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  • CAS authentication and redirects with jQuery Ajax

    - by Steve Nay
    I've got an HTML page that needs to make requests to a CAS-protected (Central Authentication Service) web service using the jQuery AJAX functions. I've got the following code: $.ajax({ type: "GET", url: request, dataType: "json", complete: function(xmlHttp) { console.log(xmlHttp); alert(xmlHttp.status); }, success: handleRedirects }); The request variable can be either to the CAS server (https://cas.mydomain.com/login?service=myServiceURL) or directly to the service (which should then redirect back to CAS to get a service ticket). Firebug shows that the request is being made and that it comes back as a 302 redirect. However, the $.ajax() function isn't handling the redirect. I wrote this function to work around this: var handleRedirects = function(data, textStatus) { console.log(data, textStatus); if (data.redirect) { console.log("Calling a redirect: " + data.redirect); $.get(data.redirect, handleRedirects); } else { //function that handles the actual data processing gotResponse(data); } }; However, even with this, the handleRedirects function never gets called, and the xmlHttp.status always returns 0. It also doesn't look like the cookies are getting sent with the cas.mydomain.com call. (See this question for a similar problem.) Is this a problem with the AJAX calls not handling redirects, or is there more going on here than meets the eye?

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  • Is it possible to convert a 40-character SHA1 hash to a 20-character SHA1 hash?

    - by ewitch
    My problem is a bit hairy, and I may be asking the wrong questions, so please bear with me... I have a legacy MySQL database which stores the user passwords & salts for a membership system. Both of these values have been hashed using the Ruby framework - roughly like this: hashedsalt = Digest::SHA1.hexdigest("--#{Time.now.to_s}--#{login}--") hashedpassword = Digest::SHA1.hexdigest("#{hashedsalt}:#{password}") So both values are stored as 40-character strings (varchar(40)) in MySQL. Now I need to import all of these users into the ASP.NET membership framework for a new web site, which uses a SQL Server database. It is my understanding that the the way I have ASP.NET membership configured, the user passwords and salts are also stored in the membership database (in table aspnet_Membership) as SHA1 hashes, which are then Base64 encoded (see here for details) and stored as nvarchar(128) data. But from the length of the Base64 encoded strings that are stored (28 characters) it seems that the SHA1 hashes that ASP.NET membership generates are only 20 characters long, rather than 40. From some other reading I have been doing I am thinking this has to do with the number of bits per character/character set/encoding or something related. So is there some way to convert the 40-character SHA1 hashes to 20-character hashes which I can then transfer to the new ASP.NET membership data table? I'm pretty familiar with ASP.NET membership by now but I feel like I'm just missing this one piece. However, it may also be known that SHA1 in Ruby and SHA1 in .NET are incompatible, so I'm fighting a losing battle... Thanks in advance for any insight.

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  • Test-Driven Development Problem

