Search Results

Search found 12806 results on 513 pages for 'die 20'.

Page 480/513 | < Previous Page | 476 477 478 479 480 481 482 483 484 485 486 487  | Next Page >

  • How to further improve error messages in Scala parser-combinator based parsers?

    - by rse
    I've coded a parser based on Scala parser combinators: class SxmlParser extends RegexParsers with ImplicitConversions with PackratParsers { [...] lazy val document: PackratParser[AstNodeDocument] = ((procinst | element | comment | cdata | whitespace | text)*) ^^ { AstNodeDocument(_) } [...] } object SxmlParser { def parse(text: String): AstNodeDocument = { var ast = AstNodeDocument() val parser = new SxmlParser() val result = parser.parseAll(parser.document, new CharArrayReader(text.toArray)) result match { case parser.Success(x, _) => ast = x case parser.NoSuccess(err, next) => { tool.die("failed to parse SXML input " + "(line " + next.pos.line + ", column " + next.pos.column + "):\n" + err + "\n" + next.pos.longString) } } ast } } Usually the resulting parsing error messages are rather nice. But sometimes it becomes just sxml: ERROR: failed to parse SXML input (line 32, column 1): `"' expected but `' found ^ This happens if a quote characters is not closed and the parser reaches the EOT. What I would like to see here is (1) what production the parser was in when it expected the '"' (I've multiple ones) and (2) where in the input this production started parsing (which is an indicator where the opening quote is in the input). Does anybody know how I can improve the error messages and include more information about the actual internal parsing state when the error happens (perhaps something like a production rule stacktrace or whatever can be given reasonably here to better identify the error location). BTW, the above "line 32, column 1" is actually the EOT position and hence of no use here, of course.

    Read the article

  • Why Can't Businesses Upgrade their Browsers from IE6/IE7?

    - by viatropos
    I have read lots these past few weeks on IE6, seeing if it was really that bad to make it look right. I have just learned HTML and CSS this past year so I've been spoiled to start with basically CSS3 and HTML5, and I can do some really cool stuff super fast. I'm no IE6 master and I don't have years of experience with IE. So I thought it'd take a little time to figure out all the hacks to IE6/7 discovered and just implement them. But it's way harder than that (or maybe just way too much work). I'd have to either completely rebuild my design using "Internet Explorer 'Principles'", or cut out a lot of the neat things I could do using more recent technologies. For a million and one other reasons, everyone who builds things online seems to think IE should die. My question is, why can't businesses upgrade their browsers? When I work with businesses, they almost always resist the first time I ask, but 5 seconds later I'll show them what it looks like on my computer and talk about how great the latest stuff is (how much more secure later browser are, all the famous IE security cases, how much smoother and faster they new browsers are, how the IE team has basically missed the boat entirely, how much smoother business processes run, etc.), and they get excited! And within a few seconds they're up and running with Chrome or something. So can businesses not upgrade for some reasons? What are the reasons a business cannot upgrade? The main reason I think of is because they have an old version of windows. But a) wasn't there a legal case against this? and b) somebody must have figured out how to install Chrome or Firefox on ancient versions of Windows by now.

    Read the article

  • Problem with configure script

    - by cube
    I am running into a problem with the ./configure script for ffmpeg. My linux environment uses busybox, which only allows for limited set of linux commands. One command which is used in the ffmpeg ./configure script is mktemp -u, the problem here is the busybox for linux does not recognize the -u switch as valid, so it complains about it and breaks the configure process. This is the relevant code in ./configure which uses the mktemp -u command: if ! check_cmd type mktemp; then # simple replacement for missing mktemp # NOT SAFE FOR GENERAL USE mktemp(){ echo "${2%XXX*}.${HOSTNAME}.${UID}.$$" } fi tmpfile(){ tmp=$(mktemp -u "${TMPDIR}/ffconf.XXXXXXXX")$2 && (set -C; exec > $tmp) 2>/dev/null || die "Unable to create temporary file in $TMPDIR." append TMPFILES $tmp eval $1=$tmp } I am not good with bash scripting at all, so I was wondering if anyone one had an idea on how I can force this configure script to not use mktemp -u and use the 'replacement' alternative option that is available in as per the snippet above. Thanks. btw... simply removing the -u switch does not work. Nor does replacing it with -t, or -p. I believe the mktemp has to be bypassed completely.

