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  • How to add a WHERE clause on the second table of a 1-to-1 join in Fluent NHibernate?

    - by daddywoodland
    I'm using a legacy database that was 'future proofed' to keep track of historical changes. It turns out this feature is never used so I want to map the tables into a single entity. My tables are: CodesHistory (CodesHistoryID (pk), CodeID (fk), Text) Codes (CodeID (pk), CodeName) To add an additional level of complexity, these tables hold the content for the drop down lists throughout the application. So, I'm trying to map a Title entity (Mr, Mrs etc.) as follows: Title ClassMap - Public Sub New() Table("CodesHistory") Id(Function(x) x.TitleID, "CodesHistoryID") Map(Function(x) x.Text) 'Call into the other half of the 1-2-1 join in order to merge them in 'this single domain object Join("Codes", AddressOf AddTitleDetailData) Where("CodeName like 'C.Title.%'") End Sub ' Method to merge two tables with a 1-2-1 join into a single entity in VB.Net Public Sub AddTitleDetailData(ByVal m As JoinPart(Of Title)) m.KeyColumn("CodeID") m.Map(Function(x) x.CodeName) End Sub From the above, you can see that my 'CodeName' field represents the select list in question (C.Title, C.Age etc). The problem is that the WHERE clause only applies to the 'CodesHistory' table but the 'CodeName' field is in the 'Codes' table. As I'm sure you can guess there's no scope to change the database. Is it possible to apply the WHERE clause to the Codes table?

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  • Json to treeview (<ul>)

    - by Pieter
    Hi I get the following data back from my WCF Data Service (I cut out the metadata) { "d" : [ {"CodeId": 6, "Title": "A Child Sub Item", "Parent":}, {"CodeId": 5, "Title": "Another Root Item", "Parent": -1}, {"CodeId": 4, "Title": "Child Item", "Parent": 2}, {"CodeId": 2, "Title": "Root Item", "Parent": -1} ] } I am trying to get this into a <ul> style tree with Parent = -1 as root and then the rest as sub items of their parent id's. Can anyone help me please, preferably in jQuery? I will use this in jstree if someone knows of a better way to do this. Thanks

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  • How to convert Xml files to Text Files 2

    - by John
    Hi all, I have around 8000 xml files that needs to be converted into text files. The text file must contain title, description and keywords of the xml file without the tags and removing other elements and attributes as well. In other words, i need to create 8000 text files containing the title,description and keywords of the xml file. I need codings for this to be done systematically. Any help would be greatly appreciated. Thanks in advance. Hey all thank you all so so much with your replies. Here's a sample of what my xml looks like: <?xml version="1.0"?> <metadata> <identifier>43productionsNightatthegraveyard</identifier> <title>Night at the graveyard</title> <collection>opensource_movies</collection> <mediatype>movies</mediatype> <resource>movies</resource> <upload_application appid="ccPublisher" version="2.2.1"/> <uploader>[email protected]</uploader> <description>una noche en el cementerio (terror)</description> <license>http://creativecommons.org/licenses/by-nc/3.0/</license> <title>Night at the graveyard</title> <format>Video</format> <adder>[email protected]</adder> <licenseurl>http://creativecommons.org/licenses/by-nc/3.0/</licenseurl> <year>2007</year> <keywords>Night,at,the,graveyard,43,productions</keywords> <holder>43 productions</holder> <publicdate>2007-04-11 19:52:28</publicdate> </metadata> And this would be the output: una noche en el cementerio (terror) Night at the graveyard Night,at,the,graveyard,43,productions This need to be saved with the same name but in text format. Thanks all so much if any more suggestions would be much appreciated.

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  • Apache Rewrite rule confusion

    - by Lee
    I'm trying to convert a simple url (below) in to a blog-style url, but not quite sure how to do it, all of my other rules are working fine, but I can't seem to figure this one out. URL I want to convert: http://www.website.com/myblog.php?id=1&title=My+blog+title URL I want it to create: http://www.website.com/1/my-blog-title What should the rule be? Any assistance appreciated :)

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  • How could I implement a fuzzy time date replacer using Knockout?

