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• Integrate with Google calendar ?

  - by Karthick

  Hi all.I am using the following code to integrate with google calendar. CalendarService myService = new CalendarService("CalService"); myService.setUserCredentials("[email protected]", "xxxxxxx"); URL feedUrl = new URL("https://www.google.com/calendar/feeds/default/private/"); CalendarFeed resultFeed = myService.getFeed(feedUrl, CalendarFeed.class); System.out.println("Your calendars:"); for (int i = 0; i < resultFeed.getEntries().size(); i++) { CalendarEntry entry = resultFeed.getEntries().get(i); System.out.println("\t" + entry.getTitle().getPlainText()); } But it gives the Exception: Invalid credentials ERROR: JDWP Unable to get JNI 1.2 environment, jvm->GetEnv() return code = -2 JDWP exit error AGENT_ERROR_NO_JNI_ENV(183): [../../../src/share/back/util.c:820] Help me to solve this. Can anyone please list the needed jar files to adding calendar events to Google calendar

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• Explicit constructor still has default values even though a default constructor is not invoked.

  - by Phoenix

  According to my understanding a default constructor initializes the state of the object to default values, so if i provide an explicit no-arg public constructor like this then how are the values of d and e still getting initialized to zero because in this case the default constructor is not invoked. public class B extends A{ private int d; private int e; public B() { System.out.println(d); System.out.println(e); } } EDIT:: The only thing default constructor does is call to super() then how come if i have a explicitly mentioned a constructor here and A has a protected variable say c which is initialized to 17 in its constructor. Should I not be explicitly calling super() to be able to see that change since I'm using my own constructor ? Why is B still getting the value of 17 through inheritance ?

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• Creation obex connection without service discovery

  - by Vio

  Hello there my problem is this,i want to create an obex connection but i already know my server adress.The problem is how to get the connection url without service discovery.I use a normal java project for my server side and a midlet project for my client side.I will post the code maybe it helps. Server connection UUID uuid=new UUID("8841",true); String url="btgoep://localhost:"+uuid+";name=FTP;authenticate=false;master=false;encrypt=false"; SessionNotifier sn=(SessionNotifier)Connector.open(url); System.out.println("Now waiting for a client to connect"); sn.acceptAndOpen(this); System.out.println("A client is now connected"); When i try to connect with the client it doesn't get to the last line :(....any ideas why?Hope u can help...thanks

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• doubt in Exceptions

  - by Ajay Singh

  class MyException extends Exception { MyException() {} MyException(String msg) { super(msg);} } public class NewException { static void f() throws MyException { System.out.println("throwing exception from f()"); throw new ClassCastException(); } static void g() throws MyException { System.out.println("throwing exception from g()"); throw new MyException("parametrized "); } public static void main(String ...strings ) { try { f(); } catch(MyException e) { e.printStackTrace(System.out); } try { g(); } catch(MyException e) { e.printStackTrace(System.out); } } } In the function f() iam specifying that "MyException " exception will be thrown and actually iam throwing some other exception which has no relation with MyException but still the compiler does not report any complain.Why is it so??

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• Polymorphic behavior not being implemented

  - by Garrett A. Hughes

  The last two lines of this code illustrate the problem: the compiler works when I use the reference to the object, but not when I assign the reference to an array element. The rest of the code is in the same package in separate files. BioStudent and ChemStudent are separate classes, as well as Student. package pkgPoly; public class Poly { public static void main(String[] arg) { Student[] stud = new Student[3]; // create a biology student BioStudent s1 = new BioStudent("Tom"); // create a chemistry student ChemStudent s2 = new ChemStudent("Dick"); // fill the student body with studs stud[0] = s0; stud[1] = s1; // compiler complains that it can't find symbol getMajor on next line System.out.println("major: " + stud[0].getMajor() ); // doesn't compile; System.out.println("major: " + s0.getMajor() ); // works: compiles and runs correctly } }

