Search Results

Search found 16365 results on 655 pages for 'auto login'.

Page 515/655 | < Previous Page | 511 512 513 514 515 516 517 518 519 520 521 522  | Next Page >

  • recommend a server side technology for gwt (beginner)

    - by user486503
    hi all ! I am developing a gwt project and am looking for an appropriate server side technology. it should support be open source and support user login (and not using openID...) with password recovery etc it seems that the de-facto standard would be spring + hibernate. however, I am unfamiliar with neither of them and understand that the learning curve (especially for spring) is very high. gwt was quite easy to learn using GOOG's excellent online tutorials but the spring equivalent seem to impose lots of configuration files and deeper understanding of its internals. so I am looking for a simpler server side technology to deploy my gwt app. I am definitely prepared to learn a new framework if necessary but not something that would take me 2 months just to understand the fundamentals... any ideas...?

    Read the article

  • Password remember does not work properly

    - by sweetsecret
    On the website I am working on it has been deployed but the problem I am facing is that when I enter a username and password and click on the check box to remember...It remembers the password for sometime.. wen I login in after 5 or 10 minutes it remembers the password but aftr a long period of time like about 2hours it forgets the username and password and i have to type it in all over again... this dint used to happen with the old server as even I could sign in and it remembered the password the next day until i log off... what can be the reason The session state im using is:

    Read the article

  • Creating a PHP web app to allow users to vote on submissions - How can I minimize abuse.

    - by sibliant
    Hi Community, I've only written a few small php web apps and I'm throwing code together right now to allow for users to submit short stories. these stories will display and allow others to vote them up. The winner receives something rather valuable and I'm paranoid people are going to try to manipulate it. Debian / Apache / PHP 5.2 / jquery users are not required to login / authenticate. users can vote multiple stories up but only once for each story Is it as simple as tagging each story with an IP address and not counting other submissions from that IP? Thanks for any advise.

    Read the article

  • Session variables return completely after unsetting.

    - by RemiX
    I have a script that should log the user out of the site. It unsets all $_SESSION and $_COOKIE variables related to the login data of the user. But somehow, it seems impossible to log out. I checked the $_SESSION array at the end of the logout script, and at the beginning of each page. At the end of the logout script it says 'array()', but when I click the home button - or any link on the site - the full session data is back again and I don't know where it comes from. This is how I try to unset the session data: unset($_SESSION); unset($_COOKIE["usid"]); unset($_COOKIE["pw"]); unset($_COOKIE["adm"]); -- I don't know how to put it on different lines, but it's not that hard to read. Why do these data keep coming back?!

    Read the article

  • How to automate IE/Firefox to download some files from a https: website with Javascript links?

    - by Horace Ho
    Some of my users download several pdf files from an internet website regularly. They'd like to automate the process to save a few minutes every day, and most importantly, to minimize errors. I tried mechanize but failed as mechanize does not process javascripts. Since the download links in the remote site are all triggered by javescript, I am looking for solutions to automate the browser itself. Any recommendations? https remote server login and search are FORM POST file download link are JavaScripts on win32 IE or Firefox thanks!

    Read the article

  • How to start SQL Server in a remote machine using code from Delphi?

    - by MLB
    Hi there: I am developing an application (Delphi 7, windows XP) that uses a connection to a remote SQL Server. Sometimes, that server is down, and I want to do something to start it. I was trying to start SQL Server in a local context, and it was fine, it worked... But the point is that I have to start it up from a remote machine. I can see SQL Server status from a remote server, but I can't start it up... Maybe it gets problems because of user and password, but where to specify the login to the remote machine? Do you have any idea to do this??? I am sorry about my English. Thanks.

    Read the article

  • oomla.. GoDaddy.. FileZilla ... :S

    - by user282659
    have created a a website in my localhost computer using Joomla Now I want to launch the site into the web.. So I brought a domain from GoDaddy.com .. Im a newbie into this and I was using This Tutorial in order to set up the website... Now Im Stuck in the Step 08 Which asks to upload some files into the web host directory... I used FileZilla as my FTP Client .. When I give the host name and the password, Port number as 21 and try to login it says.. Connection Timed Out.. and says.. Could Not Connect to server . Plase explain m on how to use the FileZilla.. And Solve th above problem ..

