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  • Get name of currently executing test in JUnit 4

    - by Dave Ray
    In JUnit 3, I could get the name of the currently running test like this: public class MyTest extends TestCase { public void testSomething() { System.out.println("Current test is " + getName()); ... } } which would print "Current test is testSomething". Is there any out-of-the-box or simple way to do this in JUnit 4? Background: Obviously, I don't want to just print the name of the test. I want to load test-specific data that is stored in a resource with the same name as the test. You know, convention over configuration and all that. Thanks!

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  • Reg : Contact changes in Android

    - by Laxman
    Hi, I am using ContentObserver on contacts. But here my problem is atleast once i have to launch my application other wise i am unable to get notification chages. My code like this ContactsContentObserver cco = new ContactsContentObserver(handler); ContentResolver contentResolver = getContentResolver(); contentResolver.registerContentObserver(RawContacts.CONTENT_URI, true, cco); } private class ContactsContentObserver extends ContentObserver { public ContactsContentObserver(Handler h) { super(h); } public void onChange(boolean selfChange) { System.out.println("##########SOMEBODAY CHANGED ANYTHING AT THE CONTACTS"); Toast.makeText(getApplication(),"####Updated####",Toast.LENGTH_LONG).show(); } .... Adv thanks. u can contact on [email protected]

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  • Is it possible to build a JPA entity by extending a POJO?

    - by Freiheit
    Lets say I have the following POJO: public class MyThing { private int myNumber; private String myData; //assume getter/setter methods } Is it now possible to extend this POJO as a JPA entity? @Entity @Table(name = "my_thing") public class MyThingEntity extends MyThing implements Serializable { @Column(name = "my_number") //????????? @Column(name = "my_data") //???????? } I want to keep the POJO separate from the JPA entity. The POJO lives in a different project and is often used without a persistence layer, my project wants to persist it in a database and do so without the overhead of mapping from a POJO to an entity and back. I understand that JPA entities are POJOs, but in order to use it I would have to include a library that implements javax.persistence and the other projects using the same base object have no use for a persistence layer. Is this possible? Is this a good idea?

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  • C# Memoization of functions with arbitrary number of arguments

    - by Lirik
    I'm trying to create a memoization interface for functions with arbitrary number of arguments, but I'm failing miserably. The first thing I tried is to define an interface for a function which gets memoized automatically upon execution: class EMAFunction:IFunction { Dictionary<List<object>, List<object>> map; class EMAComparer : IEqualityComparer<List<object>> { private int _multiplier = 97; public bool Equals(List<object> a, List<object> b) { List<object> aVals = (List<object>)a[0]; int aPeriod = (int)a[1]; List<object> bVals = (List<object>)b[0]; int bPeriod = (int)b[1]; return (aVals.Count == bVals.Count) && (aPeriod == bPeriod); } public int GetHashCode(List<object> obj) { // Don't compute hash code on null object. if (obj == null) { return 0; } // Get length. int length = obj.Count; List<object> vals = (List<object>) obj[0]; int period = (int) obj[1]; return (_multiplier * vals.GetHashCode() * period.GetHashCode()) + length;; } } public EMAFunction() { NumParams = 2; Name = "EMA"; map = new Dictionary<List<object>, List<object>>(new EMAComparer()); } #region IFunction Members public int NumParams { get; set; } public string Name { get; set; } public object Execute(List<object> parameters) { if (parameters.Count != NumParams) throw new ArgumentException("The num params doesn't match!"); if (!map.ContainsKey(parameters)) { //map.Add(parameters, List<double> values = new List<double>(); List<object> asObj = (List<object>)parameters[0]; foreach (object val in asObj) { values.Add((double)val); } int period = (int)parameters[1]; asObj.Clear(); List<double> ema = TechFunctions.ExponentialMovingAverage(values, period); foreach (double val in ema) { asObj.Add(val); } map.Add(parameters, asObj); } return map[parameters]; } public void ClearMap() { map.Clear(); } #endregion } Here are my tests of the function: private void MemoizeTest() { DataSet dataSet = DataLoader.LoadData(DataLoader.DataSource.FROM_WEB, 1024); List<String> labels = dataSet.DataLabels; Stopwatch sw = new Stopwatch(); IFunction emaFunc = new EMAFunction(); List<object> parameters = new List<object>(); int numRuns = 1000; long sumTicks = 0; parameters.Add(dataSet.GetValues("open")); parameters.Add(12); // First call for(int i = 0; i < numRuns; ++i) { emaFunc.ClearMap();// remove any memoization mappings sw.Start(); emaFunc.Execute(parameters); sw.Stop(); sumTicks += sw.ElapsedTicks; } Console.WriteLine("Average ticks not-memoized " + (sumTicks/numRuns)); sumTicks = 0; // Repeat call for (int i = 0; i < numRuns; ++i) { sw.Start(); emaFunc.Execute(parameters); sw.Stop(); sumTicks += sw.ElapsedTicks; } Console.WriteLine("Average ticks memoized " + (sumTicks/numRuns)); } The performance is confusing me... I expected the memoized function to be faster, but it didn't work out that way: Average ticks not-memoized 106,182 Average ticks memoized 198,854 I tried doubling the data instances to 2048, but the results were about the same: Average ticks not-memoized 232,579 Average ticks memoized 446,280 I did notice that it was correctly finding the parameters in the map and it going directly to the map, but the performance was still slow... I'm either open for troubleshooting help with this example, or if you have a better solution to the problem then please let me know what it is.