    Read the article

  • PHP & form validation

    - by user887515
    I have a form that I'm submitting via ajax, and I want to return a message of the list of fields that were empty. I've got that all done and dusted, but it just seems really long winded on the PHP side of things. How can I do the below in a less convoluted way? <?php if(empty($_POST["emailaddress"])){ $error = 'true'; $validation_msg = 'Country missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if(empty($_POST["password"])){ $error = 'true'; $validation_msg = 'Country missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if(empty($_POST["firstname"])){ $error = 'true'; $validation_msg = 'First name missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if(empty($_POST["lastname"])){ $error = 'true'; $validation_msg = 'Last name missing.'; if(empty($error_msg)){ $error_msg .= $validation_msg; } else{ $error_msg .= '\n' . $validation_msg; } } if($error){ header('HTTP/1.1 500 Internal Server Error'); header('Content-Type: application/json'); die($error_msg); } ?>

    Read the article

  • wxPython: MainLoop() seems to hang

    - by BandGap
    Hi all, my problem stems from the use of wxApp as far as I can tell. Inside a litte subroutine I call a wx.MessageDialog to ask for a yes or no. I retrieve the answer an process some stuff acordingly. My example code below actually works (though it might be ugly) except that the Dialog box stays open after hitting one of the buttons... import wx from os import path def HasFile(filename): if path.isfile(filename ): app = wx.App() dial = wx.MessageDialog(None, 'Die Datei "'+filename+'" wurde gefunden.\nSoll sie eingelesen werden?', 'Bitte antworten', wx.YES_NO | wx.YES_DEFAULT | wx.ICON_QUESTION) result = dial.ShowModal() dial.EndModal(retCode=0) dial.Destroy() app.MainLoop() return result == wx.ID_YES else: return False So while the rest of the program does whatever is expected, the box just sits there. It also seems like my calls to matplotlib later on are producing errors (a Tkinter error to be precise), maybe because of the wx stuff? Edit: I tried to end the app with a call to app.Destroy(). This doesn't change the fact that the box is still there. When I issue a app.IsActive() afterwards the whole program exits (almost like a sys.exit())! How come? Edit 2: Adding a wxApp like this isn't a good idea since the other scripts get affected as well. Subsequent plotting commands don't get displayed and I don't know how to fix this. Thus I decided to remove the DialogBox alltogether.

    Read the article

  • PHP syntax for postgresql Mixed-case table names

    - by yam
    I have a code below: <?php require "institution.php" /* in this portion, query for database connection is executed, and */ $institution= $_POST['institutionname']; $sCampID = 'SELECT ins_id FROM institution where ins_name= '$institution' '; $qcampID = pg_query($sCampID) or die("Error in query: $query." . pg_last_error($connection)); /* this portion outputs the ins_id */ ?> My database before has no mixed-case table names, that's why when I run this query, it shows no error at all. But because I've changed my database for some reasons, and it contains now mixed-case table names, i have to change the code above into this one: $sCampID = 'SELECT ins_id FROM "Institution" where ins_name= '$institution' '; where the Institution has to be double quoted. The query returned parse error. When i removed this portion: where ins_name= '$institution', no error occured. My question is how do I solve this problem where the table name which contains a mixed-case letter and a value stored in a variable ($institution in this case) will be combined in a single select statement? Your answers and suggestions will be very much appreciated.

    Read the article

  • opening word document contailning macros using textarea

    - by avani-nature
    Hai frnds i am avani here,actually 1.i amhaving one word document which contains macros i wann to open it in textarea.. 2.i am able to open the word document which is not containing macros 3.i am not able to open the document which contains macros 4.i am using below code 5.please do help me anyone i am thinking its some what impossible { //echo $aud; $filename = 'C:/xampp/htdocs/mts/sites/default/files/a.doc'; //echo $filename; if(isset($_REQUEST['Save'])){ $somecontent = stripslashes($_POST['somecontent']); // Let's make sure the file exists and is writable first. if (is_writable($filename)) { // In our example we're opening $filename in append mode. // The file pointer is at the bottom of the file hence // that's where $somecontent will go when we fwrite() it. if (!$handle = fopen($filename, 'w')) { echo "Cannot open file ($filename)"; exit; } // Write $somecontent to our opened file. if (fwrite($handle, $somecontent) === FALSE) { echo "Cannot write to file ($filename)"; exit; } echo "Success, wrote ($somecontent) to file ($filename) - Continue - "; fclose($handle); } else { echo "The file $filename is not writable"; } } else{ // get contents of a file into a string $handle = fopen($filename, "r"); $somecontent = fread($handle, filesize($filename)); $word = new COM("word.application") or die ("Could not initialise MS Word object."); $word-Documents-Open(realpath("$filename")); // Extract content. $somecontent = (string) $word-ActiveDocument-Content; //echo $somecontent; $word-ActiveDocument-Close(false); $word-Quit(); $word = null; unset($word); fclose($handle); } ? Edit file -------- ?

