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  • SQL : where vs. on in join

    - by Erwin
    Perhaps a dumb question, but consider these 2 tables : T1 Store Year 01 2009 02 2009 03 2009 01 2010 02 2010 03 2010 T2 Store 02 Why is this INNER JOIN giving me the results I want (filtering the [year] in the ON clause) : select t1.* from t1 inner join t2 on t1.store = t2.store and t1.[year] = '2009' Store Year 02 2009 And why the LEFT OUTER JOIN include records of year 2010 ? select t1.* from t1 left outer join t2 on t1.store = t2.store and t1.year = '2009' where t2.store is null 01 2009 03 2009 01 2010 02 2010 03 2010 And I have to write the [year] filter in the 'WHERE' clause : select t1.* from t1 left outer join t2 on t1.store = t2.store where t2.store is null and t1.year = '2009' 01 2009 03 2009 Like I said, perhaps a dumb question, but it's bugging me !

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  • SQL Server 2008 ContainsTable, CTE, and Paging

    - by David Murdoch
    I'd like to perform efficient paging using containstable. The following query selects the top 10 ranked results from my database using containstable when searching for a name (first or last) that begins with "Joh". DECLARE @Limit int; SET @Limit = 10; SELECT TOP @Limit c.ChildID, c.PersonID, c.DOB, c.Gender FROM [Person].[vFullName] AS v INNER JOIN CONTAINSTABLE( [Person].[vFullName], (FullName), IS ABOUT ( "Joh*" WEIGHT (.4), "Joh" WEIGHT (.6)) ) AS k3 ON v.PersonID = k3.[KEY] JOIN [Child].[Details] c ON c.PersonID = v.PersonID JOIN [Person].[Details] p ON p.PersonID = c.PersonID ORDER BY k3.RANK DESC, FullName ASC, p.Active DESC, c.ChildID ASC I'd like to combine it with the following CTE which returns the 10th-20th results ordered by ChildID (the primary key): DECLARE @Start int; DECLARE @Limit int; SET @Start = 10; SET @Limit = 10; WITH ChildEntities AS ( SELECT ROW_NUMBER() OVER (ORDER BY ChildID) AS Row, ChildID FROM Child.Details ) SELECT c.ChildID, c.PersonID, c.DOB, c.Gender FROM ChildEntities cte INNER JOIN Child.Details c ON cte.ChildID = c.ChildID WHERE cte.Row BETWEEN @Start+1 AND @Start+@Limit ORDER BY cte.Row ASC

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  • Microsoft SQL Server 2005 Inserting into tables from child procedure which returned multiple tables

    - by Kevin
    I've got a child procedure which returns more than table. child: PROCEDURE KevinGetTwoTables AS BEGIN SELECT 'ABC' Alpha, '123' Numeric SELECT 'BBB' Alpha, '123' Numeric1, '555' Numeric2 END example: PROCEDURE KevinTesting AS BEGIN DECLARE @Table1 TABLE ( Alpha varchar(50), Numeric1 int ) DECLARE @Table2 TABLE ( Alpha varchar(50), Numeric1 int, Numeric2 int ) --INSERT INTO @Table1 EXEC KevinGetTwoTables END

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  • SQL is this equvelent to a LEFT JoIn?

    - by Jim
    Is this equvelent to a LEFT JOIN? select distinct a.name, b.name from tableA a, (select name from tableB) as b It seems as though there is no link between the two tables. Is there an easier / more efficient way to write this?

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  • Linq-to-SQL statement issue

    - by Anicho
    I am basically looking to bind a search query to a gridview which is nice, but this must be done by a users input query (sort of like a search function). I can get single values and rows returned, but how would I get it to search all columns in my database for the inputted values and return it? My code so far is: Void SearchFunction() { TiamoDataContext context = new TiamoDataContext(); var search = from p in context.UserProfiles where = p.DanceType == UserSearchString select p; UserSearchGrid.DataSource = search; UserSearchGrid.DataBind(); } I tried p.equals but am pretty sure thats not the way to go about it.