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  • Zend_Test: No default module defined for this application

    - by jiewmeng
    UPDATE 23 Dec I had the problem where Zend Framework complains about "No default module defined for this application". I didn't use Modules and the main app works fine. I finally solved the problem with the help from weierophinney.net Your bootstrap needs to minimally set the controller directory -- do a call to $this->frontController->addControllerDirectory(...) in your appBootstrap() method. I didn't in my example, as my Initialization plugin does that sort of thing for me. The problem is solved by adding the below to setUp() $this->getFrontController()->setControllerDirectory(APPLICATION_PATH . '/controllers'); But now, I have afew other questions: 1. Why does that value not get initialized by application.ini? In application.ini, I have [production] resources.frontController.controllerDirectory = APPLICATION_PATH "/controllers" [testing : production] // didn't change anything regarding modules nor controllers 2. I tried setting the controllerDirectory in bootstrap.php of my unit test, but it does not work $front = Zend_Controller_Front::getInstance(); $front->setControllerDirectory(APPLICATION_PATH . '/controllers'); The only way that works is using setUp(). Why is that? END UPDATE 23 Dec I am getting the above error when unit testing my controller plugins. I am not using any modules. in my bootstrap.php for unit testing, I even tried adding $front = Zend_Controller_Front::getInstance(); $front->setDefaultModule('default'); But it still does not work. Anyways my bootstrap.php looks like this UPDATE: the error looks something like There were 2 errors: 1) Application_Controller_Plugin_AclTest::testAccessToUnauthorizedPageRedirectsToLogin Zend_Controller_Exception: No default module defined for this application D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:391 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:204 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:244 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Front.php:954 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Test\PHPUnit\ControllerTestCase.php:205 D:\Projects\Tickle\tests\application\controllers\plugins\aclTest.php:6 2) Application_Controller_Plugin_AclTest::testAccessToAllowedPageWorks Zend_Controller_Exception: No default module defined for this application D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:391 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:204 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Dispatcher\Standard.php:244 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Controller\Front.php:954 D:\ResourceLibrary\Frameworks\PHPFrameworks\Zend\Test\PHPUnit\ControllerTestCase.php:205 D:\Projects\Tickle\tests\application\controllers\plugins\aclTest.php:16 UPDATE I tried adding public function setUp() { $front = Zend_Controller_Front::getInstance(); $front->setDefaultModule('default'); } then 1 part works. public function testAccessToUnauthorizedPageRedirectsToLogin() { // this fails with exception "Zend_Controller_Exception: No default module defined for this application" $this->dispatch('/projects'); $this->assertController('auth'); $this->assertAction('login'); } public function testAccessToAllowedPageWorks() { // this passes $auth = Zend_Auth::getInstance(); $authAdapter = new Application_Auth_Adapter('jiewmeng', 'password'); $auth->authenticate($authAdapter); $this->dispatch('/projects'); $this->assertController('projects'); $this->assertAction('index'); }

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  • Is it possible to gzip and upload this string to Amazon S3 without ever being written to disk?

