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  • Netbeans code templates' modifiers

    - by hsz
    Hello ! I set a new PHP code template in Netbeans: /* @var $$${name}Table Model_${name}_Table */ $$${name}Table = Container::get('model')->get('${name}_Table'); and if I use as ${name} some value - shop - I have in output: /* @var $shopTable Model_shop_Table */ $shopTable = Container::get('model')->get('shop_Table'); Is it possible to add some modifier to the second and fourth ${name} so I will have it started with upper letter ? Shop_Table instead of shop_Table

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  • How do you override ProgramFilesFolder in an msi?

    - by Mark
    I have an msi file that I am trying to install in a place other than C:\Program Files. The directory table shows that ProgramFilesFolder is used as the default install directory. From reading this blog post I understand that ProgramFilesFolder is a standard directory so passing TARGETDIR as a property to the installer will not change the install location even through the directory table has it as the parent of ProgramFilesFolder. How can I override the install location? I am a total novice in this area.

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  • Select statement that combines similar rows with certain ids?

    - by vegatron
    hi I have a warehouse_products table which defines how many products in the warehouses so lets say I have 20 records/rows in the table, some rows may contain the same product id but in a different warehouse I need to create select statement that give every product one row, and in this row I must have the quantity in warehouse A and warehouse B .. so in the end I will get for example 10 rows that contain all the data

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  • How do I write a Oracle SQl query for this tricky question...

    - by atrueguy
    Here is the table data with the column name as Ships. +--------------+ Ships | +--------------+ Duke of north | ---------------+ Prince of Wales| ---------------+ Baltic | ---------------+ In the Outcomes table, transform names of the ships containing more than one space, as follows: Replace all characters between the first and the last spaces (excluding these spaces) by symbols of an asterisk (*). The number of asterisks must be equal to number

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  • MySQL: count enumerated values?

    - by John Isaacks
    If my table looks like this: daily_individual_tracking', 'CREATE TABLE `daily_individual_tracking` ( `daily_individual_tracking_id` int(10) unsigned NOT NULL auto_increment, `daily_individual_tracking_date` date NOT NULL default ''0000-00-00'', `sales` enum(''no'',''yes'') NOT NULL COMMENT ''no'', `repairs` enum(''no'',''yes'') NOT NULL COMMENT ''no'', `shipping` enum(''no'',''yes'') NOT NULL COMMENT ''no'', PRIMARY KEY (`daily_individual_tracking_id`) ) ENGINE=InnoDB AUTO_INCREMENT=4 DEFAULT CHARSET=latin1 basically the fields can be either yes or no. How can I count how many yes's their are for each column over a date range? Thanks!!

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  • Export value from Excel worksheet to Access record

    - by glinch
    Hi there, I have an excel spreadsheet that contains the primarky-key/id value for a record in a table in an access database. I would like to export specific data from certain cells in the spreadsheet to certain fields in the corresponding record in the table. Is this possible, any help would be greatly appreciated. Many thanks Noel

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  • MySQL More Tables or More Rows

    - by Pez Cuckow
    I am working on a game that I am going to open to the public to have on their game. The game stores lots of information (about 300 rows) per website and spends a lot of time updating values within this MySQL database. Is it better (faster/efficient) to add a new table for every website or to just have 1000's of rows in one table and add a column "website_id" or similar?

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  • I want to display the missing (non-matching) records

    - by Eric
    Is there a way to program the following SQL query SELECT dbo.Assets_Master.Serial_Number, dbo.Assets_Master.Account_Ident, dbo.Assets_Master.Disposition_Ident FROM dbo.Assets_Master LEFT OUTER JOIN dbo.Assets ON dbo.Assets_Master.Serial_Number = dbo.Assets.Serial_Number WHERE (dbo.Assets.Serial_Number IS NULL) in c# .net code using dataviews or data relation or something else? I have a spreadsheet of about 4k rows and a data table that should have the same records but if not I want to display the missing (non-matching) records from the table. Thanks, Eric

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  • ActiveRecord finding from inside a serialized field

    - by JP
    While working with ActiveRecord I have a table which stores a serialized array of participant usernames for each row. Is there an easy way to search for all rows who contain a specific user? I realise I could just make a new linked table for the participants, but I feel like that would increase my overhead unnecessarily -- what do you think?

