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  • A Duplicate name exists on the network

    - by Adam
    Recently we changed out office IT structure from having a dedicated server to be the DC, a dedicated server for the exchange etc... (Each running Windows Server 2003 R2) Now we have a single server running Windows SBS 2008 and created a new domain (with a different domain name) We then changed every PC so it connected to the new domain and renamed every PC with a new naming structure. After I had done this, we were getting several PCs that would get the following message just before the login screen (Alt+Ctrl+Del Screen) A Duplicate name exists on the network I have checked the ADUC and have removed the trouble PCs from the list and renamed each PC and changed the SID before connecting back onto the domain but still getting this message. I have tried everything that i can think of but still getting the problem. Any help would be greatly appreticated.

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  • How to Upload a file from client to server using OFBIZ?

    - by SIVAKUMAR.J
    Hi all, Im new to ofbiz.So is my question is have any mistake forgive me for my mistakes.Im new to ofbiz so i did not know some terminologies in ofbiz.Sometimes my question is not clear because of lack of knowledge in ofbiz.So try to understand my question and give me a good solution with respect to my level.Because some solutions are in very high level cannot able to understand for me.So please give the solution with good examples. My problem is i created a project inside the ofbiz/hot-deploy folder namely "productionmgntSystem".Inside the folder "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem" i created a .ftl file namely "app_details_1.ftl" .The following are the coding of this file <html> <head> <meta http-equiv="Content-Type" content="text/html; charset=ISO-8859-1"> <title>Insert title here</title> <script TYPE="TEXT/JAVASCRIPT" language=""JAVASCRIPT"> function uploadFile() { //alert("Before calling upload.jsp"); window.location='<@ofbizUrl>testing_service1</@ofbizUrl>' } </script> </head> <!-- <form action="<@ofbizUrl>testing_service1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> --> <form action="<@ofbizUrl>logout1</@ofbizUrl>" enctype="multipart/form-data" name="app_details_frm"> <center style="height: 299px; "> <table border="0" style="height: 177px; width: 788px"> <tr style="height: 115px; "> <td style="width: 103px; "> <td style="width: 413px; "><h1>APPLICATION DETAILS</h1> <td style="width: 55px; "> </tr> <tr> <td style="width: 125px; ">Application name : </td> <td> <input name="app_name_txt" id="txt_1" value=" " /> </td> </tr> <tr> <td style="width: 125px; ">Excell sheet &nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;&nbsp;: </td> <td> <input type="file" name="filename"/> </td> </tr> <tr> <td> <!-- <input type="button" name="logout1_cmd" value="Logout" onclick="logout1()"/> --> <input type="submit" name="logout_cmd" value="logout"/> </td> <td> <!-- <input type="submit" name="upload_cmd" value="Submit" /> --> <input type="button" name="upload1_cmd" value="Upload" onclick="uploadFile()"/> </td> </tr> </table> </center> </form> </html> the following coding is present in the file "ofbiz\hot-deploy\productionmgntSystem\webapp\productionmgntSystem\WEB-INF\controller.xml" ...... ....... ........ <request-map uri="testing_service1"> <security https="true" auth="true"/> <event type="java" path="org.ofbiz.productionmgntSystem.web_app_req.WebServices1" invoke="testingService"/> <response name="ok" type="view" value="ok_view"/> <response name="exception" type="view" value="exception_view"/> </request-map> .......... ............ .......... <view-map name="ok_view" type="ftl" page="ok_view.ftl"/> <view-map name="exception_view" type="ftl" page="exception_view.ftl"/> ................ ............. ............. The following are the coding present in the file "ofbiz\hot-deploy\productionmgntSystem\src\org\ofbiz\productionmgntSystem\web_app_req\WebServices1.java" package org.ofbiz.productionmgntSystem.web_app_req; import javax.servlet.http.HttpServletRequest; import javax.servlet.http.HttpServletResponse; import java.io.DataInputStream; import java.io.FileOutputStream; import java.io.IOException; public class WebServices1 { public static String testingService(HttpServletRequest request, HttpServletResponse response) { //int i=0; String result="ok"; System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- Start"); String contentType=request.getContentType(); System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- contentType : "+contentType); String str=new String(); // response.setContentType("text/html"); //PrintWriter writer; if ((contentType != null) && (contentType.indexOf("multipart/form-data") >= 0)) { System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) after if (contentType != null)"); try { // writer=response.getWriter(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try Start"); DataInputStream in = new DataInputStream(request.getInputStream()); int formDataLength = request.getContentLength(); byte dataBytes[] = new byte[formDataLength]; int byteRead = 0; int totalBytesRead = 0; //this loop converting the uploaded file into byte code while (totalBytesRead < formDataLength) { byteRead = in.read(dataBytes, totalBytesRead,formDataLength); totalBytesRead += byteRead; } String file = new String(dataBytes); //for saving the file name String saveFile = file.substring(file.indexOf("filename=\"") + 10); saveFile = saveFile.substring(0, saveFile.indexOf("\n")); saveFile = saveFile.substring(saveFile.lastIndexOf("\\")+ 1,saveFile.indexOf("\"")); int lastIndex = contentType.lastIndexOf("="); String boundary = contentType.substring(lastIndex + 1,contentType.length()); int pos; //extracting the index of file pos = file.indexOf("filename=\""); pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; pos = file.indexOf("\n", pos) + 1; int boundaryLocation = file.indexOf(boundary, pos) - 4; int startPos = ((file.substring(0, pos)).getBytes()).length; int endPos = ((file.substring(0, boundaryLocation)).getBytes()).length; //creating a new file with the same name and writing the content in new file FileOutputStream fileOut = new FileOutputStream("/"+saveFile); fileOut.write(dataBytes, startPos, (endPos - startPos)); fileOut.flush(); fileOut.close(); System.out.println("\n\n\t**********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - try End"); } catch(IOException ioe) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch IOException"); //ioe.printStackTrace(); return("exception"); } catch(Exception ex) { System.out.println("\n\n\t*********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) - Catch Exception"); return("exception"); } } else { System.out.println("\n\n\t********************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response) else part"); result="exception"; } System.out.println("\n\n\t*************************************\n\tInside WebServices1.testingService(HttpServletRequest request, HttpServletResponse response)- End"); return(result); } } I want to upload a file to the server.The file is get from user "<input type="file"..> tag in the "app_details_1.ftl" file & it is updated into the server by using the method "testingService(HttpServletRequest request, HttpServletResponse response)" in the class "WebServices1".But the file is not uploaded. Give me a good solution for uploading a file to the server. Thanks & Regards, Sivakumar.J

