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• TortoiseSVN Error: "OPTIONS of 'https://...' could not connect to server (...)"

  - by Zack Peterson

  I'm trying to setup a new computer to synchronize with my SVN repository that's hosted with cvsdude.com. I get this error: Here's what I did (these have worked in the past): Downloaded and installed TortoiseSVN Created a new folder C:\aspwebsite Right-clicked, chose SVN Checkout... Entered the following information, clicked OK: URL of repository: https://<reponame>-svn.cvsdude.com/aspwebsite Checkout directory: C:\aspwebsite Checkout depth: Fully recursive Omit externals: Unchecked Revision: HEAD revision Got TortoiseSVN error: OPTIONS of 'https://<reponame>-svn.cvsdude.com/aspwebsite': could not connect to server (https://<reponame>-svn.cvsdude.com) Rather than getting the error, TortoiseSVN should have asked for my username and password and then downloaded about 90MB. Why can't I checkout from my Subversion repository? Kent Fredric wrote: Either their security certificate has expired, or their hosting is broken/down. Contact CVSDude and ask them whats up. It could also be a timeout, because for me their site is exhaustively slow.. It errors after only a couple seconds. I don't think it's a timeout. Matt wrote: Try visiting https://[redacted]-svn.cvsdude.com/aspwebsite and see what happens. If you can visit it in your browser, you ought to be able to get the files in your SVN client and we can work from there. If it fails, then there's your answer. I can access the site in a web browser.

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• Cant fetch production db results using Google app engine remote_api

  - by Alon

  Hey, im trying to work out with /remote_api with a django-patch app engine app i got running. i want to select a few rows from my online production app locally. i cant seem to manage todo so, everything authenticates fine, it doesnt breaks on imports, but when i try to fetch something it just doesnt print anything. Placed the test python inside my local app dir. #!/usr/bin/env python # import os import sys # Hardwire in appengine modules to PYTHONPATH # or use wrapper to do it more elegantly appengine_dirs = ['myworkingpath'] sys.path.extend(appengine_dirs) # Add your models to path my_root_dir = os.path.abspath(os.path.dirname(__file__)) sys.path.insert(0, my_root_dir) from google.appengine.ext import db from google.appengine.ext.remote_api import remote_api_stub import getpass APP_NAME = 'Myappname' os.environ['AUTH_DOMAIN'] = 'gmail.com' os.environ['USER_EMAIL'] = '[email protected]' def auth_func(): return (raw_input('Username:'), getpass.getpass('Password:')) # Use local dev server by passing in as parameter: # servername='localhost:8080' # Otherwise, remote_api assumes you are targeting APP_NAME.appspot.com remote_api_stub.ConfigureRemoteDatastore(APP_NAME, '/remote_api', auth_func) # Do stuff like your code was running on App Engine from channel.models import Channel, Channel2Operator myresults = mymodel.all().fetch(10) for result in myresults: print result.key() it doesnt give any error or print anything. so does the remote_api console example google got. when i print the myresults i get [].

