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  • MVC route with id and sub-action

    - by Dan Revell
    I can't figure out what I need to do with MVC routing to make this work Here's my one route: routes.MapHttpRoute( name: "DefaultApi", routeTemplate: "{controller}/{id}/{action}", defaults: new { id = RouteParameter.Optional, action = RouteParameter.Optional } ); The request /Shipments/ works great. The request /Shipments/3/Packages works great. The request /Shipments/3 however fails with the error: Multiple actions were found that match the request: System.Linq.IQueryable`1[Api.Controllers.RequisitionsController+PackageRequisitionWithTracking] GetPackageRequisitions(Int32) on type Api.Controllers.RequisitionsController Api.Models.ShipmentRequisition GetShipmentRequisitions(Int32) on type Api.Controllers.RequisitionsController It can't seem to differentiate between: public ShipmentRequisition GetShipmentRequisitions(int id) and [ActionName("Packages")] public IQueryable<PackageRequisitionWithTracking> GetPackageRequisitions(int id) I would have thought the lack of action name on the get shipment by id would allow that route to work.

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  • JSP template inheritance

    - by Ryan
    Coming from a background in Django, I often use "template inheritance", where multiple templates inherit from a common base. Is there an easy way to do this in JSP? If not, is there an alternative to JSP that does this (besides Django on Jython that is :) base template <html> <body> {% block content %} {% endblock %} </body> <html> basic content {% extends "base template" %} {% block content %} <h1>{{ content.title }} <-- Fills in a variable</h1> {{ content.body }} <-- Fills in another variable {% endblock %} Will render as follows (assuming that conten.title is "Insert Title Here", and content.body is "Insert Body Here") <html> <body> <h1>Insert title Here <-- Fills in a variable</h1> Insert Body Here <-- Fills in another variable </body> <html>

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  • Proper way to use multiple stylesheets...so it WORKS?

    - by thatryan
    I am making a site where I need to have styles separated for layout, colors and typography. So basically I took my main style sheet and just copied it 3 times, and in removed everything but coloring from one, everything but type related in another and etc. But when I link to them now there must be some cascade issue or something, because a lot of the type stuff is not being applied. Is there a proper way to do this?

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  • Custom Web Control - ParseChildren & Resource Objects

    - by Raybiez
    I hope someone can help me. I have the following custom server control: [ParseChildren(true)] public class MyControl : WebControl, INamingContainer { [PersistenceMode(PersistenceMode.InnerProperty)] public string MyProperty { get;set; } } It works perfectly with the following mark-up: <acme:MyControl runat="sever"> <MyProperty>Test String</MyProperty> </acme:MyControl> But if I try to localise the property string, I get a parse error: <acme:MyControl runat="sever"> <MyProperty><%=(string)GetLocalResourceObject("MyResourceKey") %></MyProperty> </acme:MyControl> Even if I cast the type, ASP.NET indicates that the property cannot accept controls as children. How should the expression look like if I want to localise it? I can make the property accessible as an attribute of the control's tag, but I prefer the mark-up above, it looks more elegant and clean. Thanks

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  • PHP registration script: verifying and telling the user what went wrong

    - by Maxime
    Hi, I'm building a registration script and I want to insert the user's input (username, mail) ONLY if it's not already in the database. What I usually do in such cases is a request to see if something's already there, something like: "SELECT * FROM things WHERE thing_name = '$treated_user_input'". I have two fields that need to be unique this time though. Is there a way to do only one SELECT request and still be able to tell the user exactly what field went wrong? Or do I have to do one request per unique field? Thanks for your answers.

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  • Publish failed in Web Application Project (MVC)

    - by Stuck
    I usually use the "Publish" feature in VS 2008 to get the correct files and so on that I can publish to my website. But from time to time publish fails without any good error message at all. I know that it can be a couple of different reasons but I am starting to grow really tired with this now. Can anyone teach me how to build the website from the command line? As I said it is a MVC project. Can I use the aspnet_compiler for this? What parameters should I use to simulate the same behavior as a "Publish"?

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  • Best practice to send secure information over e-mail?

    - by Zolomon
    I have to send sensitive information (name, address, social security number etc.) collected from a website, that has been entered by a user, to an e-mail address. What is the best course of action to make the information secure and easy to extract on the receiver side? Edit: I will be using ASP.NET for the website, not sure what it has for capabilities on this matter. Edit: If I decide to store the information in a database and just send a mail when a new entry has been made, would this be better? And create some secure way to dump the information instead.

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  • Looking for a lean WYSIWYG inline editor for CMS projects that includes an image upload feature?

    - by Roeland
    Hey guys, I am looking to find a lean WYSIWYG inline editor. The main required feature is image uploading. A simple way to upload an image to the server and use it in the content being editted. I have come across a whole bunch of editors but nothing I liked so far. I am looking for something open source and free. So far I have checked out TinyMCE which is free.. untill you need image uploading capabilities. Ckeditor looks great.. uses jquery.. but requires you to have your own server side script to upload images. They barely give any documentation on how to do this. There were a few others, but the bottom line was that I cant find anything that is simple with out of the box image uploading capabilities. Thanks for any advice you may give!

