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  • problem in displaying list using array adapters

    - by Rahul Varma
    Hi, I am trying to display the list of songs using array adapters. But the problem is i couldnt display the list and only empty screen with preset background is showing up. Here's the code...All the thee are seperate classes... Plz help me... public class SongsAdapter extends ArrayAdapter<SongsList>{ private Context context; TextView tvTitle; TextView tvMovie; TextView tvSinger; String s; public SongsAdapter(Context context, int resource, int textViewResourceId, String title) { super(context, resource, textViewResourceId); this.context=context; } public View getView(int position, View convertView, ViewGroup parent) { final int i=position; List<SongsList> listSongs = new ArrayList<SongsList>(); String title = listSongs.get(i).gettitleName().toString(); String album = listSongs.get(i).getmovieName().toString(); String artist = listSongs.get(i).getsingerName().toString(); String imgal = listSongs.get(i).gettitleName().toString(); LayoutInflater inflater = ((Activity) context).getLayoutInflater(); View v = inflater.inflate(R.layout.row, null); tvTitle=(TextView)v.findViewById(R.id.text2); tvMovie=(TextView)v.findViewById(R.id.text3); tvSinger=(TextView)v.findViewById(R.id.text1); tvTitle.setText(title); tvMovie.setText(album); tvSinger.setText(artist); final ImageView im=(ImageView)v.findViewById(R.id.image); s="http://www.gorinka.com/"+imgal; String imgPath=s; AsyncImageLoaderv asyncImageLoaderv=new AsyncImageLoaderv(); Bitmap cachedImage = asyncImageLoaderv.loadDrawable(imgPath, new AsyncImageLoaderv.ImageCallback() { public void imageLoaded(Bitmap imageDrawable, String imageUrl) { im.setImageBitmap(imageDrawable); } }); im.setImageBitmap(cachedImage); return v; } public class imageloader implements Runnable{ private String ss; private ImageView im; public imageloader(String s, ImageView im) { this.ss=s; this.im=im; Thread thread = new Thread(this); thread.start(); } public void run(){ try { HttpGet httpRequest = null; httpRequest = new HttpGet(ss); HttpClient httpclient = new DefaultHttpClient(); HttpResponse response = (HttpResponse) httpclient.execute(httpRequest); HttpEntity entity = response.getEntity(); BufferedHttpEntity bufHttpEntity = new BufferedHttpEntity(entity); InputStream is = bufHttpEntity.getContent(); Bitmap bm = BitmapFactory.decodeStream(is); Log.d("img","img"); is.close(); im.setImageBitmap(bm); } catch (Exception t) { Log.e("bitmap url", "Exception in updateStatus()", t); } } } } public class SongsList { private String titleName; private String movieName; private String singerName; private String imagePath; private String mediaPath; // Constructor for the SongsList class public SongsList(String titleName, String movieName, String singerName,String imagePath,String mediaPath ) { super(); this.titleName = titleName; this.movieName = movieName; this.singerName = singerName; this.imagePath = imagePath; this.mediaPath = mediaPath; } public String gettitleName() { return titleName; } public void settitleName(String titleName) { this.titleName = titleName; } public String getmovieName() { return movieName; } public void setmovieName(String movieName) { this.movieName = movieName; } public String getsingerName() { return singerName; } public void setsingerName(String singerName) { this.singerName = singerName; } public String getimagePath() { return imagePath; } public void setimagePath(String imagePath) { this.imagePath = imagePath; } public String getmediaPath() { return mediaPath; } public void setmediaPath(String mediaPath) { this.mediaPath = mediaPath; } } public class MusicListActivity extends Activity { @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.openadiuofile); ListView list = (ListView)findViewById(R.id.list1); SongsAdapter adapter = new SongsAdapter(this,R.layout.row, R.id.text2, null); list.setAdapter(adapter); } }

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  • 10035 error on a blocking socket

    - by Andrew
    Does anyone have any idea what could cause a 10035 error (EWOULDBLOCK) when reading on a blocking socket with a timeout? This is under Windows XP using the .NET framework version 3.5 socket library. I've never managed to get this myself, but one of my colleagues is getting it all the time. He's sending reasonably large amounts of data to a much slower device and then waiting for a response, which often gives a 10035 error. I'm wondering if there could be issues with TCP buffers filling up, but in that case I would expect the read to wait or timeount. The socket is definitely blocking, not non-blocking.