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• Join with Three Tables

  - by John

  Hello, In MySQL, I am using the following three tables (their fields are listed after their titles): comment: commentid loginid submissionid comment datecommented login: loginid username password email actcode disabled activated created points submission: submissionid loginid title url displayurl datesubmitted I would like to display "datecommented" and "comment" for a given "username," where "username" equals a variable called $profile. I would also like to make the "comment" a hyperlink to http://www...com/.../comments/index.php?submission='.$rowc["title"].'&submissionid='.$rowc["submissionid"].'&url='.$rowc["url"].'&countcomments='.$rowc["countComments"].'&submittor='.$rowc["username"].'&submissiondate='.$rowc["datesubmitted"].'&dispurl='.$rowc["displayurl"].' where countComments equals COUNT(c.commentid) and $rowc is part of the query listed below. I tried using the code below to do what I want, but it didn't work. How could I change it to make it do what I want? Thanks in advance, John $sqlStrc = "SELECT s.loginid ,s.title ,s.url ,s.displayurl ,s.datesubmitted ,l.username ,l.loginid ,s.title ,s.submissionid ,c.comment ,c.datecommented ,COUNT(c.commentid) countComments FROM submission s INNER JOIN login l ON s.loginid = l.loginid LEFT OUTER JOIN comment c ON c.loginid = l.loginid WHERE l.username = '$profile' GROUP BY c.loginid ORDER BY s.datecommented DESC LIMIT 10"; $resultc = mysql_query($sqlStrc); $arrc = array(); echo "<table class=\"samplesrec1c\">"; while ($rowc = mysql_fetch_array($resultc)) { $dtc = new DateTime($rowc["datecommented"], $tzFromc); $dtc->setTimezone($tzToc); echo '<tr>'; echo '<td class="sitename3c">'.$dtc->format('F j, Y &\nb\sp &\nb\sp g:i a').'</a></td>'; echo '<td class="sitename1c"><a href="http://www...com/.../comments/index.php?submission='.$rowc["title"].'&submissionid='.$rowc["submissionid"].'&url='.$rowc["url"].'&countcomments='.$rowc["countComments"].'&submittor='.$rowc["username"].'&submissiondate='.$rowc["datesubmitted"].'&dispurl='.$rowc["displayurl"].'">'.stripslashes($rowc["comment"]).'</a></td>'; echo '</tr>'; } echo "</table>";

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• Having a problem inserting into database

  - by neo skosana

  I have a stored procedure: CREATE PROCEDURE busi_reg(IN instruc VARCHAR(10), IN tble VARCHAR(20), IN busName VARCHAR(50), IN busCateg VARCHAR(100), IN busType VARCHAR(50), IN phne VARCHAR(20), IN addrs VARCHAR(200), IN cty VARCHAR(50), IN prvnce VARCHAR(50), IN pstCde VARCHAR(10), IN nm VARCHAR(20), IN surname VARCHAR(20), IN eml VARCHAR(50), IN pswd VARCHAR(20), IN srce VARCHAR(50), IN refr VARCHAR(50), IN sess VARCHAR(50)) BEGIN INSERT INTO b_register SET business_name = busName, business_category = busCateg, business_type = busType, phone = phne, address = addrs, city = cty, province = prvnce, postal_code = pstCde, firstname = nm, lastname = surname, email = eml, password = pswd, source = srce, ref_no = refr; END; This is my php script: $busName = $_POST['bus_name']; $busCateg = $_POST['bus_cat']; $busType = $_POST['bus_type']; $phne = $_POST['phone']; $addrs = $_POST['address']; $cty = $_POST['city']; $prvnce = $_POST['province']; $pstCde = $_POST['postCode']; $nm = $_POST['name']; $surname = $_POST['lname']; $eml = $_POST['email']; $srce = $_POST['source']; $ref = $_POST['ref_no']; $result2 = $db->query("CALL busi_reg('$instruc', '$tble', '$busName', '$busCateg', '$busType', '$phne', '$addrs', '$cty', '$prvnce', '$pstCde', '$nm', '$surname', '$eml', '$pswd', '$srce', '$refr', '')"); if($result) { echo "Data has been saved"; } else { printf("Error: %s\n",$db->error); } Now the error that I get: Commands out of sync; you can't run this command now

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• after assembling jar - No Persistence provider for EntityManager named ....

  - by alabalaa

  im developing a standalone application and it works fine when starting it from my ide(intellij idea), but after creating an uberjar and start the application from it javax.persistence.spi.PersistenceProvider is thrown saying "No Persistence provider for EntityManager named testPU" here is my persistence.xml which is placed under meta-inf directory: <persistence-unit name="testPU" transaction-type="RESOURCE_LOCAL"> <provider>org.hibernate.ejb.HibernatePersistence</provider> <class>test.model.Configuration</class> <properties> <property name="hibernate.connection.username" value="root"/> <property name="hibernate.connection.driver_class" value="com.mysql.jdbc.Driver"/> <property name="hibernate.connection.password" value="root"/> <property name="hibernate.connection.url" value="jdbc:mysql://localhost:3306/test"/> <property name="hibernate.show_sql" value="true"/> <property name="hibernate.dialect" value="org.hibernate.dialect.MySQLInnoDBDialect"/> <property name="hibernate.c3p0.timeout" value="300"/> <property name="hibernate.hbm2ddl.auto" value="update"/> </properties> </persistence-unit> and here is how im creating the entity manager factory: emf = Persistence.createEntityManagerFactory("testPU"); im using maven and tried the assembly plug-in with the default configuration fot it, i dont have much experience with assembling jars and i dont know if im missing something, so if u have any ideas ill be glad to hear them

