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  • Link XSL Style Sheet to XForms generated XML document

    - by iHeartGreek
    Hi! Through XForms, I generate an XML document. I need this XML document to be transformed by a specific XSL. How do I link the XSL to the XML through XForms? Example of link: <?xml-stylesheet type="text/xsl" href="test.xsl"?> (The XML doc gets regenerated every time the XForms submits to it.. so I cannot hardcode the link in the XML doc, in needs to be done through the XForms) Thanks!

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  • How do I get a right outer join in L2E?

    - by Dan
    I have two tables that I set up through the VS Entity Data Model Diagram tool. I'm trying to do a right outer join and it doesn't return results from the 2nd table. I have set up a 0..1 to MANY relationship from the diagram tool. When I run a Linq-To-Entities query, it still defaults to an INNER JOIN. From my understanding of entities, if I set up the relationship using VS, when I join the tables, it should automagically figure out the join syntax based on the relationship I supply. It doesn't seem to be doing that. I am using EF v1 (not Linq-to-Sql). Query I'm running: from s in SomeTable join t in SomeOtherTable on s.ID equals t.ID select new { s.MyFieldName, t.MyOtherFieldName }

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  • Parsing XML data with Namespaces in PHP

    - by osbmedia
    I'm trying to work with this XML feed that uses namespaces and i'm not able to get past the colon in the tags. Here's how the XML feed looks like: <r25:events pubdate="2010-05-19T13:58:08-04:00"> <r25:event xl:href="event.xml?event_id=328" id="BRJDMzI4" crc="00000022" status="est"> <r25:event_id>328</r25:event_id> <r25:event_name>Testing 09/2005-08/2006</r25:event_name> <r25:alien_uid/> <r25:event_priority>0</r25:event_priority> <r25:event_type_id xl:href="evtype.xml?type_id=105">105</r25:event_type_id> <r25:event_type_name>CABINET</r25:event_type_name> <r25:node_type>C</r25:node_type> <r25:node_type_name>cabinet</r25:node_type_name> <r25:state>1</r25:state> <r25:state_name>Tentative</r25:state_name> <r25:event_locator>2005-AAAAMQ</r25:event_locator> <r25:event_title/> <r25:favorite>F</r25:favorite> <r25:organization_id/> <r25:organization_name/> <r25:parent_id/> <r25:cabinet_id xl:href="event.xml?event_id=328">328</r25:cabinet_id> <r25:cabinet_name>cabinet 09/2005-08/2006</r25:cabinet_name> <r25:start_date>2005-09-01</r25:start_date> <r25:end_date>2006-08-31</r25:end_date> <r25:registration_url/> <r25:last_mod_dt>2008-02-27T14:22:43-05:00</r25:last_mod_dt> <r25:last_mod_user>abc00296004</r25:last_mod_user> </r25:event> </r25:events> And here is what I'm using for code - I'll trying to throw these into a bunch of arrays where I can format the output however I want: <?php $ch = curl_init(); curl_setopt($ch, CURLOPT_URL, "http://somedomain.com/blah.xml"); curl_setopt ($ch, CURLOPT_HTTPHEADER, Array("Content-Type: text/xml")); curl_setopt($ch, CURLOPT_USERPWD, "username:password"); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); $output = curl_exec($ch); curl_close($ch); $xml = new SimpleXmlElement($output); foreach ($xml->events->event as $entry){ $dc = $entry->children('http://www.collegenet.com/r25'); echo $entry->event_name . "<br />"; echo $entry->event_id . "<br /><br />"; }

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  • 'Out of Memory exception' in sql server 2005 xml column

    - by Raghuraman
    Hi All, I am devloping a windows forms application and am using sql server 2005 database as my backend. I am having an xml column in my database. I am using ultrawingrid control in my application.I obtain the xml of the dataset which is bound to my ultrawingrid control and pass that as a parameter value to the stored procedure where am inserting this value into the xml column which I specified. The columns in my grid are dynamic and hence there can be any no of columns in my grid. I got 'out of memory' exception in the dataset.GetXml() statement since there were more no of columns I believe.So, what I did is that I used dataset.WriteXml() method and stored all the xml contents into an xml file, loaded the xml file into the XmlDocument object and then passed the xmlnodereader as the value to the stored procedure parameter.Now, while executing the stored procedure am getting the same 'out of memory' exception. How could I resolve this issue?

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  • remove non-UTF-8 characters from xml with declared encoding=utf-8 - Java

    - by St Nietzke
    I have to handle this scenario in Java: I'm getting a request in XML form from a client with declared encoding=utf-8. Unfortunately it may contain not utf-8 characters and there is a requirement to remove these characters from the xml on my side (legacy). Let's consider an example where this invalid XML contains £ (pound). 1) I get xml as java String with £ in it (I don't have access to interface right now, but I probably get xml as a java String). Can I use replaceAll(£, "") to get rid of this character? Any potential issues? 2) I get xml as an array of bytes - how to handle this operation safely in that case?