    - by rball
    I'd like to implement what this plugin does using jQuery: https://github.com/rmm5t/jquery-timeago A short description of that plugin: This will turn all abbr elements with a class of timeago and an ISO 8601 timestamp in the title (conforming to the datetime design pattern microformat): <abbr class="timeago" title="2011-12-17T09:24:17Z">December 17, 2011</abbr> Into something like this: <abbr class="timeago" title="December 17, 2011">about 1 day ago</abbr> Except using knockout my markup looks like this: <abbr data-bind="attr: { title: Posted }" class="timeago"></abbr> I think something isn't synced up because nothing is happening even if I put the call to timeago within the viewmodel itself. I'm guessing I need a subscriber that's attached to the observable "Posted" but I'm not sure how to set that up.

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  • Stepping thru a plist to get at info

    - by cannyboy
    If I've got a plist set up like this Key Type Value Root Array Item 0 Dictionary -Title String Part One -Description String Welcome to part one. Have fun Item 1 Dictionary -Title String Part Two -Description String Welcome to part two. Fun too. Item 2 Dictionary -Title String Part Three -Description String Welcome to part three. It's free Item 3 Dictionary -Title String Part Four -Description String It's part four. No more How would I step thru to put all the titles in one array, and all the descriptions into another?

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  • PHP write file... need help

    - by Jordan Pagaduan
    <?php $title = $_POST['title']; $filename = $title , ".php"; $fh = fopen($filename, 'w') or die ("can't open file"); $stringData = $title; fwrite($fh, $stringData); $stringData = $blog; fwrite($fh, $stringData); fclose($fh); ?> This is only a sample. What is the correct code for that?

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  • Styling an Input Field

    - by John
    Hello When I try to alter the CSS for the input field named "title" below, which is classed by "submissionfield", the position changes, but the height, length, and font of the field do not change. How could I make the height of the input field "title" 22 px, the length 550 px, and the font Times New Roman? The CSS below does not do it. Thanks in advance, John echo '<form action="http://www...com/.../submit2.php" method="post"> <input type="hidden" value="'.$_SESSION['loginid'].'" name="uid"> <div class="submissiontitle"><label for="title">Story Title:</label></div> <div class="submissionfield"><input name="title" type="title" id="title" maxlength="1000"></div> <div class="urltitle"><label for="url">Link:</label></div> <div class="urlfield"><input name="url" type="url" id="url" maxlength="500"></div> <div class="submissionbutton"><input name="submit" type="submit" value="Submit"></div> </form> '; The CSS: .submissiontitle { position:absolute; width:100px; left:30px; top:200px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; } .submissionfield { position:absolute; width:550px; left:50px; top:230px; text-align: left; margin-bottom:3px; padding:0px; font-family: "Times New Roman", Times, serif; font-size: 22px; color:#000000; } .urltitle { position:absolute; width:250px; left:30px; top:300px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; } .urlfield { position:absolute; width:550px; left:30px; top:330px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 11px; color:#000000; } .submissionbutton { position:absolute; width:250px; left:30px; top:380px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 11px; color:#000000; } .submittitle { position:absolute; width:250px; left:30px; top:150px; text-align: left; margin-bottom:3px; padding:0px; font-family:Arial, Helvetica, sans-serif; font-size: 12px; color:#000000; }

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  • Generating 8000 text files from xml files