    Read the article

  • jQuery and MySQL

    - by Wayne
    I have taken a jQuery script which would remove divs on a click, but I want to implement deleting records of a MySQL database. In the delete.php: <?php $photo_id = $_POST['id']; $sql = "DELETE FROM photos WHERE id = '" . $photo_id . "'"; $result = mysql_query($sql) or die(mysql_error()); ?> The jQuery script: $(document).ready(function() { $('#load').hide(); }); $(function() { $(".delete").click(function() { $('#load').fadeIn(); var commentContainer = $(this).parent(); var id = $(this).attr("id"); var string = 'id='+ id ; $.ajax({ type: "POST", url: "delete.php", data: string, cache: false, success: function(){ commentContainer.slideUp('slow', function() {$("#photo-" + id).remove();}); $('#load').fadeOut(); } }); return false; }); }); The div goes away when I click on it, but then after I refresh the page, it appears again... How do I get it to delete it from the database? Thanks :) EDIT: Woopsie... forgot to add the db.php to it, so it works now .<

    Read the article

  • $_FILES is null, $_POST is not null

    - by Cory Dee
    When I am going to upload a file, my $_POST variable knows the file name, but the $_FILES variable is null. I've used this code before, so I'm really stumped. Here's what I'm using for input: <label for="importFile">Attach Resume:</label> <input type="hidden" name="MAX_FILE_SIZE" value="10000000"> <input type="file" name="importFile" id="importFile" class="validate['required']"> And for processing: $uploaddir = "E:/Sites/OPL/2008/assets/apps/newjobs/resumes/"; $uploadfile = $uploaddir . time() . '-' . urlencode(basename($_FILES['importFile']['name'])); if (!move_uploaded_file($_FILES['importFile']['tmp_name'], $uploadfile)) { echo 'Error uploading file. Error number: ' . $_FILES['importFile']['error']; var_dump($_FILES['importFile']); echo $_POST['importFile']; die(); } Which is giving me this result: Error uploading file. Error number: NULL Maintaining The OPL Website.doc Any help would be greatly appreciated.

    Read the article

  • decoding jquery json data in php

    - by Mac Taylor
    hey guys recenlty i made a script to move objects and save the orders now i have a little to do to finish this script everything works fine , just one question : how can i save not numeric data in my json script this is my script : function updateWidgetData(){ var items=[]; $('.widget-title').each(function(){ var weightId=$(this).attr('id'); $('.column').each(function(){ var columnId=$(this).attr('id'); $('.widget', this).each(function(i){ var collapsed=0; if($(this).find('.widget-inside').css('display')=="none") collapsed=1; //Create Item object for current panel var item={ id: $(this).attr('id'), collapsed: collapsed, order : i, column: columnId, weight: weightId }; //Push item object into items array items.push(item); }); }); }); //Assign items array to sortorder JSON variable var sortorder={ items: items }; //Pass sortorder variable to server using ajax to save state $.post('updatePanels.php', 'data='+$.toJSON(sortorder), function(response){ if(response=="success") $("#console").html('<div class="success">Saved</div>').hide().fadeIn(1000); setTimeout(function(){ $('#console').fadeOut(1000); }, 2000); }); } and this is my php script : $data=json_decode($_POST["data"]); foreach($data->items as $item) { //Extract column number for panel $col_id=preg_replace('/[^\d\s]/', '', $item->column); //Extract id of the panel $widget_id=preg_replace('/[^\d\s]/', '', $item->id); $sql="UPDATE widgets SET column_id='$col_id', sort_no='".$item->order."', collapsed='".$item->collapsed."' WHERE id='".$widget_id."'"; mysql_query($sql) or die('Error updating widget DB'); } echo "success"; everything works fine till i use numeric value for columns' id but i need non numeric values forexample id='columnr' i want to extract r but i cant get it right any help plz !?

    Read the article

  • [Concept] How does unlink() find the file to delete?

