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  • how to display user name in login name control

    - by user569285
    I have a master page that holds the loginview content that appears on all subsequent pages based on the master page. i have a username control also nested in the loginview to display the name of the user when they are logged in. the code for the loginview from the master page is displayed as follows: <div class="loginView"> <asp:LoginView ID="MasterLoginView" runat="server"> <LoggedInTemplate> Welcome <span class="bold"><asp:LoginName ID="HeadLoginName" runat="server" /> <asp:Label ID="userNameLabel" runat="server" Text="Label"></asp:Label></span>! [ <asp:LoginStatus ID="HeadLoginStatus" runat="server" LogoutAction="Redirect" LogoutText="Log Out" LogoutPageUrl="~/Logout.aspx"/> ] <%--Welcome: <span class="bold"><asp:LoginName ID="MasterLoginName" runat="server" /> </span>!--%> </LoggedInTemplate> <AnonymousTemplate> Welcome: Guest [ <a href="~/Account/Login.aspx" ID="HeadLoginStatus" runat="server">Log In</a> ] </AnonymousTemplate> </asp:LoginView> <%--&nbsp;&nbsp; [&nbsp;<asp:LoginStatus ID="MasterLoginStatus" runat="server" LogoutAction="Redirect" LogoutPageUrl="~/Logout.aspx" />&nbsp;]&nbsp;&nbsp;--%> </div> Since VS2010 launches with a default login page in the accounts folder, i didnt think it necessary to create a separate log in page, so i just used the same log in page. please find the code for the login control below: <asp:Login ID="LoginUser" runat="server" EnableViewState="false" RenderOuterTable="false"> <LayoutTemplate> <span class="failureNotification"> <asp:Literal ID="FailureText" runat="server"></asp:Literal> </span> <asp:ValidationSummary ID="LoginUserValidationSummary" runat="server" CssClass="failureNotification" ValidationGroup="LoginUserValidationGroup"/> <div class="accountInfo"> <fieldset class="login"> <legend style="text-align:left; font-size:1.2em; color:White;">Account Information</legend> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="UserNameLabel" runat="server" AssociatedControlID="UserName">User ID:</asp:Label> <asp:TextBox ID="UserName" runat="server" CssClass="textEntry"></asp:TextBox> <asp:RequiredFieldValidator ID="UserNameRequired" runat="server" ControlToValidate="UserName" CssClass="failureNotification" ErrorMessage="User ID is required." ToolTip="User ID field is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:Label ID="PasswordLabel" runat="server" AssociatedControlID="Password">Password:</asp:Label> <asp:TextBox ID="Password" runat="server" CssClass="passwordEntry" TextMode="Password"></asp:TextBox> <asp:RequiredFieldValidator ID="PasswordRequired" runat="server" ControlToValidate="Password" CssClass="failureNotification" ErrorMessage="Password is required." ToolTip="Password is required." ValidationGroup="LoginUserValidationGroup">*</asp:RequiredFieldValidator> </p> <p style="text-align:left; font-size:1.2em; color:White;"> <asp:CheckBox ID="RememberMe" runat="server"/> <asp:Label ID="RememberMeLabel" runat="server" AssociatedControlID="RememberMe" CssClass="inline">Keep me logged in</asp:Label> </p> </fieldset> <p class="submitButton"> <asp:Button ID="LoginButton" runat="server" CommandName="Login" Text="Log In" ValidationGroup="LoginUserValidationGroup" onclick="LoginButton_Click"/> </p> </div> </LayoutTemplate> </asp:Login> I then wrote my own code for authentication since i had my own database. the following displays the code in the login buttons click event.: public partial class Login : System.Web.UI.Page { //create string objects string userIDStr, pwrdStr; protected void LoginButton_Click(object sender, EventArgs e) { //assign textbox items to string objects userIDStr = LoginUser.UserName.ToString(); pwrdStr = LoginUser.Password.ToString(); //SQL connection string string strConn; strConn = WebConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ConnectionString; SqlConnection Conn = new SqlConnection(strConn); //SqlDataSource CSMDataSource = new SqlDataSource(); // CSMDataSource.ConnectionString = ConfigurationManager.ConnectionStrings["CMSSQL3ConnectionString"].ToString(); //SQL select statement for comparison string sqlUserData; sqlUserData = "SELECT StaffID, StaffPassword, StaffFName, StaffLName, StaffType FROM Staffs"; sqlUserData += " WHERE (StaffID ='" + userIDStr + "')"; sqlUserData += " AND (StaffPassword ='" + pwrdStr + "')"; SqlCommand com = new SqlCommand(sqlUserData, Conn); SqlDataReader rdr; string usrdesc; string lname; string fname; string staffname; try { //string CurrentData; //CurrentData = (string)com.ExecuteScalar(); Conn.Open(); rdr = com.ExecuteReader(); rdr.Read(); usrdesc = (string)rdr["StaffType"]; fname = (string)rdr["StaffFName"]; lname = (string)rdr["StaffLName"]; staffname = lname.ToString() + " " + fname.ToString(); LoginUser.UserName = staffname.ToString(); rdr.Close(); if (usrdesc.ToLower() == "administrator") { Response.Redirect("~/CaseAdmin.aspx", false); } else if (usrdesc.ToLower() == "manager") { Response.Redirect("~/CaseManager.aspx", false); } else if (usrdesc.ToLower() == "investigator") { Response.Redirect("~/Investigator.aspx", false); } else { Response.Redirect("~/Default.aspx", false); } } catch(Exception ex) { string script = "<script>alert('" + ex.Message + "');</script>"; } finally { Conn.Close(); } } My authentication works perfectly and the page gets redirected to the designated destination. However, the login view does not display the users name. i actually cant figure out how to pass the users name that i had picked from the database to the login name control to be displayed. taking a close look i also noticed the logout text that should be displayed after successful log in does not show. that leaves me wondering if the loggedin template control on the masterpage even fires at all or its still the anonymous template control that keeps displaying.? How do i get this to work as expected? Please help....