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  • Radio buttons being reset in FF on cache-refresh

    - by Andrew Song
    (This is technically an addendum to an earlier StackOverflow question I had posted, but my original post asked a different question which doesn't really cover this topic -- I don't want to edit my older question as I feel this is different enough to merit its own page) While browsing my website in Firefox 3.5 (and only FF3.5), I come across a page with two radio buttons that have the following HTML code: <input id="check1" type="radio" value="True" name="check" checked="checked"/> <input id="check2" type="radio" value="False" name="check"/> This page renders as expected, with 'check1' checked and 'check2' unchecked. When I then go to refresh the page by pressing Control + R, the two radio buttons render, but they are both unchecked even though the raw HTML code is the same (as above). If I do a cache-miss refresh (via Control + F5 or Control + Shift + R), the page returns back to the way you'd expect it. This is not a problem in any other browser I've tried except FF3.5. What is causing these radio buttons to be reset on a normal refresh? How can I avoid this?

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  • Searching in Ruby on Rails - How do I search on each word entered and not the exact string?

    - by bgadoci
    I have built a blog application w/ ruby on rails and I am trying to implement a search feature. The blog application allows for users to tag posts. The tags are created in their own table and belong_to :post. When a tag is created, so is a record in the tag table where the name of the tag is tag_name and associated by post_id. Tags are strings. I am trying to allow a user to search for any word tag_name in any order. Here is what I mean. Lets say a particular post has a tag that is 'ruby code controller'. In my current search feature, that tag will be found if the user searches for 'ruby', 'ruby code', or 'ruby code controller'. It will not be found if the user types in 'ruby controller'. Essentially what I am saying is that I would like each word entered in the search to be searched for, not necessarily the 'string' that is entered into the search. I have been experimenting with providing multiple textfields to allow the user to type in multiple words, and also have been playing around with the code below, but can't seem to accomplish the above. I am new to ruby and rails so sorry if this is an obvious question and prior to installing a gem or plugin I thought I would check to see if there was a simple fix. Here is my code: View: /views/tags/index.html.erb <% form_tag tags_path, :method => 'get' do %> <p> <%= text_field_tag :search, params[:search], :class => "textfield-search" %> <%= submit_tag "Search", :name => nil, :class => "search-button" %> </p> <% end %> TagsController def index @tags = Tag.search(params[:search]).paginate :page => params[:page], :per_page => 5 @tagsearch = Tag.search(params[:search]) @tag_counts = Tag.count(:group => :tag_name, :order => 'count_all DESC', :limit => 100) respond_to do |format| format.html # index.html.erb format.xml { render :xml => @tags } end end Tag Model class Tag < ActiveRecord::Base belongs_to :post validates_length_of :tag_name, :maximum=>42 validates_presence_of :tag_name def self.search(search) if search find(:all, :order => "created_at DESC", :conditions => ['tag_name LIKE ?', "%#{search}%"]) else find(:all, :order => "created_at DESC") end end end

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  • Consume a JSON webservice and process data in Android

    - by user1783391
    I am trying to consume a the webservice below http://62.253.195.179/disaster/webservices/login.php?message=[{"email":"[email protected]","password":"welcome"}] This returns a JSON array [{"companyuserId":"2","name":"ben stein","superiorname":"Leon","departmentId":"26","departmentname":"Development","companyId":"23","UDID":"12345","isActive":"1","devicetoken":"12345","email":"[email protected]","phone":"5456465465654","userrole":"1","chngpwdStatus":"1"}] My code is below try{ String weblink = URLEncoder.encode("http://62.253.195.179/disaster/webservices/login.php?message=[{\"email\":\"[email protected]\",\"password\":\"welcome\"}]"); HttpParams httpParameters = new BasicHttpParams(); int timeoutConnection = 7500; HttpConnectionParams.setConnectionTimeout(httpParameters, timeoutConnection); int timeoutSocket = 7500; HttpConnectionParams.setSoTimeout(httpParameters, timeoutSocket); HttpClient client = new DefaultHttpClient(httpParameters); HttpGet request = new HttpGet(); URI link = new URI(weblink); request.setURI(link); HttpResponse response = client.execute(request); BufferedReader rd = new BufferedReader(new InputStreamReader( response.getEntity().getContent())); result = rd.readLine(); JSONObject myData = new JSONObject(result); JSONArray jArray = myData.getJSONArray(""); JSONObject steps = jArray.getJSONObject(0); String name = steps.getString("name"); } catch (JSONException e) { e.printStackTrace(); } But its not working and I am not 100% sure this is the best way to do it. 11-10 10:49:55.489: E/AndroidRuntime(392): java.lang.IllegalStateException: Target host must not be null, or set in parameters.