    - by Prasad
    My app has a 'Photo' field to store URL. It uses sfWidgetFormInputFileEditable for the widget schema. To delete the old image when a new image is uploaded, I use unlink before setting the value in the over-ridden setter and it works!!! if (file_exists($this->_get('photo'))) unlink($this->_get('photo')); Photos are stored in uploads/photos and when saving 'Photo' only the file name xxx-yyy.zzz is saved (and not the full path). However, I wish to know how symfony/php knows the full path of the file to be deleted? Part 2: I am using sfThumbnailPlugin to generate thumbnails. So the actual code looks like this: public function setPhoto($value) { if(!empty($value)) { Contact::generateThumbnail($value); // delete current Photo & create thumbnail $this->_set('photo',$value); // setting new value after deleting old one } } public function generateThumbnail($value) { $uploadDir = sfConfig::get('app_photo_upload'); // path to upload folder if (file_exists($this->_get('photo'))) { unlink($this->_get('photo')); // delete full-size image // path to thumbnail $thumbpath = $uploadDir.'/thumbnails/'.$this->get('photo'); // read a blog, tried setting dir manually, doesn't work :( //chdir('/thumbnails/'); // tried closing the file too, doesn't work! :( //fclose($thumbpath) or die("can't close file"); //unlink($this->_get('photo')); // doesn't work; no error :( unlink($thumbpath); // doesn't work, no error :( } $thumbnail = new sfThumbnail(150, 150); $thumbnail->loadFile($uploadDir.'/'.$value); $thumbnail->save($uploadDir.'/thumbnails/'.$value, 'image/png'); } Why can't the thumbnail be deleted using unlink()? is the sequence of ops incorrect? Is it because the old thumbnail is displayed in the sfWidgetFormInputFileEditable widget? I've spent hours trying to figure this out, but unable to nail down the real cause. Thanks in advance.

    Read the article

  • Zip multiple database PDF blob files

    - by Michael
    I have a database table that contains numerous PDF blob files. I am attempting to combine all of the files into a single ZIP file that I can download and then print. Please help! <?php include '../config.php'; include '../connect.php'; $session = $_GET['session']; $query = "SELECT $tbl_uploads.username, $tbl_uploads.description, $tbl_uploads.type, $tbl_uploads.size, $tbl_uploads.content, $tbl_members.session FROM $tbl_uploads LEFT JOIN $tbl_members ON $tbl_uploads.username = $tbl_members.username WHERE $tbl_members.session = '$session'"; $result = mysql_query($query) or die('Error, query failed'); $files = array(); while(list($username, $description, $type, $size, $content) = mysql_fetch_array($result)) { $files[] = "$username-$description.pdf"; } $zip = new ZipArchive; $zip->open('file.zip', ZipArchive::CREATE); foreach ($files as $file) { $zip->addFile($file); } $zip->close(); header('Content-Type: application/zip'); header('Content-disposition: attachment; filename=filename.zip'); header('Content-Length: ' . filesize($zipfilename)); readfile($zipname); exit(); ?>

    Read the article

  • Problem with mysql query in paging

    - by jasmine
    I have a very simple paging and mysql query. Im not sure that my query is right: $perPage =4; $page= (isset($GET['page']) && is_numeric($GET['page'])) ? $_GET['page'] : 1; $start = ($page * $perPage ) - $perPage ; if (is_numeric($_GET['cID'])){$cid = $_GET['cID'];} $totalCount = sprintf("SELECT COUNT(*) as 'Total' FROM content WHERE catID = %d", $cid ) ; $count = mysql_query($totalCount); $rowCount = mysql_fetch_array($count); $sql = sprintf("SELECT id, title, abstract, content_image FROM content WHERE catID = %d ORDER BY id DESC LIMIT %d, %d", $cid, $start, $perPage ); $query = mysql_query($sql) or die(mysql_error()); while($row = mysql_fetch_array($query)){ echo $row['id'].' : '. $row['title'] .'<br>'; } with /categories.php?cID=1&page=2 and /categories.php?cID=1&page=1 The output is: 95 : titlev 94 : titlex 93 : titlec 92 : titleb and not changed. What is wrong in my query? Thanks in advance

    Read the article

  • Help Optimizing MySQL Table (~ 500,000 records).