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  • Could not log-in properly but shows no error in joomla

    - by saeha
    This is what I did, I added variables in \libraries\joomla\database\table\user.php: var $img_content= null; //contains the blob type data var $img_name = null; var $img_type = null; then I added this code in \components\com_user\controller.php: $file = JRequest::getVar( 'pic', '', 'files', 'array' ); if(isset($file['name'])) { jimport('joomla.filesystem.file'); $fileName = $file['name']; $tmpName = $file['tmp_name']; $fileSize = $file['size']; $fileType = $file['type']; $fp = fopen($tmpName, 'r'); $content = fread($fp, filesize($tmpName)); //$content = addslashes($content); fclose($fp); $user->set('img_name', $fileName); $user->set('img_type', $fileType); $user->set('img_content', $content); } that works fine, but I found this problem in logging in with the new user with an uploaded photo, other user with an empty img_content field could login properly. What happens is when I log-in using the user with uploaded photo, it's not redirecting properly it just return to log-in, but when i log-in through backend using other user which is super admin, i could see that user which appears as logged in. I started saving the images in the database because I am having problem with the directory when I have uploaded the site. I think the log-in was affected by the blob type data in the database. Could that be the problem? What could be the solution? -saeha

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  • Can't Log Into Ubuntu 12.04

    - by Razick
    Yesterday, after turning on Ubuntu, I logged into a Gnome session. A few minutes later, I tried switching to Unity for a change. Unfortunately, the background and my desktop icons loaded, but the system bar and launcher failed to load even after several minutes. Unity had always worked fine for me. I then tried the guest account, and it worked fine on both Unity and Gnome. However, the problem with my account got worse; I couldn't log into any desktop at all anymore. I would type in my password and press enter and it would just sit there doing nothing. The computer no longer responded in any way, so I had to hold the power button and reboot. The same problem happened repeatedly. Earlier today, I tried to get on again. I found that I hadthe same problem, when I tried to log in, the computer no longer locked up, but instead flashed a black screen with theconsole output and what seemed to be an error message before returning to the log in screen. It was to quick for me to read, about 1/4-1/2 second. I'd really appreciate some help as I have some important files that are not backed up yet. I can't transfer the files to a new account, or even make a new account because I tried taking the password off my account so now I can't authenticate from the guest to perform root functions. I'd really appreciate some help as I have some important files that are not backed up yet. Thanks.