    Read the article

  • Advice regarding Java frameworks [closed]

    - by Mixiul
    I am in the process of creating a website/phone application using JQuery Mobile and PhoneGap. I am hoping to add openID support so users can login in with pre-existing accounts. It will be necessary for me to have a database with a few tables to enable me to implement all the core functionality I desire. I haven't really had much experience with frameworks before, the closest thing I have done to this is create a basic website using php that connected to a MySql database stored on the machine that hosted the apache webserver. The interaction with the database won't be complex. I am required to use a java framework for the backend of my application. My question is which java framework is most suitable (flexible and straight forward to learn)? Any advice you guys can provide is greatly appreciated. Thanks

    Read the article

  • How to integrate with google Calendar?

    - by Sumithran
    Hi all. I am new to java. I need to integrate with google calendar form my java allpication.But it gives the Exception message : Error connecting with login URI.I use the following code for connect with google. CalendarService myService = new CalendarService("CalendarService"); myService.setUserCredentials("[email protected]", "Kdfdfderekra"); URL feedUrl = new URL("http://www.google.com/calendar/feeds/default/allcalendars/full"); CalendarFeed resultFeed = myService.getFeed(feedUrl, CalendarFeed.class); System.out.println("Your calendars:"); for (int i = 0; i < resultFeed.getEntries().size(); i++) { CalendarEntry entry = resultFeed.getEntries().get(i); System.out.println("\t" + entry.getTitle().getPlainText()); }

    Read the article

  • How to persist a cookie?

    - by user246114
    Hi, I am creating a cookie in a jsp script, which is located at: www.myproject.com/login/index.jsp if I restart the browser and navigate there, all works well, I can see the cookie persist. If I navigate to: www.myproject.com I am not seeing the cookie. Do I need to set something in the cookie path or domain to make the cookie visible to the entire [myproject.com] domain (I just want to access the cookie from whatever sub path the user may be on). I am creating the cookie like: Cookie c = new Cookie("thisisatest", "foo"); c.setMaxAge(60 * 24 * 3600); response.addCookie(c); Thanks

    Read the article

  • how to run frame one after the other

    - by user1758401
    I am developing an application where the valid user gets access to the main application. But a problem arises when I run main class. The LoginFrame and Main(Editor.java) Frame start simultaneously. I want to first validate the user and then direct the user to the main application. I am calling Loginform.java from my main application (i.e Editor.java) java.awt.EventQueue.invokeLater(new Runnable() { public void run() { new Login().setVisible(true); { Editor x = new Editor(); x.setVisible(true); } } });

    Read the article

  • UITableView not showing background image.

    - by K.Honda
    I have a uitableview with 2 cells (custom tableviewcells) and a button for login. I made them programmatically. Now I want to put a background image behind the 2 custom cells and the button. I went into IB and put the image view on top of the tableview and then put a picture on it which I want as the background. Then I went into viewDidLoad and put this bit of code tblSimpleTable.backgroundColor = [UIColor clearColor]; to clear the tableviews background colour. It now looks like this: But the background does not appear. Does anyone know how to fix this? Thanks.

    Read the article

  • if else-if making code look ugly any cleaner solution?

    - by Vishal
    I have around 20 functions (is_func1, is_fucn2, is_func3...) returning boolean I assume there is only one function which returns true and I want that! I am doing: if is_func1(param1, param2): # I pass 1 to following abc(1) # I pass 1 some_list.append(1) elif is_func2(param1, param2): # I pass 2 to following abc(2) # I pass 1 some_list.append(2) ... . . elif is_func20(param1, param2): ... Please note: param1 and param2 are different for each, abc and some_list take parameters depending on the function. The code looks big and there is repetition in calling abc and some_list, I can pull this login in a function! but is there any other cleaner solution? I can think of putting functions in a data structure and loop to call them.

    Read the article

  • Upload Image to Facebook Objective-C

    - by boopyman
    I'm currently trying to upload an image from my Mac application to Facebook. To do this, I'd like for the user to simply input his username and password, and to click a button. The only issue is, Facebook doesn't actually have an API for the Mac, it only has one for iOS. This shouldn't be a problem, except for the fact that to login, you must use a web view, something I'm not to keen on doing, since I'd like the interface to be two simple text fields. I've also looked into PHFacebook, a class I found online, but it also seems to utilize an NSWebView. I'm wondering if there's a security issue when you use text fields; indeed, it's slightly strange no available API offers this function ! So, to conclude, is it possible, or is there an API, that lets you upload an image and lets you provide the user's credentials through simple NSStrings?