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• Accessing variablss through a different class within the constructor of latter classes of an object

  - by Haxed

  In the code below, I've added two lines that print output. The first line prints junk as usual, but surprisingly the second one gives me a compilation error. Why? class Student { private String name; public Student(String name){ this.name = name; } public String getName(){ return name; } } class StudentServer { public StudentServer(){ Student[] s = new Student[30]; s[0] = new Student("Nick"); // LINE 01: This compiles, although prints junk System.out.println(s[0]); // LINE 02: I get a error called cannot find symbol System.out.println(s[0].getName()); } public static void main(){ new StudentServer(); } } Many Thanks

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• What is the difference between panic and an assert?

  - by acidzombie24

  Go doesn't provide assertions. They are undeniably convenient, but our experience has been that programmers use them as a crutch to avoid thinking about proper error handling and reporting. However it has print and println which does panic like print, aborts execution after printing panicln like println, aborts execution after printing Isnt that the same thing as an assert? Why would they claim the above but have panic? i can see it leading to the same problems but adding an error msg to the end of it which can easily be abused. Am i missing something?

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• Array of an array (Database)

  - by Anne Mah Li'en

  I am trying to print out an array of an array from database Below are my codes. I am able to retrieve all the values from the first array. But error occurs when I am trying to retrieve the 2nd array from database. <% ArrayList<Questionnaire> allCategories =QuestionnaireController.getQuestionnaireByCategoryAll(); for(int i=0;i<allCategories.size();i++){ Questionnaire allCategoriesQuestionnaire=allCategories.get(i); out.println("<div class=\"silverheader\">" + "<a href= \"\">" + allCategoriesQuestionnaire.getCategory() + "</a>" + "</div>" + "<div class=\"submenu\">" + "ArrayList<Questionnaire> CategoriesSustainability =QuestionnaireController.getQuestionnaireByCategorySustainability();" + out.println(CategoriesSustainability.get(0).getCategory()); + "<br />" + "</div>"); } %>

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• add two float values in java

  - by user1845286

  acually i try to add two float values in java like this import java.text.DecimalFormat; class ExactDecimalValue { final strictfp static public void main(String... arg) { float f1=123.00000f; float f2=124.00000f; float f3=f1+f2; System.out.println(f1+f2); System.out.println("sum of two floats:"+f3); /*my expected output is:247.00000 but comming output is:247.0 and 247*/ } } Now what i can do to get the value in this format:247.00000. please any one help me. Thanks & Regards venkatesh

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• Print the next X number of lines in Scala

  - by soulesschild

  Trying to learn Scala using the Programming in Scala book and they have a very basic example for reading lines from a file. I'm trying to expand on it and read a file line by line, look for a certain phrase, then print the next 6 lines following that line if it finds the line. I can write the script easily enough in something like java or Perl but I have no idea how to do it in Scala (probably because I'm not very familiar with the language yet...) Here's the semi adapted sample code from the Programming in Scala book, import scala.io.Source if(args.length>0) { val lines = Source.fromFile(args(0)).getLines().toList for(line<-lines) { if(line.contains("secretPhrase")) { println(line) //How to get the next lines here? } } } else Console.err.println("Pleaseenterfilename")

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• Print number series in java

  - by user1898282

  I have to print the series shown below in java: ***1*** **2*2** *3*3*3* 4*4*4*4 My current implementation is: public static void printSeries(int number,int numberOfCharsinEachLine){ String s="*"; for(int i=1;i<=number;i++){ int countOfs=(numberOfCharsinEachLine-(i)-(i-1))/2; if(countOfs<0){ System.out.println("Can't be done"); break; } for(int j=0;j<countOfs;j++){ System.out.print(s); } System.out.print(i); for(int k=1;k<i;k++){ System.out.print(s); System.out.print(i); } for(int j=0;j<countOfs;j++){ System.out.print(s); } System.out.println(); } } But there are lot of for loops, so I'm wondering whether this can be done in a better way or not?

