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  • Sql Query to get total rows and total rows matching specific condition

    - by mrNepal
    OK, Here is what my table looks like ------------------------------------------------ id type ----------------------------------------------- 1 a 2 b 3 a 4 c 5 c 7 a 8 a ------------------------------------------------ Now, I need a query that can give me this output... ----------------------------------------------------------------- count(*) | count(type=a) | count(type=b) | count(type=c) ----------------------------------------------------------------- 8 4 1 3 ------------------------------------------------------------------ I only know to get the total set using count(*), but how to do the remaining

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  • Are Conditional subquery

    - by Tobias Schulte
    I have a table foo and a table bar, where each foo might have a bar (and a bar might belong to multiple foos). Now I need to select all foos with a bar. My sql looks like this SELECT * FROM foo f WHERE [...] AND ($param IS NULL OR (SELECT ((COUNT(*))>0) FROM bar b WHERE f.bar = b.id)) with $param being replaced at runtime. The question is: Will the subquery be executed even if param is null, or will the dbms optimize the subquery out?

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  • Keeping some choices in the Table for the Field of Type Dropdown

    - by Mercy
    Hi, i am having a Table named Attributes which has id form_id label size sequence_no Type 1 1 Name 200 1 Text 2 1 Age 150 2 Number 3 1 Address 300 3 Textarea 4 1 Gender 200 4 Dropdown I am having the doubt how can i keep the Choices of the Field of type "Dropdown" in the Table Eg. For Gender the choices will Male , Female.. Please give me the suggestions...

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  • Select statement that combines similar rows with certain ids?

    - by vegatron
    hi I have a warehouse_products table which defines how many products in the warehouses so lets say I have 20 records/rows in the table, some rows may contain the same product id but in a different warehouse I need to create select statement that give every product one row, and in this row I must have the quantity in warehouse A and warehouse B .. so in the end I will get for example 10 rows that contain all the data

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  • The explain tells that the query is awful (it doesn't use a single key) but I'm using LIMIT 1. Is th

    - by Ricardo
    The explain command with the query: explain SELECT * FROM leituras WHERE categorias_id=75 AND textos_id=190304 AND cookie='3f203349ce5ad3c67770ebc882927646' AND endereco_ip='127.0.0.1' LIMIT 1 The result: id select_type table type possible_keys key key_len ref rows Extra 1 SIMPLE leituras ALL (null) (null) (null) (null) 1022597 Using where Will it make any difference adding some keys on the table? Even that the query will always return only one row.

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  • Table format for Click stats

    - by Francesc
    Hello. I'm currently developing an URL shortening service. I want to allow users to see the stats for their URLs. How has to be the table. First, it has to be the url ID, but then, how I can sort the clicks per day?

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  • sql query without subquery

    - by user1285737
    I need to rewrite this query and I'm not allowed to use a subquery. I need to select the name and color of the parts that are heavier than the wheel. SELECT name, color FROM parts WHERE weight > (SELECT weight FROM parts WHERE name="wheel"); This is the table: PARTS ID NAME COLOR WEIGHT 1 wheel black 100 2 tire black 50 3 gear red 20 Thanks in advance

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  • php database image show problem

    - by Termedi
    here is the code <?php session_start(); if(!isset($_SESSION['user_name'])) { header('Location: login.php'); } $conn = mysql_connect("localhost", "root", "") or die("Can no connect to Database Server"); ?> <html> <head> </head> <body> <center> <div id="ser"> <form action="" method="post"> <label for="file">Card No:</label> <input type="text" name="card_no" id="card_no" class="fil" onKeyUp="CardNoLength()" onKeyDown="CardNoLength()" onKeyPress="CardNoLength()"/> <input type="submit" name="search" value="Search" class="btn" onClick="return CardNoLengthMIN()"/> </form> </div> </center> <br/><hr style="border: 1px solid #606060 ;" /> <center><a href="index.php">Home</a></center> <br/> <center> <?php if(isset($_POST['card_no'])) { if($conn) { if(mysql_select_db("img_mgmt", $conn)) { $sql = "select * from temp_images where card_no='".trim($_POST['card_no'])."'"; $result = mysql_query($sql); $image = mysql_fetch_array($result); if(isset($image['card_no'])) { //echo "<img src=\"".$image['file_path']."\" alt=\"".$image['card_no']."\" width=\"250\" height=\"280\"/>"; header("Content-type: image/jpeg"); echo $image['img_content']; } else { echo "<p style=\"color:red;\">Sorry, Your search came with no results ! <br/> Try with different card number"; } } else { echo "Database selection error: ".mysql_error(); } } else { echo "Could not connect: ".mysql_error(); } } ?> </center> </body> </html> But it after executing the script it shows: Cannot modify header information - headers already sent by (output started at C:\xampp\htdocs\img\search.php:61) in C:\xampp\htdocs\img\search.php on line 77

