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  • MySQL default value based on view

    - by Jake
    Basically I have a bunch of views based on a simple discriminator column (eg. CREATE VIEW tablename AS SELECT * FROM tablename WHERE discrcolumn = "discriminator value"). Upon inserting a new row into this view, it should insert "discriminator value" into discrcolumn. I tried this, but apparently MySQL doesn't figure this out itself, as it throws an error "Field of view viewname underlying table does not have a default value". The discriminator column is set to NOT NULL of course. How do I mend this? Perhaps a pre-insert trigger? UPDATE: Triggers won't work on views, see below comment. Would it work to create a trigger on the table which uses a variable, and set that variable at establishing the connection? For each connection the value of that variable would be the same, but it could differ from other connections. EDIT: This appears to work... Setup: CREATE TRIGGER insert_[tablename] BEFORE INSERT ON [tablename] FOR EACH ROW SET NEW.[discrcolumn] = @variable Runtime: SET @variable = [descrvalue]; INSERT INTO [viewname] ([columnlist]) VALUES ([values]);

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  • Accelerometer gravity components

    - by Dvd
    Hi, I know this question is definitely solved somewhere many times already, please enlighten me if you know of their existence, thanks. Quick rundown: I want to compute from a 3 axis accelerometer the gravity component on each of these 3 axes. I have used 2 axes free body diagrams to work out the accelerometer's gravity component in the world X-Z, Y-Z and X-Y axes. But the solution seems slightly off, it's acceptable for extreme cases when only 1 accelerometer axis is exposed to gravity, but for a pitch and roll of both 45 degrees, the combined total magnitude is greater than gravity (obtained by Xa^2+Ya^2+Za^2=g^2; Xa, Ya and Za are accelerometer readings in its X, Y and Z axis). More detail: The device is a Nexus One, and have a magnetic field sensor for azimuth, pitch and roll in addition to the 3-axis accelerometer. In the world's axis (with Z in the same direction as gravity, and either X or Y points to the north pole, don't think this matters much?), I assumed my device has a pitch (P) on the Y-Z axis, and a roll (R) on the X-Z axis. With that I used simple trig to get: Sin(R)=Ax/Gxz Cos(R)=Az/Gxz Tan(R)=Ax/Az There is another set for pitch, P. Now I defined gravity to have 3 components in the world's axis, a Gxz that is measurable only in the X-Z axis, a Gyz for Y-Z, and a Gxy for X-Y axis. Gxz^2+Gyz^2+Gxy^2=2*G^2 the 2G is because gravity is effectively included twice in this definition. Oh and the X-Y axis produce something more exotic... I'll explain if required later. From these equations I obtained a formula for Az, and removed the tan operations because I don't know how to handle tan90 calculations (it's infinity?). So my question is, anyone know whether I did this right/wrong or able to point me to the right direction? Thanks! Dvd

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  • Location of Embedly (JQuery-Preview) Results

    - by user749798
    Embedly/Jquery-Preview has been fantastic. However, I'm trying to change the location of the preview result, and having trouble. Right now, the result appears right below the input field...but I'd rather have it in a separate part of the page. Is there a way to do this? I've tried changing the location of the selector and loading divs, but that hasn't helped. It seems to ignore those divs and put it right below the submit button. Below is my code: <form accept-charset="UTF-8" action="private" class="new_comment" data-remote="true" id="new_comment" method="post"> <input class="photo_comm" id="comment_comment" name="comment[comment]" placeholder="add a comment or link..." size="30" type="text" /><span type="text" id="counter">1000</span> <input class="btn btn-primary btn-mini" data-disable-with="Submitting..." name="commit" type="submit" value="Post" /> </form> <!-- Placeholder that tells Preview where to put the loading icon--> <div class="loading"> <img src='http://embedly.github.com/jquery-preview/images/loading-rectangle.gif'> </div> <!-- Placeholder that tells Preview where to put the selector--> <div class="selector"></div> $('#comment_comment').preview({ key:'60f1dcdf3258476794784148a6eb65e7', // Sign up for a key: http://embed.ly/pricing selector : {type:'rich'}, preview : { submit : function(e, data){ e.preventDefault(); $.ajax({ dataType: 'script', url: this.form.attr('action'), type: 'POST', data: data }); }, }, autoplay : 0, maxwidth : 400, display : {display : 'rich'} });

