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  • Help yourself . if you like

    - by rachelp
    At Red Gate we enjoy talking to our customers. Really! If you've read recent blog posts by members of some of our customer-facing teams, you'll have spotted the pleasure they take in their work. In case you missed those posts, here they are: From our Finance team: Finance: Friends, not foes! From our reception desk: The Front line of Communication However, we recognise that sometimes our customers would like to be able to solve their problems or answer their questions without talking to us - they're in a hurry, it's outside office hours . or perhaps they just prefer not to pick up the phone and call.   Self-service customer care So we've begun a programme of work to enable more self-service; whether it's finding the answer to a "how do i.?" question or getting access to a record of what product licenses they own, we want to make it much easier for our customers to get hold of this information for themselves. If they want to.   Phase 1: make it easier to find information We decided to start by tackling findability. We've got loads of useful information on our website, but it's sometimes difficult to find, so we've been working on improving our site search. Step 1 has been to replace the search engine, clean up the search UI, and make it consistent across the site. We're nearly there! The idea is that if we improve the site search it will be easier - and much more pleasant - for people to find the information they need. The new search will go live some time in April, and then we'll be gathering feedback, looking at web analytics (more about this in an earlier article), and working out what improvements we still need to make. We'd love to hear what you think, so do give your feedback or drop us a line. Or pick up the phone and call, if you like.   What do you think? While I've got your attention, I'd love to hear what people think about self-service customer care. Do you like to call, email, live chat . or do you prefer to dig around and find out answers yourself? Who's getting it right: what self-service sites do you like? p.s. Watch this space for news of phase 2.

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  • HELP! Problem Can't do anyting on ubuntu 13.10

    - by Perbasilopou
    I upgraded from ubuntu 13.04 to 13.10 but when i open my laptop it freezes before i can login ant the gnome 3 splash screen. alt ctrl + f(any) not working. the only thing i can do is manualy power off. I tryied everything on recovery mode screen and some stuff about grub (nomodeset quiet splash stuff i found at this forum) but nothing is working. I can't reach tty's to login so i can't reinstall drivers for my ati radeon mobility hd 5xxx. that is my secs http://www.sony.co.uk/support/en/product/VPCEB2E1E_WI/specifications .

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  • Extended service set help [closed]

    - by Cygnus X
    Sorry, this is going to be long and rambly. So, at home my network is set up as such: I have a "master router" that handles DHCP, from there I have a basic 5 port switch, and coming off that, I have a second router that I put in access point mode so that I could have better wireless coverage in my house. I cant seem to access it through a web browser since the master router kicked in and assigned it an ip address. But, i told you all that story, so that i could tell you this story. At the company I work for, they are trying to set up wireless cameras, according to the manual for these, in order to connect these cameras to our network, we need to get into the wireless router and associate the router with the cameras, but the problem is, the network is setup like my home network. Theres a "master router" which is a windows 2003 server, and then a wireless router in AP mode dishing out wireless access. I cant get into the router (by the way I'm not the system admin for the company, nor do i know jack squat about windows server , nor can I easily get in contact with the system admin. (quite the cluster f*k, eh?)) I've tried using wireshark to find the routers ip, dug through arp tables, tried plugging straight into the router, but I cant seem to get into the damn thing. Any ideas/suggestions would be greatly appreciated.

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  • Java Program help [migrated]