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  • More XML Problems - Undeclared Entity 'nbsp'

    - by Gogster
    I'm getting the error: Line 49: xml = r.ReadToEnd(); Line 50: Line 51: System.Xml.Linq.XDocument xmlDoc = System.Xml.Linq.XDocument.Parse(xml); Line 52: Line 53: var query = from p in xmlDoc.Descendants("member") On my XML. When I run the code to generate the XML in an empty page, it runs without error, if I call the code within my webpage it throws this error. The only 'nbsp' on the page is a doctype declaration at the top of the XSLT: <!DOCTYPE xsl:stylesheet [ <!ENTITY nbsp "&#x00A0;"> ]> I'm at a loss as to where this error is coming from and I am looking for suggestions please! Thanks.

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  • Flex 4: Defining a XML data model in an Actionscript Class

    - by Steve
    I'm really having a hard time accessing a data model I've defined in an Actionscript class in my Flex app. The following is my AS Class (Model.as): package { import mx.rpc.http.HTTPService; public class Model { private static var _instance:Model; public static function getInstance():Model { if (!_instance) _instance = new Model(); return _instance; } [Bindable] public var xml:mx.rpc.http.HTTPService = new mx.rpc.http.HTTPService(); Model.getInstance().xml.url = "http://127.0.01/RAF/DATAPOINTS.xml"; Model.getInstance().xml.resultFormat = "e4x"; } } I'm then trying to access this in my main application with the following code: Model.getInstance().xml.send(); var sectorList:XMLList = Model.getInstance().xml.lastResult; And it just keeps throwing errors. The errors are generic so I can't determine the source in debugging. Hope this is enough info...

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  • Word 2010 for writing invoices, starting with XML

    - by TomTom
    Hello, we are doing quite some invoice generation, and so far it is based on some pretty awful word automation that is now in for a review with Word 2010. I would love to move to a XML based format for storing / presenting invoices, only going to a word document in the last stage. This means I can use easily othermeans to present an invoice internally from the XML. We use Word as "last stage" because Word is a lot better than anything else ever discovered for formatting - our invoices have quite some text sometimes, in the invoice item table, and word is smartest with handling page breaks in the "correct" way. Now, here my question: is there any proper way by now to do this with XML easily? I remember Word having (had) in 2007 some XML field mapping mechanism, but it did not handle tables in the XML. Was anything changed? What would be the proposed approach for generating an .docx document (starting with a .dotx templace) for an invoice, if the relevant data is available in XML form?

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  • how do I find the number of xml children in AS3

    - by vasion
    so live docs says this for calling .lenght() on an XML object For XML objects, this method always returns the integer 1. The length() method of the XMLList class returns a value of 1 for an XMLList object that contains only one value. i called it on an xml that looked like this: <xml> <picture>1</picture> <picture>2</picture> </xml> and it reallt returned 1. how do i get the number of children in my xml?

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  • Remote XML retrieval

    - by rrrfusco
    I'm retrieving a remote XML file with wget -O remotefile localfile with a cron tab. Every so often the local file becomes malformed probably because of double whitespace (according to firefox) between the CDATA tags. Sometimes the parser gives an error for ' > ' missing, but upon checking the xml file the ' > ' exists... The remote xml file never gives malformed errors when called in the url. EDIT It seems CDATA is not parsed by the xml parser. (w3schools) Is there a way to set wget to retain wellformed XML? If not wget, What is a good way to continously retrieve a remote XML file and keep it well formed?

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  • Dynamic query to immediate execute?

    - by Curtis White
    I am using the MSDN Dynamic linq to sql package. It allows using strings for queries. But, the returned type is an IQueryable and not an IQueryable<T>. I do not have the ToList() method. How can I this immediate execute without manually enumerating over the IQueryable? My goal is to databind to the Selecting event on a linqtosql datasource and that throws a datacontext disposed exception. I can set the query as the Datasource on a gridview though. Any help greatly appreciated! Thanks. The dynamic linq to sql is the one from the samples that comes with visual studio.

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  • parsing a xml to get some values

    - by Joan Silverstone
    Hello, i have this xml: http://www.managerleague.com/export_data.pl?data=transfers&output=xml&hide_header=0 These are player sales from a browser game. I want to save some fields from these sales. I am fetching that xml with curl and storing on my server. Then do the following: $xml_str = file_get_contents('salespage.xml'); $xml = new SimpleXMLElement($xml_str); $items = $xml->xpath('*/transfer'); print_r($items); foreach($items as $item) { echo $item['buyerTeamname'], ': ', $item['sellerTeamname'], "\n"; } The array is empty and i cant seem to get anything from it. What am i doing wrong?

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  • Maven Grails web.xml

    - by dunn less
    Might be a stupid question, but in my current maven project i do not have a web.xml in my /web-app/WEB-INF folder. There is no web-xml in my project and never has been, im trying to add it but my application is non-responsive to anything written in the web.xml. What am i missing?, iv tried specifying the path to it through the config.groovy like: grails.project.web.xml="web-app/WEB-INF/web.xml" Am i missing something? Do i need to specify the web.xml in some other config file in order to make my project utilize it ?