    - by Zeck
    Hi guys, I'm newbie to Java EE 6 and i'm trying to develop very simple JAX-RS application. RESTfull web service working fine. However when I ran my test application, I got the following. What have I done wrong? Or am i forget any configuration? Of course i'm create a JNDI and i'm using Netbeans 6.8 IDE. In finally, thank you for any advise. My Entity: @Entity @Table(name = "BOOK") @NamedQueries({ @NamedQuery(name = "Book.findAll", query = "SELECT b FROM Book b"), @NamedQuery(name = "Book.findById", query = "SELECT b FROM Book b WHERE b.id = :id"), @NamedQuery(name = "Book.findByTitle", query = "SELECT b FROM Book b WHERE b.title = :title"), @NamedQuery(name = "Book.findByDescription", query = "SELECT b FROM Book b WHERE b.description = :description"), @NamedQuery(name = "Book.findByPrice", query = "SELECT b FROM Book b WHERE b.price = :price"), @NamedQuery(name = "Book.findByNumberofpage", query = "SELECT b FROM Book b WHERE b.numberofpage = :numberofpage")}) public class Book implements Serializable { private static final long serialVersionUID = 1L; @Id @Basic(optional = false) @Column(name = "ID") private Integer id; @Basic(optional = false) @Column(name = "TITLE") private String title; @Basic(optional = false) @Column(name = "DESCRIPTION") private String description; @Basic(optional = false) @Column(name = "PRICE") private double price; @Basic(optional = false) @Column(name = "NUMBEROFPAGE") private int numberofpage; public Book() { } public Book(Integer id) { this.id = id; } public Book(Integer id, String title, String description, double price, int numberofpage) { this.id = id; this.title = title; this.description = description; this.price = price; this.numberofpage = numberofpage; } public Integer getId() { return id; } public void setId(Integer id) { this.id = id; } public String getTitle() { return title; } public void setTitle(String title) { this.title = title; } public String getDescription() { return description; } public void setDescription(String description) { this.description = description; } public double getPrice() { return price; } public void setPrice(double price) { this.price = price; } public int getNumberofpage() { return numberofpage; } public void setNumberofpage(int numberofpage) { this.numberofpage = numberofpage; } @Override public int hashCode() { int hash = 0; hash += (id != null ? id.hashCode() : 0); return hash; } @Override public boolean equals(Object object) { // TODO: Warning - this method won't work in the case the id fields are not set if (!(object instanceof Book)) { return false; } Book other = (Book) object; if ((this.id == null && other.id != null) || (this.id != null && !this.id.equals(other.id))) { return false; } return true; } @Override public String toString() { return "com.entity.Book[id=" + id + "]"; } } My Junit test class: public class BookTest { private static EntityManager em; private static EntityManagerFactory emf; public BookTest() { } @BeforeClass public static void setUpClass() throws Exception { emf = Persistence.createEntityManagerFactory("E01R01PU"); em = emf.createEntityManager(); } @AfterClass public static void tearDownClass() throws Exception { em.close(); emf.close(); } @Test public void createBook() { Book book = new Book(); book.setId(1); book.setDescription("Mastering the Behavior Driven Development with Ruby on Rails"); book.setTitle("Mastering the BDD"); book.setPrice(25.9f); book.setNumberofpage(1029); em.persist(book); assertNotNull("ID should not be null", book.getId()); } } My persistence.xml jta-data-sourceBookstoreJNDI And exception is: May 7, 2009 11:10:37 AM org.hibernate.validator.util.Version INFO: Hibernate Validator bean-validator-3.0-JBoss-4.0.2 May 7, 2009 11:10:37 AM org.hibernate.validator.engine.resolver.DefaultTraversableResolver detectJPA INFO: Instantiated an instance of org.hibernate.validator.engine.resolver.JPATraversableResolver. [EL Info]: 2009-05-07 11:10:37.531--ServerSession(13671123)--EclipseLink, version: Eclipse Persistence Services - 2.0.0.v20091127-r5931 May 7, 2009 11:10:40 AM com.sun.enterprise.transaction.JavaEETransactionManagerSimplified initDelegates INFO: Using com.sun.enterprise.transaction.jts.JavaEETransactionManagerJTSDelegate as the delegate May 7, 2009 11:10:43 AM com.sun.enterprise.connectors.ActiveRAFactory createActiveResourceAdapter SEVERE: rardeployment.class_not_found May 7, 2009 11:10:43 AM com.sun.enterprise.connectors.ActiveRAFactory createActiveResourceAdapter SEVERE: com.sun.appserv.connectors.internal.api.ConnectorRuntimeException: Error in creating active RAR at com.sun.enterprise.connectors.ActiveRAFactory.createActiveResourceAdapter(ActiveRAFactory.java:104) at com.sun.enterprise.connectors.service.ResourceAdapterAdminServiceImpl.createActiveResourceAdapter(ResourceAdapterAdminServiceImpl.java:216) at com.sun.enterprise.connectors.ConnectorRuntime.createActiveResourceAdapter(ConnectorRuntime.java:352) at com.sun.enterprise.resource.naming.ConnectorObjectFactory.getObjectInstance(ConnectorObjectFactory.java:106) at javax.naming.spi.NamingManager.getObjectInstance(NamingManager.java:304) at com.sun.enterprise.naming.impl.SerialContext.getObjectInstance(SerialContext.java:472) at com.sun.enterprise.naming.impl.SerialContext.lookup(SerialContext.java:437) at com.sun.enterprise.naming.impl.SerialContext.lookup(SerialContext.java:569) at javax.naming.InitialContext.lookup(InitialContext.java:396) at org.eclipse.persistence.sessions.JNDIConnector.connect(JNDIConnector.java:110) at org.eclipse.persistence.sessions.JNDIConnector.connect(JNDIConnector.java:94) at org.eclipse.persistence.sessions.DatasourceLogin.connectToDatasource(DatasourceLogin.java:162) at org.eclipse.persistence.internal.sessions.DatabaseSessionImpl.loginAndDetectDatasource(DatabaseSessionImpl.java:584) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryProvider.login(EntityManagerFactoryProvider.java:228) at org.eclipse.persistence.internal.jpa.EntityManagerSetupImpl.deploy(EntityManagerSetupImpl.java:368) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.getServerSession(EntityManagerFactoryImpl.java:151) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.createEntityManagerImpl(EntityManagerFactoryImpl.java:207) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.createEntityManager(EntityManagerFactoryImpl.java:195) at com.entity.BookTest.setUpClass(BookTest.java:31) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44) at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15) at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41) at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:27) at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31) at org.junit.runners.ParentRunner.run(ParentRunner.java:220) at junit.framework.JUnit4TestAdapter.run(JUnit4TestAdapter.java:39) at org.apache.tools.ant.taskdefs.optional.junit.JUnitTestRunner.run(JUnitTestRunner.java:515) at org.apache.tools.ant.taskdefs.optional.junit.JUnitTestRunner.launch(JUnitTestRunner.java:1031) at org.apache.tools.ant.taskdefs.optional.junit.JUnitTestRunner.main(JUnitTestRunner.java:888) Caused by: java.lang.ClassNotFoundException: com.sun.gjc.spi.ResourceAdapter at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:306) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:276) at java.lang.ClassLoader.loadClass(ClassLoader.java:251) at com.sun.enterprise.connectors.ActiveRAFactory.createActiveResourceAdapter(ActiveRAFactory.java:96) ... 