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  • In a bidirectional JPA OneToMany/ManyToOne association, what is meant by "the inverse side of the as

    - by Bytecode Ninja
    In these examples on TopLink JPA Annotation Reference: Example 1-59 @OneToMany - Customer Class With Generics @Entity public class Customer implements Serializable { ... @OneToMany(cascade=ALL, mappedBy="customer") public Set<Order> getOrders() { return orders; } ... } Example 1-60 @ManyToOne - Order Class With Generics @Entity public class Order implements Serializable { ... @ManyToOne @JoinColumn(name="CUST_ID", nullable=false) public Customer getCustomer() { return customer; } ... } It seams to me that the Customer entity is the owner of the association. However, in the explanation for the mappedBy attribute in the same document, it is written that: if the relationship is bidirectional, then set the mappedBy element on the inverse (non-owning) side of the association to the name of the field or property that owns the relationship as Example 1-60 shows. However, if I am not wrong, looks like in the example the mappedBy is actually specified on the owning side of the association, rather than the non-owning side. So my question is basically: In a bidirectional (one-to-many/many-to-one) association, which of the entities is the owner? How can we designate the One side as the owner? How can we designate the Many side as the owner? What is meant by "the inverse side of the association"? How can we designate the One side as the inverse? How can we designate the Many side as the inverse? Thanks in advance.

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  • foreignkey problem

    - by realshadow
    Hey, Imagine you have this model: class Category(models.Model): node_id = models.IntegerField(primary_key = True) type_id = models.IntegerField(max_length = 20) parent_id = models.IntegerField(max_length = 20) sort_order = models.IntegerField(max_length = 20) name = models.CharField(max_length = 45) lft = models.IntegerField(max_length = 20) rgt = models.IntegerField(max_length = 20) depth = models.IntegerField(max_length = 20) added_on = models.DateTimeField(auto_now = True) updated_on = models.DateTimeField(auto_now = True) status = models.IntegerField(max_length = 20) node = models.ForeignKey(Category_info, verbose_name = 'Category_info', to_field = 'node_id' The important part is the foreignkey. When I try: Category.objects.filter(type_id = 15, parent_id = offset, status = 1) I get an error that get returned more than category, which is fine, because it is supposed to return more than one. But I want to filter the results trough another field, which would be type id (from the second Model) Here it is: class Category_info(models.Model): objtree_label_id = models.AutoField(primary_key = True) node_id = models.IntegerField(unique = True) language_id = models.IntegerField() label = models.CharField(max_length = 255) type_id = models.IntegerField() The type_id can be any number from 1 - 5. I am desparately trying to get only one result where the type_id would be number 1. Here is what I want in sql: SELECT c.*, ci.* FROM category c JOIN category_info ci ON (c.node_id = ci.node_id) WHERE c.type_id = 15 AND c.parent_id = 50 AND ci.type_id = 1 Any help is GREATLY appreciated. Regards

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  • Rails - eager load the number of associated records, but not the record themselves.

    - by Max Williams
    I have a page that's taking ages to render out. Half of the time (3 seconds) is spent on a .find call which has a bunch of eager-loaded associations. All i actually need is the number of associated records in each case, to display in a table: i don't need the actual records themselves. Is there a way to just eager load the count? Here's a simplified example: @subjects = Subject.find(:all, :include => [:questions]) In my table, for each row (ie each subject) i just show the values of the subject fields and the number of associated questions for each subject. Can i optimise the above find call to suit these requirements? I thought about using a group field but my full call has a few different associations included, with some second-order associations, so i don't think group by will work. @subjects = Subject.find(:all, :include => [{:questions => :tags}, {:quizzes => :tags}], :order => "subjects.name") :tags in this case is a second-order association, via taggings. Here's my associations in case it's not clear what's going on. Subject has_many :questions has_many :quizzes Question belongs_to :subject has_many :taggings has_many :tags, :through => :taggings Quiz belongs_to :subject has_many :taggings has_many :tags, :through => :taggings Grateful for any advice - max

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  • ASP.NET MVC Newbie: why isn't my model available when creating a strongly-typed view?