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  • php, extract data from a non-standard xml document

    - by Michael
    I have some kind xml content I need to extract the information and store it into database <xml file="136000000-136100000"> <Id>136000000</Id> <Name>Sem Serxy</Na me> <Email>[email protected]</Email> <DateRegistration>10/13/2010 1:49:30 AM</DateRegistration> </xml> <xml file="136000000-136100000"> <Id>136000001</Id> <Name>God Deckor</Name> <Email>[email protected]</Email> If I try simple xml load is not working as the document doesn't seem to be valid xml. I can use regex to extract the info with preg_match_all but I feel this is not the right way as the data is already well structured. Any other method ?

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  • Write an xml file from the specified node?

    - by Googler
    Hi all, This is my xml file Input: <world> <patent> <xml>a</xml> <java>333</java> <jaxb>111</jaxb> </patent> </world> I need the read the above xml file and reproduce the following the output Output: <patent> <xml>a</xml> <java>333</java> <jaxb>111</jaxb> </patent> I dont need the world element. How to achieve this using Xpath. Can anyone help me on this?

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  • Is the XML processing instructions node mandatory ?

    - by ereOn
    I had a discussion with a colleague of mine about the XML processing instructions node (I'm talking about this = <?xml version="1.0" encoding="UTF-8"?>). I believe that for something to be called "valid XML", it requires a processing instructions node. My colleague states that the processing instruction node is optionnal, since the default encoding is UTF-8 and the version is always 1.0. This make sense, but what does the standard says ? In short, given the following file: <books> <book id="1"><title>Title</title></book> </book> Can we say that: It is valid XML ? It is a valid XML node ? It is a valid XML document ? Thank you very much.

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  • XML/XSL nub: Is it possible to create an COMPOSITE XML/XSLT document?

    - by jmweekes
    I have just recently (like 2 days) started using XSLT documents with XML. I understand the basics and am able to generate a formatted document using an .XML document that references a separate .XSLT document. My question, as in the subject, is "Is it possible to create a SINGLE, composite document that contains both the XML data and XSLT processing/formatting/styling and displays as formatted HTML?" I am writing a desktop application in which I need to generate a formatted document on the fly from XML stored in the database. I want to do this without creating or referencing any actual physical files. I will generate a text string containing the XML/XSLT document and feed this to a WebBrowser component for formatted display. Hopefully what I want to do doesn't totally go against the whole XML/XSLT methodology. Any information, direction or suggestions will be greatly appreciated.

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  • Linq to LLBLGen query problem