    - by Pyrite
    I have a MySQL table that collects player data from various game servers (Urban Terror). The bot that collects the data runs 24/7, and currently the table is up to about 475,000+ records. Because of this, querying this table from PHP has become quite slow. I wonder what I can do on the database side of things to make it as optomized as possible, then I can focus on the application to query the database. The table is as follows: CREATE TABLE IF NOT EXISTS `people` ( `id` bigint(20) unsigned NOT NULL AUTO_INCREMENT, `name` varchar(40) NOT NULL, `ip` int(4) unsigned NOT NULL, `guid` varchar(32) NOT NULL, `server` int(4) unsigned NOT NULL, `date` int(11) NOT NULL, PRIMARY KEY (`id`), UNIQUE KEY `Person` (`name`,`ip`,`guid`), KEY `server` (`server`), KEY `date` (`date`), KEY `PlayerName` (`name`) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 COMMENT='People that Play on Servers' AUTO_INCREMENT=475843 ; I'm storying the IPv4 (ip and server) as 4 byte integers, and using the MySQL functions NTOA(), etc to encode and decode, I heard that this way is faster, rather than varchar(15). The guid is a md5sum, 32 char hex. Date is stored as unix timestamp. I have a unique key on name, ip and guid, as to avoid duplicates of the same player. Do I have my keys setup right? Is the way I'm storing data efficient? Here is the code to query this table. You search for a name, ip, or guid, and it grabs the results of the query and cross references other records that match the name, ip, or guid from the results of the first query, and does it for each field. This is kind of hard to explain. But basically, if I search for one player by name, I'll see every other name he has used, every IP he has used and every GUID he has used. <form action="<?php echo $_SERVER['PHP_SELF']; ?>" method="post"> Search: <input type="text" name="query" id="query" /><input type="submit" name="btnSubmit" value="Submit" /> </form> <?php if (!empty($_POST['query'])) { ?> <table cellspacing="1" id="1up_people" class="tablesorter" width="300"> <thead> <tr> <th>ID</th> <th>Player Name</th> <th>Player IP</th> <th>Player GUID</th> <th>Server</th> <th>Date</th> </tr> </thead> <tbody> <?php function super_unique($array) { $result = array_map("unserialize", array_unique(array_map("serialize", $array))); foreach ($result as $key => $value) { if ( is_array($value) ) { $result[$key] = super_unique($value); } } return $result; } if (!empty($_POST['query'])) { $query = trim($_POST['query']); $count = 0; $people = array(); $link = mysql_connect('localhost', 'mysqluser', 'yea right!'); if (!$link) { die('Could not connect: ' . mysql_error()); } mysql_select_db("1up"); $sql = "SELECT id, name, INET_NTOA(ip) AS ip, guid, INET_NTOA(server) AS server, date FROM 1up_people WHERE (name LIKE \"%$query%\" OR INET_NTOA(ip) LIKE \"%$query%\" OR guid LIKE \"%$query%\")"; $result = mysql_query($sql, $link); if (!$result) { die(mysql_error()); } // Now take the initial results and parse each column into its own array while ($row = mysql_fetch_array($result, MYSQL_NUM)) { $name = htmlspecialchars($row[1]); $people[] = array( 'id' => $row[0], 'name' => $name, 'ip' => $row[2], 'guid' => $row[3], 'server' => $row[4], 'date' => $row[5] ); } // now for each name, ip, guid in results, find additonal records $people2 = array(); foreach ($people AS $person) { $ip = $person['ip']; $sql = "SELECT id, name, INET_NTOA(ip) AS ip, guid, INET_NTOA(server) AS server, date FROM 1up_people WHERE (ip = \"$ip\")"; $result = mysql_query($sql, $link); while ($row = mysql_fetch_array($result, MYSQL_NUM)) { $name = htmlspecialchars($row[1]); $people2[] = array( 'id' => $row[0], 'name' => $name, 'ip' => $row[2], 'guid' => $row[3], 'server' => $row[4], 'date' => $row[5] ); } } $people3 = array(); foreach ($people AS $person) { $guid = $person['guid']; $sql = "SELECT id, name, INET_NTOA(ip) AS ip, guid, INET_NTOA(server) AS server, date FROM 1up_people WHERE (guid = \"$guid\")"; $result = mysql_query($sql, $link); while ($row = mysql_fetch_array($result, MYSQL_NUM)) { $name = htmlspecialchars($row[1]); $people3[] = array( 'id' => $row[0], 'name' => $name, 'ip' => $row[2], 'guid' => $row[3], 'server' => $row[4], 'date' => $row[5] ); } } $people4 = array(); foreach ($people AS $person) { $name = $person['name']; $sql = "SELECT id, name, INET_NTOA(ip) AS ip, guid, INET_NTOA(server) AS server, date FROM 1up_people WHERE (name = \"$name\")"; $result = mysql_query($sql, $link); while ($row = mysql_fetch_array($result, MYSQL_NUM)) { $name = htmlspecialchars($row[1]); $people4[] = array( 'id' => $row[0], 'name' => $name, 'ip' => $row[2], 'guid' => $row[3], 'server' => $row[4], 'date' => $row[5] ); } } // Combine people and people2 into just people $people = array_merge($people, $people2); $people = array_merge($people, $people3); $people = array_merge($people, $people4); $people = super_unique($people); foreach ($people AS $person) { $date = ($person['date']) ? date("M d, Y", $person['date']) : 'Before 8/1/10'; echo "<tr>\n"; echo "<td>".$person['id']."</td>"; echo "<td>".$person['name']."</td>"; echo "<td>".$person['ip']."</td>"; echo "<td>".$person['guid']."</td>"; echo "<td>".$person['server']."</td>"; echo "<td>".$date."</td>"; echo "</tr>\n"; $count++; } // Find Total Records //$result = mysql_query("SELECT id FROM 1up_people", $link); //$total = mysql_num_rows($result); mysql_close($link); } ?> </tbody> </table> <p> <?php echo $count." Records Found for \"".$_POST['query']."\" out of $total"; ?> </p> <?php } $time_stop = microtime(true); print("Done (ran for ".round($time_stop-$time_start)." seconds)."); ?> Any help at all is appreciated! Thank you.