    - by BigJoe714
    I know this is probably possible using Streams, but I wasn't sure the correct syntax. I would like to pass a string to the Save method and have it gzip the string and upload it to Amazon S3 without ever being written to disk. The current method inefficiently reads/writes to disk in between. The S3 PutObjectRequest has a constructor with InputStream input as an option. import java.io.*; import java.util.zip.GZIPOutputStream; import com.amazonaws.auth.PropertiesCredentials; import com.amazonaws.services.s3.AmazonS3; import com.amazonaws.services.s3.AmazonS3Client; import com.amazonaws.services.s3.model.PutObjectRequest; public class FileStore { public static void Save(String data) throws IOException { File file = File.createTempFile("filemaster-", ".htm"); file.deleteOnExit(); Writer writer = new OutputStreamWriter(new FileOutputStream(file)); writer.write(data); writer.flush(); writer.close(); String zippedFilename = gzipFile(file.getAbsolutePath()); File zippedFile = new File(zippedFilename); zippedFile.deleteOnExit(); AmazonS3 s3 = new AmazonS3Client(new PropertiesCredentials( new FileInputStream("AwsCredentials.properties"))); String bucketName = "mybucket"; String key = "test/" + zippedFile.getName(); s3.putObject(new PutObjectRequest(bucketName, key, zippedFile)); } public static String gzipFile(String filename) throws IOException { try { // Create the GZIP output stream String outFilename = filename + ".gz"; GZIPOutputStream out = new GZIPOutputStream(new FileOutputStream(outFilename)); // Open the input file FileInputStream in = new FileInputStream(filename); // Transfer bytes from the input file to the GZIP output stream byte[] buf = new byte[1024]; int len; while ((len = in.read(buf)) > 0) { out.write(buf, 0, len); } in.close(); // Complete the GZIP file out.finish(); out.close(); return outFilename; } catch (IOException e) { throw e; } } }

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  • In ASP.NET MVC, why can't I inherit from "MyCustomView" without specifying the full type name?

    - by Seth Petry-Johnson
    In my MVC apps I normally declare a base view type that all of my views inherit from. I get a parser error when I specify Inherits="MyView" in my Page declaration, but not if I specify Inherits="MyApp.Web.Views.MyView". Strangely enough, it also works fine if I specify Inherits="MyView<T> (where T is any valid type). Why can I specify a strongly typed view without the full type name, but not a generic view? My base view class is declared like this: namespace MyApp.Web.Views { public class MyView : MyView<object> { } public class MyView<TModel> : ViewPage<TModel> where TModel : class { } }

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  • Invalid character in a Base-64 string when Concatenating and Url encoding a string