    - by Jeroen Breuer
    Hello, I've got a Stored Procedure and i'm trying to convert it to a Linq to LLBLGen query. The query in Linq to LLBGen works, but when I trace the query which is send to sql server it is far from perfect. This is the Stored Procedure: ALTER PROCEDURE [dbo].[spDIGI_GetAllUmbracoProducts] -- Add the parameters for the stored procedure. @searchText nvarchar(255), @startRowIndex int, @maximumRows int, @sortExpression nvarchar(255) AS BEGIN SET @startRowIndex = @startRowIndex + 1 SET @searchText = '%' + @searchText + '%' -- SET NOCOUNT ON added to prevent extra result sets from -- interfering with SELECT statements. SET NOCOUNT ON; -- This is the query which will fetch all the UmbracoProducts. -- This query also supports paging and sorting. WITH UmbracoOverview As ( SELECT ROW_NUMBER() OVER( ORDER BY CASE WHEN @sortExpression = 'productName' THEN umbracoProduct.productName WHEN @sortExpression = 'productCode' THEN umbracoProduct.productCode END ASC, CASE WHEN @sortExpression = 'productName DESC' THEN umbracoProduct.productName WHEN @sortExpression = 'productCode DESC' THEN umbracoProduct.productCode END DESC ) AS row_num, umbracoProduct.umbracoProductId, umbracoProduct.productName, umbracoProduct.productCode FROM umbracoProduct INNER JOIN product ON umbracoProduct.umbracoProductId = product.umbracoProductId WHERE (umbracoProduct.productName LIKE @searchText OR umbracoProduct.productCode LIKE @searchText OR product.code LIKE @searchText OR product.description LIKE @searchText OR product.descriptionLong LIKE @searchText OR product.unitCode LIKE @searchText) ) SELECT UmbracoOverview.UmbracoProductId, UmbracoOverview.productName, UmbracoOverview.productCode FROM UmbracoOverview WHERE (row_num >= @startRowIndex AND row_num < (@startRowIndex + @maximumRows)) -- This query will count all the UmbracoProducts. -- This query is used for paging inside ASP.NET. SELECT COUNT (umbracoProduct.umbracoProductId) AS CountNumber FROM umbracoProduct INNER JOIN product ON umbracoProduct.umbracoProductId = product.umbracoProductId WHERE (umbracoProduct.productName LIKE @searchText OR umbracoProduct.productCode LIKE @searchText OR product.code LIKE @searchText OR product.description LIKE @searchText OR product.descriptionLong LIKE @searchText OR product.unitCode LIKE @searchText) END This is my Linq to LLBLGen query: using System.Linq.Dynamic; var q = ( from up in MetaData.UmbracoProduct join p in MetaData.Product on up.UmbracoProductId equals p.UmbracoProductId where up.ProductCode.Contains(searchText) || up.ProductName.Contains(searchText) || p.Code.Contains(searchText) || p.Description.Contains(searchText) || p.DescriptionLong.Contains(searchText) || p.UnitCode.Contains(searchText) select new UmbracoProductOverview { UmbracoProductId = up.UmbracoProductId, ProductName = up.ProductName, ProductCode = up.ProductCode } ).OrderBy(sortExpression); //Save the count in HttpContext.Current.Items. This value will only be saved during 1 single HTTP request. HttpContext.Current.Items["AllProductsCount"] = q.Count(); //Returns the results paged. return q.Skip(startRowIndex).Take(maximumRows).ToList<UmbracoProductOverview>(); This is my Initial expression to process: value(SD.LLBLGen.Pro.LinqSupportClasses.DataSource`1[Eurofysica.DB.EntityClasses.UmbracoProductEntity]).Join(value(SD.LLBLGen.Pro.LinqSupportClasses.DataSource`1[Eurofysica.DB.EntityClasses.ProductEntity]), up => up.UmbracoProductId, p => p.UmbracoProductId, (up, p) => new <>f__AnonymousType0`2(up = up, p = p)).Where(<>h__TransparentIdentifier0 => (((((<>h__TransparentIdentifier0.up.ProductCode.Contains(value(Eurofysica.BusinessLogic.BLL.Controllers.UmbracoProductController+<>c__DisplayClass1).searchText) || <>h__TransparentIdentifier0.up.ProductName.Contains(value(Eurofysica.BusinessLogic.BLL.Controllers.UmbracoProductController+<>c__DisplayClass1).searchText)) || <>h__TransparentIdentifier0.p.Code.Contains(value(Eurofysica.BusinessLogic.BLL.Controllers.UmbracoProductController+<>c__DisplayClass1).searchText)) || <>h__TransparentIdentifier0.p.Description.Contains(value(Eurofysica.BusinessLogic.BLL.Controllers.UmbracoProductController+<>c__DisplayClass1).searchText)) || <>h__TransparentIdentifier0.p.DescriptionLong.Contains(value(Eurofysica.BusinessLogic.BLL.Controllers.UmbracoProductController+<>c__DisplayClass1).searchText)) || <>h__TransparentIdentifier0.p.UnitCode.Contains(value(Eurofysica.BusinessLogic.BLL.Controllers.UmbracoProductController+<>c__DisplayClass1).searchText))).Select(<>h__TransparentIdentifier0 => new UmbracoProductOverview() {UmbracoProductId = <>h__TransparentIdentifier0.up.UmbracoProductId, ProductName = <>h__TransparentIdentifier0.up.ProductName, ProductCode = <>h__TransparentIdentifier0.up.ProductCode}).OrderBy( => .ProductName).Count() Now this is how the queries look like that are send to sql server: Select query: Query: SELECT [LPA_L2].[umbracoProductId] AS [UmbracoProductId], [LPA_L2].[productName] AS [ProductName], [LPA_L2].[productCode] AS [ProductCode] FROM ( [eurofysica].[dbo].[umbracoProduct] [LPA_L2] INNER JOIN [eurofysica].[dbo].[product] [LPA_L3] ON [LPA_L2].[umbracoProductId] = [LPA_L3].[umbracoProductId]) WHERE ( ( ( ( ( ( ( ( [LPA_L2].[productCode] LIKE @ProductCode1) OR ( [LPA_L2].[productName] LIKE @ProductName2)) OR ( [LPA_L3].[code] LIKE @Code3)) OR ( [LPA_L3].[description] LIKE @Description4)) OR ( [LPA_L3].[descriptionLong] LIKE @DescriptionLong5)) OR ( [LPA_L3].[unitCode] LIKE @UnitCode6)))) Parameter: @ProductCode1 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Parameter: @ProductName2 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Parameter: @Code3 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Parameter: @Description4 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Parameter: @DescriptionLong5 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Parameter: @UnitCode6 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Count query: Query: SELECT TOP 1 COUNT(*) AS [LPAV_] FROM (SELECT [LPA_L2].[umbracoProductId] AS [UmbracoProductId], [LPA_L2].[productName] AS [ProductName], [LPA_L2].[productCode] AS [ProductCode] FROM ( [eurofysica].[dbo].[umbracoProduct] [LPA_L2] INNER JOIN [eurofysica].[dbo].[product] [LPA_L3] ON [LPA_L2].[umbracoProductId] = [LPA_L3].[umbracoProductId]) WHERE ( ( ( ( ( ( ( ( [LPA_L2].[productCode] LIKE @ProductCode1) OR ( [LPA_L2].[productName] LIKE @ProductName2)) OR ( [LPA_L3].[code] LIKE @Code3)) OR ( [LPA_L3].[description] LIKE @Description4)) OR ( [LPA_L3].[descriptionLong] LIKE @DescriptionLong5)) OR ( [LPA_L3].[unitCode] LIKE @UnitCode6))))) [LPA_L1] Parameter: @ProductCode1 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Parameter: @ProductName2 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Parameter: @Code3 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Parameter: @Description4 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Parameter: @DescriptionLong5 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". Parameter: @UnitCode6 : String. Length: 2. Precision: 0. Scale: 0. Direction: Input. Value: "%%". As you can see no sorting or paging is done (like in my Stored Procedure). This is probably done inside the code after all the results are fetched. This costs a lot of performance! Does anybody know how I can convert my Stored Procedure to Linq to LLBLGen the proper way?

