Search Results

Search found 41159 results on 1647 pages for 'incomplete type'.

Page 532/1647 | < Previous Page | 528 529 530 531 532 533 534 535 536 537 538 539  | Next Page >

  • Touch Screen Product Catalog for Retail Store

    - by Patrick
    I am a UI/UX designer and I would like to create kiosk type of app that would be a product catalog (help/suggestor) for customers in a retail store using a touch screen monitor (and computer). Something as simple as this: http://www.youtube.com/watch?v=aoH0u6YTTK4 This is what I would like it to do: 1st Screen (Main Menu): Pick a type of category (For example: Dog, Cat, Small Animal) 2nd Screen pick a sub-category of a main category (For example: Puppy, Adult, Senior - DOG) 3rd Screen pick a sub-category of previous sub-category (For example: Food, Healthy, Toys) Then it will display a list of all products with a picture, small description, and price. Thats it. So the point of the kiosk is to help customers find certain products that match their pet criteria. (Dog Puppy Healthy Dog Food) I am wondering what is the best solution: RIA (Flex/Air or Silveright) or flash/action script. I am not sure what is the best technology to use for the following benefits: user-experience (smoothness of touch screen actions) and fast development.

    Read the article

  • Image expire time

    - by Jens
    The google page speed tool recommends me to set 'Expires' headers for images etc. But what is the most efficient way to set an Expires header for an image? In now redirect all image requests to an imagehandler.php using htaccess: /* HTTP/1.1 404 Not Found, HTTP/1.1 400 Bad Request and content type detection stuff ... */ header( "Content-Type: " . $content_type ); header( "Cache-Control: public" ); header( "Last-Modified: ".gmdate("D, d M Y H:i:s", filemtime($path))." GMT"); header( "Expires: ". date("r",time() + (60*60*24*30))); readfile( $path ); But of course this adds extra loading time for my images on first request, and I was wondering if there was a better solution for this.

    Read the article

  • Reference variable to an object instantiated/initialized in another class in Java

    - by Alex
    The reason I'm asking is because I'm getting NullPointerException. I now this is very easy but I'm pretty new programming and find this a bit confusing. So say I have initialized an object in a class and want to access that same object from another class. Like now for instance I'm working on a small Chess game, in my model Game class I have an instance of Board, an object. Board, in turn, has an array of Squares. Square[][]. Game has board, board has Square[][]. Now if I want to access the Square[][] through the object board (in Game) of type Board. Do I just declare a variable with the same name and type or do I have to initialize it again? Board board OR Board board = new Board(); Note, I have already initialized board in the class Game so if I do it again, won't they be two totally different Board objects?

    Read the article

  • how does a research topic fit into a program?

    - by Asj
    My project is supposed to be about creating a program to help put a math test online. The program should generate questions that vary on each run of the test, and it should grade the test after someone takes it. (I found out recently that there's a system that can do some of the tasks already, but I don't think many people know how to use it) What type of research could be involved? I need to find a research article that relates to my project, and I'm having a lot of trouble figuring out what type of subject to look for.

    Read the article

  • How to use external static files with Django (serving external files once again)?

    - by Tomas Novotny
    Hi, even after Googling and reading all relevant posts at StackOverflow, I still can't get static files working in my Django application. Here is how my files look: settings.py MEDIA_ROOT = os.path.join(SITE_ROOT, 'static') MEDIA_URL = '/static/' urs.py from DjangoBandCreatorSite.settings import DEBUG if DEBUG: urlpatterns += patterns('', ( r'^static/(?P<path>.*)$', 'django.views.static.serve', {'document_root': 'static'} )) template: <script type="text/javascript" src="/static/jquery.js"></script> <script type="text/javascript"> I am trying to use jquery.js stored in directory "static". I am using: Windows XP Python 2.6.4 Django 1.2.3 Thank you very much for any help

    Read the article

  • jQuery ajax() and cakePHP urls

    - by Pickledegg
    I'm trying to call the 'tariff' action of my 'countries' controller using jQuery ajax() and pass it a country name in the following format: /countries/tariff/countryname however, with the following code ( set to GET ), it is calling this with the get '?' added: /countries/tariff/?countryname $(document).ready(function(){ $('#CountriesIndexForm select').change(function(){ $.ajax({ type: "GET", url: "/countries/tariff/", data: escape($(this).val()), success: function(html){ $(this).parent().next('div').html(html); } }); }); }); I understand its because the type: is set to GET, but is there a fix for this?