    - by Rob
    I’m trying to write some encryption code that is passed through a Url. For the sake of the issue I’ve excluded the actual encryption of the data and just shown the code causing the problem. I take a salt value, convert it to a byte array and then convert that to a base64 string. This string I concatenate to another base64 string (which was previously a byte array). These two base64 strings are then Url encoded. Here’s my code... using System; using System.Collections.Generic; using System.Linq; using System.Text; using System.Security.Cryptography; using System.IO; using System.Web; class RHEncryption { private static readonly Encoding ASCII_ENCODING = new System.Text.ASCIIEncoding(); private static readonly string SECRET_KEY = "akey"; private static string md5(string text) { return BitConverter.ToString(new MD5CryptoServiceProvider().ComputeHash(ASCII_ENCODING.GetBytes(text))).Replace("-", "").ToLower(); } public string UrlEncodedData; public RHEncryption() { // encryption object RijndaelManaged aes192 = new RijndaelManaged(); aes192.KeySize = 192; aes192.BlockSize = 192; aes192.Mode = CipherMode.CBC; aes192.Key = ASCII_ENCODING.GetBytes(md5(SECRET_KEY)); aes192.GenerateIV(); // convert Ivector to base64 for sending string base64IV = Convert.ToBase64String(aes192.IV); // salt value string s = "maryhadalittlelamb"; string salt = s.Substring(0, 8); // convert to byte array // and base64 for sending byte[] saltBytes = ASCII_ENCODING.GetBytes(salt.TrimEnd('\0')); string base64Salt = Convert.ToBase64String(saltBytes); //url encode concatenated base64 strings UrlEncodedData = HttpUtility.UrlEncode(base64Salt + base64IV, ASCII_ENCODING); } public string UrlDecodedData() { // decode the url encode string string s = HttpUtility.UrlDecode(UrlEncodedData, ASCII_ENCODING); // convert back from base64 byte[] base64DecodedBytes = null; try { base64DecodedBytes = Convert.FromBase64String(s); } catch (FormatException e) { Console.WriteLine(e.Message.ToString()); Console.ReadLine(); } return s; } } If I then call the UrlDecodedData method I get a “Invalid character in a Base-64 string” exception. This is generated because the base64Salt variable contains an invalid character (I’m guessing a line termination) but I can’t seem to strip it off.

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  • VMWare Setup with 2 Servers and a DAS (DELL MD3220)

    - by Kumala
    I am planning to use a VMWare based setup consisting of two VMWare servers (2 CPU, 256GB Memory) and a DAS (DELL MD3220 with 24x900GB disks). The virtual machines will be half running MS SQL databases (Application, Sharepoint, BI) and the other half of the VM will be file services, IIS. To enhance the capacity of the storage, we'll be adding a MD1220 enclosure with another 24x900GB to the MD3220. Both DAS will have 2 controllers. Our current measured IOPS is 1000 IOPS average, 7000 IOPS peak (those happen maybe twice per hour). We are in the planning phase now and are looking at the proper setup of the disks. The intention is to setup up both DAS one of the DAS with RAID 10 only and the other DAS with RAID 5. That will allow us to put the applications on the DAS that supports the application performance needs best. Question is how best to partition the two DASs to get best possible IOPS/MBps, each DAS will have to have 2 hot spares? For the RAID 5 Setup: Generally speaking, would it be better to have one single disk group across all 22 disks (24 - 2 hot spares) with both controllers assigned to the one disk group or is it better to have 2 disk groups each 11 disks, assigned to one of the two controllers? Same question for the RAID 10 setup: The plan is: 2 disks for logs (Raid 1), 2 Hotspare and 20 disks for RAID 10. Option 1: 5 * 4 disks (RAID 10), with two groups assigned to 1 controller and 3 groups to the other controller Option 2: One large RAID 10 across all the disks and have both controllers assigned to the same group? I would assume that there is no right or wrong, but it all depends very much on the specific application behaviour, so I am looking for some general ideas what the pros and cons are of the different options. IF there are other meaningful options, feel free to propose them.

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  • How do I migrate a ManyToOne to a ManyToMany relationship in Hibernate?

    - by spderosso
    I have a instance field of a class X that is mapped using Hibernate as a Many to One relationship. E.g: public class X{ ... @ManyToOne(optional=false) private Y iField; ... } That is correctly working with a particular schema. I know want to change this instance field iField to a List and a Many to Many relationship. public class X{ ... @ManyToMany(optional=false) private List<Y> iField; ... } What steps should I follow? Do I have to change the schema? in which way? In case you need more info let me know. Thanks!