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  • Getting 404 in Android app while trying to get xml from localhost

    - by Patrick
    This must be something really stupid, trying to solve this issue for a couple of days now and it's really not working. I searched everywhere and there probably is someone with the same problem, but I can't seem to find it. I'm working on an Android app and this app pulls some xml from a website. Since this website is down a lot, I decided to save it and run it locally. Now what I did; - I downloaded the kWs app for hosting the downloaded xml file - I put the file in the right directory and could access it through the mobile browser, but not with my app (same code as I used with pulling it from some other website, not hosted by me, only difference was the URL obviously) So I tried to host it on my PC and access it with my app from there. Again the same results, the mobile browsers had no problem finding it, but the app kept saying 404 Not Found: "The requested URL /test.xml&parama=Someone&paramb= was not found on this server." Note: Don't mind the 2 parameters I am sending, I needed that to get the right stuff from the website that wasn't hosted by me. My code: public String getStuff(String name){ String URL = "http://10.0.0.8/test.xml"; ArrayList<NameValuePair> params = new ArrayList<NameValuePair>(2); params.add(new BasicNameValuePair("parama", name)); params.add(new BasicNameValuePair("paramb", "")); APIRequest request = new APIRequest(URL, params); try { RequestXML rxml = new RequestXML(); AsyncTask<APIRequest, Void, String> a = rxml.execute(request); ... } catch(Exception e) { e.printStackTrace(); } return null; } That should be working correctly. Now the RequestXML class part: class RequestXML extends AsyncTask<APIRequest, Void, String>{ @Override protected String doInBackground(APIRequest... uri) { HttpClient httpclient = new DefaultHttpClient(); String completeUrl = uri[0].url; // ... Add parameters to URL ... HttpGet request = null; try { request = new HttpGet(new URI(completeUrl)); } catch (URISyntaxException e1) { e1.printStackTrace(); } HttpResponse response; String responseString = ""; try { response = httpclient.execute(request); StatusLine statusLine = response.getStatusLine(); if(statusLine.getStatusCode() == HttpStatus.SC_OK){ // .. It crashes here, because statusLine.getStatusCode() returns a 404 instead of a 200. The xml is just plain xml, nothing special about it. I changed the contents of the .htaccess file into "ALLOW FROM ALL" (works, cause the browser on my mobile device can access it and shows the correct xml). I am running Android 4.0.4 and I am using the default browser AND chrome on my mobile device. I am using MoWeS to host the website on my PC. Any help would be appreciated and if you need to know anything before you can find an answer to this problem, I'll be more than happy to give you that info. Thank you for you time! Cheers.

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  • Does this introduce security vulnerabilities?

    - by mcmt
    I don't think I'm missing anything. Then again I'm kind of a newbie. def GET(self, filename): name = urllib.unquote(filename) full = path.abspath(path.join(STATIC_PATH, filename)) #Make sure request is not tricksy and tries to get out of #the directory, e.g. filename = "../.ssh/id_rsa". GET OUTTA HERE assert full[:len(STATIC_PATH)] == STATIC_PATH, "bad path" return open(full).read()

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  • problem with Infopath web services

    - by AB
    I want to have some url for my infopath form and give that link to user instead of going to form library and click new...how is it possible? Also when I created Infopath form I have given some text fields and button, I don't want the Infopath services buttons(Save,save as...) how I cna remove those? Any suggestions would really be appreciated...Thanks

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  • Multiple items with PayPal button and PHP

    - by user146780
    I'm building a website where I basically want my checkout to work like this website: http://www.solutionkaizen.com/html/boutique.php It allows you to enter the quantity for each item and then press a button which brings you to PayPal and lists how many Products you have. On PayPal's website, all the info I found seems to lead to me needing a shopping cart. If this is absolutely necessary, how could I implement that? Thanks

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  • Image upload and Manipulation in Django

    - by Saransh Mohapatra
    I am trying upload images and than create an thumbnail of it and than store both in S3. After the file has been uploaded i am first uploading it to S3 and than trying to create thumbnail but it doesn't work as than PIL is not able to recognise the image. And secondly if I create the thumbnail first than while uploading original image I get EOF. I think Django allows just once for the uploaded files to be used only once....Please kindly tell me a way to do so....Thanks in advance

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  • Django: How do I get logging working?

    - by swisstony
    I've added the following to my settings.py file: import logging ... logging.basicConfig(level=logging.DEBUG, format='%(asctime)s %(levelname)s %(message)s', filename=os.path.join(rootdir, 'django.log'), filemode='a+') And in views.py, I've added: import logging log = logging.getLogger(__name__) ... log.info("testing 123!") Unfortunately, no log file is being created. Any ideas what I am doing wrong? And also is their a better method I should be using for logging? I am doing this on Webfaction.

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