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• rails 3 actionmailer cannot send email

  - by lkahtz

  I am following Ryan Bates's tutorial on Rails 3 ActionMailer. I generate the mailer in terminal and then establish a setup_mail.rb under config/initializers. I keyed in the following code: ActionMailer::Base.smtp_settings={ :address => "smtp.gmail.com", :port => 587, :domail => "gmail.com", :user_name => "my_account_at_gmail", :password => "my_password", :authentication => "plain" , :enable_starttls_auto => true } My user_mailer.rb file goes like: class UserMailer < ActionMailer::Base default :from => "[email protected]" def registration_confirmation(user) mail(:to => user.email,:subject => "registered") end end I tested in rails console: u=User.first UserMailer.registration_confirmation(u).deliver it displays: #<Mail::Message:2194479560, Multipart: false, Headers: <Date: Sat, 26 Feb 2011 14:42:06 +0800>, <From: [email protected]>, <To: [email protected]>, <Message-ID: <[email protected]>>, <Subject: registered>, <Mime-Version: 1.0>, <Content-Type: text/plain>, <Content-Transfer-Encoding: 7bit>> BUT I never received the email here... Why? How can I solve this? I guess it is some problem on send_mail.rb file..

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• javax.xml.bind.MarshalException

  - by sandeep

  Hi, I am getting javax.xml.bind.MarshalException error. I am sending List from my webservice to the backingbean and I have this error. Here is my code: Backing bean @WebServiceRef(wsdlLocation = "http://localhost:26565/Login_webserviceService/Login_webservice?WSDL") public String login() { System.out.println("Login Phase entered"); int result = 0; List list; List finalList = null; try { Weblogin.LoginWebserviceService service = new Weblogin.LoginWebserviceService(); Weblogin.LoginWebservice port = service.getLoginWebservicePort(); result = port.login(voterID, password); Weblogin.LoginWebservice port1 = service.getLoginWebservicePort(); list = port1.candDetails(1); finalList = list; this.setList(finalList); } catch (Exception e) { e.printStackTrace(); } if (result == 1) return "polling"; else return "login"; } Webservice public List candDetails(int pollEvent) { List resultList = null; List finalList = null; try { if (pollEvent == 1) { resultList = em.createNamedQuery("Cantable.findAll").getResultList(); finalList = resultList; } } catch (Exception e) { e.printStackTrace(); } return resultList; }

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• Basic user authentication with records in AngularFire

  - by ajkochanowicz

  Having spent literally days trying the different, various recommended ways to do this, I've landed on what I think is the most simple and promising. Also thanks to the kind gents from this SO question: Get the index ID of an item in Firebase AngularFire Curent setup Users can log in with email and social networks, so when they create a record, it saves the userId as a sort of foreign key. Good so far. But I want to create a rule so twitter2934392 cannot read facebook63203497's records. Off to the security panel Match the IDs on the backend Unfortunately, the docs are inconsistent with the method from is firebase user id unique per provider (facebook, twitter, password) which suggest appending the social network to the ID. The docs expect you to create a different rule for each of the login method's ids. Why anyone using 1 login method would want to do that is beyond me. (From: https://www.firebase.com/docs/security/rule-expressions/auth.html) So I'll try to match the concatenated auth.provider with auth.id to the record in userId for the respective registry item. According to the API, this should be as easy as In my case using $registry instead of $user of course. { "rules": { ".read": true, ".write": true, "registry": { "$registry": { ".read": "$registry == auth.id" } } } } But that won't work, because (see the first image above), AngularFire sets each record under an index value. In the image above, it's 0. Here's where things get complicated. Also, I can't test anything in the simulator, as I cannot edit {some: 'json'} To even authenticate. The input box rejects any input. My best guess is the following. { "rules": { ".write": true, "registry": { "$registry": { ".read": "data.child('userId').val() == (auth.provider + auth.id)" } } } } Which both throws authentication errors and simultaneously grants full read access to all users. I'm losing my mind. What am I supposed to do here?

