Search Results

Search found 18398 results on 736 pages for 'dijit form'.

Page 429/736 | < Previous Page | 425 426 427 428 429 430 431 432 433 434 435 436  | Next Page >

  • how to clear the input value using jquery

    - by rockers
    $("input[id^='exc-flwup-<%=Model.Date%>']").click(function() { $(this).val(''); }); I am using this to clear the input field..when i click on the input box its doign clear but.. on form submit if i ccheck at controler side I am still seeing this value there? do I need to do anyting else here to make null inputbox?

    Read the article

  • Use a named range in an excel worksheet to propagate a listbox

    - by user223139
    So I have a number of namedRanges in an excel worksheet. I would like to use these to fill in comboboxes on a user form in the same WorkBook. I have tried: cboMember.DataSource = Globals.Sheet1.MemberRange.Value No error is given but the combo is blank. Does anybody have any ideas? I'm trying to use VSTO for VS 2008 on an excel 2003 work book.

    Read the article

  • How would you name...

    - by BeowulfOF
    Since naming is a so important thing in programming, I would like to start a thread for giving help to all those that have same problems as I sometimes. Rules: Set a post with the description of the form||control||class or whatever you need to find a good name for. Get name hints in the answers.

    Read the article

  • jquery - "click" on keypress?

    - by WonderBugger
    I have an ajax search form that works fine if you click "submit" in that you enter a zipcode, click the "Enter" button and up pops results instantly. I'm trying to make it so that if the user presses "enter" on the keyboard, it has the same effect. It looks like it's submitting, but no results come up... I tried: if($('#search').length) { $('#zipcode').keyup(function(e) { if(e.keyCode == 13) { e.preventDefault(); $('#search').submit(); } }); }

    Read the article

  • Facebook application - Add wall

    - by fortysixandtwo
    How can I add a wall on my facebook-application (fbml). Do I have to store the wallposts (user-id and comment) in my database, and display them using fb:wall, fb:wallposts, or is it a plugin like fb:comments for this? If so, how do I add a textfield/form for interacting with the wall?

    Read the article

  • Stop $_POST from having the same value when I refresh

    - by Cortopasta
    When a vote value is changed, the form POSTs the change, then refreshes the page. This is called on the top of the page upon load: if (isset($_POST['q'.$question_id])) { $user->updateQuestionVotes($question_id, $_POST['q'.$question_id]); } Why does it update every time I refresh after the first time? Do I need to unset it somehow?

    Read the article

  • browse button on server

    - by sushant
    when we put a browse botton on a html form, it gives us the option to browse the file on our system only. if i run it on a server, will i b able to browse on server paths? basically i want to access the files available on the server. is it possible?

    Read the article

  • Any way to change the color of a radio button?

    - by Ryan
    I'm working on an android form with a radio group containing a set of radio buttons. From what I can tell there is no way to set the color a radio button highlights when you select it. It seems to always default to some bright green color. Is this something that is editable or no? Thanks

    Read the article

  • Jquery Quicksearch plugin issue with dynamic pages

    - by TheDarkMist
    Quicksearch is really cool... but it has a usability issue that makes it behave weird. A lot of users presses enter after inserting a string so the page is reloaded with no parameters and the queries are destroyed. look at that: http://www.parksmania.it/parco_list.php?rid=1 Adding $('form#filtroRapido').submit(function () { return false; }); doesn't work! Has someone already solved this?

    Read the article

  • Restoring and passing data to an already running instance of a .NET application

    - by mtranda
    The goal is to have an application that runs in the system tray and can either accept user input from its actual GUI (which isn't the actual issue) OR accept command line parameters (that would actually be done via a context menu in windows explorer). Now, while I'm aware that the command line parameters are not exactly possible once the application has started, I need a way to pass data to the already running application instance via some form of handler. I'm thinking maybe define and raise some sort of event? Thanks in advance.

    Read the article

  • drupal open id - how to get details

    - by Arun
    I'm try to use drupal open id module. When i used to login using any provider id(yahoo,google..) the step it goes to registration page of my site. My question is how to populate details of the user to my form without additional burden to the user ?. For ex name,email-id etc. Is there any module associated with it ?

    Read the article

  • How to test if table was updated in Zend Framework?

    - by AD
    When user opens a form to modify a record, but instead of changing information, he just clicks the Update button. Which causes the update() function to return 0. However, I consider this case a valid update task. How would I test it, so I can assign a success message? Is update() returns -1 when SQL query failed or also 0? Method: Zend_Db_Table_Abstract::update() Any ideas? Thanks