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  • LinqToXML why does my object go out of scope? Also should I be doing a group by?

    - by Kettenbach
    Hello All, I have an IEnumerable<someClass>. I need to transform it into XML. There is a property called 'ZoneId'. I need to write some XML based on this property, then I need some decendent elements that provide data relevant to the ZoneId. I know I need some type of grouping. Here's what I have attempted thus far without much success. **inventory is an IEnumerable<someClass>. So I query inventory for unique zones. This works ok. var zones = inventory.Select(c => new { ZoneID = c.ZoneId , ZoneName = c.ZoneName , Direction = c.Direction }).Distinct(); No I want to create xml based on zones and place. ***place is a property of 'someClass'. var xml = new XElement("MSG_StationInventoryList" , new XElement("StationInventory" , zones.Select(station => new XElement("station-id", station.ZoneID) , new XElement("station-name", station.ZoneName)))); This does not compile as "station" is out of scope when I try to add the "station-name" element. However is I remove the paren after 'ZoneId', station is in scope and I retreive the station-name. Only problem is the element is then a decendant of 'station-id'. This is not the desired output. They should be siblings. What am I doing wrong? Lastly after the "station-name" element, I will need another complex type which is a collection. Call it "places'. It will have child elements called "place". its data will come from the IEnumerable and I will only want "places" that have the "ZoneId" for the current zone. Can anyone point me in the right direction? Is it a mistake select distinct zones from the original IEnumerable? This object has all the data I need within it. I just need to make it heirarchical. Thanks for any pointers all. Cheers, Chris in San Diego

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  • nested linq-to-sql queries

    - by ile
    var result = ( from contact in db.Contacts join user in db.Users on contact.CreatedByUserID equals user.UserID orderby contact.ContactID descending select new ContactListView { ContactID = contact.ContactID, FirstName = contact.FirstName, LastName = contact.LastName, Company = (from field in contact.XmlFields.Descendants("Company") select field.Value).SingleOrDefault().ToString() }).Take(10); Here I described how my database tables look like. So, contacts table has one field that is xml type. In that field is stored Company filename and I need to read it. I tried it using this way: Company = (from field in contact.XmlFields.Descendants("Company") select field.Value).SingleOrDefault().ToString() }).Take(10); but I get following error: Member access 'System.String Value' of 'System.Xml.Linq.XElement' not legal on type 'System.Collections.Generic.IEnumerable`1[System.Xml.Linq.XElement]. Any solution for this? Thanks in advance, Ile

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  • Given an XML which contains a representation of a graph, how to apply it DFS algorithm? [on hold]