    Read the article

  • Rails modeling for a user

    - by Trevor Hartman
    When building a rails app that allows a User to login and create data, is it best to setup a belongs_to :user association on every single model? For example, let's say a user can create Favorites, Colors and Tags. And let's say Favorites has_many :tags and Colors also has_many :tags. Is it still important for Tags to belong_to :user assuming the User is the only person who has authority to edit those tags? And a similar question along the same lines: When updating data in FavoritesController, I've come to the conclusion that you perform CRUD operations by always doing something like User.favorites.find(params[:id].update_attributes(param[:favorite]) so that they can definitely only update models that belong to them. Right?

    Read the article

  • Session Issue only in IE for an ASP .NET application

    - by Siva
    We have migrated our Asp .NET application from Windows 2000 server to Windows 2003 Server when we access the site from Internet explorer we are facing some cache issues like when we click on logout its redirecting to homepage instead of login page but when i try to navigate inside its not allowing me i.e. its throwing me the user id and password is wrong.. i am facing this issue only in IE if i access the same page from Firefox i am not gettiing these kind of issue.. Is this problem related to some IIS settings or some code change is required? please help me in solving this issue...

    Read the article

  • How to give friend access to git repository without giving command line access?

    - by Jack Humphries
    I have some git repositories running on my server and I would like to give a friend read/write access to one. That's simple: I add him as a user, give him SSH access, and change the permissions to the repository folder. Everything works fine; I'm able to clone the git repository using Xcode and change things (ssh://www.example.com/repo.git). However, I do not want him to have command line access. If I recall correctly, Github does not give command line access to those who SSH in. I'm using Snow Leopard Server. Is this more of a server issue or a git issue? Do you have any idea where to begin? Setting the user's Login Shell to none (as opposed to /bin/bash) cuts off access to everything.

    Read the article

  • Pagination, next page doesn`t display

    - by user1738013
    if I click page 2 that`s error: Not Found The requested URL /rank/GetAll/30 was not found on this server. My link is: http://localhost/rank/GetAll/30 Model: Rank_Model <?php Class Rank_Model extends CI_Model { public function __construct() { parent::__construct(); } public function record_count() { return $this->db->count_all("ranking"); } public function fifa_rank($limit, $start) { $this->db->limit($limit, $start); $query = $this->db->get("ranking"); if ($query->num_rows() > 0) { foreach ($query->result() as $row) { $data[] = $row; } return $data; } return false; } } ?> Controller: Rank <?php if ( ! defined('BASEPATH')) exit('No direct script access allowed'); class rank extends CI_Controller { function __construct() { parent::__construct(); $this->load->helper("url"); $this->load->helper(array('form', 'url')); $this->load->model('Rank_Model','',TRUE); $this->load->library("pagination"); } function GetAll() { $config = array(); $config["base_url"] = base_url() . "rank/GetAll"; $config["total_rows"] = $this->Rank_Model->record_count(); $config["per_page"] = 30; $config["uri_segment"] = 3; $this->pagination->initialize($config); $page = ($this->uri->segment(3)) ? $this->uri->segment(3) : 0; $data["results"] = $this->Rank_Model->fifa_rank($config["per_page"], $page); $data['errors_login'] = array(); $data["links"] = $this->pagination->create_links(); $this->load->view('left_column/open_fifa_rank',$data); } } View Open: open_fifa_rank <?php $this->load->view('mains/header'); $this->load->view('login/loggin'); $this->load->view('mains/menu'); $this->load->view('left_column/left_column_before'); $this->load->view('left_column/menu_left'); $this->load->view('left_column/left_column'); $this->load->view('center/center_column_before'); $this->load->view('left_column/fifa_rank'); $this->load->view('center/center_column'); $this->load->view('right_column/right_column_before'); $this->load->view('login/zaloguj'); $this->load->view('right_column/right_column'); $this->load->view('mains/footer'); ?> and View: fifa_rank <table> <thead> <tr> <td>Pozycja</td> <td>Kraj</td> <td>Punkty</td> <td>Zmiana</td> </tr> </thead> <?php foreach($results as $data) {?&gt; <tbody> <tr> <td><?php print $data->pozycja;?></td> <td><?php print $data->kraj;?></td> <td><?php print $data->punkty;?></td> <td><?php print $data->zmiana;?></td> </tr> <?php } ?> </tbody> </table> <p><?php echo $links; ?></p> Maybe you know where is my problem? Now I know where is my problem. In first page I have link: http://localhost/index.php/rank/GetAll But on the next: http://localhost/rank/GetAll/30 In secend link, I don`t have index.php. How can I fix it?