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  • Ubuntu Not Waking From Suspend

    - by thenorm
    I'm running Ubuntu 12.04 (not wubi, usb install) alongside Windows 7 on my Toshiba Satellite Laptop Series L655D-S5050 I have a couple of issues, Ubuntu will not wake from suspend when closing the lid. It will show the Ubuntu screen then go to black and spit out some quick text before the screen will just flicker, as if trying to wake up. I've been googling around looking for a fix but nothing seems to help. Maybe it has something to do with the drivers? I checked additional drivers in the system settings, but it says there are no drivers present. Any ideas? Also, this issue isn't present all the time. But sometimes when I go to shutdown or restart Ubuntu, it will just loops to the login screen. Thank you, for any input or help! Also I can get some logs of these issues, but not really sure how to go about all of that. I'm not to familiar with ubuntu, as i've only been using the desktop version for a couple months now.

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  • After Filter redirects to login.jsp, proper servlet doesnt get called

    - by gnomeguru
    My simple project structure is shown in this link. I am using Eclipse and Tomcat 6. There is login.jsp which submits its form to login_servlet. The login_servlet sets a session variable and then redirects to home.jsp. The home.jsp file has links to the 4 JSP files under a directory called /sam. In web.xml I have given the url-pattern as /sam/* for the LogFiler filter. The LogFilter just reads the session variable and does doChain(request,resposne) if valid, else it redirects to /login.jsp. RequestDispatcher rd = request.getRequestDispatcher("/login.jsp"); rd.forward(request,response); Basically I don't want anyone to access files inside /sam directory directly. Now let's say, I try to directly access a file inside /sam directory, the filter kicks in and the redirection to login.jsp works and even the broswers contents are that of login.jsp, but the url in the browser doesn't change. When I enter details and press submit, instead of sending the data to login_servlet, it sends it to sam/login_servlet and then tomcat tells me there is no such servlet here! Obviously there isn't. My doubt is why is it sending it so sam/login_servlet instead of /login_servlet which is usually what it does when I start running the login.jsp on my own. One more thing, is there a way I can apply the servlet to ONLY .jsp files inside /sam diectory? I tried giving the url-pattern like /sam/*.jsp, but Tomcat was refusing to accept that url-pattern.

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  • How do I add a URL parameter to redirected login page using JSF 2.0

    - by Big Al
    I have a question about session timeouts and JSF 2. I have my exception handler working exactly the way everyone prefers but I need to pass a value to the login page. For example, I have a typical login URL - www.acme.com/?companyId=company14 which in turn presents company14 with their own custom login page (using their logo). After they enter the application and do a bit of work, they read an email or 2. The session times out and a session timeout page is shown instructing the user to click Ok to proceed to the login page. How do I add ?companyId=company14 to the URL? I can hardcode it in the exception handler by using this: requestMap.put("companyId", "company14"); and then referring to it on the viewExpired.xhtml page: <h:panelGrid id="expiredGrid" columns="1"> <f:facet name="header"> <h:outputText id="outExpireMsg" value="Your session has expired"/> </f:facet> <h:outputText id="outReqMessage" value="Reloading the page will require login."/> <h:outputText value=""/> <h:button id="okButton" type="submit" value="Ok" outcome="login?companyId=#{companyId}"/> </h:panelGrid> The issue is I can't seem to save the companyId anywhere without it getting wiped out by the session timeout. I'd like to set the companyId in the exceptionhandler using this value. Any ideas?