    - by winston smith
    Given the followin XML which is a directed graph: <?xml version="1.0" encoding="iso-8859-1" ?> <!DOCTYPE graph PUBLIC "-//FC//DTD red//EN" "../dtd/graph.dtd"> <graph direct="1"> <vertex label="V0"/> <vertex label="V1"/> <vertex label="V2"/> <vertex label="V3"/> <vertex label="V4"/> <vertex label="V5"/> <edge source="V0" target="V1" weight="1"/> <edge source="V0" target="V4" weight="1"/> <edge source="V5" target="V2" weight="1"/> <edge source="V5" target="V4" weight="1"/> <edge source="V1" target="V2" weight="1"/> <edge source="V1" target="V3" weight="1"/> <edge source="V1" target="V4" weight="1"/> <edge source="V2" target="V3" weight="1"/> </graph> With this classes i parsed the graph and give it an adjacency list representation: import java.io.IOException; import java.util.HashSet; import java.util.LinkedList; import java.util.Collection; import java.util.Iterator; import java.util.logging.Level; import java.util.logging.Logger; import practica3.util.Disc; public class ParsingXML { public static void main(String[] args) { try { // TODO code application logic here Collection<Vertex> sources = new HashSet<Vertex>(); LinkedList<String> lines = Disc.readFile("xml/directed.xml"); for (String lin : lines) { int i = Disc.find(lin, "source=\""); String data = ""; if (i > 0 && i < lin.length()) { while (lin.charAt(i + 1) != '"') { data += lin.charAt(i + 1); i++; } Vertex v = new Vertex(); v.setName(data); v.setAdy(new HashSet<Vertex>()); sources.add(v); } } Iterator it = sources.iterator(); while (it.hasNext()) { Vertex ver = (Vertex) it.next(); Collection<Vertex> adyacencias = ver.getAdy(); LinkedList<String> ls = Disc.readFile("xml/graphs.xml"); for (String lin : ls) { int i = Disc.find(lin, "target=\""); String data = ""; if (lin.contains("source=\""+ver.getName())) { Vertex v = new Vertex(); if (i > 0 && i < lin.length()) { while (lin.charAt(i + 1) != '"') { data += lin.charAt(i + 1); i++; } v.setName(data); } i = Disc.find(lin, "weight=\""); data = ""; if (i > 0 && i < lin.length()) { while (lin.charAt(i + 1) != '"') { data += lin.charAt(i + 1); i++; } v.setWeight(Integer.parseInt(data)); } if (v.getName() != null) { adyacencias.add(v); } } } } for (Vertex vert : sources) { System.out.println(vert); System.out.println("adyacencias: " + vert.getAdy()); } } catch (IOException ex) { Logger.getLogger(ParsingXML.class.getName()).log(Level.SEVERE, null, ex); } } } This is another class: import java.util.Collection; import java.util.Objects; public class Vertex { private String name; private int weight; private Collection ady; public Collection getAdy() { return ady; } public void setAdy(Collection adyacencias) { this.ady = adyacencias; } public String getName() { return name; } public void setName(String nombre) { this.name = nombre; } public int getWeight() { return weight; } public void setWeight(int weight) { this.weight = weight; } @Override public int hashCode() { int hash = 7; hash = 43 * hash + Objects.hashCode(this.name); hash = 43 * hash + this.weight; return hash; } @Override public boolean equals(Object obj) { if (obj == null) { return false; } if (getClass() != obj.getClass()) { return false; } final Vertex other = (Vertex) obj; if (!Objects.equals(this.name, other.name)) { return false; } if (this.weight != other.weight) { return false; } return true; } @Override public String toString() { return "Vertice{" + "name=" + name + ", weight=" + weight + '}'; } } And finally: /** * * @author user */ /* -*-jde-*- */ /* <Disc.java> Contains the main argument*/ import java.io.*; import java.util.LinkedList; /** * Lectura y escritura de archivos en listas de cadenas * Ideal para el uso de las clases para gráficas. * * @author Peralta Santa Anna Victor Miguel * @since Julio 2011 */ public class Disc { /** * Metodo para lectura de un archivo * * @param fileName archivo que se va a leer * @return El archivo en representacion de lista de cadenas */ public static LinkedList<String> readFile(String fileName) throws IOException { BufferedReader file = new BufferedReader(new FileReader(fileName)); LinkedList<String> textlist = new LinkedList<String>(); while (file.ready()) { textlist.add(file.readLine().trim()); } file.close(); /* for(String linea:textlist){ if(linea.contains("source")){ //String generado = linea.replaceAll("<\\w+\\s+\"", ""); //System.out.println(generado); } }*/ return textlist; }//readFile public static int find(String linea,String palabra){ int i,j; boolean found = false; for(i=0,j=0;i<linea.length();i++){ if(linea.charAt(i)==palabra.charAt(j)){ j++; if(j==palabra.length()){ found = true; return i; } }else{ continue; } } if(!found){ i= -1; } return i; } /** * Metodo para la escritura de un archivo * * @param fileName archivo que se va a escribir * @param tofile la lista de cadenas que quedaran en el archivo * @param append el bit que dira si se anexa el contenido o se empieza de cero */ public static void writeFile(String fileName, LinkedList<String> tofile, boolean append) throws IOException { FileWriter file = new FileWriter(fileName, append); for (int i = 0; i < tofile.size(); i++) { file.write(tofile.get(i) + "\n"); } file.close(); }//writeFile /** * Metodo para escritura de un archivo * @param msg archivo que se va a escribir * @param tofile la cadena que quedaran en el archivo * @param append el bit que dira si se anexa el contenido o se empieza de cero */ public static void writeFile(String msg, String tofile, boolean append) throws IOException { FileWriter file = new FileWriter(msg, append); file.write(tofile); file.close(); }//writeFile }// I'm stuck on what can be the best way to given an adjacency list representation of the graph how to apply it Depth-first search algorithm. Any idea of how to aproach to complete the task?

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  • PHP: Writing non-english characters to XML - encoding problem