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• Issue selenium code maintenance

  - by Rajasankar

  I want to group the common methods in one file and use it. For example, login to a page using selenium may be used in multiple times. Define that in class A and call it in class B. However, it throws null pointer exception. class A has public void test_Login() throws Exception { try{ selenium.setTimeout("60000"); selenium.open("http://localhost"); selenium.windowFocus(); selenium.windowMaximize(); selenium.windowFocus(); selenium.type("userName", "admin"); selenium.type("password", "admin"); Result=selenium.isElementPresent("//input[@type='image']"); selenium.click("//input[@type='image']"); selenium.waitForPageToLoad(Timeout); } catch(Exception ex) { System.out.println(ex); ex.printStackTrace(); } } with all other java syntax in class B public void test_kk() throws Exception { try { a.test_Login(); } catch(Exception ex) { System.out.println(ex); ex.printStackTrace(); } } with all syntax. When I execute class B, I got this error, java.lang.NullPointerException at A.test_Login(A.java:32) at B.test_kk(savefile.java:58) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(Unknown Source) at sun.reflect.DelegatingMethodAccessorImpl.invoke(Unknown Source) at java.lang.reflect.Method.invoke(Unknown Source) at junit.framework.TestCase.runTest(TestCase.java:168) at junit.framework.TestCase.runBare(TestCase.java:134) at com.thoughtworks.selenium.SeleneseTestCase.runBare(SeleneseTestCase.j ava:212) at junit.framework.TestResult$1.protect(TestResult.java:110) at junit.framework.TestResult.runProtected(TestResult.java:128) at junit.framework.TestResult.run(TestResult.java:113) at junit.framework.TestCase.run(TestCase.java:124) at junit.framework.TestSuite.runTest(TestSuite.java:232) at junit.framework.TestSuite.run(TestSuite.java:227) at junit.textui.TestRunner.doRun(TestRunner.java:116) at junit.textui.TestRunner.doRun(TestRunner.java:109) at junit.textui.TestRunner.run(TestRunner.java:77) at B.main(B.java:77) I hope someone must have tried this before. I may miss something here.

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• joomla! migration

  - by tim

  I have a Joomla! installation on a remote site and I want to run it locally. I'm running Joomla! locally on a Mac through a standard MAMP installation: Joomla 1.5.12 PHP 5.2.6 MySQL 5.0.41 Apache 2.0.59 OS X 10.5.8 I've added a configuration file to the local Joomla! directory with all the correct local settings, database name, database user-name, database password etc. etc. I've tried a lot of different settings. I've also recreated the remote database locally, ensuring everything copied correctly. I followed a few different sets of instructions with roughly the same steps on how to do the migration. All of the above has not worked for me; at best I get bits of text from the site rendered in the browser. Other times I get SQL errors. What I want is for an already set up remote Joomla! installation to run on my own local machine. Does anyone have any advice as to how to get this working, it'd be very much appreciated? Thanks.

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• Port Java Application to Android

  - by mihirk

  I am not so sure about the question or what I should call what I am trying to achieve. I use a dialer called super sify. Here is the download - http://thegoan.com/supersify/supersify.zip The when extracted it has two files for linux, one is a .jar file which consists of some classes. The application was written in java. The other is a .sh file, which is a shell executable and takes some parameters like username and password and machine id and stuff. I want to port this app to android. What exactly would I have to do. Some more information is the .jar file is named supersify.jar and the .sh file is named ss.sh so here is the code for ss.sh java -jar supersify.jar $* if [ $? -eq 1 ] then read fi Please help me out. This is an open source software.So I am not doing any illegal modifications. I need to port this app to android, so would I have to write the whole thing again or just something else. I know some basic hello world android app development, and I have made an app to add two numbers, I am still on my way to become an android app developer, but I need this app and will learn a lot to make this possible unless it involves rewriting all the java classes. Thank you in advance If you have anymore question I will be glad to answer to them :D.