    Read the article

  • PHP - not sure how to ask - regarding variables and $_POST

    - by Phil
    I have a PHP form. The form works but I'm trying to test to see if a value other than the first item has been selected. I can't figure out how to write the If statement. $products = array( '' => 1, 'Item 2' => 2, 'Item 3' => 3, 'Item 4' => 4, 'Item 5' => 5, 'Item 6' => 6 ); $html = generateSelect('products', $products); function generateSelect($name = '', $options = array()) { $html = '<select name="'.$name.'">'; foreach ($options as $option => $value) { $html .= '<option value='.$value.'>'.$option.'</option>'; } $html .= '</select>'; return $html; } In my table, the drop down box is displayed: <tr> <td style="width:{$left_col_width}; text-align:left; vertical-align:center; padding:{$cell_padding}; font-weight:bold; {$product[3]}">{$product[0]}</td> <td style="text-align:left; vertical-align:top; padding:{$cell_padding};"><select name="{$product[1]}"> <option value="1"></option> <option value="2">Item 2</option> <option value="3">Item 3</option> <option value="4">Item 4</option> <option value="5">Item 5</option> <option value="6">Item 6</option> </select></td> </tr> I use the following if statement to check to see if someone has entered a phone number. if they have not entered a phone number, then the "Phone:" text turns red. How do I do an if statement similar to this to verify that someone has selected a product option from the drop down box? if(!empty($_POST['phone'])) { $phone[2] = clean_var($_POST['phone']); if (function_exists('htmlspecialchars')) $phone[2] = htmlspecialchars($phone[2], ENT_QUOTES); } else { $error = 1; $phone[3] = 'color:#d20128;'; } it seems simple but I can't figure it out.

    Read the article

  • Javascript variables

    - by Uli
    I'm learning Javascript right now. Can anybody tell me why the second code block traces a empty path for -launch(this)- but using the first code block it gives me the right path? "<form action='"+launchwebsite+"/subsite/' method='post' target='_blank' onsubmit='launch(this)'>" and this not: "<a onclick='launch(this)' title='launch' class='iblack' /></a></div>" Best Uli

    Read the article

  • How to click TinyMCE toolbar's button programmatically ?

    - by hongkildong
    I want to make preview button as usual form button next to submit button(as it made in most cases of "Post new topic" forms). How can I programmatically simulate toolbar's preview button click ? I tried $('#article_body_preview').click() but it didn't work. (I use jQuery lib and #article_body_preview is toolbar's preview button element )

    Read the article

  • Add multiple ActionName for button

    - by NewToBirtReporting
    I have one controller on which i have Save button click event. Im using same controller and view for Add and Edit purpose. My code is as per below [HttpPost] [Button(ButtonName = "Save")] [ActionName("Create")] [ValidateAntiForgeryToken(Salt = "PostData")] public ActionResult Save(Ntegra m_Ntegra,FormCollection form) {} As Im Using ActionName("Create") here so button can not work for ActionName("Edit"). can anyone tell me how i can achive my requirnment!! Thanks for help...... :)

    Read the article

  • login not working when changing from mysql to mysqli

    - by user1438647
    I have a code below where it logs a teacher in by matching it's username and password in the database, if correct, then log in, if incorrect, then display a message. <?php session_start(); $username="xxx"; $password="xxx"; $database="mobile_app"; $link = mysqli_connect('localhost',$username,$password); mysqli_select_db($link, $database) or die( "Unable to select database"); foreach (array('teacherusername','teacherpassword') as $varname) { $$varname = (isset($_POST[$varname])) ? $_POST[$varname] : ''; } ?> <form action="<?php echo htmlentities($_SERVER['PHP_SELF']); ?>" method="post" id="teachLoginForm"> <p>Username</p><p><input type="text" name="teacherusername" /></p> <!-- Enter Teacher Username--> <p>Password</p><p><input type="password" name="teacherpassword" /></p> <!-- Enter Teacher Password--> <p><input id="loginSubmit" type="submit" value="Login" name="submit" /></p> </form> <?php if (isset($_POST['submit'])) { $query = " SELECT * FROM Teacher t WHERE (t.TeacherUsername = '".mysqli_real_escape_string($teacherusername)."') AND (t.TeacherPassword = '".mysqli_real_escape_string($teacherpassword)."') "; $result = mysqli_query($link, $query); $num = mysqli_num_rows($result); $loged = false; while($row = mysqli_fetch_array($result)) { if ($_POST['teacherusername'] == ($row['TeacherUsername']) && $_POST['teacherpassword'] == ($row['TeacherPassword'])) { $loged = true; } $_SESSION['teacherforename'] = $row['TeacherForename']; $_SESSION['teachersurname'] = $row['TeacherSurname']; $_SESSION['teacherusername'] = $row['TeacherUsername']; } if ($loged == true){ header( 'Location: menu.php' ) ; }else{ echo "The Username or Password that you Entered is not Valid. Try Entering it Again."; } mysqli_close($link); } ?> Now the problem is that even if the teacher has entered in the correct username and password, it still doesn't let the teacher log in. When the code above was the old mysql() code, it worked fine as teacher was able to login when username and password match, but when trying to change the code into mysqli then it causes login to not work even though username and password match. What am I doing wrong?

    Read the article

  • Easiest way to get Enum in to Key Value pair.

    - by vijay.shad
    Hi, I have defined my Enums like this. public enum UserType { RESELLER("Reseller"), SERVICE_MANAGER("Manager"), HOST("Host"); private String name; private UserType(String name) { this.name = name; } public String getName() { return name; } } What should be the easiest way to get a key-value pair form the enum values?

    Read the article

< Previous Page | 425 426 427 428 429 430 431 432 433 434 435 436  | Next Page >