32 more [EL Severe]: 2009-05-07 11:10:43.937--ServerSession(13671123)--Local Exception Stack: Exception [EclipseLink-7060] (Eclipse Persistence Services - 2.0.0.v20091127-r5931): org.eclipse.persistence.exceptions.ValidationException Exception Description: Cannot acquire data source [BookstoreJNDI]. Internal Exception: javax.naming.NamingException: Lookup failed for 'BookstoreJNDI' in SerialContext ,orb'sInitialHost=localhost,orb'sInitialPort=3700 [Root exception is javax.naming.NamingException: Failed to look up ConnectorDescriptor from JNDI [Root exception is com.sun.appserv.connectors.internal.api.ConnectorRuntimeException: Error in creating active RAR]] at org.eclipse.persistence.exceptions.ValidationException.cannotAcquireDataSource(ValidationException.java:451) at org.eclipse.persistence.sessions.JNDIConnector.connect(JNDIConnector.java:116) at org.eclipse.persistence.sessions.JNDIConnector.connect(JNDIConnector.java:94) at org.eclipse.persistence.sessions.DatasourceLogin.connectToDatasource(DatasourceLogin.java:162) at org.eclipse.persistence.internal.sessions.DatabaseSessionImpl.loginAndDetectDatasource(DatabaseSessionImpl.java:584) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryProvider.login(EntityManagerFactoryProvider.java:228) at org.eclipse.persistence.internal.jpa.EntityManagerSetupImpl.deploy(EntityManagerSetupImpl.java:368) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.getServerSession(EntityManagerFactoryImpl.java:151) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.createEntityManagerImpl(EntityManagerFactoryImpl.java:207) at org.eclipse.persistence.internal.jpa.EntityManagerFactoryImpl.createEntityManager(EntityManagerFactoryImpl.java:195) at com.entity.BookTest.setUpClass(BookTest.java:31) at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method) at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39) at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25) at java.lang.reflect.Method.invoke(Method.java:597) at org.junit.runners.model.FrameworkMethod$1.runReflectiveCall(FrameworkMethod.java:44) at org.junit.internal.runners.model.ReflectiveCallable.run(ReflectiveCallable.java:15) at org.junit.runners.model.FrameworkMethod.invokeExplosively(FrameworkMethod.java:41) at org.junit.internal.runners.statements.RunBefores.evaluate(RunBefores.java:27) at org.junit.internal.runners.statements.RunAfters.evaluate(RunAfters.java:31) at org.junit.runners.ParentRunner.run(ParentRunner.java:220) at junit.framework.JUnit4TestAdapter.run(JUnit4TestAdapter.java:39) at org.apache.tools.ant.taskdefs.optional.junit.JUnitTestRunner.run(JUnitTestRunner.java:515) at org.apache.tools.ant.taskdefs.optional.junit.JUnitTestRunner.launch(JUnitTestRunner.java:1031) at org.apache.tools.ant.taskdefs.optional.junit.JUnitTestRunner.main(JUnitTestRunner.java:888) Caused by: javax.naming.NamingException: Lookup failed for 'BookstoreJNDI' in SerialContext ,orb'sInitialHost=localhost,orb'sInitialPort=3700 [Root exception is javax.naming.NamingException: Failed to look up ConnectorDescriptor from JNDI [Root exception is com.sun.appserv.connectors.internal.api.ConnectorRuntimeException: Error in creating active RAR]] at com.sun.enterprise.naming.impl.SerialContext.lookup(SerialContext.java:442) at com.sun.enterprise.naming.impl.SerialContext.lookup(SerialContext.java:569) at javax.naming.InitialContext.lookup(InitialContext.java:396) at org.eclipse.persistence.sessions.JNDIConnector.connect(JNDIConnector.java:110) ... 23 more Caused by: javax.naming.NamingException: Failed to look up ConnectorDescriptor from JNDI [Root exception is com.sun.appserv.connectors.internal.api.ConnectorRuntimeException: Error in creating active RAR] at com.sun.enterprise.resource.naming.ConnectorObjectFactory.getObjectInstance(ConnectorObjectFactory.java:109) at javax.naming.spi.NamingManager.getObjectInstance(NamingManager.java:304) at com.sun.enterprise.naming.impl.SerialContext.getObjectInstance(SerialContext.java:472) at com.sun.enterprise.naming.impl.SerialContext.lookup(SerialContext.java:437) ... 26 more Caused by: com.sun.appserv.connectors.internal.api.ConnectorRuntimeException: Error in creating active RAR at com.sun.enterprise.connectors.ActiveRAFactory.createActiveResourceAdapter(ActiveRAFactory.java:104) at com.sun.enterprise.connectors.service.ResourceAdapterAdminServiceImpl.createActiveResourceAdapter(ResourceAdapterAdminServiceImpl.java:216) at com.sun.enterprise.connectors.ConnectorRuntime.createActiveResourceAdapter(ConnectorRuntime.java:352) at com.sun.enterprise.resource.naming.ConnectorObjectFactory.getObjectInstance(ConnectorObjectFactory.java:106) ... 29 more Caused by: java.lang.ClassNotFoundException: com.sun.gjc.spi.ResourceAdapter at java.net.URLClassLoader$1.run(URLClassLoader.java:200) at java.security.AccessController.doPrivileged(Native Method) at java.net.URLClassLoader.findClass(URLClassLoader.java:188) at java.lang.ClassLoader.loadClass(ClassLoader.java:306) at sun.misc.Launcher$AppClassLoader.loadClass(Launcher.java:276) at java.lang.ClassLoader.loadClass(ClassLoader.java:251) at com.sun.enterprise.connectors.ActiveRAFactory.createActiveResourceAdapter(ActiveRAFactory.java:96) ... 32 more Exception Description: Cannot acquire data source [BookstoreJNDI]. Internal Exception: javax.naming.NamingException: Lookup failed for 'BookstoreJNDI' in SerialContext ,orb'sInitialHost=localhost,orb'sInitialPort=3700 [Root exception is javax.naming.NamingException: Failed to look up ConnectorDescriptor from JNDI [Root exception is com.sun.appserv.connectors.internal.api.ConnectorRuntimeException: Error in creating active RAR]])

