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  • selecting the first of multiple classes

    - by gleddy
    Not sure if you can do this, but I want to select the first of two classes of an element with jQuery and return it's first class only. <div class="module blue"> I want to return 'module'. tried this: var state = $('body').attr('class').first(); but none of that seems to work, thanks for any advice.

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  • Jboss logging issue - pl check this

    - by balaji
    I’m Working as deployer and server administrator. We use Jboss 4.0x AS to deploy our applications. The issue I'm facing is, Whenever we redeploy/restart the server, server.log is getting created but after sometime the logging goes off. Yes it is not at all updating the server.log file. Due to this, we could not trace the other critical issues we have. Actually we have two separate nodes and we do deploy/restarting the server separately on two nodes. We are facing the issue in both of our test and production environment. I could not trace out where exactly the issue is. Could you please help me in resolving the issue? If we have any other issues, we can check the log files. If log itself is not getting updated/logged, how can we move further in analyzing the issues without the recent/updated logs? Below are the logs found in the stdout.log: 18:55:50,303 INFO [Server] Core system initialized 18:55:52,296 INFO [WebService] Using RMI server codebase: http://kl121tez.is.klmcorp.net:8083/ 18:55:52,313 INFO [Log4jService$URLWatchTimerTask] Configuring from URL: resource:log4j.xml 18:55:52,860 ERROR [STDERR] LOG0026E The Log Manager cannot create the object AmasRBPFTraceLogger without a class name. 18:55:52,860 ERROR [STDERR] LOG0026E The Log Manager cannot create the object AmasRBPFMessageLogger without a class name. 18:55:54,273 ERROR [STDERR] LOG0026E The Log Manager cannot create the object AmasCacheTraceLogger without a class name. 18:55:54,274 ERROR [STDERR] LOG0026E The Log Manager cannot create the object AmasCacheMessageLogger without a class name. 18:55:54,334 ERROR [STDERR] LOG0026E The Log Manager cannot create the object JACCTraceLogger without a class name. 18:55:54,334 ERROR [STDERR] LOG0026E The Log Manager cannot create the object JACCMessageLogger without a class name. 18:55:56,059 INFO [ServiceEndpointManager] WebServices: jbossws-1.0.3.SP1 (date=200609291417) 18:55:56,635 INFO [Embedded] Catalina naming disabled 18:55:56,671 INFO [ClusterRuleSetFactory] Unable to find a cluster rule set in the classpath. Will load the default rule set. 18:55:56,672 INFO [ClusterRuleSetFactory] Unable to find a cluster rule set in the classpath. Will load the default rule set. 18:55:56,843 INFO [Http11BaseProtocol] Initializing Coyote HTTP/1.1 on http-0.0.0.0-8180 18:55:56,844 INFO [Catalina] Initialization processed in 172 ms 18:55:56,844 INFO [StandardService] Starting service jboss.web Please help..

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  • got a question about Linked-List in java code.

    - by glacier89
    Linked-List: Mirror Consider the following private class for a node of a singly-linked list of integers: private class Node{ public int value; public Node next; } A wrapper-class, called, ListImpl, contains a pointer, called start to the first node of a linked list of Node. Write an instance-method for ListImpl with the signature: public void mirror(); That makes a reversed copy of the linked-list pointed to by start and appends that copy to the end of the list. So, for example the list: start 1 2 3 after a call to mirror, becomes: start 1 2 3 3 2 1 Note: in your answer you do not need to dene the rest of the class for ListImpl just the mirror method.

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  • Using Rails and Rspec, how do you test that the database is not touched by a method

    - by Will Tomlins
    So I'm writing a test for a method which for performance reasons should achieve what it needs to achieve without using SQL queries. I'm thinking all I need to know is what to stub: describe SomeModel do describe 'a_getter_method' do it 'should not touch the database' do thing = SomeModel.create something_inside_rails.should_not_receive(:a_method_querying_the_database) thing.a_getter_method end end end EDIT: to provide a more specific example: class Publication << ActiveRecord::Base end class Book << Publication end class Magazine << Publication end class Student << ActiveRecord::Base has_many :publications def publications_of_type(type) #this is the method I am trying to test. #The test should show that when I do the following, the database is queried. self.publications.find_all_by_type(type) end end describe Student do describe "publications_of_type" do it 'should not touch the database' do Student.create() student = Student.first(:include => :publications) #the publications relationship is already loaded, so no need to touch the DB lambda { student.publications_of_type(:magazine) }.should_not touch_the_database end end end So the test should fail in this example, because the rails 'find_all_by' method relies on SQL.