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  • XML Output is Truncated in SQL

    - by Muhammad Akhtar
    Hi, I need to return my result set in XML and this works fine, but if the number of records are increased, my xml output is truncated here is my query select t.id,t.name,t.address from test FOR XML AUTO, ROOT('Response'), ELEMENTS However I have set some option to increase the output result set like.. Tools --> Options --> Query Results --> SQL Server --> Results to Text --> Maximum number of characters displayed in each column Tools --> Options --> Results --> Maximum characters per column but still I am unable to get my desired result. please suggest my solution Thanks....

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  • extract digg data by digg api

    - by vamsivanka
    I am trying to extract digg data for a user using this url "http://services.digg.com/user/vamsivanka/diggs?count=25&appkey=34asd56asdf789as87df65s4fas6" and the web response is throwing an error "The remote server returned an error: (403) Forbidden." Please let me know. public static XmlTextReader CreateWebRequest(string url) { HttpWebRequest webRequest = (HttpWebRequest)WebRequest.Create(url); webRequest.UserAgent = ".NET Framework digg Test Client"; webRequest.Credentials = System.Net.CredentialCache.DefaultCredentials; webRequest.Accept = "text/xml"; HttpWebResponse webResponse = (HttpWebResponse)webRequest.GetResponse(); System.IO.Stream responseStream = webResponse.GetResponseStream(); XmlTextReader reader = new XmlTextReader(responseStream); return reader; }

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  • Unable to retrieve data from SQLite database iOS6.0

    - by kunalg
    When i run build ios5.0 or less then Sqlite response correct and retrieve data its work fine but when run on ios6.0 i am trying to fetch data from my.sqlite database but it is not executing my if case. It always enters in else condition. What wrong thing i am doing? I am not able to execute my if case i.e. if(sqlite3_prepare_v2(database, sqlQuerry, -1, &querryStatement, NULL)==SQLITE_OK). for reference check this code . NSLog(@"sqlite3_prepare_v2 = %d SQLITE_OK %d ",sqlite3_prepare_v2(sqlite, [strQuery UTF8String], -1, &compiledStatement, nil),SQLITE_OK); if(sqlite3_prepare_v2(sqlite, [strQuery UTF8String], -1, &compiledStatement, nil)==SQLITE_OK) { NSLog(@"sqlite3_step = %d SQLITE_ROW %d ",sqlite3_step(compiledStatement),SQLITE_ROW); while (sqlite3_step(compiledStatement)==SQLITE_ROW) { if(sqlite3_column_text(compiledStatement, 2) != nil) modelObj.Name = [NSString stringWithUTF8String:(char *)sqlite3_column_text(compiledStatement, 2)]; } } else { } ////////// in ios6.0 log Print sqlite3_prepare_v2 = 1 SQLITE_OK 0 sqlite3_step = 21 SQLITE_ROW 100 in iOS5.0 log Print sqlite3_prepare_v2 = 0 SQLITE_OK 0 sqlite3_step = 100 SQLITE_ROW 100

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  • problem in return value from server to client in ajax

    - by user1400
    hello i try to use ajax and zend framework in my application , i could pass variable to server but i can not get data from server , it does not return values, it return all html code page, where is my mistake? $('#myForm').submit(function($e){ $e.preventDefault(); var $paramToServer=$("#myForm").serialize(); $.ajax({ type:'POST', url:'test', data:$paramToServer , success:function(re){ var res = $.evalJSON(re); console.log(res.id); // to see in firebog }, dataType:'json' }); }); public function testAction() { $this->_helper->getHelper('viewRenderer')->setNoRender(); //disable layout Zend_Layout::getMvcInstance()->disableLayout(); $name=$this->getRequest()->getParam ( 'name' ); //pass $name to server $return = array( 'id' => '5', 'family' => 'hello ', ); $return = Zend_Json::encode( $return); // Response $this->getResponse()->setBody($return); }

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  • Parsing JSON file with Python -> google map api

    - by Hannes
    Hi all, I am trying to get started with JSON in Python, but it seems that I misunderstand something in the JSON concept. I followed the google api example, which works fine. But when I change the code to a lower level in the JSON response (as shown below, where I try to get access to the location), I get the following error message for code below: Traceback (most recent call last): File "geoCode.py", line 11, in test = json.dumps([s['location'] for s in jsonResponse['results']], indent=3) KeyError: 'location' How can I get access to lower information level in the JSON file in python? Do I have to go to a higher level and search the result string? That seems very weird to me? Here is the code I have tried to run: import urllib, json URL2 = "http://maps.googleapis.com/maps/api/geocode/json?address=1600+Amphitheatre+Parkway,+Mountain+View,+CA&sensor=false" googleResponse = urllib.urlopen(URL2); jsonResponse = json.loads(googleResponse.read()) test = json.dumps([s['location'] for s in jsonResponse['results']], indent=3) print test Thank you for your responses.

