JRuby program notices the messages on the queue, performs the work and sends back status via a different queue. This will be a very low-volume application. At $1.00 for a million requests (plus a handful of data transfer charges), Amazon SQS looks a lot more affordable than having my own server of any type. And super reliable, that's important for me too. Are there better/standard toolkits or architectures for this kind of remote control? Cost is not a big issue, but I prefer the tons I learn by doing it myself. I'm moderately concerned about security, but doubt it will be a problem. The list of commands recognized will be very short, and only recognized in specific contexts. No "erase hard drive" stuff. update: I'll probably distribute these programs to some other people who want the same function, but who don't have Amazon SQS accounts. For now, they'll use anonymous access to my queues, with random 80-character queue names.

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  • Add login / logout to drupal menu that's not a primary or secondary menu

    - by user367766
    Hello, Im trying to append an item to a menu that I created. I know its get the primary and secondary menus using "menu_secondary_local_tasks()" etc, and then add items within preprocess page. How would I go about this with a menu that I created? Here is the code I am using to check is the user is logged in... function themeName_check_login() { global $user; if ($user->uid) { print l("Log out, " . $user->name,"logout"); } else { print l("Log In ","user"); } } Thanks in advance, -Matt

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  • ASP.NET MVC Login ReturnUrl always NULL?

    - by aherrick
    Using Forms Authentication in ASP.NET MVC when trying to log back into a site, it puts a ReturnUrl parameter in the query string. My Logon action method accepts a "returnUrl" string. However it seems that returnUrl string is always null, even when it is clearly in the query string. Any thoughts on why this might be the case or a possible fix?

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  • Windows Login Integration

    - by Dusty Roberts
    Hi Peeps. I am building facial recognition software for a certain purpose, however, as a spin-off i would like to use that same software / concept, to automatically recognize me when i sit in front of the PC, and log me in. recognition is handled.. however, i need to incorporate this into windows, the same way fingerprint logins work. where can i go to get some more info on the doing this?

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  • Login Script for PostGreSQL and PHP not working =[

    - by MrEnder
    Ok I'm quite new at logins what not so bare with me here lol but I gota learn so don't discourage me. I tried this so far <?php $error = ""; $conn = pg_connect("host=localhost dbname=brittains_db user=brittains password=XXXX" ); $sql = "SELECT * FROM logins"; $result = pg_query($conn, $sql); if($_SERVER["REQUEST_METHOD"] == "GET") { $userName=""; $password=""; } else if($_SERVER["REQUEST_METHOD"] == "POST") { $userName=trim($_POST["userNameLogin"]); $password=trim($_POST["passwordLogin"]); if(pg_fetch_result($results, $userName, "userName")==true && pg_fetch_result($results, $password, "userName")==true) { setcookie("userIDforDV", $userName, time()+43200); } else { $error = "Your username and or password is incorrect"; } } $userName = $_COOKIE['userIDforDV']; if(isset($userName) && $userName!="") { echo "Welcome " . $userName; } echo $error; ?> <form> <table> <tr> <td class="signupTd"> User Name:&nbsp; </td> <td> <input type="text" name="userNameLogin" value="" size="20" /> </td> </tr> <tr> <td class="signupTd"> Password:&nbsp; </td> <td> <input type="password" name="passwordLogin" value="" size="20" /> </td> </tr> <tr> <td class="signupTd" colspan="2"> <input type="submit" name="submit" value="Submit"/> </td> </tr> </table> </form> that was the idea I came up with... but its prolly a really bad idea and it doesn't work... how might I go about this properly? I need really detailed descriptions please. Thanks a tun Shelby

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  • Making a login Using JavaScript, Will Incorporate PHP Later

    - by TIMOTHY
    not sure why my code wont work, im teaching myself javascript i know php moderatly and i also know the intelligence of using java to hold a password and username, but at the moment i just want the script to work. <html> <head> <title>34webs</title> <link rel="stylesheet" href="css/lightbox.css" type="text/css" media="screen" /> <link rel="stylesheet" type="text/css" media="screen" href="main.css"> <script type="text/javascript" src="js/prototype.js"></script> <script type="text/javascript" src="js/scriptaculous.js?load=effects,builder"></script> <script type="text/javascript" src="js/lightbox.js"></script> <script type="javascript" > function logintry (){ var usern = document.logn.username.value; var passw = document.logn.password.value; if(usern == blue && passw == bluee){ alert('password is correct!'); }else{ alert('password is wrong'); } } </script> </head> <body> <div id="bod"> <div id="nav"> <p id="buttonhead">34 web</p> <a href="#" class="button">HOME</a> <a href="#" class="button">NEWS</a> <a href="#" class="button">DOWNLOADS</a> <a href="#" class="button">ERA</a> <a href="#" class="button">IE BROWSER</a> <a href="#" class="button">DRIVERS</a> <form name="logn"> <table style="margin:0 auto; background:#0174DF; color:white;"> <tr> <td> Username<br> <input type="text" name="username" value=""> </td> </tr> <tr> <td> Password<br> <input type="password" name="password" value=""> </td> </tr> <tr> <td style="text-align:center;"> <input type="button" name="Submit" value="submit" onclick= javascript: logintry()> </td> </tr> </table> </form> </div>

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  • Login problem with php

    - by shinod
    I want to prevent multiple log in with same log in credentials simultaneously. So I made a column login_status and set it to 1 when some one logging in and change to 0 when logging out besides I set session after successful logged in. If user won't click on log out(in case of user close tab or because of some network problem) it doesn't update database and then one can't use that log in credentials again. So I use a ajax call to set current time stamp in database with related log in credentials and it is updated in each 2 minutes if user not navigate from that page. Then if some one attempts to log in with same log in credentials, it will check these time stamp if column login_status is 1, then if the time stamp is older than 3 minutes it allows the log in.Then it solving that problem. But the new problem is if user closes the tab or browser window and after 3 minutes one can log in with same log in credentials from somewhere and if the previous user open that page automatically it will log in as session is already set. How can I prevent this.

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