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  • Java compiler error: "cannot find symbol" when trying to access local variable

    - by HH
    $ javac GetAllDirs.java GetAllDirs.java:16: cannot find symbol symbol : variable checkFile location: class GetAllDirs System.out.println(checkFile.getName()); ^ 1 error $ cat GetAllDirs.java import java.util.*; import java.io.*; public class GetAllDirs { public void getAllDirs(File file) { if(file.isDirectory()){ System.out.println(file.getName()); File checkFile = new File(file.getCanonicalPath()); }else if(file.isFile()){ System.out.println(file.getName()); File checkFile = new File(file.getParent()); }else{ // checkFile should get Initialized at least HERE! File checkFile = file; } System.out.println(file.getName()); // WHY ERROR HERE: checkfile not found System.out.println(checkFile.getName()); } public static void main(String[] args) { GetAllDirs dirs = new GetAllDirs(); File current = new File("."); dirs.getAllDirs(current); } }

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  • Visual Studio 2008 project file does not load because of an unexpected encoding change.

    - by Xenan
    In our team we have a database project in visual Studio 2008 which is under source control by Team Foundation Server. Every two weeks or so, after one co-worker checks in, the project file won't load on the other developers machines. The error message is: The project file could not be loaded. Data at the root level is invalid. Line 1, position 1. When I look at the project file in Notepad++, the file looks like this: ??<NUL?NULxNULmNULlNUL NULvNULeNULrNULsNULiNULoNULnNUL ... and so on (you can see <?xml version in this) whereas an normal project file looks like: <?xml version="1.0" encoding="utf-16"?> ... So probably something is wrong with the encoding of the file. This is a problem for us because it turns out to be impossible to get the file encoding correct again. The 'solution' is to throw away the project file an get the last know working version from source control. According to the file, the encoding should be UTF-16. According to Notepad++, the corrupted file is actually UTF-8. My questions are: Why is Visual Studio messing up the encoding of the project file, apparently at random times and at random machines? What should we do to prevent this? When it has happened, is there a possibility to restore the current file in the correct encoding instead of pulling an older version from source control? As a last note: the problem is with one single project file, all other project files don't expose this problem.