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  • MS SQL Database with clustered GUID PKs - switch clustered index or switch to sequential (comb) GUID

    - by Eyvind
    We have a database in which all the PKs are GUIDs, and most of the PKs are also the clustered index for the table. We know that this is bad (due to the random nature of GUIDs). So, it seems there are basically two options here (short of throwing out GUIDs as PKs altogether, which we cannot do (at least not at this time)). We could change the GUID generation algorithm to e.g. the one that NHibernate uses, as detailed in this post, or we could, for the tables that are under the heaviest use, change to a different clustered index, e.g. an IDENTITY column, and keep the "random" GUIDs as PKs. Is it possible to give any general recommendations in such a scenario? The application in question has 500+ tables, the largest one presently at about 1,5 million rows, a few tables around 500 000 rows, and the rest significantly lower (most of them well below 10K). Furthermore, the application is installed at several customer sites already, so we have to take any possible negative effects for existing customer into consideration. Thanks!

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  • "dig +trace fqdn" and "dig fqdn" do not give the same result on a LAN with windows DNS server, why?

    - by Sulliwane
    in my company LAN I have a Ubuntu 14.04 server running in Virtualbox (as guest) on a Windows 7 (the host) with network interface bridged (so the Ubuntu server belongs to the LAN, with its ip: 192.168.1.85). I have a website on this server: mywebsite.com The gateway for the LAN to the internet is 192.168.1.1 (Cisco 1841)--188.188.188.254 as public IP. There is a Windows 2008 server that acts as DNS server and DHCP server on the LAN. I added a Forward zone "mywebsite.com" with A record - 192.168.1.85. Outside the LAN, mywebsite.com has public Dns records that point on the Cisco 1841 public IP (188.188.188.254) Now when I ping mywebsite.com from the lan, I quickly get 192.168.1.85. But when I'm connecting through the browser on the clients, it's not always fast. So I'm wondering: Are my requests really/directly resolved and forwarded to 192.168.1.85, OR are they sent out of the LAN, and then forwarded back to the CISCO public 188.188.188.254:80 and NAT to the Ubuntu server before being served ??? To try to answer this question, I looked for tracking the DNS request from my linux client on the LAN: v@v-ss9:~$ dig mywebsite.com ; <<>> DiG 9.9.5-3-Ubuntu <<>> mywebsite.com ;; global options: +cmd ;; Got answer: ;; ->>HEADER<<- opcode: QUERY, status: NOERROR, id: 24850 ;; flags: qr aa rd ra; QUERY: 1, ANSWER: 1, AUTHORITY: 0, ADDITIONAL: 1 ;; OPT PSEUDOSECTION: ; EDNS: version: 0, flags:; udp: 4000 ;; QUESTION SECTION: ;mywebsite.com. IN A ;; ANSWER SECTION: mywebsite.com. 3600 IN A 192.168.1.85 ;; Query time: 1 msec ;; SERVER: 127.0.1.1#53(127.0.1.1) ;; WHEN: Fri Aug 22 09:50:16 CST 2014 ;; MSG SIZE rcvd: 66 This answer looks right: 192.168.1.85. But then look at this: v@v-ss9:~$ dig +trace mywebsite.com ; <<>> DiG 9.9.5-3-Ubuntu <<>> +trace mywebsite.com ;; global options: +cmd . 