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  • PHP Strange error "0:". Possible Object syntax problem?

    - by Michael Stone
    I'm trying to transfer a site from one hosting company to another. I was using 000webhost until the client had hosting and a domain. Now that the client has their domain and hosting, using FatCow.com, I can not for the life of me, debug my PHP code. I'm not getting any errors. I have a successful DB connection. If you procedurally display data, it works, but when I try to use my original objects, something is breaking and just returns "0:". I have all errors on. On old server where the site worked: PHP Version 5.2.11 MySQL Version: 5.0.81 On new server where I get the "0:": PHP Version 5.2.12 MySQL Version 5.0.32 I've setup a test page to test just the output of the variables with the DB connection. Below is my code: <?php error_reporting(E_ALL); ini_set('display_errors', '1'); try { $link = mysql_connect('connectionstring', 'username', 'password'); if (!$link) { die('Could not connect: ' . mysql_error()); } else{ $db = mysql_select_db('a8210422_lit'); } if($db){ include_once('admin/classes/clsPOW.php'); include_once('admin/classes/clsProviders.php'); $pow = new POW(); $prov = new Providers(); $new = $pow->getNew(); $newAr = $new->val(); $get = $prov->getAll($newAr['providerId']); $getAr = $get->val(); $img = $getAr['image']; $name = $getAr['provider']; $desc = $getAr['description']; $zip = $getAr['zip']; $web = $getAr['link']; if($zip==0){ $zip = "Unavailable"; } print $img; print $name; print $desc; print $zip; print $web; } else{ print 'fail!'; } } //catch exception catch(Exception $e) { echo 'Message: ' .$e->getMessage(); } ?>

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  • Arrays become null after passing to function in PHP

    - by William
    So when I pass my filled arrays to the function createform the form is created with $max_avatars options, but they have no name or value. Why are my arrays becoming null? <?php $avatar_image_name = array('hacker','samurai','cool','happy','thatsnice','angry','tv','bang'); $avatar_name = array('Hacker','Samurai','Cool','Happy','That\'s nice','Angry','TV','Bang'); $max_avatars = 6; createform($max_avatars, $avatar_image_name, $avatar_name); ?> The function createform: function createform($max_avatars, $avatar_image_name, $avatar_name) { $string ='<table id="formtable"> <tr><td class="formtext">Name:</td><td><input type="text" name=name size=25 /></td></tr> <tr><td class="formtext">Trip:</td><td><input type="text" name=trip size=25 /> (<font style="color: #ff0000">Don\'t use your password</font>)</td></tr> <tr><td class="formtext">Comment</td><td><textarea name=post rows="4" cols="50"></textarea></td></tr> <tr><td class="formtext">Avatar:</td> <td> <select name=avatar>'; for($i = 0; $i < $max_avatars; $i++){ $string = ($string . '<option value="'.$avatar_image_name[i].'">'.$avatar_name[i].'</option>'); } $string = ($string . '</select> </td> <tr><td class="formtext">Extra</td><td>Fortune: <input type="radio" name="extra" value="fortune" /> Poker: <input type="radio" name="extra" value="poker" /></td></tr> </table> <input type=submit value="Submit" id="submitbutton">'); echo $string; }

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  • Losing session after Login - Java

    - by Patrick Villela
    I'm building an application that needs to login to a certain page and make a navigation. I can login, provided that the response contains a string that identifies it. But, when I navigate to the second page, I can't see the page as a logged user, only as anonymous. I'll provide my code. import java.net.*; import java.security.*; import java.security.cert.*; import javax.net.ssl.*; import java.io.*; import java.util.*; public class PostTest { static HttpsURLConnection conn = null; private static class DefaultTrustManager implements X509TrustManager { @Override public void checkClientTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public void checkServerTrusted(X509Certificate[] arg0, String arg1) throws CertificateException {} @Override public X509Certificate[] getAcceptedIssuers() { return null; } } public static void main(String[] args) { try { SSLContext ctx = SSLContext.getInstance("TLS"); ctx.init(new KeyManager[0], new TrustManager[] {new DefaultTrustManager()}, new SecureRandom()); SSLContext.setDefault(ctx); String data = URLEncoder.encode("txtUserName", "UTF-8") + "=" + URLEncoder.encode(/*username*/, "UTF-8"); data += "&" + URLEncoder.encode("txtPassword", "UTF-8") + "=" + URLEncoder.encode(/*password*/", "UTF-8"); data += "&" + URLEncoder.encode("envia", "UTF-8") + "=" + URLEncoder.encode("1", "UTF-8"); connectToSSL(/*login url*/); conn.setDoOutput(true); OutputStreamWriter wr = new OutputStreamWriter(conn.getOutputStream()); wr.write(data); wr.flush(); BufferedReader rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); String line; String resposta = ""; while((line = rd.readLine()) != null) { resposta += line + "\n"; } System.out.println("valid login -> " + resposta.contains(/*string that assures me I'm looged in*/)); connectToSSL(/*first navigation page*/); rd = new BufferedReader(new InputStreamReader(conn.getInputStream())); while((line = rd.readLine()) != null) { System.out.println(line); } } catch(Exception e) { e.printStackTrace(); } } private static void connectToSSL(String address) { try { URL url = new URL(address); conn = (HttpsURLConnection) url.openConnection(); conn.setHostnameVerifier(new HostnameVerifier() { @Override public boolean verify(String arg0, SSLSession arg1) { return true; } }); } catch(Exception ex) { ex.printStackTrace(); } } } Any further information, just ask. Thanks in advance.

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  • Integrating PayMill: The token filled input field is not created, error "field_invalid_amount"