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  • calll html button onclick event from asp server side login authenticate event

    - by CraigJSte
    Need to programmatically click an html button from a login event (code behind? the html button sends variables to Flash using method: no response - with no postback and uses ExternalInterface API via javascript. Going from SWF ASPX is great, but need to send User.Identity to SWF from ASPX via javascript after authenticate with login event which am having impossible time getting to work... (calling HTML event from Login button) tried scripting in javascript to login event with no luck, possibly because postback clears SWF variables - so perhaps keeping separate (login then html send) would work... Here is my relevant code: function sendToActionScript(value) { swfobject.getObjectById("Property").sendToActionScript(value); } </script> <object ..// SWF File embedded> </object <form id="form1" runat="server"> <asp:Login id="login1" OnAuthenticate="login1_Authenticate"/> </form> <form id="form" onsubmit="return false;"> <input type="text" name="input" id="input" value="" runat="server" /> <button id="btnInput" runat="server" causesvalidation="false" visible="true" style="width: 51px" onclick="sendToActionScript(this.form.input.value);" >Send</button><br /> </form> // CODE BEHIND protected void Login1_Authenticate(object sender, AuthenticateEventArgs e) { // do something to get User Id and Role //bind the string (user or role) to input.value //then call the HTML button onclick event to send it to SWF file. //which I could put in separate function and call from Login_Authenticate } Can anyone help me I am out of ideas. Craig

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  • How to get Facebook Login Button To Display "Logout"

    - by Will Merydith
    I apologize ahead of time if this is clearly documented somewhere on the FB developer site - but I can't find it (so please link me if appropriate). I've implemented the FB login button on a website using GAE + Python. Here is the HTML: <fb:login-button></fb:login-button> <div id="fb-root"></div> <script src="http://connect.facebook.net/en_US/all.js"></script> <script> FB.init({appId: 'ad16a806fc10bef5d30881322e73be68', status: true, cookie: true, xfbml: true}); FB.Event.subscribe('auth.sessionChange', function(response) { if (response.session) { // A user has logged in, and a new cookie has been saved } else { // The user has logged out, and the cookie has been cleared } }); </script> Currently the behavior is - if I click on the "login" button, I am asked to allow the application access to FB. Which I then choose, "OK". But then the login button is still showing "login" and not "logout". How do I implement that? On the server or client side?

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  • login/logout problem in PHP

    - by user356170
    i have a question. I have a website in which i am giving security like login id and password( as usual). No what i want is that, 1) I don't want to allow a single user to login in different machine at the same time. 2) For this i am using a column in database which is keeping the current status of user(i.e. loging/logout). I am allowing user to login only when has session has not closed and status is login. 3) So my problem is that when i am logging out manually. it is closing the session as well as updating the database with status "logout". 4) but when i am closing the window from Cross buttonat top right corner. it is closing the ssion but table data is still "login". so later on i can't be able to login into the same user. 5) So how could i solve this problem. Please help me!

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  • Is my approach for persistent login secure ?

    - by Jay
    I'm very much stuck with the reasonable secure approach to implement 'Remember me' feature in a login system. Here's my approach so far, Please advice me if it makes sense and is reasonably secure: Logging: User provides email and password to login (both are valid).. Get the user_id from DB Table Users by comparing provided email Generate 2 random numbers hashed strings: key1, key2 and store in cookies. In DB Table COOKIES, store key1, key2 along with user_id. To Check login: If key1 and key2 both cookies exist, validate both keys in DB Table COOKIES (if a row with key1, and key2 exists, user is logged). if cookie is valid, regenrate key2 and update it in cookie and also database. Why re-genrating key: Because if someone steals cookie and login with that cookie, it will be working only until the real user login. When the real user will login, the stolen cookie will become invalid. Right? Why do I need 2 keys: Because if i store user_id and single key in cookie and database, and the user want to remember the password on another browser, or computer, then the new key will be updated in database, so the user's cookie in earlier browser/PC will become invalid. User wont be able to remember password on more than one place. Thanks for your opinions.

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  • NSClient++ FAIL on Windows 2008 R2 -- PDHCollector.cpp(215) Failed to query performance counters

    - by John DaCosta
    I am attempting to monitor windows server 2008 r2 x64 Enterprise with Nagios. When I test/install the nsclientI get the following error: PDHCollector.cpp(215) Failed to query performance counters: \Processor(_total)\% Processor Time: PdhGetFormattedCounterValue failed: A counter with a negative denominator value was detected. (800007D6) Has anyone else encountered the same issue and / or resolved it, found a work around?