12955 IN NS h.gtld-servers.net. . 12955 IN NS g.gtld-servers.net. . 12955 IN NS m.gtld-servers.net. . 12955 IN NS i.gtld-servers.net. . 12955 IN NS l.gtld-servers.net. . 12955 IN NS k.gtld-servers.net. . 12955 IN NS j.gtld-servers.net. . 12955 IN NS d.gtld-servers.net. . 12955 IN NS b.gtld-servers.net. . 12955 IN NS c.gtld-servers.net. . 12955 IN NS a.gtld-servers.net. . 12955 IN NS e.gtld-servers.net. . 12955 IN NS f.gtld-servers.net. ;; Received 516 bytes from 127.0.1.1#53(127.0.1.1) in 18 ms mywebsite.com. 172800 IN NS ns3.rmi.fr. mywebsite.com. 172800 IN NS ns4.rmi.fr. CK0POJMG874LJREF7EFN8430QVIT8BSM.com. 86400 IN NSEC3 1 1 0 - CK0QFMDQRCSRU0651QLVA1JQB21IF7UR NS SOA RRSIG DNSKEY NSEC3PARAM CK0POJMG874LJREF7EFN8430QVIT8BSM.com. 86400 IN RRSIG NSEC3 8 2 86400 20140825045016 20140818034016 6122 com. Imq8K9xlvFXlB4IjUkdxOc5YHoTEhqSQUlRSJ9QCIhd9wzGpWJ54AfVf WJ0SUKThalpzqS0cXdLGtNmuYgqLfwUMjpUlT4c+zJyx7I4QMPLImQZh Ov0xy3mUr7dLlymAJYGs9dLI2IaheLvpKTBwaV1gAvo8QEkU8VRiJ7gW 9dk= U0PIA23FHMVPTKSDHC9PJ1BEA9SIB65R.com. 86400 IN NSEC3 1 1 0 - U0PL33R61V6TCCPBS1171PROP57ASRD9 NS DS RRSIG U0PIA23FHMVPTKSDHC9PJ1BEA9SIB65R.com. 86400 IN RRSIG NSEC3 8 2 86400 20140825043502 20140818032502 6122 com. qsC5sJbwklao+OedCHpcYo56aQaY0N+7peKmPu8szvjAQoJFRWyuDfAh Nw/gvHXEMzG7tYLriQGVfsiK8GZdPXyG4Ghe1MNN4jOZnSahkT5LjlqL 5QyGC0QiClRMPDAYjUOFGQDkjOJcJYvTNkEyXC2BEpfLI5SwCbYqwqg3 RkE= ;; Received 585 bytes from 192.41.162.30#53(l.gtld-servers.net) in 297 ms mywebsite.com. 86400 IN A 188.188.188.254 mywebsite.com. 86400 IN NS ns3.rmi.fr. mywebsite.com. 86400 IN NS ns4.rmi.fr. ;; Received 204 bytes from 212.51.161.18#53(ns3.rmi.fr) in 310 ms Here I get my CISCO public IP 188.188.188.254!!! Is it normal? How to know if my browser (from the LAN) is really directly communicating with 192.168.1.85 when using mywebsite.com? Thank you for your help.

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  • Linq To Sql - DataContext.SubmitChanges() problem

    - by Ahmet Altun
    I have a code like this. DBContext is Datacontext instance. try { TBLORGANISM org = new TBLORGANISM(); org.OrganismDesc = p.Subject; DBContext.TBLORGANISMs.InsertOnSubmit(org); DBContext.SubmitChanges(); } catch (Exception) { } At this point, I want to IGNORE the error and want to be skipped. Not to be retried. But when I try another insert like TBLACTION act = new TBLACTION(); act.ActionDesc = p.ActionName; DBContext.TBLACTIONs.InsertOnSubmit(act); DBContext.SubmitChanges(); SubmitChanges firstly retries previous attempt. How can I tell "skip errors, don't try again"?