    - by automatix
    I'm implementing the Credit Card Payment form of PayMill according to the Payment Form docu. So I copied the JS from the Bridge docu page and the form from the Payment Form docu page. But no token is created. When I try to debug the JS and add console.info(error.apierror); into the paymillResponseHandler(...) function, I get the error code: field_invalid_amount. According to the support page There are three possible reasons for this error message: no amount value was provided numbers were rounded wrong delimiter symbol But the amuont is provided and I've already tried different delimiter symbols. What "numbers were rounded" means, is not clear. What can be the problem and how to fix this issue? Code: <!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"> <html> <head> <meta name="generator" content="PSPad editor, www.pspad.com"> <script src="https://ajax.googleapis.com/ajax/libs/jquery/1.7.2/jquery.min.js"></script> <title> </title> </head> <body> <!-- PayMill HEAD start --> <link rel="stylesheet" href="https://netdna.bootstrapcdn.com/twitter-bootstrap/2.2.1/css/bootstrap.no-responsive.no-icons.min.css" /> <script type="text/javascript"> var PAYMILL_PUBLIC_KEY = '51668632777bf03b57f861c5a7278a38'; </script> <script type="text/javascript" src="https://bridge.paymill.com/"></script> <!-- PayMill HEAD stop --> <!-- PayMill FORM start --> <form id="payment-form" class="span4" action="payment.php" method="POST"> <p class="payment-errors alert-error span3" style="display:none;"> </p> <div id="payment-form-cc"> <div class="controls controls-row"> <div class="span2"> <label class="card-number-label">Kreditkarte </label> <input class="card-number span2" type="text" size="20" value="4111111111111111"/> </div> <div class="span1"> <label class="card-cvc-label">CVC </label> <input class="card-cvc span1" type="text" size="4" value="111"/> </div> </div> <div class="controls controls-row"> <div class="span3 card-icon"> </div> </div> <div class="controls controls-row"> <div class="span3"> <label class="card-holdername-label">Karteninhaber </label> <input class="card-holdername span3" type="text" size="20" value="lala"/> </div> </div> <div class="controls controls-row"> <div class="span3"> <label class="card-expiry-label">Gültigkeitsdatum (MM/YYYY) </label> <input class="card-expiry-month span1" type="text" size="2" value="12"/> <span style="float:left;"> / </span> <input class="card-expiry-year span1" type="text" size="4" value="2015"/> </div> </div> </div> <div class="controls controls-row"> <div class="span2"> <label class="amount-label">Betrag </label> <input class="amount span2" type="text" size="5" value="9,99" name="amount"/> </div> <div class="span1"> <label class="currency-label">Währung </label> <input class="currency span1" type="text" size="3" value="EUR" name="currency"/> </div> </div> <div class="controls controls-row"> <div class="span4"> <button class="submit-button btn btn-primary" type="submit" >Pay!</button> </div> </div> </form> <!-- PayMill FORM stop --> <!-- PayMill FOOT start --> <script type="text/javascript"> function paymillResponseHandler(error, result) { if (error) { console.info(error.apierror); // Displays the error above the form $(".payment-errors").text(error.apierror); } else { console.info('OK'); var form = $("#payment-form"); // Output token var token = result.token; // Insert token into form in order to submit to server form.append( "<input type='hidden' name='paymillToken' value='"+token+"'/>" ); // Submit form form.get(0).submit(); } } </script> <script type="text/javascript"> paymill.createToken({ number: $('.card-number').val(), // required exp_month: $('.card-expiry-month').val(), // required exp_year: $('.card-expiry-year').val(), // required cvc: $('.card-cvc').val(), // required amount_int: $('.card-amount-int').val(), // required, e.g. "4900" for 49.00 EUR currency: $('.currency').val(), // required cardholder: $('.card-holdername').val() // optional }, paymillResponseHandler); </script> <!-- PayMill FOOT stop --> </body> </html>

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  • Problem passing variables in php form.

    - by Joshxtothe4
    I have the following php form. I am trying to make it so that when the form is loaded, the values will be assigned the appropriate check- variable. This variable will contain either "checked or "". If it contains checked, the way it is displayed with the html should cause the relevant checkbox to be checked. As it is, the variables do not seem to be being passed. When I echo out $deleted or $notice from within the submitinfo branch, they are blank. Furthermore, nothing is being inserted into the database, and I am not getting any database error. How can I check this? <?php if (isset($_GET["cmd"])) $cmd = $_GET["cmd"]; else if (isset($_POST["cmd"])) $cmd = $_POST["cmd"]; else die("Invalid URL"); if (isset($_GET["pk"])) { $pk = $_GET["pk"]; } if (isset($_POST["deleted"])) { $deleted = $_POST["deleted"]; } if (isset($_POST["notice"])) { $notice = $_POST["notice"]; } $con = mysqli_connect("localhost","user","password", "db"); if (!$con) { echo "Can't connect to MySQL Server. Errorcode: %s\n". mysqli_connect_error(); exit; } $con->set_charset("utf8"); $getformdata = $con->query("select * from STATUS where ARTICLE_NO = '$pk'"); $checkDeleted = ""; $checkNotice = ""; while ($row = mysqli_fetch_assoc($getformdata)) { $checkDeleted = $row['deleted']; $checkNotice = $row['notice']; } if($cmd=="submitinfo") { $statusQuery = "INSERT INTO STATUS VALUES (?, ?)"; if ($statusInfo = $con->prepare($statusQuery)) { $statusInfo->bind_param("ss", $deleted, $notice); $statusInfo->execute(); $statusInfo->close(); echo "true"; } else { echo "false"; } print_r($con->error); } if($cmd=="EditStatusData") { echo "<form name=\"statusForm\" action=\"test.php\" method=\"post\" enctype=\"multipart/form-data\"> <h1>Editing information for auction: ".$pk."</h1> Löschung Ebay: <input type=\"checkbox\" name=\"deleted\" value=\"checked\" ".$checkDeleted." /> <br /> Abmahnung: <input type=\"checkbox\" name=\"notice\" value=\"checked\" ".$checkNotice." /> <br /> <input type=\"hidden\" name=\"cmd\" value=\"submitinfo\" /> <input name=\"Submit\" type=\"submit\" value=\"submit\" /> </form>"; } else { print_r($con->error); }

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  • Rails send mail with GMail

    - by Danny McClelland
    Hi Everyone, I am on rails 2.3.5 and have the latest Ruby installed and my application is running well, except, GMail emails. I am trying to setup my gmail imap connection which has worked previously but now doesnt want to know. This is my code: # Be sure to restart your server when you modify this file # Uncomment below to force Rails into production mode when # you don't control web/app server and can't set it the proper way # ENV['RAILS_ENV'] ||= 'production' # Specifies gem version of Rails to use when vendor/rails is not present RAILS_GEM_VERSION = '2.3.5' unless defined? RAILS_GEM_VERSION # Bootstrap the Rails environment, frameworks, and default configuration require File.join(File.dirname(__FILE__), 'boot') Rails::Initializer.run do |config| # Gems config.gem "capistrano-ext", :lib => "capistrano" config.gem "configatron" # Make Time.zone default to the specified zone, and make Active Record store time values # in the database in UTC, and return them converted to the specified local zone. config.time_zone = "London" # The internationalization framework can be changed to have another default locale (standard is :en) or more load paths. # All files from config/locales/*.rb,yml are added automatically. # config.i18n.load_path << Dir[File.join(RAILS_ROOT, 'my', 'locales', '*.{rb,yml}')] #config.i18n.default_locale = :de # Your secret key for verifying cookie session data integrity. # If you change this key, all old sessions will become invalid! # Make sure the secret is at least 30 characters and all random, # no regular words or you'll be exposed to dictionary attacks. config.action_controller.session = { :session_key => '_base_session', :secret => '7389ea9180b15f1495a5e73a69a893311f859ccff1ffd0fa2d7ea25fdf1fa324f280e6ba06e3e5ba612e71298d8fbe7f15fd7da2929c45a9c87fe226d2f77347' } config.active_record.observers = :user_observer end ActiveSupport::CoreExtensions::Date::Conversions::DATE_FORMATS.merge!(:default => '%d/%m/%Y') ActiveSupport::CoreExtensions::Time::Conversions::DATE_FORMATS.merge!(:default => '%d/%m/%Y') require "will_paginate" ActionMailer::Base.delivery_method = :smtp ActionMailer::Base.smtp_settings = { :enable_starttls_auto => true, :address => "smtp.gmail.com", :port => 587, :domain => "XXXXXXXX.XXX", :authentication => :plain, :user_name => "XXXXXXXXXX.XXXXXXXXXX.XXX", :password => "XXXXX" } But the above just results in an SMTP auth error in the production log. I have read varied reports of this not working in Rails 2.2.2 but nothing for 2.3.5, anyone got any ideas? Thanks, Danny