    Read the article

  • Prism : Add a window in a region

    - by esylvestre
    Hi, I'm new working with Prism with WPF, and I have a question which I can't find answer. Why it is impossible to add a window in a Region ? I can understand there's a good reason, so I will need another solution to my problem. It is quite simple, I got a LoginView (Window) which I want to appear first. For the previous reason, in my Region, I added a MainView (UserControl) where I just show my LoginView on the Loaded event. The problem if the user quit the application or if he cancels his login, the MainView is still showing up. It seems a stupid problem, but I can't find a smart solution. Thanks for your time.

    Read the article

  • Integrate existing Spring based web application with a CMS

    - by anne_developer
    We have stable spring based (spring 2.x) web application. We have a new requirement which is our data entry operators should be able to login to some kind of an admin module and simply change the text in the web pages, change the color etc. I have seen PHP based CMS’s that allows authorized user to change the content in WYSIWYG manner. If anyone of you knows such open source Java CMS or third party application, which can facilitate such thing, please let me know. Please note: we cannot write our application from scratch. We are looking for pluggable component.

    Read the article

  • Rails gives wrong headers after upgrade 2.3.5 -> 2.3.8

    - by macsniper
    I just upgraded from rails 2.3.5 to rails 2.3.8, but now my redirects are not working properly. I get the following as the response HTTP Headers: HTTP/1.1 302 Moved Temporarily Date: Wed, 02 Jun 2010 09:40:39 GMT Content-Length: 93 Content-Type: text/html whereas I got previous: HTTP/1.1 302 Moved Temporarily Connection: close Date: Wed, 02 Jun 2010 09:41:18 GMT Set-Cookie: _session_id=<correct id>; path=/ Status: 302 Found Location: <correct url> Cache-Control: no-cache Server: Mongrel 1.1.5 Content-Type: text/html; charset=utf-8 Content-Length: 93 Anyone knows how to fix this? Despite the fact that the redirect is not working, the login-cookie is not set too (but I think, this is both related somehow). I have already tried to override redirect_to in order to set response.headers['Location'] etc., but they did not appear in the response.

    Read the article

  • c# save contents of IE browser as html

    - by herrow
    I have an Internet Explorer window open. The title of this window will always be "test123" how do I save the source of the contents of the window as an HTML file? Please note that the process should not be to open a URL and read the HTML into a variable. I absolutely HAVE TO do it the way I described since I need to login to a site to be able to view the HTML that I want to save. **if it makes it easier to do this through my winform and putting a webbrowser control on it, that is fine as well.