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  • Don't Understand Sql Server Error

    - by Jonathan Wood
    I have a table of users (User), and need to create a new table to track which users have referred other users. So, basically, I'm creating a many-to-many relation between rows in the same table. So I'm trying to create table UserReferrals with the columns UserId and UserReferredId. I made both columns a compound primary key. And both columns are foreign keys that link to User.UserID. Since deleting a user should also delete the relationship, I set both foreign keys to cascade deletes. When the user is deleted, any related rows in UserReferrals should also delete. But this gives me the message: 'User' table saved successfully 'UserReferrals' table Unable to create relationship 'FK_UserReferrals_User'. Introducing FOREIGN KEY constraint 'FK_UserReferrals_User' on table 'UserReferrals' may cause cycles or multiple cascade paths. Specify ON DELETE NO ACTION or ON UPDATE NO ACTION, or modify other FOREIGN KEY constraints. Could not create constraint. See previous errors. I don't get this error. A cascading delete only deletes the row with the foreign key, right? So how can it cause "cycling cascade paths"? Thanks for any tips.

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  • Show SQL query results in Sharepoint

    - by JoeOD
    Hi All I support Rational clearquest for my company and have been asked to show some of the data in Sharepoint. I can query the data in Clearquest no problem (Using Toad) but have no idea about how to go displaying it in Sharepoint. The data I'm querying contains dates and ideally I'd like to be able display it in a sharepoint calendar but list format would do for the moment. Can anybody offer advice on even where to start? Thanks, Joe

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  • Sql Query - Selecting rows where user can be both friend and user

    - by Gublooo
    Hey Sorry the title is not very clear. This is a follow up to my earlier question where one of the members helped me with a query. I have a following friends Table Friend friend_id - primary key user_id user_id_friend status The way the table is populated is - when I send a friend request to John - my userID appears in user_id and Johns userID appears in user_id_friend. Now another scenario is say Mike sends me a friend request - in this case mike's userID will appear in user_id and my userID will appear in user_id_friend So to find all my friends - I need to run a query to find where my userID appears in both user_id column as well as user_id_friend column What I am trying to do now is - when I search for user say John - I want all users Johns listed on my site to show up along with the status of whether they are my friend or not and if they are not - then show a "Add Friend" button. Based on the previous post - I got this query which does part of the job - My example user_id is 1: SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id = u.user_id and f.user_id_friend = 1 where u.name like '%' So this only shows users with whom I am friends where they have sent me request ie my userID appears in user_id_friend. Although I am friends with others (where my userID appears in user_id column) - this query will return that as null To get those I need another query like this SELECT u.user_id, f.status FROM user u LEFT OUTER JOIN friend f ON f.user_id_friend = u.user_id and f.user_id = 1 where u.name like '%' So how do I combine these queries to return 1 set of users and what my friendship status with them is. I hope my question is clear Thanks

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  • SQL DATEDIFF Not working!?

    - by James
    Hi all, I am running a simple DATEDIFF query but it doesn't seem to calculate the days properly or i'm doing something wrong. If I run PRINT DATEDIFF(Day, 2010-01-20, 2010-01-01) RETURN 19 Which is correct. If i change the month in the first date to Feb (02) I get something strange. PRINT DATEDIFF(Day, 2010-02-20, 2010-01-01) RETURN 20 Now shouldn't it be 48 or something? Can anyone see what i'm doing wrong or is this not the correct function to be using if I want the No of days between these dates? I've tried taking one date from the other: PRINT (2010-02-20) - (2010-01-01) RETURN -20 Any help much appreciated. Thanks J.

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  • SQL Server: Difference between PARTITION BY and GROUP BY

    - by Mike Mooney
    I've been using GROUP BY for all types of aggregate queries over the years. Recently, I've been reverse-engineering some code that uses PARTITION BY to perform aggregations. In reading through all the documentation I can find about PARTITION BY, it sounds a lot like GROUP BY, maybe with a little extra functionality added in? Are they two versions of the same general functionality, or are they something different entirely?