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  • NoClassDefFoundError with new eclipse bundle

    - by djmedic
    I am informed by a customer that they are receiving an error. On the report they filed it is continuosly coming up with NoClassDefFoundError. It appears none of my other customers are having this issue. I'm not having this issue running the app on my Motorola Droid Maxx. The customer is running the app on a rooted Droid Bionic. Everything was working fine on my version at 2.3 but when I updated it to 2.4, this issue arose. I also replaced my computer with a new and now I am running windows 8 and installed the adt bundle. The only change I made to the file in question in changing a -90 to -85. Below is the code...I have also included below the code the error report. This is only happening on phone. import android.app.Activity; import android.content.Context; import android.content.Intent; import android.net.ConnectivityManager; import android.net.NetworkInfo; import android.os.Bundle; import android.telephony.PhoneStateListener; import android.telephony.SignalStrength; import android.telephony.TelephonyManager; public class ConnectivityCheck extends Activity { TelephonyManager Tel; MyPhoneStateListener MyListener; boolean isGsm; boolean cellAvailable; int strengthAmplitudeGSM; int strengthAmplitudeCDMA; @Override public void onCreate(Bundle icicle) { super.onCreate(icicle); ConnectivityManager connec = (ConnectivityManager)getSystemService(Context.CONNECTIVITY_SERVICE); if (connec.getNetworkInfo(0) != null) { cellAvailable = true; } if (cellAvailable) { /* Update the listener, and start it */ MyListener = new MyPhoneStateListener(); Tel = ( TelephonyManager )getSystemService(Context.TELEPHONY_SERVICE); Tel.listen(MyListener ,PhoneStateListener.LISTEN_SIGNAL_STRENGTHS); } if (connec.getNetworkInfo(1).getState() == NetworkInfo.State.CONNECTED) { startActivity(new Intent(ConnectivityCheck.this, LicenseCheck.class)); if (cellAvailable) { Tel.listen(MyListener, PhoneStateListener.LISTEN_NONE); } finish(); } else if (cellAvailable) { if (connec.getNetworkInfo(0).getState() == NetworkInfo.State.CONNECTED && strengthAmplitudeCDMA >= -90) { startActivity(new Intent(ConnectivityCheck.this, LicenseCheck.class)); Tel.listen(MyListener, PhoneStateListener.LISTEN_NONE); finish(); } else if (connec.getNetworkInfo(0).getState() == NetworkInfo.State.CONNECTED && isGsm && strengthAmplitudeGSM >= 10 && strengthAmplitudeGSM <= 31) { startActivity(new Intent(ConnectivityCheck.this, LicenseCheck.class)); Tel.listen(MyListener, PhoneStateListener.LISTEN_NONE); finish(); } else { startActivity(new Intent(ConnectivityCheck.this, ProtocolsMMenuActivity.class)); Tel.listen(MyListener, PhoneStateListener.LISTEN_NONE); finish(); } } else { startActivity(new Intent(ConnectivityCheck.this, ProtocolsMMenuActivity.class)); if (cellAvailable) { Tel.listen(MyListener, PhoneStateListener.LISTEN_NONE); } finish(); } } /* Called when the application is minimized */ @Override protected void onPause() { super.onPause(); if (cellAvailable) { Tel.listen(MyListener, PhoneStateListener.LISTEN_NONE); } } /* Called when the application resumes */ @Override protected void onResume() { super.onResume(); if (cellAvailable) { Tel.listen(MyListener, PhoneStateListener.LISTEN_SIGNAL_STRENGTHS); } } /* Start the PhoneState listener */ private class MyPhoneStateListener extends PhoneStateListener { /* Get the Signal strength from the provider, each tiome there is an update */ @Override public void onSignalStrengthsChanged(SignalStrength signalStrength) { isGsm = signalStrength.isGsm(); strengthAmplitudeGSM = signalStrength.getGsmSignalStrength(); strengthAmplitudeCDMA = signalStrength.getCdmaDbm(); super.onSignalStrengthsChanged(signalStrength); } };/* End of private Class */ } Here is the error report java.lang.NoClassDefFoundError: com.emsprotocols.njalsprotocolspaidac.ConnectivityCheck at com.emsprotocols.njalsprotocolspaidac.ProtocolsSplashActivity$1.onAnimationEnd (ProtocolsSplashActivity.java:144) at android.view.animation.AnimationSet.getTransformation(AnimationSet.java:411) at android.view.animation.Animation.getTransformation(Animation.java:920) at android.view.ViewGroup.drawChild(ViewGroup.java:2657) at android.view.ViewGroup.dispatchDraw(ViewGroup.java:2489) at android.view.ViewGroup.drawChild(ViewGroup.java:2885) at android.view.ViewGroup.dispatchDraw(ViewGroup.java:2489) at android.view.ViewGroup.drawChild(ViewGroup.java:2885) at android.view.ViewGroup.dispatchDraw(ViewGroup.java:2489) at android.view.View.draw(View.java:11009) at android.widget.FrameLayout.draw(FrameLayout.java:450) at com.android.internal.policy.impl.PhoneWindow$DecorView.draw(PhoneWindow.java:2154) at android.view.ViewRootImpl.draw(ViewRootImpl.java:2096) at android.view.ViewRootImpl.performTraversals(ViewRootImpl.java:1679) at android.view.ViewRootImpl.handleMessage(ViewRootImpl.java:2558) at android.os.Handler.dispatchMessage(Handler.java:99) at android.os.Looper.loop(Looper.java:137) at android.app.ActivityThread.main(ActivityThread.java:4722) at java.lang.reflect.Method.invokeNative(Native Method) at java.lang.reflect.Method.invoke(Method.java:511) at com.android.internal.os.ZygoteInit$MethodAndArgsCaller.run(ZygoteInit.java:787) at com.android.internal.os.ZygoteInit.main(ZygoteInit.java:554) at dalvik.system.NativeStart.main(Native Method)