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  • Html.DescriptionFor<T>

    - by Stacey
    I'm trying to emulate the Html Helper for "LabelFor" to work with the [Description] Attribute. I'm having a lot of trouble figuring out how to get the property from the helper though. This is the current signature... class Something { [Description("Simple Description")] [DisplayName("This is a Display Name, not a Description!")] public string Name { get; set; } } public static MvcHtmlString DescriptionFor<TModel, TValue>(this HtmlHelper<TModel> html, Expression<Func<TModel, TValue>> expression);

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  • Android serialization: ImageView

    - by embo
    I have a simple class: public class Ball2 extends ImageView implements Serializable { public Ball2(Context context) { super(context); } } Serialization ok: private void saveState() throws IOException { ObjectOutputStream oos = new ObjectOutputStream(openFileOutput("data", MODE_PRIVATE)); try { Ball2 data = new Ball2(Game2.this); oos.writeObject(data); oos.flush(); } catch (Exception e) { Log.e("write error", e.getMessage(), e); } finally { oos.close(); } } But deserealization private void loadState() throws IOException { ObjectInputStream ois = new ObjectInputStream(openFileInput("data")); try { Ball2 data = (Ball2) ois.readObject(); } catch (Exception e) { Log.e("read error", e.getMessage(), e); } finally { ois.close(); } } fail with error: 03-24 21:52:43.305: ERROR/read error(1948): java.io.InvalidClassException: android.widget.ImageView; IllegalAccessException How deserialize object correctly?

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  • Is this a well known design pattern? what is it's name

    - by GenEric35
    Hi I have seen this often in code, but when I speak of it i don't know the name of such 'pattern' I have a method with 2 arguments that calls an overloaded method that has 3 arguments and intentionality sets the 3rd one to empty string. public DoWork(string name, string phoneNumber) { CreateContact(name, phoneNumber, string.Empty) } public DoWork(string name, string phoneNumber, string emailAddress) { //do the work } The reason I'm doing this is I to not duplicate code, and allow the existing callers to still call the method that has only 2 parameters. I have associate a few tags to this question, but it probably fit in more categories of questions. Is this a pattern, and does it have a name?

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  • newbie: Rails on remote Apache server not displaying index.html.erb

    - by paracaudex
    I played around with Rails on my laptop (running Linux + Apache + MySQL) and had no trouble getting the Getting Started with Rails tutorial to work locally. Now I'm trying the same thing at work on a remote Mac OS X + Apache server, and things aren't quite so rosy. I typed rails blog -d mysql to create a directory called blog in /Library/WebServer/Documents/mydirectory. The trouble is, if I go to server.com/mydirectory/public, I get the public/index.html in my browser. But, I don't get this file if I go to server.com/mydirectory/. Instead, I get a 403 error. Also, when I: script/generate controller home index to create: app/views/home/index.html.erb I am unable to view this file, whether I go to server.com/mydirectory/home/index, or if I add a new line (map.root :controller => "home") to config/routes.rb and go to server.com/mydirectory. Am I missing something really obvious about Apache and Rails?

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  • Issue while access contacts of android

    - by Rishabh
    I am new for android development. I am trying read and write contacts to android addressbook. I tried following line of code for write name into android public class SecondApp extends Activity { /** Called when the activity is first created. */ @Override public void onCreate(Bundle savedInstanceState) { super.onCreate(savedInstanceState); setContentView(R.layout.main); ContentValues values = new ContentValues(); values.put(Contacts.People.NAME, "Rishabh"); ContentResolver cr = getContentResolver(); Uri uri = cr.insert(People.CONTENT_URI, values); but i am getting "The application has stopped unexpectedly. Please try again" message. what is wrong in it ? How can i access contacts of android ?