    - by Dean
    Hello, I wrote a small PHP script to edit the site news XML file. I used DOM to manipulate the XML (Loading, writing, editing). It works fine when writing English characters, but when non-English characters are written, PHP throws an error when trying to load the file. If I manually type non-English characters into the file - it's loaded perfectly fine, but if PHP writes the non-English characters the encoding goes wrong, although I specified the utf-8 encoding. Any help is appreciated. Errors: Warning: DOMDocument::load() [domdocument.load]: Entity 'times' not defined in filepath Warning: DOMDocument::load() [domdocument.load]: Input is not proper UTF-8, indicate encoding ! Bytes: 0x91 0x26 0x74 0x69 in filepath Here are the functions responsible for loading and saving the file (self-explanatory): function get_tags_from_xml(){ // Load news entries from XML file for display $errors = Array(); if(!$xml_file = load_news_file()){ // Load file // String indicates error presence $errors = "file not found"; return $errors; } $taglist = $xml_file->getElementsByTagName("text"); return $taglist; } function set_news_lang(){ // Sets the news language global $news_lang; if($_POST["news-lang"]){ $news_lang = htmlentities($_POST["news-lang"]); } elseif($_GET["news-lang"]){ $news_lang = htmlentities($_GET["news-lang"]); } else{ $news_lang = "he"; } } function load_news_file(){ // Load XML news file for proccessing, depending on language global $news_lang; $doc = new DOMDocument('1.0','utf-8'); // Create new XML document $doc->load("news_{$news_lang}.xml"); // Load news file by language $doc->formatOutput = true; // Nicely format the file return $doc; } function save_news_file($doc){ // Save XML news file, depending on language global $news_lang; $doc->saveXML($doc->documentElement); $doc->save("news_{$news_lang}.xml"); } Here is the code for writing to XML (add news): <?php ob_start()?> <?php include("include/xml_functions.php")?> <?php include("../include/functions.php")?> <?php get_lang();?> <?php //TODO: ADD USER AUTHENTICATION! if(isset($_POST["news"]) && isset($_POST["news-lang"])){ set_news_lang(); $news = htmlentities($_POST["news"]); $xml_doc = load_news_file(); $news_list = $xml_doc->getElementsByTagName("text"); // Get all existing news from file $doc_root_element = $xml_doc->getElementsByTagName("news")->item(0); // Get the root element of the new XML document $new_news_entry = $xml_doc->createElement("text",$news); // Create the submited news entry $doc_root_element->appendChild($new_news_entry); // Append submited news entry $xml_doc->appendChild($doc_root_element); save_news_file($xml_doc); header("Location: /cpanel/index.php?lang={$lang}&news-lang={$news_lang}"); } else{ header("Location: /cpanel/index.php?lang={$lang}&news-lang={$news_lang}"); } ?> <?php ob_end_flush()?>

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  • jqgrid with asp.net webmethod and json working with sorting, paging, searching and LINQ

