Extract a specific string from a curl'd result
- by allentown
Given this curl command:
curl --user-agent "fogent" --silent -o page.html "http://www.google.com/search?q=insansiate"
* Spelling is intentionally incorrect. I want to grab the suggestion as my result.
I want to be able to either grep into the page.html file perhaps with grep -oE or pipe it right from curl and never store a file.
The result should be: 'instantiate'
I need only the word 'instantiate', or the phrase, whatever google is auto correcting, is what I am after.
Here is the basic html that is returned:
<span class=spell style="color:#cc0000">Did you mean: </span><a href="/search?hl=en&ie=UTF-8&&sa=X&ei=VEMUTMDqGoOINraK3NwL&ved=0CB0QBSgA&q=instantiate&spell=1"class=spell><b><i>instantiate</i></b></a> <span class=std>Top 2 results shown</span>
So perhaps from/to of the string below, which I hope is unique enough to cover all my bases.
class=spell><b><i>instantiate</i></b></a>
I keep running into issues with greedy grep; perhaps I should run it though an html prettify tool first to get a line break or 50 in there. I don't know of any simple way to do so in bash, which is what I would ideally like this to be in. I really don't want to deal with firing up perl, and making sure I have the correct module.
Any suggestions, thank you?