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  • Saving a select count(*) value to an integer (SQL Server)

    - by larryq
    Hi everyone, I'm having some trouble with this statement, owing no doubt to my ignorance of what is returned from this select statement: declare @myInt as INT set @myInt = (select COUNT(*) from myTable as count) if(@myInt <> 0) begin print 'there's something in the table' end There are records in myTable, but when I run the code above the print statement is never run. Further checks show that myInt is in fact zero after the assignment above. I'm sure I'm missing something, but I assumed that a select count would return a scalar that I could use above?

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  • Sql order by within a group by with aggregate

    - by NG
    Say I have Team/Name/Some number Cardinals Jason 8 Cardinals Chris 5 Yankees Joba 6 Cubs Carlos 6 Cardinals Chris 6 And I want Cardinals Jason 8 Cardinals Chris 11 Cubs Carlos 6 Yankees Joba 6 So, what I'm doing is grouping by team, grouping by name, summing by some number However, within cardinals I want to make sure the names are in a particular order. If I just do an "order by name desc" for example then the the whole grouping gets ignored. So how can I order within a group.

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  • LINQ(2 SQL) Insert Multiple Tables Question

    - by Refracted Paladin
    I have 3 tables. A primary EmploymentPlan table with PK GUID EmploymentPlanID and 2 FK's GUID PrevocServicesID & GUID JobDevelopmentServicesID. There are of course other fields, almost exclusively varchar(). Then the 2 secondary tables with the corresponding PK to the primary's FK's. I am trying to write the LINQ INSERT Method and am struggling with the creation of the keys. Say I have a method like below. Is that correct? Will that even work? Should I have seperate methods for each? Also, when INSERTING I didn't think I needed to provide the PK for a table. It is auto-generated, no? Thanks, public static void InsertEmploymentPlan(int planID, Guid employmentQuestionnaireID, string user, bool communityJob, bool jobDevelopmentServices, bool prevocServices, bool transitionedPrevocIntegrated, bool empServiceMatchPref) { using (var context = MatrixDataContext.Create()) { var empPrevocID = Guid.NewGuid(); var prevocPlan = new tblEmploymentPrevocService { EmploymentPrevocID = empPrevocID }; context.tblEmploymentPrevocServices.InsertOnSubmit(prevocPlan); var empJobDevID = Guid.NewGuid(); var jobDevPlan = new tblEmploymentJobDevelopmetService() { JobDevelopmentServicesID = empJobDevID }; context.tblEmploymentJobDevelopmetServices.InsertOnSubmit(jobDevPlan); var empPlan = new tblEmploymentQuestionnaire { CommunityJob = communityJob, EmploymentQuestionnaireID = Guid.NewGuid(), InsertDate = DateTime.Now, InsertUser = user, JobDevelopmentServices = jobDevelopmentServices, JobDevelopmentServicesID =empJobDevID, PrevocServices = prevocServices, PrevocServicesID =empPrevocID, TransitionedPrevocToIntegrated =transitionedPrevocIntegrated, EmploymentServiceMatchPref = empServiceMatchPref }; context.tblEmploymentQuestionnaires.InsertOnSubmit(empPlan); context.SubmitChanges(); } } I understand I can use more then 1 InsertOnSubmit, See SO ? HERE, I just don't understand how that would apply to my situation and the PK/FK creation.

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  • LINQ to SQL: filter nested objects with soft deletes

    - by Alex
    Hello everyone, I'm using soft deleting in my database (IsDeleted field). I'm actively using LoadWith and AssociateWith methods to retrieve and filter nested records. The thing is AssociateWith only works with properties that represents a one-to-many relationship. DataLoadOptions loadOptions = new DataLoadOptions(); loadOption.LoadWith<User>(u = > u.Roles); loadOption.AssociateWith<User>(u = > u.Roles.Where(r = > !r.IsDeleted)); In the example above I just say: I want to retrieve users with related (undeleted) roles. But when I have one-to-one relationship, e.g. Document - File (the only one file is related to the document) I'm unable to filter soft deleted object: DataLoadOptions loadOptions = new DataLoadOptions(); loadOption.LoadWith<Document>(d = > d.File); // the next certainly won't work loadOption.AssociateWith<File>(f = > !f.IsDeleted); So, is there any idea how to filter records within the one-to-one relationship? Thanks!

