Boost Python : How to only expose the constructor of a class with virtual (pure & impure) methods
- by fallino
Hello, I'm a newbie with Boost::Python but I tried to search on the web to do so
I want to expose a 3rd party library to Python. One of the class of the library (.hpp) is composed of
a public constructor with arguments
a protected constructor and functions
various regular functions
various pure virtual functions
various non pure virtual functions
First, I did not succeed in building it without having errors about this protected constructor. I finally commented it. A first question would be :
Is there a way to exclude these protected functions since I don't want to expose them ?
(I know it's possible and easy with Py++, but I started without using it)
Then I tried to expose all of my functions, beginning with the pure virtual ones (commenting them all except one), which wasn't a success too
So I finally decided not to expose these virtual functions (which in fact seems logical...), but, here again, I didn't manage building it with a simple constructor with arguments (without no_init). So my second question is : Is there a way to exclude these virtual functions since I don't want to expose them ?
Sorry if it seems trivial but I didn't find anything explicit on the web and I need something rather explicit :).
Thanks in advance