    Read the article

  • Urban Airship Tags issue

    - by Moshe
    I modified the alias sample code from: [request addRequestHeader: @"Content-Type" value: @"application/json"]; [request appendPostData:[[NSString stringWithFormat: @"{\"alias\": \"%@\"}", self.deviceAlias] dataUsingEncoding:NSUTF8StringEncoding]]; to: [request addRequestHeader: @"Content-Type" value: @"application/json"]; [request appendPostData:[[NSString stringWithFormat: @"{\"tags\": \"%@\"}", offsetStr] dataUsingEncoding:NSUTF8StringEncoding]]; offsetStr is a string containing a Timezone offset (which can be any number between -12 and 12). For some reason, Urban Airship is making each character of the string into its own tag. I've tried to substitute the - for a string neg with the same results. What's wrong?

    Read the article

  • Alert is showing two times. how to restrict?

    - by Dev
    function test(myObject, flag) { if ( (flag) || ((event.keyCode == 59) || (event.which == 59)) || ((event.keyCode == 44) || (event.which == 44))) {alert(myObject.value);} } function closeWin() {self.close();} --foaram name='test' --textaarea name='textareaName' cols='44' rows='3' onChange='test(this, true);' --onKeyPress='test(this);' onBlur='test(this, true);' ---inpaut type='text' name='textName' --inpaut type='button' name='buttonName' onclick='closeWin();' value='Cancel' --/foarm I have a problem: when input value(e.g: test;) into textareaName field, the test function is always run more one time. Please show me the way can run this only one time.

    Read the article

  • jquery ajax form success callback not being called

    - by Michael Merchant
    I'm trying to upload a file using "AJAX", process data in the file and then return some of that data to the UI so I can dynamically update the screen. I'm using the JQuery Ajax Form Plugin, jquery.form.js found at http://jquery.malsup.com/form/ for the javascript and using Django on the back end. The form is being submitted and the processing on the back end is going through without a problem, but when a response is received from the server, my Firefox browser prompts me to download/open a file of type "application/json". The file has the json content that I've been trying to send to the browser. I don't believe this is an issue with how I'm sending the json as I have a modularized json_wrapper() function that I'm using in multiple places in this same application. Here is what my form looks after Django templates are applied: <form method="POST" enctype="multipart/form-data" action="/test_suites/active/upload_results/805/"> <p> <label for="id_resultfile">Upload File:</label> <input type="file" id="id_resultfile" name="resultfile"> </p> </form> You won't see any submit buttons because I'm calling submit with a button else where and am using ajaxSubmit() from the jquery.form.js plugin. Here is the controlling javascript code: function upload_results($dialog_box){ $form = $dialog_box.find("form"); var options = { type: "POST", success: function(data){ alert("Hello!!"); }, dataType: "json", error: function(){ console.log("errors"); }, beforeSubmit: function(formData, jqForm, options){ console.log(formData, jqForm, options); }, } $form.submit(function(){ $(this).ajaxSubmit(options); return false; }); $form.ajaxSubmit(options); } As you can see, I've gotten desperate to see the success callback function work and simply have an alert message created on success. However, we never reach that call. Also, the error function is not called and the beforeSubmit function is executed. The file that I get back has the following contents: {"count": 18, "failed": 0, "completed": 18, "success": true, "trasaction_id": "SQEID0.231"} I use 'success' here to denote whether or not the server was able to run the post command adequately. If it failed the result would look something like: {"success": false, "message":"<error_message>"} Your time and help is greatly appreciated. I've spent a few days on this now and would love to move on.

    Read the article

  • How to pass some data to JQuery AJAX in CAKEPHP

    - by kwokwai
    Hi all, I am learning how to use JQuery to help check data availability. To start with it, I wrote a few lines of codes using cakePHP. I have written a function in a Controller for checking data input, and the URL is like this: http://www.mywebsite.com/controllers/action/avariable I was trying to pass the value in a Input TextBox field using the JQuery Ajax to the URL above,but I don't know why it is not working in passing a variable to the Controller's action. Could you help me out please? <Script language="javascript"> //<!-- $(document).ready(function(){ $(document).change(function() { var usr = $("#data\\[User\\]\\[name\\]").val(); if(usr.length >= 3){ $("#username").append('<span><img align="absmiddle" src="loader.gif" />Checking</span>'); $.ajax({ type: "POST", url: "http://www.mywebsite.com/controllers/action/", data: usr, success: function(msg){ if(msg == 'OK') { $("#username").append('<span><img align="absmiddle" src="accepted.png"/></span>'); } else { $("#username").append('<span>'+msg+'</span>'); } } }); } else { $("#username").append('<span>The username should have at least 3 characters.</span>'); } }); }); //--> </Script> <form name="adduser" id="adduser" method="post" action="/controllers/action2"> <table border=0 width="100%"> <tr> <td>Username</td> <td> <div id="username"> <input type=text name="data[User][name]" id="data[User][name]"> </div> </td> </tr> <tr> <td> <input type="submit" value="Send"> </td> </tr> </table> </form>

    Read the article

  • Where should I put interface?