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  • For Nvarchar(Max) I am only getting 4000 characters in TSQL?

    - by Malcolm
    Hi, This is for SS 2005. Why I am i only getting 4000 characters and not 8000? It truncates the string @SQL1 at 4000. ALTER PROCEDURE sp_AlloctionReport( @where NVARCHAR(1000), @alldate NVARCHAR(200), @alldateprevweek NVARCHAR(200)) AS DECLARE @SQL1 NVARCHAR(Max) SET @SQL1 = 'SELECT DISTINCT VenueInfo.VenueID, VenueInfo.VenueName, VenuePanels.PanelID, VenueInfo.CompanyName, VenuePanels.ProductCode, VenuePanels.MF, VenueInfo.Address1, VenueInfo.Address2, '' As AllocationDate, '' As AbbreviationCode, VenueInfo.Suburb, VenueInfo.Route, VenueInfo.ContactFirstName, VenueInfo.ContactLastName, VenueInfo.SuitableTime, VenueInfo.OldVenueName, VenueCategories.Category, VenueInfo.Phone, VenuePanels.Location, VenuePanels.Comment, [VenueCategories].[Category] + '' Allocations'' AS ReportHeader, ljs.AbbreviationCode AS PrevWeekCampaign FROM (((VenueInfo INNER JOIN VenuePanels ON VenueInfo.VenueID = VenuePanels.VenueID) INNER JOIN VenueCategories ON VenueInfo.CategoryID = VenueCategories.CategoryID) LEFT JOIN (SELECT CampaignProductions.AbbreviationCode, VenuePanels.PanelID, CampaignAllocations.AllocationDate FROM (((VenueInfo INNER JOIN VenuePanels ON VenueInfo.VenueID=VenuePanels.VenueID) INNER JOIN CampaignAllocations ON VenuePanels.PanelID=CampaignAllocations.PanelID) INNER JOIN CampaignProductions ON CampaignAllocations.CampaignID=CampaignProductions.CampaignID) INNER JOIN VenueCategories ON VenueInfo.CategoryID=VenueCategories.CategoryID WHERE ' + @alldateprevweek + ') ljs ON VenuePanels.PanelID = ljs.PanelID) INNER JOIN (SELECT VenueInfo.VenueID, VenuePanels.PanelID, VenueInfo.VenueName, VenueInfo.CompanyName, VenuePanels.ProductCode, VenuePanels.MF, VenueInfo.Address1, VenueInfo.Address2, CampaignAllocations.AllocationDate, CampaignProductions.AbbreviationCode, VenueInfo.Suburb, VenueInfo.Route, VenueInfo.ContactFirstName, VenueInfo.ContactLastName, VenueInfo.SuitableTime, VenueInfo.OldVenueName, VenueCategories.Category, VenueInfo.Phone, VenuePanels.Location, VenuePanels.Comment, [Category] + '' Allocations'' AS ReportHeader, ljs2.AbbreviationCode AS PrevWeekCampaign FROM ((((VenueInfo INNER JOIN VenuePanels ON VenueInfo.VenueID = VenuePanels.VenueID) INNER JOIN CampaignAllocations ON VenuePanels.PanelID = CampaignAllocations.PanelID) INNER JOIN CampaignProductions