    - by Rax Olgud
    I'm starting with ASP.NET MVC, and working with NerdDinner as reference. I did the following: Created a new project Added a couple of tables Created LINQ to SQL for them Created a new controller My Models directory now contains MyModel.dbml, under which I have MyModel.designer.cs, that contains classes for models relating to both of my tables (let's call them Categories and Products). Now, under my new controller, I would like to create a strongly typed view. So for example I have the following code in my controller (for my application I must work by name, and the "Name" field is unique): public ActionResult Details(string name) { MyModelDataContext db = new MyModelDataContext(); Product user = db.Products.Single(t => t.Name == name); return View(user); } I would like to create a strongly-typed view. So I right-click the line "return View(user)", and choose "Add View...". I click "Create a strongly-typed view". When I click the dropdown of "View data class", I don't see my models, but only: MyProject.Controllers.AccountMembershipService MyProject.Controllers.FormsAuthenticationService What am I missing?

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  • SQLAlchemy - relationship limited on more than just the foreign key

    - by Marian
    I have a wiki db layout with Page and Revisions. Each Revision has a page_id referencing the Page, a page relationship to the referenced page; each Page has a all_revisions relationship to all its revisions. So far so common. But I want to implement different epochs for the pages: If a page was deleted and is recreated, the new revisions have a new epoch. To help find the correct revisions, each page has a current_epoch field. Now I want to provide a revisions relation on the page that only contains its revisions, but only those where the epochs match. This is what I've tried: revisions = relationship('Revision', primaryjoin = and_( 'Page.id == Revision.page_id', 'Page.current_epoch == Revision.epoch', ), foreign_keys=['Page.id', 'Page.current_epoch'] ) Full code (you may run that as it is) However this always raises ArgumentError: Could not determine relationship direction for primaryjoin condition ...`, I've tried all I had come to mind, it didn't work. What am I doing wrong? Is this a bad approach for doing this, how could it be done other than with a relationship?

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  • ASP.NET MVC editor template for property

    - by Idsa
    Usually I render my forms by @Html.RenderModel, but this time I have a complex rendering logic and I render it manually. I decided to create a editor template for one property. Here is the code (copy pasted from default object editor template implementation): <%@ Control Language="C#" Inherits="System.Web.Mvc.ViewUserControl" %> <% var modelMetadata = ViewData.ModelMetadata; %> <% if (modelMetadata.HideSurroundingHtml) { %> <%= Html.Editor(modelMetadata.PropertyName) %> <% } else { %> <% if (!String.IsNullOrEmpty(Html.Label(modelMetadata.PropertyName).ToHtmlString())) { %> <div class="editor-label"><%= Html.Label(modelMetadata.PropertyName) %></div> <% } %> <div class="editor-field"> <%= Html.Editor(modelMetadata.PropertyName) %> <%= Html.ValidationMessage(modelMetadata.PropertyName) %> </div> <% } %> And here is how I use it: @Html.EditorFor(x => x.SomeProperty, "Property") //"Property" is template above But it didn't work: labels are rendered regardless of DisplayName and editors are not rendered at all (in Watches Html.Editor(modelMetadata.PropertyName shows empty string). What am I doing wrong?