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  • Eclipse outline of Prototype javascript classes

    - by Rob Agar
    Is there a way to show the structure of a javascript class declared using Prototype's Class.create function in the Eclipse outline view? The declarations look like: var Foo = Class.create({ bar: function() { ... }, baz: function() { ... }, }); At the moment all I get is "Foo:". (A google search turned up http://marketplace.eclipse.org/content/prototypewtp, but the link to the plugin homepage is dead)

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  • [iPhone]Objective C, objects which do not conform to NSCoding. How to write them to a file.

    - by Noah
    Hi, I am using an Objective c class, a subclass of NSObject. This class cannot be modified. I have an instance of this class that I wish to write to a file which can be retrieved and later reinstate. The object does not conform to NSCoding. To sum up, I need to save an instance of a class to a file which can be retrieved later, without using any of the NSCoding methods such as NSKeyedArchiving encodeWithCoder ... Using them returns this... NSInvalidArgumentException ...encodeWithCoder:] unrecognised selector sent to instance... Is there any other way I can store this object for later use Thank you

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  • Eclipse Javadoc tooltip help doesn't show classes' supertypes and interfaces

    - by Pooria
    I'm talking about the tooltip that pops up when you hover your mouse over a class in your source (which also helps with intellisense and auto completion), which describes what a class/method/etc does. I find it very annoying that it doesn't show what superclass the class (being described) extends or what interfaces it implements. Is there a way to make eclipse show the additional information?

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  • Easiest way to rename a model using Django/South?

    - by vaughnkoch
    Hi everyone, I've been hunting for an answer to this on South's site, google, and SO, but couldn't find a simple way to do this. I want to rename a Django model using South. Say you have the following: class Foo(models.Model): name = models.CharField() class FooTwo(models.Model): name = models.CharField() foo = models.ForeignKey(Foo) and you want to convert Foo to Bar, namely class Bar(models.Model): name = models.CharField() class FooTwo(models.Model): name = models.CharField() foo = models.ForeignKey(Bar) To keep it simple, I'm just trying to change the name from Foo to Bar, but ignore the 'foo' member in FooTwo for now. What's the easiest way to do this using South? a) I could probably do a data migration, but that seems pretty involved. b) Write a custom migration, e.g. db.rename_table('city_citystate', 'geo_citystate'), but I'm not sure how to fix the foreign key in this case. c) An easier way that you know? Thanks!

