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• Direct Access on Server 2012

  - by francisswest

  Scenario: Windows Server 2012 with the Remote Access role installed. IP set to static, registered DNS. 3 domain controllers, all running Server 2003 (I suspect this may be the issue) Done so far: DNS registered, firewall turned off after IPsec was applied. Able to ping all 3 DC's with no issues Problem: Going through the DA wizard generates this error. I am logged in as a domain admin, verified that I can ping the DC, verified IPsec allows me to contact it. Since this version hasnt been readily deployed yet, there isnt much help available online from what I can find. Any assistance ayone could provide would be greatly appreciated. I am still new to the server world as far as things are considered. I would fit, user wise, between Superuser.com and serverfault.com (junior admin) Thanks to anyone who may be able to assist!

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• What programming technique not done by you, was ahead of its time?

  - by Ferds

  There are developers who understand a technology and produce a solution months or years ahead of its time. I worked with a guy who designed an system using C# beta which would monitor different system components on several servers. He used SQL Server that would pick up these system monitoring components (via reflection) and would instantiate them via an NT Service. The simplicity in this design, was that another developer (me), who understood part of a system, would produce a component that could monitor it, as he had the specialized knowledge of that part of the system. I would derive from the monitor base class (to start, stop and log info), install on the monitoring server GAC and then add an entry to the components table in sql server. Then the main engine would pick up this component and do its magic. I understood parts of it, but couldn't work out by derive from a base class, why add to the GAC etc. This was 6 years ago and it took me months to realize what he achieved. What programming technique not done by you was ahead of its time? EDIT : Techniques that you have seen at work or journals/blogs - I don't mean historically over years.

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• Persistence store in blackberry

  - by arunabha

  i am trying to save a simple string value "1".If i go back from one screen to another,its saving,but when i exit the app,and start again,i dont see that value being saved.I am implementing persistable interface.Can anyone suggest me where i am getting wrong import net.rim.device.api.util.Persistable; import net.rim.device.api.system.PersistentObject; import net.rim.device.api.system.PersistentStore; public class Persist implements Persistable { public static PersistentObject abc; public static String b; static { abc = PersistentStore.getPersistentObject(0xb92c8fe20b256b82L); } public static void data(){ synchronized (abc) { abc.setContents(1+""); abc.commit(); } } public static String getCurrQuestionNumber() { synchronized (abc) { System.out.println("new title is"+b); b= (String)abc.getContents(); System.out.println("title is"+b); return b; } } }

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• Strange behavior of Switch Case statement in Java

  - by supernova

  I understand that Java switch case are designed this way but why is this behavior in Java int x = 1; switch(x){ case 1: System.out.println(1); case 2: System.out.println(2); case 3: System.out.println(3); default: System.out.println("default"); } output : 1 2 3 default My question is why case 2 and 3 are executed? I know I omitted break statement but x was never 2 or 3 but case 2 and case 3 still executes?

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• Mono 2.10.5 Runtime error on Ubuntu 11.10

  - by johnluetke

  I've install mono-runtime via apt in order to run my Mono console application on Ubuntu via SSH. However, when I run the command mono myapp.exe, It exits, with no message, and my program does nothing. If I throw the -v switch to Mono, such as mono -v myapp.exe, I get about 10k lines of output (as expected, -v is verbose), with the first few lines being: converting method System.OutOfMemoryException:.ctor (string) Method System.OutOfMemoryException:.ctor (string) emitted at 0xb7052c28 to 0xb7052c4b (code length 35) [myapp.exe] converting method (wrapper runtime-invoke) <Module>:runtime_invoke_void__this___object (object,intptr,intptr,intptr) Method (wrapper runtime-invoke) <Module>:runtime_invoke_void__this___object (object,intptr,intptr,intptr) emitted at 0xb7052c68 to 0xb7052cf6 (code length 142) [myapp.exe] converting method System.SystemException:.ctor (string) I read this as the runtime throwing an OutOfMemory exception, but the machine is under no intense load, has plenty of available RAM, and is running nothing other that system processes. I've removed and reinstalled Mono countless times, and have even run the executable on other machines perfectly fine. Am I missing something completely obvious here?