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  • Redirecting from an update action to the referrer of the edit

    - by Mark Westling
    My Rails 2.3 application has a User model and the usual controller actions. The edit form can be reached two ways: when a user edits his own profile from the home page, or when an admin user edits someone else's profile from users collection. What I'd like to do is have the update action redirect back to the referred of the edit action, not the update action. If I do a simple redirect_to(:back) within update, it goes back to the edit form -- not good. One solution is to forget entirely about referrers and redirect based on the current_user and the updated user: if they're the same, go back to the home page, else go to the users collection page. This will break if I ever add a third path to the edit form. It's doubtful I'll ever do this but I'd prefer a solution that's not so brittle. Another solution is to store the referrer of edit form in a hidden field and then redirect to this value from inside the update action. This doesn't feel quite right, though I can't explain why. Are there any better approaches? Or, should I stop worrying and go with one of the two I've mentioned?

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  • SQL UNION ALL with a INNER JOIN

    - by kOhm
    I'm looking for the best way to display all rows from two tables while joining first by one field (dwg) then where applicable a 2nd join on part. Table1 data consists of schematics(dwg) along with a list of parts required to build the item depicted in the drawing. Table2 consists of data about the actual parts ordered to build the schematic. Some parts in table2 are a combination of parts in table1 (ex: foo and bar in table1 were ordered as foobar in table2). I can display all rows in both tables with UNION ALL, but this doesn't join on both the dwg and part fields. I looked at FULL OUTER JOIN also, but I haven't figured out how to join first by dwg, then by part. Here is an example of the data. table1 table2 dwg part qty order dwg part qty ----- ----- ----- ----- ----- ----- ----- 123 foo 1 ord1 123 foobar 1 123 bar 1 ord1 123 bracket 2 123 widget 2 ord2 123 screw 4 123 bracket 4 ord2 123 nut 4 456 foo 1 ord2 123 widget 2 ord2 123 bracket 2 ord3 456 foo 1 Desired output: The goal is to create a view that provides visibility to all parts in table1 and the associated orders in table2 (including those parts that appear in one but not the other table) so that I can see all the drawing parts in table1 and the associated records in table2 along with records in table2 where the part wasn't in table1. part_request_order_report dwg part qty order part qty ----- ----- ----- ------ ----- ----- 123 foo 1 123 bar 1 123 widget 2 ord2 widget 2 123 bracket 4 ord1 bracket 2 123 bracket 4 ord2 bracket 2 123 ord1 foobar 1 123 ord1 screw 4 123 ord1 nut 4 456 foo 1 ord3 foo 1 Is this possible? Or am I better off iterating through the data to build the report table? Thanks in advance.

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  • How to build a Django form which requires a delay to be re-submitted ?

    - by pierre-guillaume-degans
    Hey, In order to avoid spamming, I would like to add a waiting time to re-submit a form (i.e. the user should wait a few seconds to submit the form, except the first time that this form is submitted). To do that, I added a timestamp to my form (and a security_hash field containing the timestamp plus the settings.SECRET_KEY which ensures that the timestamp is not fiddled with). This look like: class MyForm(forms.Form): timestamp = forms.IntegerField(widget=forms.HiddenInput) security_hash = forms.CharField(min_length=40, max_length=40, widget=forms.HiddenInput) # + some other fields.. # + methods to build the hash and to clean the timestamp... # (it is based on django.contrib.comments.forms.CommentSecurityForm) def clean_timestamp(self): """Make sure the delay is over (5 seconds).""" ts = self.cleaned_data["timestamp"] if not time.time() - ts > 5: raise forms.ValidationError("Timestamp check failed") return ts # etc... This works fine. However there is still an issue: the timestamp is checked the first time the form is submitted by the user, and I need to avoid this. Any idea to fix it ? Thank you ! :-)

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  • Unity IoC and MVC modelbinding