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  • Webservice won't accept JSON requests

    - by V-Man
    Hi, The main issue is that I cannot run a webservice that accepts requests in JSON format. I keep getting a 500 Server error stating that the "request format is invalid." My ASP.NET AJAX extensions are installed. My server is running Plesk Control Panel 8.6 which is undoubtedly causing these problems. The default handler for this specified extension is shown in the web.config like so: For my applications webservice to handle JSON it needs to have this reference: <add name="ScriptHandlerFactory" verb="*" path="*.asmx" preCondition="integratedMode" type="System.Web.Script.Services.ScriptHandlerFactory, System.Web.Extensions, Version=3.5.0.0, Culture=neutral, PublicKeyToken=31BF3856AD364E35"/> Plesk is not allowing the request to be handled properly. I need to know the correct http directive(s) to put into the web.config to properly handle JSON webservices. I tried posting to the Plesk forum two days ago but no response yet. Any insight would be great =)

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  • Run Windows XP on a usb drive virtually on Windows XP?

    - by Russell
    I am sick of not being able to run and install certain applications on my work computer due to admin restrictions (eg: Adobe AIR) . I have heard of smaller versions of Windows running on a usb thumb drive and have looked into it but can't find anything on running windows virtually from a usb drive. I would like to be able to login to this particular computer, insert my usb drive and then open up another version of windows installed on the thumb drive while still being able to use the windows I logged in on (literally be able to alt+tab between the main desktop and the virtual desktop from the usb drive). Is this even possible? For further clarification: The version of windows has to be Windows XP and there is no other option available for what I want to do. Looking forward to a response.

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  • I keep Getting KeyError: 'tried' Whenever I Tried to Run Django Dev Server from Remote Machine

    - by Spikie
    I am running django on python2.6.1, and did start the django web server like this manage.py runserver 192.0.0.1:8000 then tried to connect to the django dev web server on http://192.0.0.1:8000/ keep getting this message on the remote computer Traceback (most recent call last): File "C:\Python26\Lib\site-packages\django\core\servers\basehttp.py", line 279, in run self.result = application(self.environ, self.start_response) File "C:\Python26\Lib\site-packages\django\core\servers\basehttp.py", line 651, in call return self.application(environ, start_response) File "C:\Python26\lib\site-packages\django\core\handlers\wsgi.py", line 241, in call response = self.get_response(request) File "C:\Python26\lib\site-packages\django\core\handlers\base.py", line 115, in get_response return debug.technical_404_response(request, e) File "C:\Python26\Lib\site-packages\django\views\debug.py", line 247, in technical_404_response tried = exception.args[0]['tried'] KeyError: 'tried' what i am doing wrong ? it seen to work ok if i run http://192.0.0.1:8000/ on the computer that runs the Django web server and have that ip 192.0.0.1:8000

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  • Bing search api . colon in xml

    - by nicky
    i am trying to parse bing search xml but whenever i try to access xml element there is colon in every elemet which gives error Parse error: syntax error, unexpected ':' in / here is my php code foreach($searchresponse->web:Web->web:Results as $result) { printf(" \n%s", $result->web:Description); } here is bing xml response <SearchResponse Version="2.2"> - <Query> <SearchTerms>ipl</SearchTerms> </Query> - <web:Web> <web:Total>2430000</web:Total> <web:Offset>0</web:Offset> - <web:Results> - <web:WebResult> <web:Title>Indian Premier League | IPLT20</web:Title> what is the meaning of colon in xml tags.

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  • How to find the mime type of a file in python?

    - by Daren Thomas
    Let's say you want to save a bunch of files somewhere, for instance in BLOBs. Let's say you want to dish these files out via a web page and have the client automatically open the correct application/viewer. Assumption: The browser figures out which application/viewer to use by the mime-type (content-type?) header in the HTTP response. Based on that assumption, in addition to the bytes of the file, you also want to save the MIME type. How would you find the MIME type of a file? I'm currently on a Mac, but this should also work on Windows. Does the browser add this information when posting the file to the web page? Is there a neat python library for finding this information? A WebService or (even better) a downloadable database? Edit: Thank you, Dave Webb.