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  • On reference_wrapper and callable objects

    - by Nicola Bonelli
    Given the following callable object: struct callable : public std::unary_function &lt;void, void&gt; { void operator()() const { std::cout << "hello world" << std::endl; } }; a std::tr1::reference_wrapper< calls through it: callable obj; std::tr1::ref(obj)(); Instead, when the operator() accepts an argument: struct callable : public std::unary_function &lt;int, void&gt; { void operator()(int n) const { std::cout << n << std::endl; } }; std::tr1::bind accepts a reference_wrapper to it as a callable wrapper... callable obj; std::tr1::bind( std::tr1::ref(obj), 42 )(); but what's wrong with this? std::tr1::ref(obj)(42);

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  • WCF DataContract deserialization of complex types

    - by Meidan Alon
    Hi, I have a service that returns a collection of MyClass objects. If all of the MyClass instances have null in MyClass2Reference then everything works fine. Otherwise, I get a "Connection reset" error on the client side. What am I doing wrong? Nevrmind: was a problem with NHibernate lazy proxy objects. [DataContract] public MyClass { [DataMember] int ID; [DataMember] MyClass2 MyClass2Reference; } [DataContract] public MyClass2 { [DataMember] int ID; [DataMember] string Name; }

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  • Multithreading and booleans

    - by Ikaso
    Hi Everyone, I have a class that contains a boolean field like this one: public class MyClass { private boolean boolVal; public boolean BoolVal { get { return boolVal; } set { boolVal = value; } } } The field can be read and written from many threads using the property. My question is if I should fence the getter and setter with a lock statement? Or should I simply use the volatile keyword and save the locking? Or should I totally ignore multithreading since getting and setting boolean values atomic? regards,

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  • both ssl and non-ssl on single port

    - by Zulakis
    I would like to make my apache2 webserver serve both http and https on the same port. With the different method i tried it was either not working on http or on https.. How can I do this? Update: If I enable SSL and then visit the with http I get page like this: <!DOCTYPE HTML PUBLIC "-//IETF//DTD HTML 2.0//EN"> <html><head> <title>400 Bad Request</title> </head><body> <h1>Bad Request</h1> <p>Your browser sent a request that this server could not understand.<br /> Reason: You're speaking plain HTTP to an SSL-enabled server port.<br /> Instead use the HTTPS scheme to access this URL, please.<br /> <blockquote>Hint: <a href="https://server/"><b>https://server/</b></a></blockquote></p> <hr> <address>Apache/2.2.9 (Debian) PHP/5.2.6-1+lenny16 with Suhosin-Patch mod_ssl/2.2.9 OpenSSL/0.9.8g Server at server Port 443</address> </body></html> Because of this, it seems very much possible to have both http and https on the same port. A first step would be to change this default-page so it would present a 301-Moved header. Update2: According to this, it is possible. Now, the question is just how to configure apache to do it.

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  • Java: conditional initialization?

    - by HH
    Ruby has conditional initialization. Apparently, Java does not or does it? I try to write more succintly, to limit the range as small as possible. import java.io.*; import java.util.*; public class InitFor{ public static void main(String[] args){ for(int i=7,k=999;i+((String h="hello").size())<10;i++){} System.out.println("It should be: hello = "+h); } } Errors Press ENTER or type command to continue InitFor.java:8: ')' expected for(int i=7,k=999;i+((String h="hello").size())<10;i++){} ^

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  • Displaying untrusted HTML using PHP

    - by esryl
    I have a read a number of excellent questions and answers today about dealing with user input. I am now using htmlspecialchars() to display user data in the create/edit forms (but accepting the raw input via prepared PDO statements into my database). The main question I know have is, what do you do when you are allowing the user to submit HTML which will then be displayed to the public. Obviously htmlspecialchars() is no longer suitable as it just encodes the tags and renders the content useless for purpose. My application is currently accepting HTML from an admin for product descriptions. This would allow a malicious admin to inject potentially unsafe data into public facing pages. How do people cope with this?

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  • Subclassing QGraphicsItemGroup

    - by onurozcelik
    Hi everyone I have system that has classes derived from QGraphicsWidget. I manage derived class objects in layouts on QGraphicsScene. Now I need a compound item that contain two or more QGraphicsWidget in it and also I need to put that item inside my layout. So I choose QGraphicsItemGroup and write I class like this. class CompositeItem : public QGraphicsItemGroup,public QGraphicsLayoutItem { ... }; I only implemented sizeHint function again. When add CompositeItem instance to layout it does not shown. What may cause this? Where I made wrong?