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• JDBC going to the wrong address

  - by DCSoft

  When I try and connect it my mysql database with JDBC in java, it doesn't go to my web server. Here is the code String dbtime; String dbUrl = "jdbc:mysql://184.172.176.18:3306/dcsoft_dcsoft_balloon"; String dbUser = "myuser"; String dcPass = "mypass"; String dbClass = "com.mysql.jdbc.Driver"; String query = "Select * FROM users"; try { Class.forName("com.mysql.jdbc.Driver"); Connection con = DriverManager.getConnection(dbUrl, dbUser, dcPass); Statement stmt = con.createStatement(); ResultSet rs = stmt.executeQuery(query); while (rs.next()) { dbtime = rs.getString(1); System.out.println(dbtime); } //end while con.close(); } //end try catch(ClassNotFoundException e) { e.printStackTrace(); } catch(SQLException e) { e.printStackTrace(); } This code is supposed to go to my web server but it gives this error java.sql.SQLException: Access denied for user 'dcsoft_dcsoft_java'@'jamesposse.force9.co.uk' (using password: YES) jamesposse.force9.co.uk is the not the address im trying to connect to I'm trying to connect to 184.172.176.18:3306. Thanks.

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• Drupal 7 configuration error with Postgresql in Mac OS 10.6.5

  - by Sam

  I am trying to configure Drupal 7 with Postgres. At the database setup step, I get the following error. Warning: PDO::_construct(): [2002] No such file or directory (trying to connect via unix:///var/mysql/mysql.sock) in DatabaseConnection-_construct() (line 300 of /Users/shamod/Sites/drupal/7/includes/database/database.inc). In order for Drupal to work, and to continue with the installation process, you must resolve all issues reported below. For more help with configuring your database server, see the installation handbook. If you are unsure what any of this means you should probably contact your hosting provider. Failed to connect to your database server. The server reports the following message: SQLSTATE[HY000] [2002] No such file or directory. Is the database server running? Does the database exist, and have you entered the correct database name? Have you entered the correct username and password? Have you entered the correct database hostname? NOTE: I am trying to connect to Postgresql but it fails on var/mysql/mysql.sock error. I have setup the database connection string in settings.php for Postgresql. It still does not work. Any idea?

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• Where to store: User connection information?

  - by TomTom

  ;) I am writing a .NET application wher ethe user connects to a given server. ALl information within the application is stored in the server. But I want / need to store the following information for the user: The server he connected to last The username he used to connect last (and no, no password, never ever). Any idea where to store this best? the application config file is not sensible (user != admin, application.config is write protected for him). So, my options are: In the registry. 2 keys under my own subkey. In a sort of ini file, stored in the user's data directory (AppData). This would possibly also allow later expansion (into like saving more information, some of which may not fit into the registry). Anyone a tip? Other alternatives? I tend so far to go for the AppData directory with my own subfolder - simply because it is a nice preparation for later to keep like a local copy of configuration etc.

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• using asp.net membership provider in a dll

  - by Keith Barrows

  I've used Membership Providers in web apps over the last several years. I now have a new "request" for an internal project at work. They would like a service (not a web service) to do a quick authenticate against. Basically, exposing the ValidateUser(UserName, Password) method... I am building this in a DLL that will sit with our internal web site. What is the best approach to make this work? The DLL will not reference the web app and the web app will reference the DLL. How do I make the DLL aware of the Membership Provider? TIA PS: If this has been answered elsewhere please direct me to that... EDIT: I found an article on using ASP.NET Membership with WinForms and/or WPF applications. Unfortunately, these depend on an app.config file. A DLL appears to not use the app.config once published. If I am wrong, please set me straight! The article is here: http://aspalliance.com/1595_Client_Application_Services__Part_1.all

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• how to connect to MSSQL using activerecord, JDBC, JTDS and Integrated Security

