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  • problem in displays data in one page

    - by user318068
    hi ,,,,, I have a problem in the following code ... The following code works as follows displays the invites for each member so that if he had five invite from supposed to be displayed all on one page But before you code that does not function Proper image is the only display one invite on the page and until the approval or rejection of the invitation displays the invite the other .... But this is not my want to offer all on one page I wish I could solve the problem and I can view all calls in one page I think that the problem is in the order code I think that the problem is in the order code my code : <?php session_start(); if (!isset($_SESSION['user_id'])) { header("Location: login.php"); } $id=$_SESSION['user_id']; ?> <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd"> <html xmlns="http://www.w3.org/1999/xhtml"> <head> <meta http-equiv="Content-Type" content="text/html; charset=utf-8" /> <title>Untitled Document</title> </head> <body> <center> <?php include("connect.php"); $sql =mysql_query("select * from ninvite where recieverMemberID ='$id' and viwed= '0'"); $num =mysql_num_rows($sql); echo $num ; if ($num>0) { while($row=mysql_fetch_array($sql)) { $sender=$row['SenderMemberID']; $room=$row['RoomID']; $sql =mysql_query("select MemberName from members where MemberID ='$sender' "); $sql1 =mysql_query("select RoomName from rooms where RoomID ='$room' "); while($row=mysql_fetch_array($sql)) {$mem =$row['MemberName']; } while($rows=mysql_fetch_array($sql1)) { $Ro =$rows['RoomName']; ?> <form action="join.php" method="post"> <label> </label> <br/> <label> <?php echo " you have invite from $mem to join $Ro"; ?> </label> <br/><br/> <label>accept</label> <input name="radio1" type="radio" value="accpet" /> <label>reject</label> <input name="radio1" type="radio" value="Reject" /><br/> <input type="submit" name="submit" value="done" /> </form> <?php } } } ?> </center> </body> </html> thanks alot. my SQl -- phpMyAdmin SQL Dump -- version 3.2.4 -- http://www.phpmyadmin.net -- Host: localhost -- Generation Time: May 07, 2010 at 12:50 ? -- Server version: 5.1.41 -- PHP Version: 5.3.1 SET SQL_MODE="NO_AUTO_VALUE_ON_ZERO"; /*!40101 SET @OLD_CHARACTER_SET_CLIENT=@@CHARACTER_SET_CLIENT /; /!40101 SET @OLD_CHARACTER_SET_RESULTS=@@CHARACTER_SET_RESULTS /; /!40101 SET @OLD_COLLATION_CONNECTION=@@COLLATION_CONNECTION /; /!40101 SET NAMES utf8 */; -- -- Database: tr -- -- Table structure for table joinroom CREATE TABLE IF NOT EXISTS joinroom ( MemberID int(10) NOT NULL, RoomID int(10) NOT NULL, PRIMARY KEY (MemberID,RoomID) ) ENGINE=MyISAM DEFAULT CHARSET=latin1; -- -- Dumping data for table joinroom INSERT INTO joinroom (MemberID, RoomID) VALUES (28, 1); -- -- Table structure for table members CREATE TABLE IF NOT EXISTS members ( MemberID int(10) unsigned NOT NULL AUTO_INCREMENT, MemberName varchar(20) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, MemberPass varchar(10) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, MemberEmail varchar(30) CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, MemberLocation text CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, MemberImg text CHARACTER SET utf8 COLLATE utf8_bin NOT NULL, PRIMARY KEY (MemberID) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=34 ; -- -- Dumping data for table members INSERT INTO members (MemberID, MemberName, MemberPass, MemberEmail, MemberLocation, MemberImg) VALUES (28, 'marwa', '1234', '[email protected]', 'mmmmmm', 'dddddddddd'), (29, 'nora', '1234', '[email protected]', 'fffffffffffgg', 'gggggggggggggg'), (30, 'soso', '1234', '[email protected]', 'ffffffff', 'kkkkkkkkkkkkkkkkkk'), (31, 'gege', '1234', '[email protected]', 'kkkkkkkkkkkkkkkk', 'uuuuuuuuuuuuuuuuu'), (32, 'nono', '1234', '[email protected]', 'ggggggggggggaaaaa', 'aaaaaaaaaaaaaaa'), (33, 'nda', '1234', '[email protected]', 'kkkkkkkkkkkkkkkk', 'ooooooooooooooo'); -- -- Table structure for table ninvite CREATE TABLE IF NOT EXISTS ninvite ( SenderMemberID int(11) NOT NULL AUTO_INCREMENT, recieverMemberID varchar(30) NOT NULL, RoomID int(11) NOT NULL, viwed int(11) NOT NULL, PRIMARY KEY (SenderMemberID,recieverMemberID,RoomID) ) ENGINE=MyISAM DEFAULT CHARSET=latin1 AUTO_INCREMENT=33 ; -- -- Dumping data for table ninvite INSERT INTO ninvite (SenderMemberID, recieverMemberID, RoomID, viwed) VALUES (28, '33', 1, 0), (28, '32', 1, 0), (28, '31', 1, 0); /*!40101 SET CHARACTER_SET_CLIENT=@OLD_CHARACTER_SET_CLIENT /; /!40101 SET CHARACTER_SET_RESULTS=@OLD_CHARACTER_SET_RESULTS /; /!40101 SET COLLATION_CONNECTION=@OLD_COLLATION_CONNECTION */;