    - by danielovich
    Is it ok to have a static field in my controller for my modelbinder to call ? Eg. public class AuctionItemsController : Controller { private IRepository<IAuctionItem> GenericAuctionItemRepository; private IAuctionItemRepository AuctionItemRepository; public AuctionItemsController(IRepository<IAuctionItem> genericAuctionItemRepository, IAuctionItemRepository auctionItemRepository) { GenericAuctionItemRepository = genericAuctionItemRepository; AuctionItemRepository = auctionItemRepository; StaticGenericAuctionItemRepository = genericAuctionItemRepository; } internal static IRepository<IAuctionItem> StaticGenericAuctionItemRepository; here is the modelbinder public class AuctionItemModelBinder : DefaultModelBinder { public override object BindModel(ControllerContext controllerContext, ModelBindingContext bindingContext) { if (AuctionItemsController.StaticGenericAuctionItemRepository != null) { AuctionLogger.LogException(new Exception("controller is null")); } NameValueCollection form = controllerContext.HttpContext.Request.Form; var item = AuctionItemsController.StaticGenericAuctionItemRepository.GetSingle(Convert.ToInt32(controllerContext.RouteData.Values["id"])); item.Description = form["title"]; item.Price = int.Parse(form["price"]); item.Title = form["title"]; item.CreatedDate = DateTime.Now; item.AuctionId = 1; //TODO: Stop hardcoding this item.UserId = 1; return item; }} i am using Unity as IoC and I find it weird to register my modelbinder in the IoC container. Any other good design considerations I shold do ?

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  • SPWorkflowCollection on SPListItem is always empty

    - by armannvg
    Hi I'm having a problem relating to Sharepoint workflows and the associated task list. I have 2 custom workflows that we created for our product. They both use the same Task list that has a custom content type that inherits from the Task content type. Now I have a case where a running workflow has been deleted via the list has been deleted or the document, this results in orphaned tasks. I want to overwrite the Task lists OnDeleting event, so that users can cleanup their tasks so that it won't contain unneccessary orphaned tasks. So my item deleting looks like this public override void ItemDeleting(SPItemEventProperties properties) { SPListItem currentListItem = properties.ListItem; } The problem is that when I go into debug mode and check the currentListItem.Workflows.Count field then it's always 0. It doesn't matter which workflow I initiate or what task i look at, the SPWorkflowCollection returned is always empty :( I was wondering if this might be related to a bug in our custom workflow where it's not wired up properly (but it finishes correctly and tasks are deleted when a workflow is terminated) or am I looking at this the wrong way ?

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  • vb.net inline IF with OR... not evaluating

    - by rockinthesixstring
    I'm working on a small problem where I'm trying to show/hide a panel based on two criteria A specific data field must not be blank The specific data filed must also not equal "Not Relocatable" Unfortunately this doesn't seem to be working for me (note that setting either one or the other criteria works just fine.) <asp:Panel runat="server" Visible='<%#If(Not String.IsNullOrEmpty(DataBinder.Eval(Container.DataItem, "_236")) Or Not DataBinder.Eval(Container.DataItem, "_236") = "Not Relocatable", True, False)%>'> <tr> <td> </td> <td class="align-right lightgreen"> Buyer would consider relocating a business, if it is: </td> <td> </td> <td colspan="3"> <%#DataBinder.Eval(Container.DataItem, "_236")%> </td> <td> </td> </tr> </asp:Panel> Can anyone lend a hand to rectify this problem for me?

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  • C# : Forcing a clean run in a long running SQL reader loop?

    - by Wardy
    I have a SQL data reader that reads 2 columns from a sql db table. once it has done its bit it then starts again selecting another 2 columns. I would pull the whole lot in one go but that presents a whole other set of challenges. My problem is that the table contains a large amount of data (some 3 million rows or so) which makes working with the entire set a bit of a problem. I'm trying to validate the field values so i'm pulling the ID column then one of the other cols and running each value in the column through a validation pipeline where the results are stored in another database. My problem is that when the reader hits the end of handlin one column I need to force it to immediately clean up every little block of ram used as this process uses about 700MB and it has about 200 columns to go through. Without a full Garbage Collect I will definately run out of ram. Anyone got any ideas how I can do this? I'm using lots of small reusable objects, my thought was that I could just call GC.Collect() on the end of each read cycle and that would flush everything out, unfortunately that isn't happening for some reason.

