Reference and Value confusion
- by rgamber
Hi I read this question on Stack overflow, and tried to do an example.
I had the below code:
public static void main(String[] args){
int i = 5;
Integer I = new Integer(5);
increasePrimitive(i);
increaseObject(I);
System.out.println(i); //Prints 5 - correct
System.out.println(I); //Still prints 5
System.out.println(increaseObject2(I)); //Still prints 5
}
public static void increasePrimitive(int n){
n++;
}
public static void increaseObject(Integer n){
n++;
}
public static int increaseObject2(Integer n){
return n++;
}
Does the increaseObject print 5 because the value of reference is changing inside that function? Am I right?
I am confused why the increasedObject2 prints 5 and not 6.
Can anyone please explain?