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  • Creating form object for variable kind of form.

    - by Bunny Rabbit
    i want to create a form for users to submit questions in django ..so far the models i have created are class Question(models.Model): statement=models.CharField(max_length=100) class Choice(models.Model): statement=models.CharField(max_length=100) value=models.IntegerField() question=models.ForeignKey(Question) Now i want to write a Form class for creating a above form but the problem is the number of choices are variable,a user can decide how many choices a question must have .How do i do that in django?

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  • In the following list, how do I prevent jQuery from interacting with part of it.

    - by kylex
    I have the following list structure: <ul> <li>One</li> <li class="topActive">Two <ul> <li class="active">Two-1 <ul> <li>Two-1-1</li> </ul> </li> <li>Two-2</li> </ul> </li> <li>Three <ul> <li>Three-1</li> </ul> </li> </ul> with the following jQuery: $("ul>li>ul").hide(); $("ul>li>ul>li>ul").hide(); $("ul>li>ul>li>ul>ul>li").hide(); $('.active').parents().show();????????? $("ul>li").hoverIntent( function(){ $(this).children('ul').slideDown('fast'); }, function(){ $(this).children('ul').slideUp('fast'); } ); $("ul>li>ul>li").hoverIntent( function(){ $(this).children('ul').slideDown('fast'); }, function(){ $(this).children('ul').slideUp('fast'); } ); What I would like is this: When an li class is topActive, everything within that class down to the current class can not be affected by the jQuery that causes the list to slide up and down. so in the case provided the following would show, along with the top level: One Two Two-1 Two-2 Three And when I mouse over either, Two, or Two-1 or Two-2 nothing happens, but if I mouse over Three, the jQuery will cause it to slide up or slide down. In this example: <ul> <li>One</li> <li class="topActive">Two <ul> <li class="active">Two-1 <ul> <li>Two-1-1</li> </ul> </li> <li>Two-2</li> </ul> </li> <li>Three <ul> <li>Three-1</li> </ul> </li> </ul> When I mouseover Two-1, it will slide down, but when I mouse out Two-1 will remain. One Two Two-1 Two-2 Three Any suggestsions for either a CSS or jQuery implementation (or mixture of the two)?

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  • Addind link with existin href.

    - by Dom
    Hello gurus, Im trying to create link inside my list tag that will have href inherited from link that already exists in this list tag. Don't know how much sense does it makes, but i have this: <ul> <li><a href="page1.html">Support</a></li> <li><a href="page2.html">Products</a></li> <li><a href="page3.html">Management</a></li> <li><a href="page4.html">Others</a></li> </ul> and I need soothing like this: <ul> <li> <a href="page1.html">Support</a> <div class="slideLink"><a href="page1.html">Click Here</a></div> </li> <li> <a href="page2.html">Products</a> <div class="slideLink"><a href="page2.html">Click Here</a></div> </li> <li> <a href="page3.html">Management</a> <div class="slideLink"><a href="page3.html">Click Here</a></div> </li> <li> <a href="page4.html">Others</a> <div class="slideLink"><a href="page4.html">Click Here</a></div> </li> </ul> So far I have managed to add div with class and link within it with "click here" text, but i don't have a clue how to grab link href and add it to my new link. $('ul li a').each(function(){ $(this).after("<div class='slideLink'><a href=" + Link + ">Read more</div>"); }); Thank you for your help in advance. Best Regards Dom

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  • How to create a true singleton in java?

    - by rjoshi
    I am facing a problem with my singleton when used across multiple class loaders. E.g Singleton accessed by multiple EJBs. Is there any way to create a singleton which has only one instance across all class loader? I am looking for pure java solution either using custom class loader or some other way.

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  • Why is String final in Java?

    - by Alex
    From when I learned that the class java.lang.String is declared as final in Java, I was wondering why is that? I didn't find any answer back then, but this post: How to create a replica of String class in Java? reminded me of my query. Sure, String provides all the functionality I ever needed, and never thought of any operation that would require an extension of class String, but still you'll never know what someone might need! So, does anyone know what was the intent of the designers when they decided to make it final? See also: Why is String a sealed class in C#?