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  • "Checksum failed" during Kerberos SSO

    - by Buddy Casino
    This is an error that occurs when a mod_auth_kerb protected webapp is being accessed, and I have no idea what the cause might be. Can anyone give hints as into which direction I should look? Thankful for any help! Search Subject for Kerberos V5 ACCEPT cred (HTTP/[email protected], sun.security.jgss.krb5.Krb5AcceptCredential) Found key for HTTP/[email protected](23) Entered Krb5Context.acceptSecContext with state=STATE_NEW >>> EType: sun.security.krb5.internal.crypto.ArcFourHmacEType Checksum failed ! 16:36:30,248 TP-Processor31 WARN [site.servlet.KerberosSessionSetupPrivilegedAction] Caught GSS Error GSSException: Failure unspecified at GSS-API level (Mechanism level: Checksum failed) at sun.security.jgss.krb5.Krb5Context.acceptSecContext(Krb5Context.java:741) at sun.security.jgss.GSSContextImpl.acceptSecContext(GSSContextImpl.java:323) at sun.security.jgss.GSSContextImpl.acceptSecContext(GSSContextImpl.java:267) at sun.security.jgss.krb5.Krb5Context.acceptSecContext(Krb5Context.java:741) at sun.security.jgss.GSSContextImpl.acceptSecContext(GSSContextImpl.java:323) at sun.security.jgss.GSSContextImpl.acceptSecContext(GSSContextImpl.java:267) at org.alfresco.web.site.servlet.KerberosSessionSetupPrivilegedAction.run(KerberosSessionSetupPrivilegedAction.java:95) at org.alfresco.web.site.servlet.KerberosSessionSetupPrivilegedAction.run(KerberosSessionSetupPrivilegedAction.java:44) at org.alfresco.web.site.servlet.KerberosSessionSetupPrivilegedAction.run(KerberosSessionSetupPrivilegedAction.java:44) at java.security.AccessController.doPrivileged(Native Method) at java.security.AccessController.doPrivileged(Native Method) at javax.security.auth.Subject.doAs(Subject.java:337) at org.alfresco.web.site.servlet.SSOAuthenticationFilter.doKerberosLogon(SSOAuthenticationFilter.java:994) at org.alfresco.web.site.servlet.SSOAuthenticationFilter.doKerberosLogon(SSOAuthenticationFilter.java:994) at org.alfresco.web.site.servlet.SSOAuthenticationFilter.doFilter(SSOAuthenticationFilter.java:438) at org.alfresco.web.site.servlet.SSOAuthenticationFilter.doFilter(SSOAuthenticationFilter.java:438) at org.apache.catalina.core.ApplicationFilterChain.internalDoFilter(ApplicationFilterChain.java:235) at org.apache.catalina.core.ApplicationFilterChain.doFilter(ApplicationFilterChain.java:206) at org.apache.catalina.core.StandardWrapperValve.invoke(StandardWrapperValve.java:233) at org.apache.catalina.core.StandardContextValve.invoke(StandardContextValve.java:191) at org.apache.catalina.core.StandardHostValve.invoke(StandardHostValve.java:127) at org.apache.catalina.valves.ErrorReportValve.invoke(ErrorReportValve.java:102) at org.apache.catalina.valves.AccessLogValve.invoke(AccessLogValve.java:555) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.core.StandardEngineValve.invoke(StandardEngineValve.java:109) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.catalina.connector.CoyoteAdapter.service(CoyoteAdapter.java:298) at org.apache.jk.server.JkCoyoteHandler.invoke(JkCoyoteHandler.java:190) at org.apache.jk.common.HandlerRequest.invoke(HandlerRequest.java:291) at org.apache.jk.common.ChannelSocket.invoke(ChannelSocket.java:774) at org.apache.jk.common.ChannelSocket.processConnection(ChannelSocket.java:703) at org.apache.jk.common.ChannelSocket$SocketConnection.runIt(ChannelSocket.java:896) at org.apache.tomcat.util.threads.ThreadPool$ControlRunnable.run(ThreadPool.java:690) at java.lang.Thread.run(Thread.java:662) Caused by: KrbException: Checksum failed at sun.security.krb5.internal.crypto.ArcFourHmacEType.decrypt(ArcFourHmacEType.java:85) at sun.security.krb5.internal.crypto.ArcFourHmacEType.decrypt(ArcFourHmacEType.java:77) at sun.security.krb5.EncryptedData.decrypt(EncryptedData.java:168) at sun.security.krb5.KrbApReq.authenticate(KrbApReq.java:268) at sun.security.krb5.KrbApReq.<init>(KrbApReq.java:134) at sun.security.jgss.krb5.InitSecContextToken.<init>(InitSecContextToken.java:79) at sun.security.jgss.krb5.Krb5Context.acceptSecContext(Krb5Context.java:724) ... 24 more Caused by: java.security.GeneralSecurityException: Checksum failed at sun.security.krb5.internal.crypto.dk.ArcFourCrypto.decrypt(ArcFourCrypto.java:388) at sun.security.krb5.internal.crypto.ArcFourHmac.decrypt(ArcFourHmac.java:74) at sun.security.krb5.internal.crypto.ArcFourHmacEType.decrypt(ArcFourHmacEType.java:83) ... 30 more