ON CampaignAllocations.CampaignID = CampaignProductions.CampaignID) INNER JOIN VenueCategories ON VenueInfo.CategoryID = VenueCategories.CategoryID) LEFT JOIN (SELECT CampaignProductions.AbbreviationCode, VenuePanels.PanelID, CampaignAllocations.AllocationDate FROM (((VenueInfo INNER JOIN VenuePanels ON VenueInfo.VenueID=VenuePanels.VenueID) INNER JOIN CampaignAllocations ON VenuePanels.PanelID=CampaignAllocations.PanelID) INNER JOIN CampaignProductions ON CampaignAllocations.CampaignID=CampaignProductions.CampaignID) INNER JOIN VenueCategories ON VenueInfo.CategoryID=VenueCategories.CategoryID WHERE ' + @alldateprevweek + ') ljs2 ON VenuePanels.PanelID = ljs2.PanelID WHERE ' + @alldate + ' AND ' + @where + ') ljs3 ON VenueInfo.VenueID = ljs3.VenueID WHERE (((VenuePanels.PanelID)<>ljs3.[PanelID] And (VenuePanels.PanelID) Not In (SELECT PanelID FROM CampaignAllocations WHERE ' + @alldateprevweek + ')) AND ' + @where + ') UNION ALL SELECT VenueInfo.VenueID, VenueInfo.VenueName, VenuePanels.PanelID, VenueInfo.CompanyName, VenuePanels.ProductCode, VenuePanels.MF, VenueInfo.Address1, VenueInfo.Address2, CampaignAllocations.AllocationDate, CampaignProductions.AbbreviationCode, VenueInfo.Suburb, VenueInfo.Route, VenueInfo.ContactFirstName, VenueInfo.ContactLastName, VenueInfo.SuitableTime, VenueInfo.OldVenueName, VenueCategories.Category, VenueInfo.Phone, VenuePanels.Location, VenuePanels.Comment, [Category] + '' Allocations'' AS ReportHeader, ljs.AbbreviationCode AS PrevWeekCampaign FROM ((((VenueInfo INNER JOIN VenuePanels ON VenueInfo.VenueID = VenuePanels.VenueID) INNER JOIN CampaignAllocations ON VenuePanels.PanelID = CampaignAllocations.PanelID) INNER JOIN CampaignProductions ON CampaignAllocations.CampaignID = CampaignProductions.CampaignID) INNER JOIN VenueCategories ON VenueInfo.CategoryID = VenueCategories.CategoryID) LEFT JOIN (SELECT CampaignProductions.AbbreviationCode, VenuePanels.PanelID, CampaignAllocations.AllocationDate FROM (((VenueInfo INNER JOIN VenuePanels ON VenueInfo.VenueID=VenuePanels.VenueID) INNER JOIN CampaignAllocations ON VenuePanels.PanelID=CampaignAllocations.PanelID) INNER JOIN CampaignProductions ON CampaignAllocations.CampaignID=CampaignProductions.CampaignID) INNER JOIN VenueCategories ON VenueInfo.CategoryID=VenueCategories.CategoryID WHERE ' + @alldateprevweek + ') ljs ON VenuePanels.PanelID = ljs.PanelID WHERE ' + @alldate + ' AND ' + @where Select @SQL1