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  • Why do WCF clients depend on the app.config file?

    - by routeNpingme
    Like a lot of things, I'm sure there's a good reason for this, so please help me understand... Why, by default, do WCF services store settings in app.config? This has been so frustrating trying to work with multiple Silverlight class libraries. These class libraries are supposed to be completely independent from each other, and this dependency on the app.config seems to cause the following headaches: Single Responsibility Principle - I should be able to add a reference to a class library and go. If that class library uses a service reference, this idea is shot before I even start coding against it. Muddy Configuration - To get other libraries to work, I have to copy and paste the service configurations into the "main" application configs. If an endpoint changes in any way, I can't just worry about a new version of that class DLL - I have to worry about anything that uses it, too. Complex Alternatives - Programmatically creating the endpoint isn't pretty. Period. There has to be a better way. Why doesn't WCF at least separate the service configurations into a ServiceName.config or something that gets copied to an output directory. What am I missing? How do you deal with this?

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  • No improvement in speed when using Ehcache with Hibernate

    - by paddydub
    I'm getting no improvement in speed when using Ehcache with Hibernate Here are the results I get when i run the test below. The test is reading 80 Stop objects and then the same 80 Stop objects again using the cache. On the second read it is hitting the cache, but there is no improvement in speed. Any idea's on what I'm doing wrong? Speed Test: First Read: Reading stops 1-80 : 288ms Second Read: Reading stops 1-80 : 275ms Cache Info: elementsInMemory: 79 elementsInMemoryStore: 79 elementsInDiskStore: 0 JunitCacheTest public class JunitCacheTest extends TestCase { static Cache stopCache; public void testCache() { ApplicationContext context = new ClassPathXmlApplicationContext("beans-hibernate.xml"); StopDao stopDao = (StopDao) context.getBean("stopDao"); CacheManager manager = new CacheManager(); stopCache = (Cache) manager.getCache("ie.dataStructure.Stop.Stop"); //First Read for (int i=1; i<80;i++) { Stop toStop = stopDao.findById(i); } //Second Read for (int i=1; i<80;i++) { Stop toStop = stopDao.findById(i); } System.out.println("elementsInMemory " + stopCache.getSize()); System.out.println("elementsInMemoryStore " + stopCache.getMemoryStoreSize()); System.out.println("elementsInDiskStore " + stopCache.getDiskStoreSize()); } public static Cache getStopCache() { return stopCache; } } HibernateStopDao @Repository("stopDao") public class HibernateStopDao implements StopDao { private SessionFactory sessionFactory; @Transactional(readOnly = true) public Stop findById(int stopId) { Cache stopCache = JunitCacheTest.getStopCache(); Element cacheResult = stopCache.get(stopId); if (cacheResult != null){ return (Stop) cacheResult.getValue(); } else{ Stop result =(Stop) sessionFactory.getCurrentSession().get(Stop.class, stopId); Element element = new Element(result.getStopID(),result); stopCache.put(element); return result; } } } ehcache.xml <cache name="ie.dataStructure.Stop.Stop" maxElementsInMemory="1000" eternal="false" timeToIdleSeconds="5200" timeToLiveSeconds="5200" overflowToDisk="true"> </cache> stop.hbm.xml <class name="ie.dataStructure.Stop.Stop" table="stops" catalog="hibernate3" mutable="false" > <cache usage="read-only"/> <comment></comment> <id name="stopID" type="int"> <column name="STOPID" /> <generator class="assigned" /> </id> <property name="coordinateID" type="int"> <column name="COORDINATEID" not-null="true"> <comment></comment> </column> </property> <property name="routeID" type="int"> <column name="ROUTEID" not-null="true"> <comment></comment> </column> </property> </class> Stop public class Stop implements Comparable<Stop>, Serializable { private static final long serialVersionUID = 7823769092342311103L; private Integer stopID; private int routeID; private int coordinateID; }

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  • Error while including j2ssh in a j2me midlet

    - by Farhan
    I obtained an evaluation license for j2ssh maverick, downloaded the library and included the j2me jar into my project. But i get the following error when i try to run/build the project (in netbeans, using WTK 3.0) Error preverifying class com.maverick.events.J2SSHEventMessages VERIFIER ERROR com/maverick/events/J2SSHEventMessages.class$(Ljava/lang/String;)Ljava/lang/Class;: Cannot find class java/lang/NoClassDefFoundError I get the same error when i use eclipse (error in preverifying stage). Any pointers ? There are more than one NoClassDefFoundErrors in the preverifying stage. Am i using the wrong .jar file ?