    - by georgetheevilman
    Okay I have a really annoying error. Its coming from my retainAll method. The problem is that I am outputting 1,3,5 in ints at the end, but I need 1,3,5,7,9. Here is the code below for the MySet and driver classes public class MySetTester { public static void main(String[]args) { MySet<String> strings = new MySet<String>(); strings.add("Hey!"); strings.add("Hey!"); strings.add("Hey!"); strings.add("Hey!"); strings.add("Hey!"); strings.add("Listen!"); strings.add("Listen!"); strings.add("Sorry, I couldn't resist."); strings.add("Sorry, I couldn't resist."); strings.add("(you know you would if you could)"); System.out.println("Testing add:\n"); System.out.println("Your size: " + strings.size() + ", contains(Sorry): " + strings.contains("Sorry, I couldn't resist.")); System.out.println("Exp. size: 4, contains(Sorry): true\n"); MySet<String> moreStrings = new MySet<String>(); moreStrings.add("Sorry, I couldn't resist."); moreStrings.add("(you know you would if you could)"); strings.removeAll(moreStrings); System.out.println("Testing remove and removeAll:\n"); System.out.println("Your size: " + strings.size() + ", contains(Sorry): " + strings.contains("Sorry, I couldn't resist.")); System.out.println("Exp. size: 2, contains(Sorry): false\n"); MySet<Integer> ints = new MySet<Integer>(); for (int i = 0; i < 100; i++) { ints.add(i); } System.out.println("Your size: " + ints.size()); System.out.println("Exp. size: 100\n"); for (int i = 0; i < 100; i += 2) { ints.remove(i); } System.out.println("Your size: " + ints.size()); System.out.println("Exp. size: 50\n"); MySet<Integer> zeroThroughNine = new MySet<Integer>(); for (int i = 0; i < 10; i++) { zeroThroughNine.add(i); } ints.retainAll(zeroThroughNine); System.out.println("ints should now only retain odd numbers" + " 0 through 10\n"); System.out.println("Testing your iterator:\n"); for (Integer i : ints) { System.out.println(i); } System.out.println("\nExpected: \n\n1 \n3 \n5 \n7 \n9\n"); System.out.println("Yours:"); for (String s : strings) { System.out.println(s); } System.out.println("\nExpected: \nHey! \nListen!"); strings.clear(); System.out.println("\nClearing your set...\n"); System.out.println("Your set is empty: " + strings.isEmpty()); System.out.println("Exp. set is empty: true"); } } And here is the main code. But still read the top part because that's where my examples are. import java.util.Set; import java.util.Collection; import java.lang.Iterable; import java.util.Iterator; import java.util.Arrays; import java.lang.reflect.Array; public class MySet implements Set, Iterable { // instance variables - replace the example below with your own private E[] backingArray; private int numElements; /** * Constructor for objects of class MySet */ public MySet() { backingArray=(E[]) new Object[5]; numElements=0; } public boolean add(E e){ for(Object elem:backingArray){ if (elem==null ? e==null : elem.equals(e)){ return false; } } if(numElements==backingArray.length){ E[] newArray=Arrays.copyOf(backingArray,backingArray.length*2); newArray[numElements]=e; numElements=numElements+1; backingArray=newArray; return true; } else{ backingArray[numElements]=e; numElements=numElements+1; return true; } } public boolean addAll(Collection<? extends E> c){ for(E elem:c){ this.add(elem); } return true; } public void clear(){ E[] newArray=(E[])new Object[backingArray.length]; numElements=0; backingArray=newArray; } public boolean equals(Object o){ if(o instanceof Set &&(((Set)o).size()==numElements)){ for(E elem:(Set<E>)o){ if (this.contains(o)==false){ return false; } return true; } } return false; } public boolean contains(Object o){ for(E backingElem:backingArray){ if (o!=null && o.equals(backingElem)){ return true; } } return false; } public boolean containsAll(Collection<?> c){ for(E elem:(Set<E>)c){ if(!(this.contains(elem))){ return false; } } return true; } public int hashCode(){ int sum=0; for(E elem:backingArray){ if(elem!=null){ sum=sum+elem.hashCode(); } } return sum; } public boolean isEmpty(){ if(numElements==0){ return true; } else{ return false; } } public boolean remove(Object o){ int i=0; for(Object elem:backingArray){ if(o!=null && o.equals(elem)){ backingArray[i]=null; numElements=numElements-1; E[] newArray=Arrays.copyOf(backingArray,backingArray.length-1); return true; } i=i+1; } return false; } public boolean removeAll(Collection<?> c){ for(Object elem:c){ this.remove(elem); } return true; } public boolean retainAll(Collection<?> c){ MySet<E> removalArray=new MySet<E>(); for(E arrayElem:backingArray){ if(arrayElem!= null && !(c.contains(arrayElem))){ this.remove(arrayElem); } } return false; } public int size(){ return numElements; } public <T> T[] toArray(T[] a) throws ArrayStoreException,NullPointerException{ for(int i=0;i<numElements;i++){ a[i]=(T)backingArray[i]; } for(int j=numElements;j<a.length;j++){ a[j]=null; } return a; } public Object[] toArray(){ Object[] newArray=new Object[numElements]; for(int i=0;i<numElements;i++){ newArray[i]=backingArray[i]; } return newArray; } public Iterator<E> iterator(){ setIterator iterator=new setIterator(); return iterator; } private class setIterator implements Iterator<E>{ private int currIndex; private E lastElement; public setIterator(){ currIndex=0; lastElement=null; } public boolean hasNext(){ while(currIndex<=numElements && backingArray[currIndex]==null){ currIndex=currIndex+1; } if (currIndex<=numElements){ return true; } return false; } public E next(){ E element=backingArray[currIndex]; currIndex=currIndex+1; lastElement=element; return element; } public void remove() throws UnsupportedOperationException,IllegalStateException{ if(lastElement!=null){ MySet.this.remove((Object)lastElement); numElements=numElements-1; } else{ throw new IllegalStateException(); } } } } I've been able to reduce the problems, but otherwise this thing is still causing problems.