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  • proxy: pass request body failed

    - by bux
    I'm trying to enable proxy virtualhost: <VirtualHost *:80> ServerName xxxxx.domain.tdl SSLProxyEngine On SSLProxyCheckPeerCN on ProxyPass / https://localhost:1234 ProxyPassReverse / https://localhost:1234 </VirtualHost> But i've an 500 err and my error.log (apache2) display: [Tue Jan 03 15:41:42 2012] [error] (502)Unknown error 502: proxy: pass request body failed to [::1]:1234 (localhost) [Tue Jan 03 15:41:42 2012] [error] proxy: pass request body failed to [::1]:1234 (localhost) from 82.252.xxx.xx () Missing some parameters ?

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  • PulseAudio on Cygwin: Failed to create secure directory: Unknown error 13

    - by Nithin
    I am unable to run PulseAudio on Cygwin. Operating System: Windows 8 Pro 64 bit Cygwin Setup.exe Version: 2.831 (64 bit) PulseAudio Version: 2.1-1 When I run: pulseaudio -vv this is the output: D: [(null)] core-util.c: setpriority() worked. I: [(null)] core-util.c: Successfully gained nice level -11. I: [(null)] main.c: This is PulseAudio 2.1 D: [(null)] main.c: Compilation host: x86_64-unknown-cygwin D: [(null)] main.c: Compilation CFLAGS: -ggdb -O2 -pipe -fdebug-prefix-map=/usr/src/ports/pulseaudio/pulseaudio-2.1-1/build=/usr/src/debug/pulseaudio-2.1-1 -fdebug-prefix-map=/usr/src/ports/pulseaudio/pulseaudio-2.1-1/src/pulseaudio-2.1=/usr/src/debug/pulseaudio-2.1-1 -Wall -W -Wextra -Wno-long-long -Wvla -Wno-overlength-strings -Wunsafe-loop-optimizations -Wundef -Wformat=2 -Wlogical-op -Wsign-compare -Wformat-security -Wmissing-include-dirs -Wformat-nonliteral -Wpointer-arith -Winit-self -Wdeclaration-after-statement -Wfloat-equal -Wmissing-prototypes -Wredundant-decls -Wmissing-declarations -Wmissing-noreturn -Wshadow -Wendif-labels -Wcast-align -Wstrict-aliasing -Wwrite-strings -Wno-unused-parameter -ffast-math -Wp,-D_FORTIFY_SOURCE=2 -fno-common -fdiagnostics-show-option D: [(null)] main.c: Running on host: CYGWIN_NT-6.2 x86_64 1.7.25(0.270/5/3) 2013-08-31 20:37 D: [(null)] main.c: Found 4 CPUs. I: [(null)] main.c: Page size is 65536 bytes D: [(null)] main.c: Compiled with Valgrind support: no D: [(null)] main.c: Running in valgrind mode: no D: [(null)] main.c: Running in VM: no D: [(null)] main.c: Optimized build: yes D: [(null)] main.c: FASTPATH defined, only fast path asserts disabled. I: [(null)] main.c: Machine ID is 5d8bd07cb924c67197184e42527f2603. E: [(null)] core-util.c: Failed to create secure directory: Unknown error 13 When I instead run pulseaudio -vv --start the output is this: E: [autospawn] core-util.c: Failed to create secure directory: Unknown error 13 W: [autospawn] lock-autospawn.c: Cannot access autospawn lock. E: [(null)] main.c: Failed to acquire autospawn lock When I ran strace pulseaudio -vv, the red-colored lines in the output were: 28 1637050 [main] pulseaudio 5104 fhandler_pty_slave::write: (669): pty output_mutex(0xBC) released 26 1637076 [main] pulseaudio 5104 write: 7 = write(2, 0x3FE171079, 7) 42 1637118 [main] pulseaudio 5104 fhandler_pty_slave::write: pty0, write(0x60003BB40, 51) 27 1637145 [main] pulseaudio 5104 fhandler_pty_slave::write: (654): pty output_mutex (0xBC): waiting -1 ms 23 1637168 [main] pulseaudio 5104 fhandler_pty_slave::write: (654): pty output_mutex: acquired Failed to create secure directory: Unknown error 13 21 1637189 [main] pulseaudio 5104 fhandler_pty_slave::write: (669): pty output_mutex(0xBC) released 29 1637218 [main] pulseaudio 5104 write: 51 = write(2, 0x60003BB40, 51) 46 1637264 [main] pulseaudio 5104 fhandler_pty_slave::write: pty0, write(0x3FE17106F, 4) 24 1637288 [main] pulseaudio 5104 fhandler_pty_slave::write: (654): pty output_mutex (0xBC): waiting -1 ms 24 1637312 [main] pulseaudio 5104 fhandler_pty_slave::write: (654): pty output_mutex: acquired Please can someone help me?