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  • Selecting first records of a type in a given period

    - by Emanuil Rusev
    I have a database table that stores user comments: comments(id, user_id, created_at) I want to get from it the number of users that have commented for the first time in the past week. Here's what I have so far: SELECT COUNT(DISTINCT `user_id`) FROM `comments` WHERE `created_at` BETWEEN DATE_SUB(NOW(), INTERVAL 7 DAY) AND NOW() This would give the number of users that have commented, but it would not take into consideration whether these comments are first for these users.

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  • Save phone calls data in a DB?

    - by Alex
    How would you save this data on a database: An user can make phone calls (id, date, hour, duration, outcome). The "outcome" can be, for example, to recall the client on another day (so I have to save the date, the hour, etc of this "future" call). How would you manage this data on a db? At the moment i have only a "Call" table.

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  • Help needed to construct a SQL query

    - by song202y
    Need your help to get the list of suggested friends (who aren't friends of the current user but are friends of 2 or more of the current user's friends). The primary ordering should put people at the same school at the top, and the secondary ordering should put people with more common friends (that is, the number of people who are friends of that person and the current user) near the top. Users: user_id PK, user_name Profiles: user_id PK, school_name, ... Friendships: id PK, user_id FK, friend_id FK Thank you in advance. Joe

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  • All is working except if($_POST['submit']=='Update')