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  • "The data types text and nvarchar are incompatible in the equal to operator" in SQL Query

    - by kenom
    Why i get this error: The data types text and nvarchar are incompatible in the equal to operator. The field of "username" in database is text type... This is my soruce: <%@ Control Language="C#" AutoEventWireup="true" CodeFile="my_answers.ascx.cs" Inherits="kontrole_login_my_answers" %> <div style=" margin-top:-1280px; float:left;"> <p></p> <div id="question"> Add question </div> </div> <asp:GridView ID="GridView1" runat="server" DataSourceID="SqlDataSource1" > </asp:GridView> <asp:SqlDataSource ID="SqlDataSource1" runat="server" ConnectionString="<%$ ConnectionStrings:estudent_piooConnectionString %>" SelectCommand="SELECT * FROM [question] WHERE ([username] = @fafa)"> <SelectParameters> <asp:QueryStringParameter Name="fafa" QueryStringField="user" Type="String"/> </SelectParameters> </asp:SqlDataSource>

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  • Method for defining simultaneous has-many and has-one associations between two models in CakePHP?

    - by Hobonium
    One thing with which I have long had problems, within the CakePHP framework, is defining simultaneous hasOne and hasMany relationships between two models. For example: BlogEntry hasMany Comment BlogEntry hasOne MostRecentComment (where MostRecentComment is the Comment with the most recent created field) Defining these relationships in the BlogEntry model properties is problematic. CakePHP's ORM implements a has-one relationship as an INNER JOIN, so as soon as there is more than one Comment, BlogEntry::find('all') calls return multiple results per BlogEntry. I've worked around these situations in the past in a few ways: Using a model callback (or, sometimes, even in the controller or view!), I've simulated a MostRecentComment with: $this->data['MostRecentComment'] = $this->data['Comment'][0]; This gets ugly fast if, say, I need to order the Comments any way other than by Comment.created. It also doesn't Cake's in-built pagination features to sort by MostRecentComment fields (e.g. sort BlogEntry results reverse-chronologically by MostRecentComment.created. Maintaining an additional foreign key, BlogEntry.most_recent_comment_id. This is annoying to maintain, and breaks Cake's ORM: the implication is BlogEntry belongsTo MostRecentComment. It works, but just looks...wrong. These solutions left much to be desired, so I sat down with this problem the other day, and worked on a better solution. I've posted my eventual solution below, but I'd be thrilled (and maybe just a little mortified) to discover there is some mind-blowingly simple solution that has escaped me this whole time. Or any other solution that meets my criteria: it must be able to sort by MostRecentComment fields at the Model::find level (ie. not just a massage of the results); it shouldn't require additional fields in the comments or blog_entries tables; it should respect the 'spirit' of the CakePHP ORM. (I'm also not sure the title of this question is as concise/informative as it could be.)

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  • What would you write in a consitution (law book) for a programmers' country?

    - by Developer Art
    After we have got our great place to talk about professional matters and sozialize online - on SO, I believe the next logical step would be to found our own country! I invite you all to participate and bring together your available resources. We will buy an island, better even a group of island so that we could establish states like .NET territories, Java land, Linux republic etc. We will build a society of programmers (girls - we need you too). To the organizational side, we're going to need some constitution or a law book. I suggest we write it together. I make it a wiki as it should be a cooperative effort. I'll open the work. Section 1. Programmers' rights. Every citizen has a right to an Internet connection 24/7. Every citizen can freely choose the field of interest Section 2. Programmers' obligations. Every citizen must embrace the changing nature of the profession and constanly educate himself Section 3. Law enforcement. Code duplication when can be avoided is punished by limiting the bandwith speed to 64Kbit for a period of one week. Using ugly hacks instead of refactoring code is punished by cutting the Internet connection for a period of one month. Usage of technologies older than 5/10 years is punished by restricting the web access to the sites last updated 5/10 years ago for a period of one month. Please feel free to modify and extend the list. We'll need to have it ready before we proceed formally with the country foundation. A purchase fund will be established shortly. Everyone is invited to participate.