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  • jquery function call with parameters

    - by Kaushik Gopal
    Hi a newb question: I have a table with a bunch of buttons like so: <tr class="hr-table-cell" > <td>REcord 1</td> <td> <INPUT type="button" value="Approve" onclick="" /> <INPUT type="button" value="Reject" onclick="" /> <INPUT type="button" value="Delete" onclick="fnDeletePpAppl(222445,704);" /> </td> </tr> <tr class="hr-table-cell" > <td>REcord 1</td> <td align="center" class="hr-table-bottom-blue-border" valign="middle"> <INPUT type="button" value="Approve" onclick="" /> <INPUT type="button" value="Reject" onclick="" /> <INPUT type="button" value="Delete" onclick="fnDeletePpAppl(237760,776);" /> </td> </tr> I have my jquery like so: <script type="text/javascript"> // JQUERY stuff $(document).ready(function(){ function fnDeletePpAppl(empno, applno) { alert('Entering here'); $("form").get(0).empno.value = empno; $("form").get(0).applNo.value = applno; $("form").get(0).listPageAction.value = "delete"; $("form").get(0).action.value = "pprelreqlist.do"; $("form").get(0).submit(); } }); This doesn't seem to work.I thought this means, the function is ready only after the dom is ready. After the dom is ready and i click the button, why is not recognizing the function declaration within the .ready() function? However if i use the function directly: <script type="text/javascript"> function fnDeletePpAppl(empno, applno) { alert('Entering here'); $("form").get(0).empno.value = empno; $("form").get(0).applNo.value = applno; $("form").get(0).listPageAction.value = "delete"; $("form").get(0).action.value = "pprelreqlist.do"; $("form").get(0).submit(); } This works. I want to get my fundamentals straight here... If i do the declaration without the .ready() , does that mean i'm using plain vanilla jscript? If i were to do this with the document.ready - the usual jquery declaration way, what would i have to change to make it work? I understand there are much better ways to do this like binding with buttons etc, but I want to know why this particular way doesn't seem to be working. Thanks. Cheers. K

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  • Free tool to watch database for changes?

    - by 01
    Im looking for a tool that can watch database(mysql and oracle) for changes. When someone inserts or updates something in any table i want to get to know about it. I know that it can be done using triggers(http://stackoverflow.com/questions/167254/watching-a-table-for-change-in-mysql), but im more interested in some tool that can do it. free tool.

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  • How to define variable for Trac TicketQuery?

    - by JOM
    Using TRAC TicketQuery template for sprint to show what's going on. How would I type name of current sprint only ONCE, when template needs it in multiple location? For example "Sprint1" is needed is 6 places: = New items = [[TicketQuery(milestone=Sprint1,status=new,format=table,order=priority,col=id|summary|priority|component|owner|type)]] = Items in progress = [[TicketQuery(milestone=Sprint1,status=in_progress,format=table,order=priority,col=id|summary|priority|component|owner|type)]]

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  • The explain tells that the query is awful (it doesn't use a single key) but I'm using LIMIT 1. Is th

    - by Ricardo
    The explain command with the query: explain SELECT * FROM leituras WHERE categorias_id=75 AND textos_id=190304 AND cookie='3f203349ce5ad3c67770ebc882927646' AND endereco_ip='127.0.0.1' LIMIT 1 The result: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE leituras ALL (null) (null) (null) (null) 1022597 Using where Will it make any difference adding some keys on the table? Even that the query will always return only one row.

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  • hibernate annotation- extending base class - values are not being set - strange error

