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  • what's wrong with this code?

    - by user329820
    Hi this is my code which will not work correctly ! what is wrong with its data type :( thanks CREATE TABLE T1 (A INTEGER NOT NULL); CREATE TABLE T3 (A SMALLINT NOT NULL); INSERT T1 VALUES (32768.5); SELECT * FROM T1; INSERT T3 SELECT * FROM T1; SELECT * FROM T3;

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  • mysql_fetch_array() expects parameter 1 to be resource problem

    - by user225269
    I don't get it, I see no mistakes in this code but there is this error, please help: mysql_fetch_array() expects parameter 1 to be resource problem <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO=".$_GET['id']); ?> <?php while ($row = mysql_fetch_array($result)) { ?> <table class="a" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#D3D3D3"> <tr> <form name="formcheck" method="get" action="updateact.php" onsubmit="return formCheck(this);"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Update Students</td> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $_GET['id']; ?>"></td> </tr> <tr> <td width="30" height="35"><font size="2">*Year:</td> <td width="30"><input name="yr" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $row["YEAR"]; ?>"></td> <?php } ?> I'm just trying to load the data in the forms but I don't know why that error appears. What could possibly be the mistake in here?

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  • Copying a database into a new database including structure and data

    - by Jason
    In phpMyAdmin under operations I can "Copy database to:" and select Structure and data CREATE DATABASE before copying Add AUTO_INCREMENT value I need to be able to do that without using phpMyAdmin. I know how to create the database and user. I have a source database that's a shell that I can work from so all I really need is the how to copy all the table structure and data part. (I know, the harder part) system() & exec() are not options for me which rules out mysqldump. (I think) How can I loop through each table and recreate it's structure and data? Is it just looping through the results of SHOW TABLES then for each table looping through DESCRIBE tablename Then, is there an easy way for getting the data copied?

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  • How to find the differences between the values of a specific column based on a key?

    - by Holicreature
    I've two tables as purchase_details and invoice_details and i want to store the inventory/stock of each product from the data of these two tables. structure of purchase_details. 'pid', 'int(10)' 'product_id', 'int(10)' 'quantity', 'float(8,2)' 'amount', 'float(12,2)' 'expiry_date', 'date' structure of purchase_details. 'invoice_id', 'int(10) unsigned' 'product_id', 'int(10) unsigned' 'quantity', 'float(10,2)' 'price', 'float(12,2)' i want to calculate the total quantity of remaining stock (quantity of sum of products from purchase_details - quantity of sum of products from invoice_details). Product_id is would be same for the two tables. how can i proceed?

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  • How do I make all the finders on the model ignorecase?

    - by Glex
    I have a model with several attributes, among them title and artist. The case of title and artist should be ignored in all the Active Record finders. Basically, if title or artist are present in the :conditions (or dynamically i.e. find_all_by_artist), then the WHERE artist = :artist should become WHERE UPPER(artist) = UPPER(:artist) or something along these lines. Is there a way of doing it with Rails?

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  • In what way does Wordpress rewrite page URLs?

    - by Mac Taylor
    Hey Recently I'm interested in post's structure of Wordpress. They use a table named (wp_posts) and in this table they saved 3 related fields such as : post_title post_name guid It's clear that they save title of each story in post_title field , and slugs in post_name , and full url of a post in guild filed . But where the hell, they rewrite these urls in way it appears in browsers : http://localhost/wordpress/about/ There is no htaccess rules for this ! I checked rewrite.php and didn't understand an inch ?! i need to create similar pages , what steps should i take !?

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  • Random Record from Recordset

    - by Tony Hanks
    I have the fillowing Query: SELECT a.*, ps4_media.filename, ps4_galleries.name as galleryname, ps4_media_iptc.description, ps4_media_iptc.title, ps4_media_iptc.headline, ps4_media.date_added, ps4_galleries.created, ps4_folders.name as foldername, ps4_galleries.gallery_count FROM ps4_media_galleries a INNER JOIN (SELECT ps4_media_galleries.gallery_id, min(ps4_media_galleries.gmedia_id) AS minID FROM ps4_media_galleries GROUP BY ps4_media_galleries.gallery_id) b ON a.gallery_id = b.gallery_id AND a.gmedia_id = b.minID INNER JOIN ps4_media ON ps4_media.media_id = a.gmedia_id INNER JOIN ps4_folders ON ps4_folders.folder_id = ps4_media.folder_id INNER JOIN ps4_galleries ON ps4_galleries.gallery_id = a.gallery_id INNER JOIN ps4_media_iptc ON ps4_media_iptc.media_id = a.gmedia_id ORDER BY ps4_galleries.created DESC How do I get ps4_media.filename to be random, everything else is fine just want the thumbnail which ps4_media.filename is to be and of the records in the found set.