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  • top rounded corners in my jquery

    - by Sohail
    Hello everybody, I have this jquery for my menu buttons, what I want is to get top-corner rounded for my menu, this is a whole code: <html> <style type="text/css"> #menuBarHolder { width: 860px; height:45px; background-color:#000; color:#fff; font-family:Arial; font-size:14px; margin-top:20px;} #menuBarHolder ul{ list-style-type:none; display:block;} .firstchild { border-left:1px solid #ccc;} #container { margin-top:10px;} #menuBar li{ float:left; padding:15px; height:16px; width:70px; border-right:1px solid #ccc; } #menuBar li a{color:#fff; text-decoration:none; letter-spacing:-1px; font-weight:bold;} .menuHover { background-color:#999;} .menuInfo { cursor:hand; background-color:#000; color:#fff; width:74px; font-size:11px;height:100px; padding:3px; display:none; position:absolute; margin-left:-15px; margin-top:0px; -moz-border-radius-bottomright: 5px; -moz-border-radius-bottomleft: 5px; -webkit-border-bottom-left-radius: 5px; -webkit-border-bottom-right-radius: 5px; -khtml-border-radius-bottomright: 5px; -khtml-border-radius-bottomleft: 5px; border-radius-bottomright: 5px;border-radius-bottomleft: 5px; } </style> <!--[if IE]> <style type="text/css"> #menuBar li a{width:50px;} .menuInfo { margin-left:-65px; width:80px;} </style> <![endif]--> <script src="http://jqueryjs.googlecode.com/files/jquery-1.2.6.js"></script> <script type="text/javascript"> $(document).ready(function() { $('#menuBar li').click(function() { var url = $(this).find('a').attr('href'); document.location.href = url; }); $('#menuBar li').hover(function() { $(this).find('.menuInfo').slideDown(); }, function() { $(this).find('.menuInfo').slideUp(); }); }); </script> <center> <div id="menuBarHolder"> <ul id="menuBar"> <li class="firstchild"><a href="javascript:#">Home</a><div class="menuInfo">I am some text about the home section</div></li> <li><a href="javascript:#">About Us</a><div class="menuInfo">I am some text about the services section</div></li> <li><a href="javascript:#">News</a><div class="menuInfo">I am some text about the clients section</div></li> <li><a href="javascript:#">Equipment</a><div class="menuInfo">I am some text about the portfolio section</div></li> <li><a href="javascript:#">Services</a><div class="menuInfo">I am some text about the about section</div></li> <li><a href="javascript:#">Project</a><div class="menuInfo">I am some text about the blog section</div></li> <li><a href="javascript:#">Contact Us</a><div class="menuInfo">I am some text about the follow section</div></li> </ul> </div> </div> </center> </html> Thanks for your help.

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  • tomcat resource missing, servlet not running

    - by user2837260
    import javax.servlet.*; import java.io.*; public class MyServlet implements Servlet { public void init(ServletConfig con) {} public void service(ServletRequest req, ServletResponse res) throws IOException,ServletException { res.setContentType("text/html"); PrintWriter out=res.getWriter(); String s="blah"; String s1="blah"; out.println("<html><body>"); if((s.equals(req.getParameter("firstname")))&&(s1.equals(req.getParameter("pwd")))) out.println("passwords match"); else out.println("password and name combo does not match"); out.println("</body></html>"); } public void destroy() {} public ServletConfig getServletConfig() { return null;} public String getServletInfo() { return null;} } this is my java file with the servlet class.its saved with the name MyServlet.java and so is the class file. and here is the xml file: <web-app> <servlet> <servlet-name>demoo</servlet-name> <servlet-class>MyServlet</servlet-class> </servlet> <servlet-mapping> <servlet-name>demoo</servlet-name> <url-pattern>/demo</url-pattern> </servlet-mapping> </web-app> i have made the folder as WEB-INF and then classes... WEB-INF also contains the .xml file but when i try to run the servlet , it says resource not found ps- i am already looking for the servlet with the name :demo localhost:8081/s1/demo* s1 is the war file * a html file in the war file seems to run fine on the server though. *