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  • NIS password mapping question

    - by papoyan
    I have NIS server with user "techsupport", which has uid/gid = 517 I've configured NIS and NFS on that server, as well as NFS/NIS client on the remote web server. Now I need to techsupport user to be able to login to web server using techsupport username, but HAVE root privileges. I need this, so I can easily track, which support agent doing what on the web server. Everything works fine, when from NIS server, I ssh to the web server with tech support user nisserver# ssh [email protected] I can authenticate against the NIS server just fine, and my home directory that is on NIS server, get's mounted on web server just fine. The Only two problems I have are : my GID on web server is webserver# id uid=517(techsupport) gid=517(client_jonny) groups=517(client_jonny) (as you can see, that it picked up gid of a client that exists on the web server, since it's same number) I need to make sure, that my "techsupport" user has ROOT privileges. How can I achieve this? I remember that I've seen identical results elsewhere, but LDAP was used, is there a way to achieve this with NIS/NFS setup? Thank you in advance,

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  • Users in database server or database tables

    - by Batcat
    Hi all, I came across an interesting issue about client server application design. We have this browser based management application where it has many users using the system. So obvisously within that application we have an user management module within it. I have always thought having an user table in the database to keep all the login details was good enough. However, a senior developer said user management should be done in the database server layer if not then is poorly designed. What he meant was, if a user wants to use the application then a user should be created in the user table AND in the database server as a user account as well. So if I have 50 users using my applications, then I should have 50 database server user logins. I personally think having just one user account in the database server for this database was enough. Just grant this user with the allowed privileges to operate all the necessary operation need by the application. The users that are interacting with the application should have their user accounts created and managed within the database table as they are more related to the application layer. I don't see and agree there is need to create a database server user account for every user created for the application in the user table. A single database server user should be enough to handle all the query sent by the application. Really hope to hear some suggestions / opinions and whether I'm missing something? performance or security issues? Thank you very much.

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  • Silverlight RIA Services - how to do Windows Authentication?

    - by Gustavo Cavalcanti
    I am building my first Silverlight 3 + RI Services application and need some help. It will be deployed in an controlled corporate intranet, 100% windows clients. I have started from the Silverlight Business Application template. These are my requirements: Upon launch the application needs to recognize the currently logged-in user. The application needs to have access to other properties of the user in AD, such as email, full name, and group membership. Group membership is used to grand certain features in the application. A "login as a different user" link is to be always available - Some machines are available throughout the enterprise, logged-in as a certain generic user (verified by the absence of certain membership groups). In this case one can enter credentials and log in (impersonate) to the application as a user different from the one already logged-into the machine. This user is to be used in service calls I have modified the following in the default Business Application template: App.xaml: appsvc:WindowsAuthentication instead of the default FormsAuthentication Web.config: authentication mode="Windows" With these modifications I resolve requirement #1 (get the currently logged-in user). But when I examine RiaContext.Current.User, I don't have access to other properties from AD, such as group memberships. How can I achieve my other requirements? Thanks for your help.

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  • cant get connexion using MongoTor

    - by Abdelouahab Pp
    i was trying to change my code to make it asynchronous using MongoTor here is my simple code: class BaseHandler(tornado.web.RequestHandler): @property def db(self): if not hasattr(self,"_db"): _db = Database.connect('localhost:27017', 'essog') return _db @property def fs(self): if not hasattr(BaseHandler,"_fs"): _fs = gridfs.GridFS(self.db) return _fs class LoginHandler(BaseHandler): @tornado.web.asynchronous @tornado.gen.engine def post(self): email = self.get_argument("email") password = self.get_argument("pass1") try: search = yield tornado.gen.Task(self.db.users.find, {"prs.mail":email}) .... i got this error: Traceback (most recent call last): File "C:\Python27\lib\site-packages\tornado-2.4.post1-py2.7.egg\tornado\web.py", line 1043, in _stack_context_handle_exception raise_exc_info((type, value, traceback)) File "C:\Python27\lib\site-packages\tornado-2.4.post1-py2.7.egg\tornado\web.py", line 1162, in wrapper return method(self, *args, **kwargs) File "C:\Python27\lib\site-packages\tornado-2.4.post1-py2.7.egg\tornado\gen.py", line 122, in wrapper runner.run() File "C:\Python27\lib\site-packages\tornado-2.4.post1-py2.7.egg\tornado\gen.py", line 365, in run yielded = self.gen.send(next) File "G:\Mon projet\essog\handlers.py", line 92, in post search = yield tornado.gen.Task(self.db.users.find, {"prs.mail":email}) File "G:\Mon projet\essog\handlers.py", line 62, in db _db = Database.connect('localhost:27017', 'essog') File "build\bdist.win-amd64\egg\mongotor\database.py", line 131, in connect database.init(addresses, dbname, read_preference, **kwargs) File "build\bdist.win-amd64\egg\mongotor\database.py", line 62, in init ioloop_is_running = IOLoop.instance().running() AttributeError: 'SelectIOLoop' object has no attribute 'running' ERROR:tornado.access:500 POST /login (::1) 3.00ms and, excuse me for this other question, but how do i make distinct in this case? here is what worked in blocking mode: search = self.db.users.find({"prs.mail":email}).distinct("prs.mail")[0] Update: it seems that this error happenes when there is no Tornado running! it's the same error raised when using only the module in console. test = Database.connect("localhost:27017", "essog") --------------------------------------------------------------------------- AttributeError Traceback (most recent call last) in () ---- 1 test = Database.connect("localhost:27017", "essog") C:\Python27\lib\site-packages\mongotor-0.0.10-py2.7.egg\mongotor\database.pyc in connect(cls, addresses, dbname, read_preference, **kwargs) 131 132 database = Database() -- 133 database.init(addresses, dbname, read_preference, **kwargs) 134 135 return database C:\Python27\lib\site-packages\mongotor-0.0.10-py2.7.egg\mongotor\database.pyc in init(self, addresses, dbname, read_preference, **kwargs) 60 self._nodes.append(node) 61 --- 62 ioloop_is_running = IOLoop.instance().running() 63 self._config_nodes(callback=partial(self._on_config_node, ioloop_is_running)) 64 AttributeError: 'SelectIOLoop' object has no attribute 'running'

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  • Devise routes /:param not working

    - by Jacob Schatz
    Using devise 2.1.0 I am trying to send the new registration page a PricingPlan model. So in my routes I have: devise_scope :user do delete "/logout" => "devise/sessions#destroy" get "/login" => "devise/sessions#new" get "/signup/:plan" => "devise/registrations#new" end And I override the devise registration controller. With this in my routes.rb to make it work: devise_for :users, :controllers => {:registrations => "registrations"} In my actual Registration controller which overrides Devise's controller I have: class RegistrationsController < Devise::RegistrationsController view_paths = "app/views/devise" def new super @plan = PricingPlan.find_by_name(params[:plan]) end So that the default views still go to devise.... In my new view for the registration controller I call this: <h3>You've chosen the <%= @plan.name %> plan.</h3> And I get this error: undefined method `name' for nil:NilClass Also... in my PricingPlan model: class PricingPlan < ActiveRecord::Base has_many :users And in my User model: class User < ActiveRecord::Base belongs_to :pricing_plan I'm rather new at rails.