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  • Hibernate MappingException Unknown entity: $Proxy2

    - by slynn1324
    I'm using Hibernate annotations and have a VERY basic data object: import java.io.Serializable; import javax.persistence.Entity; import javax.persistence.Id; @Entity public class State implements Serializable { /** * */ private static final long serialVersionUID = 1L; @Id private String stateCode; private String stateFullName; public String getStateCode() { return stateCode; } public void setStateCode(String stateCode) { this.stateCode = stateCode; } public String getStateFullName() { return stateFullName; } public void setStateFullName(String stateFullName) { this.stateFullName = stateFullName; } } and am trying to run the following test case: public void testCreateState(){ Session s = HibernateUtil.getSessionFactory().getCurrentSession(); Transaction t = s.beginTransaction(); State state = new State(); state.setStateCode("NE"); state.setStateFullName("Nebraska"); s.save(s); t.commit(); } and get an org.hibernate.MappingException: Unknown entity: $Proxy2 at org.hibernate.impl.SessionFactoryImpl.getEntityPersister(SessionFactoryImpl.java:628) at org.hibernate.impl.SessionImpl.getEntityPersister(SessionImpl.java:1366) at org.hibernate.event.def.AbstractSaveEventListener.saveWithGeneratedId(AbstractSaveEventListener.java:121) .... I haven't been able to find anything referencing the $Proxy part of the error - and am at a loss.. Any pointers to what I'm missing would be greatly appreciated. hibernate.cfg.xml <property name="hibernate.connection.driver_class">org.hsqldb.jdbcDriver</property> <property name="connection.url">jdbc:hsqldb:hsql://localhost/xdb</property> <property name="connection.username">sa</property> <property name="connection.password"></property> <property name="current_session_context_class">thread</property> <property name="dialect">org.hibernate.dialect.HSQLDialect</property> <property name="show_sql">true</property> <property name="hbm2ddl.auto">update</property> <property name="hibernate.transaction.factory_class">org.hibernate.transaction.JDBCTransactionFactory</property> <mapping class="com.test.domain.State"/> in HibernateUtil.java public static SessionFactory getSessionFactory(boolean testing ) { if ( sessionFactory == null ){ try { String configPath = HIBERNATE_CFG; AnnotationConfiguration config = new AnnotationConfiguration(); config.configure(configPath); sessionFactory = config.buildSessionFactory(); } catch (Exception e){ e.printStackTrace(); throw new ExceptionInInitializerError(e); } } return sessionFactory; }

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  • How a database is loaded into an application?

    - by Audel
    Hi All i need is a simple explanation on how does this function work I also attached a piece of php which I think is the one that retrieves the data from the database. Please correct me if I'm wrong Cheers. function loadDatabaseRecords () { // Mozilla/Safari if (window.XMLHttpRequest) { xmlHttpReq = new XMLHttpRequest(); } // IE else if (window.ActiveXObject) { xmlHttpReq = new ActiveXObject("Microsoft.XMLHTTP"); } alert ("To Server (Load Records):\n\najax-open-DB.php"); xmlHttpReq.open('GET', "ajax-open-DB.php", true); xmlHttpReq.onreadystatechange = loadDatabaseRecordsCallback; xmlHttpReq.send(null); } <?php $link = mysql_connect ("ipaddress", "localhost", "password"); mysql_select_db ("database1"); $query = "SELECT * from addressbook"; $result = mysql_query ($query); print "<table>"; print "<tr>"; print "<th>Firstname</th><th>Lastname</th><th>Address</th><th>Telephone</th>"; print "</tr>"; for ($i = 0; $i < mysql_num_rows ($result); $i ++) { $row = mysql_fetch_object ($result); print "<tr>"; print "<td>$row->firstname</td>"; print "<td>$row->lastname</td>"; print "<td>$row->address</td>"; print "<td>$row->telephone</td>"; print "</tr>"; } print "</table>"; mysql_close ($link); ?>

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  • How do I write sql data into a textbox after a submit type event

    - by Matt
    Finishing up some homework and Im having trouble with figuring out how to take information generated in sql column(a primary key set up to assign a record number to a customer example 1046) at submit and writing it to my redirected recipt page. I call it recipt.aspx. Any takers Professor says to use a datareader...but things go bad after that. public partial class _Default : System.Web.UI.Page { String cnStr = "EDITED FOR THE PURPOSE OF NOT DISPLAYED SQL SERVERta Source=111.11.111.11; uid=xxxxxxx; password=xxxx; database=xxxxxx; "; String insertStr; SqlDataReader reader; SqlConnection myConnection = new SqlConnection(); protected void submitbutton_Click(object sender, EventArgs e) { myConnection.ConnectionString = cnStr; try { //more magic happens as myConnection opens myConnection.Open(); insertStr = "insert into connectAssignment values ('" + TextBox2.Text + "','" + TextBox3.Text + "','" + TextBox4.Text + "','" + TextBox5.Text + "','" + bigtextthing.Text + "','" + DropDownList1.SelectedItem.Value + "')"; //magic happens as Connection string is assigned to connection object and passes in the SQL statment //associate the command to the the myConnection connection object SqlCommand cmd = new SqlCommand(insertStr, myConnection); cmd.ExecuteNonQuery(); Session["passmyvalue1"] = TextBox2.Text; Session["passmyvalue2"] = TextBox3.Text; Session["passmyvalue3"] = TextBox4.Text; Session["passmyvalue4"] = TextBox5.Text; Session["passmyvalue5"] = bigtextthing.Text; Session["I NEED SOME HELP RIGHT HERE"] =Textbox6.Text; Response.Redirect("receipt.aspx"); } catch { bigtextthing.Text = "Error submitting" + "Possible casues: Internet is down,server is down, check your settings!"; } finally { myConnection.Close(); TextBox2.Text = ""; TextBox3.Text = ""; TextBox4.Text = ""; TextBox5.Text = ""; bigtextthing.Text = ""; } //reset validators? } The recipt page public partial class _Default : System.Web.UI.Page { protected void Page_Load(object sender, EventArgs e) { if(Session["passmyvalue1"] != null) { TextBox1.Text = (string)Session["passmyvalue1"]; TextBox2.Text = (string)Session["passmyvalue2"]; TextBox3.Text = (string)Session["passmyvalue3"]; TextBox4.Text = (string)Session["passmyvalue4"]; TextBox5.Text = (string)Session["passmyvalue5"]; TextBox6.Text = I don't know ; } } } THanks for the help

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  • how to insert into database from stored procedure in log4net?