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  • mysql_fetch_array() expects parameter 1 to be resource problem

    - by user225269
    I don't get it, I see no mistakes in this code but there is this error, please help: mysql_fetch_array() expects parameter 1 to be resource problem <?php $con = mysql_connect("localhost","root","nitoryolai123$%^"); if (!$con) { die('Could not connect: ' . mysql_error()); } mysql_select_db("school", $con); $result = mysql_query("SELECT * FROM student WHERE IDNO=".$_GET['id']); ?> <?php while ($row = mysql_fetch_array($result)) { ?> <table class="a" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#D3D3D3"> <tr> <form name="formcheck" method="get" action="updateact.php" onsubmit="return formCheck(this);"> <td> <table border="0" cellpadding="3" cellspacing="1" bgcolor=""> <tr> <td colspan="16" height="25" style="background:#5C915C; color:white; border:white 1px solid; text-align: left"><strong><font size="2">Update Students</td> <tr> <td width="30" height="35"><font size="2">*I D Number:</td> <td width="30"><input name="idnum" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $_GET['id']; ?>"></td> </tr> <tr> <td width="30" height="35"><font size="2">*Year:</td> <td width="30"><input name="yr" onkeypress="return isNumberKey(event)" type="text" maxlength="5" id='numbers'/ value="<?php echo $row["YEAR"]; ?>"></td> <?php } ?> I'm just trying to load the data in the forms but I don't know why that error appears. What could possibly be the mistake in here?

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  • JSON onFailure issue

    - by Mikey1980
    I’m having trouble getting a AJAX/JSON function to work correctly. I had this function grabbing value from a drop down box but now I want to use an anchor tag to set it's value. I thought it would be easy to just use the onClick event to pass string to the function I was using for the drop down box but I get the alert in JSON onFailure event even though data gets added to MySQL. I tried removing the alert from onFailure event but then it doesn't add the data. The drop down still continues work work fine, no alerts. (I should note that removing the alert also broke my drop down box) 1st I add an onClick event… <a href="<?php echo Settings::get('app.webroot'); ?>?view=schedule&action=questions" onmouseout="MM_swapImgRestore();" onmouseover="MM_swapImage('bre','','template/images/schedule/bre_f2.gif',1)" onclick="assignCallType('testing')";> 2nd I check main.js.php function assignCallType(type) { alert(type); new Request.JSON({ url: "ajax.php", onSuccess: function(rtndata,txt){ if (rtndata['STATUS'] != 'OK') alert('Status was not okay'); }, onFailure : function () { alert("onFailure") } }).get({ 'action': 'assignCallType', 'call_type': type }); } 3rd Ajax.php: the variable is back in PHP and values get added to MySQL but I get the Alert in the JSON onFailure event if ($_GET['action'] == "assignCallType") { if ($USER->isInsideSales()) { $call_type = $_GET['call_type']; $_SESSION['callinfo']->setCallType($call_type); $_SESSION['callinfo']->save($callid); echo json_encode(array('STATUS'=>'OK')); } else { echo json_encode(array('STATUS'=>'DENIED')); } } Any idea where I am going wrong. The only difference between this and the working drop down is how the function was called, I used onchange="assignCallType(this.value)".