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• Java : Using parent class method to access child class variable

  - by Jayant

  I have the following scenario : public class A { private int x = 5; public void print() { System.out.println(x); } } public class B extends A { private int x = 10; /*public void print() { System.out.println(x); }*/ public static void main(String[] args) { B b = new B(); b.print(); } } On executing the code, the output is : 5. How to access the child class(B's) variable(x) via the parent class method? Could this be done without overriding the print() method (i.e. uncommenting it in B)? [This is important because on overriding we will have to rewrite the whole code for the print() method again]

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• i have a arraylist where i am verifying particular object is existing or not but even it exists it always returns false

  - by Raghavender Reddy

  hi i have class called userdata which returns the Userarraylist which is of type User. when ever i try to use contains method to check particular property is existing or not it always returns false why? Actually i want the array list to be generic which should return the objects that are set in array list. String className = data.getUserData().get(0).getClass().getSimpleName(); if(className.equalsIgnoreCase("User")) { ArrayList<User> userdata=new ArrayList(); userdata = data.getUserData(); System.out.println(data.getUserData().contains(u.getUserId())); if(userdata.contains(u.getUserName())) { System.out.println(userdata.get(0).getEmailId()); } }

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• IP Address not obtained in java

  - by nilesh

  This code used to return my local ip address as 192.xxx.x.xxx but now it is returning 127.0.0.1 . Please help me why the same code is returning different value. Is there something that I need to watch at linux OS. import java.util.*; import java.lang.*; import java.net.*; public class GetOwnIP { public static void main(String args[]) { try{ InetAddress ownIP=InetAddress.getLocalHost(); System.out.println("IP of my system is := "+ownIP.getHostAddress()); }catch (Exception e){ System.out.println("Exception caught ="+e.getMessage()); } } }

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• Log user authentication in grails/acegi

  - by xain

  Hi, where can I put a println in order to register a user's successful authentication in grails using acegi ? Thanks

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• In scala can I pass repeated parameters to other methods?

  - by Fred Haslam

  Here is something I can do in java, take the results of a repeated parameter and pass it to another method: public void foo(String ... args){bar(args);} public void bar(String ... args){System.out.println("count="+args.length);} In scala it would look like this: def foo(args:String*) = bar(args) def bar(args:String*) = println("count="+args.length) But this won't compile, the bar signature expects a series of individual strings, and the args passed in is some non-string structure. For now I'm just passing around arrays. It would be very nice to use starred parameters. Is there some way to do it?

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• call method from main class, gives error

  - by user557039

  try to call method ss from class from it return me error, Blockquote Exception in thread "main" java.lang.NullPointerException at teste1.exp.ss(exp.java:16) at teste1.Main.main(Main.java:64) Java Result: 1 Blockquote <pre> public class Main { public static void main(String[] arguments) { ................... private static String[] ff; exp mega = new exp(); mega.ss(ff); } class exp { public void ss (String gvanswer[]){ String answer[] = new String[3]; answer[0] = "pacific "; answer[1] = "everest"; answer[2] = "amazon "; if (gvnswer[0].equals("pacific")) {System.out.println("eeeeeeeeeeeeee ");} if (gvanswer[1].equals(answer[1])){System.out.println("l ");} }

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• A strange issue... No code changes getting reflected.

  - by sachin

  I am using netbeans to develop an applet, i have a piece of code which looked like this: ipAddresss = DEFAULT_IP; System.out.println("portlet.services.hostname:" + ipAddresss); Now I changed it to something like this: ipAddresss = DEFAULT_IP; System.out.println("portlet.services.hostname using default IP Address:" + ipAddresss); But no matter what I do, it sill keep on printing: portlet.services.hostname:null I have tried deleting all .netbeans folder from documents and settings, tried creating new project, but now i am completely baffled by this issue... So, the problem is, no matter what I do, no change is getting reflected when I run the program. Can there be a java applet cache, netbeans cache, i am not sure why...

