Search Results

Search found 34195 results on 1368 pages for 'try'.

Page 410/1368 | < Previous Page | 406 407 408 409 410 411 412 413 414 415 416 417  | Next Page >

  • Is there a way to prevent UIImagePickerController change statusbar style?

    - by Eonil
    UIImagePickerController changes statusbar style to black/opaque. I want to keep status-bar style black/translucent. I'm finding a way to prevent status bar style changing. Or making it transited smoothly. Now, presenting UIImagePickerController changes status-bar style instantly, even -[presentModalViewController:picker animated:YES] specified. Any method, welcome, including hacking or private method. This is an app for AppStore, however I want to even try.

    Read the article

  • Timer Job from a SPWeb

    - by Faiz
    Hi, I guess starting a timer job from within the code required Farm admin credetials. However, i need to start a timer job from a web part that will be used in any site. Now when i try to start the job it gives me access denied error and obviously so as app pool identity is not farm admin. Any ideas on how to resolve this issue? Thanks,

    Read the article

  • Vim error E492: Not an editor command: dd

    - by Roberts Jameson
    I started learning vim today and installed it using sudo apt-get install vim Now, when I try to do something like :5dd it gives me the not an editor command error. I'm not sure why this is. Am I doing anything wrong? I looked at tutorials and everywhere I look I see that 5dd is a valid command.

    Read the article

  • Emulating Button Press Using Kinect/SimpleOpenNI + Processing Depth

    - by Alex Lu
    I am using Kinect with Simple OpenNI and Processing, and I was trying to use the Z position of a hand to emulate a button press. So far when I try it using one hand it works really well, however, when I try to get it to work with a second hand, only one of the hands work. (I know it can be more efficient by moving everything except the fill out of the if statements, but I kept those in there just in case I want to change the sizes or something.) irz and ilz are the initial Z positions of the hands when they are first recognized by onCreateHands and rz and lz are the current Z positions. As of now, the code works fine with one hand, but the other hand will either stay pressed or unpressed. If i comment one of the sections out, it works fine as well. if (rz - irz > 0) { pushStyle(); fill(60); ellipse(rx, ry, 10, 10); popStyle(); rpressed = true; } else { pushStyle(); noFill(); ellipse(rx, ry, 10, 10); popStyle(); rpressed = false; } if (lz - ilz > 0) { pushStyle(); fill(60); ellipse(lx, ly, 10, 10); popStyle(); lpressed = true; } else { pushStyle(); noFill(); ellipse(lx, ly, 10, 10); popStyle(); lpressed = false; } I tried outputting the values of rz - irz and lz - ilz and the numbers range from small negative values to small positive values (around -8 to 8) for lz - ilz. But rz - irz outputs numbers from around 8-30 depending on each time I run it and is never consistent. Also, when I comment out the code for the lz-ilz, the values for rz-irz look just fine and it operates as intended. Is there a reason tracking both Z positions throws off one hand? And is there a way to get it to work? Thanks!

    Read the article

  • Creating a console in Java

    - by DeadMG
    When I try to use java.lang.System.console(), I get a null pointer. I can still write to out and read from in, but this only works when I run straight from my IDE. When I run the .jar file directly, nothing happens. How can I create a console like I'd see using std::cout for use in Java?

    Read the article

  • Python urllib.urlopen() call doesn't work with a URL that a browser accepts

    - by Charles Anderson
    If I point Firefox at http://bitbucket.org/tortoisehg/stable/wiki/Home/ReleaseNotes, I get a page of HTML. But if I try this in Python: import urllib site = 'http://bitbucket.org/tortoisehg/stable/wiki/Home/ReleaseNotes' req = urllib.urlopen(site) text = req.read() I get the following: 500 Internal Server Error The server encountered an internal error or misconfiguration and was unable to complete your request. What am I doing wrong?

    Read the article

  • List of web-based interpreters of various programming languages

    - by Bolo
    Let's say you're away from your computer and all you've got is a web browser. You'd still like to run a piece of code (e.g. to check an answer on SO). What are your options? Let's create a list of on-line interpreters of various programming languages. Here are some examples: Python: http://try-python.mired.org/ Haskell: http://tryhaskell.org/ Scala: http://www.simplyscala.com/ Many languages: http://ideone.com/ Many languages: http://codepad.org/

    Read the article

  • collection_check_boxes get value

    - by 24sharon
    this is my view code <%=collection_check_boxes(nil, :admin_ids, Admin.all, :id, :name )%> but when i try get the value in the controller i get always an empty value if the user doesnt check any item and the length is always more than zero when i write this code arr = params[:admin_ids] ||= [] puts arr.length ther arr.length is 1 even if the user doesnt select any of the items how can i get an array of selected items only with no empty values

    Read the article

  • how to login in google account with app engine webproxy

    - by user313446
    hi,a webproxy on app engine oncyberspace.appspot.com , save cookie in the database, when i try to login in the google with my account, it redirect to google.com . how to solve these problem ? and another problem , when i this the above web to login in twitter,it works !but i can not use it to update my tweet. i don't know why, may be i can't pass oauth . how to solve this ?

    Read the article

  • Changing scaling of MATLAB Figure

    - by Phil
    I have a figure that displays 20,000 points on the x-axis. So it labels the x-axis from 0 ... 20,000. However, now I would like to scale it from 0 to 50. But when I try to do this in the plot window it just shows me the first 50 points, instead of changing the scale. Is there any straightforward way to do that in MATLAB?