    Read the article

  • How would i output a message that says "values inserted to table" ?

    - by ranlo
    <?php error_reporting(0); $con=mysql_connect("localhost","root",""); if (!$con) { die('could not connect:'.mysql_error()); } mysql_select_db("final?orgdocs",$con); $org_name = $_POST["org_name"]; $org_type = $_POST["org_type"]; $org_code = $_POST["org_code"]; $description = $_POST["description"]; $stmt = "INSERT INTO organization VALUES('".$org_name."','".$org_type."','".$org_code."','".$description."')"; $result = mysql_query("SELECT * FROM organization WHERE org_name = '$org_name' "); echo '<TABLE BORDER = "1">'; $result1 = $result; while ($row = mysql_fetch_array($result1)){ echo '<TR>'.'<TD>'.'Organization Name'.'</TD>'.'<TD>'.'Organization Type'.'</TD>'.'<TD>'.'Organization Code'.'</TD>'.'<TD>'.'Description'.'</TD>'.'<TD>'.'Constitution'.'</TD>'; echo '</TR>'; echo '<TR>'.'<TD>'.$row['org_name'].'</TD>'.'<TD>'.$row['org_type'].'</TD>'; echo '<TD>'.$row['org_code'].'</TD>'.'<TD>'.$row['description'].'</TD>'.'<TD>'; echo '</TR>'; } echo '</TABLE>'; ?>

    Read the article

  • CodeIgniter URI routing (dynamic, multilingual)

    - by koteko
    I'm trying to redirect all routs to one main controller. Here is my routes.php $route['default_controller'] = "main"; $route['scaffolding_trigger'] = ""; //$route['(\w{2})/(.*)'] = '$2'; //$route['(\w{2})'] = $route['default_controller']; $route['(en|ge)/(:any)'] = $route['default_controller']."/index/$1"; $route['(:any)'] = $route['default_controller']."/index/$1"; I need language id to be passed with every link (like: http://site.com/en/hello-world) Here is my main controller: class Main extends Controller { function __construct() { parent::Controller(); } function index($page_type=false, $param=false) { die($page_type.' | '.$param.'| Aaa!'); } } I want to check if predefined file type exists (like: http://site.com/en/archive/05-06-2010 - here predefined type would be archive) then do something. If not then search in the database for slug. If not found then go to 404. The problem is that I can't get index function parameters ($page_type, $param). Thanks for help.

    Read the article

  • PHP PDO changes remote host to local hostname

    - by Wade Urry
    I'm trying to connect to a remote mysql server using PDO. However, regardless of the hostname or ip address i supply in the dsn, when the script is run it always reverts the address to the hostname of the local server where the webserver is running. Google suggests this could be something to do with SELinux and apaches ability to connect to remote databases, however i have SELinux disabled. Distro: Ubuntu 11.04 x64 Apache version: 2.2.17 PHP Version: PHP 5.3.5-1ubuntu7.11 with Suhosin-Patch (cli) Edit: Added code as requested. Though i dont believe this is an issue with my coding as it works fine on the local server, but doesnt allow remote connection. public function db_connect($driver, $dbhost, $dbname, $user, $pass) { $dsn = $driver . ':host=' . $dbhost . ';dbname=' . $dbname; try { $this->DB = new PDO($dsn, $user, $pass); } catch (PDOException $err) { print 'Database Connection Failed: ' . $err->getMessage(); die(); } } $remote_db = new DB('mysql', 'remote_server.domain.tld', 'database_name', 'user_name', 'password'); This is the error message i am receiving. Database Connection Failed: SQLSTATE[28000] [1045] Access denied for user 'user_name'@'local_server.domain.tld' (using password: YES)