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  • MySQL Database Query - Codeigniter

    - by user2450349
    I am building an application with Codeigniter and need some help with a DB query. I have a table called users with the following fields: user_id, user_name, user_password, user_email, user_role, user_manager_id In my app, I pull all records from the user table using the following: function get_clients() { $this->db->select('*'); $this->db->where('user_role', 'client'); $this->db->order_by("user_name", "Asc"); $query = $this->db->get("users"); return $query->result_array(); } This works as expected, however when I display the results in the view, I also want to display a new column called Manager which will display the managers user_name field. The user_manager_id is the id of the user from the same table. Im guessing you can create an outer join on the same table but not sure. In the view, I am displaying the returned info as follows: <table class="table table-striped" id="zero-configuration"> <thead> <tr> <th>Name</th> <th>Email</th> <th>Manager</th> </tr> </thead> <tbody> <?php foreach($clients as $row) { ?> <tr> <td><?php echo $row['user_name']; ?> (<?php echo $row['user_username']; ?>)</td> <td><?php echo $row['user_email']; ?></td> <td><?php echo $row['???']; ?></td> </tr> <?php } ?> </tbody> </table> Any idea of how I can form the query and display the manager name is the view? Example: user_id user_name user_password user_email user_role user_manager_id 1 Ollie adjjk34jcd [email protected] client null 2 James djklsdfsdjk [email protected] client 1 When i query the database, i want to display results like this: Ollie [email protected] James [email protected] Ollie

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  • Form Submitting Incorrect Information to MySQL Database

    - by ThatMacLad
    I've created a form that submits data to a MySQL database but the Date, Time, Year and Month fields constantly revert to the exact same date (1st January 1970) despite the fact that when I submit the information to the database the form displays the current date, time etc to me. I've already set it so that the time and date fields automatically display the current time and date. Could someone please help me with this. Form: <html> <head> <title>Blog | New Post</title> <link rel="stylesheet" href="css/newposts.css" type="text/css" /> </head> <body> <div class="new-form"> <div class="header"> <a href="edit.php"><img src="images/edit-home-button.png"></a> </div> <div class="form-bg"> <?php if (isset($_POST['submit'])) { $month = htmlspecialchars(strip_tags($_POST['month'])); $date = htmlspecialchars(strip_tags($_POST['date'])); $year = htmlspecialchars(strip_tags($_POST['year'])); $time = htmlspecialchars(strip_tags($_POST['time'])); $title = htmlspecialchars(strip_tags($_POST['title'])); $entry = $_POST['entry']; $timestamp = strtotime($month . " " . $date . " " . $year . " " . $time); $entry = nl2br($entry); if (!get_magic_quotes_gpc()) { $title = addslashes($title); $entry = addslashes($entry); } mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "INSERT INTO php_blog (timestamp,title,entry) VALUES ('$timestamp','$title','$entry')"; $result = mysql_query($sql) or print("Can't insert into table php_blog.<br />" . $sql . "<br />" . mysql_error()); if ($result != false) { print "<p class=\"success\">Your entry has successfully been entered into the blog. </p>"; } mysql_close(); } ?> <?php $current_month = date("F"); $current_date = date("d"); $current_year = date("Y"); $current_time = date("H:i"); ?> <form method="post" action="<?php echo $_SERVER['PHP_SELF']; ?>"> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_month; ?>" /> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_date; ?>" /> <input class="field" type="text" name="date" id="date" size="2" value="<?php echo $current_year; ?>" /> <input type="text" name="time" id="time" size="5"value="<?php echo $current_time; ?>" /> <input class="field2" type="text" id="title" value="Title Goes Here." name="title" size="40" /> <textarea class="textarea" cols="80" rows="20" name="entry" id="entry" class="field2"></textarea> <input class="field" type="submit" name="submit" id="submit" value="Submit"> </form> </div> </div> </div> <div class="bottom"></div> </body> </html>

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  • Ajax post failing in asp