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  • Trying to write a loop that uses an OutputStream to write to a text file.

    - by Steve McLain
    I'm not a java programmer, I'm a VB programmer. I am doing this as part of an assignment, however, I'm not asking for help on something assignment related. I'd like to figure out how to get the OutputStreamWriter to work properly in this instance. I just want to capture the values I'm generating and place them into a text document. The file is generated, but only one entry exists, not the 40 I'm expecting. I could do this in a heartbeat with VB, but java feels very strange to me right now. Your help is appreciated. Thanks, Steve Here's the code: public static void main(String[] args){ long start, end; double result,difference; try {//OutputStream code assistance from http://tutorials.jenkov.com/java-io/outputstreamwriter.html OutputStream outputStream = new FileOutputStream("c:\\Temp\\output1.txt"); Writer out = new OutputStreamWriter(outputStream); for(int n=1; n<=20; n++){ //Calculate the Time for n^2. start = System.nanoTime(); //Add code to call method to calculate n^2 result = mN2(n); end = System.nanoTime(); difference = (end - start); //Output results to a file out.write("N^2 End time: " + end + " Difference: " + difference + "\n"); out.close(); } } catch (IOException e){ } try { OutputStream outputStream = new FileOutputStream("c:\\Temp\\output1.txt"); Writer out = new OutputStreamWriter(outputStream); for(int n=1; n<=20; n++){ //Calculate the Time for 2^n. start = System.nanoTime(); //Add code to call method to calculate 2^n result = m2N(n); end = System.nanoTime(); difference = (end - start); //Output results to a file out.write("N^2 End time: " + end + " Difference: " + difference + "\n"); out.close(); } } catch (IOException e){ } } //Calculate N^2 public static double mN2(double n) { n = n*n; return n; } //Calculate 2N public static double m2N (double n) { n = 2*n; return n; }

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  • Implementing an interface using an asynchronous WCF service?

    - by John K.
    Hello, I am trying to figure out if it is possible to implement a .NET interface, where the interface method has to return something and you are implementing that particular interface method with an asynchronous WCF service? Hopefully you should already see the issue I am encountering. Here is the interface: public interface IDataService { IDataServiceResponse SendDataRequest(); } IDataServiceResponse is supposed to represent a simple container that holds the result of my asynchronous WCF callback. Here is the code snippet where I am implementing the interface method, SendDataRequest() public IDataServiceResponse SendDataRequest() { InitializeDataServiceParameters(); // Call the web service asynchronously, here.... _client.BeginQueryJobs(_parameters, DataServiceQueryCallBack, _client); // How do I return _dataServiceResponse, if I am calling the WCF service // asynchronously?? return _dataServiceResponse; } And the callback method signature: void DataServiceQueryCallBack(IAsyncResult result) { // ... implementation code } Thanks in advance, John

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  • Can I configure NUnit so that Debug.Fail doesn't show a message box when I run my tests?

    - by panamack
    I have this property: public SubjectStatus Status { get { return status; } set { if (Enum.IsDefined(typeof(SubjectStatus), value)) { status = value; } else { Debug.Fail("Error setting Subject.Status", "There is no SubjectStatus enum constant defined for that value."); return; } } } and this unit test [Test] public void StatusProperty_StatusChangedToValueWithoutEnumDefinition_StatusUnchanged() { Subject subject = new TestSubjectImp("1"); // assigned by casting from an int to a defined value subject.Status = (SubjectStatus)2; Assert.AreEqual(SubjectStatus.Completed, subject.Status); // assigned by casting from an int to an undefined value subject.Status = (SubjectStatus)100; // no change to previous value Assert.AreEqual(SubjectStatus.Completed, subject.Status); } Is there a way I can prevent Debug.Fail displaying a message box when I run my tests, but allow it to show me one when I debug my application?

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