    - by Samreen
    I have to log thread context properties like this: string logFilePath = AppDomain.CurrentDomain.BaseDirectory + "log4netconfig.xml"; FileInfo finfo = new FileInfo(logFilePath); log4net.Config.XmlConfigurator.ConfigureAndWatch(finfo); ILog logger = LogManager.GetLogger("Exception.Logging"); log4net.ThreadContext.Properties["MESSAGE"] = exception.Message; log4net.ThreadContext.Properties["MODULE"] = "module1"; log4net.ThreadContext.Properties["COMPONENT"] = "component1"; logger.Debug("test"); and the configuration file is: <configuration> <configSections> <section name="log4net" type="log4net.Config.Log4NetConfigurationSectionHandler,Log4net"/> </configSections> <log4net> <logger name="Exception.Logging" level="Debug"> <appender-ref ref="AdoNetAppender"/> </logger> <appender name="AdoNetAppender" type="log4net.Appender.AdoNetAppender"> <connectionString value="Data Source=xe;User ID=test;Password=test;" /> <connectionType value="System.Data.OracleClient.OracleConnection, System.Data.OracleClient, Version=2.0.0.0, Culture=neutral, PublicKeyToken=b77a5c561934e089" /> <bufferSize value="10000"/> <commandText value="Log_Exception_Pkg.Insert_Log" /> <commandType value="StoredProcedure" /> <parameter> <parameterName value="@p_Error_Message" /> <dbType value="String" /> <size value="255" /> <layout type="log4net.Layout.PatternLayout"> <conversionPattern value="%property{MESSAGE}"/> </layout> </parameter> <parameter> <parameterName value="@p_Module" /> <dbType value="String" /> <size value="225" /> <layout type="log4net.Layout.PatternLayout"> <conversionPattern value="%property{MODULE}"/> </layout> </parameter> <parameter> <parameterName value="@p_Component" /> <dbType value="String" /> <size value="225" /> <layout type="log4net.Layout.PatternLayout"> <conversionPattern value="%property{COMPONENT}"/> </layout> </parameter> </appender> </log4net> </configuration> But its not inserting them in the database. How can I get that to work?

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  • Inserting checkbox values

    - by rabeea
    hey i have registration form that has checkboxes along with other fields. i cant insert the selected checkbox values into the data base. i have made one field in the database for storing all checked values. this is the code for checkbox part in the form: Websites, IT and Software Writing and Content <pre><input type="checkbox" name="expertise[]" value="Design and Media"> Design and Media <input type="checkbox" name="expertise[]" value="Data entry and Admin"> Data entry and Admin </pre> <pre><input type="checkbox" name="expertise[]" value="Engineering and Skills"> Engineering and Science <input type="checkbox" name="expertise[]" value="Seles and Marketing"> Sales and Marketing </pre> <pre><input type="checkbox" name="expertise[]" value="Business and Accounting"> Business and Accounting <input type="checkbox" name="expertise[]" value="Others"> Others </pre> and this is the corresponding php code for inserting data $checkusername=mysql_query("SELECT * FROM freelancer WHERE fusername='{$_POST['username']}'"); if (mysql_num_rows($checkusername)==1) { echo "username already exist"; } else { $query = "insert into freelancer(ffname,flname,fgender,femail,fusername,fpwd,fphone,fadd,facc,facc_name,fbank_details,fcity,fcountry,fexpertise,fprofile,fskills,fhourly_rate,fresume) values ('".$_POST['first_name']."','".$_POST['last_name']."','".$_POST['gender']."','".$_POST['email']."','".$_POST['username']."','".$_POST['password']."','".$_POST['phone']."','".$_POST['address']."','".$_POST['acc_num']."','".$_POST['acc_name']."','".$_POST['bank']."','".$_POST['city']."','".$_POST['country']."','".implode(',',$_POST['expertise'])."','".$_POST['profile']."','".$_POST['skills']."','".$_POST['rate']."','".$_POST['resume']."')"; $result = ($query) or die (mysql_error()); this code inserts data for all fields but the checkbox value field remains empty???

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  • Account confirmation email sent as SPAM :( PHP

    - by praveen
    Hi, I'm using PHPMailer to send a confirmation email for newly registered users in my social network. But i found out most of them have ended up in user's spam list. (hotmail and yahoo). How to avoid this? This is my script $mail=new PHPMailer(); $mail->IsSMTP(); $mail->SMTPAuth = mSMTPAuth(); $mail->SMTPSecure = mSMTPSecure(); $mail->Host = mHost(); $mail->Port = mPort(); $mail->Username = mUsername(); $mail->Password = mPassword(); $mail->From = mFrom(); $mail->FromName = "SiteName"; $mail->Subject = "SiteName New Account Activation"; $mail->IsHTML(true); $mail->WordWrap = 50; $mail->Body = "<h2>Welcome to " .$sitename. " " .$username. "! </h2><br><br>"; $mail->Body .= "Please click on the link below to verify your email address:<br><br>"; $mail->Body .= "<a href='".$base. "verify.php?a=" .$gen_key."'>".$base. "verify.php?a=" .$gen_key."</a>"; $mail->Body .= "<br><br>Regards<br>"; $mail->AltBody = "Welcome to " .$sitename. " " .$username. "!\n\nTo verify your email address, please click on the link below:\n\n".$base. "verify.php?a=" .$gen_key; $mail->AddAddress($email); $mail->Send(); $mail->ClearAddresses(); Please help. This is really confusing. Thanks in advance

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  • problem to create session of facebook

    - by khoyendra
    try { HttpClient http = new HttpClient(); http.setParams(new HttpClientParams()); //http.getHostConfiguration().setHost("http://www.facebook.com/"); http.setState(new HttpState()); String api_key = "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx"; String secret = "xxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxxx"; // String appId=124812364218050; //http://www.facebook.com/developers/editapp.php?app_id=124812364218050 FacebookRestClient client = new FacebookRestClient(api_key, secret); client.setIsDesktop(true); // String sessionKey = request.getParameter(FacebookParam.SESSION_KEY.toString()); // boolean b = client.users_setStatus("This is a test..."); // System.out.println("User Status RESULT : " + b); String token = client.auth_createToken(); final String loginId = "http://www.facebook.com/login.php"; GetMethod get = new GetMethod(loginId + "?api_key=" + api_key + "&v=1.0&auth_token=" +token); System.out.println("Get="+get); http.executeMethod(get); PostMethod post = new PostMethod(loginId); post.addParameter(new NameValuePair("api_key", api_key)); post.addParameter(new NameValuePair("v", "1.0")); post.addParameter(new NameValuePair("auth_token", token)); post.addParameter(new NameValuePair("fbconnect","true")); post.addParameter(new NameValuePair("return_session","true")); post.addParameter(new NameValuePair("session_key_only","true")); post.addParameter(new NameValuePair("req_perms","read_stream,publish_stream")); post.addParameter(new NameValuePair("email", email)); post.addParameter(new NameValuePair("pass", password)); System.out.println("Token ="+token); int postStatus = http.executeMethod(post); System.out.println("Response : " + postStatus); session = client.auth_getSession(token); // Here I am getting error System.out.println("Session string: " + session); long userid = client.users_getLoggedInUser(); System.out.println("User Id is : " + userid); } catch (Exception e) { e.printStackTrace(); } please solve my problem i cannot create session of facebook.