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• CutePDF in a domain environment

  - by poke

  We've recently migrated from a workstation to domain environment. Since the migration, we've been unable to install CutePDF (CuteWriter.exe) on our Win XP Pro boxes. No error, it just fails silently. We were not having having issue prior to the domain migration. CutePDF is a PDF creator that works by emulating a printer. The installer is supposed to create a regular Windows printer that users can select to print to when they want to make a PDF. We are using Group Policy, but I didn't really see any GPOs that would be affecting this. Does anyone have any thoughts or suggestions on this issue? I've tried installing as a domain admin and also as a local admin.

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• FileInfo.MoveTo() vs File.Move()

  - by Eric

  Is there any difference between these two methods of moving a file? System.IO.FileInfo f = new System.IO.FileInfo(@"c:\foo.txt"); f.MoveTo(@"c:\bar.txt"); //vs System.IO.File.Move(@"c:\foo.txt", @"c:\bar.txt");

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• How to get CurrentLocation from GPS FirstTime quickly?

  - by Are

  Hi, Iam using locationManager = (LocationManager) getSystemService(LOCATION_SERVICE); Criteria criteria = new Criteria(); String bestProvider = locationManager.getBestProvider(criteria, true); locationManager.requestLocationUpdates(bestProvider, 0, 0, this); location = locationManager.getLastKnownLocation(bestProvider); but first time it is not giving location object.Always giving me null.I read in developer.android.com , "Cached Location is dismissed if it is too old" But second time it is giving location updates.How to solve my problem. Regards, Android Developer

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• question about python sched schedular.

  - by samy

  I have read about python sched (task schedular), it works like a cron. but I have a question : lets say if i schedule a function to ryn after every 2 hours and in the mean time my system gets shut down, then I again restart the system...did the schedular automatically starts and will run the function after 2 hours? or i have to start that again after shutting down the system? did sched work like a deamon?

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• How to get a debug flow of execution in C++

  - by Rich

  Hi, I work on a global trading system which supports many users. Each user can book,amend,edit,delete trades. The system is regulated by a central deal capture service. The deal capture service informs all the user of any updates that occur. The problem comes when we have crashes, as the production environment is impossible to re-create on a test system, I have to rely on crash dumps and log files. However this doesn't tell me what the user has been doing. I'd like a system that would (at the time of crashing) dump out a history of what the user has been doing. Anything that I add has to go into the live environment so it can't impact performance too much. Ideas wise I was thinking of a MACRO at the top of each function which acted like a stack trace (only I could supply additional user information, like trade id's, user dialog choices, etc ..) The system would record stack traces (on a per thread basis) and keep a history in a cyclic buffer (varying in size, depending on how much history you wanted to capture). Then on crash, I could dump this history stack. I'd really like to hear if anyone has a better solution, or if anyone knows of an existing framework? Thanks Rich

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• Conditional references in .NET project, possible to get rid of warning?

  - by Lasse V. Karlsen

  I have two references to a SQLite assembly, one for 32-bit and one for 64-bit, which looks like this (this is a test project to try to get rid of the warning, don't get hung up on the paths): <Reference Condition=" '$(Platform)' == 'x64' " Include="System.Data.SQLite, Version=1.0.61.0, Culture=neutral, PublicKeyToken=db937bc2d44ff139, processorArchitecture=AMD64"> <SpecificVersion>True</SpecificVersion> <HintPath>..\..\LVK Libraries\SQLite3\version_1.0.65.0\64-bit\System.Data.SQLite.DLL</HintPath> </Reference> <Reference Condition=" '$(Platform)' == 'x86' " Include="System.Data.SQLite, Version=1.0.65.0, Culture=neutral, PublicKeyToken=db937bc2d44ff139, processorArchitecture=x86"> <SpecificVersion>True</SpecificVersion> <HintPath>..\..\LVK Libraries\SQLite3\version_1.0.65.0\32-bit\System.Data.SQLite.DLL</HintPath> </Reference> This produces the following warning: Warning 1 The referenced component 'System.Data.SQLite' could not be found. Is it possible for me to get rid of this warning? One way I've looked at it to just configure my project to be 32-bit when I develop, and let the build machine fix the reference when building for 64-bit, but this seems a bit awkward and probably prone to errors. Any other options? The reason I want to get rid of it is that the warning is apparently being picked up by TeamCity and periodically flagged as something I need to look into, so I'd like to get completely rid of it.