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  • Resuming execution of code after exception is thrown and caught

    - by dotnetdev
    Hi, How is it possible to resume code execution after an exception is thrown? For exampel, take the following code: namespace ConsoleApplication1 { class Test { public void s() { throw new NotSupportedException(); string @class = "" ; Console.WriteLine(@class); Console.ReadLine(); } } class Program { static void Main(string[] args) { try { new Test().s(); } catch (ArgumentException x) { } catch (Exception ex) { } } } } After catching the exception when stepping through, the program will stop running. How can I still carry on execution? Thanks

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  • how to model a follower stream in appengine?

    - by molicule
    I am trying to design tables to buildout a follower relationship. Say I have a stream of 140char records that have user, hashtag and other text. Users follow other users, and can also follow hashtags. I am outlining the way I've designed this below, but there are two limitaions in my design. I was wondering if others had smarter ways to accomplish the same goal. The issues with this are The list of followers is copied in for each record If a new follower is added or one removed, 'all' the records have to be updated. The code class HashtagFollowers(db.Model): """ This table contains the followers for each hashtag """ hashtag = db.StringProperty() followers = db.StringListProperty() class UserFollowers(db.Model): """ This table contains the followers for each user """ username = db.StringProperty() followers = db.StringListProperty() class stream(db.Model): """ This table contains the data stream """ username = db.StringProperty() hashtag = db.StringProperty() text = db.TextProperty() def save(self): """ On each save all the followers for each hashtag and user are added into a another table with this record as the parent """ super(stream, self).save() hfs = HashtagFollowers.all().filter("hashtag =", self.hashtag).fetch(10) for hf in hfs: sh = streamHashtags(parent=self, followers=hf.followers) sh.save() ufs = UserFollowers.all().filter("username =", self.username).fetch(10) for uf in ufs: uh = streamUsers(parent=self, followers=uf.followers) uh.save() class streamHashtags(db.Model): """ The stream record is the parent of this record """ followers = db.StringListProperty() class streamUsers(db.Model): """ The stream record is the parent of this record """ followers = db.StringListProperty() Now, to get the stream of followed hastags indexes = db.GqlQuery("""SELECT __key__ from streamHashtags where followers = 'myusername'""") keys = [k,parent() for k in indexes[offset:numresults]] return db.get(keys) Is there a smarter way to do this?

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  • Which design pattern is most appropriate?

    - by Anon
    Hello, I want to create a class that can use one of four algorithms (and the algorithm to use is only known at run-time). I was thinking that the Strategy design pattern sounds appropriate, but my problem is that each algorithm requires slightly different parameters. Would it be a bad design to use strategy, but pass in the relevant parameters into the constructor?. Here is an example (for simplicity, let's say there are only two possible algorithms) ... class Foo { private: // At run-time the correct algorithm is used, e.g. a = new Algorithm1(1); AlgorithmInterface* a; }; class AlgorithmInterface { public: virtual void DoSomething = 0; }; class Algorithm1 : public AlgorithmInterface { public: Algorithm1( int i ) : value(i) {} virtual void DoSomething(){ // Does something with int value }; int value; }; class Algorithm2 : public AlgorithmInterface { public: Algorithm2( bool b ) : value(b) {} virtual void DoSomething(){ // Do something with bool value }; bool value; };

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  • Python decorator question

    - by nsharish
    decorator 1: def dec(f): def wrap(obj, *args, **kwargs): f(obj, *args,**kwargs) return wrap decorator 2: class dec: def __init__(self, f): self.f = f def __call__(self, obj, *args, **kwargs): self.f(obj, *args, **kwargs) A sample class, class Test: @dec def disp(self, *args, **kwargs): print(*args,**kwargs) The follwing code works with decorator 1 but not with decorator 2. a = Test() a.disp("Message") I dont understand why decorator 2 is not working here. Can someone help me with this?

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