    Read the article

  • My MYSQL & PHP while code is out of memory, when there is only one row

    - by Sam
    Hey all, why is this code throwing an out of memory error, when there is only 1 row in the database.. $request_db = mysql_query("SELECT * FROM requests WHERE haveplayed='0'") or die(mysql_error()); $request = mysql_fetch_array( $request_db ); echo "<table border=\"1\" align=\"center\">"; while ( $request['haveplayed'] == "0" ) { echo "<tr><td>"; echo $request['SongName']; echo "</td><td>"; echo "<tr><td>"; echo $request['Artist']; echo "</td><td>"; echo "<tr><td>"; echo $request['DedicatedTo']; echo "</td><td>"; } echo "</table>"; Thanks.

    Read the article

  • Ordering by number of rows?

    - by Rob
    Alright, so I have a table outputting data from a MySQL table in a while loop. Well one of the columns it outputs isn't stored statically in the table, instead it's the sum of how many times it appears in a different MySQL table. Sorry I'm not sure this is easy to understand. Here's my code: $query="SELECT * FROM list WHERE added='$addedby' ORDER BY time DESC"; $result=mysql_query($query); while($row=mysql_fetch_array($result, MYSQL_ASSOC)){ $loghwid = $row['hwid']; $sql="SELECT * FROM logs WHERE hwid='$loghwid' AND time < now() + interval 1 hour"; $query = mysql_query($sql) OR DIE(mysql_error()); $boots = mysql_num_rows($query); //Display the table } The above is the code displaying the table. As you can see it's grabbing data from two different MySQL tables. However I want to be able to ORDER BY $boots DESC. But as its a counting of a completely different table, I have no idea of how to go about doing that. I would appreciate any help, thank you.

    Read the article

  • Image download from mysql results

    - by rozatrra
    i need to give my users the opportunity to download all the images I display in my project. images are displayed from a mysql query like this: $query = mysql_query("SELECT tl.customername, tl.visitdate, tl.employeename, pz.webpath from table tl inner join pictures pz on pz.visitid = tl.visitid and pz.groupid = tl.groupid inner join agenti ag on ag.idh = tl.employeeid WHERE tl.visitdate >= '$from' AND tl.visitdate <= '$to' AND tl.employeename like '$r_employee' AND tl.customerowner like '$r_customer' AND tl.customername like '$r_customername' AND tl.visitdate like '$r_date' group by pz.webpath order by tl.customername") or die(mysql_error()); while( $associate = mysql_fetch_assoc($query)) { echo '<li> <figure> <img src="../core/includes/timthumb.php?src='.$associate['webpath'].'&w=200&h=200" /> <figcaption> <h3>'.$associate['customername'].'</h3> <h6>'.$associate['employeename'].'</h6> <h6>'.$associate['visitdate'].' </h6> '; echo '<a class="fancybox" rel="gallery" href="'.$associate['webpath'].'" title=" '.$associate['visitdate'].' / '.$associate['customername'].'">Big picture</i></a>'; echo '</figcaption> </figure> </li>'; $zip->addFromString(pathinfo ( urldecode($associate['webpath']), PATHINFO_BASENAME), urldecode($associate['webpath'])); } How can i add a download button which will save all the images as zip on user computer?

    Read the article

  • php memory how much is too much

    - by Rob
    I'm currently re-writing my site using my own framework (it's very simple and does exactly what I need, i've no need for something like Zend or Cake PHP). I've done alot of work in making sure everything is cached properly, caching pages in files so avoid sql queries and generally limiting the number of sql queries. Overall it looks like it's very speedy. The average time taken for the front page (taken over 100 times) is 0.046152 microseconds. But one thing i'm not sure about is whether i've done enough to reduce php memory usage. The only time i've ever encountered problems with it is when uploading large files. Using memory_get_peak_usage(TRUE), which I THINK returns the highest amount of memory used whilst the script has been running, the average (taken over 100 times) is 1572864 bytes. Is that good? I realise you don't know what it is i'm doing (it's rather simple, get the 10 latest articles, the comment count for each, get the user controls, popular tags in the sidebar etc). But would you be at all worried with a script using that sort of memory getting hit 50,000 times a day? Or once every second at peak times? I realise that this is a very open ended question. Hopefully you can understand that it's a bit of a stab in the dark and i'm really just looking for some re-assurance that it's not going to die horribly come re-launch day.