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  • How RSS Feeds Help in SEO Optimization

    RSS, which stands for Really Simple Syndication is a web feed that is designed to publish updated content such as blog post, podcast and video. Submitting your RSS feeds to the blog directory allows the search engine to crawl your blog more often so that it can pick up new content.

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  • Web Directories Help Improve the Internet

    Web directory submission has always been in the menu list of SEO. It is one of the foremost activities for link building in promoting Web sites and helping them improve their rank with search engines. It also helps them to rank for their keywords and increase their position in search engine results page (SERP).

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  • Please explain how Trial Division works for Primality Test

    - by mister_dani
    I came across this algorithm for testing primality through trial division I fully understand this algorithm static boolean isPrime(int N) { if (N < 2) return false; for (int i = 2; i <= Math.sqrt(N); i++) if (N % i == 0) return false; return true; } It works just fine. But then I came across this other one which works just as good but I do not fully understand the logic behind it. static boolean isPrime(int N) { if (N < 2) return false; for (int i = 2; i * i<N; i++) if (N % i == 0) return false; return true; } It seems like i *i < N behaves like i <= Math.sqrt(N). If so, why?

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  • How Good SEO Can Help Promote Your Blog

    Are you a blogger with something to say, but need a bigger audience to hear you out? If so, then you're not alone. With millions of blogs flooding the Internet from points around the world, it can be tough to get your voice to stand out.

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  • Java Swing Visual Editor HELP please

    - by bat
    How would i call this function in my main? private JFrame getMainpageframe1() { if (mainpageframe1 == null) { mainpageframe1 = new JFrame(); mainpageframe1.setSize(new Dimension(315, 306)); mainpageframe1.setContentPane(getMainpage()); mainpageframe1.setTitle("Shopping For Less: Main Page"); mainpageframe1.setVisible(true); mainpageframe1.setDefaultCloseOperation(JFrame.EXIT_ON_CLOSE); } return mainpageframe1; } public static void main(String[] args) { //call that function to output the JFrame? } thanks

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  • help me about install ubuntu server 12.04 on vmware