    - by aimlessWonderer
    THIS WORKS! Most topics covering jqgrid and asp.net seem to relate to just receiving JSON, or working in the MVC framework, or utilizing other handlers or web services... but not many dealt with actually passing parameters back to an actual webmethod in the codebehind. Furthermore, scarce are the examples that contain successful implementation the AJAX paging, sorting, or searching along with LINQ to SQL for asp.net jqGrid. Below is a working example that may help others who need help to pass parameters to jqGrid in order to have correct paging, sorting, filtering.. it uses pieces from here and there... ================================================== First, THE JAVASCRIPT <script type="text/javascript"> $(document).ready(function() { var grid = $("#list"); $("#list").jqGrid({ // setup custom parameter names to pass to server prmNames: { search: "isSearch", nd: null, rows: "numRows", page: "page", sort: "sortField", order: "sortOrder" }, // add by default to avoid webmethod parameter conflicts postData: { searchString: '', searchField: '', searchOper: '' }, // setup ajax call to webmethod datatype: function(postdata) { mtype: "GET", $.ajax({ url: 'PageName.aspx/getGridData', type: "POST", contentType: "application/json; charset=utf-8", data: JSON.stringify(postdata), dataType: "json", success: function(data, st) { if (st == "success") { var grid = jQuery("#list")[0]; grid.addJSONData(JSON.parse(data.d)); } }, error: function() { alert("Error with AJAX callback"); } }); }, // this is what jqGrid is looking for in json callback jsonReader: { root: "rows", page: "page", total: "totalpages", records: "totalrecords", cell: "cell", id: "id", //index of the column with the PK in it userdata: "userdata", repeatitems: true }, colNames: ['Id', 'First Name', 'Last Name'], colModel: [ { name: 'id', index: 'id', width: 55, search: false }, { name: 'fname', index: 'fname', width: 200, searchoptions: { sopt: ['eq', 'ne', 'cn']} }, { name: 'lname', index: 'lname', width: 200, searchoptions: { sopt: ['eq', 'ne', 'cn']} } ], rowNum: 10, rowList: [10, 20, 30], pager: jQuery("#pager"), sortname: "fname", sortorder: "asc", viewrecords: true, caption: "Grid Title Here" }).jqGrid('navGrid', '#pager', { edit: false, add: false, del: false }, {}, // default settings for edit {}, // add {}, // delete { closeOnEscape: true, closeAfterSearch: true}, //search {} ) }); </script> ================================================== Second, THE C# WEBMETHOD [WebMethod] public static string getGridData(int? numRows, int? page, string sortField, string sortOrder, bool isSearch, string searchField, string searchString, string searchOper) { string result = null; MyDataContext db = null; try { //--- retrieve the data db = new MyDataContext("my connection string path"); var query = from u in db.TBL_USERs select u; //--- determine if this is a search filter if (isSearch) { searchOper = getOperator(searchOper); // need to associate correct operator to value sent from jqGrid string whereClause = String.Format("{0} {1} {2}", searchField, searchOper, "@" + searchField); //--- associate value to field parameter Dictionary<string, object> param = new Dictionary<string, object>(); param.Add("@" + searchField, searchString); query = query.Where(whereClause, new object[1] { param }); } //--- setup calculations int pageIndex = page ?? 1; //--- current page int pageSize = numRows ?? 10; //--- number of rows to show per page int totalRecords = query.Count(); //--- number of total items from query int totalPages = (int)Math.Ceiling((decimal)totalRecords / (decimal)pageSize); //--- number of pages //--- filter dataset for paging and sorting IQueryable<TBL_USER> orderedRecords = query.OrderBy(sortfield); IEnumerable<TBL_USER> sortedRecords = orderedRecords.ToList(); if (sortorder == "desc") sortedRecords= sortedRecords.Reverse(); sortedRecords= sortedRecords .Skip((pageIndex - 1) * pageSize) //--- page the data .Take(pageSize); //--- format json var jsonData = new { totalpages = totalPages, //--- number of pages page = pageIndex, //--- current page totalrecords = totalRecords, //--- total items rows = ( from row in sortedRecords select new { i = row.USER_ID, cell = new string[] { row.USER_ID.ToString(), row.FNAME.ToString(), row.LNAME } } ).ToArray() }; result = Newtonsoft.Json.JsonConvert.SerializeObject(jsonData); } catch (Exception ex) { Debug.WriteLine(ex); } finally { if (db != null) db.Dispose(); } return result; } ================================================== Third, NECESSITIES In order to have dynamic OrderBy clauses in the LINQ, I had to pull in a class to my AppCode folder called 'Dynamic.cs'. You can retrieve the file from downloading here. You will find the file in the "DynamicQuery" folder. That file will give you the ability to utilized dynamic ORDERBY clause since we don't know what column we're filtering by except on the initial load. To serialize the JSON back from the C-sharp to the JS, I incorporated the James Newton-King JSON.net DLL found here : http://json.codeplex.com/releases/view/37810. After downloading, there is a "Newtonsoft.Json.Compact.dll" which you can add in your Bin folder as a reference Here's my USING's block using System; using System.Collections; using System.Collections.Generic; using System.Linq; using System.Web.UI.WebControls; using System.Web.Services; using System.Linq.Dynamic; For the Javascript references, I'm using the following scripts in respective order in case that helps some folks: 1) jquery-1.3.2.min.js ... 2) jquery-ui-1.7.2.custom.min.js ... 3) json.min.js ... 4) i18n/grid.locale-en.js ... 5) jquery.jqGrid.min.js For the CSS, I'm using jqGrid's necessities as well as the jQuery UI Theme: 1) jquery_theme/jquery-ui-1.7.2.custom.css ... 2) ui.jqgrid.css The key to getting the parameters from the JS to the WebMethod without having to parse an unserialized string on the backend or having to setup some JS logic to switch methods for different numbers of parameters was this block postData: { searchString: '', searchField: '', searchOper: '' }, Those parameters will still be set correctly when you actually do a search and then reset to empty when you "reset" or want the grid to not do any filtering Hope this helps some others!!!! Please reply if you find major issues or ways of refactoring or doing better that I haven't considered.

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  • Linq to Datarow, Select multiple columns as distinct?

    - by Beta033
    basically i'm trying to reproduce the following mssql query as LINQ SELECT DISTINCT [TABLENAME], [COLUMNNAME] FROM [DATATABLE] the closest i've got is Dim query = (From row As DataRow In ds.Tables("DATATABLE").Rows _ Select row("COLUMNNAME") ,row("TABLENAME").Distinct when i do the above i get the error Range variable name can be inferred only from a simple or qualified name with no arguments. i was sort of expecting it to return a collection that i could then iterate through and perform actions for each entry. maybe a datarow collection? As a complete LINQ newb, i'm not sure what i'm missing. i've tried variations on Select new with { row("COLUMNNAME") ,row("TABLENAME")} and get: Anonymous type member name can be inferred only from a simple or qualified name with no arguments. Also, does anyone know of any good books/resources to get fluent?

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  • SQL Subquery in LINQ for Entity Framework 4.0

    - by Jorin
    I'm new to LINQ and EF, but I've been able to stumble through for the majority of the queries I have, but this one has me completely confused. No matter what I try, it comes up in SQL Profiler as a big mess :-). I have two tables: Users and UsersProjects. The goal of this query is to list all the users who are working on projects with the specified user. Here is the query as I have it written in SQL. It's a subquery, but I don't know of a way to simplify it further, but I'm open to suggestions there as well. SELECT DISTINCT Users.FirstName, Users.LastName FROM Users INNER JOIN UsersProjects ON Users.ID=UsersProjects.UserID WHERE UsersProjects.ProjectID IN (SELECT ProjectID FROM UsersProjects WHERE UserID=@UserID) Anybody able to help?? It seems like a fairly simple subquery in SQL, but in LINQ, I'm baffled. Thanks, Jorin

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