    - by Dave Kiss
    hey guys, this might be really stupid, but hopefully someone can help. I'm trying to post to an external script using ajax so i can mail the data, but for some reason my data is not making it to the script. $(document).ready(function() { $("#submitContactForm").click(function () { $('#loading').append('<img src="http://www.xxxxxxxx.com/demo/copyshop/images/loading.gif" alt="Currently Loading" id="loadingComment" />'); var name = $('#name').val(); var email = $('#email').val(); var comment = $('#comment').val(); var dataString = 'name='+ name + '&email=' + email + '&comment=' + comment; $.ajax({ url: 'http://www.xxxxx.com/demo/copyshop/php/sendmail.php', type: 'POST', data: '?name=Dave&[email protected]&comment=hiiii', success: function(result) { $('#loading').append('success'); } }); return false; }); }); the php script is simple (for now - just wanted to make sure it worked) <?php $name = $_POST['name']; $email = $_POST['email']; $comment = $_POST['comment']; $to = '[email protected]'; $subject = 'New Contact Inquiry'; $message = $comment; mail($to, $subject, $message); ?> the jquery is embedded in an .aspx page (a language i'm not familiar with) but is posting to a php script. i'm receiving emails properly but there is no data inside. am i missing something? i tried to bypass the variables in this example, but its still not working thanks

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  • convert mysql code to codeigniter

    - by Jethro Tamares Doble
    How can i convert this code into an acceptable codeigniter code: mysql_select_db($database_connection_ched, $connection_ched); $query_Institutions = "SELECT * FROM tb_institutional_profile ORDER BY tb_institutional_profile.institution_name ASC"; $Institutions = mysql_query($query_Institutions, $connection_ched) or die(mysql_error()); $row_Institutions = mysql_fetch_assoc($Institutions); $totalRows_Institutions = mysql_num_rows($Institutions); <td width="192"><select name="institution_id"> <?php do { <option value="<?php echo $row_Institutions['institution_id']?>" ><?php echo $row_Institutions['institution_name']?></option> <?php } while ($row_Institutions = mysql_fetch_assoc($Institutions)); ?> </select></td>

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  • Problems using "at" with Apache

    - by Alex Padgett
    I'm trying to use a PHP script to create at jobs, but when it comes time to execute the jobs, nothing seems to be happening. I've tried to output any errors to log files, but have had no luck. It seems obvious that it's a permissions issue, because when I set apache to run as my personal user, everything works fine. However, when I exec wget directly from PHP, everything works fine so it seems that apache has the correct permissions to use it. The problem appears to be when using at in conjunction with apache. So I need to find a way to make this work with apache running as its own user. Here is the command I'm using: echo "wget -qO- http://example.com/" | at now + 1 minute 2>&1 Any ideas? EDIT: Apache can create the at jobs, it just seems that when they execute nothing is happening.

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  • Wordpress is_front_page if statment

    - by Anders Kitson
    I have the following code below. I am trying to get rid of the box articles div when I am on the home page the code works when the html is outside of the else portion of the IF statement, as soon as I put it inside the page goes blank, I can't seem to figure out where I have broken the code. Any help would be great. <?php if(is_front_page()) { if(function_exists('wp_content_slider')) { wp_content_slider(); } } else{ ?> <div class="box articles"> <div class="block" id="articles"> <h2><?php the_title(); ?></h2> <div class="article"> <div class="entry"> <?php the_content(); ?> </div> <?php edit_post_link('Modifca Contenuto.', '<p>', '</p>'); ?> </div> </div> </div> <?php endwhile; endif; ?> <? } ?>

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  • variable $base_path is not working

    - by Nidhi Prasad
    I am trying to get the value of base_path variable in PHP (on lamp server) . I have kept the code insider beta_test directory inside www directly. i.e, base path function should return " /beta_test/ " . But it is returning just single slash ( "/" ) . The code that I tried is <script type="text/javascript" src="<?php print base_path(); ?>sites/all/themes/people10/slider/call.js"></script> Expected output is <script type="text/javascript" src="/beta_test/sites/all/themes/people10/slider/call.js"></script> But its giving <script type="text/javascript" src="/sites/all/themes/people10/slider/call.js"></script> I am using php version 5.3.3.Can anyone please help me in getting this issue solved? I am newbie to php and drupal .