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  • Weird Issues with WPMU I Can't Figure Out

    - by HollerTrain
    I know I should post this on the WPMU forum, but no one writes me back and I'm just trying to find a larger audience hoping you have run into this issue as well. I have built a WPMU site for a client, and I am able to upload media into the Media Library and within a Post or Page perfectly. I thought my job was finished, yet the client can't upload any media at all. I'm located in Kentucky, they are located in New England (if that even matters). I had the client record their process of uploading as I thought they were simply not following my instructions for uploading, yet they are doing everything correctly. When uploading a file it goes through the process of allowing them to select a file and it says it uploads it, yet when it is finished uploading nothing is in the Media Library or in the Post. Video of the client trying to upload in Media Manager (http://www.screencast.com/users/CatherineWeber/folders/Jing/media/945d33fa-a752-45fd-9bc1-f76fc5a1814a) Video of the client trying to upload within a Post (http://www.screencast.com/users/CatherineWeber/folders/Jing/media/b5c60e25-f0b5-40c0-a820-c2fc9eb00906) Asking the client to disable Flash Uploader didn't work :( Yet, I can login to the WPMU site, access their blog's backend and can easily upload a ton of files. I am so lost at to what the issue is here. I am running version 2.8.4a, and will try to upgrade to latest release hoping this will fix things.

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  • Submit WordPress form password programmatically

    - by songdogtech
    How can I let a user access a WordPress protected page with a URL that will submit the password in the form below? I want to be able to let a user get to a password protected WordPress page without needing to type the password, so when they go to the page, the password is submitted by a POST URL on page load. This not intended to be secure in any respect; I'll need to hardcode the password in the URL and the PHP. It's just for simplicity for the user, and once they're in, the cookie will let them in for 10 more days. I will select the particular user with separate PHP function that determines their IP or WordPress login status. I used Wireshark to find the POST string: post_password=mypassword&Submit=Submit but using this URL mydomain.com/wp-pass.php?post_password=mypassword&Submit=Submit gives me a blank page. This is the form: <form action="http://mydomain.com/wp-pass.php" method="post"> Password: <input name="post_password" type="password" size="20" /> <input type="submit" name="Submit" value="Submit" /></form> This is wp-pass.php: <?php require( dirname(__FILE__) . '/wp-load.php'); if ( get_magic_quotes_gpc() ) $_POST['post_password'] = stripslashes($_POST['post_password']); setcookie('wp-postpass_' . COOKIEHASH, $_POST['post_password'], time() + 864000, COOKIEPATH); wp_safe_redirect(wp_get_referer()); ?> What am I doing wrong? Or is there a better way to let a user into a password protected page automatically?

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  • Database not updating after UPDATE SQL statement in ASP.net

    - by Ronnie
    I currently have a problem attepting to update a record within my database. I have a webpage that displays in text boxes a users details, these details are taken from the session upon login. The aim is to update the details when the user overwrites the current text in the text boxes. I have a function that runs when the user clicks the 'Save Details' button and it appears to work, as i have tested for number of rows affected and it outputs 1. However, when checking the database, the record has not been updated and I am unsure as to why. I've have checked the SQL statement that is being processed by displaying it as a label and it looks as so: UPDATE [users] SET [email]=@email, [firstname]=@firstname, [lastname]=@lastname, [promo]=@promo WHERE ([users].[user_id] = 16) The function and other relevant code is: Sub Button1_Click(sender As Object, e As EventArgs) changeDetails(emailBox.text, firstBox.text, lastBox.text, promoBox.text) End Sub Function changeDetails(ByVal email As String, ByVal firstname As String, ByVal lastname As String, ByVal promo As String) As Integer Dim connectionString As String = "Provider=Microsoft.Jet.OLEDB.4.0; Ole DB Services=-4; Data Source=C:\Documents an"& _ "d Settings\Paul Jarratt\My Documents\ticketoffice\datab\ticketoffice.mdb" Dim dbConnection As System.Data.IDbConnection = New System.Data.OleDb.OleDbConnection(connectionString) Dim queryString As String = "UPDATE [users] SET [email]=@email, [firstname]=@firstname, [lastname]=@lastname, "& _ "[promo]=@promo WHERE ([users].[user_id] = " + session.contents.item("ID") + ")" Dim dbCommand As System.Data.IDbCommand = New System.Data.OleDb.OleDbCommand dbCommand.CommandText = queryString dbCommand.Connection = dbConnection Dim dbParam_email As System.Data.IDataParameter = New System.Data.OleDb.OleDbParameter dbParam_email.ParameterName = "@email" dbParam_email.Value = email dbParam_email.DbType = System.Data.DbType.[String] dbCommand.Parameters.Add(dbParam_email) Dim dbParam_firstname As System.Data.IDataParameter = New System.Data.OleDb.OleDbParameter dbParam_firstname.ParameterName = "@firstname" dbParam_firstname.Value = firstname dbParam_firstname.DbType = System.Data.DbType.[String] dbCommand.Parameters.Add(dbParam_firstname) Dim dbParam_lastname As System.Data.IDataParameter = New System.Data.OleDb.OleDbParameter dbParam_lastname.ParameterName = "@lastname" dbParam_lastname.Value = lastname dbParam_lastname.DbType = System.Data.DbType.[String] dbCommand.Parameters.Add(dbParam_lastname) Dim dbParam_promo As System.Data.IDataParameter = New System.Data.OleDb.OleDbParameter dbParam_promo.ParameterName = "@promo" dbParam_promo.Value = promo dbParam_promo.DbType = System.Data.DbType.[String] dbCommand.Parameters.Add(dbParam_promo) Dim rowsAffected As Integer = 0 dbConnection.Open Try rowsAffected = dbCommand.ExecuteNonQuery Finally dbConnection.Close End Try labelTest.text = rowsAffected.ToString() if rowsAffected = 1 then labelSuccess.text = "* Your details have been updated and saved" else labelError.text = "* Your details could not be updated" end if End Function Any help would be greatly appreciated.