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• Mail being sent as root on Ubuntu 14.04

  - by Benjamin Allison

  I'm really struggling with this. I'm trying to set up this server to send mail using Gmail's SMTP. Google keeps bouncing the messages, saying that that Authentication is required: smtp.gmail.com[74.125.196.109]:25: 530-5.5.1 Authentication Required. Learn more at smtp.gmail.com[74.125.196.109]:25: 530 5.5.1 http://support.google.com/mail/bin/answer.py?answer=14257 But it seems my server is trying to send mail as [email protected]. I'm baffled. Here's what I've done so far: Updated mail.cf relayhost = [smtp.gmail.com]:587 smtp_sasl_auth_enable = yes smtp_sasl_password_maps = hash:/etc/postfix/sasl_passwd smtp_sasl_security_options = noanonymous smtp_tls_CAfile = /etc/postfix/cacert.pem smtp_use_tls = yes Created /etc/postfix/sasl_passwd: [smtp.gmail.com]:587 [email protected]:password Then did the following: sudo chmod 400 /etc/postfix/sasl_passwd sudo postmap /etc/postfix/sasl_passwd cat /etc/ssl/certs/Thawte_Premium_Server_CA.pem | sudo tee -a /etc/postfix/cacert.pem service postfix restart I can't for the life me get a mail message to send, or change the default mail user from [email protected] to [email protected] (FWIW, I'm using Google Apps, that's why it's not a .gmail address).

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• Loading a Windows DLL in Java and initiate a class from it

  - by Joy

  I have a Windows DLL file from .NET namely "System.Management.dll". I work with it using the code I write below: ManagementObjectSearcher searcher = new ManagementObjectSearcher("root\\CIMV2", "SELECT * FROM Win32_LogicalDisk WHERE Name = 'C:'"); foreach (ManagementObject queryObj in searcher.Get()) { Console.WriteLine("Win32_LogicalDisk instance: "); if (queryObj["VolumeSerialNumber"] != null) { Console.WriteLine("Drive Name : " + queryObj["Name"]); Console.WriteLine("VolumeSerialNumber:", queryObj["VolumeSerialNumber"]); SysdriveSerial = queryObj["VolumeSerialNumber"].ToString(); } } Now I need this piece of code to be in Java. So can I do this? Without anything like c++ unmanaged code. I don't want to use c++ unmanaged code to call to this dll. I want something like this : public class CallToCsharp { private static native void ManagementObjectSearcher(); public static void main(String[] args) { System.loadLibrary("System.Management"); System.out.println("Loaded"); ManagementObjectSearcher searcher = new ManagementObjectSearcher("root\\CIMV2", "SELECT * FROM Win32_LogicalDisk WHERE Name = 'C:'"); } }

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• View results of affine transform

  - by stckjp

  I am trying to find out the reason why when I apply affine transformations on an image in OpenCV, the result of it is not visible in the preview window, but the entire window is black.How can I find workaround for this problem so that I can always view my transformed image (the result of the affine transform) in the window no matter the applied transformation? Update: I think that this happens because all the transformations are calculated with respect to the origin of the coordinate system (top left corner of the image). While for rotation I can specify the center of the rotation, and I am able to view the result, when I perform scaling I am not able to control where the transformed image goes. Is it possible to somehow move the coordinate system to make the image fit in the window? Update2: I have an image which contains only ROI at some position in it (the rest of the image is black), and I need to apply a set of affine transforms on it. To make things simpler and to see the effect of each individual transform, I applied each transform one by one. What I noticed is that, whenever I move (translate) the image such that the center of the ROI is in the center of the coordinate system (top left corner of the view window), all the affine transforms perform correctly without moving. However, by translating the center of ROI at the center of the coordinate system, the upper and the left part of the ROI remain cut out of the current view window. If I move ROI's central point to another point in the view window (for example the window center), an affine transform of type: A=[a 0 0; 0 b 0] (A is 2x3 matrix, parameter of the warpAffine function) moves the image (ROI), outside of the view window (which doesn't happen if the ROI's center is in the top-left corner). How can I modify the affine transform so the image doesn't move out of its place (behaves the same way as when the ROI center is in the center of the coordinate system)?