    - by gt_ebuddy
    I was following Hibernate: Use a Base Class to Map Common Fields and openjpa inheritance tutorial to put common columns like ID, lastModifiedDate etc in base table. My annotated mappings are as follow : BaseTable : @MappedSuperclass public abstract class BaseTable { @Id @GeneratedValue @Column(name = "id") private int id; @Column(name = "lastmodifieddate") private Date lastModifiedDate; ... Person table - @Entity @Table(name = "Person ") public class Person extends BaseTable implements Serializable{ ... Create statement generated : create table Person (id integer not null auto_increment, lastmodifieddate datetime, name varchar(255), primary key (id)) ; After I save a Person object to db, Person p = new Person(); p.setName("Test"); p.setLastModifiedDate(new Date()); .. getSession().save(p); I am setting the date field but, it is saving the record with generated ID and LastModifiedDate = null, and Name="Test". Insert Statement : insert into Person (lastmodifieddate, name) values (?, ?) binding parameter [1] as [TIMESTAMP] - <null> binding parameter [2] as [VARCHAR] - Test Read by ID query : When I do hibernate query (get By ID) as below, It reads person by given ID. Criteria c = getSession().createCriteria(Person.class); c.add(Restrictions.eq("id", id)); Person person= c.list().get(0); //person has generated ID, LastModifiedDate is null select query select person0_.id as id8_, person0_.lastmodifieddate as lastmodi8_, person0_.name as person8_ from Person person0_ - Found [1] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test] as column [person8_] ReadAll query : //read all Query query = getSession().createQuery("from " + Person.class.getName()); List allPersons=query.list(); Corresponding SQL for read all select query select person0_.id as id8_, person0_.lastmodifieddate as lastmodi8_, person0_.name as person8_ from Person person0_ - Found [1] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test] as column [person8_] - Found [2] as column [id8_] - Found [null] as column [lastmodi8_] - Found [Test2] as column [person8_] But when I print out the list in console, its being more weird. it is selecting List of Person object with ID fields = all 0 (why all 0 ?) LastModifiedDate = null Name fields have valid values I don't know whats wrong here. Could you please look at it? FYI, My Hibernate-core version : 4.1.2, MySQL Connector version : 5.1.9 . In summary, There are two issues here Why I am getting All ID Fields =0 when using read all? Why the LastModifiedDate is not being inserted?

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  • How to make an add friend/defriend function in PHP?

    - by user300371
    I have created a site where people can create a profile. But I am trying to figure out how to start on making an add friend button so users can have friends. In my user table, i have user_id, first_name, last_name, email, etc. Should I somehow relate the user_id of the user and the friend in a friend table? I am a novice to programming, so these things are still new to me. Thanks!

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  • MySQL doesn't use index in join query

    - by Kocsonya Laci
    I have two tables: comments(id(primary key), author, ip(index)) and visitors(id(primary key), date_time, ip(index)) I want to join them like that: SELECT visitors.date_time FROM comments LEFT JOIN visitors ON ( comments.ip = visitors.ip ) WHERE comments.author = 'author' LIMIT 10 It works, but very slow.. In EXPLAIN it shows that it doesn't use the index on the visitors table: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE comments ref author author 78 const 9660 Using where 1 SIMPLE visitors ALL NULL NULL NULL NULL 8033 Any ideas? Thanks!

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  • mysql update unique index

    - by atno
    Is there a way to say UPDATE items SET qty=10 WHERE **unique key** instead of saying UPDATE items SET qty=10 WHERE userID=1 AND listID=10 and itemID=100 on the following table? CREATE TABLE IF NOT EXISTS `items` ( `userID` int(20) NOT NULL, `listID` int(20) NOT NULL, `itemID` int(20) NOT NULL, `qty` int(10) NOT NULL, UNIQUE KEY `unique` (`userID`,`listID`,`itemID`) ) ENGINE=MyISAM DEFAULT CHARSET=utf8 COLLATE=utf8_unicode_ci;

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  • Hibernate one to one with multiple columns

    - by Erdem Emekligil
    How can i bind two columns, using @OneToOne annotation? Lets say I've 2 tables A and B. Table A: id1 (primary key) id2 (pk) other columns Table B: id1 (pk) id2 (pk) other columns In class A i want to write something like this: @OneToOne(fetch = FetchType.EAGER, targetEntity = B.class) @JoinColumn(name = "id1 and id2", referencedColumnName = "id1 and id2") private B b; Is it possible to do this using annotations? Thanks.

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  • Deleting rows from different tables

    - by Ross
    Here is what i'm trying to do: Delete the project from projects table and all the images associated with that project in the images table Lets say $del_id = 10 DELETE FROM projects, images WHERE projects.p_id = '$del_id' AND images.p_id = '$del_id' What is wrong with this query

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  • How to write this query in Linq2Sql

    - by RememberME
    I have a table company which holds the company_id, company_name and other details. I have a table subcontracts which has a company_id column that maps to company.company_id. How can I write a select statement to get all companies which have not been assigned to a subcontract? IE The company_id cannot be found in subcontracts.company_id

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  • How to get the exact string within the brackets in mysql

    - by sreenath
    In my mysql table a field values are as follows: table name - "clients" field name - "accent" values are - "Eastern(Northern,Southern),Scottish(East Coast)" "Eastern(South,North,Southern),Scottish(East Coast)" If I give select accent from clients where accent like '%north%' if more than 100 records not in the same order. Strings with in the brackets are not in the same order means. It will give above two values. How should i get only second value? Please help me, thanks.

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