    - by Roman
    I program a class in which I have a method which takes an callback object from an external software. At the moment Eclipse says that it does not know the type of the object I gave as argument (it is expectable since I do not specify this type, it's done by the external software). So, I think I need to write an interface for the object which I give as an argument to my method. In this respect I have two questions. Is it really so? Can I solve the mentioned problem in the mentioned way. If it is the case, where should I put this interface? In the same file where my class is? In the class? Outside of the class?

    Read the article

  • Can I send a POST form in an encoding other than of its body?

    - by Daziplqa
    Hi gang, I've Html page that looks like: <HTML> <meta http-equiv='Content-Type' content='text/html; charset=gb2312'> <BODY onload='document.forms[0].submit();'> <form name="form" method="post" action="/path/to/some/servlet"> <input type="hidden" name="username" value="??"> <!-- UTF-8 characters --> </form> </BODY> </HTML> As you can see, the content of this page is UTF-8, but I need to send it with GB2312 character encoding, as the servlet that I am sending this page to expects from me GB2312. Is this a valid scenario? Because in the servlet, I couldn't retive these chines characters back using a filter that sets the character encoding to GB2312!! Please help

    Read the article

  • Linking Post Title to Specific Page ID

    - by ThatMacLad
    I've created a form to update my websites homepage with content but I wanted to know how I could set it up so that a posts title links to a specific post ID. I'd also like to add a Read More link that directs anybody reading the blog to the correct post. Here is my PHP code: <html> <head> <title>Blog Name</title> </head> <body> <?php mysql_connect ('localhost', 'root', 'root') ; mysql_select_db ('tmlblog'); $sql = "SELECT * FROM php_blog ORDER BY timestamp DESC LIMIT 5"; $result = mysql_query($sql) or print ("Can't select entries from table php_blog.<br />" . $sql . "<br />" . mysql_error()); while($row = mysql_fetch_array($result)) { $date = date("l F d Y", $row['timestamp']); $title = stripslashes($row['title']); $entry = stripslashes($row['entry']); $password = $row['password']; $id = $row['id']; if ($password == 1) { echo "<p><strong>" . $title . "</strong></p>"; printf("<p>This is a password protected entry. If you have a password, log in below.</p>"); printf("<form method=\"post\" action=\"post.php?id=%s\"><p><strong><label for=\"username\">Username:</label></strong><br /><input type=\"text\" name=\"username\" id=\"username\" /></p><p><strong><label for=\"pass\">Password:</label></strong><br /><input type=\"password\" name=\"pass\" id=\"pass\" /></p><p><input type=\"submit\" name=\"submit\" id=\"submit\" value=\"submit\" /></p></form>",$id); print "<hr />"; } else { ?> <p><strong><?php echo $title; ?></strong><br /><br /> <?php echo $entry; ?><br /><br /> Posted on <?php echo $date; ?> <hr /></p> <?php } } ?> </body> </html> Thanks for any help. I really appreciate any input!

    Read the article

  • Does a servlet knows the encoding of the sent form that specified using http-equiv?

    - by Daziplqa
    Does a servlet knows the encoding of the sent form that specified using http-equiv? When I specify an encoding of a POSTed form using http-equiv like that: <HTML> <head> <meta http-equiv='Content-Type' content='text/html; charset=gb2312'/> </head> <BODY > <form name="form" method="post" > <input type="text" name="v_rcvname" value="????"> </form> </BODY> </HTML> And then at the servlet I use the method, request.getCharacterEncoding() I got null ! So, Is there a way that I can tell the server that I am encoding the data in some char encoding??

    Read the article

  • Repeating characters in VIM insert mode

    - by Cthutu
    Is there a way of repeating a character while in Vim's insert mode? For example, say I would like to insert 80 dashes, in something like emacs I would type: Ctrl+U 8 0 - The only way I know how to do it in VIM is to exit normal mode for the repeat argument, then go back into insert mode to type the dash, then exit to insert the actual dashes, AND then go back into insert mode to carry on typing. The sequence is a really long: <ESC> 8 0 a - <ESC> a It would be nice not to switch in and out of modes. Thanks

    Read the article

  • How to get the age from a birthdate using PHP & MySQL?

