Make the JavaScript Test Pass
Add code on the commented line: var f = function () { var value = // ??? return f.sum = (f.sum || 0) + value;}
... to make the following QUnit test pass:
test("Running sum", function () { equals(f(3), 3); equals(f(3), 6); equals(f(4), 10); jQuery([1, 2, 3]).each(f); equals(f(0), 16); });
Possible Answer
It's a goofy scenario, but one possible solution uses a technique you'll see frequently inside today's JavaScript libraries. First, we'll need to use the implicit arguments parameter inside...Did you know that DotNetSlackers also publishes .net articles written by top known .net Authors? We already have over 80 articles in several categories including Silverlight. Take a look: here.