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  • File.Move does not inherit permissions from target directory?

    - by Joseph Kingry
    In case something goes wrong in creating a file, I've been writing to a temporary file and then moving to the destination. Something like: var destination = @"C:\foo\bar.txt"; var tempFile = Path.GetTempFileName(); using (var stream = File.OpenWrite(tempFile)) { // write to file here here } string backupFile = null; try { var dir = Path.GetDirectoryName(destination); if (!Directory.Exists(dir)) { Directory.CreateDirectory(dir); Util.SetPermissions(dir); } if (File.Exists(destination)) { backupFile = Path.Combine(Path.GetTempPath(), new Guid().ToString()); File.Move(destination, backupFile); } File.Move(tempFile, destination); if (backupFile != null) { File.Delete(backupFile); } } catch(IOException) { if(backupFile != null && !File.Exists(destination) && File.Exists(backupFile)) { File.Move(backupFile, destination); } } The problem is that the new "bar.txt" in this case does not inherit permissions from the "C:\foo" directory. Yet if I create a file via explorer/notepad etc directly in the "C:\foo" there's no issues, so I believe the permissions are correctly set on "C:\foo". Update Found Inherited permissions are not automatically updated when you move folders, maybe it applies to folders as well. Now looking for a way to force an update of file permissions. Is there a better way overall of doing this?

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  • Can't access my files in ASP.NET web site

    - by jumbojs
    I'm having a very difficult time. I am running windows 2008 server, I have an Able Commerce site using ASP.NET with C#. I'm writing an automated task that will ftp some xml files down into a local directory on our web server and then the program parses the xml file and saves information to our database. The problem, once I save the files to our local directory, my program has no access to the files. The NETWORK SERVICE user permissions isn't being inherited by the xml files so my program can't do anything with them. I can manually change the permissions, but this wouldn't be automated and won't work. How can I get this to work? help please, it's very frustrating.

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  • XML File as Excel file.

    - by FrustratedWithFormsDesigner
    I have a number of reports that I run against my database that need to eventually go to the end-users as Excel spreadsheets. Initially, I was creating text reports, but the steps to convert the text to a spreadsheet were a bit cumbersome. There were too many steps to import text to the spreadsheet, and multi-line text rows were imported as individual rows in Excel (which was incorrect). Currently, I am generating simple XML saving the file with an ".xls" extension. This works better, but there is still the problem of Excel prompting the user with an XML import dialogue every time they open the file, and then having to save a new file if they add notes or change the layout to the file (which they almost certainly will be doing). Sample "xls" file: <?xml version="1.0" standalone="yes"?> <report_rows> <row> <NAME>Test Data</NAME> <COUNT>345</COUNT> </row> <!-- many more row elements... --> </report_rows> Is there any way to add markup to the file to hint to Excel how it should import and handle the file? Ideally, the end user should be able to open and save the file like any othe spreadsheet they create directly from Excel. Is this even possible? UPDATE: We are running Office 2003 here. UPDATE: The XML is generated from a sqlplus script, no option to use C#/.NET here.

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  • What would happen if a same file being read and appended at the same time(python programming)?

    - by Shane
    I'm writing a script using two separate thread one doing file reading operation and the other doing appending, both threads run fairly frequently. My question is, if one thread happens to read the file while the other is just in the middle of appending strings such as "This is a test" into this file, what would happen? I know if you are appending a smaller-than-buffer string, no matter how frequently you read the file in other threads, there would never be incomplete line such as "This i" appearing in your read file, I mean the os would either do: append "This is a test" - read info from the file; or: read info from the file - append "This is a test" to the file; and such would never happen: append "This i" - read info from the file - append "s a test". But if "This is a test" is big enough(assuming it's a bigger-than-buffer string), the os can't do appending job in one operation, so the appending job would be divided into two: first append "This i" to the file, then append "s a test", so in this kind of situation if I happen to read the file in the middle of the whole appending operation, would I get such result: append "This i" - read info from the file - append "s a test", which means I might read a file that includes an incomplete string?

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  • General question: Filesystem or database?

