jquery show hidden div
- by Fahad
Firstly, I'm sort of embarrassed asking about this, so many people have already asked this question but even after having gone through so many posts, I'm unable to achieve what I want.
Basically, a div, initially hidden, has to be displayed on a button click.
I tried hiding the div using display:none and hide() and then displaying it using show(), toggle(), and css("display","block"). Using all sorts of combinations of the above, I was still unable to get the result.
Code:
<html xmlns="http://www.w3.org/1999/xhtml">
<head runat="server">
<title></title>
<link href="css/smoothness/jquery-ui-1.9.2.custom.min.css" rel="stylesheet" type="text/css" />
<script src="jQuery/jquery-1.8.3.min.js" type="text/javascript"></script>
<script src="jQuery/jquery-ui-1.9.2.custom.min.js" type="text/javascript"></script>
<script type="text/javascript">
$(document).ready(function () {
$('#one').hide();
$('#Button1').click(function () {
$('#one').toggle(500);
});
});
</script>
</head>
<body>
<form id="form1" runat="server">
<div id="one" style="height: 20px;width:200px; background-color: Red; ">
</div>
<asp:Button ID="Button1" runat="server" Text="Show" />
</form>
</body>
</html>
On button click, the div is shown for a brief second before it disappears again.
The same thing happens if I use show() instead of toggle() in the above code.
Again the same thing if I set style="display:none" to the div instead of using hide() and then use show() or toggle().
I also tried using $('#one').css("display","block"); but again, the same result.
Can anyone please tell me where I'm going wrong. Just started learning jQuery and it is really frustrating when something apparently so simple will not work.
Thanks in advance. :)