    - by user1319909
    I have a working registration and login system. I am trying to create a form where a user can add product registration info (via mysql update). I can't seem to get the db to actually update the fields. What am I missing here?!? <?php define('INCLUDE_CHECK',true); require 'connect.php'; require 'functions.php'; // Those two files can be included only if INCLUDE_CHECK is defined session_name('tzLogin'); // Starting the session session_set_cookie_params(2*7*24*60*60); // Making the cookie live for 2 weeks session_start(); if($_SESSION['id'] && !isset($_COOKIE['tzRemember']) && !$_SESSION['rememberMe']) { // If you are logged in, but you don't have the tzRemember cookie (browser restart) // and you have not checked the rememberMe checkbox: $_SESSION = array(); session_destroy(); // Destroy the session } if(isset($_GET['logoff'])) { $_SESSION = array(); session_destroy(); header("Location: index_login3.php"); exit; } if($_POST['submit']=='Login') { // Checking whether the Login form has been submitted $err = array(); // Will hold our errors if(!$_POST['username'] || !$_POST['password']) $err[] = 'All the fields must be filled in!'; if(!count($err)) { $_POST['username'] = mysql_real_escape_string($_POST['username']); $_POST['password'] = mysql_real_escape_string($_POST['password']); $_POST['rememberMe'] = (int)$_POST['rememberMe']; // Escaping all input data $row = mysql_fetch_assoc(mysql_query("SELECT * FROM electrix_users WHERE usr='{$_POST['username']}' AND pass='".md5($_POST['password'])."'")); if($row['usr']) { // If everything is OK login $_SESSION['usr']=$row['usr']; $_SESSION['id'] = $row['id']; $_SESSION['email'] = $row['email']; $_SESSION['first'] = $row['first']; $_SESSION['last'] = $row['last']; $_SESSION['address1'] = $row['address1']; $_SESSION['address2'] = $row['address2']; $_SESSION['city'] = $row['city']; $_SESSION['state'] = $row['state']; $_SESSION['zip'] = $row['zip']; $_SESSION['country'] = $row['country']; $_SESSION['product1'] = $row['product1']; $_SESSION['serial1'] = $row['serial1']; $_SESSION['product2'] = $row['product2']; $_SESSION['serial2'] = $row['serial2']; $_SESSION['product3'] = $row['product3']; $_SESSION['serial3'] = $row['serial3']; $_SESSION['rememberMe'] = $_POST['rememberMe']; // Store some data in the session setcookie('tzRemember',$_POST['rememberMe']); } else $err[]='Wrong username and/or password!'; } if($err) $_SESSION['msg']['login-err'] = implode('<br />',$err); // Save the error messages in the session header("Location: index_login3.php"); exit; } else if($_POST['submit']=='Register') { // If the Register form has been submitted $err = array(); if(strlen($_POST['username'])<4 || strlen($_POST['username'])>32) { $err[]='Your username must be between 3 and 32 characters!'; } if(preg_match('/[^a-z0-9\-\_\.]+/i',$_POST['username'])) { $err[]='Your username contains invalid characters!'; } if(!checkEmail($_POST['email'])) { $err[]='Your email is not valid!'; } if(!count($err)) { // If there are no errors $pass = substr(md5($_SERVER['REMOTE_ADDR'].microtime().rand(1,100000)),0,6); // Generate a random password $_POST['email'] = mysql_real_escape_string($_POST['email']); $_POST['username'] = mysql_real_escape_string($_POST['username']); $_POST['first'] = mysql_real_escape_string($_POST['first']); $_POST['last'] = mysql_real_escape_string($_POST['last']); $_POST['address1'] = mysql_real_escape_string($_POST['address1']); $_POST['address2'] = mysql_real_escape_string($_POST['address2']); $_POST['city'] = mysql_real_escape_string($_POST['city']); $_POST['state'] = mysql_real_escape_string($_POST['state']); $_POST['zip'] = mysql_real_escape_string($_POST['zip']); $_POST['country'] = mysql_real_escape_string($_POST['country']); // Escape the input data mysql_query(" INSERT INTO electrix_users(usr,pass,email,first,last,address1,address2,city,state,zip,country,regIP,dt) VALUES( '".$_POST['username']."', '".md5($pass)."', '".$_POST['email']."', '".$_POST['first']."', '".$_POST['last']."', '".$_POST['address1']."', '".$_POST['address2']."', '".$_POST['city']."', '".$_POST['state']."', '".$_POST['zip']."', '".$_POST['country']."', '".$_SERVER['REMOTE_ADDR']."', NOW() )"); if(mysql_affected_rows($link)==1) { send_mail( '[email protected]', $_POST['email'], 'Your New Electrix User Password', 'Thank you for registering at www.electrixpro.com. Your password is: '.$pass); $_SESSION['msg']['reg-success']='We sent you an email with your new password!'; } else $err[]='This username is already taken!'; } if(count($err)) { $_SESSION['msg']['reg-err'] = implode('<br />',$err); } header("Location: index_login3.php"); exit; } if($_POST['submit']=='Update') { { mysql_query(" UPDATE electrix_users(product1,serial1,product2,serial2,product3,serial3) WHERE usr='{$_POST['username']}' VALUES( '".$_POST['product1']."', '".$_POST['serial1']."', '".$_POST['product2']."', '".$_POST['serial2']."', '".$_POST['product3']."', '".$_POST['serial3']."', )"); if(mysql_affected_rows($link)==1) { $_SESSION['msg']['upd-success']='Thank you for registering your Electrix product'; } else $err[]='So Sad!'; } if(count($err)) { $_SESSION['msg']['upd-err'] = implode('<br />',$err); } header("Location: index_login3.php"); exit; } if($_SESSION['msg']) { // The script below shows the sliding panel on page load $script = ' <script type="text/javascript"> $(function(){ $("div#panel").show(); $("#toggle a").toggle(); }); </script>'; } ?>

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  • need an sql query

    - by CKeven
    I currently have two tables: 1. car(plate_number, brand, cid) 2. borrow(StartDate, endDate, brand, id) I want to write a query to get all available brand and count of available cars for each brand