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  • iPhone ASIHttpRequest - can't POST variables asynchronously

    - by Eamorr
    Greetings, I'm trying to simply POST data to a url using ASIHttpRequest. Here is my code: __block ASIHTTPRequest *request=[ASIHTTPRequest requestWithURL:url]; [request setPostBody:[NSMutableData dataWithData:[@"uname=Hello" dataUsingEncoding:NSUTF8StringEncoding]]]; [request setDelegate:self]; [request setCompletionBlock:^{ NSString *response=[request responseString]; UIAlertView *msg=[[UIAlertView alloc] initWithTitle:@"Response" message:response delegate:self cancelButtonTitle:@"OK" otherButtonTitles:nil]; [msg show]; [msg release]; }]; [request setFailedBlock:^{ NSError *error =[request error]; }]; [request startAsynchronous]; Basically, my url is xxx.xxx.xxx.xxx/login.php, when I dump the PHP $_POST variable, I just get an empty array - i.e. no POST parameters are sent! The rest of the PHP is tested and working fine. I've looked through the allseeing-i.com documentation and examples and can't seem to resolve this problem. Any insight greatly appreciated. Many thanks in advance,

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  • Sample twitter application.

    - by Jack
    <?php function updateTwitter($status) { // Twitter login information $username = 'xxxxx'; $password = 'xxxxxx'; // The url of the update function $url = 'http://twitter.com/statuses/update.xml'; // Arguments we are posting to Twitter $postargs = 'status='.urlencode($status); // Will store the response we get from Twitter $responseInfo=array(); // Initialize CURL $ch = curl_init($url); // Tell CURL we are doing a POST curl_setopt ($ch, CURLOPT_POST, true); // Give CURL the arguments in the POST curl_setopt ($ch, CURLOPT_POSTFIELDS, $postargs); // Set the username and password in the CURL call curl_setopt($ch, CURLOPT_USERPWD, $username.':'.$password); // Set some cur flags (not too important) curl_setopt($ch, CURLOPT_VERBOSE, 1); curl_setopt($ch, CURLOPT_NOBODY, 0); curl_setopt($ch, CURLOPT_HEADER, 0); curl_setopt($ch, CURLOPT_FOLLOWLOCATION,1); curl_setopt($ch, CURLOPT_RETURNTRANSFER, 1); // execute the CURL call $response = curl_exec($ch); // Get information about the response $responseInfo=curl_getinfo($ch); // Close the CURL connection curl_close($ch); // Make sure we received a response from Twitter if(intval($responseInfo['http_code'])==200){ // Display the response from Twitter echo $response; }else{ // Something went wrong echo "Error: " . $responseInfo['http_code']; } } updateTwitter("Just finished a sweet tutorial on http://brandontreb.com"); ?> I get the following output Error: 0 Please help.

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  • [SOLVED]: Delegate OpenID to Google (NOT Google Apps)

    - by Rio
    OK, I searched this question on SO but no good answer. After spent some time I figured out how to do it. I'm going to answer this myself as a way to share it. Not sure if this is the correct way to use SO, but here it goes: Now it is possible delegate OpenID to your Google account (not Google Apps). No, this is not using the demo OpenID provider using App Engine. This is your REAL Google account! First you need to enable your Google Profiles. Try to view your profile and edit it, there should be an option to set your Profile URL. You have two choices there: either use your Gmail account name (without the @gmail.com part) as your profile id, or a random number assigned to you. It's up to you to decide which one to use. Either way, that id is your profile id below. Now add the following HTML code to your delegating page: <link rel="openid2.provider" href="https://www.google.com/accounts/o8/ud?source=profiles" > <link rel="openid2.local_id" href="http://www.google.com/profiles/[YOUR PROFILE ID]" > And it's done. Now try login SO with your custom url!

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  • What is session management in Java ?

    - by Sarang
    I have faced this question in my Interview as well. I do have many confusion with Session Scope & it management in java. In web.xml we do have the entry : <session-config> <session-timeout> 30 </session-timeout> </session-config> What does it indicate actually ? Is is scope of whole project ? Another point confusing me is how can we separate the session scope of multiple request in the same project? Means if I am logging in from a PC & at the same time I am logging in from another PC, does it differentiate it ? Also, another confusing thing is the browser difference. Why does the different Gmails possible to open in different browsers ? And Gmail can prevent a session from Login to Logout. How is it maintained with our personal web ?