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  • can't insert arecord in a oracle database using C#

    - by Gya
    try { int val4 = Convert.ToInt32(tbGrupa.Text); string MyConString = "Data Source=**;User ID=******;Password=*****"; OracleConnection conexiune = new OracleConnection(MyConString); OracleCommand comanda = new OracleCommand(); comanda.Connection = conexiune; conexiune.Open(); comanda.Transaction = conexiune.BeginTransaction(); int id_stud = Convert.ToInt16(tbCodStud.Text); string nume = tbNume.Text; string prenume = tbPrenume.Text; string initiala_tatalui = tbInitiala.Text; string email = tbEmail.Text; string facultate = tbFac.Text; int grupa = Convert.ToInt16(tbGrupa.Text); string serie = tbSeria.Text; string forma_de_inv = tbFormaInvatamant.Text; DateTime data_acceptare_coordonare = dateTimePicker1.Value; DateTime data_sustinere_licenta = dateTimePicker2.Value; string sustinere = tbSustinereLicenta.Text; string parola_acces = tbParola.Text; try { comanda.Parameters.AddWithValue("id_stud", id_stud); comanda.Parameters.AddWithValue("nume", nume); comanda.Parameters.AddWithValue("prenume", prenume); comanda.Parameters.AddWithValue("initiala_tatalui", initiala_tatalui); comanda.Parameters.AddWithValue("facultate", facultate); comanda.Parameters.AddWithValue("email", email); comanda.Parameters.AddWithValue("seria", serie); comanda.Parameters.AddWithValue("grupa", grupa); comanda.Parameters.AddWithValue("forma_de_inv", forma_de_inv); comanda.Parameters.AddWithValue("data_acceptare_coordonare", data_acceptare_coordonare); comanda.Parameters.AddWithValue("data_sustinere_licenta", data_sustinere_licenta); comanda.Parameters.AddWithValue("sustinere_licenta", sustinere); comanda.Parameters.AddWithValue("parola_acces", parola_acces); comanda.Transaction.Commit(); MessageBox.Show("Studentul " + tbNume.Text + " " + tbPrenume.Text + " a fost adaugat în baza de date!"); } catch (Exception er) { comanda.Transaction.Rollback(); MessageBox.Show("ER1.1:" + er.Message); MessageBox.Show("ER1.2:" + er.StackTrace); } finally { conexiune.Close(); } } catch (Exception ex) { MessageBox.Show("ER2.1:"+ex.Message); MessageBox.Show("ER2.2:"+ex.StackTrace); } }

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  • Strategies for "Always-Connected" Windows Client Data Architecture

    - by magz2010
    Hi. Let me start by saying: this is my 1st post here, this is a bit lenghty, and I havent done Windows Forms development in years....with that in mind please excuse me if this isn't directly a programming question and please bear with me as I really need the help!! I have been asked to develop a Windows Forms app for our company that talks to a central (local area network) Linux Server hosting a PostgreSQL database. The app is to allow users to authenticate themselves into the system and thereafter conduct the usual transactions with the PG database. Ordinarily, I would propose writing a webforms app against Mono, but the clients need to utilise local resources such as USB peripheral devices, so that is out of the question. While it might not seem clear, my questions are italised below: Dilemma #1: The application is meant to be always connected. How should I structure my DAL/BLL - Should this reside on the server or with the client? Dilemma #2: I have been reading up on Client Application Services (CAS), and it seems like a great fit for authentication, as everything is exposed via URIs. I know that a .NET Data Provider exists for PostgreSQL, but not too sure if CAS will all work on a Linux (Debian) server? Believe me, I would get my hands dirty and try myself, but I need to come up with a logical design first before resources are allocated to me for "trial purposes"! Dilemma #3: If the DAL/BLL is to reside on the server, is there any way I can create data services, and expose only these services to authenticated clients. There is a (security) requirement whereby a connection string with username and password to the database cannot be present on any client machines...even if security on the database side is quite rigid. I'm guessing that the only way for this to work would be to create the various CRUD data service methods that are exposed by an ASP.NET app, and have the WindowsForms make a request for data or persist data to the ASP.NET app (thru a URI) and have that return a resultset or value. Would I be correct in assuming this? Should I be looking into WCF Data Services? and will WCF work with a non-SQL Server database? Thank you for taking the time out to read this, but know that I am desperately seeking any advice on this! THANKS A MILLION!!!!

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  • devise register confirmation

    - by mattherick
    hello! i have a user and an admin role in my project. i created my authentification with devise, really nice and goot tool for handling the authentification. in my admin role i don´t have any confirmation or something like that. it is really simple and doesn´t make problems. but in my user model i have following things: model: devise :database_authenticatable, :confirmable, :recoverable, :rememberable, :trackable, :validatable, :timeoutable, :registerable # Setup accessible (or protected) attributes for your model attr_accessible :email, :username, :prename, :surname, :phone, :street, :number, :location, :password, :password_confirmation and few validations, but they aren´t relevant this time. my migration looks like following one: class DeviseCreateUsers < ActiveRecord::Migration def self.up create_table(:users) do |t| t.database_authenticatable :null = false t.confirmable t.recoverable t.rememberable t.trackable t.timeoutable t.validateable t.string :username t.string :prename t.string :surname t.string :phone t.string :street t.integer :number t.string :location t.timestamps end add_index :users, :email, :unique => true add_index :users, :confirmation_token, :unique => true add_index :users, :reset_password_token, :unique => true add_index :users, :username, :unique => true add_index :users, :prename, :unique => false add_index :users, :surname, :unique => false add_index :users, :phone, :unique => false add_index :users, :street, :unique => false add_index :users, :number, :unique => false add_index :users, :location, :unique => false end def self.down drop_table :users end end into my route.rb I added following statements: map.devise_for :admins map.devise_for :users, :path_names = { :sign_up = "register", :sign_in = "login" } map.root :controller = "main" and now my problem.. if I register a new user, I fill in all my data in the register form and submit it. After that I get redirected to the controller main with the flash-notice "You have signed up successfully." And I am logged in. But I don´t want to be logged in, because I don´t have confirmed my new user account yet. If I open the console I see the last things in the logs and there I see the confirmation-mail and the text and all stuff, but I am already logged in... I can´t explain why, ... does somebody of you have an idea? If I copy out the confirmation-token from the logs and confirm my account, I can log in, but if I don´t confirm, I also can log in..