    Read the article

  • Unknown Space between 2 Container Divs

    - by Paul
    Im trying to determine why there would be space between 2 Containing Divs as shown, and I would appreciate any insight as to why this is occurring: The unknown space occurs between the mid-feature div (olive) and bottom-wrap div (orange) I have no heights set anywhere. I would like to see the orange div up against the olive div just above it. I can post all of the CSS, or you can FireBug this: www.davincispainting.com Here is all of the CSS: *{ margin:0; padding:0 } body { /*background: url("/images/blueback5.jpg") repeat-x scroll 0 0 transparent;*/ background-color: #9EB0C8; font-family: Arial,Helvetica,sans-serif; font-size: 62.5%; } #top-wrap { height: 126px; width: 940px; /*background-color: Yellow;*/ margin: 5px 0 0 0; } #head-logo { background: url("/images/logo3.png") no-repeat scroll 0 0 transparent; /*background-color: Green;*/ height: 126px; width: 214px; margin: 0px 0 0 58px; position: absolute; z-index: 100; } #submenu1 { border: 0 solid #000000; color: #FFFFFF; /*background-color:Green;*/ font-family: Arial,Impact,Impact5,Charcoal6,sans-serif; font-size: 1.6em; height: 35px; width: 155px; /*padding: 10px 0 0;*/ margin: 7px 0 0 774px; position: absolute; } #submenu2 { /*border: 0 solid #000000;*/ color: #FFFFFF; /*background-color:Blue;*/ font-family: Arial,Impact,Impact5,Charcoal6,sans-serif; font-size: 1.8em; text-align: right; height: 20px; width: 114px; margin: 30px 0 0 818px; /*padding: 5px 0 0;*/ } a.contact { background-image: url("/images/RapidButton2.png"); /*border: 1px solid #CCCCCC;*/ /*clear: both;*/ /*color: #FFFFFF;*/ display: block; font-size: 11px; /*margin-bottom: 1px;*/ /*padding: 3px 5px;*/ text-align: center; width: 165px; height: 27px; } a.contact:hover { background-image: url("/images/RapidButtonHov2.png"); } #navigation-primary { margin: 12px 0 0 276px; position: absolute; } #global-wrap { margin: 0 auto; text-align: left; width: 880px; overflow: hidden; } #global-inner { background: url("/images/main_bg.gif") repeat-y scroll 0 0 #E4EAEF; font-family: Arial; font-size: 1.2em; margin: 15px 0 55px 0; overflow: hidden; text-align: left; width: 880px; } #global-inner .topleft { background: url("/images/main_left_top_corner2.jpg") no-repeat scroll left top transparent; float: left; height: 9px; width: 9px; } #global-inner .topright { background: url("/images/main_right_top_corner2.jpg") no-repeat scroll right top transparent; float: right; height: 9px; width: 9px; } #global-inner .bottomleft { background: url("/images/main_left_bottom_corner.jpg") no-repeat scroll left bottom transparent; float: left; height: 9px; margin-top: -8px; /*margin: 776px 0 0 0;*/ width: 9px; } #global-inner .bottomright { background: url("/images/main_right_bottom_corner.jpg") no-repeat scroll right bottom transparent; float: right; height: 9px; margin-top: -8px; /*margin: 776px 0 0 0;*/ width: 9px; } #top-feature { height:330px; width: 848px; margin: 12px 0 0 16px; background: #E4EAEF; /*background: orange;*/ /*padding: 10px 0 0 10px;*/ position: absolute; text-align: left; } .slideshow { height: 330px; width: 848px; margin: 0 0 0 0; /*background: blue;*/ position: absolute; } #mid-feature { margin:350px 0 0 16px; width:848px; height:318px; background-color:Olive; position:relative; overflow:hidden; } #mid-featureleft { height:318px; width:552px; /*background-color:Purple;*/ float:left; position:relative; } #mid-featureright { height:318px; width:296px; background-color:#B9C1CC; /*background-color: red;*/ float:left; position: relative; } #mid-featureleft h1 { color: #FF0000; font-family: Arial,Helvetica,sans-serif; font-size: 2.1em; } #mid-featureleft .contentbox { padding:7px 7px 7px 7px; } #mid-featureleft p { color: #0C2A55; margin:0px 0 11px 0px; /*font-style:normal;*/ /*width: 97%;*/ /*font-size: .5em;*/ font-size: 12px; } #bottom-wrap { height:60px; width: 868px; margin: auto 0 0 6px; background:orange; position: relative; } #copyright { float: left; /*background-color:Teal;*/ width: 260px; height: 60px; text-align: left; position: absolute; margin:0 0 0 6px; } #bottom-logos { height:60px; width:596px; margin:0 0 0 267px; background: url("/images/logos2.png") no-repeat scroll 0 0 transparent; /*background-color:red;*/ position:absolute; }

    Read the article

  • Stopping users posting more than once

    - by user342391
    Before posting my form I am checking the database to see if there are any previous posts from the user. If there are previous posts then the script will kick back a message saying you have already posted. The problem is that what I am trying to achieve isn't working it all goes wrong after my else statement. It is also probable that there is an sql injection vulnerability too. Can you help??4 <?php include '../login/dbc.php'; page_protect(); $customerid = $_SESSION['user_id']; $checkid = "SELECT customerid FROM content WHERE customerid = $customerid"; if ($checkid = $customerid) {echo 'You cannot post any more entries, you have already created one';} else $sql="INSERT INTO content (customerid, weburl, title, description) VALUES ('$_POST[customerid]','$_POST[webaddress]','$_POST[pagetitle]','$_POST[pagedescription]')"; if (!mysql_query($sql)) { die('Error: ' . mysql_error()); } echo "1 record added"; ?>

    Read the article

< Previous Page | 511 512 513 514 515 516 517 518 519 520 521 522  | Next Page >