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  • Apache on Windows in production environment? Why not?

    - by tillda
    "Everyone" know that Apache is for Linux/Unix and on Windows IIS is the way to go. However, I'm not a pro at Linux and it would be an enormous relief for me to use just the same setup in the production environment that I use during development. I'm a solo developer and I'm trying to make things as simple as possible. I've already got rid of other issues like storage (-cloud) emails (-postmark). So, what are the real drawbacks that can happen when I just put Apache in Windows virtual private server from Rackspace and use it as the main production environment for a PHP project? Money for more VPS resources is not that big issue compared to the possibility of not having to learn a different OS. Super-heavy traffic is not expected. Also my PHP project can be quite optimized. There are some heavy scripts, but only for the inside (logged) users. All else can be served more or less statically.

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  • highlight page selected in pagination?

    - by Mahmoud
    Hey There i have a php page, that shows all products that are stored on the database, so everything in fine, but my problem is that i am trying to highlight or give a color when a selected number is clicked, example, let say i all my product are showing and there are 2 pages, so when the user clicks on next the next fade and number 2 is colored yellow this well help the user to on which page he is below is my php code <?php echo"<a style:'color:#FFF;font-style:normal;'> "; include "im/config.php"; include('im/ps_pagination.php'); $result = ("Select * from product "); $pager = new PS_Pagination($conn, $result, 5, 6, "product=product"); $rs = $pager->paginate(); echo"<div id='image_container'>"; echo $pager->renderFullNav(); echo "<br /><br />\n"; while($row = mysql_fetch_array($rs)){ echo" <div class='virtualpage hidepiece'><a href='gal/".$row['pro_image']."' rel='lightbox[roadtrip]' title='".$row['pro_name']." : ".$row['pro_mini_des']."' style='color:#000'><img src='thumb/".$row['pro_thumb']."' /> </a></div>"; } echo"</div>"; echo "<br /><br />\n"; echo $pager->renderFullNav(); echo"</a>"; ?> Thank everyone

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  • Where to start when setting up a gambling website [closed]

    - by molleman
    I don't know if this is the correct place or this question by I couldn't find anywhere else. I am looking into building a gambling website, I have good HTML CSS and JavaScript skills but I do not know enough of the server side to actually build a backend for a gambling website. Firstly where would you start , what language , I work With Wordpress , so I understand php a little but not a lot . Would php be a good place to start . If so what framework would be able to scale if the number of users on the website increased . clearly I would like a backend where you could view 1. Users 2. Transactions 3. input games which you can bet on And so on.. Also users should be able to see all there associated information If anyone could help that would be great.

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  • inserts 'Array' into mysql table

    - by Noah Smith
    i want to insert an array into a mysql table. The array is produced by script scanning all the links, converting into absolute links and then displaying them in an array. i decided to mysql_query the array into the table but now i am stuck. it only posts 'Array', instead of every row from the array into a different row. Any ideas??! <?php require_once('simplehtmldom_1_5/simple_html_dom.php'); require_once('url_to_absolute/url_to_absolute.php'); $connect = mysql_connect("xxxx", "xxxx", "xxx") or die('Couldn\'t connect to MySQL Server: ' . mysql_error()); mysql_select_db("xxxx", $connect ) or die('Couldn\'t Select the database: ' . mysql_error( $connect )); $links = Array(); $URL = 'http://www.theqlick.com'; // change it for urls to grab // grabs the urls from URL $file = file_get_html($URL); foreach ($file->find('a') as $theelement) { $links[] = url_to_absolute($URL, $theelement->href); } print_r($links); mysql_query("INSERT INTO pages (url) VALUES ('$links[]')"); mysql_close($connect);

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  • Upgrading Fedora to Current Version - Dependent Applications Concerns

    - by nicorellius
    Is it possible to upgrade to Fedora 11 and still keep the server functional (it's running Fedora Core release 6 now, with MySQL 5.0, PHP 5.1 and Apache 2.2)? I have a Customer Relationship Management system on there and it is required on a daily basis. I am trying to figure out if I should upgrade (and whether that will cause huge problems) or if I should start over with a new OS (like Ubuntu) and install the CRM fresh, with updated version of MySQL, PHP, Apache, etc. I ask because I am not really the sysadmin, but have but put in charge of this server.