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  • .NET datetime issue with SQL stored procedure

    - by DanO
    I am getting the below error when executing my application on a Windows XP machine with .NET 2.0 installed. On my computer Windows 7 .NET 2.0 - 3.5 I am not having any issues. The target SQL server version is 2005. This error started occurring when I added the datetime to the stored procedure. I have been reading alot about using .NET datetime with SQL datetime and I still have not figured this out. If someone can point me in the right direction I would appreciate it. Here is the where I believe the error is coming from. private static void InsertRecon(string computerName, int EncryptState, TimeSpan FindTime, Int64 EncryptSize, DateTime timeWritten) { SqlConnection DBC = new SqlConnection("server=server;UID=InventoryServer;Password=pass;database=Inventory;connection timeout=30"); SqlCommand CMD = new SqlCommand(); try { CMD.Connection = DBC; CMD.CommandType = CommandType.StoredProcedure; CMD.CommandText = "InsertReconData"; CMD.Parameters.Add("@CNAME", SqlDbType.NVarChar); CMD.Parameters.Add("@ENCRYPTEXIST", SqlDbType.Int); CMD.Parameters.Add("@RUNTIME", SqlDbType.Time); CMD.Parameters.Add("@ENCRYPTSIZE", SqlDbType.BigInt); CMD.Parameters.Add("@TIMEWRITTEN", SqlDbType.DateTime); CMD.Parameters["@CNAME"].Value = computerName; CMD.Parameters["@ENCRYPTEXIST"].Value = EncryptState; CMD.Parameters["@RUNTIME"].Value = FindTime; CMD.Parameters["@ENCRYPTSIZE"].Value = EncryptSize; CMD.Parameters["@TIMEWRITTEN"].Value = timeWritten; DBC.Open(); CMD.ExecuteNonQuery(); } catch (System.Data.SqlClient.SqlException e) { PostMessage(e.Message); } finally { DBC.Close(); CMD.Dispose(); DBC.Dispose(); } } Unhandled Exception: System.ArgumentOutOfRangeException: The SqlDbType enumeration value, 32, is invalid. Parameter name: SqlDbType at System.Data.SqlClient.MetaType.GetMetaTypeFromSqlDbType(SqlDbType target) at System.Data.SqlClient.SqlParameter.set_SqlDbType(SqlDbType value) at System.Data.SqlClient.SqlParameter..ctor(String parameterName, SqlDbType dbType) at System.Data.SqlClient.SqlParameterCollection.Add(String parameterName, SqlDbType sqlDbType) at ReconHelper.getFilesInfo.InsertRecon(String computerName, Int32 EncryptState, TimeSpan FindTime, Int64 EncryptSize, DateTime timeWritten) at ReconHelper.getFilesInfo.Main(String[] args)

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  • Feedback on Optimizing C# NET Code Block

    - by Brett Powell
    I just spent quite a few hours reading up on TCP servers and my desired protocol I was trying to implement, and finally got everything working great. I noticed the code looks like absolute bollocks (is the the correct usage? Im not a brit) and would like some feedback on optimizing it, mostly for reuse and readability. The packet formats are always int, int, int, string, string. try { BinaryReader reader = new BinaryReader(clientStream); int packetsize = reader.ReadInt32(); int requestid = reader.ReadInt32(); int serverdata = reader.ReadInt32(); Console.WriteLine("Packet Size: {0} RequestID: {1} ServerData: {2}", packetsize, requestid, serverdata); List<byte> str = new List<byte>(); byte nextByte = reader.ReadByte(); while (nextByte != 0) { str.Add(nextByte); nextByte = reader.ReadByte(); } // Password Sent to be Authenticated string string1 = Encoding.UTF8.GetString(str.ToArray()); str.Clear(); nextByte = reader.ReadByte(); while (nextByte != 0) { str.Add(nextByte); nextByte = reader.ReadByte(); } // NULL string string string2 = Encoding.UTF8.GetString(str.ToArray()); Console.WriteLine("String1: {0} String2: {1}", string1, string2); // Reply to Authentication Request MemoryStream stream = new MemoryStream(); BinaryWriter writer = new BinaryWriter(stream); writer.Write((int)(1)); // Packet Size writer.Write((int)(requestid)); // Mirror RequestID if Authenticated, -1 if Failed byte[] buffer = stream.ToArray(); clientStream.Write(buffer, 0, buffer.Length); clientStream.Flush(); } I am going to be dealing with other packet types as well that are formatted the same (int/int/int/str/str), but different values. I could probably create a packet class, but this is a bit outside my scope of knowledge for how to apply it to this scenario. If it makes any difference, this is the Protocol I am implementing. http://developer.valvesoftware.com/wiki/Source_RCON_Protocol

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  • Cannot extend a class located in another file, PHP

    - by NightMICU
    I am trying to set up a class with commonly used tasks, such as preparing strings for input into a database and creating a PDO object. I would like to include this file in other class files and extend those classes to use the common class' code. However, when I place the common class in its own file and include it in the class it will be used in, I receive an error that states the second class cannot be found. For example, if the class name is foo and it is extending bar (the common class, located elsewhere), the error says that foo cannot be found. But if I place the code for class bar in the same file as foo, it works. Here are the classes in question - Common Class abstract class coreFunctions { protected $contentDB; public function __construct() { $this->contentDB = new PDO('mysql:host=localhost;dbname=db', 'username', 'password'); } public function cleanStr($string) { $cleansed = trim($string); $cleansed = stripslashes($cleansed); $cleansed = strip_tags($cleansed); return $cleansed; } } Code from individual class include $_SERVER['DOCUMENT_ROOT'] . '/includes/class.core-functions.php'; $mode = $_POST['mode']; if (isset($mode)) { $gallery = new gallery; switch ($mode) { case 'addAlbum': $gallery->addAlbum($_POST['hash'], $_POST['title'], $_POST['description']); } } class gallery extends coreFunctions { private function directoryPath($string) { $path = trim($string); $path = strtolower($path); $path = preg_replace('/[^ \pL \pN]/', '', $path); $path = preg_replace('[\s+]', '', $path); $path = substr($path, 0, 18); return $path; } public function addAlbum($hash, $title, $description) { $title = $this->cleanStr($title); $description = $this->cleanStr($description); $path = $this->directoryPath($title); if ($title && $description && $hash) { $addAlbum = $this->contentDB->prepare("INSERT INTO gallery_albums (albumHash, albumTitle, albumDescription, albumPath) VALUES (:hash, :title, :description, :path)"); $addAlbum->execute(array('hash' => $hash, 'title' => $title, 'description' => $description, 'path' => $path)); } } } The error when I try it this way is Fatal error: Class 'gallery' not found in /home/opheliad/public_html/admin/photo-gallery/includes/class.admin_photo-gallery.php on line 10