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• Error Reading Image

  - by javawarrior

  When I tried to open a simple smile.png image using package com.java3d.java3d.graphics; import java.awt.Color; import java.awt.image.BufferedImage; import java.io.File; import javax.imageio.ImageIO; public class Texture { public static Render floor = loadBitMap("smile.png"); public Texture(){} public static Render loadBitMap(String fileName) { try { BufferedImage image = ImageIO.read(Thread.currentThread().getContextClassLoader().getResource(fileName)); System.out.print(image==null); int width = image.getWidth(); System.out.println(width); int height = image.getHeight(); System.out.println(height); System.out.println(image.getRGB(4, 4)); Render result = new Render(width, height); image.getRGB(0, 0, width, height, result.pixels, 0, width); return result; } catch (Exception e) { System.out.println("CRASH!"); throw new RuntimeException(e); } } } it returns every pixel as -1; what could be causing this problem? Here is the image:

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• Formatting a byte array to string in java

  - by rgksugan

  I am using this code to find the MAC address of a machine.This code prints directly the MAC address, but i want to return it as a string.I am completely confused. please help. try { InetAddress add = InetAddress.getByName("10.123.96.102"); NetworkInterface ni1 = NetworkInterface.getByInetAddress(add); if (ni1 != null) { byte[] mac1 = ni1.getHardwareAddress(); if (mac1 != null) { for (int k = 0; k < mac1.length; k++) { System.out.format("%02X%s", mac1[k], (k < mac1.length - 1) ? "-" : ""); } } else { System.out.println("Address doesn't exist "); } System.out.println(); } else { System.out.println("address is not found."); } } catch (UnknownHostException e) { e.printStackTrace(); } catch (SocketException e) { e.printStackTrace(); }

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• DD-WRT with both https and sshd running in port 443

  - by Bruno

  I have a buffalo router with dd-wrt v24 SP2. After setting up the basic stuff, I enabled the https access to the admin page. Several days later, while setting up remote ssh, I changed the default port from 22 to 443. And now..well :) You got the picture :) I can ssh the router but I have no web access to it's admin page. Before rushing to a cold-hearted configuration reset, is there any way to change the ssh port from a shell? Or make dd-wrt accessible thru basic http?

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• Approaching Java from a Ruby perspective

  - by Travis

  There are plenty of resources available to a Java developer for getting a jump-start into Ruby/Rails development. The reverse doesn't appear to be true. What resources would you suggest for getting up-to-date on the current state of java technologies? How about learning how to approach DRY (don't repeat yourself) without the use of metaprogramming? Or how to approach various scenarios where a ruby developer is used to passing in a function (proc/lambda/block) as an argument (callbacks, etc)?

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• Fast response on first Socket I/O request but slow every other time when communicating with remote serial port

  - by GreenGodot

  I'm using sockets to pass Serial commands to a remote device. And the response to that request is sent back and printed out. However, I am having a problem in that the first time it is instant but the rest of the time it can take up to 20 seconds to receive a reply. I think the problem is with my attempt at threading but I am not entirely sure. new Thread() { @Override public void run() { System.out.println("opened"); try { isSocketRetrieving.setText("Opening Socket"); socket = new Socket(getAddress(), getRemotePort())); DataOutput = new DataOutputStream(socket .getOutputStream()); inFromServer = new BufferedReader( new InputStreamReader(socket .getInputStream())); String line = ""; isSocketRetrieving.setText("Reading Stream......"); while ((line = inFromServer.readLine()) != null) { System.out.println(line); if (line.contains(getHandshakeRequest())) { DataOutput.write((getHandshakeResponse()toString() + "\r").getBytes()); DataOutput.flush(); DataOutput .write((getCommand().toString() + "\r").getBytes()); DataOutput.flush(); int pause = (line.length()*8*1000)/getBaud(); sleep(pause); } else if (line.contains(readingObject .getExpected())) { System.out.println(line); textArea.append("value = " + line + "\n"); textAreaScroll.revalidate(); System.out.println("Got Value"); break; } } System.out.println("Ended"); try { inFromServer.close(); DataOutput.close(); socket.close(); isSocketRetrieving.setText("Socket is inactive..."); rs232Table.addMouseListener(listener); interrupt(); join(); } catch (IOException e) { e.printStackTrace(); } catch (InterruptedException e) { System.out.println("Thread exited"); } } catch (NumberFormatException e1) { e1.printStackTrace(); } catch (UnknownHostException e1) { e1.printStackTrace(); } catch (IOException e1) { e1.printStackTrace(); } catch (InterruptedException e) { // TODO Auto-generated catch block e.printStackTrace(); } } }.start();