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  • NOT LIKE not working on comparison to a column

    - by rodling
    Data is fairly large and takes few minutes to run it every time, so its taking a lot of time debugging this problem. When I run like concat('%',T.item,'%') on smaller data it seems to identify items properly. However, when I run it on the main DB (the code shown), it still shows many(maybe even all) of the exceptions. EDIT: it seems when i add NOT it stops identifying items select distinct T.comment from (select comment, source, item from data, non_informative where ticker != "O" and source != 7 and source != 6) as T where T.comment not like concat('%',T.item,'%') order by T.comment; comment and source are in data, item is in non_informative Some items from T.item: 'Stock Analysis -', '#InsideTrades', 'IIROC Trade' Example comment which should be removed '#InsideTrades #4 | MACNAB CRAIG (Director,Officer,Chief Executive Officer): Filed Form 4 for $NNN (NATIONAL RETA' Can't seem to figure out it why shows all the items

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  • Fetching a result twice with deferend name

    - by user1799842
    I have 1 table with tasks named opentask:columns: id,title,description,expires,creator_id,creator_name, executer_id, executer_name, priority_id, status_id1 table with users named user: with columns: user_id, username What I want is to create a query where there will be all columns from opentask table where the executer_id will be equal to the user_id of user table AND the creator_id will be equal to the user_id again. This creates a confusion because the first equality excludes the second.So I need somehow to create a query where I will include the usernames for the executer with something like where "opentask.executer_id=user_user_id" and at the same time I will include the username again (as a differend name?) for the creator with something like "where opentask.executer_id=user_user_id"So I try this, which of course I know that is missing something, can you help? SELECT DISTINCT id, title, description, expires, creator_id, executer_id, oc_opentask.priority_id, oc_opentask.status_id, priority_name, status_name, user_id, username, (SELECT username FROM oc_opentask, oc_user WHERE oc_opentask.creator_id=oc_user.user_id) AS username2 FROM oc_opentask, oc_opentask_priority, oc_user, oc_opentask_status WHERE oc_opentask.priority_id=oc_opentask_priority.priority_id AND oc_opentask.executer_id=oc_user.user_id AND oc_opentask.status_id=oc_opentask_status.status_id ORDER BY oc_opentask.expires DESC

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • Yes another ON DUPLICATE KEY UPDATE query

    - by Andy Gee
    I've been reading all the questions on here but I still don't get it I have two identical tables of considerable size. I would like to update table packages_sorted with data from packages_sorted_temp without destroying the existing data on packages_sorted Table packages_sorted_temp contains data on only 2 columns db_id and quality_rank Table packages_sorted contains data on all 35 columns but quality_rank is 0 The primary key on each table is db_id and this is what I want to trigger the ON DUPLICATE KEY UPDATE with. In essence how do I merge these two tables by and change packages_sorted.quality_rank of 0 to the quality_rank stored in packages_sorted_temp under the same primary key Here's what's not working INSERT INTO `packages_sorted` ( `db_id` , `quality_rank` ) SELECT `db_id` , `quality_rank` FROM `packages_sorted_temp` ON DUPLICATE KEY UPDATE `packages_sorted`.`db_id` = `packages_sorted`.`db_id`

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  • second time auto login to twitter using oauth php

    - by JAMES
    Any can tell me how to second time auto connect with twitter from my site. I did... the following CODE if(empty($outh_key_db)){ $token=$_SESSION['oauth_token'] ; $outh_secr_db=$_SESSION['oauth_token_secret']; $con = mysql_connect("localhost","rathin","xxxxxxxxx"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("my_twtbook", $con); mysql_query("UPDATE register SET outh_key = '".$token."', outh_secr='".$outh_secr_db."' WHERE userid='".$loguser_email."'"); mysql_close($con); This code save the outh_token and outh_tk_secret to my DB. But on second time log in to my site I passed the 'outh_token and outh_tk_secret' in session with username. The oauth not authenticate that.... Kindly suggest me.... to make aouth connect to twitter using oauth...if user once(1st time made the) connect twitter

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  • Want to save data field from form into two columns of two models.

    - by vette982
    I have a Profile model with a hasOne relationship to a Detail model. I have a registration form that saves data into both model's tables, but I want the username field from the profile model to be copied over to the usernamefield in the details model so that each has the same username. function new_account() { if(!empty($this->data)) { $this->Profile->modified = date("Y-m-d H:i:s"); if($this->Profile->save($this->data)) { $this->data['Detail']['profile_id'] = $this->Profile->id; $this->data['Detail']['username'] = $this->Profile->username; $this->Profile->Detail->save($this->data); $this->Session->setFlash('Your registration was successful.'); $this->redirect(array('action'=>'index')); } } } This code in my Profile controller gives me the error: Undefined property: Profile::$username Any ideas?