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  • SQL - Rank() on a table

    - by Abhi
    create table v (mydate,value) as select to_date('20/03/2010 00','dd/mm/yyyy HH24'),98 from dual union all select to_date('20/03/2010 01','dd/mm/yyyy HH24'),124 from dual union all select to_date('20/03/2010 02','dd/mm/yyyy HH24'),140 from dual union all select to_date('20/03/2010 03','dd/mm/yyyy HH24'),138 from dual union all select to_date('20/03/2010 04','dd/mm/yyyy HH24'),416 from dual union all select to_date('20/03/2010 05','dd/mm/yyyy HH24'),196 from dual union all select to_date('20/03/2010 06','dd/mm/yyyy HH24'),246 from dual union all select to_date('20/03/2010 07','dd/mm/yyyy HH24'),176 from dual union all select to_date('20/03/2010 08','dd/mm/yyyy HH24'),124 from dual union all select to_date('20/03/2010 09','dd/mm/yyyy HH24'),128 from dual union all select to_date('20/03/2010 10','dd/mm/yyyy HH24'),32010 from dual union all select to_date('20/03/2010 11','dd/mm/yyyy HH24'),384 from dual union all select to_date('20/03/2010 12','dd/mm/yyyy HH24'),368 from dual union all select to_date('20/03/2010 13','dd/mm/yyyy HH24'),392 from dual union all select to_date('20/03/2010 14','dd/mm/yyyy HH24'),374 from dual union all select to_date('20/03/2010 15','dd/mm/yyyy HH24'),350 from dual union all select to_date('20/03/2010 16','dd/mm/yyyy HH24'),248 from dual union all select to_date('20/03/2010 17','dd/mm/yyyy HH24'),396 from dual union all select to_date('20/03/2010 18','dd/mm/yyyy HH24'),388 from dual union all select to_date('20/03/2010 19','dd/mm/yyyy HH24'),360 from dual union all select to_date('20/03/2010 20','dd/mm/yyyy HH24'),194 from dual union all select to_date('20/03/2010 21','dd/mm/yyyy HH24'),234 from dual union all select to_date('20/03/2010 22','dd/mm/yyyy HH24'),328 from dual union all select to_date('20/03/2010 23','dd/mm/yyyy HH24'),216 from dual From this table, how to rank() over 'value', partitioning by each hour of the day? and select only the 1st ranked result?

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  • How to move 100mb hidden system reserved partition on Windows Server 2008 R2 to other drive?

    - by Artyom Krivokrisenko
    Hello! I have a server with two 1.5TB hard drives. I was going to install a Windows Server 2008 R2 and create software RAID1 using Windows Disk Management Utility. I instaleld Windows, open this console and that is what I see: http://i.imgur.com/KoC9a.png Setup program created a System Reserved Partition at my second HDD. I don't understand now, how can I create RAID1, because space, which supposed to be used for copy of disk C, now is used for this hidden partition. So is there any way now to create correct RAID1? May it is possible to move this partition to the Disk 0, where I have plenty of free space? Unfortunately I can't reinstall Windows and apply other options at the disk management step of the installation, because installation image is not longer connected to the server and I have no physical access to server, only remote desktop.

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  • sql group by with left join

    - by cometta
    fail statement:Error: ORA-00979: not a GROUP BY expression select org_division.name , org_department.name , org_surveylog.division_code as divisionCode,org_surveylog.department_code as departmentCode , max(org_surveylog.actiondate) from org_surveylog left join org_division on (org_surveylog.division_code= org_division.division_code and org_surveylog.SURVEY_NUM= org_division.survey_num) left join org_department on (org_surveylog.department_code = org_department.department_code and org_surveylog.SURVEY_NUM = org_department.survey_num) group by org_surveylog.division_code,org_surveylog.department_code but below is ok select org_surveylog.division_code as divisionCode,org_surveylog.department_code as departmentCode , max(org_surveylog.actiondate) from org_surveylog left join org_division on (org_surveylog.division_code= org_division.division_code and org_surveylog.SURVEY_NUM= org_division.survey_num) left join org_department on (org_surveylog.department_code = org_department.department_code and org_surveylog.SURVEY_NUM = org_department.survey_num) group by org_surveylog.division_code,org_surveylog.department_code how to use group by with left join when i need to show value of org_division.name , org_department.name ?

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  • SQL Server CONTAINS with digits gives no results

    - by dale
    Hi, I have a database table which is full-text indexed and i use the CONTAINS-function to perform a search-query on it. When I do: SELECT * FROM Plants WHERE CONTAINS(Plants.Description, '"Plant*" AND "one*"'); I get back all correct results matching a description with the words "Plant" and "one". Some plant are named like "Plant 1", "Plant 2" etc. and this is the problem. When i do this, i get no results: SELECT * FROM Plants WHERE CONTAINS(Plants.Description, '"Plant*" AND "1*"'); Anyone know why?

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