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• Heap property of this array

  - by davit-datuashvili

  From programming pearls, it is known that array[1...n] has heap property if for all 2<=i<=n x[i/2]<=x[i]. Here is my code: import java.math.*; public class Heap { public static void main(String[]args){ int x[]=new int[]{12,20,15,29,23,17,22,35,40,26,51,19}; int i=1; while (i<x.length) { if (x[Math.round(i/2)]<=x[i]) System.out.println("heap"); i++; } System.out.println("not heap"); } } Here I used Math.round because 4/2 and 5/2 is same and =2. When I compile this code it shows me at last line that it is not heap. Maybe because the index starts from 1 and we don't pay attention to index 0, yes?

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• How to leave out some System.out/logging statements while executing java code?

  - by iamrohitbanga

  In C++ if we do not want some statements to compile into code that ships like assert function calls, we control their compilation through #ifndef preprocessor directives. How do we do this in Java? I have some System.out.println() statements for debugging which I would like to remove for the final code. one way is to make them execute conditionally under the affect of a boolean variable. Is there a better way of doing this? As I have a java swing application I can turn off the System.out.println statements without affecting the output. What is the method of doing this?

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• Why is the output like this?

  - by javatechi

  class another { public void method(Object o) { System.out.println("This is in method which takes object"); } public void method(String s) { System.out.println("This is method which takes string"); } } public class NewClass { public static void main(String args[]) { another an = new another(); an.method(null); } } When I try to execute this, I get This is method which takes string as the output. Why not "This is in method which takes object"? Object can also be null and string can also be null, why doesn't it invoke first method?

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• How is `toString` in `scala.Enumeration$Value` implemented?

  - by Red Hyena

  I have an enum Fruit defined as: object Fruit extends Enumeration { val Apple, Banana, Cherry = Value } Now printing values of this enum, on Scala 2.7.x gives: scala> Fruit foreach println line1$object$$iw$$iw$Fruit(0) line1$object$$iw$$iw$Fruit(1) line1$object$$iw$$iw$Fruit(2) However the same operation on Scala 2.8 gives: scala> Fruit foreach println warning: there were deprecation warnings; re-run with -deprecation for details Apple Banana Cherry My question is: How is the method toString in Enumeration in Scala 2.8 is implemented? I tried looking into the source of Enumeration but couldn't understand anything.

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• comma in regex in String.replaceAll() method?

  - by kknight

  My code tries to replace "," with "/" in a string. Should I escape "," in the regex string? Both of the two code snippets generated the same results, so I am confused. Code snippet 1: String test = "a,bc,def"; System.out.println(test.replaceAll("\\,", "/")); Code snippet 2: String test = "a,bc,def"; System.out.println(test.replaceAll(",", "/")); Should I use "," or "\,"? Which is safer? Thanks.

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• Bash redirection: save stderr/stdout to different files and still print them out on a console

  - by Alby

  Here is a simple program. class Redirection { public static void main (String args[]){ System.out.println("Hello World_Stdout"); System.err.println("Hello World_Stderr"); } } I want to see the all the outputs on a console, but at the same time I want to store stdout and stderr in different files. I tried the following command, to no avail. $java Redirection 3>&1 2>stderr 1>stdout 1>&3 2>&3 stderr& stdout files have the file size of 0. So basically I want to do what "tee" command does but I also want to capture stderr as well.

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• What is the differance between those two Strings in Java

  - by user1816808

  why when we declare string in java we can't use == to compare this string and always will turn to false while if we initialize the string from the beginning it will be true . for example : import java.util.Scanner; public class MyString { /** * @param args */ public static void main(String[] args) { // TODO Auto-generated method stub Scanner input = new Scanner(System.in); String s = input.nextLine(); if(s=="Hello") system.out.println("Hello"); String d = "Hello"; if(d=="Hello") system.out.println("Hello"); } } I need an explanation please ??

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