    - by Ray
    Hi all, i need to generate the same number of text files as the xml files i have. Within the text files, i need the title and maybe some other tags of it. I can generate text files with the elements i wanted but not all xml files can be generated. Only some of them are generated. Something might be wrong with my parser so help out please thanks. This is my code. Please have a look and give me suggestions. Thanks in advance. import java.io.File; import javax.xml.parsers.DocumentBuilder; import javax.xml.parsers.DocumentBuilderFactory; import org.w3c.dom.*; import java.io.*; public class AccessingXmlFile1 { public static void main(String argv[]) { try { //File file = new File("C:\\MyFile.xml"); // create a file that is really a directory File aDirectory = new File("C:/Documents and Settings/I2R/Desktop/test"); // get a listing of all files in the directory String[] filesInDir = aDirectory.list(); System.out.println(""+filesInDir.length); // sort the list of files (optional) // Arrays.sort(filesInDir); //////////////////////////////////////////////////////////////////////////////////// //////////////////////////////////////////////////////////////////////////////////// // have everything i need, just print it now for ( int a=0; a<filesInDir.length; a++ ) { String xmlFile = filesInDir[a]; String newLine = System.getProperty("line.separator"); File file = new File(xmlFile); DocumentBuilderFactory dbf = DocumentBuilderFactory.newInstance(); DocumentBuilder db = dbf.newDocumentBuilder(); Document document = db.parse(file); document.getDocumentElement().normalize(); //System.out.println("Root element " + document.getDocumentElement().getNodeName()); NodeList node = document.getElementsByTagName("metadata"); System.out.println("Information of Xml File"); System.out.println(xmlFile.substring(0, xmlFile.length() - 4)); //////////////////////////////////////////////////////////////////////////////////// String titleStoreText = ""; String descriptionStoreText = ""; String collectionStoreText = ""; String textToWrite = ""; //////////////////////////////////////////////////////////////////////////////////// for (int i = 0; i < node.getLength(); i++) { Node firstNode = node.item(i); if (firstNode.getNodeType() == Node.ELEMENT_NODE) { Element element = (Element) firstNode; NodeList titleElementList = element.getElementsByTagName("title"); Element titleElement = (Element) titleElementList.item(0); NodeList title = titleElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(titleElement == null) titleStoreText = " There is no title for this file."+ newLine; else titleStoreText = titleStoreText+((Node) title.item(0)).getNodeValue() + newLine; //titleStoreText = titleStoreText+((Node) title.item(0)).getNodeValue()+ newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Title : " + titleStoreText); NodeList collectionElementList = element.getElementsByTagName("collection"); Element collectionElement = (Element) collectionElementList.item(0); NodeList collection = collectionElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(collectionElement == null) collectionStoreText = " There is no collection for this file."+ newLine; else collectionStoreText = collectionStoreText+((Node) collection.item(0)).getNodeValue() + newLine; //collectionStoreText = collectionStoreText+((Node) collection.item(0)).getNodeValue()+ newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Collection : " + collectionStoreText); NodeList descriptionElementList = element.getElementsByTagName("description"); Element descriptionElement = (Element) descriptionElementList.item(0); NodeList description = descriptionElement.getChildNodes(); //////////////////////////////////////////////////////////////////////////////////// if(descriptionElement == null) descriptionStoreText = " There is no description for this file."+ newLine; else descriptionStoreText = descriptionStoreText+((Node) description.item(0)).getNodeValue() + newLine; //descriptionStoreText = descriptionStoreText+((Node) description.item(0)).getNodeValue() + newLine; //////////////////////////////////////////////////////////////////////////////////// System.out.println("Description : " + descriptionStoreText); //////////////////////////////////////////////////////////////////////////////////// textToWrite = "=====Title=====" + newLine + titleStoreText + newLine + "=====Collection=====" + newLine + collectionStoreText + newLine + "=====Description=====" + newLine + descriptionStoreText;// + newLine + "=====Subject=====" + newLine + subjectStoreText; //////////////////////////////////////////////////////////////////////////////////// } } ///////////////////////////////////////////write to file part is here///////////////////////////////////////// Writer output = null; File file2 = new File(xmlFile.substring(0, xmlFile.length() - 4)+".txt"); output = new BufferedWriter(new FileWriter(file2)); output.write(textToWrite); output.close(); System.out.println("Your file has been written"); //////////////////////////////////////////////////////////////////////////////////// } } catch (Exception e) { e.printStackTrace(); } } }

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  • combine lines from 2 prints to single line and insert into mysql database

    - by bleomycin
    Hello everyone i currently have this: import feedparser d = feedparser.parse('http://store.steampowered.com/feeds/news.xml') for i in range(10): print d.entries[i].title print d.entries[i].date How would i go about making it so that the title and date are on the same line? Also it doesn't need to print i just have that in there for testing, i would like to dump this output into a mysql db with the title and date, any help is greatly appreciated!

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  • Facebook Like button - comment box with breif description and image

    - by Dave Smith
    On my website when the user selects the facebook like button they have the option to enter comments. This popup window to enter comments only contains the users avatar and place to enter comments. How can i include my pic and a brief description of the site directly below the comment??? At first I thought it was from the HTML title attribute or meta property="og:title" ... but populating these have no affect I have another site that contains both pic and a desc below the comment but the pic seems to be grabed at random -but always the same- from the site and the short desc I thought from the -title- attribute but its not - I changed the -title- and it still shows the same desc, its like its cached??? Any ideas how to control or populate a brief description and image within the comment section of a like button???

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  • How can I get Perl to detect the bad UTF-8 sequences?