    - by TaG
    I ask my users for their birthdate and store it in my database in the following way $month $day $year output May 6 1901 but I was wondering how can I get the age from the stored birthdate using PHP & MySQL? Here is the PHP code. if (isset($_POST['submitted'])) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"SELECT users.* FROM users WHERE user_id=3"); $month_options = array("Month", "January", "February", "March", "April", "May", "June", "July", "August", "September", "October", "November", "December"); $day_options = array("Day", "1", "2", "3", "4", "5", "6", "7", "8", "9", "10", "11", "12", "13", "14", "15", "16", "17", "18", "19", "20", "21", "22", "23", "24", "25", "26", "27", "28", "29", "30", "31"); $month = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['month']))); $day = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['day']))); $year = mysqli_real_escape_string($mysqli, htmlentities(strip_tags($_POST['year']))); if (mysqli_num_rows($dbc) == 0) { $mysqli = mysqli_connect("localhost", "root", "", "sitename"); $dbc = mysqli_query($mysqli,"INSERT INTO users (user_id, month, day, year) VALUES ('$user_id', '$month', '$day', '$year')"); } if ($dbc == TRUE) { $dbc = mysqli_query($mysqli,"UPDATE users SET month = '$month', day = '$day', year = '$year' WHERE user_id = '$user_id'"); echo '<p class="changes-saved">Your changes have been saved!</p>'; } if (!$dbc) { print mysqli_error($mysqli); return; } } Here is the html. <form method="post" action="index.php"> <fieldset> <ul> <li><label>Date of Birth: </label> <label for="month" class="hide">Month: </label> <?php // month options echo '<select name="month" id="month">' . "\n"; foreach($month_options as $option) { if ($option == $month) { echo '<option value="' . stripslashes(htmlentities(strip_tags($option))) . '" selected="selected">' . stripslashes(htmlentities(strip_tags($option))) . '</option>' . "\n"; } else { echo '<option value="'. stripslashes(htmlentities(strip_tags($option))) . '">' . stripslashes(htmlentities(strip_tags($option))) . '</option>'."\n"; } } echo '</select>'; ?> <label for="day" class="hide">Day: </label> <?php // day options echo '<select id="day" name="day">' . "\n"; foreach($day_options as $option) { if ($option == $day) { echo '<option value="' . stripslashes(htmlentities(strip_tags($option))) . '" selected="selected">' . stripslashes(htmlentities(strip_tags($option))) . '</option>' . "\n"; } else { echo '<option value="'. stripslashes(htmlentities(strip_tags($option))) . '">' . stripslashes(htmlentities(strip_tags($option))) . '</option>'."\n"; } } echo '</select>'; ?> <label for="year" class="hide">Year: </label><input type="text" name="year" id="year" size="4" maxlength="4" value="<?php if (isset($_POST['year'])) { echo stripslashes(htmlentities(strip_tags($_POST['year']))); } else if(!empty($year)) { echo stripslashes(htmlentities(strip_tags($year))); } ?>" /></li> <li><input type="submit" name="submit" value="Save Changes" class="save-button" /> <input type="hidden" name="submitted" value="true" /> <input type="submit" name="submit" value="Preview Changes" class="preview-changes-button" /></li> </ul> </fieldset> </form>

    Read the article

  • Making dynamic images have static filenames

    - by michaeltk
    My website currently has various links to a php script that generates the images dynamically. For example, the link may say "img source="/dynamic_images.php?type=pie-chart&color=red" Obviously, this is not great for SEO. I'd like to somehow make the filenames of these links appear to be static, and use a solution (like Mod-Rewrite) to ensure that the images can still be dynamically created. I suppose I could have something like "img src="average-profits-in-scuba-diving-industry.png?type=pie-chart&color=red" (and use Mod-Rewrite to take care of changing the filename prefix to dynamic_images.php), but I'm afraid that the search engines would shy away from the querystring on the end of the image filename. Any solutions? Thanks in advance.

    Read the article

  • Possible to have empty values with Html For Helpers such as Html.TextBoxFor()?

    - by chobo2
    Hi Is it possible to have to make a html for helper in asp.net mvc 2.0 have a default value of "empty string" Like if I do this Html.TextBoxFor( u => u.ProductName) would render to <input id ="ProductName" name="ProdcutName" type="text" value="Jim" /> Now I don't want the textbox to display jim. I want it to display nothing. <input id ="ProductName" name="ProdcutName" type="text" value="" /> I tried to do this Html.TextBoxFor( u => u.ProductName, new { @value = " "}) but that seems to do nothing. So how can I do this. I hope you can do something like this otherwise I think these new helpers have a great flaw since now I need to use like javascript to remove them since I hardly ever want a default value in the textbox especially when I have a label right beside the textbox saying what it is.