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  • Visual studio 2008 - Find in files : lists everything twice

    - by Aheho
    In VS2008, I have a web-site project. When I use find in files and search for a string, the find results window will list every occurence twice. What could be causing this? [EDIT] Below is the screen capture from VS. I was searching for the work CommissionBucketProductID within my website project. Notice that each line is returned twice. [EDIT2] In response to your questions. I am only searching within the project, not the whole solution. I currently don't have these files under VSS, although they were in the past.

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  • ASP.net VB Timers

    - by Tom Gullen
    I would like to be able to time a page load time in ASP.net (VBscript). Adding Trace="true" to the page directive is nice, but I need to actually time an event and store it in a variable. In ASP it was easy with the Timer object, but in .net I can't find anything on Google. I need something along the lines of: Dim startTime Dim endTime startTime = now() doBigFunction() endTime = now() response.write("That took " & endTime - startTime & " milliseconds") Cheers!

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  • [PHP] DOMDocument load on a page returning 400 Bad Request status

    - by PeteWilliams
    Hiya, I'm trying to use the Last.fm API for an application I'm creating, but am having some problems with validation. If an API request gives an error it returns a code and message in the response XML like this: <lfm status="failed"> <error code="6">No user with that name</error> </lfm> However, the request also returns an HTTP status of 400 (or in some cases 403) which DOMDocument considers an error and so then refuses to parse the XML. Is there any way round this, so that I can retrieve the error code and message? Thanks Pete

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  • Why does running rake gems:unpack result in a Gem::FilePermissionError

    - by Globalkeith
    I'm attempting to upgrade the friendly_id gem in a rails project. I have removed the old gem from the vendor directory, installed the new gem from rubygems.org. When I type: rake gems:unpack I get the following response: ERROR: While executing gem ... (Gem::FilePermissionError) You don't have write permissions into the /usr/lib/ruby/gems/1.8 directory. Sure, I realise I can sudo it, but what I don't understand is if I would like to unpack the gem into my project vender directory, why does it need access to /usr/lib/ruby/gems....

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  • In Python, urllib2 giving error

    - by pythBegin
    I tried running this, >>> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') But it is giving error like this, can anyone tell me a solution ? Traceback (most recent call last): File "<pyshell#11>", line 1, in <module> urllib2.urlopen('http://tycho.usno.navy.mil/cgi-bin/timer.pl') File "C:\Python26\lib\urllib2.py", line 126, in urlopen return _opener.open(url, data, timeout) File "C:\Python26\lib\urllib2.py", line 391, in open response = self._open(req, data) File "C:\Python26\lib\urllib2.py", line 409, in _open '_open', req) File "C:\Python26\lib\urllib2.py", line 369, in _call_chain result = func(*args) File "C:\Python26\lib\urllib2.py", line 1161, in http_open return self.do_open(httplib.HTTPConnection, req) File "C:\Python26\lib\urllib2.py", line 1136, in do_open raise URLError(err) URLError: <urlopen error [Errno 11001] getaddrinfo failed>

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  • jquery ajax image

    - by Nishima
    Hi all, I am sending an ajax request on dblick for creating the image of the screen where it is double clicked.I am ising imagegrabscreen() function of PHP to create image but instead of creating its image it is creates a black image. dblclick(function (ev,ui) { var response = $.ajax({ type:"POST", url: "grabImage.php", data:"name=John&location=Boston&function_name=img", complete: function(msg){ var resp = msg.responseText; if(msg && msg.readyState != 4) { alert("Ready State :"+msg.readyState); return; } else{ //wb_load(); alert( "Data Saved: " + resp); } } }); } ); GRAB IMAGE FUNCTION function img() { $im = imagegrabscreen(); imagepng($im, "C:\myscreenshot.png"); //echo $im; //imagedestroy($im); return $im; define('imge',$im); }

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  • StackExchange API key

    - by user21289
    I am working on a project with the StackExchange API, the problem is at a moment I have this Exception on eclipse console: java.io.IOException: Server returned HTTP response code: 400 for URL: https://api.stackexchange.com/2.1/questions?order=desc&sort=votes&tagged=OSM&site=stackoverflow at sun.net.www.protocol.http.HttpURLConnection.getInputStream(Unknown Source) at sun.net.www.protocol.https.HttpsURLConnectionImpl.getInputStream(Unknown Source) atbr.inf.pucrio.sog.StackOverflowAcessor.getQuestionsIds(StackOverflowAcessor.java:41) After verifying on the browser with the same link, I have this error message: {"error_id":502,"error_name":"throttle_violation","error_message":"too many requests from this IP, more requests available in 74089 seconds"} I am wondering if this is dur to the limited numbers of the queries per day, if it is the case, how can I do to have the key? if it is not, how can I do to resolve the problem?