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  • ADOdv sanitizing queries

    - by pixel
    Just trying to make sure all my queries are sanitized. We're using ADOdb (it's already in place, so no talking me out of it). Is there something in ADOdb like mysql_real_escape_string?

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  • Convert multiquery to a query using group by and so on

    - by ffffff
    -schema CREATE TABLE `ratings` ( `id` int(11) NOT NULL default '0', `rating` int(11) NOT NULL default '1', `rating_start` datetime NOT NULL default '0000-00-00 00:00:00', PRIMARY KEY (`id`) ) TYPE=MyISAM -myprogram.php foreach($ids as $id){ $sql = "SELECT rating FROM ratings WHERE id = '$id' AND rating_start >= NOW()"; $sql .= "ORDER BY rating_start DESC LIMIT 1;" $ret = $db->execute($id); } Can I teke same date from a Query? by using id IN (".implode(",",$ids).") and GROUP BY id

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  • get value from database based on array in codeigniter

    - by Developer
    I have an array $user = array([0]=>1 [1]=>2 [2]=>3) which contains id's of certain users. I need to get the countries of these users from database. foreach($userid as $user){ $this->db->select('country'); $this->db->where('user_id',$user); $this->db->from('company'); $usercountry = $this->db->get(); $count = $usercountry->row(); $country = $count->country; } Suppose user1 has country ES, user2 has IN, user3 has US, user4 has UK. then if array contains 1,2,3. Then i need to get the countries ES,IN,US.

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  • Translate SQL statement into named_scope?

    - by keruilin
    How can I translate this SQL into a named_scope? Also, I want the total comments param to be passed through a lambda. "select users., count() as total_comments from users, comments where (users.id = comments.user_id) and (comments.public_comment = 1) and (comments.aasm_state = 'posted') and (comments.forum_user_id is null) group by users.id having total_comments 25"

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  • Can't select database table even though the code is right

    - by Lisa
    I am trying to display a list of my vbulliten threads on a non-vbulliten portion of my site. However I can't select the vbulliten database: <?php $host = "localhost"; $user = "my username"; $pass = "my password"; $dbname = "tableprefix_forum"; mysql_connect($host, $user, $pass) or die ("Could not connect to database server."); mysql_select_db($dbname) or die ("Could not select database."); ?> I am substituting some things here in this example but all my credentials are correct including my db server username, password and forum db name. So what is the problem? Is it due to some internal security feature in vbulliten, does this system not allow you to connect to it's db if the page trying to connect to it is a non-vbulliten page?

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  • Help converting subquery to query with joins

    - by Tim
    I'm stuck on a query with a join. The client's site is running mysql4, so a subquery isn't an option. My attempts to rewrite using a join aren't going too well. I need to select all of the contractors listed in the contractors table who are not in the contractors2label table with a given label ID & county ID. Yet, they might be listed in contractors2label with other label and county IDs. Table: contractors cID (primary, autonumber) company (varchar) ...etc... Table: contractors2label cID labelID countyID psID This query with a subquery works: SELECT company, contractors.cID FROM contractors WHERE contractors.complete = 1 AND contractors.archived = 0 AND contractors.cID NOT IN ( SELECT contractors2label.cID FROM contractors2label WHERE labelID <> 1 AND countyID <> 1 ) I thought this query with a join would be the equivalent, but it returns no results. A manual scan of the data shows I should get 34 rows, which is what the subquery above returns. SELECT company, contractors.cID FROM contractors LEFT OUTER JOIN contractors2label ON contractors.cID = contractors2label.cID WHERE contractors.complete = 1 AND contractors.archived = 0 AND contractors2label.labelID <> 1 AND contractors2label.countyID <> 1 AND contractors2label.cID IS NULL

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  • where to store information like gender and year of birth?

    - by fayer
    i have users and i need them to specify a gender (male, female) and year of birth (1930, 1931...1999, 2000). i wonder where i should store these values: in the database? in php file? if i store them in the database i have to manually create all entries first. but a good thing is that the user table will have constraints so the gender field will always be male or female, it cannot be something else. if i store them in the php file (eg. as html) then i can easily add/remove values. but a con is that i dont have the constraints in database, so another value could be stored as gender by mistake, even though i could add validation in php backend so even if someone hacked the html it is not stored unless it's either male or female. what is best practice to do this? thanks

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