    Read the article

  • Alert on gridview edit based on permission

    - by Vicky
    I have a gridview with edit option at the start of the row. Also I maintain a seperate table called Permission where I maintain user permissions. I have three different types of permissions like Admin, Leads, Programmers. These all three will have access to the gridview. Except admin if anyone tries to edit the gridview on clicking the edit option, I need to give an alert like This row has important validation and make sure you make proper changes. When I edit, the action with happen on table called Application. The table has a column called Comments. Also the alert should happen only when they try to edit rows where the Comments column have these values in them. ManLog datas Funding Approved Exported Applications My try so far. public bool IsApplicationUser(string userName) { return CheckUser(userName); } public static bool CheckUser(string userName) { string CS = ConfigurationManager.ConnectionStrings["ConnectionString"].ToString(); DataTable dt = new DataTable(); using (SqlConnection connection = new SqlConnection(CS)) { SqlCommand command = new SqlCommand(); command.Connection = connection; string strquery = "select * from Permissions where AppCode='Nest' and UserID = '" + userName + "'"; SqlCommand cmd = new SqlCommand(strquery, connection); SqlDataAdapter da = new SqlDataAdapter(cmd); da.Fill(dt); } if (dt.Rows.Count >= 1) return true; else return true; } protected void Details_RowCommand(object sender, GridViewCommandEventArgs e) { string currentUser = HttpContext.Current.Request.LogonUserIdentity.Name; string str = ConfigurationManager.ConnectionStrings["ConnectionString"].ToString(); string[] words = currentUser.Split('\\'); currentUser = words[1]; bool appuser = IsApplicationUser(currentUser); if (appuser) { DataSet ds = new DataSet(); using (SqlConnection connection = new SqlConnection(str)) { SqlCommand command = new SqlCommand(); command.Connection = connection; string strquery = "select Role_Cd from User_Role where AppCode='PM' and UserID = '" + currentUser + "'"; SqlCommand cmd = new SqlCommand(strquery, connection); SqlDataAdapter da = new SqlDataAdapter(cmd); da.Fill(ds); } if (e.CommandName.Equals("Edit") && ds.Tables[0].Rows[0]["Role_Cd"].ToString().Trim() != "ADMIN") { int index = Convert.ToInt32(e.CommandArgument); GridView gvCurrentGrid = (GridView)sender; GridViewRow row = gvCurrentGrid.Rows[index]; string strID = ((Label)row.FindControl("lblID")).Text; string strAppName = ((Label)row.FindControl("lblAppName")).Text; Response.Redirect("AddApplication.aspx?ID=" + strID + "&AppName=" + strAppName + "&Edit=True"); } } } Kindly let me know if I need to add something. Thanks for any suggestions.

    Read the article

  • Increasing your efficiency during programming

    - by Tom
    Yeah, yeah, I know, it is a little bit of offtopic, but let's try. So, I want to increase my efficiency during my programming as much as possible to programme as fast and sensibly as possiblle. What do you do before starting coding? Drink a lot of coffee, energy drinks? Do you listen to music during programming or you keep quite? Share your ideas.

    Read the article

  • Using the slash character in Git branch name

    - by faB
    I'm pretty sure I saw somewhere in a popular Git project the branches had a pattern like "feature/xyz". However when I try to create a branch with the slash character, I get an error: $ git branch foo/bar error: unable to resolve reference refs/heads/labs/feature: Not a directory fatal: Failed to lock ref for update: Not a directory Same problem for (my initial attempt): $ git checkout -b foo/bar How does one create a branch in Git with the slash character?

    Read the article

  • Advanced count and join in Rails

    - by trobrock
    I am try to find the top n number of categories as they relate to articles, there is a habtm relationship set up between the two. This is the SQL I want to execute, but am unsure of how to do this with ActiveRecord, aside from using the find_by_sql method. is there any way of doing this with ActiveRecord methods: SELECT "categories".id, "categories".name, count("articles".id) as counter FROM "categories" JOIN "articles_categories" ON "articles_categories".category_id = "categories".id JOIN "articles" ON "articles".id = "articles_categories".article_id GROUP BY "categories".id ORDER BY counter DESC LIMIT 5;

    Read the article

  • Automatic authentication in PHPMyAdmin

    - by Konstantin
    Hello! I have a local phpMyAdmin (installed via apt-get) adn I'm tired of entering login and password every time I try to open it. Database contains no sensitive info, just test tables, and is visible only from 127.0.0.1 I want phpMyAdmin already be logged in as root user with password 1234 (for example) when I open it. How do I do that? P.S. Saving password in a browser is not what I want.

    Read the article

  • Convert Subclass to Inherited Class

    - by Dave
    I have a C# .NET 2.0 project A that has a form (TreeForm) that uses Tree objects. I have a project B that has a class Oak that inherits Tree. When I try to reference and use the TreeForm in project B with my Oak objects, it's looking for objects of type Tree. I've tried casting the Oak objects to Tree, but I get the error "Cannot convert type Oak to Tree". How can I use my Oak objects in the TreeForm from project A?

    Read the article

  • iPhone "touchesBegan" and "touchesMoved" message ... do not move to centre of touch

    - by Nippysaurus
    I am modifying the "MoveMe" example from the apple web site. When I get the "touchesMoved" message I move the centre of the target view to the centre of the touch. Is there a way that when the touch starts ("touchesBegan" message) I can remember the offset from the target view and keep that offset. Let me know if this is hard to understand and I will try to explain it a bit better.

    Read the article

  • Init Startup of Tomcat

    - by azoor
    Hi I put a init script into /etc/init.d to startup the Apache-tomcat. when i'm reboot the machine. i think the Tomcat try to start and aborted in some level. i am using Ubuntu 9.04. my guessing is the given time to start the tomcat is not enough. if any way have to increase the time to execute a script in startup.

    Read the article

< Previous Page | 406 407 408 409 410 411 412 413 414 415 416 417  | Next Page >