  - by Rob

  As per the above, I've tried: establish_connection(:adapter => "jdbcmssql", :url => "jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain='mynetwork';", :username => 'user', :password=>'pass' ) establish_connection(:adapter => "jdbcmssql", :url => 'jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain="mynetwork";user="mynetwork\user"' ) establish_connection(:adapter => "jdbcmssql", :url => "jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain='mynetwork';", :username=>'user' ) establish_connection(:adapter => "jdbcmssql", :url => "jdbc:jtds:sqlserver://myserver:1433/mydatabase;domain='mynetwork';integratedSecurity='true'", :username=>'user' ) .. and various other combinations. Each time I get: net/sourceforge/jtds/jdbc/SQLDiagnostic.java:368:in `addDiagnostic': java.sql.SQLException: Login failed for user ''. The user is not associated with a trusted SQL Server connection. (NativeException) Any tips? Thanks, activerecord (2.3.5) activerecord-jdbc-adapter (0.9.6) activerecord-jdbcmssql-adapter (0.9.6) jdbc-jtds (1.2.5) jruby 1.4.0 (ruby 1.8.7 patchlevel 174) (2009-11-02 69fbfa3) (Java HotSpot(TM) Client VM 1.6.0_18) [x86-java]

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• How to configure multiple mappings using FluentHibernate?

  - by chris.baglieri

  First time rocking it with NHibernate/Fluent so apologies in advance if this is a naive question. I have a set of Models I want to map. When I create my session factory I'm trying to do all mappings at once. I am not using auto-mapping (though I may if what I am trying to do ends up being more painful than it ought to be). The problem I am running into is that it seems only the top map is taking. Given the code snippet below and running a unit test that attempts to save 'bar', it fails and checking the logs I see NHibernate is trying to save a bar entity to the foo table. While I suspect it's my mappings it could be something else that I am simply overlooking. Code that creates the session factory (note I've also tried separate calls into .Mappings): Fluently.Configure().Database(MsSqlConfiguration.MsSql2008 .ConnectionString(c => c .Server(@"localhost\SQLEXPRESS") .Database("foo") .Username("foo") .Password("foo"))) .Mappings(m => { m.FluentMappings.AddFromAssemblyOf<FooMap>() .Conventions.Add(FluentNHibernate.Conventions.Helpers .Table.Is(x => "foos")); m.FluentMappings.AddFromAssemblyOf<BarMap>() .Conventions.Add(FluentNHibernate.Conventions.Helpers .Table.Is(x => "bars")); }) .BuildSessionFactory(); Unit test snippet: using (var session = Data.SessionHelper.SessionFactory.OpenSession()) { var bar = new Bar(); session.Save(bar); Assert.NotNull(bar.Id); }

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• Issue with the Entity Manager and phpunit in Symfony 2

  - by rgazelot

  I have an issue with my Entity Manager in phpunit. This is my test : public function testValidChangeEmail() { $client = self::createAuthClient('user','password'); $crawler = $client->request('GET', '/user/edit/30'); $crawler = $client->submit($crawler->selectButton('submit')->form(array( 'form[email]' => '[email protected]', ))); /* * With this em, this work perfectly * $em = $client->getContainer()->get('doctrine.orm.entity_manager'); */ $user = self::$em->getRepository('MyBundle:User')->findUser('[email protected]'); die(var_dump($user->getEmail())); } and this is my WebTestCase which extends original WebTestCase : class WebTestCase extends BaseWebTestCase { static protected $container; static protected $em; static protected function createClient(array $options = array(), array $server = array()) { $client = parent::createClient($options, $server); self::$em = $client->getContainer()->get('doctrine.orm.entity_manager'); self::$container = $client->getContainer(); return $client; } protected function createAuthClient($user, $pass) { return self::createClient(array(), array( 'PHP_AUTH_USER' => $user, 'PHP_AUTH_PW' => $pass, )); } As you can see, I replace the self::$em when I created my client. My issue : In my test, the die() give me the old email and not the new email ([email protected]) which has registered in the test. However in my database, I have the [email protected] correctly saved. When I retrieve my user in the database, I use sefl::$em. If I use the $em in comments, I retrieve the right new email. I don't understand why in my WebTestCase, I can access to the new Entity Manager...