    - by poeschlorn
    Hey guys, i want to create a small document management system. there are several users who store their files. each file which is uploaded contains an info which user uploaded it and the document content itself. In a view there are displayed all files of ONE specific user, ordered by date. What would be better: 1) giving the documents a name or metadata(XML) which contain the date and user (and iterate through them to get the metadata) or 2) giving the files a random/unique name and store metadata in a DB? something like this: date | user | filename What would you say and why? The used programming language is java and the DB is MySQL.

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  • CASE + IF MysQL query

    - by terence6
    Problem is as follows. I have a product that can be in one of three categories (defined by category_id). Each category table has category_id field related to category_id in product table. So I have 3 cases. I'm checking If my product.category_id is in table one. If yes, I take some values. If not I check in tables that are left. What can I write In the ELSE section? Can anyone correct my query ? CASE WHEN IF EXISTS(SELECT * FROM table1 WHERE category_id='category_id') THEN SELECT type_id FROM table1 WHERE category_id='category_id'; WHEN IF EXISTS(SELECT * FROM table2 WHERE category_id='category_id') THEN SELECT value_id FROM table2 WHERE category_id='category_id'; WHEN IF EXISTS(SELECT * FROM table3 WHERE category_id='category_id') THEN SELECT group_id FROM table3 WHERE category_id='category_id'; ELSE "dont know what here"; END;

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  • Python: Parsing a colon delimited file with various counts of fields

    - by Mark
    I'm trying to parse a a few files with the following format in 'clientname'.txt hostname:comp1 time: Fri Jan 28 20:00:02 GMT 2011 ip:xxx.xxx.xx.xx fs:good:45 memory:bad:78 swap:good:34 Mail:good Each section is delimited by a : but where lines 0,2,6 have 2 fields... lines 1,3-5 have 3 or more fields. (A big issue I've had trouble with is the time: line, since 20:00:02 is really a time and not 3 separate fields. I have several files like this that I need to parse. There are many more lines in some of these files with multiple fields. ... for i in clients: if os.path.isfile(rpt_path + i + rpt_ext): # if the rpt exists then do this rpt = rpt_path + i + rpt_ext l_count = 0 for line in open(rpt, "r"): s_line = line.rstrip() part = s_line.split(':') print part l_count = l_count + 1 else: # else break break First I'm checking if the file exists first, if it does then open the file and parse it (eventually) As of now I'm just printing the output (print part) to make sure it's parsing right. Honestly, the only trouble I'm having at this point is the time: field. How can I treat that line specifically different than all the others? The time field is ALWAYS the 2nd line in all of my report files.

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  • Efficient way to check for changes to the contents of folders

    - by MrVimes
    I am creating an application that maintains a database of files of a certain type in a given folder (and all subfolders) Initially the program will recurse the folders and add any file it finds of that type to the database. I want the application to have the ability to re-scan the folder and add any files that were not there the last time the folders were scanned. It can't use the date created property of the file because there is a high chance of a file being added to the folders that isn't a new file. I am wondering what the most efficient way of doing this is, and if there is a way that doesn't involve checking each file is in the database already (which, if there are 5000 files would mean 5000 queries of a list 5000 items in size, or 25 million 'checks' for the sql engine to perform) I suppose a more specific question to acheive the same goal would be - is there a property of a file (in Microsoft Windows) that will reliably tell you when that file arrived in that folder.

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  • Best way to rename existing unique field names in database?

    - by Rajdeep Siddhapura
    I have a database table that contains id, filename, userId id is unique identifier filename should also be unique table may contain 10000 records When a user uploads a file it should be entered in database with given rules: If there is no record with same filename, it should be added as it is (Ex. foobar.pdf) If there is record with same filename, it should be added as uploadedName(2).ext (foobar(2).pdf) If there are n records with same base filename (foobar), it should be added as uploadedName(n+1).ext (foobar(20).pdf) Now if foobar(2).pdf is uploaded, it should be added as foobar(2)(2).pdf & so on This pattern needs to be followed because the file is already being uploaded at client side using ajax before sending the details to server and the file hosting service follows the above rules to name the files. My solution: maintain a file that contains all the names and the number of times it has occurred. if a filename that exists in file is entered, increase occurrence count and new name is generated, else add to it to file if the new name generated is in database, add it to file and generate new name

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  • Check if a Mail folder exists using Zend Mail

    - by Ali
    How can I check if an email folder exists using Zend_Mail_Storage_Imap, theres a createFOlder, renameFOlder and removeFolder and also a getFOlders but not exactly any fixed method to query if a certain mail folder exists? The GetFOlders returns a humonogous tree of folders to start with.