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  • Cannot login to Postgrest database despite setting password for user 'postgres'

    - by Serg
    I'm trying to use pgAdmin III to manage my Postgres database. Here are the commands I've run on my machine: sudo apt-get install postgresql Then I installed the pgAdmin III application: sudo apt-get install pgadmin3 Next I focused on setting my username and password in order to login: sudo -u postgres psql postgres Here I set my password \password postgres Finally I just created my database: sudo -u postgres createdb repairsdatabase When I try to login using pgAdmin III, I get the error: An error has occurred: Error connecting to the server: FATAL: Peer authentication failed for user "postgres"

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  • Exchange 2010 - resolving Calendar Attendant\Requests Failed

    - by marcwenger
    On my mailbox server, I am receiving the alert: MSExchange Calendar Attendant\Requests Failed Or in Solarwinds Requests Failed (Calendar Attendant) for Exchange 2010 Mailbox Role Counters (Advanced) on *servername* All I know is this figure should be 0 at all times. Currently I am at 2 and this is the only alert on the Exchange servers. No where I can find how to resolve this. How can I fix this? thank you

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  • Forward all traffic through an ssh tunnel

    - by Eamorr
    I hope someone can follow this and I'll explain as best I can. I'm trying to forward all traffic from port 6999 on x.x.x.224, through an ssh tunnel, and onto port 7000 on x.x.x.218. Here is some ASCII art: |browser|-----|Squid on x.x.x.224|------|ssh tunnel|------<satellite link>-----|Squid on x.x.x.218|-----|www| 3128 6999 7000 80 When I remove the ssh tunnel, everything works fine. The idea is to turn off encryption on the ssh tunnel (to save bandwidth) and turn on maximum compression (to save more bandwidth). This is because it's a satellite link. Here's the ssh tunnel I've been using: ssh -C -f -C -o CompressionLevel=9 -o Cipher=none [email protected] -L 7000:172.16.1.224:6999 -N The trouble is, I don't know how to get data from Squid on x.x.x.224 into the ssh tunnel? Am I going about this the wrong way? Should I create an ssh tunnel on x.x.x.218? I use iptables to stop squid on x.x.x.224 from reading port 80, but to feed from port 6999 instead (i.e. via the ssh tunnel). Do I need another iptables rule? Any comments greatly appreciated. Many thanks in advance, Regarding Eduardo Ivanec's question, here is a netstat -i any port 7000 -nn dump from x.x.x.218: 14:42:15.386462 IP 172.16.1.224.40006 > 172.16.1.218.7000: Flags [S], seq 2804513708, win 14600, options [mss 1460,sackOK,TS val 86702647 ecr 0,nop,wscale 4], length 0 14:42:15.386690 IP 172.16.1.218.7000 > 172.16.1.224.40006: Flags [R.], seq 0, ack 2804513709, win 0, length 0 Update 2: When I run the second command, I get the following error in my browser: ERROR The requested URL could not be retrieved The following error was encountered while trying to retrieve the URL: http://109.123.109.205/index.php Zero Sized Reply Squid did not receive any data for this request. Your cache administrator is webmaster. Generated Fri, 01 Jul 2011 16:06:06 GMT by remote-site (squid/2.7.STABLE9) remote-site is 172.16.1.224 When I do a tcpdump -i any port 7000 -nn I get the following: root@remote-site:~# tcpdump -i any port 7000 -nn tcpdump: verbose output suppressed, use -v or -vv for full protocol decode listening