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  • chained selects with one table

    - by Owen
    I know I am going about this in an unusual way, every tut I've seen uses multiple tables, but due to the way the rest of my site works I would like to create a chained select which operates using a single table. My table structure is: ---------------------- |Catagory|SubCategory| |01|cat1 |subcat1 | |02|cat1 |subcat2 | |03|cat2 |subcat1 | |04|cat2 |subcat2 | ---------------------- The code I have so far looks like: <tr> <td class="shadow"><strong>Category:</strong> </td> <td class="shadow"> <select id="category" name="category" style="width:150px"> <option selected="selected" value="<?php echo $category ?>"><?php echo $category?></option> <?php include('connect.php'); $result1 = mysql_query("SELECT DISTINCT category FROM categories") or die(mysql_error()); while($row = mysql_fetch_array( $result1 )) { $category = $row['category']; echo "<option value='". $row['category'] ."'>". $row['category'] ."</option>"; } ?> </select> </td> </tr> <tr> <td class="shadow"><strong>Sub Category:</strong> </td> <td class="shadow"> <select id="sub_catgory" name="sub_category" style="width:150px;"> <option selected="selected" value="<?php echo $sub_category ?>"><?php echo $sub_category ?></option> <?php include('connect.php'); $result2 = mysql_query("SELECT sub_category FROM categories WHERE ") or die(mysql_error()); while($row = mysql_fetch_array ($result2 )){ echo "<option value='" . $row['sub_category'] . "'>". $row['sub_category']. "</option>"; } ?> </select> </td> </tr> On the second select I am not sure how to state the WHERE clause. I need it to display the subcategories which have the same category as selected in the first select. PART 2 how would I include AJAX in this to preload the data so i don't need to refresh the page. Could someone either help me finish what I've started here or point me to a good tutorial. thanks

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  • SQL query joining rows with same value

    - by user1285737
    I need to write a query that creates a view that calculates the total cost of each sale, by considering quantity and price of each bought item. The view should return the debit and total cost. In the answer each debit-number should only occur once. Thanks in advance Table ITEM: ID NAME PRICE 118 Jeans 100 120 Towel 20 127 Shirt 55 Table DEBIT: DEBIT ITEM Quantity 100581 118 5 100581 120 1 100586 127 5

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  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

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  • Autopopulate from Select box from database

    - by Chris Spalton
    hope you can help, please forgive any poor coding or anytihng, I'm new to this and just hacking my way through to get things to work. That said, on one of my projects I have this code, which successfully populates the dropdown from a database when the page is loaded: <select name="Region" id="Region"> <option value="">-- Select Region --</option> <?php $region=$POST['Region']; if ($region); { $regionquery = "SELECT DISTINCT REGION FROM Sales_Execs "; $regionresult = mysql_query($regionquery); while($row = mysql_fetch_array($regionresult)) { echo "<option value=\"".$row['REGION']."\">".$row['REGION']."</option>\n "; } } ?> <script type="text/javascript"> document.getElementById('Region').value = <?php echo json_encode(trim($_POST['Region']));?>; </script> </select> On my next project that I'm working on now, I need to do the same thing, so I copied the above code amended, and placed in my new project: <select name="Sales_Exec" id="Sales_Exec"> <option value="">-- Select SE --</option> <?php $salesexec=$POST['Sales_Exec']; if ($salesexec); { $salesexecquery = "SELECT DISTINCT Assigned FROM Data "; $salesexecresult = mysql_query($salesexecquery); while($row = mysql_fetch_array($salesexecresult)) { echo "<option value=\"".$row['ASSIGNED']."\">".$row['ASSIGNED']."</option>\n "; } } ?> <script type="text/javascript"> document.getElementById('Sales_Exec').value = <?php echo json_encode(trim($_POST['Sales_Exec']));?>; </script> </select> This second chunk of code doesn't work... and I can't work out why as it seems I've copied it all and amended all the neccersary parts, can anyone spot what is wrong? Thankyou!

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  • How to put comma in counted numbers?