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  • POST with HTTPBuilder -> NullPointerException?

    - by Stefan Kendall
    I'm trying to make a simple HTTP POST request, and I have no idea why the following is failing. I tried following the examples here, and I don't see where I'm going wrong. Exception java.lang.NullPointerException at groovyx.net.http.HTTPBuilder$RequestConfigDelegate.setBody(HTTPBuilder.java:1131) ... Code def List<String> search(String query, int maxResults) { def http = new HTTPBuilder("mywebsite") http.request(POST) { uri.path = '/search/' body = [string1: "", query: "test"] requestContentType = URLENC headers.'User-Agent' = 'Mozilla/5.0 Ubuntu/8.10 Firefox/3.0.4' response.success = { resp, InputStreamReader reader -> assert resp.statusLine.statusCode == 200 String data = reader.readLines().join() println data } } [] }

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  • Bypass Forbidden and Server Internal Error with httpwebrequest

    - by Burnzy
    i'm a getting forbidden (403) and Server Internal Error(500) when doing a request to a site even if when trying it with the browser, everything is fine. Here's my code and my appdata tag concerning httpwebrequest HttpWebRequest request = (HttpWebRequest)WebRequest.Create( uri ); request.Method = "HEAD"; request.UserAgent = "Mozilla/4.0 (compatible; MSIE 8.0; Windows NT 6.2; Trident/4.0)"; request.AllowAutoRedirect = true; request.SendChunked = true; request.UnsafeAuthenticatedConnectionSharing = true; request.KeepAlive = false; request.Timeout = 7500; using( HttpWebResponse response = (HttpWebResponse)request.GetResponse() ) { request.Abort(); } app settings: Thank you!

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  • Rails, using jQuery without jrails

    - by ibuck
    Hello all, I have been trying to convert my rails 2.2.2 app over to jQuery, and would like so without using jrails. The only reference material I can find on the subject is Railscasts Episode 136. Ryan goes over how to use jQuery to post a form and handle the response in a .js.erb file. My questions is has anyone tried to use jQuery with .js.erb files with anchors as the trigger? As a replacement for "link_to_remote". I have gotten jQuery to do a .get to submit this link on click to the controller, but I cannot seem to get it to go into the .js.erb file. Thanks

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  • How return 304 status with FileResult in ASP.NET MVC RC1

    - by Maysam
    As you may know we have got a new ActionResult called FileResult in RC1 version of ASP.NET MVC. Using that, your action methods can return image to browser dynamically. Something like this: public ActionResult DisplayPhoto(int id) { Photo photo = GetPhotoFromDatabase(id); return File(photo.Content, photo.ContentType); } In the HTML code, we can use something like this: <img src="http://mysite.com/controller/DisplayPhoto/657"> Since the image is returned dynamically, we need a way to cache the returned stream so that we don't need to read the image again from database. I guess we can do it with something like this, I'm not sure: Response.StatusCode = 304; This tells the browser that you already have the image in your cache. I just don't know what to return in my action method after setting StatusCode to 304. Should I return null or something?

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  • ASP.NET SetAuthCookie weird behaviour

    - by rlb.usa
    Hello SO, I'm trying to do user impersonation for a web application we have. The user selects the user they'd like to emulate/impersonate and then clicks the button which fires this: protected void uxImpersonate_Click(object sender, EventArgs e) { ... FormsAuthentication.SetAuthCookie(uxUserToEmulate.SelectedValue, false); Response.Redirect("Impersonation.aspx"); //reload page manually } We have a dev - test - production server environment and on two servers this works just fine, but on another one, in all browsers, it kicks me to the login screen. What's going on and how can I fix it? We're on ASP.NET 2.0

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  • Routing classic asp and through an MVC application

    - by Matthias
    We are starting to convert a large classic asp application into MVC (using C#). An additional requirement is, that all classic routes get "translated" to MVC ones ('mydomain.com/productdetail.asp?id=13' should become 'mydomain.com/products/13') even before we start writing the first controller or view. So basically, we want to use the routing from MVC but have the classic asp handle the response. An these are my questions: How to use the new nice urls but have the classic asp handle the construction of the html result? Within the classic asp page, the new MVC url pattern should be used for links. What is the best way of translating the old urls to the new ones and make the accessible within the classic asp site (using COM I guess). When an old/classic url is requested, how would I correctly handle that request so that browsers/searchengines would understand that the page has moved to the new url? Thanks in advance!

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