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• Cannot connect to MySQL server using JSP

  - by Dibya

  I just set foot on JSP. I started writing simple programs to display dates, system info. Then I tried to connect a MySQL database I have a free hosting account, but I am not able to connect to MySQL database. Here is my code: <%@ page import="java.sql.*" %> <%@ page import="java.io.*" %>  <html> <head> <title>Connection with mysql database</title> </head> <body> <h1>Connection status</h1> <% try { String connectionURL = "jdbc:mysql://mysql2.000webhost.com/a3932573_product"; Connection connection = null; Class.forName("com.mysql.jdbc.Driver").newInstance(); connection = DriverManager.getConnection(connectionURL, "a3932573_dibya", "******"); if(!connection.isClosed()) out.println("Successfully connected to " + "MySQL server using TCP/IP..."); connection.close(); }catch(Exception ex){ out.println("Unable to connect to database."); } %> </font> </body> </html> I am getting Message as Connection Status unable to connect to database. I have tested this connection using PHP using the same username, password and database name. Where am I making mistake?

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• Colorbox iFrame content not appearing in IE 8/9

  - by Rocketpig

  I'm using ColorBox to call a few informational modals on-screen and given the client's requirements, the best way to do this is via iFrames (not my first choice but whatever). Everything is working peachy in Chrome, FF, etc. but the iFrame content is not working in any version of IE. The modal wrapper appears but nothing is inside. This is what I've done so far: Changed the doctype to transitional and strict for IE. No dice. Removed the "iframe: true" and replaced it with HTML "Hello". That worked fine and "Hello" appeared in the Colorbox modal. I've removed all stylesheets from the header. No luck so it's not a CSS issue. Just to be sure, I rolled back my JQuery library to 1.6.2 from 1.8.2. Nothing there, either. Any help would be appreciated. This is aggravating. Some code: $(function () { $(".modal-large").colorbox({iframe:true, innerWidth:580, innerHeight:500}); }) HTML: <div class="top-droptext"><a class="modal-large" href="modal/serviceproviderinfo.html">Update Password</a></div>

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• Recommended approach for error handling with PHP and MYSQL

  - by iama

  I am trying to capture database (MYSQL) errors in my PHP web application. Currently, I see that there are functions like mysqli_error(), mysqli_errno() for capturing the last occurred error. However, this still requires me to check for error occurrence using repeated if/else statements in my php code. You may check my code below to see what I mean. Is there a better approach to doing this? (or) Should I write my own code to raise exceptions and catch them in one single place? What is the recommended approach? Also, does PDO raise exceptions? Thanks. function db_userexists($name, $pwd, &$dbErr) { $bUserExists = false; $uid = 0; $dbErr = ''; $db = new mysqli(SERVER, USER, PASSWORD, DB); if (!mysqli_connect_errno()) { $query = "select uid from user where uname = ? and pwd = ?"; $stmt = $db->prepare($query); if ($stmt) { if ($stmt->bind_param("ss", $name, $pwd)) { if ($stmt->bind_result($uid)) { if ($stmt->execute()) { if ($stmt->fetch()) { if ($uid) $bUserExists = true; } } } } if (!$bUserExists) $dbErr = $db->error(); $stmt->close(); } if (!$bUserExists) $dbErr = $db->error(); $db->close(); } else { $dbErr = mysqli_connect_error(); } return $bUserExists; }

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• How would I authenticate against a local windows user on another machine in an ASP.NET application?

  - by Daniel Chambers

  In my ASP.NET application, I need to be able to authenticate/authorise against local Windows users/groups (ie. not Active Directory) on a different machine, as well as be able to change the passwords of said remote local Windows accounts. Yes, I know Active Directory is built for this sort of thing, but unfortunately the higher ups have decreed it needs to be done this way (so authentication against users in a database is out as well). I've tried using DirectoryEntry and WinNT like so: DirectoryEntry user = new DirectoryEntry(String.Format("WinNT://{0}/{1},User", serverName, username), username, password, AuthenticationTypes.Secure) but this results in an exception when you try to log in more than one user: Multiple connections to a server or shared resource by the same user, using more than one user name, are not allowed. Disconnect all previous connections to the server or shared resource and try again. I've tried making sure my DirectoryEntries are used inside a using block, so they're disposed properly, but this doesn't seem to fix the issue. Plus, even if that did work it is possible that two users could hit that line of code concurrently and therefore try to create multiple connections, so it would be fragile anyway. Is there a better way to authenticate against local Windows accounts on a remote machine, authorise against their groups, and change their passwords? Thanks for your help in advance.