    - by zohreh
    I want to install Ubuntu server 64-bit on vmware 8.0.2 but I face with a problem ! I don't know why ! the problem is: From here you can choose to retry DHCP network autoconfiguration (which may succeed if your DHCP server takes a long time to respond) or to configure the network manually. Some DHCP servers require a DHCP hostname to be sent by the client, so you can also choose to retry DHCP network autoconfiguration with a hostname that you provide. there are 4 option for Continuation i don't know exactly to select which option also what is The cause of the problem? thanks a lot

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  • 3 Ways to Help Your Website Be Seen Online

    When it comes to conducting business online, having good search engine optimization (SEO) foundations is just as important as having a Web site in the first place. Whether you use your Web site to share information about your business, get customers, sell a product or service, or more, it's essential that you incorporate some tried and true SEO strategies if your Web site is going to successfully serve its purpose.

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  • i have done code so please help

    - by davit-datuashvili
    public class bitap{ public static void main(String[]args){ String text="tbillisi"; String pattern="tbilxiri"; int k=2; int m=pattern.length(); long pattern_mask[]=new long[Character.MAX_VALUE+1]; String result=""; boolean[]R=new boolean[m+1]; long i,d; for (i=0;i<=k;i++){ R[i]=~1; } for (i=0;i if (0==(R[k]& (1< System.out.println(result); } } http://en.wikipedia.org/wiki/Bitap_algorithm from this site

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  • Help with selecting objects on a map

    - by Dave
    I have a object selection function by checking the mouse click and getting the relevant object. How ever there is a rare situation where if one object is partially behind the other then both objects are in the given area so im wondering how i can make the game know which one was selected, as currently my method does not know. This is my function that works it out: function getobj(e){ mx = e.pageX - curleft; //mouse click x my = e.pageY - curtop; //mouse click y function searchSprites(sprites, x, y) { var matches = [], i = 0, data = null; for (i = 0; i < spritea.length; ++i) { data = spritea[i].data; if (x > data[0] && y > data[1] && x < data[2] && y < data[3]) { var imageData = ctx2.getImageData(x, y, 1, 1); if(imageData.data[3] !== 0){ return [spritea[i].id]; i = spritea.length; } } } } res = searchSprites(spritea, mx, my); bid = res[0]; if(bid === '1'){ alert('You selected the skyscraper in front!'); }else if(bid === '3'){ alert('You selected the skyscraper behind!'); } } Image of the map: http://i.imgur.com/qcKij.jpg It keeps telling me i clicked the skyscraper behind which is not necessarily what the user is trying to do... how can i improve the accuracy of this ?

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  • Help with off-game tasks

    - by peoro
    I love writing video games for fun, and often do that. I noticed, anyway, that most of the times implementing the gameplay itself doesn't take too much time to me (maybe because I already did that plenty times and know what and how to do for most of the things), but when I try to implement off-game stuff I get lost. By off-game I mean what is not gameplay: menus, cutscenes between levels, world map to choose levels, saving and loading status, managing replays ... Only tried to write a few of these a few times, but always failed; that's why I never really completed and distributed a game. Are these common problems? And where should I start to do this? Where could I find some books/guides about such stuff?

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  • Can you please explain onCreate and Bundles?

    - by Mike
    I have been looking it up and I just cant seem to wrap myself around the onCreate and Bundles. I understand that the onCreate is called when the program starts but its how the Bundles get passed around and how they are pertinent. Can anyone try to put this into plain english because I cant seem to find it well described. Thanks

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  • tag cloud filter help please

    - by rod
    Hi All, I have a div that contains many spans and each of those spans contains a single href. Basically it's a tag cloud. What I'd like to do is have a textbox that filters the tag cloud on KeyUp event. Any ideas or is this possible? Thanks, rodchar

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  • Your Blog Will Help You With SEO

    One of the factors that can greatly improve your rankings is constantly having updated content on your website. Due to the nature of blogs, you can easily have updated content by making a simple post. Most of you know that Google indexes blog content more frequently.

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