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  • Imap cyrillic mail

    - by atredis
    I use the mailsystem.NET library to put a message in my inbox. This is my code: Imap4Client imap = new Imap4Client(); imap.ConnectSsl("imap.gmail.com", 993); imap.Login(mylogin, mypassword); Mailbox mails; mails = imap.SelectMailbox("INBOX"); Message commomMessage = new Message(); commomMessage.From = new Address("someAddress", "someName"); commomMessage.To.Add(mylogin, "myName"); commomMessage.Subject = "someSubject"; commomMessage.BodyHtml.Text = "?????? ???";//or some cyrillic text commomMessage.Date = DateTime.Now; mails.Append(commomMessage); When I open my gmail inbox, I see this mail, but the body contains ????? ??? rather than "?????? ???". If commomMessage.BodyHtml.Text contains only Latin characters, there is no problem.

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  • Spring Security 3.0 - Intercept-URL - All pages require authentication but one

    - by gav
    Hi All, I want any user to be able to submit their name to a volunteer form but only administrators to be able to view any other URL. Unfortunately I don't seem to be able to get this correct. My resources.xml are as follows; <?xml version="1.0" encoding="UTF-8"?> <beans:beans xmlns="http://www.springframework.org/schema/security" xmlns:beans="http://www.springframework.org/schema/beans" xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xsi:schemaLocation="http://www.springframework.org/schema/beans http://www.springframework.org/schema/beans/spring-beans-3.0.xsd http://www.springframework.org/schema/security http://www.springframework.org/schema/security/spring-security-3.0.xsd"> <http realm = "BumBumTrain Personnel list requires you to login" auto-config="true" use-expressions="true"> <http-basic/> <intercept-url pattern="/person/volunteer*" access=""/> <intercept-url pattern="/**" access="isAuthenticated()" /> </http> <authentication-manager alias="authenticationManager"> <authentication-provider> <user-service> <user name="admin" password="admin" authorities="ROLE_ADMIN"/> </user-service> </authentication-provider> </authentication-manager> </beans:beans> Specifically I am trying to achieve the access settings I described via; <intercept-url pattern="/person/volunteer*" access=""/> <intercept-url pattern="/**" access="isAuthenticated()" /> Could someone please describe how to use intercept-url to achieve the outcome I've described? Thanks Gav

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  • Possible to recover mysql root pass with sudo server access?

    - by jonathonmorgan
    I've inherited development for a website on vps hosting, and have login info for a user with sudo privileges, but don't have the password for the mysql root user. After digging around a little, it looks like the only way to fix this is to stop mysql (something like this: http://waoewaoe.wordpress.com/2010/02/03/recover-reset-mysql-root-password/). But because the website it's serving is currently in production, I'm hoping you guys can enlighten me to any potential consequences (or let me know if there's typically a file where the password would be accessible). a) during the time mysql is stopped, information in the database won't be accessible, right -- even by other users? b) will resetting the root password have any impact on other users after mysql has restarted? Will their username/passwords still be valid? The current application is using an account with limited privileges to read/write to the database, and while 5min downtime in the middle of the night would probably go unnoticed, half a day while I tie up loose ends/figure out what I screwed up will land in me hot water. Thanks in advance for your help!

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  • Fatal error: Uncaught exception 'Zend_Gdata_App_HttpException' with message 'Expected response code 200, got 401'

    - by Peak Reconstruction Wavelength
    I am using a php-script that has been working for years, but suddenly it aborts with Fatal error: Uncaught exception 'Zend_Gdata_App_HttpException' with message 'Expected response code 200, got 401' NoLinkedYouTubeAccount Error 401 It starts like this <?php function anmelden_yt($name,$passwort) { $yt_source = 'known'; $yt_api_key = 'key'; $yt = null; $authenticationURL= 'https://www.google.com/accounts/ClientLogin'; $httpClient = Zend_Gdata_ClientLogin::getHttpClient( $username = $name, $password = $passwort, $service = 'youtube', $client = null, $source = $yt_source, // a short string identifying your application $loginToken = null, $loginCaptcha = null, $authenticationURL); abschnitt("Login"); return new Zend_Gdata_YouTube($httpClient, $yt_source, NULL, $yt_api_key); } require_once("Zend/Gdata/ClientLogin.php"); require_once("Zend/Gdata/HttpClient.php"); require_once("Zend/Gdata/YouTube.php"); require_once("Zend/Gdata/App/MediaFileSource.php"); require_once("Zend/Gdata/App/HttpException.php"); require_once('Zend/Uri/Http.php'); require_once 'Zend/Loader.php'; Zend_Loader::loadClass('Zend_Gdata_YouTube'); Zend_Loader::loadClass('Zend_Gdata_AuthSub'); Zend_Loader::loadClass('Zend_Gdata_ClientLogin'); $yt = anmelden_yt($name,$pass); $videoFeed = $yt->getUserUploads('Google'); sleep(0.5); @ob_flush(); @flush(); ?> What could be the reason for this? ..................................................................................................

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  • T4MVC not generating an action

    - by Maslow
    I suspected there was some hidden magic somewhere that stopped what looks like actual method calls all over the place in T4MVC. Then I had a view fail to compile, and the stackTrace went into my actual method. [Authorize] public string Apply(string shortName) { if (shortName.IsNullOrEmpty()) return "Failed alliance name was not transmitted"; if (Request.IsAuthenticated == false || User == null || User.Identity == null) return "Apply authentication failed"; Models.Persistence.AlliancePersistance.Apply(User.Identity.Name, shortName); return "Applied"; } So this method isn't generating in the template after all. <%=Ajax.ActionLink("Apply", "Apply", new RouteValueDictionary() { { "shortName", item.Shortname } }, new AjaxOptions() { UpdateTargetId = "masterstatus" })%> <%=Html.ActionLink("Apply",MVC.Alliance.Apply(item.Shortname),new AjaxOptions() { UpdateTargetId = "masterstatus" }) %> The second method threw an exception on compile because the method Apply in my controller has an [Authorize] attribute so that if someone that isn't logged on clicks this, they get redirected to login, then right back to this page. There they can click on apply again, this time being logged in. And yes I realize one is Ajax.ActionLink while the other is Html.ActionLink I did try them both with the T4MVC version.