    - by gorilla
    I'm running Perl 5.10.0 and Postgres 8.4.3, and strings into a database, which is behind a DBIx::Class. These strings should be in UTF-8, and therefore my database is running in UTF-8. Unfortunatly some of these strings are bad, containing malformed UTF-8, so when I run it I'm getting an exception DBI Exception: DBD::Pg::st execute failed: ERROR: invalid byte sequence for encoding "UTF8": 0xb5 I thought that I could simply ignore the invalid ones, and worry about the malformed UTF-8 later, so using this code, it should flag and ignore the bad titles. if(not utf8::valid($title)){ $title="Invalid UTF-8"; } $data->title($title); $data->update(); However Perl seems to think that the strings are valid, but it still throws the exceptions. How can I get Perl to detect the bad UTF-8?

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  • How to bind value to its parent element value?

    - by KentZhou
    Silverlight provides element to element binding. How to apply it this is case: I have a xaml as below: <TextBlock Text="{Binding ABC}" > <ToolTipService.ToolTip> <local:MyControl Title="{Binding ...}" /> </ToolTipService.ToolTip> </TextBlock> I want to bind MyControl Title to the same data as its parent Textblock Text, but I don't want set x:Name for its parent Textblock. I know there is one solution to bind Title to same data source: <local:MyControl Title="{Binding ABC}" /> This may cause two times to call "{Binding ABC}", with my case, there ValurConverter for this binding. I don't want to use this way.

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  • Regular expressions in a Python find-and-replace script?

    - by Haidon
    I'm new to Python scripting, so please forgive me in advance if the answer to this question seems inherently obvious. I'm trying to put together a large-scale find-and-replace script using Python. I'm using code similar to the following: findreplace = [ ('term1', 'term2'), ] inF = open(infile,'rb') s=unicode(inF.read(),charenc) inF.close() for couple in findreplace: outtext=s.replace(couple[0],couple[1]) s=outtext outF = open(outFile,'wb') outF.write(outtext.encode('utf-8')) outF.close() How would I go about having the script do a find and replace for regular expressions? Specifically, I want it to find some information (metadata) specified at the top of a text file. Eg: Title: This is the title Author: This is the author Date: This is the date and convert it into LaTeX format. Eg: \title{This is the title} \author{This is the author} \date{This is the date} Maybe I'm tackling this the wrong way. If there's a better way than regular expressions please let me know! Thanks!

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  • Help needed in AdventureWorks in a sql query.

    - by vaibhav
    I was just playing with adventureworks database in sqlserver. I got stuck in a query. I wanted to Select all titles from HumanResources.Employee which are either 'Male' or 'Female' but not both. i.e if title Accountant is Male and Female both I want to leave that title. I need only those titles where Gender is either Male or Female. I have done this till yet. select distinct(title) from humanresources.employee where gender='M' select distinct(title) from humanresources.employee where gender='F' Probably a join between these two queries, would work. But If you have any other solution, please let me know. It is not a homework. :) Thanks in advance.

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  • ASP Repeater Evals mixed with HTML

    - by Bry4n
    I want to include HTML and Eval within a Repeater: <asp:Repeater ID="Rpt" runat="server" DataSourceID="DS"> <HeaderTemplate><div id="gallery"></HeaderTemplate> <ItemTemplate> <a href='<%# Eval("Url") %>' class="show"> <img src='<%# Eval("Image") %>' alt='<%# Eval("Title") %>' title="" runat="server" id="sb1" rel='<%# Eval("Title") %>'/></a> </ItemTemplate> <FooterTemplate></FooterTemplate> </asp:Repeater> I want the rel attribute Eval Title to have h3 tags wrapped around it. I've done this before, but I'm drawing a huge blank

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  • Controller not accepting params value but the same value hard coded is accepted

    - by Numbers
    Rails.logger.info(params[:question]) => {"title"=>"katt"} @question_list.questions.create(params[:question]) => ActiveModel::ForbiddenAttributesError (ActiveModel::ForbiddenAttributesError) @question_list.questions.create("title"=>"katt") # SUCCES! I cannot understand why Rails not accepts the params when the exact same value written by hand works fine? Update controller: def new_question @question_list.questions.create(params[:question]) render nothing: true end private def set_question_list @question_list = QuestionList.find(params[:id]) end def question_list_params params.require(:question_list).permit(questions_attributes: [:id, :question_list_id, :title, :position, :_destroy]) end view: <%= form_for @question_list, url: new_question_question_list_path, remote: true do |f| %> <%= f.text_field :title %> <%= f.submit %> <% end %>

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  • MySQL Query, how to group and count in one row ?