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• Constructing a WeakReference<T> throws COMException

  - by ChaseMedallion

  The following code: IDisposable d = ... new WeakReference<IDisposable>(d); Has started throwing the following exception on SOME machines. What could cause this? System.Runtime.InteropServices.COMException: Unspecified error (Exception from HRESULT: 0x80004005 (E_FAIL)) EDIT: the machines that experience the error are running Windows Server 2008 R2. Windows Server 2012 and desktop machines running windows 7 work fine. (this is true, but I now think a different issue is the relevant difference... see below). EDIT: as an additional note, this occurred right after updating our codebase to Entity Framework 6.1.1.-beta1. In the above code, The IDisposable is a class which wraps an EF DbContext. EDIT: why the votes to close? EDIT: the stack trace of the failure ends at the WeakReference<T> constructor called in the above code: at System.WeakReference`1..ctor(T target, Boolean trackResurrection) // from here on down it's code we wrote/simple LINQ. None of this code has changed recently; // we just upgraded to EF6 and saw this failure start happening at Core.Data.EntityFrameworkDataContext.RegisterDependentDisposable(IDisposable child) at Core.Data.ServiceFactory.GetConstructorParameter[TService](Type parameterType) at System.Linq.Enumerable.WhereSelectListIterator`2.MoveNext() at System.Linq.Buffer`1..ctor(IEnumerable`1 source) at System.Linq.Enumerable.ToArray[TSource](IEnumerable`1 source) at Core.Data.ServiceFactory.CreateService[TService]() at MVC controller action method EDIT: it turns out that the machines having issues with this were running AppDynamics. Uninstalling that seems to have removed the issue.

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• Java: file write on finalize method

  - by sowrov

  In my understanding a singleton object will destroy only when the application is about to terminate. So in C++ I write a Singleton class to log my application and in that Singleton logger's destructor I log the time when my application was terminated. Things worked perfectly in C++. Now I want to have that same logger in Java, as in java there is no destructor so I implemented the finalize method for that singleton logger. But it seem that finalize method actually never get called. So, I add that System.runFinalizersOnExit(true); line, somewhere in my code (though I know it is deprecated) and that finalize method get called every time before termination of the app. But still there is a problem! If I try to write anything on file in that finalize method, It does not work, though System.out work without any problem! :( Can you guys help me on this problem? Here is a sample code of what I am try to do: Singleton Logger Class: public class MyLogger { FileWriter writer; private MyLogger() { try { this.writer = new FileWriter("log.txt"); } catch (IOException ex) { } } public static MyLogger getInstance() { return MyLoggerHolder.INSTANCE; } private static class MyLoggerHolder { private static final MyLogger INSTANCE = new MyLogger(); } @Override protected void finalize () { try { super.finalize(); System.out.println("Here"); //worked correctly. this.writer.write(new Date().toString()+System.getProperty("line.separator")); this.writer.write("End"); this.writer.flush(); //does not work! this.writer.close(); } catch (Throwable ex) { } } public synchronized void log(String str) { try { this.writer.write(new Date().toString()+System.getProperty("line.separator")); this.writer.write(str+"\n"); this.writer.flush(); } catch (IOException ex) { } } } Main: public class Main { public static void main(String[] args) { System.runFinalizersOnExit(true); MyLogger logger = MyLogger.getInstance(); logger.log("test"); } }