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  • Adding a button or link to an inline in Django admin

    - by Lexo
    Hello, I have created the following django models: class Entry(SiteObject): parent = models.ForeignKey(Blog, related_name="entries") content = models.TextField(help_text = "The Content of the blog post") class EntryImage(models.Model): entry = models.ForeignKey(Entry, related_name="entryimages") imagewidth = models.PositiveIntegerField(editable=False,) imageheight = models.PositiveIntegerField(editable=False,) image_file = ImageWithThumbnailsField( #from sorl-thumbnail. Basically a wrapper for an ImageField that generates a thumbnail. upload_to="images/blogs", height_field="imageheight", width_field="imagewidth", help_text = "Select an image to upload.", thumbnail={'size': (360,720)}, generate_on_save=True, ) The EntryImage class shows up as an inline in the admin page for Entry. What I'd like to do is place a link or a button beside each of these inlines that does the following: Save the EntryImage Append <Image x> to the content of the Entry, where x is the number of the EntryImage. This will be replaced by the image's thumbnail using a template filter. Save the Entry Return to editing the Entry I have looked into this, but I just can't wrap my head around where I'm supposed to add this button or link. Has anyone else tried something similar? I've got JQuery available, since I'm using WYMEditor for the content field of the Entry class. Would this help? Thanks in advance, Lexo

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  • How to print contents from a session variable by looping in a foreach statement

    - by itsover9000
    im trying to write a code where can print and loop through the contents of my session variable by using a foreach statement here is my code <form class="form form-inline" method = "post" action="reportmaker.php"> <select name="rfield"> <option value="">--Select Field--</option> <?php $sc2=mysql_query("SELECT * from searchcolumn s left join report_fields r on s.scol_id=r.field_id where s.category != 'wh'"); foreach($sc2 as $sc){ ?> <option value="<?php echo $sc[advsearch_col]; ?>"><?php echo $sc[advsearch_name]; ?></option> <?php } ?> </select> <button type="submit" value = "submit" id="add" name="add" class="btn pull-right">Add More</button> </form> <?php if(isset($_POST['add'])) { $_SESSION['temp'][]=$_POST['rfield']; } if($_SESSION[temp][]!=""){ foreach($_SESSION[temp][] as $temp) { echo $temp; } } ?> the error that appears with this code is Fatal error: Cannot use [] for reading the line where the error is is this if($_SESSION[temp][]!=""){ i need to print the contents of the session array and this is the only way i know how is there a way to fix this? thanks =========EDIT thanks for the answers guys i finally got it

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  • Password Confirmation in zend framework

    - by Behrang
    I add this class to library/My/Validate/PasswordConfirmation.php <?php require_once 'Zend/Validate/Abstract.php'; class My_Validate_PasswordConfirmation extends Zend_Validate_Abstract { const NOT_MATCH = 'notMatch'; protected $_messageTemplates = array( self::NOT_MATCH => 'Password confirmation does not match' ); public function isValid($value, $context = null) { $value = (string) $value; $this->_setValue($value); if (is_array($context)) { if (isset($context['password']) && ($value == $context['password'])) { return true; } } elseif (is_string($context) && ($value == $context)) { return true; } $this->_error(self::NOT_MATCH); return false; } } ?> then I create two field in my form like this : $userPassword = $this->createElement('password', 'user_password'); $userPassword->setLabel('Password: '); $userPassword->setRequired('true'); $this->addElement($userPassword); //create the form elements user_password repeat $userPasswordRepeat = $this->createElement('password', 'password_confirm'); $userPasswordRepeat->setLabel('Password repeat: '); $userPasswordRepeat->setRequired('true'); $userPasswordRepeat->addPrefixPath('My_Validate','My/Validate','validate'); $userPasswordRepeat->addValidator('PasswordConfirmation'); $this->addElement($userPasswordRepeat) everything is good but when i submit form always I get the 'Password confirmation does not match' message ? What's Wrong in my code

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  • DB design for master file in enterprise software