    Read the article

  • PHP login, getting wrong count value from query / fetch array

    - by Chris
    Hello, *EDIT*Thanks to the comments below it has been figured out that the problem lies with the md5, without everything works as it should. But how do i implent the md5 then? I am having some troubles with the following code below to login. The database and register system are already working. The problem lies that it does not find any result at all in the query. IF the count is 0 it should redirect the user to a secured page. But this only works if i write count = 0, but this should be 0 , only if the user name and password is found he should be directed to the secure (startpage) of the site after login. For example root (username) root (password) already exists but i cannot seem to properly login with it. <?php session_start(); if (!empty($_POST["send"])) { $username = ($_POST["username"]); $password = (md5($_POST["password"])); $count = 0; $con = mysql_connect("localhost" , "root", ""); mysql_select_db("testdb", $con); $result = mysql_query("SELECT name, password FROM user WHERE name = '".$username."' AND password = '".$password."' ") or die("Error select statement"); $count = mysql_num_rows($result); if($count > 0) // always goes the to else, only works with >=0 but then the data is not found in the database, hence incorrect { $row = mysql_fetch_array($result); $_SESSION["username"] = $row["name"]; header("Location: StartPage.php"); } else { echo "Wrong login data, please try again"; } mysql_close($con); } ?>

    Read the article

  • problem during data fetch

    - by nectar
    here is my code $sql="SELECT * FROM $tbl_name WHERE ownerId='$UserId'"; $result=mysql_query($sql,$link)or die(mysql_error()); $row = mysql_fetch_array($result, MYSQL_ASSOC); <?php while($row = mysql_fetch_array($result, MYSQL_ASSOC)) { echo "<tr>"; echo "<td>".$row['pinId']."</td>"; echo "<td>".$row['usedby']."</td>"; echo "<td>".$row['status']."</td>"; echo "</tr>"; } ?> it is ignoring the first record means if 4 rows are in $row its ignoring the 1st one rest three are coming on page. ownerId is not primary key.

    Read the article

  • After mysql_query, no result output

    - by Jerry
    I have a simple mysql_query() update command to update mysql. When a user submits my form, it will jump to an update page to update the data. The problem is that there's supposed to be some data shown after the update, but it comes out blank. My form <form id="form1" method="POST" action="scheduleUpdate.php" > <select name=std1> <option>AA</option> <option>BB</option> <option>CC</option> </select> <select name=std2> <option>DD</option> <option>EE</option> <option>FF</option> </select> .......//more drop down menu but the name is std3..std4..etc... ....... </form> scheduleUpdate.php //$i is the value posted from my main app to tell me how many std we have for($k=0;$k<$i;$k++){ $std=$_POST['std'.$k]; //if i remove the updateQuery, the html will output.I know the query is the problem but i //couldn't fix it.. $updateQuery=mysql_query("UPDATE board SET student='$std' WHERE badStudent='$std' or goodStudent='$std'",$connection); //no output below this line at all if($updateQuery){ DIE('mysql Error:'+mysql_error()); } } // I have bunch of HTML here....but no output at all!!!! MySQL will be updated after I hit submit, but it doesn't shown any HTML.

    Read the article

  • How can I add one line into all php files' beginning?

    - by Tom
    So, ok. I have many php files and one index.php file. All files can't work without index.php file, because I include them in index.php. For example. if somebody click Contact us the URL will become smth like index.php?id=contact and I use $_GET['id'] to include contacts.php file. But, if somebody find the file's path, for example /system/files/contacts.php I don't want that that file would be executed. So, I figured out that I can add before including any files in index.php line like this $check_hacker = 1 and use if in every files beginning like this if($check_hacker <> 1) die();. So, how can I do it without opening all files and adding this line to each of them? Is it possible? Because I actually have many .php files. And maybe there is other way to do disable watching separate file? Any ideas? Thank you.

    Read the article

< Previous Page | 476 477 478 479 480 481 482 483 484 485 486 487  | Next Page >