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  • NHibernate unable to create SessionFactory

    - by Tyler
    I'm having a bit of trouble setting up NHibernate, and I'm not too sure what the problem is exactly. I'm attempting to save a domain object to the database (Oracle 10g XE). However, I'm getting a TypeInitializationException while trying to create the ISessionFactory. Here is what my hibernate.cfg.xml looks like: <?xml version="1.0" encoding="utf-8"?> <hibernate-configuration xmlns="urn:nhibernate-configuration-2.2" > <session-factory name="MyProject.DataAccess"> <property name="connection.driver_class">NHibernate.Driver.OracleClientDriver</property> <property name="connection.connection_string"> User ID=myid;Password=mypassword;Data Source=localhost </property> <property name="show_sql">true</property> <property name="dialect">NHibernate.Dialect.OracleDialect</property> <property name="proxyfactory.factory_class">NHibernate.ByteCode.LinFu.ProxyFactoryFactory, NHibernate.ByteCode.LinFu</property> <mapping resource="MyProject/Domain/User.hbm.xml"/> </session-factory> </hibernate-configuration> I created a DAO which I will use to persist domain objects to the database. The DAO uses a HibernateUtil class that creates the SessionFactory. Both classes are in the DataAccess namespace along with the Hibernate configuration. This is where the exception is occuring. Here's that class: public class HibernateUtil { private static ISessionFactory SessionFactory = BuildSessionFactory(); private static ISessionFactory BuildSessionFactory() { try { // This seems to be where the problem occurs return new Configuration().Configure().BuildSessionFactory(); } catch (TypeInitializationException ex) { Console.WriteLine("Initial SessionFactory creation failed." + ex); throw new Exception("Unable to create SessionFactory."); } } public static ISessionFactory GetSessionFactory() { return SessionFactory; } } The DataAccess namespace references the NHibernate DLLs. This is virtually the same setup I've used with Hibernate in Java, so I'm not entirely sure what I'm doing wrong here. Any ideas? Edit The innermost exception is the following: "Could not find file 'C:\Users\Tyler\Documents\Visual Studio 2010\Projects\MyProject\MyProject\ConsoleApplication\bin\Debug\hibernate.cfg.xml'." ConsoleApplication contains the entry point where I've created a User object and am trying to persist it with my DAO. Why is it looking for the configuration file there? The actual persisting takes place in the DAO, which is in DataAccess. Also, when I add the configuration file to ConsoleApplication, it still does not find it.

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  • Running OpenMPI on Windows XP

    - by iamweird
    Hi there. I'm trying to build a simple cluster based on Windows XP. I compiled OpenMPI-1.4.2 successfully, and tools like mpicc and ompi_info work too, but I can't get my mpirun working properly. The only output I can see is Z:\orterun --hostfile z:\hosts.txt -np 2 hostname [host0:04728] Failed to initialize COM library. Error code = -2147417850 [host0:04728] [[8946,0],0] ORTE_ERROR_LOG: Error in file ..\..\openmpi-1.4.2 \orte\mca\ess\hnp\ess_hnp_module.c at line 218 -------------------------------------------------------------------------- It looks like orte_init failed for some reason; your parallel process is likely to abort. There are many reasons that a parallel process can fail during orte_init; some of which are due to configuration or environment problems. This failure appears to be an internal failure; here's some additional information (which may only be relevant to an Open MPI developer): orte_plm_init failed -- Returned value Error (-1) instead of ORTE_SUCCESS -------------------------------------------------------------------------- [host0:04728] [[8946,0],0] ORTE_ERROR_LOG: Error in file ..\..\openmpi-1.4.2 \orte\runtime\orte_init.c at line 132 -------------------------------------------------------------------------- It looks like orte_init failed for some reason; your parallel process is likely to abort. There are many reasons that a parallel process can fail during orte_init; some of which are due to configuration or environment problems. This failure appears to be an internal failure; here's some additional information (which may only be relevant to an Open MPI developer): orte_ess_set_name failed -- Returned value Error (-1) instead of ORTE_SUCCESS -------------------------------------------------------------------------- [host0:04728] [[8946,0],0] ORTE_ERROR_LOG: Error in file ..\..\..\..\openmpi -1.4.2\orte\tools\orterun\orterun.c at line 543 Where z:\hosts.txt appears as follows: host0 host1 Z: is a shared network drive available to both host0 and host1. What my problem is and how do I fix it? Upd: Ok, this problem seems to be fixed. It seems to me that WideCap driver and/or software components causes this error to appear. A "clean" machine runs local task successfully. Anyway, I still cannot run a task within at least 2 machines, I'm getting following message: Z:\mpirun --hostfile z:\hosts.txt -np 2 hostname connecting to host1 username:cluster password:******** Save Credential?(Y/N) y [host0:04728] This feature hasn't been implemented yet. [host0:04728] Could not connect to namespace cimv2 on node host1. Error code =-2147024891 -------------------------------------------------------------------------- mpirun was unable to start the specified application as it encountered an error. More information may be available above. -------------------------------------------------------------------------- I googled a little and did all the things as described here: http://www.open-mpi.org/community/lists/users/2010/03/12355.php but I'm still getting the same error. Can anyone help me? Upd2: Error code -2147024891 might be WMI error WBEM_E_INVALID_PARAMETER (0x80041008) which occures when one of the parameters passed to the WMI call is not correct. Does this mean that the problem is in OpenMPI source code itself? Or maybe it's because of wrong/outdated wincred.h and credui.lib I used while building OpenMPI from the source code?

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  • Table prefix for MySqlMembershipProvider