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  • Redirection Still not working (updated on earlier question)

    - by NoviceCoding
    So earlier I asked this question: JQuery Login Redirect. Code Included The php file is sending the following: $return['error'] = false; $return['msg'] = 'You have successfully logged in!!'; I've tried all the suggestions, quoting the error on php and ajax end, 2 equals instead of 3, I've also tried DNE true which should be the same as an else statement: $(document).ready(function(){ $('#submit').click(function() { $('#waiting').show(500); $('#empty').show(500); $('#reg').hide(0); $('#message').hide(0); $.ajax({ type : 'POST', url : 'logina.php', dataType : 'json', data: { type : $('#typeof').val(), login : $('#login').val(), pass : $('#pass').val(), }, success : function(data){ $('#waiting').hide(500); $('#empty').show(500); $('#message').removeClass().addClass((data.error === true) ? 'error' : 'success') .text(data.msg).show(500) if(data.error != true) window.location.replace("http://blahblah.com/usercp.php"); if (data.error === true) $('#reg').show(500); $('#empty').hide() }, error : function(XMLHttpRequest, textStatus, errorThrown) { $('#waiting').hide(500); $('#message').removeClass().addClass('error') .text("There was an Error. Please try again.").show(500); $('#reg').show(500); $('#empty').hide(); Recaptcha.reload(); } }); return false; }); And it still wont work. Any ideas on how to make a redirection work if login is successful and error returns false? Also while I am asking, can I put a .delay(3000) 3s at the end of window.location.replace("http://blahblah.com/usercp.php")?

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  • Is there a script that can dynamically list the contents of a folder?

    - by user294756
    I am redesigning my company's intranet site in Wordpress and one of the things they need is an archive of company memos. There are over 300 memos saved in one location and I'm wondering if there is a jQuery script that I can run that will read the contents of a local (network) folder and auto-generate a list of the contents of that folder dynamically (and generate those names as a hyperlink to that file, but if I can list the files, I can get include the hyperlink tag myself). I can always manually create the list of hyperlinks (would take a couple days to do so) but if I can generate it dynamically, whenever a new memo is added, the script will automatically include it making the site much easier to maintain. Is this at all possible? I know that this can probably be done in PHP, but the page I need to do this on is not a php page, it is one of the subpages that is created in wordpress that does not have a php file extension and can't run php code (that I know of) Thanks in advance for any and all assistance.

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  • Drop down of Superfish Menu appear under Smart Slide Show in wordpress

    - by oscar
    Hi, I spent almost my entire Saturday trying to solve this problem and have not had success. Firefox works well, but in IE8 and Chrome, the dropdown menu appears below the Smart Slide Show (Flash). Please could someone help me? the link to the page: http://www.institutoforlanini.com.br/novosite This is the code of the index: <?php get_header (); ?> <div id=conteiner> <div id=content> <div id="slider"> php echo do_shortcode ('[smart_slide_show ]');?> </ div> </div> </div> <! - End of content div -> <?php get_sidebar ();?> <?php get_footer ();?>

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  • Using curl to submit/retrieve a forms results

    - by Jason
    I need help in trying to use curl to post data to a page and retrieve the results after the form has been submitted. I created a simple form: <form name="test" method="post" action="form.php"> <input type="text" name="name" size="40" />e <input type="text" name="comment" size="140" /> <input type="submit" name="submit" value="submit" /> </form> In addition, I have php code to handle this form in the same page. All it does is echo back the form values. The curl that I have been using is this: $h = curl_init(); curl_setopt($h, CURLOPT_URL, "path/to/form.php"); curl_setopt($h, CURLOPT_POST, true); curl_setopt($h, CURLOPT_POSTFIELDS, array( 'name' = 'yes', 'comment' = 'no' )); curl_setopt($h, CURLOPT_HEADER, false); curl_setopt($h, CURLOPT_RETURNTRANSFER, 1); $result = curl_exec($h); When I launch the page with the curl code in it, I get the form.php page contents but it doesn't not show the variables that PHP should have echo'd when the form is submitted. would appreciate any help with this. Thanks.

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