    - by Thang Nguyen
    Dear all. I want to write an enterprise software and now I'm in the DB design phase. The software will have some master data such as Suppliers, Customers, Inventories, Bankers... I considering 2 options: Put each of these on one separate table. The advantage: the table will have all necessary information for that kind of master file (Customer: name, address,.../Inventory: Type, Manufacturer, Condition...). Disadvantage: Not flexible. When I want to have a new type of master data, such as Insurer, I have to design another table. Put all in one table and this table have foreign key to another table which have type of each kind of master data (table 1: id, data_type, code, name, address....; table 2: data_type, data_type_name). Advantage: flexible - if I want more master data such as Insurer, I just put in table 2: code: 002, name: Insurer, and then put detail each insurer into table 1). Disadvantage: table 1 must have sufficient field to store all kind of information including: customer name, address, account, inventory's manufacturer, inventory's quality...). So which method do you usually do (or you think work better). Thank you very much

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  • django: How to make one form from multiple models containing foreignkeys

    - by Tim
    I am trying to make a form on one page that uses multiple models. The models reference each other. I am having trouble getting the form to validate because I cant figure out how to get the id of two of the models used in the form into the form to validate it. I used a hidden key in the template but I cant figure out how to make it work in the views My code is below: views: def the_view(request, a_id,): if request.method == 'POST': b_form= BForm(request.POST) c_form =CForm(request.POST) print "post" if b_form.is_valid() and c_form.is_valid(): print "valid" b_form.save() c_form.save() return HttpResponseRedirect(reverse('myproj.pro.views.this_page')) else: b_form= BForm() c_form = CForm() b_ide = B.objects.get(pk=request.b_id) id_of_a = A.objects.get(pk=a_id) return render_to_response('myproj/a/c.html', {'b_form':b_form, 'c_form':c_form, 'id_of_a':id_of_a, 'b_id':b_ide }) models class A(models.Model): name = models.CharField(max_length=256, null=True, blank=True) classe = models.CharField(max_length=256, null=True, blank=True) def __str__(self): return self.name class B(models.Model): aid = models.ForeignKey(A, null=True, blank=True) number = models.IntegerField(max_length=1000) other_number = models.IntegerField(max_length=1000) class C(models.Model): bid = models.ForeignKey(B, null=False, blank=False) field_name = models.CharField(max_length=15) field_value = models.CharField(max_length=256, null=True, blank=True) forms from mappamundi.mappa.models import A, B, C class BForm(forms.ModelForm): class Meta: model = B exclude = ('aid',) class CForm(forms.ModelForm): class Meta: model = C exclude = ('bid',) B has a foreign key reference to A, C has a foreign key reference to B. Since the models are related, I want to have the forms for them on one page, 1 submit button. Since I need to fill out fields for the forms for B and C & I dont want to select the id of B from a drop down list, I need to somehow get the id of the B form into the form so it will validate. I have a hidden field in the template, I just need to figure how to do it in the views

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  • Reverse search in Hibernate Search

    - by Javi
    Hello, I'm using Hibernate Search (which uses Lucene) for searching some Data I have indexed in a directory. It works fine but I need to do a reverse search. By reverse search I mean that I have a list of queries stored in my database I need to check which one of these queries match with a Data object each time Data Object is created. I need it to alert the user when a Data Object matches with a Query he has created. So I need to index this single Data Object which has just been created and see which queries of my list has this object as a result. I've seen Lucene MemoryIndex Class to create an index in memory so I can do something like this example for every query in a list (though iterating in a Java list of queries would not be very efficient): //Iterating over my list<Query> MemoryIndex index = new MemoryIndex(); //Add all fields index.addField("myField", "myFieldData", analyzer); ... QueryParser parser = new QueryParser("myField", analyzer); float score = index.search(query); if (score > 0.0f) { System.out.println("it's a match"); } else { System.out.println("no match found"); } The problem here is that this Data Class has several Hibernate Search Annotations @Field,@IndexedEmbedded,... which indicated how fields should be indexed, so when I invoke index() method on the FullTextEntityManager instance it uses this information to index the object in the directory. Is there a similar way to index it in memory using this information? Is there a more efficient way of doing this reverse search? Thanks

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