    - by Akarun
    Hi All, To simplify, I have tree tables: products, products-vs-orders, orders products fields : 'ProductID', 'Name', 'isGratis', ... products-vs-orders fields : 'ProductID', 'OrderID' orders fields : 'OrderID', 'Title', ... Actually, I have a query like this: SELECT orders.OrderID, orders.Title, COUNT(`products`.`isGratis`) AS "Quantity", `products`.`isGratis` FROM `orders`, `products-vs-orders`, `products` WHERE `orders`.`OrderID` = `products-vs-orders`.`OrderID` AND `products-vs-orders`.`ProductID` = `products`.`ProductID` GROUP BY `products`.`PackID`, `products`.`isGratis` This query works and return this surch of result: OrderID, Title, Quantity, isGratis 1 My Order 20 0 1 My Order 3 1 2 An other 8 0 2 An other 1 1 How can I retrieve the count of products 'gratis' and 'paid' in to separate cols ? OrderID, Title, Qt Paid, Qt Gratis 1 My Order 20 3 2 An other 8 1 Thanks for your help

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  • 2 Select or 1 Join query ?

    - by xRobot
    I have 2 tables: book ( id, title, age ) ---- 100 milions of rows author ( id, book_id, name, born ) ---- 10 millions of rows Now, supposing I have a generic id of a book. I need to print this page: Title: mybook authors: Tom, Graham, Luis, Clarke, George So... what is the best way to do this ? 1) Simple join like this: Select book.title, author.name From book, author WHERE ( author.book_id = book.id ) AND ( book.id = 342 ) 2) For avoid the join, I could make 2 simple query: Select title FROM book WHERE id = 342 Select name FROM author WHERE book_id = 342 What is the most efficient way ?

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  • function not printing out anything

    - by Abdul Latif
    I have the following function below: public function setupHead($title){ $displayHead .='<!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Strict//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-strict.dtd"> <html xmlns="http://www.w3.org/1999/xhtml" xml:lang="en"> <head> <meta http-equiv="Content-Type" content="text/html; charset=UTF-8" /> <title>'.$title.'</title>'; $displayHead .='<script type="text/javascript" src="'.PATH.'js/jquery-1.3.2.min.js"></script> <script type="text/javascript" src="'.PATH.'js/thickbox.js"></script> <script type="text/javascript" src="'.PATH.'js/ui.core.js"></script> <!--<script type="text/javascript" src="'.PATH.'js/js.js"></script>--> <link rel="stylesheet" href="'.PATH.'css/thickbox.css" type="text/css" media="screen" /> <link rel="stylesheet" type="text/css" href="'.PATH.'css/styles.css"> <link rel="stylesheet" type="text/css" href="'.PATH.'css/menu_allbrowsers.css"> <link rel="stylesheet" href="'.PATH.'css/news.css" type="text/css" media="screen" /> <link rel="stylesheet" href="'.PATH.'css/text.css" type="text/css" media="screen" /> <script type="text/javascript" src="'.PATH.'js/swfobject.js"></script> <!--[if IE 7]><link rel="stylesheet" type="text/css" href="'.PATH.'css/IE7menu.css" /><![endif]--> <!--[if IE 6]><link rel="stylesheet" type="text/css" href="'.PATH.'css/ie6.css" /><![endif]--> <!--[if IE 7]><link rel="stylesheet" type="text/css" href="'.PATH.'css/ie7.css" /><![endif]--> </head>'; return $displayHead; } but when it call is using: echo classname->setupHead($title); nothing gets displayed. doesn't php allow html in strings? Thanks in advance

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  • PHP Notice: Undefined index when looping array...

    - by Jonathan
    Hi, I'm looping a two-dimensional array like this: if (!empty($aka)) { foreach ($aka as $ak) { if($ak["lang"]=="es") { $sptitle=$ak["title"]; } } } Pretty simple. If the array ($aka) is not empty I loop trough it and when it finds that the "lang" index is equal to "es" I just save the "title" value for that index in $sptitle. The problem is that the array ($aka) contains a lot of information and sometimes there is no "lang" index... and I get this error: Notice: Undefined index: lang. How can I fix this??? This is a extract of the array to help you understand. Notice that [1] doesn't have a [lang] index but [2] does have: [1] =&gt; Array ( [title] =&gt; The Lord of the Rings: The Motion Picture [year] =&gt; [country] =&gt; USA [comment] =&gt; promotional title ) [2] =&gt; Array ( [title] =&gt; Señor de los anillos: La comunidad del anillo, El [year] =&gt; [country] =&gt; Argentina [comment] =&gt; Chile, Mexico, Peru, Spain [lang] =&gt; es ) Thanks!

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