    - by Ronnie Chester Lynwood
    hey huys im counting my table with this code: $county = mysql_query("SELECT COUNT(id) from table where type = 'application'"); $county = mysql_result($county, 0); $applications = ''.$county.''; this give me result like 1156563. but I want to see it like 1,156,563 with commas. how can i do this?

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  • How to get a list of unrepeatable date from my db in PHP?

    - by SzamDev
    Hi in my db there are 5 fields (id, list_date, amount, total, m_from) and contain data, for example : 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/4/2010 - 10 - 50 - 'example154 1 - 1/1/2010 - 10 - 50 - 'example111' 1 - 1/5/2010 - 10 - 50 - 'test' I need to know how I can get dates from list_date but without repeatable dates like '1/1/2010, 1/5/2010, 1/4/2010' Thanks in Advance.

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  • Is possible use 'div id' as name of array?

    - by rflfn
    Please view this jsfiddle jsfiddle.net/rflfn/uS4jd/ This is other try jsfiddle.net/rflfn/T3ZT6/ I'm using SMOF to developper Wordpress theme, I need make one function to change some values when link is clicked, but when I make array with name of div, the array returns null value... <a class="button" id="settext1">Some Link</a> <br /> <a class="button" id="settext2">Another Link</a> <br /> <a class="button" id="settext3">Link 3</a> <br /> JQ: $(document).ready(function(){ // var col_settext1 = new Array(); // <-- I need make this array with name of DIV cliked col_settext1['field_id1']='#FF0000'; col_settext1['field_id2']='#00FFFF'; // var txt_settext1 = new Array(); // <-- I need make this array with name of DIV cliked txt_settext1['field_id3']='Some Text Here'; txt_settext1['field_id4']='Another Text Here'; // var txt_settext2 = new Array(); // <-- I need make this array with name of DIV cliked txt_settext2['field_id5']='Some Text Here'; // var col_settext2 = new Array(); // <-- I need make this array with name of DIV cliked col_settext2['field_id6']='Another Text Here'; // var chk_settext2 = new Array(); // <-- I need make this array with name of DIV cliked chk_settext2['field_id7']="checked"; }); $('.button').click(function(){ $myclass = this.id; $col = 'col_' + $myclass; $txt = 'txt_' + $myclass; $chk = 'chk_' + $myclass; // Based I clicked on the link 'settext1', Here I have this: // col_settext1 // txt_settext1 // chk_settext1 // THE PROBLEM ARE HERE! $col = new Array(); // <--- Here I use name of DIV as Array, but the value is lost... $txt = new Array(); $chk = new Array(); // Test... alert($col); // <--- Here no have any value :( alert($col[1]); // <--- Here no have any value :( for (id in $col) { // 'id' is value of array --> col_settext1['field_id1']='#FF0000'; // do function based on array values... // just example: alert(id); } for (id in $txt) { // 'id' is value of array --> txt_settext1['field_id1']='#FF0000'; // do function based on array values... } for (id in $chk) { // 'id' is value of array --> chk_settext1['field_id1']='#FF0000'; // do function based on array values... } }); Is possible use name of the div as array name? Any suggestion or any other method to solve this problem is welcome.

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  • What SQL query should I perform to get the result set expected?

    - by texai
    What SQL query should I perform to get the result set expected, giving the first element of the chain (2) as input data, or any of them ? table name: changes +----+---------------+---------------+ | id | new_record_id | old_record_id | +----+---------------+---------------+ | 1| 4| 2| | -- non relevant data -- | | 6| 7| 4| | -- non relevant data -- | | 11| 13| 7| | 12| 14| 13| | -- non relevant data -- | | 31| 20| 14| +----+---------------+---------------+ Result set expected: +--+ | 2| | 4| | 7| |13| |14| |20| +--+ I know I should consider change my data model, but: What if I couldn't? Thank you in advance!

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  • checkbox checked with php form post?

    - by Patrick
    how do I check a checkbox? I've tried 1, On, Yes that doesn't work. putting the worked "checked" alone works but then how do I check with php after form post of the checkbox is checked? <input type="checkbox" class="inputcheckbox" id="newmsg" name=chk[newmsg2] value="1" />

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