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  • OSX Weak Linking - check if a class exists and use that class

    - by psychotik
    I'm trying to create a universal iPhone app, but it uses a class defined only in a newer version of the SDK. The framework exists on older systems, but a class defined in the framework doesn't. I know I want to use some kind of weak linking, but any documentation I can find talks about runtime checks for function existence - how do I check that a class exists?

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  • Check if cookie exists if not create it.

    - by Ozaki
    TLDR: Want to check if cookie exists, if it doesn't create it. Am using jquery1.4.2 and jquery cookie, I know this is probably very simple but I just cant get my head right at the moment. I want to: Check to see if a cookie with name of "query" exists If so nothing. If not create a cookie "query" with a value of 1. But only if it doesn't already exist. Thanks in advance

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  • Check if Django model field choices exists

    - by Justin Lucas
    I'm attempting to check if a value exists in the choices tuple set for a model field. For example lets say I have a Model like this: class Vote(models.Model): VOTE_TYPE = ( (1, "Up"), (-1, "Down"), ) value = models.SmallIntegerField(max_length=1, choices=VOTE_TYPES) Now lets say in a view I have a variable new_value = 'Up' that I would like to use as the value field in a new Vote. How can I first check to see if the value of that variable exists in the VOTE_TYPE tuple? Thank you.

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  • Rewrite URL if file exists

    - by Anthony Faull
    I need to redirect web requests of the form /{language}-{country}/{file} to: /{language}-{country}/{file} if it exists, otherwise /{language}/{file} if it exists, otherwise /en-US/{file} The existing .htaccess fulfils requirements 1 and 3. What changes do I need to fulfil requirement 2? .htaccess: Options +FollowSymLinks RewriteEngine On RewriteCond $0 !i18n/en-US [NC] RewriteCond %{REQUEST_FILENAME} !-f RewriteRule ^(i18n)/([^/]+)/(.*)$ $1/en-US/$3 [NC,L]

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  • ActiveRecord WHERE NOT EXISTS

    - by jspooner
    Is there a way to use EXISTS with ActiveRecord besides find_by_sql? I'd like a nice way to find all records without an association in a One-to-Many relationship. SELECT DISTINCT store_type FROM stores WHERE NOT EXISTS (SELECT * FROM cities_stores WHERE cities_stores.store_type = stores.store_type)

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  • Simple Mod-Rewrite rule - single rule - file exists

    - by Andy Gee
    I have a very simple mod rewrite rule Options FollowSymLinks RewriteEngine On RewriteRule ^hosted/essws/([^/]*)/$ /hosted/essws/?key=$1 [L] I would like this rewrite to activate even if the file or directory exists. For example: The URL: http://localhost/hosted/essws/candy-sweets-buffet/ Will load: http://localhost/hosted/essws/index.php?key=candy-sweets-buffet Even though the directory /hosted/essws/candy-sweets-buffet/ exists. Any help would be much appreciated.

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  • SFTP jail & Keeping file ownership the same / File owner per folder

    - by Dragonshadow
    I want to setup a jailed SFTP account for a subfolder of another user's home folder, but want the owner of everything in that subfolder to stay the same, including new files and folders uploaded and created by the sftp user, while still allowing access to the files and folders of that subfolder as if the SFTP user was the parent user. rawny bawb-sftp /home/rawny <- rawny owns this /home/rawny/sftp <- rawny owns this too, but bawb-sftp can upload to it, edit files, etc bawb-sftp uploads a file /home/rawny/sftp/lol.txt rawny should still own the file, as if he made it in the first place, even though bawb-sftp was the one that uploaded it. Basically I guess I'm asking for an sftp jail that acts as a highly limited passthrough/puppet for another user?

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  • I started getting a weird message "Encrypting file system - Back up your file encryption key"

    - by user22559
    Hello I started getting a strange message when I start my computer. An icon appears in the system tray, and a popup tells me "Encrypting file system - Back up your file encryption key". I know what EFS is, but I don't use it. To my knowledge, I don't have any encrypted files on my partition. I have searched using Total Commander on all the partitions for files that have the "encrypted" attribute, but I found nothing. So I don't have any encrypted files. Does anyone know what I did to get this message?

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