    Read the article

  • Array with mutiple types?

    - by aleluja
    Hello, I was wondering if there is a way to make an array which would have mutiple types of data fields. So far i was using aMyArray: array of array [0..1] of TPoint; But now, it is not enough for me. I need to add 3 more elements to the existing 2 "Point" elements making it an array like aMyArray: array of (TPoint,TPoint,real,real,real) So each element of aMyArray would have 5 'children', 2 of which are of a TPoint type and 3 of them are 'real' type. Is this possible to implement somehow?

    Read the article

  • how to get a constant in java with class

    - by vincent
    basically I need to get a constant for a class however I have no instance of the object but only its class. In PHP I would do constant(XYZ); Is there a similar way of retrieving a constant in JAVA? I need it to facilitate a dynamic getMethod call Class parameterType = Class.forName(class_name); object.setProperty(field name, field value, parameterType); the set property method would then get the correct method and set the specified property, however I cant get a method which has int as parameter type without using Interger.TYPE

    Read the article

  • jQuery doesn't work in <head>?!

    - by Hanz
    This code is supposed to make a slideshow out of stacked list-elements (I commented out the CSS so I can see what's going on) by fading out the topmost elements until only the first one is visible, then fade in the topmost element and the rest and start anew. If I put the script below my content inside the <body> and throw out the $(function() { it works perfectly fine, but in the <head> nothing happens. I wrote this yesterday and today I still can't see the mistake, so I'm posting it here. <!DOCTYPE html> <html> <head> <title></title> <style type="text/css"> ul { position: relative; } ul li { /*position: absolute; left: 0; top: 0;*/ } </style> <script src="jquery-1.5.1.min.js" type="text/javascript"></script> <script type="text/javascript"> $(function() { var i = 0; var count = $('ul li').size(); function fade() { if (i < count-1) { $('ul li:nth-child('+(count-i)+')').fadeOut(300); i++; } else { $('ul li:nth-child('+count+')').fadeIn(300, function(){$('ul li').show();}); i = 0; } } $('button').click(function() { setInterval('fade()', 1000); }); }); </script> </head> <body> <button>Slideshow GO!</button> <ul id="slider"> <li><img src="1.jpg" /></li> <li><img src="2.jpg" /></li> <li><img src="3.jpg" /></li> <li><img src="4.jpg" /></li> </ul> </body> </html> Thanks

    Read the article

  • Error with my JQuery code in IE but not Firefox

    - by Kaz Lee
    Guys, I have this code below which works in firefox and all others except in IE. Am I making a syntaxt error somewhere? Can't seem to find it and its driving me nuts. Any help is appreciated! <script> $(document).ready(function(){ $("label:contains('Number')").html("Register:"); $("input[type='textbox']").each(function(){ var name = $(this).attr('name'); // grab name of original /* create new visible input */ var html = '<input type="checkbox" class="NetscapeFix" size="4" maxlength="5" name="'+name+'" id="'+name+'" value="1" dir="rtl" />'; $(this).after(html).remove(); // add new, then remove original input }); }); </script> Thank you, Kaz

    Read the article

  • problem with logout script in php

    - by user225269
    I'm a beginner in php, and I am trying to create a login and logout. But I am having problems in logging out. My logout just calls for the login form which is this: <? session_start(); session_destroy(); ?> <table width="300" border="0" align="center" cellpadding="0" cellspacing="1" bgcolor="#CCCCCC"> <tr> <form name="form1" method="post" action="checklogin.php"> <td> <table width="100%" border="0" cellpadding="3" cellspacing="1" bgcolor="#FFFFFF"> <tr> <td colspan="3"><strong>Member Login </strong></td> </tr> <tr> <td width="78">Username</td> <td width="6">:</td> <td width="294"><input name="myusername" type="text" id="myusername"></td> </tr> <tr> <td>Password</td> <td>:</td> <td><input name="mypassword" type="text" id="mypassword"></td> </tr> <tr> <td>&nbsp;</td> <td>&nbsp;</td> <td><input type="submit" name="Submit" value="Login"></td> </tr> </table> </td> </form> </tr> </table> My problem is, when I try to press the back button in the browser. Whoever user is using it can still access what is not supposed to be accessed when a user hasn't logged in. Do I need to add a code on the user page? I have this code on the user page: <? session_start(); if(!session_is_registered(myusername)){ header("location:main_login.php"); } ?> What can you recommend that I would do so that a script will prompt to enter the username and password again when a user clicks on the back button.

    Read the article

< Previous Page | 528 529 530 531 532 533 534 535 536 537 538 539  | Next Page >