    - by choudeshell
    I have MySqlMembershipProvider working with Asp.Net MVC. My question is how can I configure the table prefix... so instead of 'my_aspnet_' prefix on the tables, I want this to be either none or defined by me. My web.config: <?xml version="1.0"?> <add name="ApplicationServices" connectionString="server=localhost;user id=root;Password=*********;database=sparkSources" providerName="MySql.Data.MySqlClient"/> <authentication mode="Forms"> <forms loginUrl="~/Account/LogOn" timeout="2880" /> </authentication> <membership defaultProvider="MySqlMembershipProvider"> <providers> <clear/> <add name="MySqlMembershipProvider" type="MySql.Web.Security.MySQLMembershipProvider, MySql.Web, Version=6.3.4.0, Culture=neutral, PublicKeyToken=c5687fc88969c44d" autogenerateschema="true" tablePrefix="ss" connectionStringName="ApplicationServices" enablePasswordRetrieval="false" enablePasswordReset="true" requiresQuestionAndAnswer="false" requiresUniqueEmail="false" passwordFormat="Hashed" maxInvalidPasswordAttempts="5" minRequiredPasswordLength="6" minRequiredNonalphanumericCharacters="0" passwordAttemptWindow="10" passwordStrengthRegularExpression="" applicationName="sparkSources" /> </providers> </membership> <profile> <providers> <clear/> <add name="AspNetSqlProfileProvider" type="System.Web.Profile.SqlProfileProvider" connectionStringName="ApplicationServices" applicationName="/" /> </providers> </profile> <roleManager enabled="false"> <providers> <clear/> <add name="AspNetSqlRoleProvider" type="System.Web.Security.SqlRoleProvider" connectionStringName="ApplicationServices" applicationName="/" /> <add name="AspNetWindowsTokenRoleProvider" type="System.Web.Security.WindowsTokenRoleProvider" applicationName="/" /> </providers> </roleManager> <pages> <namespaces> <add namespace="System.Web.Mvc" /> <add namespace="System.Web.Mvc.Ajax" /> <add namespace="System.Web.Mvc.Html" /> <add namespace="System.Web.Routing" /> </namespaces> </pages>

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  • L-Soft LISTSERV TCPGUI Interface for PHP Creation

    - by poolnoodl
    I'm trying to use LISTSERV's "API" in PHP. L-Soft calls this TCPGUI, and essentially, you can request data like over Telnet. To do this, I'm using PHP's TCP socket functions. I've seen this done in other languages but can't quite convert it to PHP. I can connect, I can change set ASCII or BINARY mode. But I can never quite craft the header packet the way I need to authenticate, so I'm thinking I'm messing up my conversion. C: http://www.lsoft.com/manuals/16.0/htmlhelp/advanced%20topics/TCPGUI.html#2334328 $origin = '[email protected]'; $pwd = 'password'; $host = "example.com"; $port = 2306; $email = "[email protected]"; $list = "mailinglist"; $command = "Query $list FOR $email"; $fp = stream_socket_client("tcp://$host:$port", $errno, $errstr, 30); $cmd = $command . " PW=" . $pwd; $len = strlen($cmd); $orglen = strlen($origin); $n = $len + $orglen + 1; $headerPacket[0] = "1"; $headerPacket[1] = "B"; $headerPacket[2] = "\r"; $headerPacket[3] = "\n"; $headerPacket[4] = ord($n / 256); $headerPacket[5] = ord($n + 255); $headerPacket[6] = ord($orglen); for ($i = 0; $i < $orglen; $i++) { $headerPacket[$i + 7] = ord($origin[$i]); } for ($i = 0; $i < $len; $i++) { $cmdPacket[$i] = ord($cmd[$i]); } fwrite($fp, implode($headerPacket)); while (!feof($fp)) { echo fgets($fp, 1024); } Any thoughts on where I'm going wrong? I'd much appreciate it if anyone could point me toward some code to do this, days of googling and searching here on SO has only lead me to examples in other languages. Of course, if you know C (or Java or Perl as linked below in my comment to bypass the spam filter), PHP, and socket programming fairly well, you could probably rewrite the whole of the code in an hour, maybe a few minutes. You'd have my eternal thanks for that.

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  • Converting my lightweight MySQL DB wrapper into MySQLi. Pesky Problems

    - by Chaplin
    Here is the original code: http://pastebin.com/DNxtmApY. I'm not that interested in prepared statements at the moment, I just want this wrapper updating to MySQLi so once MySQL becomes depreciated I haven't got to update a billion websites. Here is my attempt at converting to MySQLi. <? $database_host = "127.0.0.1"; $database_user = "user"; $database_pass = "pass"; $database_name = "name"; $db = new database($database_host, $database_user, $database_pass, $database_name); class database { var $link, $result; function database($host, $user, $pass, $db) { $this->link = mysqli_connect($host, $user, $pass, $db) or $this->error(); mysqli_select_db($db, $this->link) or $this->error(); } function query($query) { $this->result = mysqli_query($query, $this->link) or $this->error(); $this->_query_count++; return $this->result; } function countRows($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_num_rows($result); } function fetch($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result); } function fetch_num($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result, mysqli_NUM); } function fetch_assoc($result = "") { if ( empty( $result ) ) $result = $this->result; return mysqli_fetch_array($result, mysqli_ASSOC); } function escape($str) { return mysqli_real_escape_string($str); } function error() { if ( $_GET["debug"] == 1 ){ die(mysqi_error()); } else { echo "Error in db code"; } } } function sanitize($data) { //apply stripslashes if magic_quotes_gpc is enabled if(get_magic_quotes_gpc()) $data = stripslashes($data); // a mysqli connection is required before using this function $data = trim(mysqli_real_escape_string($data)); return $data; } However it chucks all sorts of errors: Warning: mysql_query(): Access denied for user 'www-data'@'localhost' (using password: NO) in /home/count/Workspace/lib/classes/user.php on line 7 Warning: mysql_query(): A link to the server could not be established in /home/count/Workspace/lib/classes/user.php on line 7 Warning: mysql_fetch_array() expects parameter 1 to be resource, boolean given in /home/count/Workspace/lib/classes/user.php on line 8 Warning: mysqli_fetch_array() expects parameter 1 to be mysqli_result, object given in /home/count/Workspace/lib/classes/database.php on line 31

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  • assign a model's attribute through association

    - by justcode
    I'm new to rails and working on a rails app and I'm stuck pondering this issue. I have three models class product < ActiveRecord::Base attr_accessible :name, :issn, :category validates_presence_of :name, :issn, :category validates_numericality_of :issn, :message => "has to be a number" has_many :user_products has_many :users, :through => :user_products end class UserProduct < ActiveRecord::Base attr_accessible :price, :category validates_presence_of :price, :category validates_numericality_of :price, :message = "has to be a number" belongs_to :user belongs_to :product end class user < ActiveRecord::Base # devise authentication here # Setup accessible (or protected) attributes for your model attr_accessible :email, :password, :password_confirmation, :remember_me has_many :user_products has_many :products, :through = :user_products end here is my new.html.erb <div class="MainBodyWrapper"> <div class="span8"> <div id="listBoxWrapper"> <fieldset> <%= form_for(@product, :html => { :class => "form-inline" }, :style => "margin-bottom: 60px" ) do |f| %> <div class="control-group"> <label class="control-label" for="name">name</label> <div class="controls"> <%= f.text_field :price, :class => 'input-xlarge input-name', :id => "name" %> </div> </div> <div class="listingButtons"> <button class="btn btn-info"></i>Add</button> <a class="btn">Upload Pictures (anytime)</a> </div> </fieldset> </div> </div> There are reasons why I want to setup the models this way. So the question is this: I want the user to enter the info for the product in the form but it also involves putting in the price of the product which exists in a different model/table (user_product) that is associated with product. How can I do this? You can see that my form_for uses @product. Any help will be appreciated.

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