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• connecting to mysql from excel: ODBC driver does not support the requested properties.

  - by every_answer_gets_a_point

  i am trying to add data to mysql from excel. i am getting the above error on this line: rs.Open strSQL, oConn, adOpenDynamic, adLockOptimistic here is my code: Dim oConn As ADODB.Connection Private Sub ConnectDB() Set oConn = New ADODB.Connection oConn.Open "DRIVER={MySQL ODBC 5.1 Driver};" & _ "SERVER=localhost;" & _ "DATABASE=employees;" & _ "USER=root;" & _ "PASSWORD=some_pass;" & _ "Option=3" End Sub Function esc(txt As String) esc = Trim(Replace(txt, "'", "\'")) End Function Private Sub InsertData() Dim rs As ADODB.Recordset Set rs = New ADODB.Recordset ConnectDB With wsBooks For rowCursor = 2 To 11 strSQL = "INSERT INTO tutorial (author, title, price) " & _ "VALUES ('" & esc(.Cells(rowCursor, 1)) & "', " & _ "'" & esc(.Cells(rowCursor, 2)) & "', " & _ esc(.Cells(rowCursor, 3)) & ")" rs.Open strSQL, oConn, adOpenDynamic, adLockOptimistic Next End With End Sub whats wrong with rs.Open strSQL, oConn, adOpenDynamic, adLockOptimistic ? why am i getting the odbc error?

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• How to configure ldap login with php

  - by Drew G

  I'm attempting to implement a login that works with ldap, My extension=php_ldap.dll is uncommented in both of my php config files, ldap shows up in my phpinfo() I have access to AD and I've been using dsquery to snoop around. So I believe I'm very close to achieving my goal function authenticate($user, $password) { $ldap_host = "na.ad.mycompanyname.com"; $ldap_dn = "CN=USA-USERS,DC=ad,DC=mycompanyname,DC=com"; $ldap_user_group = "Domain Users"; $ldap_manager_group = "Domain Admins"; $ldap_usr_dom = "@na.ad.mycompany.com"; So for now when I enter my login credentials, it fails and I get the appropriate error, my question is, what information do I need to enter and which dsquery commands should I use? Without being spoonfed, could someone point me in the right direction? I've done some extensive research, but nothing I could find really assists with figuring out which CN's and OU's to use. Yes I realize I need to be using the correct CN's and OU's that correspond to my location, but I've been trying the guess and check method to no avail, so I figured I would ask. Any assistance is appreciated. THANKS!!!

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• Strange befaviour of spring transaction support for JPA + Hibernate +@Transactional annotation

  - by abovesun

  I found out really strange behavior on relatively simple use case, probably I can't understand it because of not deep knowledges of spring @Transactional nature, but this is quite interesting. I have simple User dao that extends spring JpaDaoSupport class and contains standard save method: @Transactional public User save(User user) { getJpaTemplate().persist(user); return user; } If was working fine until I've add new method to same class: User getSuperUser(), this method should return user with isAdmin == true, and if there is no super user in db, method should create one. Thats how it was looking like: public User createSuperUser() { User admin = null; try { admin = (User) getJpaTemplate().execute(new JpaCallback() { public Object doInJpa(EntityManager em) throws PersistenceException { return em.createQuery("select u from UserImpl u where u.admin = true").getSingleResult(); } }); } catch (EmptyResultDataAccessException ex) { User admin = new User('login', 'password'); admin.setAdmin(true); save(admin); // THIS IS THE POINT WHERE STRANGE THING COMING OUT } return admin; } As you see code is strange forward and I was very confused when found out that no transaction was created and committed on invocation of save(admin) method and no new user wasn't actually created despite @Transactional annotation. In result we have situation: when save() method invokes from outside of UserDAO class - @Transactional annotation counted and user successfully created, but if save() invokes from inside of other method of the same dao class - @Transactional annotation ignored. Here how I was change save() method to force it always create transaction. public User save(User user) { getJpaTemplate().execute(new JpaCallback() { public Object doInJpa(EntityManager em) throws PersistenceException { em.getTransaction().begin(); em.persist(user); em.getTransaction().commit(); return null; } }); return user; } As you see I manually invoke begin and commit. Any ideas?

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