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  • cross-platform scripting for windows, Linux, MacOS X

    - by karolrvn
    Hi. I'm looking for cross-platform scripting (language) for windows, Linux, MacOS X. I'm tired of .bat / bash . I would like to do things like for example ,,lock workstation'' at automatic login (I had this in X-Window but the solution was pretty ugly; now, I would like that on MS Windows and not that ugly :-) ). Generally: automate tasks. Or would I be better off with Windows Scripting Host? PowerShell also comes to mind, but that's seems to Windows-only for my taste. Can languages like Python, Ruby, (Java?) interact (elegantly? sensibly?) with WSH? Also things like DBUS, DCOM, etc come to mind as part of the picture. Currently I use a mixture of Java, .bat, bash, Ruby, Scala; some VBA for Excel. Which sometimes gets pretty ugly. I would like a cross-platform general solution with/using ,,native'' parts close to OS-specifics. Like e.g. Ruby driving some Windows-specific stuff (just a guess). What do You use? TIA

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  • web development using google sites

    - by CHID
    Hi, I have hosted a website. But now my client asks to change it to http://sites.google.com. They hav registered their domain in google. I logged in the site and saw the procedures to create a website from scratch. But is there any way to directly replace the site into google sites. Like, in my site i hav included css files in a folder called stylesheets/css and access it through the link tag. And there are several folders lik that, viz images, scripts etc. 1.Now if i have to transfer it to google sites, where do i create the folders and stuff. I have the priviliges to login to the admin part of the site. 2.And also is there anyway to create database and access it in google sites? 3.Also i see that only html pages can be created. Is there a way to add php pages or other scripting languages? 4.Going forward will google sites be usefull for professional web designing. pls give ideas on whether or not google sites is a good idea to go with

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  • Web form is not updating tables, why?

    - by JPJedi
    I have a web application and on page is an update page to update some profile information. Below is the code I am using to update the table. But I think it is wrong. Does anything stick out? The connection string works cause it is used to read the database to get the profile information, I just removed it due to it containing password/login info for the db. player is the class of properties that contains player information and ds is the dataset, but I would like to update the database itself online... Dim connectionString As String = "" Dim GigsterDBConnection As New System.Data.SqlClient.SqlConnection(connectionString) GigsterDBConnection.Open() Dim updatetoursql As String = "UPDATE PLAYERS SET FIRSTNAME = '" & player.FIRSTNAME & "', LASTNAME = '" & player.LASTNAME & "', ADDRESS = '" & player.ADDRESS & "', CITY = '" & player.CITY & "', ZIP = '" & player.ZIP & "', PHONE = '" & player.PHONE & "', EMAIL = '" & player.EMAIL & "', REFFEREDBY = '" & player.REFEREDBY & "' " updatetoursql = updatetoursql & "PLAYERID = '" & player.PLAYERID & "';" Dim cmd As New System.Data.SqlClient.SqlCommand(updatetoursql, GigsterDBConnection) Dim sqlAdapter As New System.Data.SqlClient.SqlDataAdapter(cmd) sqlAdapter.Update(ds, "PLAYERS") I think the issue is something the 3 last lines of the code. am I doing it right or is their a better way? Thanks

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  • modifying ajax returned data before showing

    - by Nick
    I'm processing subscribtion form with jQuery/ajax and need to display results with success function (they are different depending on if email exists in database). But the trick is I do not need h2 and first "p" tag. How can I show only div#alertmsg and second "p" tag? I've tried revoming unnecessary elements with method described here, but it didn't work. Thanks in advance. Here is my code: var dataString = $('#subscribe').serialize(); $.ajax({ type: "POST", url: "/templates/willrock/pommo/user/process.php", data: dataString, success: function(data){ var result = $(data); $('#success').append(result); } Here is the data returned: <h2>Subscription Review</h2> <p><a href="url" onClick="history.back(); return false;"><img src="/templates/willrock/pommo/themes/shared/images/icons/back.png" alt="back icon" class="navimage" /> Back to Subscription Form</a></p> <div id="alertmsg" class="error"> <ul> <li>Email address already exists. Duplicates are not allowed.</li> </ul> </div> <p><a href="login.php">Update your records</a></p>

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  • getting incorrect error even if the condition is fulfilled

    - by Tapan Desai
    I am trying to show the message based on the text shown on webpage after a particular action. If the webpage contains text MESSAGE HAS BEEN SUBMITTED SUCCESSFULLY, I want to print Message sent successfully on the screen otherwise MESSAGE SENDING FAILED. Everything is working fine but for one thing. PrintWriter printWriter = new PrintWriter(new OutputStreamWriter(sendConnection.getOutputStream()), true); printWriter.print(sendContent); printWriter.flush(); printWriter.close(); //Reading the returned web page to analyse whether the operation was sucessfull BufferedReader bufferedReader = new BufferedReader(new InputStreamReader(sendConnection.getInputStream())); StringBuilder SendResult = new StringBuilder(); String line; while ((line = bufferedReader.readLine()) != null) { SendResult.append(line); } if (SendResult.toString().contains("MESSAGE HAS BEEN SUBMITTED SUCCESSFULLY")) { System.out.println("Message sent to " + phoneNumber + " successfully."); } else { System.err.println("Message could not send to " + phoneNumber + ". Also check login credentials"); } bufferedReader.close(); The problem is that even if the webpage contains the text MESSAGE HAS BEEN SUBMITTED SUCCESSFULLY, the condition always goes into ELSE part and show MESSAGE SENDING FAILED but thats not true because the message has been sent and i see the MESSAGE HAS BEEN SUBMITTED SUCCESSFULLY on the webpage. Can anyone tell me where am i going wrong?

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