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• Just an experiment changing the application data path

  - by Arthur

  When I change the Appication Data path in windows xp registry to a network folder I get this error message on the next system startup: "windows cannot load the user's profile but has logged you with the default profile system" The registry keys are: "[HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Explorer\Shell Folders]" "[HKEY_CURRENT_USER\Software\Microsoft\Windows\CurrentVersion\Explorer\User Shell Folders]" under the names "AppData" and "Local AppData" I dont care if "Windows logins you with the default profile system" but is there a way to disable that message, or change the message timeout form 30 seconds to 0?,or maybe create an script that changes the Application Data path every system startup? P.S. The computer with the shared folder is always on.

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• ArgumentException was unhandled Application.run

  - by user369758

  Hi I've been through many sites and can't seem to find an answer. I modified a view that was connected to a Datagridview connected through a tableadapter on a C# Winforms app and in order to "reconnect" I had to delete the tableadapter and reconnect it. This was to get rid of an error regarding Unique contstraints. So I fixed that and now the application launches but when I click on the tab that that grid is on I get: System.ArgumentException was unhandled Message="Cannot bind to the property or column Id on the DataSource.\r\nParameter name: dataMember" Source="System.Windows.Forms" ParamName="dataMember" StackTrace: at System.Windows.Forms.BindToObject.CheckBinding() at System.Windows.Forms.BindToObject.SetBindingManagerBase(BindingManagerBase lManager)......... I can't seem to find an answer to this problem. Can someone help me? Thanks

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• GridView to excel after create send mail c#

  - by Diego Bran

  I want to send a .xlsx , first I created (It has html code in it) then I used a SMTP server to send it , it does attach the file but when I tried to open it " It says that the file is corrupted etc" any help? Here is my code try { System.IO.StringWriter sw = new System.IO.StringWriter(); System.Web.UI.HtmlTextWriter htw = new System.Web.UI.HtmlTextWriter(sw); // Render grid view control. gvStock.RenderControl(htw); // Write the rendered content to a file. string renderedGridView = sw.ToString(); File.WriteAllText(@"C:\test\ExportedFile.xls", renderedGridView); // File.WriteAllText(@"C:\test\ExportedFile.xls", p1); } catch (Exception e) { Response.Write(e.Message); } try { MailMessage mail = new MailMessage(); SmtpClient SmtpServer = new SmtpClient("server"); mail.From = new MailAddress("[email protected]"); mail.To.Add("[email protected]"); mail.Subject = "Test Mail - 1"; mail.Body = "mail with attachment"; Attachment data = new Attachment("C:/test/ExportedFile.xls"); mail.Attachments.Add(data); SmtpServer.Port = 25; SmtpServer.Credentials = new System.Net.NetworkCredential("user", "pass"); // SmtpServer.EnableSsl = true; SmtpServer.UseDefaultCredentials = false; SmtpServer.Send(mail); } catch( Exception e) { Response.Write(e.Message); }

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• Why are these lines being skipped? (java)

  - by David

  Here's the relevant bit of the source code: class Dice { String name ; int x ; int[] sum ; ... public Dice (String name) { this.name = name ; this.x = 0 ; this.sum = new int[7] ; } ... public static void main (String[] arg) { Dice a1 = new Dice ("a1") ; printValues (a1) ; } public static void printDice (Dice Dice) { System.out.println (Dice.name) ; System.out.println ("value: "+Dice.x) ; printValues (Dice) ; } public static void printValues (Dice Dice) { for (int i = 0; i<Dice.sum.length; i++) System.out.println ("#of "+i+"'s: "+Dice.sum[i]) ; } } Here is the output: #of 0's: 0 #of 1's: 0 #of 2's: 0 #of 3's: 0 #of 4's: 0 #of 5's: 0 #of 6's: 0 Why didn't these two lines execute inside printDice: System.out.println (Dice.name) ; System.out.println ("value: "+Dice.x) ; if they had then i would expect to see "a1" and "Value: 0" printed at the top of the rows of #of's

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