on any, link-type LINUX_SLL (Linux cooked), capture size 65535 bytes channel 2: open failed: connect failed: Connection refused channel 2: open failed: connect failed: Connection refused channel 2: open failed: connect failed: Connection refused channel 2: open failed: connect failed: Connection refused channel 2: open failed: connect failed: Connection refused channel 2: open failed: connect failed: Connection refused channel 2: open failed: connect failed: Connection refused channel 2: open failed: connect failed: Connection refused channel 2: open failed: connect failed: Connection refused channel 2: open failed: connect failed: Connection refused channel 2: open failed: connect failed: Connection refused

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  • IIS login Problem to open localhost

    - by Shahid Mahmood Adil
    i have winXp sp2 on my machine. i have installed IIS. when i am trying to open my localhost as http://localhost/ it asks for login and password. when i am using my windows authentication to login creates an error message http 500 internal server error and error detail is error '8002801c' Error accessing the OLE registry. /iisHelp/common/500-100.asp, line 17 how can i resolve this problem?

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  • Failed dependencies warning while installing pure-ftpd

    - by Anil
    I am trying to install pure-ftpd which is getting failed with the following warnings warning: pure-ftpd-1.0.36-1.el5.rf.i386.rpm: Header V3 DSA/SHA1 Signature, key ID 6b8d79e6: NOKEY error: Failed dependencies: libmysqlclient.so.15 is needed by pure-ftpd-1.0.36-1.el5.rf.i386 libmysqlclient.so.15(libmysqlclient_15) is needed by pure-ftpd-1.0.36-1.el5.rf.i386 libpq.so.4 is needed by pure-ftpd-1.0.36-1.el5.rf.i386 I used locate libmysqlclient libpq where i could find libmysqlclient.so.16 and libpq.so.5 installed in my server I am using CentOS 6 server.

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  • Outlook 2007 login prompt repeat prompt and exchange 2010

    - by Dan
    It seems when I first setup a new user in Outlook 2007, a login prompt comes up and asks for credentials. After the account is setup, the login prompt will repeatedly prompt throughout the day and is a little annoying. This happened recently as all other machines are not doing this - just a few machines on the network (HP 8200 Elite small form factor machines to be exact) Any help would be much appreciated.

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  • windows XP login issue

    - by Vineel Kumar Reddy
    When i start my XP machine i willnot directly taken to login screen instead i have to press alt-tab and then a messagebox appears and then click have to click no or yes each time to get to login screen. please any body suggest how i can resolve this issue.

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  • How to automatically define functions and aliases on remote server after ssh login

    - by Ramon
    I want to define bash functions and aliases in my remote shell automatically on login. I can't put the definitions into .profile or similar because the users I log in as are often shared with others who use the same systems and I don't have control of this. What I'm trying to do is execute a few bash function definitions in the remote process and then continue as a login shell. I tried this but it did not work: cat ~/.profile - | ssh -tt user@host bash -l Any ideas?

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